3.26.16 \(\int \frac {-5 x+6 x^3-x^3 \log (x)+(-30 x+5 x \log (x)) \log (6-\log (x))+(-12 x^3+2 x^3 \log (x)+(-60 x+10 x \log (x)) \log (6-\log (x))) \log (\frac {x^2+5 \log (6-\log (x))}{x})}{(-6 x^2+x^2 \log (x)+(-30+5 \log (x)) \log (6-\log (x))) \log ^2(\frac {x^2+5 \log (6-\log (x))}{x})} \, dx\) [2516]

3.26.16.1 Optimal result
3.26.16.2 Mathematica [A] (verified)
3.26.16.3 Rubi [F]
3.26.16.4 Maple [A] (verified)
3.26.16.5 Fricas [A] (verification not implemented)
3.26.16.6 Sympy [A] (verification not implemented)
3.26.16.7 Maxima [A] (verification not implemented)
3.26.16.8 Giac [A] (verification not implemented)
3.26.16.9 Mupad [F(-1)]

3.26.16.1 Optimal result

Integrand size = 131, antiderivative size = 21 \[ \int \frac {-5 x+6 x^3-x^3 \log (x)+(-30 x+5 x \log (x)) \log (6-\log (x))+\left (-12 x^3+2 x^3 \log (x)+(-60 x+10 x \log (x)) \log (6-\log (x))\right ) \log \left (\frac {x^2+5 \log (6-\log (x))}{x}\right )}{\left (-6 x^2+x^2 \log (x)+(-30+5 \log (x)) \log (6-\log (x))\right ) \log ^2\left (\frac {x^2+5 \log (6-\log (x))}{x}\right )} \, dx=\frac {x^2}{\log \left (x+\frac {5 \log (6-\log (x))}{x}\right )} \]

output
x^2/ln(5*ln(-ln(x)+6)/x+x)
 
3.26.16.2 Mathematica [A] (verified)

Time = 0.11 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.00 \[ \int \frac {-5 x+6 x^3-x^3 \log (x)+(-30 x+5 x \log (x)) \log (6-\log (x))+\left (-12 x^3+2 x^3 \log (x)+(-60 x+10 x \log (x)) \log (6-\log (x))\right ) \log \left (\frac {x^2+5 \log (6-\log (x))}{x}\right )}{\left (-6 x^2+x^2 \log (x)+(-30+5 \log (x)) \log (6-\log (x))\right ) \log ^2\left (\frac {x^2+5 \log (6-\log (x))}{x}\right )} \, dx=\frac {x^2}{\log \left (x+\frac {5 \log (6-\log (x))}{x}\right )} \]

input
Integrate[(-5*x + 6*x^3 - x^3*Log[x] + (-30*x + 5*x*Log[x])*Log[6 - Log[x] 
] + (-12*x^3 + 2*x^3*Log[x] + (-60*x + 10*x*Log[x])*Log[6 - Log[x]])*Log[( 
x^2 + 5*Log[6 - Log[x]])/x])/((-6*x^2 + x^2*Log[x] + (-30 + 5*Log[x])*Log[ 
6 - Log[x]])*Log[(x^2 + 5*Log[6 - Log[x]])/x]^2),x]
 
output
x^2/Log[x + (5*Log[6 - Log[x]])/x]
 
3.26.16.3 Rubi [F]

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {6 x^3+x^3 (-\log (x))+\left (-12 x^3+2 x^3 \log (x)+(10 x \log (x)-60 x) \log (6-\log (x))\right ) \log \left (\frac {x^2+5 \log (6-\log (x))}{x}\right )-5 x+(5 x \log (x)-30 x) \log (6-\log (x))}{\left (-6 x^2+x^2 \log (x)+(5 \log (x)-30) \log (6-\log (x))\right ) \log ^2\left (\frac {x^2+5 \log (6-\log (x))}{x}\right )} \, dx\)

\(\Big \downarrow \) 7292

\(\displaystyle \int \frac {-6 x^3+x^3 \log (x)-\left (-12 x^3+2 x^3 \log (x)+(10 x \log (x)-60 x) \log (6-\log (x))\right ) \log \left (\frac {x^2+5 \log (6-\log (x))}{x}\right )+5 x-(5 x \log (x)-30 x) \log (6-\log (x))}{(6-\log (x)) \left (x^2+5 \log (6-\log (x))\right ) \log ^2\left (x+\frac {5 \log (6-\log (x))}{x}\right )}dx\)

