3.10.31 \(\int \frac {21600+76375 x-23350 x^2+(-15000-61000 x+19400 x^2) \log (x)+(3600+18500 x-6200 x^2) \log ^2(x)+(-300-2500 x+900 x^2) \log ^3(x)+(125 x-50 x^2) \log ^4(x)}{312987 x-558144 x \log (x)+442632 x \log ^2(x)-203808 x \log ^3(x)+59586 x \log ^4(x)-11328 x \log ^5(x)+1368 x \log ^6(x)-96 x \log ^7(x)+3 x \log ^8(x)} \, dx\) [931]

3.10.31.1 Optimal result
3.10.31.2 Mathematica [A] (verified)
3.10.31.3 Rubi [F]
3.10.31.4 Maple [A] (verified)
3.10.31.5 Fricas [A] (verification not implemented)
3.10.31.6 Sympy [A] (verification not implemented)
3.10.31.7 Maxima [A] (verification not implemented)
3.10.31.8 Giac [A] (verification not implemented)
3.10.31.9 Mupad [B] (verification not implemented)

3.10.31.1 Optimal result

Integrand size = 128, antiderivative size = 30 \[ \int \frac {21600+76375 x-23350 x^2+\left (-15000-61000 x+19400 x^2\right ) \log (x)+\left (3600+18500 x-6200 x^2\right ) \log ^2(x)+\left (-300-2500 x+900 x^2\right ) \log ^3(x)+\left (125 x-50 x^2\right ) \log ^4(x)}{312987 x-558144 x \log (x)+442632 x \log ^2(x)-203808 x \log ^3(x)+59586 x \log ^4(x)-11328 x \log ^5(x)+1368 x \log ^6(x)-96 x \log ^7(x)+3 x \log ^8(x)} \, dx=\frac {25 \left (1+\frac {1}{3} (5-x) x\right )}{-1+\left (2+(4-\log (x))^2\right )^2} \]

output
25*(1+1/3*x*(5-x))/((2+(-ln(x)+4)^2)^2-1)
 
3.10.31.2 Mathematica [A] (verified)

Time = 0.05 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.20 \[ \int \frac {21600+76375 x-23350 x^2+\left (-15000-61000 x+19400 x^2\right ) \log (x)+\left (3600+18500 x-6200 x^2\right ) \log ^2(x)+\left (-300-2500 x+900 x^2\right ) \log ^3(x)+\left (125 x-50 x^2\right ) \log ^4(x)}{312987 x-558144 x \log (x)+442632 x \log ^2(x)-203808 x \log ^3(x)+59586 x \log ^4(x)-11328 x \log ^5(x)+1368 x \log ^6(x)-96 x \log ^7(x)+3 x \log ^8(x)} \, dx=-\frac {25 \left (-3-5 x+x^2\right )}{3 \left (323-288 \log (x)+100 \log ^2(x)-16 \log ^3(x)+\log ^4(x)\right )} \]

input
Integrate[(21600 + 76375*x - 23350*x^2 + (-15000 - 61000*x + 19400*x^2)*Lo 
g[x] + (3600 + 18500*x - 6200*x^2)*Log[x]^2 + (-300 - 2500*x + 900*x^2)*Lo 
g[x]^3 + (125*x - 50*x^2)*Log[x]^4)/(312987*x - 558144*x*Log[x] + 442632*x 
*Log[x]^2 - 203808*x*Log[x]^3 + 59586*x*Log[x]^4 - 11328*x*Log[x]^5 + 1368 
*x*Log[x]^6 - 96*x*Log[x]^7 + 3*x*Log[x]^8),x]
 
output
(-25*(-3 - 5*x + x^2))/(3*(323 - 288*Log[x] + 100*Log[x]^2 - 16*Log[x]^3 + 
 Log[x]^4))
 
