Integrand size = 31, antiderivative size = 380 \[ \int \frac {a+b \arcsin (c x)}{(f+g x) \sqrt {d-c^2 d x^2}} \, dx=-\frac {i \sqrt {1-c^2 x^2} (a+b \arcsin (c x)) \log \left (1-\frac {i e^{i \arcsin (c x)} g}{c f-\sqrt {c^2 f^2-g^2}}\right )}{\sqrt {c^2 f^2-g^2} \sqrt {d-c^2 d x^2}}+\frac {i \sqrt {1-c^2 x^2} (a+b \arcsin (c x)) \log \left (1-\frac {i e^{i \arcsin (c x)} g}{c f+\sqrt {c^2 f^2-g^2}}\right )}{\sqrt {c^2 f^2-g^2} \sqrt {d-c^2 d x^2}}-\frac {b \sqrt {1-c^2 x^2} \operatorname {PolyLog}\left (2,\frac {i e^{i \arcsin (c x)} g}{c f-\sqrt {c^2 f^2-g^2}}\right )}{\sqrt {c^2 f^2-g^2} \sqrt {d-c^2 d x^2}}+\frac {b \sqrt {1-c^2 x^2} \operatorname {PolyLog}\left (2,\frac {i e^{i \arcsin (c x)} g}{c f+\sqrt {c^2 f^2-g^2}}\right )}{\sqrt {c^2 f^2-g^2} \sqrt {d-c^2 d x^2}} \]
-I*(a+b*arcsin(c*x))*ln(1-I*(I*c*x+(-c^2*x^2+1)^(1/2))*g/(c*f-(c^2*f^2-g^2 )^(1/2)))*(-c^2*x^2+1)^(1/2)/(c^2*f^2-g^2)^(1/2)/(-c^2*d*x^2+d)^(1/2)+I*(a +b*arcsin(c*x))*ln(1-I*(I*c*x+(-c^2*x^2+1)^(1/2))*g/(c*f+(c^2*f^2-g^2)^(1/ 2)))*(-c^2*x^2+1)^(1/2)/(c^2*f^2-g^2)^(1/2)/(-c^2*d*x^2+d)^(1/2)-b*polylog (2,I*(I*c*x+(-c^2*x^2+1)^(1/2))*g/(c*f-(c^2*f^2-g^2)^(1/2)))*(-c^2*x^2+1)^ (1/2)/(c^2*f^2-g^2)^(1/2)/(-c^2*d*x^2+d)^(1/2)+b*polylog(2,I*(I*c*x+(-c^2* x^2+1)^(1/2))*g/(c*f+(c^2*f^2-g^2)^(1/2)))*(-c^2*x^2+1)^(1/2)/(c^2*f^2-g^2 )^(1/2)/(-c^2*d*x^2+d)^(1/2)
Time = 0.16 (sec) , antiderivative size = 232, normalized size of antiderivative = 0.61 \[ \int \frac {a+b \arcsin (c x)}{(f+g x) \sqrt {d-c^2 d x^2}} \, dx=\frac {\sqrt {1-c^2 x^2} \left (-i (a+b \arcsin (c x)) \left (\log \left (1+\frac {i e^{i \arcsin (c x)} g}{-c f+\sqrt {c^2 f^2-g^2}}\right )-\log \left (1-\frac {i e^{i \arcsin (c x)} g}{c f+\sqrt {c^2 f^2-g^2}}\right )\right )-b \operatorname {PolyLog}\left (2,-\frac {i e^{i \arcsin (c x)} g}{-c f+\sqrt {c^2 f^2-g^2}}\right )+b \operatorname {PolyLog}\left (2,\frac {i e^{i \arcsin (c x)} g}{c f+\sqrt {c^2 f^2-g^2}}\right )\right )}{\sqrt {c^2 f^2-g^2} \sqrt {d-c^2 d x^2}} \]
(Sqrt[1 - c^2*x^2]*((-I)*(a + b*ArcSin[c*x])*(Log[1 + (I*E^(I*ArcSin[c*x]) *g)/(-(c*f) + Sqrt[c^2*f^2 - g^2])] - Log[1 - (I*E^(I*ArcSin[c*x])*g)/(c*f + Sqrt[c^2*f^2 - g^2])]) - b*PolyLog[2, ((-I)*E^(I*ArcSin[c*x])*g)/(-(c*f ) + Sqrt[c^2*f^2 - g^2])] + b*PolyLog[2, (I*E^(I*ArcSin[c*x])*g)/(c*f + Sq rt[c^2*f^2 - g^2])]))/(Sqrt[c^2*f^2 - g^2]*Sqrt[d - c^2*d*x^2])