\(\Big \downarrow \) 7293

\(\displaystyle \int \left (\frac {5 x \log (x) \log (6-\log (x))}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log ^2\left (x+\frac {5 \log (6-\log (x))}{x}\right )}-\frac {30 x \log (6-\log (x))}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log ^2\left (x+\frac {5 \log (6-\log (x))}{x}\right )}-\frac {5 x}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log ^2\left (x+\frac {5 \log (6-\log (x))}{x}\right )}+\frac {10 x \log (x) \log (6-\log (x))}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log \left (x+\frac {5 \log (6-\log (x))}{x}\right )}-\frac {60 x \log (6-\log (x))}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log \left (x+\frac {5 \log (6-\log (x))}{x}\right )}-\frac {x^3 \log (x)}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log ^2\left (x+\frac {5 \log (6-\log (x))}{x}\right )}+\frac {6 x^3}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log ^2\left (x+\frac {5 \log (6-\log (x))}{x}\right )}+\frac {2 x^3 \log (x)}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log \left (x+\frac {5 \log (6-\log (x))}{x}\right )}-\frac {12 x^3}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log \left (x+\frac {5 \log (6-\log (x))}{x}\right )}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle -5 \int \frac {x}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log ^2\left (x+\frac {5 \log (6-\log (x))}{x}\right )}dx-30 \int \frac {x \log (6-\log (x))}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log ^2\left (x+\frac {5 \log (6-\log (x))}{x}\right )}dx+5 \int \frac {x \log (x) \log (6-\log (x))}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log ^2\left (x+\frac {5 \log (6-\log (x))}{x}\right )}dx-60 \int \frac {x \log (6-\log (x))}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log \left (x+\frac {5 \log (6-\log (x))}{x}\right )}dx+10 \int \frac {x \log (x) \log (6-\log (x))}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log \left (x+\frac {5 \log (6-\log (x))}{x}\right )}dx+6 \int \frac {x^3}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log ^2\left (x+\frac {5 \log (6-\log (x))}{x}\right )}dx-\int \frac {x^3 \log (x)}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log ^2\left (x+\frac {5 \log (6-\log (x))}{x}\right )}dx-12 \int \frac {x^3}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log \left (x+\frac {5 \log (6-\log (x))}{x}\right )}dx+2 \int \frac {x^3 \log (x)}{(\log (x)-6) \left (x^2+5 \log (6-\log (x))\right ) \log \left (x+\frac {5 \log (6-\log (x))}{x}\right )}dx\)

input
Int[(-5*x + 6*x^3 - x^3*Log[x] + (-30*x + 5*x*Log[x])*Log[6 - Log[x]] + (- 
12*x^3 + 2*x^3*Log[x] + (-60*x + 10*x*Log[x])*Log[6 - Log[x]])*Log[(x^2 + 
5*Log[6 - Log[x]])/x])/((-6*x^2 + x^2*Log[x] + (-30 + 5*Log[x])*Log[6 - Lo 
g[x]])*Log[(x^2 + 5*Log[6 - Log[x]])/x]^2),x]
 
output
$Aborted
 

3.26.16.3.1 Defintions of rubi rules used

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 7292
Int[u_, x_Symbol] :> With[{v = NormalizeIntegrand[u, x]}, Int[v, x] /; v =! 
= u]
 

rule 7293
Int[u_, x_Symbol] :> With[{v = ExpandIntegrand[u, x]}, Int[v, x] /; SumQ[v] 
]
 
3.26.16.4 Maple [A] (verified)

Time = 11.98 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.19

method result size
parallelrisch \(\frac {x^{2}}{\ln \left (\frac {5 \ln \left (-\ln \left (x \right )+6\right )+x^{2}}{x}\right )}\) \(25\)
risch \(-\frac {2 i x^{2}}{\pi \,\operatorname {csgn}\left (i \left (5 \ln \left (-\ln \left (x \right )+6\right )+x^{2}\right )\right ) {\operatorname {csgn}\left (\frac {i \left (5 \ln \left (-\ln \left (x \right )+6\right )+x^{2}\right )}{x}\right )}^{2}-\pi \,\operatorname {csgn}\left (i \left (5 \ln \left (-\ln \left (x \right )+6\right )+x^{2}\right )\right ) \operatorname {csgn}\left (\frac {i}{x}\right ) \operatorname {csgn}\left (\frac {i \left (5 \ln \left (-\ln \left (x \right )+6\right )+x^{2}\right )}{x}\right )-\pi {\operatorname {csgn}\left (\frac {i \left (5 \ln \left (-\ln \left (x \right )+6\right )+x^{2}\right )}{x}\right )}^{3}+\pi \,\operatorname {csgn}\left (\frac {i}{x}\right ) {\operatorname {csgn}\left (\frac {i \left (5 \ln \left (-\ln \left (x \right )+6\right )+x^{2}\right )}{x}\right )}^{2}+2 i \ln \left (x \right )-2 i \ln \left (5 \ln \left (-\ln \left (x \right )+6\right )+x^{2}\right )}\) \(176\)