3.10.31.3 Rubi [F]

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {-23350 x^2+\left (125 x-50 x^2\right ) \log ^4(x)+\left (900 x^2-2500 x-300\right ) \log ^3(x)+\left (-6200 x^2+18500 x+3600\right ) \log ^2(x)+\left (19400 x^2-61000 x-15000\right ) \log (x)+76375 x+21600}{312987 x+3 x \log ^8(x)-96 x \log ^7(x)+1368 x \log ^6(x)-11328 x \log ^5(x)+59586 x \log ^4(x)-203808 x \log ^3(x)+442632 x \log ^2(x)-558144 x \log (x)} \, dx\)

\(\Big \downarrow \) 7292

\(\displaystyle \int \frac {-23350 x^2+\left (125 x-50 x^2\right ) \log ^4(x)+\left (900 x^2-2500 x-300\right ) \log ^3(x)+\left (-6200 x^2+18500 x+3600\right ) \log ^2(x)+\left (19400 x^2-61000 x-15000\right ) \log (x)+76375 x+21600}{3 x \left (\log ^4(x)-16 \log ^3(x)+100 \log ^2(x)-288 \log (x)+323\right )^2}dx\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{3} \int \frac {25 \left (\left (5 x-2 x^2\right ) \log ^4(x)-4 \left (-9 x^2+25 x+3\right ) \log ^3(x)+4 \left (-62 x^2+185 x+36\right ) \log ^2(x)-8 \left (-97 x^2+305 x+75\right ) \log (x)-934 x^2+3055 x+864\right )}{x \left (\log ^4(x)-16 \log ^3(x)+100 \log ^2(x)-288 \log (x)+323\right )^2}dx\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {25}{3} \int \frac {\left (5 x-2 x^2\right ) \log ^4(x)-4 \left (-9 x^2+25 x+3\right ) \log ^3(x)+4 \left (-62 x^2+185 x+36\right ) \log ^2(x)-8 \left (-97 x^2+305 x+75\right ) \log (x)-934 x^2+3055 x+864}{x \left (\log ^4(x)-16 \log ^3(x)+100 \log ^2(x)-288 \log (x)+323\right )^2}dx\)

\(\Big \downarrow \) 7293

\(\displaystyle \frac {25}{3} \int \left (\frac {5-2 x}{2 \left (\log ^2(x)-8 \log (x)+17\right )}+\frac {2 x-5}{2 \left (\log ^2(x)-8 \log (x)+19\right )}+\frac {\left (x^2-5 x-3\right ) (\log (x)-4)}{x \left (\log ^2(x)-8 \log (x)+17\right )^2}-\frac {\left (x^2-5 x-3\right ) (\log (x)-4)}{x \left (\log ^2(x)-8 \log (x)+19\right )^2}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {25}{3} \left (-4 \int \frac {x}{\left (\log ^2(x)-8 \log (x)+17\right )^2}dx+\int \frac {x \log (x)}{\left (\log ^2(x)-8 \log (x)+17\right )^2}dx-\int \frac {x}{\log ^2(x)-8 \log (x)+17}dx+4 \int \frac {x}{\left (\log ^2(x)-8 \log (x)+19\right )^2}dx-\int \frac {x \log (x)}{\left (\log ^2(x)-8 \log (x)+19\right )^2}dx+\int \frac {x}{\log ^2(x)-8 \log (x)+19}dx-\frac {5}{12} \left (4+i \sqrt {3}\right ) e^{4+i \sqrt {3}} \operatorname {ExpIntegralEi}\left (\log (x)-i \sqrt {3}-4\right )+\frac {5 i e^{4+i \sqrt {3}} \operatorname {ExpIntegralEi}\left (\log (x)-i \sqrt {3}-4\right )}{4 \sqrt {3}}+\frac {5}{3} e^{4+i \sqrt {3}} \operatorname {ExpIntegralEi}\left (\log (x)-i \sqrt {3}-4\right )-\frac {5}{12} \left (4-i \sqrt {3}\right ) e^{4-i \sqrt {3}} \operatorname {ExpIntegralEi}\left (\log (x)+i \sqrt {3}-4\right )-\frac {5 i e^{4-i \sqrt {3}} \operatorname {ExpIntegralEi}\left (\log (x)+i \sqrt {3}-4\right )}{4 \sqrt {3}}+\frac {5}{3} e^{4-i \sqrt {3}} \operatorname {ExpIntegralEi}\left (\log (x)+i \sqrt {3}-4\right )+\frac {3}{2 \left (\log ^2(x)-8 \log (x)+17\right )}-\frac {3}{2 \left (\log ^2(x)-8 \log (x)+19\right )}+\frac {5 i x}{2 (-2 \log (x)+(8+2 i))}-\frac {5 \left (4-i \sqrt {3}\right ) x}{12 \left (-\log (x)-i \sqrt {3}+4\right )}+\frac {5 x}{3 \left (-\log (x)-i \sqrt {3}+4\right )}-\frac {5 \left (4+i \sqrt {3}\right ) x}{12 \left (-\log (x)+i \sqrt {3}+4\right )}+\frac {5 x}{3 \left (-\log (x)+i \sqrt {3}+4\right )}+\frac {5 i x}{2 (2 \log (x)-(8-2 i))}\right )\)

