3.13.86 \(\int \frac {405+810 x+270 \log (4)+(405+810 x+270 \log (4)) \log (5)}{2916+972 x+1053 x^2+162 x^3+81 x^4+(648 x+108 x^2+108 x^3) \log (4)+(108+18 x+54 x^2) \log ^2(4)+12 x \log ^3(4)+\log ^4(4)+(5832+972 x+972 x^2+648 x \log (4)+108 \log ^2(4)) \log (5)+2916 \log ^2(5)} \, dx\) [1286]

3.13.86.1 Optimal result
3.13.86.2 Mathematica [B] (verified)
3.13.86.3 Rubi [A] (verified)
3.13.86.4 Maple [A] (verified)
3.13.86.5 Fricas [A] (verification not implemented)
3.13.86.6 Sympy [A] (verification not implemented)
3.13.86.7 Maxima [A] (verification not implemented)
3.13.86.8 Giac [B] (verification not implemented)
3.13.86.9 Mupad [B] (verification not implemented)

3.13.86.1 Optimal result

Integrand size = 117, antiderivative size = 27 \begin {dmath*} \int \frac {405+810 x+270 \log (4)+(405+810 x+270 \log (4)) \log (5)}{2916+972 x+1053 x^2+162 x^3+81 x^4+\left (648 x+108 x^2+108 x^3\right ) \log (4)+\left (108+18 x+54 x^2\right ) \log ^2(4)+12 x \log ^3(4)+\log ^4(4)+\left (5832+972 x+972 x^2+648 x \log (4)+108 \log ^2(4)\right ) \log (5)+2916 \log ^2(5)} \, dx=3-\frac {5}{6+\frac {x+\left (x+\frac {\log (4)}{3}\right )^2}{1+\log (5)}} \end {dmath*}

output
3-5/(6+((x+2/3*ln(2))^2+x)/(ln(5)+1))
 
3.13.86.2 Mathematica [B] (verified)

Leaf count is larger than twice the leaf count of optimal. \(69\) vs. \(2(27)=54\).

Time = 0.05 (sec) , antiderivative size = 69, normalized size of antiderivative = 2.56 \begin {dmath*} \int \frac {405+810 x+270 \log (4)+(405+810 x+270 \log (4)) \log (5)}{2916+972 x+1053 x^2+162 x^3+81 x^4+\left (648 x+108 x^2+108 x^3\right ) \log (4)+\left (108+18 x+54 x^2\right ) \log ^2(4)+12 x \log ^3(4)+\log ^4(4)+\left (5832+972 x+972 x^2+648 x \log (4)+108 \log ^2(4)\right ) \log (5)+2916 \log ^2(5)} \, dx=\frac {15 (1+\log (5)) \left (207-6 \log (4)+4 \log ^2(4)+216 \log (5)-3 \log (16)-2 \log (4) \log (16)\right )}{(-69+4 \log (4)-72 \log (5)) \left (54+9 x+9 x^2+6 x \log (4)+\log ^2(4)+54 \log (5)\right )} \end {dmath*}

input
Integrate[(405 + 810*x + 270*Log[4] + (405 + 810*x + 270*Log[4])*Log[5])/( 
2916 + 972*x + 1053*x^2 + 162*x^3 + 81*x^4 + (648*x + 108*x^2 + 108*x^3)*L 
og[4] + (108 + 18*x + 54*x^2)*Log[4]^2 + 12*x*Log[4]^3 + Log[4]^4 + (5832 
+ 972*x + 972*x^2 + 648*x*Log[4] + 108*Log[4]^2)*Log[5] + 2916*Log[5]^2),x 
]
 
output
(15*(1 + Log[5])*(207 - 6*Log[4] + 4*Log[4]^2 + 216*Log[5] - 3*Log[16] - 2 
*Log[4]*Log[16]))/((-69 + 4*Log[4] - 72*Log[5])*(54 + 9*x + 9*x^2 + 6*x*Lo 
g[4] + Log[4]^2 + 54*Log[5]))
 
