3.23.80 \(\int \frac {(32 x^3-32 x^4 \log (x)) \log (-4+x-\log (\log (x)))+((256 x^3-64 x^4) \log (x)+64 x^3 \log (x) \log (\log (x))) \log ^2(-4+x-\log (\log (x)))}{(4-x) \log (x)+\log (x) \log (\log (x))} \, dx\) [2280]

3.23.80.1 Optimal result
3.23.80.2 Mathematica [F]
3.23.80.3 Rubi [F]
3.23.80.4 Maple [A] (verified)
3.23.80.5 Fricas [A] (verification not implemented)
3.23.80.6 Sympy [A] (verification not implemented)
3.23.80.7 Maxima [A] (verification not implemented)
3.23.80.8 Giac [A] (verification not implemented)
3.23.80.9 Mupad [B] (verification not implemented)

3.23.80.1 Optimal result

Integrand size = 79, antiderivative size = 16 \[ \int \frac {\left (32 x^3-32 x^4 \log (x)\right ) \log (-4+x-\log (\log (x)))+\left (\left (256 x^3-64 x^4\right ) \log (x)+64 x^3 \log (x) \log (\log (x))\right ) \log ^2(-4+x-\log (\log (x)))}{(4-x) \log (x)+\log (x) \log (\log (x))} \, dx=16 x^4 \log ^2(-4+x-\log (\log (x))) \]

output
16*x^4*ln(-ln(ln(x))+x-4)^2
 
3.23.80.2 Mathematica [F]

\[ \int \frac {\left (32 x^3-32 x^4 \log (x)\right ) \log (-4+x-\log (\log (x)))+\left (\left (256 x^3-64 x^4\right ) \log (x)+64 x^3 \log (x) \log (\log (x))\right ) \log ^2(-4+x-\log (\log (x)))}{(4-x) \log (x)+\log (x) \log (\log (x))} \, dx=\int \frac {\left (32 x^3-32 x^4 \log (x)\right ) \log (-4+x-\log (\log (x)))+\left (\left (256 x^3-64 x^4\right ) \log (x)+64 x^3 \log (x) \log (\log (x))\right ) \log ^2(-4+x-\log (\log (x)))}{(4-x) \log (x)+\log (x) \log (\log (x))} \, dx \]

input
Integrate[((32*x^3 - 32*x^4*Log[x])*Log[-4 + x - Log[Log[x]]] + ((256*x^3 
- 64*x^4)*Log[x] + 64*x^3*Log[x]*Log[Log[x]])*Log[-4 + x - Log[Log[x]]]^2) 
/((4 - x)*Log[x] + Log[x]*Log[Log[x]]),x]
 
output
Integrate[((32*x^3 - 32*x^4*Log[x])*Log[-4 + x - Log[Log[x]]] + ((256*x^3 
- 64*x^4)*Log[x] + 64*x^3*Log[x]*Log[Log[x]])*Log[-4 + x - Log[Log[x]]]^2) 
/((4 - x)*Log[x] + Log[x]*Log[Log[x]]), x]
 
3.23.80.3 Rubi [F]

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\left (64 x^3 \log (x) \log (\log (x))+\left (256 x^3-64 x^4\right ) \log (x)\right ) \log ^2(x-\log (\log (x))-4)+\left (32 x^3-32 x^4 \log (x)\right ) \log (x-\log (\log (x))-4)}{(4-x) \log (x)+\log (\log (x)) \log (x)} \, dx\)

\(\Big \downarrow \) 7292

\(\displaystyle \int \frac {32 x^3 \log (x-\log (\log (x))-4) (-x \log (x)-2 x \log (x-\log (\log (x))-4) \log (x)+2 \log (\log (x)) \log (x-\log (\log (x))-4) \log (x)+8 \log (x-\log (\log (x))-4) \log (x)+1)}{\log (x) (-x+\log (\log (x))+4)}dx\)

\(\Big \downarrow \) 27

\(\displaystyle 32 \int \frac {x^3 \log (x-\log (\log (x))-4) (-x \log (x)-2 x \log (x-\log (\log (x))-4) \log (x)+2 \log (\log (x)) \log (x-\log (\log (x))-4) \log (x)+8 \log (x-\log (\log (x))-4) \log (x)+1)}{\log (x) (-x+\log (\log (x))+4)}dx\)