input
Int[(21600 + 76375*x - 23350*x^2 + (-15000 - 61000*x + 19400*x^2)*Log[x] + 
 (3600 + 18500*x - 6200*x^2)*Log[x]^2 + (-300 - 2500*x + 900*x^2)*Log[x]^3 
 + (125*x - 50*x^2)*Log[x]^4)/(312987*x - 558144*x*Log[x] + 442632*x*Log[x 
]^2 - 203808*x*Log[x]^3 + 59586*x*Log[x]^4 - 11328*x*Log[x]^5 + 1368*x*Log 
[x]^6 - 96*x*Log[x]^7 + 3*x*Log[x]^8),x]
 
output
$Aborted
 

3.10.31.3.1 Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 7292
Int[u_, x_Symbol] :> With[{v = NormalizeIntegrand[u, x]}, Int[v, x] /; v =! 
= u]
 

rule 7293
Int[u_, x_Symbol] :> With[{v = ExpandIntegrand[u, x]}, Int[v, x] /; SumQ[v] 
]
 
3.10.31.4 Maple [A] (verified)

Time = 0.97 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.17

method result size
risch \(-\frac {25 \left (x^{2}-5 x -3\right )}{3 \left (\ln \left (x \right )^{4}-16 \ln \left (x \right )^{3}+100 \ln \left (x \right )^{2}-288 \ln \left (x \right )+323\right )}\) \(35\)
parallelrisch \(\frac {-25 x^{2}+125 x +75}{3 \ln \left (x \right )^{4}-48 \ln \left (x \right )^{3}+300 \ln \left (x \right )^{2}-864 \ln \left (x \right )+969}\) \(37\)
default \(\text {Expression too large to display}\) \(622\)

input
int(((-50*x^2+125*x)*ln(x)^4+(900*x^2-2500*x-300)*ln(x)^3+(-6200*x^2+18500 
*x+3600)*ln(x)^2+(19400*x^2-61000*x-15000)*ln(x)-23350*x^2+76375*x+21600)/ 
(3*x*ln(x)^8-96*x*ln(x)^7+1368*x*ln(x)^6-11328*x*ln(x)^5+59586*x*ln(x)^4-2 
03808*x*ln(x)^3+442632*x*ln(x)^2-558144*x*ln(x)+312987*x),x,method=_RETURN 
VERBOSE)
 
output
-25/3*(x^2-5*x-3)/(ln(x)^4-16*ln(x)^3+100*ln(x)^2-288*ln(x)+323)
 
3.10.31.5 Fricas [A] (verification not implemented)

Time = 0.23 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.13 \[ \int \frac {21600+76375 x-23350 x^2+\left (-15000-61000 x+19400 x^2\right ) \log (x)+\left (3600+18500 x-6200 x^2\right ) \log ^2(x)+\left (-300-2500 x+900 x^2\right ) \log ^3(x)+\left (125 x-50 x^2\right ) \log ^4(x)}{312987 x-558144 x \log (x)+442632 x \log ^2(x)-203808 x \log ^3(x)+59586 x \log ^4(x)-11328 x \log ^5(x)+1368 x \log ^6(x)-96 x \log ^7(x)+3 x \log ^8(x)} \, dx=-\frac {25 \, {\left (x^{2} - 5 \, x - 3\right )}}{3 \, {\left (\log \left (x\right )^{4} - 16 \, \log \left (x\right )^{3} + 100 \, \log \left (x\right )^{2} - 288 \, \log \left (x\right ) + 323\right )}} \]

