Integrand size = 16, antiderivative size = 115 \[ \int \frac {d+e x}{a+b \arcsin (c x)} \, dx=\frac {d \cos \left (\frac {a}{b}\right ) \operatorname {CosIntegral}\left (\frac {a}{b}+\arcsin (c x)\right )}{b c}-\frac {e \operatorname {CosIntegral}\left (\frac {2 a}{b}+2 \arcsin (c x)\right ) \sin \left (\frac {2 a}{b}\right )}{2 b c^2}+\frac {d \sin \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a}{b}+\arcsin (c x)\right )}{b c}+\frac {e \cos \left (\frac {2 a}{b}\right ) \text {Si}\left (\frac {2 a}{b}+2 \arcsin (c x)\right )}{2 b c^2} \]
d*Ci(a/b+arcsin(c*x))*cos(a/b)/b/c+1/2*e*cos(2*a/b)*Si(2*a/b+2*arcsin(c*x) )/b/c^2+d*Si(a/b+arcsin(c*x))*sin(a/b)/b/c-1/2*e*Ci(2*a/b+2*arcsin(c*x))*s in(2*a/b)/b/c^2
Time = 0.17 (sec) , antiderivative size = 98, normalized size of antiderivative = 0.85 \[ \int \frac {d+e x}{a+b \arcsin (c x)} \, dx=\frac {2 c d \cos \left (\frac {a}{b}\right ) \operatorname {CosIntegral}\left (\frac {a}{b}+\arcsin (c x)\right )-e \operatorname {CosIntegral}\left (2 \left (\frac {a}{b}+\arcsin (c x)\right )\right ) \sin \left (\frac {2 a}{b}\right )+2 c d \sin \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a}{b}+\arcsin (c x)\right )+e \cos \left (\frac {2 a}{b}\right ) \text {Si}\left (2 \left (\frac {a}{b}+\arcsin (c x)\right )\right )}{2 b c^2} \]
(2*c*d*Cos[a/b]*CosIntegral[a/b + ArcSin[c*x]] - e*CosIntegral[2*(a/b + Ar cSin[c*x])]*Sin[(2*a)/b] + 2*c*d*Sin[a/b]*SinIntegral[a/b + ArcSin[c*x]] + e*Cos[(2*a)/b]*SinIntegral[2*(a/b + ArcSin[c*x])])/(2*b*c^2)
Time = 0.51 (sec) , antiderivative size = 109, normalized size of antiderivative = 0.95, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.188, Rules used = {5246, 7293, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {d+e x}{a+b \arcsin (c x)} \, dx\) |
\(\Big \downarrow \) 5246 |
\(\displaystyle \frac {\int \frac {(c d+c e x) \sqrt {1-c^2 x^2}}{a+b \arcsin (c x)}d\arcsin (c x)}{c^2}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle \frac {\int \left (\frac {c \sqrt {1-c^2 x^2} d}{a+b \arcsin (c x)}+\frac {c e x \sqrt {1-c^2 x^2}}{a+b \arcsin (c x)}\right )d\arcsin (c x)}{c^2}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {\frac {c d \cos \left (\frac {a}{b}\right ) \operatorname {CosIntegral}\left (\frac {a}{b}+\arcsin (c x)\right )}{b}-\frac {e \sin \left (\frac {2 a}{b}\right ) \operatorname {CosIntegral}\left (\frac {2 a}{b}+2 \arcsin (c x)\right )}{2 b}+\frac {c d \sin \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a}{b}+\arcsin (c x)\right )}{b}+\frac {e \cos \left (\frac {2 a}{b}\right ) \text {Si}\left (\frac {2 a}{b}+2 \arcsin (c x)\right )}{2 b}}{c^2}\) |
((c*d*Cos[a/b]*CosIntegral[a/b + ArcSin[c*x]])/b - (e*CosIntegral[(2*a)/b + 2*ArcSin[c*x]]*Sin[(2*a)/b])/(2*b) + (c*d*Sin[a/b]*SinIntegral[a/b + Arc Sin[c*x]])/b + (e*Cos[(2*a)/b]*SinIntegral[(2*a)/b + 2*ArcSin[c*x]])/(2*b) )/c^2
3.1.18.3.1 Defintions of rubi rules used
Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_)*((d_.) + (e_.)*(x_))^(m_.), x_S ymbol] :> Simp[1/c^(m + 1) Subst[Int[(a + b*x)^n*Cos[x]*(c*d + e*Sin[x])^ m, x], x, ArcSin[c*x]], x] /; FreeQ[{a, b, c, d, e, n}, x] && IGtQ[m, 0]
