Integrand size = 246, antiderivative size = 28 \[ \int \frac {-5 e^7+e^6 \left (-5 e^4+20 e^2 x\right )+e^6 \left (20 e^2 x+10 e^4 x\right ) \log (x)+\left (-e^4 x+e^3 \left (-2 e^4 x+8 e^2 x^2\right )+e^6 \left (4 e^4 x+8 e^2 x^2-16 x^3\right )\right ) \log ^2(x)+\left (2 e^7 x^2+e^6 \left (2 e^4 x^2-8 e^2 x^3\right )\right ) \log ^3(x)-e^{10} x^3 \log ^4(x)}{\left (e^4 x+e^3 \left (2 e^4 x-8 e^2 x^2\right )+e^6 \left (e^4 x-8 e^2 x^2+16 x^3\right )\right ) \log ^2(x)+\left (-2 e^7 x^2+e^6 \left (-2 e^4 x^2+8 e^2 x^3\right )\right ) \log ^3(x)+e^{10} x^3 \log ^4(x)} \, dx=-x+\frac {5}{\log (x) \left (1+\frac {1}{e^3}-x \left (\frac {4}{e^2}+\log (x)\right )\right )} \]
Leaf count is larger than twice the leaf count of optimal. \(61\) vs. \(2(28)=56\).
Time = 0.09 (sec) , antiderivative size = 61, normalized size of antiderivative = 2.18 \[ \int \frac {-5 e^7+e^6 \left (-5 e^4+20 e^2 x\right )+e^6 \left (20 e^2 x+10 e^4 x\right ) \log (x)+\left (-e^4 x+e^3 \left (-2 e^4 x+8 e^2 x^2\right )+e^6 \left (4 e^4 x+8 e^2 x^2-16 x^3\right )\right ) \log ^2(x)+\left (2 e^7 x^2+e^6 \left (2 e^4 x^2-8 e^2 x^3\right )\right ) \log ^3(x)-e^{10} x^3 \log ^4(x)}{\left (e^4 x+e^3 \left (2 e^4 x-8 e^2 x^2\right )+e^6 \left (e^4 x-8 e^2 x^2+16 x^3\right )\right ) \log ^2(x)+\left (-2 e^7 x^2+e^6 \left (-2 e^4 x^2+8 e^2 x^3\right )\right ) \log ^3(x)+e^{10} x^3 \log ^4(x)} \, dx=-x+\frac {5 e^3}{\left (1+e^3-4 e x\right ) \log (x)}-\frac {5 e^6 x}{\left (1+e^3-4 e x\right ) \left (-1-e^3+4 e x+e^3 x \log (x)\right )} \]
Integrate[(-5*E^7 + E^6*(-5*E^4 + 20*E^2*x) + E^6*(20*E^2*x + 10*E^4*x)*Lo g[x] + (-(E^4*x) + E^3*(-2*E^4*x + 8*E^2*x^2) + E^6*(4*E^4*x + 8*E^2*x^2 - 16*x^3))*Log[x]^2 + (2*E^7*x^2 + E^6*(2*E^4*x^2 - 8*E^2*x^3))*Log[x]^3 - E^10*x^3*Log[x]^4)/((E^4*x + E^3*(2*E^4*x - 8*E^2*x^2) + E^6*(E^4*x - 8*E^ 2*x^2 + 16*x^3))*Log[x]^2 + (-2*E^7*x^2 + E^6*(-2*E^4*x^2 + 8*E^2*x^3))*Lo g[x]^3 + E^10*x^3*Log[x]^4),x]
-x + (5*E^3)/((1 + E^3 - 4*E*x)*Log[x]) - (5*E^6*x)/((1 + E^3 - 4*E*x)*(-1 - E^3 + 4*E*x + E^3*x*Log[x]))
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {-e^{10} x^3 \log ^4(x)+\left (2 e^7 x^2+e^6 \left (2 e^4 x^2-8 e^2 x^3\right )\right ) \log ^3(x)+\left (e^3 \left (8 e^2 x^2-2 e^4 x\right )+e^6 \left (-16 x^3+8 e^2 x^2+4 e^4 x\right )-e^4 x\right ) \log ^2(x)+e^6 \left (20 e^2 x-5 e^4\right )+e^6 \left (10 e^4 x+20 e^2 x\right ) \log (x)-5 e^7}{e^{10} x^3 \log ^4(x)+\left (e^6 \left (8 e^2 x^3-2 e^4 x^2\right )-2 e^7 x^2\right ) \log ^3(x)+\left (e^3 \left (2 e^4 x-8 e^2 x^2\right )+e^6 \left (16 x^3-8 e^2 x^2+e^4 x\right )+e^4 x\right ) \log ^2(x)} \, dx\) |