input
integrate(((-50*x^2+125*x)*log(x)^4+(900*x^2-2500*x-300)*log(x)^3+(-6200*x 
^2+18500*x+3600)*log(x)^2+(19400*x^2-61000*x-15000)*log(x)-23350*x^2+76375 
*x+21600)/(3*x*log(x)^8-96*x*log(x)^7+1368*x*log(x)^6-11328*x*log(x)^5+595 
86*x*log(x)^4-203808*x*log(x)^3+442632*x*log(x)^2-558144*x*log(x)+312987*x 
),x, algorithm=\
 
output
-25/3*(x^2 - 5*x - 3)/(log(x)^4 - 16*log(x)^3 + 100*log(x)^2 - 288*log(x) 
+ 323)
 
3.10.31.6 Sympy [A] (verification not implemented)

Time = 0.09 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.20 \[ \int \frac {21600+76375 x-23350 x^2+\left (-15000-61000 x+19400 x^2\right ) \log (x)+\left (3600+18500 x-6200 x^2\right ) \log ^2(x)+\left (-300-2500 x+900 x^2\right ) \log ^3(x)+\left (125 x-50 x^2\right ) \log ^4(x)}{312987 x-558144 x \log (x)+442632 x \log ^2(x)-203808 x \log ^3(x)+59586 x \log ^4(x)-11328 x \log ^5(x)+1368 x \log ^6(x)-96 x \log ^7(x)+3 x \log ^8(x)} \, dx=\frac {- 25 x^{2} + 125 x + 75}{3 \log {\left (x \right )}^{4} - 48 \log {\left (x \right )}^{3} + 300 \log {\left (x \right )}^{2} - 864 \log {\left (x \right )} + 969} \]

input
integrate(((-50*x**2+125*x)*ln(x)**4+(900*x**2-2500*x-300)*ln(x)**3+(-6200 
*x**2+18500*x+3600)*ln(x)**2+(19400*x**2-61000*x-15000)*ln(x)-23350*x**2+7 
6375*x+21600)/(3*x*ln(x)**8-96*x*ln(x)**7+1368*x*ln(x)**6-11328*x*ln(x)**5 
+59586*x*ln(x)**4-203808*x*ln(x)**3+442632*x*ln(x)**2-558144*x*ln(x)+31298 
7*x),x)
 
output
(-25*x**2 + 125*x + 75)/(3*log(x)**4 - 48*log(x)**3 + 300*log(x)**2 - 864* 
log(x) + 969)
 
3.10.31.7 Maxima [A] (verification not implemented)

Time = 0.23 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.13 \[ \int \frac {21600+76375 x-23350 x^2+\left (-15000-61000 x+19400 x^2\right ) \log (x)+\left (3600+18500 x-6200 x^2\right ) \log ^2(x)+\left (-300-2500 x+900 x^2\right ) \log ^3(x)+\left (125 x-50 x^2\right ) \log ^4(x)}{312987 x-558144 x \log (x)+442632 x \log ^2(x)-203808 x \log ^3(x)+59586 x \log ^4(x)-11328 x \log ^5(x)+1368 x \log ^6(x)-96 x \log ^7(x)+3 x \log ^8(x)} \, dx=-\frac {25 \, {\left (x^{2} - 5 \, x - 3\right )}}{3 \, {\left (\log \left (x\right )^{4} - 16 \, \log \left (x\right )^{3} + 100 \, \log \left (x\right )^{2} - 288 \, \log \left (x\right ) + 323\right )}} \]

input
integrate(((-50*x^2+125*x)*log(x)^4+(900*x^2-2500*x-300)*log(x)^3+(-6200*x 
^2+18500*x+3600)*log(x)^2+(19400*x^2-61000*x-15000)*log(x)-23350*x^2+76375 
*x+21600)/(3*x*log(x)^8-96*x*log(x)^7+1368*x*log(x)^6-11328*x*log(x)^5+595 
86*x*log(x)^4-203808*x*log(x)^3+442632*x*log(x)^2-558144*x*log(x)+312987*x 
),x, algorithm=\
 
output
-25/3*(x^2 - 5*x - 3)/(log(x)^4 - 16*log(x)^3 + 100*log(x)^2 - 288*log(x) 
+ 323)
 