Time = 1.02 (sec) , antiderivative size = 288, normalized size of antiderivative = 0.76, number of steps used = 10, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.290, Rules used = {5276, 5272, 3042, 3804, 2694, 27, 2620, 2715, 2838}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {a+b \arcsin (c x)}{\sqrt {d-c^2 d x^2} (f+g x)} \, dx\) |
\(\Big \downarrow \) 5276 |
\(\displaystyle \frac {\sqrt {1-c^2 x^2} \int \frac {a+b \arcsin (c x)}{(f+g x) \sqrt {1-c^2 x^2}}dx}{\sqrt {d-c^2 d x^2}}\) |
\(\Big \downarrow \) 5272 |
\(\displaystyle \frac {\sqrt {1-c^2 x^2} \int \frac {a+b \arcsin (c x)}{c f+c g x}d\arcsin (c x)}{\sqrt {d-c^2 d x^2}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {\sqrt {1-c^2 x^2} \int \frac {a+b \arcsin (c x)}{c f+g \sin (\arcsin (c x))}d\arcsin (c x)}{\sqrt {d-c^2 d x^2}}\) |
\(\Big \downarrow \) 3804 |
\(\displaystyle \frac {2 \sqrt {1-c^2 x^2} \int \frac {e^{i \arcsin (c x)} (a+b \arcsin (c x))}{2 c e^{i \arcsin (c x)} f-i e^{2 i \arcsin (c x)} g+i g}d\arcsin (c x)}{\sqrt {d-c^2 d x^2}}\) |
\(\Big \downarrow \) 2694 |
\(\displaystyle \frac {2 \sqrt {1-c^2 x^2} \left (\frac {i g \int \frac {e^{i \arcsin (c x)} (a+b \arcsin (c x))}{2 \left (c f-i e^{i \arcsin (c x)} g+\sqrt {c^2 f^2-g^2}\right )}d\arcsin (c x)}{\sqrt {c^2 f^2-g^2}}-\frac {i g \int \frac {e^{i \arcsin (c x)} (a+b \arcsin (c x))}{2 \left (c f-i e^{i \arcsin (c x)} g-\sqrt {c^2 f^2-g^2}\right )}d\arcsin (c x)}{\sqrt {c^2 f^2-g^2}}\right )}{\sqrt {d-c^2 d x^2}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {2 \sqrt {1-c^2 x^2} \left (\frac {i g \int \frac {e^{i \arcsin (c x)} (a+b \arcsin (c x))}{c f-i e^{i \arcsin (c x)} g+\sqrt {c^2 f^2-g^2}}d\arcsin (c x)}{2 \sqrt {c^2 f^2-g^2}}-\frac {i g \int \frac {e^{i \arcsin (c x)} (a+b \arcsin (c x))}{c f-i e^{i \arcsin (c x)} g-\sqrt {c^2 f^2-g^2}}d\arcsin (c x)}{2 \sqrt {c^2 f^2-g^2}}\right )}{\sqrt {d-c^2 d x^2}}\) |
\(\Big \downarrow \) 2620 |