| \(\Big \downarrow \) 7239 |
| \(\displaystyle \int \frac {-e^6 x^3 \log ^4(x)+2 e^3 x^2 \left (-4 e x+e^3+1\right ) \log ^3(x)-x \left (16 e^2 x^2-8 e^4 x-8 e x-4 e^6+2 e^3+1\right ) \log ^2(x)-5 e^3 \left (-4 e x+e^3+1\right )+10 e^4 \left (2+e^2\right ) x \log (x)}{x \log ^2(x) \left (-4 e x-e^3 x \log (x)+e^3+1\right )^2}dx\) |
| \(\Big \downarrow \) 7293 |
| \(\displaystyle \int \left (\frac {5 e^3}{\left (4 e x-e^3-1\right ) x \log ^2(x)}-\frac {20 e^7 x}{\left (-4 e x+e^3+1\right )^2 \left (4 e x+e^3 x \log (x)-e^3-1\right )}+\frac {20 e^4}{\left (-4 e x+e^3+1\right )^2 \log (x)}+\frac {5 \left (e^9 x+e^9+e^6\right )}{\left (-4 e x+e^3+1\right ) \left (4 e x+e^3 x \log (x)-e^3-1\right )^2}-1\right )dx\) |
| \(\Big \downarrow \) 2009 |
| \(\displaystyle 5 e^3 \int \frac {1}{x \left (4 e x-e^3-1\right ) \log ^2(x)}dx+20 e^4 \int \frac {1}{\left (-4 e x+e^3+1\right )^2 \log (x)}dx-\frac {5}{4} e^8 \int \frac {1}{\left (e^3 \log (x) x+4 e x-e^3-1\right )^2}dx+\frac {5}{4} e^6 \left (4+e^2+4 e^3+e^5\right ) \int \frac {1}{\left (-4 e x+e^3+1\right ) \left (e^3 \log (x) x+4 e x-e^3-1\right )^2}dx-5 e^6 \left (1+e^3\right ) \int \frac {1}{\left (-4 e x+e^3+1\right )^2 \left (e^3 \log (x) x+4 e x-e^3-1\right )}dx+5 e^6 \int \frac {1}{\left (-4 e x+e^3+1\right ) \left (e^3 \log (x) x+4 e x-e^3-1\right )}dx-x\) |
Int[(-5*E^7 + E^6*(-5*E^4 + 20*E^2*x) + E^6*(20*E^2*x + 10*E^4*x)*Log[x] + (-(E^4*x) + E^3*(-2*E^4*x + 8*E^2*x^2) + E^6*(4*E^4*x + 8*E^2*x^2 - 16*x^ 3))*Log[x]^2 + (2*E^7*x^2 + E^6*(2*E^4*x^2 - 8*E^2*x^3))*Log[x]^3 - E^10*x ^3*Log[x]^4)/((E^4*x + E^3*(2*E^4*x - 8*E^2*x^2) + E^6*(E^4*x - 8*E^2*x^2 + 16*x^3))*Log[x]^2 + (-2*E^7*x^2 + E^6*(-2*E^4*x^2 + 8*E^2*x^3))*Log[x]^3 + E^10*x^3*Log[x]^4),x]
3.18.40.3.1 Defintions of rubi rules used
Int[u_, x_Symbol] :> With[{v = SimplifyIntegrand[u, x]}, Int[v, x] /; Simpl erIntegrandQ[v, u, x]]
Time = 0.92 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.14
| method | result | size |
| risch | \(-x -\frac {5 \,{\mathrm e}^{3}}{\left (x \,{\mathrm e}^{3} \ln \left (x \right )-{\mathrm e}^{3}+4 x \,{\mathrm e}-1\right ) \ln \left (x \right )}\) | \(32\) |