3.13.86.3 Rubi [A] (verified)

Time = 0.32 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.26, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.060, Rules used = {6, 2459, 27, 27, 1380, 27, 241}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {810 x+\log (5) (810 x+405+270 \log (4))+405+270 \log (4)}{81 x^4+162 x^3+1053 x^2+\log (5) \left (972 x^2+972 x+648 x \log (4)+5832+108 \log ^2(4)\right )+\left (54 x^2+18 x+108\right ) \log ^2(4)+\left (108 x^3+108 x^2+648 x\right ) \log (4)+972 x+12 x \log ^3(4)+2916+\log ^4(4)+2916 \log ^2(5)} \, dx\)

\(\Big \downarrow \) 6

\(\displaystyle \int \frac {810 x+\log (5) (810 x+405+270 \log (4))+405+270 \log (4)}{81 x^4+162 x^3+1053 x^2+\log (5) \left (972 x^2+972 x+648 x \log (4)+5832+108 \log ^2(4)\right )+\left (54 x^2+18 x+108\right ) \log ^2(4)+\left (108 x^3+108 x^2+648 x\right ) \log (4)+x \left (972+12 \log ^3(4)\right )+2916+\log ^4(4)+2916 \log ^2(5)}dx\)

\(\Big \downarrow \) 2459

\(\displaystyle \int \frac {810 (1+\log (5)) \left (x+\frac {1}{324} (162+108 \log (4))\right )}{81 \left (x+\frac {1}{324} (162+108 \log (4))\right )^4+\frac {27}{2} (69-4 \log (4)+72 \log (5)) \left (x+\frac {1}{324} (162+108 \log (4))\right )^2+\frac {9}{16} (69+72 \log (5)-\log (256))^2}d\left (x+\frac {1}{324} (162+108 \log (4))\right )\)

\(\Big \downarrow \) 27

\(\displaystyle 810 (1+\log (5)) \int \frac {16 \left (x+\frac {1}{324} (162+108 \log (4))\right )}{9 \left (144 \left (x+\frac {1}{324} (162+108 \log (4))\right )^4+24 (69-4 \log (4)+72 \log (5)) \left (x+\frac {1}{324} (162+108 \log (4))\right )^2+(-69-72 \log (5)+\log (256))^2\right )}d\left (x+\frac {1}{324} (162+108 \log (4))\right )\)

\(\Big \downarrow \) 27

\(\displaystyle 1440 (1+\log (5)) \int \frac {x+\frac {1}{324} (162+108 \log (4))}{144 \left (x+\frac {1}{324} (162+108 \log (4))\right )^4+24 (69-4 \log (4)+72 \log (5)) \left (x+\frac {1}{324} (162+108 \log (4))\right )^2+(-69-72 \log (5)+\log (256))^2}d\left (x+\frac {1}{324} (162+108 \log (4))\right )\)

\(\Big \downarrow \) 1380

\(\displaystyle 207360 (1+\log (5)) \int \frac {x+\frac {1}{324} (162+108 \log (4))}{144 \left (12 \left (x+\frac {1}{324} (162+108 \log (4))\right )^2+72 \log (5)-4 \log (4)+69\right )^2}d\left (x+\frac {1}{324} (162+108 \log (4))\right )\)

\(\Big \downarrow \) 27

\(\displaystyle 1440 (1+\log (5)) \int \frac {x+\frac {1}{324} (162+108 \log (4))}{\left (12 \left (x+\frac {1}{324} (162+108 \log (4))\right )^2+72 \log (5)-4 \log (4)+69\right )^2}d\left (x+\frac {1}{324} (162+108 \log (4))\right )\)

