3.4.83 \(\int \frac {a+b \arcsin (c x^n)}{x} \, dx\) [383]

3.4.83.1 Optimal result

Integrand size = 14, antiderivative size = 75 \[ \int \frac {a+b \arcsin \left (c x^n\right )}{x} \, dx=-\frac {i b \arcsin \left (c x^n\right )^2}{2 n}+\frac {b \arcsin \left (c x^n\right ) \log \left (1-e^{2 i \arcsin \left (c x^n\right )}\right )}{n}+a \log (x)-\frac {i b \operatorname {PolyLog}\left (2,e^{2 i \arcsin \left (c x^n\right )}\right )}{2 n} \]

output

-1/2*I*b*arcsin(c*x^n)^2/n+b*arcsin(c*x^n)*ln(1-(I*c*x^n+(1-c^2*(x^n)^2)^( 
1/2))^2)/n+a*ln(x)-1/2*I*b*polylog(2,(I*c*x^n+(1-c^2*(x^n)^2)^(1/2))^2)/n
 

3.4.83.2 Mathematica [B] (verified)

Both result and optimal contain complex but leaf count is larger than twice the leaf count of optimal. \(157\) vs. \(2(75)=150\).

Time = 0.15 (sec) , antiderivative size = 157, normalized size of antiderivative = 2.09 \[ \int \frac {a+b \arcsin \left (c x^n\right )}{x} \, dx=a \log (x)+b \arcsin \left (c x^n\right ) \log (x)-\frac {b c \left (\log (x) \log \left (\sqrt {-c^2} x^n+\sqrt {1-c^2 x^{2 n}}\right )+\frac {i \left (i \text {arcsinh}\left (\sqrt {-c^2} x^n\right ) \log \left (1-e^{-2 \text {arcsinh}\left (\sqrt {-c^2} x^n\right )}\right )-\frac {1}{2} i \left (-\text {arcsinh}\left (\sqrt {-c^2} x^n\right )^2+\operatorname {PolyLog}\left (2,e^{-2 \text {arcsinh}\left (\sqrt {-c^2} x^n\right )}\right )\right )\right )}{n}\right )}{\sqrt {-c^2}} \]

input

Integrate[(a + b*ArcSin[c*x^n])/x,x]
 

output

a*Log[x] + b*ArcSin[c*x^n]*Log[x] - (b*c*(Log[x]*Log[Sqrt[-c^2]*x^n + Sqrt 
[1 - c^2*x^(2*n)]] + (I*(I*ArcSinh[Sqrt[-c^2]*x^n]*Log[1 - E^(-2*ArcSinh[S 
qrt[-c^2]*x^n])] - (I/2)*(-ArcSinh[Sqrt[-c^2]*x^n]^2 + PolyLog[2, E^(-2*Ar 
cSinh[Sqrt[-c^2]*x^n])])))/n))/Sqrt[-c^2]
 

3.4.83.3 Rubi [A] (verified)

Time = 0.30 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {7293, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {a+b \arcsin \left (c x^n\right )}{x} \, dx\)

\(\Big \downarrow \) 7293

\(\displaystyle \int \left (\frac {a}{x}+\frac {b \arcsin \left (c x^n\right )}{x}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle a \log (x)-\frac {i b \operatorname {PolyLog}\left (2,e^{2 i \arcsin \left (c x^n\right )}\right )}{2 n}-\frac {i b \arcsin \left (c x^n\right )^2}{2 n}+\frac {b \arcsin \left (c x^n\right ) \log \left (1-e^{2 i \arcsin \left (c x^n\right )}\right )}{n}\)

input

Int[(a + b*ArcSin[c*x^n])/x,x]
 

output

((-1/2*I)*b*ArcSin[c*x^n]^2)/n + (b*ArcSin[c*x^n]*Log[1 - E^((2*I)*ArcSin[ 
c*x^n])])/n + a*Log[x] - ((I/2)*b*PolyLog[2, E^((2*I)*ArcSin[c*x^n])])/n
 

3.4.83.3.1 Defintions of rubi rules used

rule 2009

Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 7293

Int[u_, x_Symbol] :> With[{v = ExpandIntegrand[u, x]}, Int[v, x] /; SumQ[v] 
]
 