| default | \(-\frac {-\frac {{\mathrm e}^{-3} \left ({\mathrm e}^{3}+1\right )^{2} {\mathrm e}^{4} \ln \left (x \right )}{4}+\frac {{\mathrm e}^{4} \left ({\mathrm e}^{3}+1\right ) \ln \left (x \right )^{2} x}{4}+{\mathrm e}^{2} \ln \left (x \right )^{2} {\mathrm e}^{3} x^{2}+5 \,{\mathrm e}^{2} {\mathrm e}^{3}+4 \,{\mathrm e}^{3} \ln \left (x \right ) x^{2}}{\ln \left (x \right ) \left ({\mathrm e}^{3} {\mathrm e}^{2} x \ln \left (x \right )-{\mathrm e}^{2} {\mathrm e}^{3}+4 x \,{\mathrm e}^{3}-{\mathrm e}^{2}\right )}\) | \(94\) |
| norman | \(\frac {\frac {{\mathrm e}^{4} {\mathrm e}^{-3} \left ({\mathrm e}^{6}+2 \,{\mathrm e}^{3}+1\right ) \ln \left (x \right )}{4}+\left (-\frac {{\mathrm e}^{3} {\mathrm e}^{4}}{4}-\frac {{\mathrm e}^{4}}{4}\right ) x \ln \left (x \right )^{2}-5 \,{\mathrm e}^{2} {\mathrm e}^{3}-4 \,{\mathrm e}^{3} \ln \left (x \right ) x^{2}-{\mathrm e}^{2} \ln \left (x \right )^{2} {\mathrm e}^{3} x^{2}}{\ln \left (x \right ) \left ({\mathrm e}^{3} {\mathrm e}^{2} x \ln \left (x \right )-{\mathrm e}^{2} {\mathrm e}^{3}+4 x \,{\mathrm e}^{3}-{\mathrm e}^{2}\right )}\) | \(104\) |
| parallelrisch | \(-\frac {\left ({\mathrm e}^{4} \ln \left (x \right )^{2} {\mathrm e}^{6} x +4 \,{\mathrm e}^{2} \ln \left (x \right )^{2} {\mathrm e}^{6} x^{2}+{\mathrm e}^{4} \ln \left (x \right )^{2} {\mathrm e}^{3} x -{\mathrm e}^{4} {\mathrm e}^{6} \ln \left (x \right )+16 \ln \left (x \right ) {\mathrm e}^{6} x^{2}-2 \,{\mathrm e}^{3} \ln \left (x \right ) {\mathrm e}^{4}-{\mathrm e}^{4} \ln \left (x \right )+20 \,{\mathrm e}^{2} {\mathrm e}^{6}\right ) {\mathrm e}^{-3}}{4 \ln \left (x \right ) \left ({\mathrm e}^{3} {\mathrm e}^{2} x \ln \left (x \right )-{\mathrm e}^{2} {\mathrm e}^{3}+4 x \,{\mathrm e}^{3}-{\mathrm e}^{2}\right )}\) | \(128\) |
int((-x^3*exp(2)^2*exp(3)^2*ln(x)^4+((2*x^2*exp(2)^2-8*x^3*exp(2))*exp(3)^ 2+2*x^2*exp(2)^2*exp(3))*ln(x)^3+((4*x*exp(2)^2+8*x^2*exp(2)-16*x^3)*exp(3 )^2+(-2*x*exp(2)^2+8*x^2*exp(2))*exp(3)-x*exp(2)^2)*ln(x)^2+(10*x*exp(2)^2 +20*exp(2)*x)*exp(3)^2*ln(x)+(-5*exp(2)^2+20*exp(2)*x)*exp(3)^2-5*exp(2)^2 *exp(3))/(x^3*exp(2)^2*exp(3)^2*ln(x)^4+((-2*x^2*exp(2)^2+8*x^3*exp(2))*ex p(3)^2-2*x^2*exp(2)^2*exp(3))*ln(x)^3+((x*exp(2)^2-8*x^2*exp(2)+16*x^3)*ex p(3)^2+(2*x*exp(2)^2-8*x^2*exp(2))*exp(3)+x*exp(2)^2)*ln(x)^2),x,method=_R ETURNVERBOSE)
Leaf count of result is larger than twice the leaf count of optimal. 61 vs. \(2 (27) = 54\).