\(\Big \downarrow \) 241

\(\displaystyle -\frac {60 (1+\log (5))}{12 \left (x+\frac {1}{324} (162+108 \log (4))\right )^2+69+72 \log (5)-4 \log (4)}\)

input
Int[(405 + 810*x + 270*Log[4] + (405 + 810*x + 270*Log[4])*Log[5])/(2916 + 
 972*x + 1053*x^2 + 162*x^3 + 81*x^4 + (648*x + 108*x^2 + 108*x^3)*Log[4] 
+ (108 + 18*x + 54*x^2)*Log[4]^2 + 12*x*Log[4]^3 + Log[4]^4 + (5832 + 972* 
x + 972*x^2 + 648*x*Log[4] + 108*Log[4]^2)*Log[5] + 2916*Log[5]^2),x]
 
output
(-60*(1 + Log[5]))/(69 - 4*Log[4] + 12*(x + (162 + 108*Log[4])/324)^2 + 72 
*Log[5])
 

3.13.86.3.1 Defintions of rubi rules used

rule 6
Int[(u_.)*((v_.) + (a_.)*(Fx_) + (b_.)*(Fx_))^(p_.), x_Symbol] :> Int[u*(v 
+ (a + b)*Fx)^p, x] /; FreeQ[{a, b}, x] &&  !FreeQ[Fx, x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 241
Int[(x_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(a + b*x^2)^(p + 1)/ 
(2*b*(p + 1)), x] /; FreeQ[{a, b, p}, x] && NeQ[p, -1]
 

rule 1380
Int[(u_)*((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> S 
imp[1/c^p   Int[u*(b/2 + c*x^n)^(2*p), x], x] /; FreeQ[{a, b, c, n, p}, x] 
&& EqQ[n2, 2*n] && EqQ[b^2 - 4*a*c, 0] && IntegerQ[p]
 

rule 2459
Int[(Pn_)^(p_.)*(Qx_), x_Symbol] :> With[{S = Coeff[Pn, x, Expon[Pn, x] - 1 
]/(Expon[Pn, x]*Coeff[Pn, x, Expon[Pn, x]])}, Subst[Int[ExpandToSum[Pn /. x 
 -> x - S, x]^p*ExpandToSum[Qx /. x -> x - S, x], x], x, x + S] /; Binomial 
Q[Pn /. x -> x - S, x] || (IntegerQ[Expon[Pn, x]/2] && TrinomialQ[Pn /. x - 
> x - S, x])] /; FreeQ[p, x] && PolyQ[Pn, x] && GtQ[Expon[Pn, x], 2] && NeQ 
[Coeff[Pn, x, Expon[Pn, x] - 1], 0] && PolyQ[Qx, x] &&  !(MonomialQ[Qx, x] 
&& IGtQ[p, 0])
 
3.13.86.4 Maple [A] (verified)

Time = 0.08 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.26

method result size
gosper \(-\frac {45 \left (\ln \left (5\right )+1\right )}{4 \ln \left (2\right )^{2}+12 x \ln \left (2\right )+9 x^{2}+54 \ln \left (5\right )+9 x +54}\) \(34\)
norman \(\frac {-45-45 \ln \left (5\right )}{4 \ln \left (2\right )^{2}+12 x \ln \left (2\right )+9 x^{2}+54 \ln \left (5\right )+9 x +54}\) \(35\)
parallelrisch \(\frac {-405-405 \ln \left (5\right )}{36 \ln \left (2\right )^{2}+108 x \ln \left (2\right )+81 x^{2}+486 \ln \left (5\right )+81 x +486}\) \(36\)
risch \(-\frac {45 \ln \left (5\right )}{4 \left (\ln \left (2\right )^{2}+3 x \ln \left (2\right )+\frac {9 x^{2}}{4}+\frac {27 \ln \left (5\right )}{2}+\frac {9 x}{4}+\frac {27}{2}\right )}-\frac {45}{4 \left (\ln \left (2\right )^{2}+3 x \ln \left (2\right )+\frac {9 x^{2}}{4}+\frac {27 \ln \left (5\right )}{2}+\frac {9 x}{4}+\frac {27}{2}\right )}\) \(58\)
default \(\frac {\left (135 \ln \left (5\right )+135\right ) \left (-648+\left (4 \ln \left (2\right )+3\right ) \left (12 \ln \left (2\right )+9\right )-48 \ln \left (2\right )^{2}-648 \ln \left (5\right )\right )}{\left (-216 \ln \left (2\right )+1944 \ln \left (5\right )+1863\right ) \left (4 \ln \left (2\right )^{2}+12 x \ln \left (2\right )+9 x^{2}+54 \ln \left (5\right )+9 x +54\right )}\) \(72\)