\(\Big \downarrow \) 7239

\(\displaystyle 32 \int \frac {x^3 \log (x-\log (\log (x))-4) (1-\log (x) (x+2 (x-\log (\log (x))-4) \log (x-\log (\log (x))-4)))}{\log (x) (-x+\log (\log (x))+4)}dx\)

\(\Big \downarrow \) 7293

\(\displaystyle 32 \int \left (2 \log ^2(x-\log (\log (x))-4) x^3+\frac {(x \log (x)-1) \log (x-\log (\log (x))-4) x^3}{\log (x) (x-\log (\log (x))-4)}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle 32 \left (\int \frac {x^4 \log (x-\log (\log (x))-4)}{x-\log (\log (x))-4}dx+2 \int x^3 \log ^2(x-\log (\log (x))-4)dx-\int \frac {x^3 \log (x-\log (\log (x))-4)}{\log (x) (x-\log (\log (x))-4)}dx\right )\)

input
Int[((32*x^3 - 32*x^4*Log[x])*Log[-4 + x - Log[Log[x]]] + ((256*x^3 - 64*x 
^4)*Log[x] + 64*x^3*Log[x]*Log[Log[x]])*Log[-4 + x - Log[Log[x]]]^2)/((4 - 
 x)*Log[x] + Log[x]*Log[Log[x]]),x]
 
output
$Aborted
 

3.23.80.3.1 Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 7239
Int[u_, x_Symbol] :> With[{v = SimplifyIntegrand[u, x]}, Int[v, x] /; Simpl 
erIntegrandQ[v, u, x]]
 

rule 7292
Int[u_, x_Symbol] :> With[{v = NormalizeIntegrand[u, x]}, Int[v, x] /; v =! 
= u]
 

rule 7293
Int[u_, x_Symbol] :> With[{v = ExpandIntegrand[u, x]}, Int[v, x] /; SumQ[v] 
]
 
3.23.80.4 Maple [A] (verified)

Time = 2.88 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.06

method result size
risch \(16 x^{4} \ln \left (-\ln \left (\ln \left (x \right )\right )+x -4\right )^{2}\) \(17\)
parallelrisch \(16 x^{4} \ln \left (-\ln \left (\ln \left (x \right )\right )+x -4\right )^{2}\) \(17\)

input
int(((64*x^3*ln(x)*ln(ln(x))+(-64*x^4+256*x^3)*ln(x))*ln(-ln(ln(x))+x-4)^2 
+(-32*x^4*ln(x)+32*x^3)*ln(-ln(ln(x))+x-4))/(ln(x)*ln(ln(x))+(-x+4)*ln(x)) 
,x,method=_RETURNVERBOSE)
 
output
16*x^4*ln(-ln(ln(x))+x-4)^2
 
3.23.80.5 Fricas [A] (verification not implemented)

Time = 0.24 (sec) , antiderivative size = 16, normalized size of antiderivative = 1.00 \[ \int \frac {\left (32 x^3-32 x^4 \log (x)\right ) \log (-4+x-\log (\log (x)))+\left (\left (256 x^3-64 x^4\right ) \log (x)+64 x^3 \log (x) \log (\log (x))\right ) \log ^2(-4+x-\log (\log (x)))}{(4-x) \log (x)+\log (x) \log (\log (x))} \, dx=16 \, x^{4} \log \left (x - \log \left (\log \left (x\right )\right ) - 4\right )^{2} \]

input
integrate(((64*x^3*log(x)*log(log(x))+(-64*x^4+256*x^3)*log(x))*log(-log(l 
og(x))+x-4)^2+(-32*x^4*log(x)+32*x^3)*log(-log(log(x))+x-4))/(log(x)*log(l 
og(x))+(-x+4)*log(x)),x, algorithm=\
 