Time = 0.38 (sec) , antiderivative size = 61, normalized size of antiderivative = 2.18 \[ \int \frac {-5 e^7+e^6 \left (-5 e^4+20 e^2 x\right )+e^6 \left (20 e^2 x+10 e^4 x\right ) \log (x)+\left (-e^4 x+e^3 \left (-2 e^4 x+8 e^2 x^2\right )+e^6 \left (4 e^4 x+8 e^2 x^2-16 x^3\right )\right ) \log ^2(x)+\left (2 e^7 x^2+e^6 \left (2 e^4 x^2-8 e^2 x^3\right )\right ) \log ^3(x)-e^{10} x^3 \log ^4(x)}{\left (e^4 x+e^3 \left (2 e^4 x-8 e^2 x^2\right )+e^6 \left (e^4 x-8 e^2 x^2+16 x^3\right )\right ) \log ^2(x)+\left (-2 e^7 x^2+e^6 \left (-2 e^4 x^2+8 e^2 x^3\right )\right ) \log ^3(x)+e^{10} x^3 \log ^4(x)} \, dx=-\frac {x^{2} e^{3} \log \left (x\right )^{2} + {\left (4 \, x^{2} e - x e^{3} - x\right )} \log \left (x\right ) + 5 \, e^{3}}{x e^{3} \log \left (x\right )^{2} + {\left (4 \, x e - e^{3} - 1\right )} \log \left (x\right )} \]
integrate((-x^3*exp(2)^2*exp(3)^2*log(x)^4+((2*x^2*exp(2)^2-8*x^3*exp(2))* exp(3)^2+2*x^2*exp(2)^2*exp(3))*log(x)^3+((4*x*exp(2)^2+8*x^2*exp(2)-16*x^ 3)*exp(3)^2+(-2*x*exp(2)^2+8*x^2*exp(2))*exp(3)-x*exp(2)^2)*log(x)^2+(10*x *exp(2)^2+20*exp(2)*x)*exp(3)^2*log(x)+(-5*exp(2)^2+20*exp(2)*x)*exp(3)^2- 5*exp(2)^2*exp(3))/(x^3*exp(2)^2*exp(3)^2*log(x)^4+((-2*x^2*exp(2)^2+8*x^3 *exp(2))*exp(3)^2-2*x^2*exp(2)^2*exp(3))*log(x)^3+((x*exp(2)^2-8*x^2*exp(2 )+16*x^3)*exp(3)^2+(2*x*exp(2)^2-8*x^2*exp(2))*exp(3)+x*exp(2)^2)*log(x)^2 ),x, algorithm=\
-(x^2*e^3*log(x)^2 + (4*x^2*e - x*e^3 - x)*log(x) + 5*e^3)/(x*e^3*log(x)^2 + (4*x*e - e^3 - 1)*log(x))
Time = 0.14 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.14 \[ \int \frac {-5 e^7+e^6 \left (-5 e^4+20 e^2 x\right )+e^6 \left (20 e^2 x+10 e^4 x\right ) \log (x)+\left (-e^4 x+e^3 \left (-2 e^4 x+8 e^2 x^2\right )+e^6 \left (4 e^4 x+8 e^2 x^2-16 x^3\right )\right ) \log ^2(x)+\left (2 e^7 x^2+e^6 \left (2 e^4 x^2-8 e^2 x^3\right )\right ) \log ^3(x)-e^{10} x^3 \log ^4(x)}{\left (e^4 x+e^3 \left (2 e^4 x-8 e^2 x^2\right )+e^6 \left (e^4 x-8 e^2 x^2+16 x^3\right )\right ) \log ^2(x)+\left (-2 e^7 x^2+e^6 \left (-2 e^4 x^2+8 e^2 x^3\right )\right ) \log ^3(x)+e^{10} x^3 \log ^4(x)} \, dx=- x - \frac {5 e^{3}}{x e^{3} \log {\left (x \right )}^{2} + \left (4 e x - e^{3} - 1\right ) \log {\left (x \right )}} \]
integrate((-x**3*exp(2)**2*exp(3)**2*ln(x)**4+((2*x**2*exp(2)**2-8*x**3*ex p(2))*exp(3)**2+2*x**2*exp(2)**2*exp(3))*ln(x)**3+((4*x*exp(2)**2+8*x**2*e xp(2)-16*x**3)*exp(3)**2+(-2*x*exp(2)**2+8*x**2*exp(2))*exp(3)-x*exp(2)**2 )*ln(x)**2+(10*x*exp(2)**2+20*exp(2)*x)*exp(3)**2*ln(x)+(-5*exp(2)**2+20*e xp(2)*x)*exp(3)**2-5*exp(2)**2*exp(3))/(x**3*exp(2)**2*exp(3)**2*ln(x)**4+ ((-2*x**2*exp(2)**2+8*x**3*exp(2))*exp(3)**2-2*x**2*exp(2)**2*exp(3))*ln(x )**3+((x*exp(2)**2-8*x**2*exp(2)+16*x**3)*exp(3)**2+(2*x*exp(2)**2-8*x**2* exp(2))*exp(3)+x*exp(2)**2)*ln(x)**2),x)
Leaf count of result is larger than twice the leaf count of optimal. 60 vs. \(2 (27) = 54\).