input
int(((540*ln(2)+810*x+405)*ln(5)+540*ln(2)+810*x+405)/(2916*ln(5)^2+(432*l 
n(2)^2+1296*x*ln(2)+972*x^2+972*x+5832)*ln(5)+16*ln(2)^4+96*x*ln(2)^3+4*(5 
4*x^2+18*x+108)*ln(2)^2+2*(108*x^3+108*x^2+648*x)*ln(2)+81*x^4+162*x^3+105 
3*x^2+972*x+2916),x,method=_RETURNVERBOSE)
 
output
-45*(ln(5)+1)/(4*ln(2)^2+12*x*ln(2)+9*x^2+54*ln(5)+9*x+54)
 
3.13.86.5 Fricas [A] (verification not implemented)

Time = 0.26 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.22 \begin {dmath*} \int \frac {405+810 x+270 \log (4)+(405+810 x+270 \log (4)) \log (5)}{2916+972 x+1053 x^2+162 x^3+81 x^4+\left (648 x+108 x^2+108 x^3\right ) \log (4)+\left (108+18 x+54 x^2\right ) \log ^2(4)+12 x \log ^3(4)+\log ^4(4)+\left (5832+972 x+972 x^2+648 x \log (4)+108 \log ^2(4)\right ) \log (5)+2916 \log ^2(5)} \, dx=-\frac {45 \, {\left (\log \left (5\right ) + 1\right )}}{9 \, x^{2} + 12 \, x \log \left (2\right ) + 4 \, \log \left (2\right )^{2} + 9 \, x + 54 \, \log \left (5\right ) + 54} \end {dmath*}

input
integrate(((540*log(2)+810*x+405)*log(5)+540*log(2)+810*x+405)/(2916*log(5 
)^2+(432*log(2)^2+1296*x*log(2)+972*x^2+972*x+5832)*log(5)+16*log(2)^4+96* 
x*log(2)^3+4*(54*x^2+18*x+108)*log(2)^2+2*(108*x^3+108*x^2+648*x)*log(2)+8 
1*x^4+162*x^3+1053*x^2+972*x+2916),x, algorithm=\
 
output
-45*(log(5) + 1)/(9*x^2 + 12*x*log(2) + 4*log(2)^2 + 9*x + 54*log(5) + 54)
 
3.13.86.6 Sympy [A] (verification not implemented)

Time = 0.87 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.26 \begin {dmath*} \int \frac {405+810 x+270 \log (4)+(405+810 x+270 \log (4)) \log (5)}{2916+972 x+1053 x^2+162 x^3+81 x^4+\left (648 x+108 x^2+108 x^3\right ) \log (4)+\left (108+18 x+54 x^2\right ) \log ^2(4)+12 x \log ^3(4)+\log ^4(4)+\left (5832+972 x+972 x^2+648 x \log (4)+108 \log ^2(4)\right ) \log (5)+2916 \log ^2(5)} \, dx=\frac {- 45 \log {\left (5 \right )} - 45}{9 x^{2} + x \left (12 \log {\left (2 \right )} + 9\right ) + 4 \log {\left (2 \right )}^{2} + 54 + 54 \log {\left (5 \right )}} \end {dmath*}

input
integrate(((540*ln(2)+810*x+405)*ln(5)+540*ln(2)+810*x+405)/(2916*ln(5)**2 
+(432*ln(2)**2+1296*x*ln(2)+972*x**2+972*x+5832)*ln(5)+16*ln(2)**4+96*x*ln 
(2)**3+4*(54*x**2+18*x+108)*ln(2)**2+2*(108*x**3+108*x**2+648*x)*ln(2)+81* 
x**4+162*x**3+1053*x**2+972*x+2916),x)
 
output
(-45*log(5) - 45)/(9*x**2 + x*(12*log(2) + 9) + 4*log(2)**2 + 54 + 54*log( 
5))
 