\(\displaystyle \frac {2 \sqrt {1-c^2 x^2} \left (\frac {i g \left (\frac {(a+b \arcsin (c x)) \log \left (1-\frac {i g e^{i \arcsin (c x)}}{\sqrt {c^2 f^2-g^2}+c f}\right )}{g}-\frac {b \int \log \left (1-\frac {i e^{i \arcsin (c x)} g}{c f+\sqrt {c^2 f^2-g^2}}\right )d\arcsin (c x)}{g}\right )}{2 \sqrt {c^2 f^2-g^2}}-\frac {i g \left (\frac {(a+b \arcsin (c x)) \log \left (1-\frac {i g e^{i \arcsin (c x)}}{c f-\sqrt {c^2 f^2-g^2}}\right )}{g}-\frac {b \int \log \left (1-\frac {i e^{i \arcsin (c x)} g}{c f-\sqrt {c^2 f^2-g^2}}\right )d\arcsin (c x)}{g}\right )}{2 \sqrt {c^2 f^2-g^2}}\right )}{\sqrt {d-c^2 d x^2}}\) |
\(\Big \downarrow \) 2715 |
\(\displaystyle \frac {2 \sqrt {1-c^2 x^2} \left (\frac {i g \left (\frac {i b \int e^{-i \arcsin (c x)} \log \left (1-\frac {i e^{i \arcsin (c x)} g}{c f+\sqrt {c^2 f^2-g^2}}\right )de^{i \arcsin (c x)}}{g}+\frac {(a+b \arcsin (c x)) \log \left (1-\frac {i g e^{i \arcsin (c x)}}{\sqrt {c^2 f^2-g^2}+c f}\right )}{g}\right )}{2 \sqrt {c^2 f^2-g^2}}-\frac {i g \left (\frac {i b \int e^{-i \arcsin (c x)} \log \left (1-\frac {i e^{i \arcsin (c x)} g}{c f-\sqrt {c^2 f^2-g^2}}\right )de^{i \arcsin (c x)}}{g}+\frac {(a+b \arcsin (c x)) \log \left (1-\frac {i g e^{i \arcsin (c x)}}{c f-\sqrt {c^2 f^2-g^2}}\right )}{g}\right )}{2 \sqrt {c^2 f^2-g^2}}\right )}{\sqrt {d-c^2 d x^2}}\) |
\(\Big \downarrow \) 2838 |
\(\displaystyle \frac {2 \sqrt {1-c^2 x^2} \left (\frac {i g \left (\frac {(a+b \arcsin (c x)) \log \left (1-\frac {i g e^{i \arcsin (c x)}}{\sqrt {c^2 f^2-g^2}+c f}\right )}{g}-\frac {i b \operatorname {PolyLog}\left (2,\frac {i e^{i \arcsin (c x)} g}{c f+\sqrt {c^2 f^2-g^2}}\right )}{g}\right )}{2 \sqrt {c^2 f^2-g^2}}-\frac {i g \left (\frac {(a+b \arcsin (c x)) \log \left (1-\frac {i g e^{i \arcsin (c x)}}{c f-\sqrt {c^2 f^2-g^2}}\right )}{g}-\frac {i b \operatorname {PolyLog}\left (2,\frac {i e^{i \arcsin (c x)} g}{c f-\sqrt {c^2 f^2-g^2}}\right )}{g}\right )}{2 \sqrt {c^2 f^2-g^2}}\right )}{\sqrt {d-c^2 d x^2}}\) |
(2*Sqrt[1 - c^2*x^2]*(((-1/2*I)*g*(((a + b*ArcSin[c*x])*Log[1 - (I*E^(I*Ar cSin[c*x])*g)/(c*f - Sqrt[c^2*f^2 - g^2])])/g - (I*b*PolyLog[2, (I*E^(I*Ar cSin[c*x])*g)/(c*f - Sqrt[c^2*f^2 - g^2])])/g))/Sqrt[c^2*f^2 - g^2] + ((I/ 2)*g*(((a + b*ArcSin[c*x])*Log[1 - (I*E^(I*ArcSin[c*x])*g)/(c*f + Sqrt[c^2 *f^2 - g^2])])/g - (I*b*PolyLog[2, (I*E^(I*ArcSin[c*x])*g)/(c*f + Sqrt[c^2 *f^2 - g^2])])/g))/Sqrt[c^2*f^2 - g^2]))/Sqrt[d - c^2*d*x^2]