Time = 0.08 (sec) , antiderivative size = 103, normalized size of antiderivative = 0.90
method | result | size |
derivativedivides | \(\frac {\frac {d \left (\operatorname {Si}\left (\arcsin \left (c x \right )+\frac {a}{b}\right ) \sin \left (\frac {a}{b}\right )+\operatorname {Ci}\left (\arcsin \left (c x \right )+\frac {a}{b}\right ) \cos \left (\frac {a}{b}\right )\right )}{b}+\frac {e \left (\operatorname {Si}\left (2 \arcsin \left (c x \right )+\frac {2 a}{b}\right ) \cos \left (\frac {2 a}{b}\right )-\operatorname {Ci}\left (2 \arcsin \left (c x \right )+\frac {2 a}{b}\right ) \sin \left (\frac {2 a}{b}\right )\right )}{2 c b}}{c}\) | \(103\) |
default | \(\frac {\frac {d \left (\operatorname {Si}\left (\arcsin \left (c x \right )+\frac {a}{b}\right ) \sin \left (\frac {a}{b}\right )+\operatorname {Ci}\left (\arcsin \left (c x \right )+\frac {a}{b}\right ) \cos \left (\frac {a}{b}\right )\right )}{b}+\frac {e \left (\operatorname {Si}\left (2 \arcsin \left (c x \right )+\frac {2 a}{b}\right ) \cos \left (\frac {2 a}{b}\right )-\operatorname {Ci}\left (2 \arcsin \left (c x \right )+\frac {2 a}{b}\right ) \sin \left (\frac {2 a}{b}\right )\right )}{2 c b}}{c}\) | \(103\) |
1/c*(d*(Si(arcsin(c*x)+a/b)*sin(a/b)+Ci(arcsin(c*x)+a/b)*cos(a/b))/b+1/2/c *e*(Si(2*arcsin(c*x)+2*a/b)*cos(2*a/b)-Ci(2*arcsin(c*x)+2*a/b)*sin(2*a/b)) /b)
\[ \int \frac {d+e x}{a+b \arcsin (c x)} \, dx=\int { \frac {e x + d}{b \arcsin \left (c x\right ) + a} \,d x } \]
\[ \int \frac {d+e x}{a+b \arcsin (c x)} \, dx=\int \frac {d + e x}{a + b \operatorname {asin}{\left (c x \right )}}\, dx \]
\[ \int \frac {d+e x}{a+b \arcsin (c x)} \, dx=\int { \frac {e x + d}{b \arcsin \left (c x\right ) + a} \,d x } \]
Time = 0.30 (sec) , antiderivative size = 139, normalized size of antiderivative = 1.21 \[ \int \frac {d+e x}{a+b \arcsin (c x)} \, dx=\frac {d \cos \left (\frac {a}{b}\right ) \operatorname {Ci}\left (\frac {a}{b} + \arcsin \left (c x\right )\right )}{b c} - \frac {e \cos \left (\frac {a}{b}\right ) \operatorname {Ci}\left (\frac {2 \, a}{b} + 2 \, \arcsin \left (c x\right )\right ) \sin \left (\frac {a}{b}\right )}{b c^{2}} + \frac {e \cos \left (\frac {a}{b}\right )^{2} \operatorname {Si}\left (\frac {2 \, a}{b} + 2 \, \arcsin \left (c x\right )\right )}{b c^{2}} + \frac {d \sin \left (\frac {a}{b}\right ) \operatorname {Si}\left (\frac {a}{b} + \arcsin \left (c x\right )\right )}{b c} - \frac {e \operatorname {Si}\left (\frac {2 \, a}{b} + 2 \, \arcsin \left (c x\right )\right )}{2 \, b c^{2}} \]
d*cos(a/b)*cos_integral(a/b + arcsin(c*x))/(b*c) - e*cos(a/b)*cos_integral (2*a/b + 2*arcsin(c*x))*sin(a/b)/(b*c^2) + e*cos(a/b)^2*sin_integral(2*a/b + 2*arcsin(c*x))/(b*c^2) + d*sin(a/b)*sin_integral(a/b + arcsin(c*x))/(b* c) - 1/2*e*sin_integral(2*a/b + 2*arcsin(c*x))/(b*c^2)
Timed out. \[ \int \frac {d+e x}{a+b \arcsin (c x)} \, dx=\int \frac {d+e\,x}{a+b\,\mathrm {asin}\left (c\,x\right )} \,d x \]