input
int((((10*x*ln(x)-60*x)*ln(-ln(x)+6)+2*x^3*ln(x)-12*x^3)*ln((5*ln(-ln(x)+6 
)+x^2)/x)+(5*x*ln(x)-30*x)*ln(-ln(x)+6)-x^3*ln(x)+6*x^3-5*x)/((5*ln(x)-30) 
*ln(-ln(x)+6)+x^2*ln(x)-6*x^2)/ln((5*ln(-ln(x)+6)+x^2)/x)^2,x,method=_RETU 
RNVERBOSE)
 
output
x^2/ln((5*ln(-ln(x)+6)+x^2)/x)
 
3.26.16.5 Fricas [A] (verification not implemented)

Time = 0.25 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.14 \[ \int \frac {-5 x+6 x^3-x^3 \log (x)+(-30 x+5 x \log (x)) \log (6-\log (x))+\left (-12 x^3+2 x^3 \log (x)+(-60 x+10 x \log (x)) \log (6-\log (x))\right ) \log \left (\frac {x^2+5 \log (6-\log (x))}{x}\right )}{\left (-6 x^2+x^2 \log (x)+(-30+5 \log (x)) \log (6-\log (x))\right ) \log ^2\left (\frac {x^2+5 \log (6-\log (x))}{x}\right )} \, dx=\frac {x^{2}}{\log \left (\frac {x^{2} + 5 \, \log \left (-\log \left (x\right ) + 6\right )}{x}\right )} \]

input
integrate((((10*x*log(x)-60*x)*log(-log(x)+6)+2*x^3*log(x)-12*x^3)*log((5* 
log(-log(x)+6)+x^2)/x)+(5*x*log(x)-30*x)*log(-log(x)+6)-x^3*log(x)+6*x^3-5 
*x)/((5*log(x)-30)*log(-log(x)+6)+x^2*log(x)-6*x^2)/log((5*log(-log(x)+6)+ 
x^2)/x)^2,x, algorithm=\
 
output
x^2/log((x^2 + 5*log(-log(x) + 6))/x)
 
3.26.16.6 Sympy [A] (verification not implemented)

Time = 0.44 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.81 \[ \int \frac {-5 x+6 x^3-x^3 \log (x)+(-30 x+5 x \log (x)) \log (6-\log (x))+\left (-12 x^3+2 x^3 \log (x)+(-60 x+10 x \log (x)) \log (6-\log (x))\right ) \log \left (\frac {x^2+5 \log (6-\log (x))}{x}\right )}{\left (-6 x^2+x^2 \log (x)+(-30+5 \log (x)) \log (6-\log (x))\right ) \log ^2\left (\frac {x^2+5 \log (6-\log (x))}{x}\right )} \, dx=\frac {x^{2}}{\log {\left (\frac {x^{2} + 5 \log {\left (6 - \log {\left (x \right )} \right )}}{x} \right )}} \]

input
integrate((((10*x*ln(x)-60*x)*ln(-ln(x)+6)+2*x**3*ln(x)-12*x**3)*ln((5*ln( 
-ln(x)+6)+x**2)/x)+(5*x*ln(x)-30*x)*ln(-ln(x)+6)-x**3*ln(x)+6*x**3-5*x)/(( 
5*ln(x)-30)*ln(-ln(x)+6)+x**2*ln(x)-6*x**2)/ln((5*ln(-ln(x)+6)+x**2)/x)**2 
,x)
 
output
x**2/log((x**2 + 5*log(6 - log(x)))/x)
 
3.26.16.7 Maxima [A] (verification not implemented)

Time = 0.26 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.19 \[ \int \frac {-5 x+6 x^3-x^3 \log (x)+(-30 x+5 x \log (x)) \log (6-\log (x))+\left (-12 x^3+2 x^3 \log (x)+(-60 x+10 x \log (x)) \log (6-\log (x))\right ) \log \left (\frac {x^2+5 \log (6-\log (x))}{x}\right )}{\left (-6 x^2+x^2 \log (x)+(-30+5 \log (x)) \log (6-\log (x))\right ) \log ^2\left (\frac {x^2+5 \log (6-\log (x))}{x}\right )} \, dx=\frac {x^{2}}{\log \left (x^{2} + 5 \, \log \left (-\log \left (x\right ) + 6\right )\right ) - \log \left (x\right )} \]

input
integrate((((10*x*log(x)-60*x)*log(-log(x)+6)+2*x^3*log(x)-12*x^3)*log((5* 
log(-log(x)+6)+x^2)/x)+(5*x*log(x)-30*x)*log(-log(x)+6)-x^3*log(x)+6*x^3-5 
*x)/((5*log(x)-30)*log(-log(x)+6)+x^2*log(x)-6*x^2)/log((5*log(-log(x)+6)+ 
x^2)/x)^2,x, algorithm=\
 
output
x^2/(log(x^2 + 5*log(-log(x) + 6)) - log(x))
 