Time = 0.28 (sec) , antiderivative size = 60, normalized size of antiderivative = 2.14 \[ \int \frac {-5 e^7+e^6 \left (-5 e^4+20 e^2 x\right )+e^6 \left (20 e^2 x+10 e^4 x\right ) \log (x)+\left (-e^4 x+e^3 \left (-2 e^4 x+8 e^2 x^2\right )+e^6 \left (4 e^4 x+8 e^2 x^2-16 x^3\right )\right ) \log ^2(x)+\left (2 e^7 x^2+e^6 \left (2 e^4 x^2-8 e^2 x^3\right )\right ) \log ^3(x)-e^{10} x^3 \log ^4(x)}{\left (e^4 x+e^3 \left (2 e^4 x-8 e^2 x^2\right )+e^6 \left (e^4 x-8 e^2 x^2+16 x^3\right )\right ) \log ^2(x)+\left (-2 e^7 x^2+e^6 \left (-2 e^4 x^2+8 e^2 x^3\right )\right ) \log ^3(x)+e^{10} x^3 \log ^4(x)} \, dx=-\frac {x^{2} e^{3} \log \left (x\right )^{2} + {\left (4 \, x^{2} e - x {\left (e^{3} + 1\right )}\right )} \log \left (x\right ) + 5 \, e^{3}}{x e^{3} \log \left (x\right )^{2} + {\left (4 \, x e - e^{3} - 1\right )} \log \left (x\right )} \]
integrate((-x^3*exp(2)^2*exp(3)^2*log(x)^4+((2*x^2*exp(2)^2-8*x^3*exp(2))* exp(3)^2+2*x^2*exp(2)^2*exp(3))*log(x)^3+((4*x*exp(2)^2+8*x^2*exp(2)-16*x^ 3)*exp(3)^2+(-2*x*exp(2)^2+8*x^2*exp(2))*exp(3)-x*exp(2)^2)*log(x)^2+(10*x *exp(2)^2+20*exp(2)*x)*exp(3)^2*log(x)+(-5*exp(2)^2+20*exp(2)*x)*exp(3)^2- 5*exp(2)^2*exp(3))/(x^3*exp(2)^2*exp(3)^2*log(x)^4+((-2*x^2*exp(2)^2+8*x^3 *exp(2))*exp(3)^2-2*x^2*exp(2)^2*exp(3))*log(x)^3+((x*exp(2)^2-8*x^2*exp(2 )+16*x^3)*exp(3)^2+(2*x*exp(2)^2-8*x^2*exp(2))*exp(3)+x*exp(2)^2)*log(x)^2 ),x, algorithm=\
-(x^2*e^3*log(x)^2 + (4*x^2*e - x*(e^3 + 1))*log(x) + 5*e^3)/(x*e^3*log(x) ^2 + (4*x*e - e^3 - 1)*log(x))
Leaf count of result is larger than twice the leaf count of optimal. 66 vs. \(2 (27) = 54\).