3.13.86.7 Maxima [A] (verification not implemented)

Time = 0.20 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.26 \begin {dmath*} \int \frac {405+810 x+270 \log (4)+(405+810 x+270 \log (4)) \log (5)}{2916+972 x+1053 x^2+162 x^3+81 x^4+\left (648 x+108 x^2+108 x^3\right ) \log (4)+\left (108+18 x+54 x^2\right ) \log ^2(4)+12 x \log ^3(4)+\log ^4(4)+\left (5832+972 x+972 x^2+648 x \log (4)+108 \log ^2(4)\right ) \log (5)+2916 \log ^2(5)} \, dx=-\frac {45 \, {\left (\log \left (5\right ) + 1\right )}}{9 \, x^{2} + 3 \, x {\left (4 \, \log \left (2\right ) + 3\right )} + 4 \, \log \left (2\right )^{2} + 54 \, \log \left (5\right ) + 54} \end {dmath*}

input
integrate(((540*log(2)+810*x+405)*log(5)+540*log(2)+810*x+405)/(2916*log(5 
)^2+(432*log(2)^2+1296*x*log(2)+972*x^2+972*x+5832)*log(5)+16*log(2)^4+96* 
x*log(2)^3+4*(54*x^2+18*x+108)*log(2)^2+2*(108*x^3+108*x^2+648*x)*log(2)+8 
1*x^4+162*x^3+1053*x^2+972*x+2916),x, algorithm=\
 
output
-45*(log(5) + 1)/(9*x^2 + 3*x*(4*log(2) + 3) + 4*log(2)^2 + 54*log(5) + 54 
)
 
3.13.86.8 Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 71 vs. \(2 (29) = 58\).

Time = 0.27 (sec) , antiderivative size = 71, normalized size of antiderivative = 2.63 \begin {dmath*} \int \frac {405+810 x+270 \log (4)+(405+810 x+270 \log (4)) \log (5)}{2916+972 x+1053 x^2+162 x^3+81 x^4+\left (648 x+108 x^2+108 x^3\right ) \log (4)+\left (108+18 x+54 x^2\right ) \log ^2(4)+12 x \log ^3(4)+\log ^4(4)+\left (5832+972 x+972 x^2+648 x \log (4)+108 \log ^2(4)\right ) \log (5)+2916 \log ^2(5)} \, dx=-\frac {45 \, {\left (\log \left (5\right )^{2} + 2 \, \log \left (5\right ) + 1\right )}}{4 \, \log \left (5\right ) \log \left (2\right )^{2} + 9 \, x^{2} + 3 \, {\left (3 \, x^{2} + 4 \, x \log \left (2\right ) + 3 \, x\right )} \log \left (5\right ) + 54 \, \log \left (5\right )^{2} + 12 \, x \log \left (2\right ) + 4 \, \log \left (2\right )^{2} + 9 \, x + 108 \, \log \left (5\right ) + 54} \end {dmath*}

input
integrate(((540*log(2)+810*x+405)*log(5)+540*log(2)+810*x+405)/(2916*log(5 
)^2+(432*log(2)^2+1296*x*log(2)+972*x^2+972*x+5832)*log(5)+16*log(2)^4+96* 
x*log(2)^3+4*(54*x^2+18*x+108)*log(2)^2+2*(108*x^3+108*x^2+648*x)*log(2)+8 
1*x^4+162*x^3+1053*x^2+972*x+2916),x, algorithm=\
 
output
-45*(log(5)^2 + 2*log(5) + 1)/(4*log(5)*log(2)^2 + 9*x^2 + 3*(3*x^2 + 4*x* 
log(2) + 3*x)*log(5) + 54*log(5)^2 + 12*x*log(2) + 4*log(2)^2 + 9*x + 108* 
log(5) + 54)
 