3.26.16.8 Giac [A] (verification not implemented)

Time = 0.41 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.19 \[ \int \frac {-5 x+6 x^3-x^3 \log (x)+(-30 x+5 x \log (x)) \log (6-\log (x))+\left (-12 x^3+2 x^3 \log (x)+(-60 x+10 x \log (x)) \log (6-\log (x))\right ) \log \left (\frac {x^2+5 \log (6-\log (x))}{x}\right )}{\left (-6 x^2+x^2 \log (x)+(-30+5 \log (x)) \log (6-\log (x))\right ) \log ^2\left (\frac {x^2+5 \log (6-\log (x))}{x}\right )} \, dx=\frac {x^{2}}{\log \left (x^{2} + 5 \, \log \left (-\log \left (x\right ) + 6\right )\right ) - \log \left (x\right )} \]

input
integrate((((10*x*log(x)-60*x)*log(-log(x)+6)+2*x^3*log(x)-12*x^3)*log((5* 
log(-log(x)+6)+x^2)/x)+(5*x*log(x)-30*x)*log(-log(x)+6)-x^3*log(x)+6*x^3-5 
*x)/((5*log(x)-30)*log(-log(x)+6)+x^2*log(x)-6*x^2)/log((5*log(-log(x)+6)+ 
x^2)/x)^2,x, algorithm=\
 
output
x^2/(log(x^2 + 5*log(-log(x) + 6)) - log(x))
 
3.26.16.9 Mupad [F(-1)]

Timed out. \[ \int \frac {-5 x+6 x^3-x^3 \log (x)+(-30 x+5 x \log (x)) \log (6-\log (x))+\left (-12 x^3+2 x^3 \log (x)+(-60 x+10 x \log (x)) \log (6-\log (x))\right ) \log \left (\frac {x^2+5 \log (6-\log (x))}{x}\right )}{\left (-6 x^2+x^2 \log (x)+(-30+5 \log (x)) \log (6-\log (x))\right ) \log ^2\left (\frac {x^2+5 \log (6-\log (x))}{x}\right )} \, dx=-\int \frac {5\,x+x^3\,\ln \left (x\right )+\ln \left (6-\ln \left (x\right )\right )\,\left (30\,x-5\,x\,\ln \left (x\right )\right )+\ln \left (\frac {5\,\ln \left (6-\ln \left (x\right )\right )+x^2}{x}\right )\,\left (\ln \left (6-\ln \left (x\right )\right )\,\left (60\,x-10\,x\,\ln \left (x\right )\right )-2\,x^3\,\ln \left (x\right )+12\,x^3\right )-6\,x^3}{{\ln \left (\frac {5\,\ln \left (6-\ln \left (x\right )\right )+x^2}{x}\right )}^2\,\left (\ln \left (6-\ln \left (x\right )\right )\,\left (5\,\ln \left (x\right )-30\right )+x^2\,\ln \left (x\right )-6\,x^2\right )} \,d x \]

input
int(-(5*x + x^3*log(x) + log(6 - log(x))*(30*x - 5*x*log(x)) + log((5*log( 
6 - log(x)) + x^2)/x)*(log(6 - log(x))*(60*x - 10*x*log(x)) - 2*x^3*log(x) 
 + 12*x^3) - 6*x^3)/(log((5*log(6 - log(x)) + x^2)/x)^2*(log(6 - log(x))*( 
5*log(x) - 30) + x^2*log(x) - 6*x^2)),x)
 
output
-int((5*x + x^3*log(x) + log(6 - log(x))*(30*x - 5*x*log(x)) + log((5*log( 
6 - log(x)) + x^2)/x)*(log(6 - log(x))*(60*x - 10*x*log(x)) - 2*x^3*log(x) 
 + 12*x^3) - 6*x^3)/(log((5*log(6 - log(x)) + x^2)/x)^2*(log(6 - log(x))*( 
5*log(x) - 30) + x^2*log(x) - 6*x^2)), x)