3.4.83.4 Maple [A] (verified)

Time = 0.97 (sec) , antiderivative size = 143, normalized size of antiderivative = 1.91

method	result	size
parts	\(a \ln \left (x \right )+\frac {b \left (-\frac {i \arcsin \left (c \,x^{n}\right )^{2}}{2}+\arcsin \left (c \,x^{n}\right ) \ln \left (1+i c \,x^{n}+\sqrt {1-c^{2} x^{2 n}}\right )-i \operatorname {polylog}\left (2, -i c \,x^{n}-\sqrt {1-c^{2} x^{2 n}}\right )+\arcsin \left (c \,x^{n}\right ) \ln \left (1-i c \,x^{n}-\sqrt {1-c^{2} x^{2 n}}\right )-i \operatorname {polylog}\left (2, i c \,x^{n}+\sqrt {1-c^{2} x^{2 n}}\right )\right )}{n}\)	\(143\)
derivativedivides	\(\frac {a \ln \left (c \,x^{n}\right )+b \left (-\frac {i \arcsin \left (c \,x^{n}\right )^{2}}{2}+\arcsin \left (c \,x^{n}\right ) \ln \left (1+i c \,x^{n}+\sqrt {1-c^{2} x^{2 n}}\right )-i \operatorname {polylog}\left (2, -i c \,x^{n}-\sqrt {1-c^{2} x^{2 n}}\right )+\arcsin \left (c \,x^{n}\right ) \ln \left (1-i c \,x^{n}-\sqrt {1-c^{2} x^{2 n}}\right )-i \operatorname {polylog}\left (2, i c \,x^{n}+\sqrt {1-c^{2} x^{2 n}}\right )\right )}{n}\)	\(148\)
default	\(\frac {a \ln \left (c \,x^{n}\right )+b \left (-\frac {i \arcsin \left (c \,x^{n}\right )^{2}}{2}+\arcsin \left (c \,x^{n}\right ) \ln \left (1+i c \,x^{n}+\sqrt {1-c^{2} x^{2 n}}\right )-i \operatorname {polylog}\left (2, -i c \,x^{n}-\sqrt {1-c^{2} x^{2 n}}\right )+\arcsin \left (c \,x^{n}\right ) \ln \left (1-i c \,x^{n}-\sqrt {1-c^{2} x^{2 n}}\right )-i \operatorname {polylog}\left (2, i c \,x^{n}+\sqrt {1-c^{2} x^{2 n}}\right )\right )}{n}\)	\(148\)

input

int((a+b*arcsin(c*x^n))/x,x,method=_RETURNVERBOSE)
 

output

a*ln(x)+b/n*(-1/2*I*arcsin(c*x^n)^2+arcsin(c*x^n)*ln(1+I*c*x^n+(1-c^2*(x^n 
)^2)^(1/2))-I*polylog(2,-I*c*x^n-(1-c^2*(x^n)^2)^(1/2))+arcsin(c*x^n)*ln(1 
-I*c*x^n-(1-c^2*(x^n)^2)^(1/2))-I*polylog(2,I*c*x^n+(1-c^2*(x^n)^2)^(1/2)) 
)
 

3.4.83.5 Fricas [F(-2)]

Exception generated. \[ \int \frac {a+b \arcsin \left (c x^n\right )}{x} \, dx=\text {Exception raised: TypeError} \]

input

integrate((a+b*arcsin(c*x^n))/x,x, algorithm="fricas")
 

output

Exception raised: TypeError >>  Error detected within library code:   inte 
grate: implementation incomplete (has polynomial part)
 

3.4.83.6 Sympy [F]

\[ \int \frac {a+b \arcsin \left (c x^n\right )}{x} \, dx=\int \frac {a + b \operatorname {asin}{\left (c x^{n} \right )}}{x}\, dx \]

input

integrate((a+b*asin(c*x**n))/x,x)
 

output

Integral((a + b*asin(c*x**n))/x, x)
 

3.4.83.7 Maxima [F]

\[ \int \frac {a+b \arcsin \left (c x^n\right )}{x} \, dx=\int { \frac {b \arcsin \left (c x^{n}\right ) + a}{x} \,d x } \]

input

integrate((a+b*arcsin(c*x^n))/x,x, algorithm="maxima")
 

output

(c*n*integrate(sqrt(c*x^n + 1)*sqrt(-c*x^n + 1)*x^n*log(x)/(c^2*x*x^(2*n) 
- x), x) + arctan2(c*x^n, sqrt(c*x^n + 1)*sqrt(-c*x^n + 1))*log(x))*b + a* 
log(x)
 

3.4.83.8 Giac [F]

\[ \int \frac {a+b \arcsin \left (c x^n\right )}{x} \, dx=\int { \frac {b \arcsin \left (c x^{n}\right ) + a}{x} \,d x } \]

input

integrate((a+b*arcsin(c*x^n))/x,x, algorithm="giac")
 

output

integrate((b*arcsin(c*x^n) + a)/x, x)
 

3.4.83.9 Mupad [F(-1)]

Timed out. \[ \int \frac {a+b \arcsin \left (c x^n\right )}{x} \, dx=\int \frac {a+b\,\mathrm {asin}\left (c\,x^n\right )}{x} \,d x \]

input

int((a + b*asin(c*x^n))/x,x)
 

output

int((a + b*asin(c*x^n))/x, x)