3.1.60 \(\int 8 e^{e^{\frac {8}{5} x^5 (i \pi +\log (4))}+\frac {8}{5} x^5 (i \pi +\log (4))} x^4 (i \pi +\log (4)) \, dx\) [60]

3.1.60.1 Optimal result
3.1.60.2 Mathematica [A] (verified)
3.1.60.3 Rubi [F]
3.1.60.4 Maple [A] (verified)
3.1.60.5 Fricas [A] (verification not implemented)
3.1.60.6 Sympy [A] (verification not implemented)
3.1.60.7 Maxima [A] (verification not implemented)
3.1.60.8 Giac [A] (verification not implemented)
3.1.60.9 Mupad [B] (verification not implemented)

3.1.60.1 Optimal result

Integrand size = 48, antiderivative size = 19 \begin {dmath*} \int 8 e^{e^{\frac {8}{5} x^5 (i \pi +\log (4))}+\frac {8}{5} x^5 (i \pi +\log (4))} x^4 (i \pi +\log (4)) \, dx=e^{e^{\frac {8}{5} x^5 (i \pi +\log (4))}} \end {dmath*}

output
exp(exp(8/5*x^5*(2*ln(2)+I*Pi)))
 
3.1.60.2 Mathematica [A] (verified)

Time = 0.07 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.00 \begin {dmath*} \int 8 e^{e^{\frac {8}{5} x^5 (i \pi +\log (4))}+\frac {8}{5} x^5 (i \pi +\log (4))} x^4 (i \pi +\log (4)) \, dx=e^{e^{\frac {8}{5} x^5 (i \pi +\log (4))}} \end {dmath*}

input
Integrate[8*E^(E^((8*x^5*(I*Pi + Log[4]))/5) + (8*x^5*(I*Pi + Log[4]))/5)* 
x^4*(I*Pi + Log[4]),x]
 
output
E^E^((8*x^5*(I*Pi + Log[4]))/5)
 
3.1.60.3 Rubi [F]

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int 8 x^4 (\log (4)+i \pi ) \exp \left (\frac {8}{5} x^5 (\log (4)+i \pi )+e^{\frac {8}{5} x^5 (\log (4)+i \pi )}\right ) \, dx\)

\(\Big \downarrow \) 27

\(\displaystyle 8 (\log (4)+i \pi ) \int \exp \left (\frac {8}{5} (i \pi +\log (4)) x^5+2^{\frac {16 x^5}{5}} e^{\frac {8}{5} i \pi x^5}\right ) x^4dx\)

\(\Big \downarrow \) 7266

\(\displaystyle \frac {8}{5} (\log (4)+i \pi ) \int \exp \left (\frac {8}{5} (i \pi +\log (4)) x^5+2^{\frac {16 x^5}{5}} e^{\frac {8}{5} i \pi x^5}\right )dx^5\)

\(\Big \downarrow \) 7281

\(\displaystyle (\log (4)+i \pi ) \int \exp \left (\frac {8}{5} (i \pi +\log (4)) x^5+2^{\frac {16 x^5}{5}} e^{\frac {8}{5} i \pi x^5}\right )d\frac {8 x^5}{5}\)

\(\Big \downarrow \) 7299

\(\displaystyle (\log (4)+i \pi ) \int \exp \left (\frac {8}{5} (i \pi +\log (4)) x^5+2^{\frac {16 x^5}{5}} e^{\frac {8}{5} i \pi x^5}\right )d\frac {8 x^5}{5}\)

input
Int[8*E^(E^((8*x^5*(I*Pi + Log[4]))/5) + (8*x^5*(I*Pi + Log[4]))/5)*x^4*(I 
*Pi + Log[4]),x]
 
output
$Aborted
 

3.1.60.3.1 Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 7266
Int[(u_)*(x_)^(m_.), x_Symbol] :> Simp[1/(m + 1)   Subst[Int[SubstFor[x^(m 
+ 1), u, x], x], x, x^(m + 1)], x] /; FreeQ[m, x] && NeQ[m, -1] && Function 
OfQ[x^(m + 1), u, x]
 

rule 7281
Int[u_, x_Symbol] :> With[{lst = FunctionOfLinear[u, x]}, Simp[1/lst[[3]] 
 Subst[Int[lst[[1]], x], x, lst[[2]] + lst[[3]]*x], x] /;  !FalseQ[lst]]
 

rule 7299
Int[u_, x_] :> CannotIntegrate[u, x]
 
3.1.60.4 Maple [A] (verified)

Time = 0.43 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.89

method result size
derivativedivides \({\mathrm e}^{{\mathrm e}^{\frac {8 x^{5} \left (2 \ln \left (2\right )+i \pi \right )}{5}}}\) \(17\)
norman \({\mathrm e}^{{\mathrm e}^{\frac {8 x^{5} \left (2 \ln \left (2\right )+i \pi \right )}{5}}}\) \(17\)
default \({\mathrm e}^{{\mathrm e}^{\frac {8 x^{5} \left (2 \ln \left (2\right )+i \pi \right )}{5}}}\) \(39\)
parallelrisch \({\mathrm e}^{{\mathrm e}^{\frac {8 x^{5} \left (2 \ln \left (2\right )+i \pi \right )}{5}}}\) \(39\)
risch \(\frac {{\mathrm e}^{2^{\frac {16 x^{5}}{5}} {\mathrm e}^{\frac {8 i \pi \,x^{5}}{5}}} \pi }{-2 i \ln \left (2\right )+\pi }-\frac {2 i {\mathrm e}^{2^{\frac {16 x^{5}}{5}} {\mathrm e}^{\frac {8 i \pi \,x^{5}}{5}}} \ln \left (2\right )}{-2 i \ln \left (2\right )+\pi }\) \(61\)

input
int(8*x^4*(2*ln(2)+I*Pi)*exp(8/5*x^5*(2*ln(2)+I*Pi))*exp(exp(8/5*x^5*(2*ln 
(2)+I*Pi))),x,method=_RETURNVERBOSE)
 
output
exp(exp(8/5*x^5*(2*ln(2)+I*Pi)))
 