output
16*x^4*log(x - log(log(x)) - 4)^2
 
3.23.80.6 Sympy [A] (verification not implemented)

Time = 0.44 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.94 \[ \int \frac {\left (32 x^3-32 x^4 \log (x)\right ) \log (-4+x-\log (\log (x)))+\left (\left (256 x^3-64 x^4\right ) \log (x)+64 x^3 \log (x) \log (\log (x))\right ) \log ^2(-4+x-\log (\log (x)))}{(4-x) \log (x)+\log (x) \log (\log (x))} \, dx=16 x^{4} \log {\left (x - \log {\left (\log {\left (x \right )} \right )} - 4 \right )}^{2} \]

input
integrate(((64*x**3*ln(x)*ln(ln(x))+(-64*x**4+256*x**3)*ln(x))*ln(-ln(ln(x 
))+x-4)**2+(-32*x**4*ln(x)+32*x**3)*ln(-ln(ln(x))+x-4))/(ln(x)*ln(ln(x))+( 
-x+4)*ln(x)),x)
 
output
16*x**4*log(x - log(log(x)) - 4)**2
 
3.23.80.7 Maxima [A] (verification not implemented)

Time = 0.23 (sec) , antiderivative size = 16, normalized size of antiderivative = 1.00 \[ \int \frac {\left (32 x^3-32 x^4 \log (x)\right ) \log (-4+x-\log (\log (x)))+\left (\left (256 x^3-64 x^4\right ) \log (x)+64 x^3 \log (x) \log (\log (x))\right ) \log ^2(-4+x-\log (\log (x)))}{(4-x) \log (x)+\log (x) \log (\log (x))} \, dx=16 \, x^{4} \log \left (x - \log \left (\log \left (x\right )\right ) - 4\right )^{2} \]

input
integrate(((64*x^3*log(x)*log(log(x))+(-64*x^4+256*x^3)*log(x))*log(-log(l 
og(x))+x-4)^2+(-32*x^4*log(x)+32*x^3)*log(-log(log(x))+x-4))/(log(x)*log(l 
og(x))+(-x+4)*log(x)),x, algorithm=\
 
output
16*x^4*log(x - log(log(x)) - 4)^2
 
3.23.80.8 Giac [A] (verification not implemented)

Time = 0.38 (sec) , antiderivative size = 16, normalized size of antiderivative = 1.00 \[ \int \frac {\left (32 x^3-32 x^4 \log (x)\right ) \log (-4+x-\log (\log (x)))+\left (\left (256 x^3-64 x^4\right ) \log (x)+64 x^3 \log (x) \log (\log (x))\right ) \log ^2(-4+x-\log (\log (x)))}{(4-x) \log (x)+\log (x) \log (\log (x))} \, dx=16 \, x^{4} \log \left (x - \log \left (\log \left (x\right )\right ) - 4\right )^{2} \]

input
integrate(((64*x^3*log(x)*log(log(x))+(-64*x^4+256*x^3)*log(x))*log(-log(l 
og(x))+x-4)^2+(-32*x^4*log(x)+32*x^3)*log(-log(log(x))+x-4))/(log(x)*log(l 
og(x))+(-x+4)*log(x)),x, algorithm=\
 
output
16*x^4*log(x - log(log(x)) - 4)^2
 
3.23.80.9 Mupad [B] (verification not implemented)

Time = 14.22 (sec) , antiderivative size = 16, normalized size of antiderivative = 1.00 \[ \int \frac {\left (32 x^3-32 x^4 \log (x)\right ) \log (-4+x-\log (\log (x)))+\left (\left (256 x^3-64 x^4\right ) \log (x)+64 x^3 \log (x) \log (\log (x))\right ) \log ^2(-4+x-\log (\log (x)))}{(4-x) \log (x)+\log (x) \log (\log (x))} \, dx=16\,x^4\,{\ln \left (x-\ln \left (\ln \left (x\right )\right )-4\right )}^2 \]

input
int((log(x - log(log(x)) - 4)*(32*x^4*log(x) - 32*x^3) - log(x - log(log(x 
)) - 4)^2*(log(x)*(256*x^3 - 64*x^4) + 64*x^3*log(log(x))*log(x)))/(log(x) 
*(x - 4) - log(log(x))*log(x)),x)
 
output
16*x^4*log(x - log(log(x)) - 4)^2