3.10.31.8 Giac [A] (verification not implemented)

Time = 0.29 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.13 \[ \int \frac {21600+76375 x-23350 x^2+\left (-15000-61000 x+19400 x^2\right ) \log (x)+\left (3600+18500 x-6200 x^2\right ) \log ^2(x)+\left (-300-2500 x+900 x^2\right ) \log ^3(x)+\left (125 x-50 x^2\right ) \log ^4(x)}{312987 x-558144 x \log (x)+442632 x \log ^2(x)-203808 x \log ^3(x)+59586 x \log ^4(x)-11328 x \log ^5(x)+1368 x \log ^6(x)-96 x \log ^7(x)+3 x \log ^8(x)} \, dx=-\frac {25 \, {\left (x^{2} - 5 \, x - 3\right )}}{3 \, {\left (\log \left (x\right )^{4} - 16 \, \log \left (x\right )^{3} + 100 \, \log \left (x\right )^{2} - 288 \, \log \left (x\right ) + 323\right )}} \]

input
integrate(((-50*x^2+125*x)*log(x)^4+(900*x^2-2500*x-300)*log(x)^3+(-6200*x 
^2+18500*x+3600)*log(x)^2+(19400*x^2-61000*x-15000)*log(x)-23350*x^2+76375 
*x+21600)/(3*x*log(x)^8-96*x*log(x)^7+1368*x*log(x)^6-11328*x*log(x)^5+595 
86*x*log(x)^4-203808*x*log(x)^3+442632*x*log(x)^2-558144*x*log(x)+312987*x 
),x, algorithm=\
 
output
-25/3*(x^2 - 5*x - 3)/(log(x)^4 - 16*log(x)^3 + 100*log(x)^2 - 288*log(x) 
+ 323)
 
3.10.31.9 Mupad [B] (verification not implemented)

Time = 13.29 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.60 \[ \int \frac {21600+76375 x-23350 x^2+\left (-15000-61000 x+19400 x^2\right ) \log (x)+\left (3600+18500 x-6200 x^2\right ) \log ^2(x)+\left (-300-2500 x+900 x^2\right ) \log ^3(x)+\left (125 x-50 x^2\right ) \log ^4(x)}{312987 x-558144 x \log (x)+442632 x \log ^2(x)-203808 x \log ^3(x)+59586 x \log ^4(x)-11328 x \log ^5(x)+1368 x \log ^6(x)-96 x \log ^7(x)+3 x \log ^8(x)} \, dx=\frac {-\frac {25\,x^2}{6}+\frac {125\,x}{6}+\frac {25}{2}}{{\ln \left (x\right )}^2-8\,\ln \left (x\right )+17}-\frac {-\frac {25\,x^2}{6}+\frac {125\,x}{6}+\frac {25}{2}}{{\ln \left (x\right )}^2-8\,\ln \left (x\right )+19} \]

input
int((76375*x + log(x)^4*(125*x - 50*x^2) - log(x)^3*(2500*x - 900*x^2 + 30 
0) + log(x)^2*(18500*x - 6200*x^2 + 3600) - log(x)*(61000*x - 19400*x^2 + 
15000) - 23350*x^2 + 21600)/(312987*x + 442632*x*log(x)^2 - 203808*x*log(x 
)^3 + 59586*x*log(x)^4 - 11328*x*log(x)^5 + 1368*x*log(x)^6 - 96*x*log(x)^ 
7 + 3*x*log(x)^8 - 558144*x*log(x)),x)
 
output
((125*x)/6 - (25*x^2)/6 + 25/2)/(log(x)^2 - 8*log(x) + 17) - ((125*x)/6 - 
(25*x^2)/6 + 25/2)/(log(x)^2 - 8*log(x) + 19)