3.1.47.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[(((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)*((c_.) + (d_.)*(x_))^(m_.))/ ((a_) + (b_.)*((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)), x_Symbol] :> Simp [((c + d*x)^m/(b*f*g*n*Log[F]))*Log[1 + b*((F^(g*(e + f*x)))^n/a)], x] - Si mp[d*(m/(b*f*g*n*Log[F])) Int[(c + d*x)^(m - 1)*Log[1 + b*((F^(g*(e + f*x )))^n/a)], x], x] /; FreeQ[{F, a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]
Int[((F_)^(u_)*((f_.) + (g_.)*(x_))^(m_.))/((a_.) + (b_.)*(F_)^(u_) + (c_.) *(F_)^(v_)), x_Symbol] :> With[{q = Rt[b^2 - 4*a*c, 2]}, Simp[2*(c/q) Int [(f + g*x)^m*(F^u/(b - q + 2*c*F^u)), x], x] - Simp[2*(c/q) Int[(f + g*x) ^m*(F^u/(b + q + 2*c*F^u)), x], x]] /; FreeQ[{F, a, b, c, f, g}, x] && EqQ[ v, 2*u] && LinearQ[u, x] && NeQ[b^2 - 4*a*c, 0] && IGtQ[m, 0]
Int[Log[(a_) + (b_.)*((F_)^((e_.)*((c_.) + (d_.)*(x_))))^(n_.)], x_Symbol] :> Simp[1/(d*e*n*Log[F]) Subst[Int[Log[a + b*x]/x, x], x, (F^(e*(c + d*x) ))^n], x] /; FreeQ[{F, a, b, c, d, e, n}, x] && GtQ[a, 0]
Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> Simp[-PolyLog[2 , (-c)*e*x^n]/n, x] /; FreeQ[{c, d, e, n}, x] && EqQ[c*d, 1]
Int[((c_.) + (d_.)*(x_))^(m_.)/((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]), x_Sy mbol] :> Simp[2 Int[(c + d*x)^m*(E^(I*(e + f*x))/(I*b + 2*a*E^(I*(e + f*x )) - I*b*E^(2*I*(e + f*x)))), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ [a^2 - b^2, 0] && IGtQ[m, 0]
Int[(((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*((f_) + (g_.)*(x_))^(m_.))/Sq rt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[1/(c^(m + 1)*Sqrt[d]) Subst[In t[(a + b*x)^n*(c*f + g*Sin[x])^m, x], x, ArcSin[c*x]], x] /; FreeQ[{a, b, c , d, e, f, g, n}, x] && EqQ[c^2*d + e, 0] && IntegerQ[m] && GtQ[d, 0] && (G tQ[m, 0] || IGtQ[n, 0])
Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*((f_) + (g_.)*(x_))^(m_.)*((d_ ) + (e_.)*(x_)^2)^(p_), x_Symbol] :> Simp[Simp[(d + e*x^2)^p/(1 - c^2*x^2)^ p] Int[(f + g*x)^m*(1 - c^2*x^2)^p*(a + b*ArcSin[c*x])^n, x], x] /; FreeQ [{a, b, c, d, e, f, g, n}, x] && EqQ[c^2*d + e, 0] && IntegerQ[m] && Intege rQ[p - 1/2] && !GtQ[d, 0]
Time = 0.49 (sec) , antiderivative size = 508, normalized size of antiderivative = 1.34
method | result | size |