3.1.60.5 Fricas [A] (verification not implemented)

Time = 0.28 (sec) , antiderivative size = 39, normalized size of antiderivative = 2.05 \begin {dmath*} \int 8 e^{e^{\frac {8}{5} x^5 (i \pi +\log (4))}+\frac {8}{5} x^5 (i \pi +\log (4))} x^4 (i \pi +\log (4)) \, dx=\cosh \left (-e^{\left (\frac {8}{5} i \, \pi x^{5} + \frac {16}{5} \, x^{5} \log \left (2\right )\right )}\right ) - \sinh \left (-e^{\left (\frac {8}{5} i \, \pi x^{5} + \frac {16}{5} \, x^{5} \log \left (2\right )\right )}\right ) \end {dmath*}

input
integrate(8*x^4*(2*log(2)+I*pi)*exp(8/5*x^5*(2*log(2)+I*pi))*exp(exp(8/5*x 
^5*(2*log(2)+I*pi))),x, algorithm=\
 
output
cosh(-e^(8/5*I*pi*x^5 + 16/5*x^5*log(2))) - sinh(-e^(8/5*I*pi*x^5 + 16/5*x 
^5*log(2)))
 
3.1.60.6 Sympy [A] (verification not implemented)

Time = 82.59 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.89 \begin {dmath*} \int 8 e^{e^{\frac {8}{5} x^5 (i \pi +\log (4))}+\frac {8}{5} x^5 (i \pi +\log (4))} x^4 (i \pi +\log (4)) \, dx=e^{e^{\frac {8 x^{5} \cdot \left (2 \log {\left (2 \right )} + i \pi \right )}{5}}} \end {dmath*}

input
integrate(8*x**4*(2*ln(2)+I*pi)*exp(8/5*x**5*(2*ln(2)+I*pi))*exp(exp(8/5*x 
**5*(2*ln(2)+I*pi))),x)
 
output
exp(exp(8*x**5*(2*log(2) + I*pi)/5))
 
3.1.60.7 Maxima [A] (verification not implemented)

Time = 0.39 (sec) , antiderivative size = 39, normalized size of antiderivative = 2.05 \begin {dmath*} \int 8 e^{e^{\frac {8}{5} x^5 (i \pi +\log (4))}+\frac {8}{5} x^5 (i \pi +\log (4))} x^4 (i \pi +\log (4)) \, dx=\cosh \left (-e^{\left (\frac {8}{5} i \, \pi x^{5} + \frac {16}{5} \, x^{5} \log \left (2\right )\right )}\right ) - \sinh \left (-e^{\left (\frac {8}{5} i \, \pi x^{5} + \frac {16}{5} \, x^{5} \log \left (2\right )\right )}\right ) \end {dmath*}

input
integrate(8*x^4*(2*log(2)+I*pi)*exp(8/5*x^5*(2*log(2)+I*pi))*exp(exp(8/5*x 
^5*(2*log(2)+I*pi))),x, algorithm=\
 
output
cosh(-e^(8/5*I*pi*x^5 + 16/5*x^5*log(2))) - sinh(-e^(8/5*I*pi*x^5 + 16/5*x 
^5*log(2)))
 
3.1.60.8 Giac [A] (verification not implemented)

Time = 0.30 (sec) , antiderivative size = 39, normalized size of antiderivative = 2.05 \begin {dmath*} \int 8 e^{e^{\frac {8}{5} x^5 (i \pi +\log (4))}+\frac {8}{5} x^5 (i \pi +\log (4))} x^4 (i \pi +\log (4)) \, dx=\cosh \left (-e^{\left (\frac {8}{5} i \, \pi x^{5} + \frac {16}{5} \, x^{5} \log \left (2\right )\right )}\right ) - \sinh \left (-e^{\left (\frac {8}{5} i \, \pi x^{5} + \frac {16}{5} \, x^{5} \log \left (2\right )\right )}\right ) \end {dmath*}

input
integrate(8*x^4*(2*log(2)+I*pi)*exp(8/5*x^5*(2*log(2)+I*pi))*exp(exp(8/5*x 
^5*(2*log(2)+I*pi))),x, algorithm=\
 
output
cosh(-e^(8/5*I*pi*x^5 + 16/5*x^5*log(2))) - sinh(-e^(8/5*I*pi*x^5 + 16/5*x 
^5*log(2)))
 
3.1.60.9 Mupad [B] (verification not implemented)

Time = 13.19 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.89 \begin {dmath*} \int 8 e^{e^{\frac {8}{5} x^5 (i \pi +\log (4))}+\frac {8}{5} x^5 (i \pi +\log (4))} x^4 (i \pi +\log (4)) \, dx={\mathrm {e}}^{2^{\frac {16\,x^5}{5}}\,{\mathrm {e}}^{\frac {\Pi \,x^5\,8{}\mathrm {i}}{5}}} \end {dmath*}

input
int(8*x^4*exp((8*x^5*(Pi*1i + 2*log(2)))/5)*exp(exp((8*x^5*(Pi*1i + 2*log( 
2)))/5))*(Pi*1i + 2*log(2)),x)
 
output
exp(2^((16*x^5)/5)*exp((Pi*x^5*8i)/5))