Time = 0.44 (sec) , antiderivative size = 66, normalized size of antiderivative = 2.36 \[ \int \frac {-5 e^7+e^6 \left (-5 e^4+20 e^2 x\right )+e^6 \left (20 e^2 x+10 e^4 x\right ) \log (x)+\left (-e^4 x+e^3 \left (-2 e^4 x+8 e^2 x^2\right )+e^6 \left (4 e^4 x+8 e^2 x^2-16 x^3\right )\right ) \log ^2(x)+\left (2 e^7 x^2+e^6 \left (2 e^4 x^2-8 e^2 x^3\right )\right ) \log ^3(x)-e^{10} x^3 \log ^4(x)}{\left (e^4 x+e^3 \left (2 e^4 x-8 e^2 x^2\right )+e^6 \left (e^4 x-8 e^2 x^2+16 x^3\right )\right ) \log ^2(x)+\left (-2 e^7 x^2+e^6 \left (-2 e^4 x^2+8 e^2 x^3\right )\right ) \log ^3(x)+e^{10} x^3 \log ^4(x)} \, dx=-\frac {x^{2} e^{3} \log \left (x\right )^{2} + 4 \, x^{2} e \log \left (x\right ) - x e^{3} \log \left (x\right ) - x \log \left (x\right ) + 5 \, e^{3}}{x e^{3} \log \left (x\right )^{2} + 4 \, x e \log \left (x\right ) - e^{3} \log \left (x\right ) - \log \left (x\right )} \]
integrate((-x^3*exp(2)^2*exp(3)^2*log(x)^4+((2*x^2*exp(2)^2-8*x^3*exp(2))* exp(3)^2+2*x^2*exp(2)^2*exp(3))*log(x)^3+((4*x*exp(2)^2+8*x^2*exp(2)-16*x^ 3)*exp(3)^2+(-2*x*exp(2)^2+8*x^2*exp(2))*exp(3)-x*exp(2)^2)*log(x)^2+(10*x *exp(2)^2+20*exp(2)*x)*exp(3)^2*log(x)+(-5*exp(2)^2+20*exp(2)*x)*exp(3)^2- 5*exp(2)^2*exp(3))/(x^3*exp(2)^2*exp(3)^2*log(x)^4+((-2*x^2*exp(2)^2+8*x^3 *exp(2))*exp(3)^2-2*x^2*exp(2)^2*exp(3))*log(x)^3+((x*exp(2)^2-8*x^2*exp(2 )+16*x^3)*exp(3)^2+(2*x*exp(2)^2-8*x^2*exp(2))*exp(3)+x*exp(2)^2)*log(x)^2 ),x, algorithm=\
-(x^2*e^3*log(x)^2 + 4*x^2*e*log(x) - x*e^3*log(x) - x*log(x) + 5*e^3)/(x* e^3*log(x)^2 + 4*x*e*log(x) - e^3*log(x) - log(x))
Time = 14.17 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.21 \[ \int \frac {-5 e^7+e^6 \left (-5 e^4+20 e^2 x\right )+e^6 \left (20 e^2 x+10 e^4 x\right ) \log (x)+\left (-e^4 x+e^3 \left (-2 e^4 x+8 e^2 x^2\right )+e^6 \left (4 e^4 x+8 e^2 x^2-16 x^3\right )\right ) \log ^2(x)+\left (2 e^7 x^2+e^6 \left (2 e^4 x^2-8 e^2 x^3\right )\right ) \log ^3(x)-e^{10} x^3 \log ^4(x)}{\left (e^4 x+e^3 \left (2 e^4 x-8 e^2 x^2\right )+e^6 \left (e^4 x-8 e^2 x^2+16 x^3\right )\right ) \log ^2(x)+\left (-2 e^7 x^2+e^6 \left (-2 e^4 x^2+8 e^2 x^3\right )\right ) \log ^3(x)+e^{10} x^3 \log ^4(x)} \, dx=-x-\frac {5}{x\,\left ({\ln \left (x\right )}^2-\frac {{\mathrm {e}}^{-3}\,\ln \left (x\right )\,\left ({\mathrm {e}}^3-4\,x\,\mathrm {e}+1\right )}{x}\right )} \]
int(-(5*exp(7) + exp(6)*(5*exp(4) - 20*x*exp(2)) + log(x)^2*(x*exp(4) - ex p(6)*(4*x*exp(4) + 8*x^2*exp(2) - 16*x^3) + exp(3)*(2*x*exp(4) - 8*x^2*exp (2))) + log(x)^3*(exp(6)*(8*x^3*exp(2) - 2*x^2*exp(4)) - 2*x^2*exp(7)) - e xp(6)*log(x)*(20*x*exp(2) + 10*x*exp(4)) + x^3*exp(10)*log(x)^4)/(log(x)^2 *(exp(6)*(x*exp(4) - 8*x^2*exp(2) + 16*x^3) + x*exp(4) + exp(3)*(2*x*exp(4 ) - 8*x^2*exp(2))) + log(x)^3*(exp(6)*(8*x^3*exp(2) - 2*x^2*exp(4)) - 2*x^ 2*exp(7)) + x^3*exp(10)*log(x)^4),x)