default | \(-\frac {a \ln \left (\frac {-\frac {2 d \left (c^{2} f^{2}-g^{2}\right )}{g^{2}}+\frac {2 c^{2} d f \left (x +\frac {f}{g}\right )}{g}+2 \sqrt {-\frac {d \left (c^{2} f^{2}-g^{2}\right )}{g^{2}}}\, \sqrt {-\left (x +\frac {f}{g}\right )^{2} c^{2} d +\frac {2 c^{2} d f \left (x +\frac {f}{g}\right )}{g}-\frac {d \left (c^{2} f^{2}-g^{2}\right )}{g^{2}}}}{x +\frac {f}{g}}\right )}{g \sqrt {-\frac {d \left (c^{2} f^{2}-g^{2}\right )}{g^{2}}}}-\frac {i b \sqrt {-d \left (c^{2} x^{2}-1\right )}\, \sqrt {-c^{2} f^{2}+g^{2}}\, \sqrt {-c^{2} x^{2}+1}\, \left (i \arcsin \left (c x \right ) \ln \left (\frac {i c f +\left (i c x +\sqrt {-c^{2} x^{2}+1}\right ) g -\sqrt {-c^{2} f^{2}+g^{2}}}{i c f -\sqrt {-c^{2} f^{2}+g^{2}}}\right )-i \arcsin \left (c x \right ) \ln \left (\frac {i c f +\left (i c x +\sqrt {-c^{2} x^{2}+1}\right ) g +\sqrt {-c^{2} f^{2}+g^{2}}}{i c f +\sqrt {-c^{2} f^{2}+g^{2}}}\right )+\operatorname {dilog}\left (\frac {i c f +\left (i c x +\sqrt {-c^{2} x^{2}+1}\right ) g -\sqrt {-c^{2} f^{2}+g^{2}}}{i c f -\sqrt {-c^{2} f^{2}+g^{2}}}\right )-\operatorname {dilog}\left (\frac {i c f +\left (i c x +\sqrt {-c^{2} x^{2}+1}\right ) g +\sqrt {-c^{2} f^{2}+g^{2}}}{i c f +\sqrt {-c^{2} f^{2}+g^{2}}}\right )\right )}{d \left (c^{2} x^{2}-1\right ) \left (c^{2} f^{2}-g^{2}\right )}\) | \(508\) |
parts | \(-\frac {a \ln \left (\frac {-\frac {2 d \left (c^{2} f^{2}-g^{2}\right )}{g^{2}}+\frac {2 c^{2} d f \left (x +\frac {f}{g}\right )}{g}+2 \sqrt {-\frac {d \left (c^{2} f^{2}-g^{2}\right )}{g^{2}}}\, \sqrt {-\left (x +\frac {f}{g}\right )^{2} c^{2} d +\frac {2 c^{2} d f \left (x +\frac {f}{g}\right )}{g}-\frac {d \left (c^{2} f^{2}-g^{2}\right )}{g^{2}}}}{x +\frac {f}{g}}\right )}{g \sqrt {-\frac {d \left (c^{2} f^{2}-g^{2}\right )}{g^{2}}}}-\frac {i b \sqrt {-d \left (c^{2} x^{2}-1\right )}\, \sqrt {-c^{2} f^{2}+g^{2}}\, \sqrt {-c^{2} x^{2}+1}\, \left (i \arcsin \left (c x \right ) \ln \left (\frac {i c f +\left (i c x +\sqrt {-c^{2} x^{2}+1}\right ) g -\sqrt {-c^{2} f^{2}+g^{2}}}{i c f -\sqrt {-c^{2} f^{2}+g^{2}}}\right )-i \arcsin \left (c x \right ) \ln \left (\frac {i c f +\left (i c x +\sqrt {-c^{2} x^{2}+1}\right ) g +\sqrt {-c^{2} f^{2}+g^{2}}}{i c f +\sqrt {-c^{2} f^{2}+g^{2}}}\right )+\operatorname {dilog}\left (\frac {i c f +\left (i c x +\sqrt {-c^{2} x^{2}+1}\right ) g -\sqrt {-c^{2} f^{2}+g^{2}}}{i c f -\sqrt {-c^{2} f^{2}+g^{2}}}\right )-\operatorname {dilog}\left (\frac {i c f +\left (i c x +\sqrt {-c^{2} x^{2}+1}\right ) g +\sqrt {-c^{2} f^{2}+g^{2}}}{i c f +\sqrt {-c^{2} f^{2}+g^{2}}}\right )\right )}{d \left (c^{2} x^{2}-1\right ) \left (c^{2} f^{2}-g^{2}\right )}\) | \(508\) |
-a/g/(-d*(c^2*f^2-g^2)/g^2)^(1/2)*ln((-2*d*(c^2*f^2-g^2)/g^2+2*c^2*d*f/g*( x+f/g)+2*(-d*(c^2*f^2-g^2)/g^2)^(1/2)*(-(x+f/g)^2*c^2*d+2*c^2*d*f/g*(x+f/g )-d*(c^2*f^2-g^2)/g^2)^(1/2))/(x+f/g))-I*b*(-d*(c^2*x^2-1))^(1/2)*(-c^2*f^ 2+g^2)^(1/2)*(-c^2*x^2+1)^(1/2)*(I*arcsin(c*x)*ln((I*c*f+(I*c*x+(-c^2*x^2+ 1)^(1/2))*g-(-c^2*f^2+g^2)^(1/2))/(I*c*f-(-c^2*f^2+g^2)^(1/2)))-I*arcsin(c *x)*ln((I*c*f+(I*c*x+(-c^2*x^2+1)^(1/2))*g+(-c^2*f^2+g^2)^(1/2))/(I*c*f+(- c^2*f^2+g^2)^(1/2)))+dilog((I*c*f+(I*c*x+(-c^2*x^2+1)^(1/2))*g-(-c^2*f^2+g ^2)^(1/2))/(I*c*f-(-c^2*f^2+g^2)^(1/2)))-dilog((I*c*f+(I*c*x+(-c^2*x^2+1)^ (1/2))*g+(-c^2*f^2+g^2)^(1/2))/(I*c*f+(-c^2*f^2+g^2)^(1/2))))/d/(c^2*x^2-1 )/(c^2*f^2-g^2)
\[ \int \frac {a+b \arcsin (c x)}{(f+g x) \sqrt {d-c^2 d x^2}} \, dx=\int { \frac {b \arcsin \left (c x\right ) + a}{\sqrt {-c^{2} d x^{2} + d} {\left (g x + f\right )}} \,d x } \]
integral(-sqrt(-c^2*d*x^2 + d)*(b*arcsin(c*x) + a)/(c^2*d*g*x^3 + c^2*d*f* x^2 - d*g*x - d*f), x)
\[ \int \frac {a+b \arcsin (c x)}{(f+g x) \sqrt {d-c^2 d x^2}} \, dx=\int \frac {a + b \operatorname {asin}{\left (c x \right )}}{\sqrt {- d \left (c x - 1\right ) \left (c x + 1\right )} \left (f + g x\right )}\, dx \]
\[ \int \frac {a+b \arcsin (c x)}{(f+g x) \sqrt {d-c^2 d x^2}} \, dx=\int { \frac {b \arcsin \left (c x\right ) + a}{\sqrt {-c^{2} d x^{2} + d} {\left (g x + f\right )}} \,d x } \]
Exception generated. \[ \int \frac {a+b \arcsin (c x)}{(f+g x) \sqrt {d-c^2 d x^2}} \, dx=\text {Exception raised: TypeError} \]
Exception raised: TypeError >> an error occurred running a Giac command:IN PUT:sage2:=int(sage0,sageVARx):;OUTPUT:index.cc index_m i_lex_is_greater E rror: Bad Argument Value
Timed out. \[ \int \frac {a+b \arcsin (c x)}{(f+g x) \sqrt {d-c^2 d x^2}} \, dx=\int \frac {a+b\,\mathrm {asin}\left (c\,x\right )}{\left (f+g\,x\right )\,\sqrt {d-c^2\,d\,x^2}} \,d x \]