3.13.86.9 Mupad [B] (verification not implemented)

Time = 19.67 (sec) , antiderivative size = 2558, normalized size of antiderivative = 94.74 \begin {dmath*} \int \frac {405+810 x+270 \log (4)+(405+810 x+270 \log (4)) \log (5)}{2916+972 x+1053 x^2+162 x^3+81 x^4+\left (648 x+108 x^2+108 x^3\right ) \log (4)+\left (108+18 x+54 x^2\right ) \log ^2(4)+12 x \log ^3(4)+\log ^4(4)+\left (5832+972 x+972 x^2+648 x \log (4)+108 \log ^2(4)\right ) \log (5)+2916 \log ^2(5)} \, dx=\text {Too large to display} \end {dmath*}

input
int((810*x + 540*log(2) + log(5)*(810*x + 540*log(2) + 405) + 405)/(972*x 
+ 2*log(2)*(648*x + 108*x^2 + 108*x^3) + 4*log(2)^2*(18*x + 54*x^2 + 108) 
+ 96*x*log(2)^3 + log(5)*(972*x + 1296*x*log(2) + 432*log(2)^2 + 972*x^2 + 
 5832) + 16*log(2)^4 + 2916*log(5)^2 + 1053*x^2 + 162*x^3 + 81*x^4 + 2916) 
,x)
 
output
symsum(log(4009802061150*root(418066920000*log(2)*log(5)^3 - 9447840000*lo 
g(2)^2*log(5) + 210804930000*log(2)*log(5)^4 - 2361960000*log(2)^2*log(5)^ 
4 + 42515280000*log(2)*log(5)^5 - 14171760000*log(2)^2*log(5)^2 - 94478400 
00*log(2)^2*log(5)^3 + 414523980000*log(2)*log(5)^2 + 205490520000*log(2)* 
log(5) - 2790397400625*log(5)^4 - 1069525012500*log(5) - 1131969330000*log 
(5)^5 - 2361960000*log(2)^2 - 191318760000*log(5)^6 - 2712342003750*log(5) 
^2 + 40743810000*log(2) - 3668271502500*log(5)^3 - 175707680625, z, k) + 3 
486784401000*x + 2324522934000*log(2) + 5230176601500*log(5) + 48814981614 
00*root(418066920000*log(2)*log(5)^3 - 9447840000*log(2)^2*log(5) + 210804 
930000*log(2)*log(5)^4 - 2361960000*log(2)^2*log(5)^4 + 42515280000*log(2) 
*log(5)^5 - 14171760000*log(2)^2*log(5)^2 - 9447840000*log(2)^2*log(5)^3 + 
 414523980000*log(2)*log(5)^2 + 205490520000*log(2)*log(5) - 2790397400625 
*log(5)^4 - 1069525012500*log(5) - 1131969330000*log(5)^5 - 2361960000*log 
(2)^2 - 191318760000*log(5)^6 - 2712342003750*log(5)^2 + 40743810000*log(2 
) - 3668271502500*log(5)^3 - 175707680625, z, k)*log(2) + 12203745403500*r 
oot(418066920000*log(2)*log(5)^3 - 9447840000*log(2)^2*log(5) + 2108049300 
00*log(2)*log(5)^4 - 2361960000*log(2)^2*log(5)^4 + 42515280000*log(2)*log 
(5)^5 - 14171760000*log(2)^2*log(5)^2 - 9447840000*log(2)^2*log(5)^3 + 414 
523980000*log(2)*log(5)^2 + 205490520000*log(2)*log(5) - 2790397400625*log 
(5)^4 - 1069525012500*log(5) - 1131969330000*log(5)^5 - 2361960000*log(...