Integrand size = 12, antiderivative size = 173 \[ \int \frac {1}{(a+b \text {sech}(c+d x))^3} \, dx=\frac {x}{a^3}-\frac {b \left (6 a^4-5 a^2 b^2+2 b^4\right ) \arctan \left (\frac {\sqrt {a-b} \tanh \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a+b}}\right )}{a^3 (a-b)^{5/2} (a+b)^{5/2} d}+\frac {b^2 \tanh (c+d x)}{2 a \left (a^2-b^2\right ) d (a+b \text {sech}(c+d x))^2}+\frac {b^2 \left (5 a^2-2 b^2\right ) \tanh (c+d x)}{2 a^2 \left (a^2-b^2\right )^2 d (a+b \text {sech}(c+d x))} \]
x/a^3-b*(6*a^4-5*a^2*b^2+2*b^4)*arctan((a-b)^(1/2)*tanh(1/2*d*x+1/2*c)/(a+ b)^(1/2))/a^3/(a-b)^(5/2)/(a+b)^(5/2)/d+1/2*b^2*tanh(d*x+c)/a/(a^2-b^2)/d/ (a+b*sech(d*x+c))^2+1/2*b^2*(5*a^2-2*b^2)*tanh(d*x+c)/a^2/(a^2-b^2)^2/d/(a +b*sech(d*x+c))
Time = 1.14 (sec) , antiderivative size = 205, normalized size of antiderivative = 1.18 \[ \int \frac {1}{(a+b \text {sech}(c+d x))^3} \, dx=\frac {(b+a \cosh (c+d x)) \text {sech}^3(c+d x) \left (2 (c+d x) (b+a \cosh (c+d x))^2+\frac {2 b \left (6 a^4-5 a^2 b^2+2 b^4\right ) \arctan \left (\frac {(-a+b) \tanh \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right ) (b+a \cosh (c+d x))^2}{\left (a^2-b^2\right )^{5/2}}+\frac {a b^3 \sinh (c+d x)}{(-a+b) (a+b)}+\frac {3 a b^2 \left (2 a^2-b^2\right ) (b+a \cosh (c+d x)) \sinh (c+d x)}{(a-b)^2 (a+b)^2}\right )}{2 a^3 d (a+b \text {sech}(c+d x))^3} \]
((b + a*Cosh[c + d*x])*Sech[c + d*x]^3*(2*(c + d*x)*(b + a*Cosh[c + d*x])^ 2 + (2*b*(6*a^4 - 5*a^2*b^2 + 2*b^4)*ArcTan[((-a + b)*Tanh[(c + d*x)/2])/S qrt[a^2 - b^2]]*(b + a*Cosh[c + d*x])^2)/(a^2 - b^2)^(5/2) + (a*b^3*Sinh[c + d*x])/((-a + b)*(a + b)) + (3*a*b^2*(2*a^2 - b^2)*(b + a*Cosh[c + d*x]) *Sinh[c + d*x])/((a - b)^2*(a + b)^2)))/(2*a^3*d*(a + b*Sech[c + d*x])^3)
Time = 1.05 (sec) , antiderivative size = 217, normalized size of antiderivative = 1.25, number of steps used = 14, number of rules used = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.083, Rules used = {3042, 4272, 25, 3042, 4548, 25, 3042, 4407, 3042, 4318, 3042, 3138, 221}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {1}{(a+b \text {sech}(c+d x))^3} \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \frac {1}{\left (a+b \csc \left (i c+i d x+\frac {\pi }{2}\right )\right )^3}dx\) |
| \(\Big \downarrow \) 4272 |
| \(\displaystyle \frac {b^2 \tanh (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))^2}-\frac {\int -\frac {b^2 \text {sech}^2(c+d x)-2 a b \text {sech}(c+d x)+2 \left (a^2-b^2\right )}{(a+b \text {sech}(c+d x))^2}dx}{2 a \left (a^2-b^2\right )}\) |
| \(\Big \downarrow \) 25 |
| \(\displaystyle \frac {\int \frac {b^2 \text {sech}^2(c+d x)-2 a b \text {sech}(c+d x)+2 \left (a^2-b^2\right )}{(a+b \text {sech}(c+d x))^2}dx}{2 a \left (a^2-b^2\right )}+\frac {b^2 \tanh (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {b^2 \tanh (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))^2}+\frac {\int \frac {b^2 \csc \left (i c+i d x+\frac {\pi }{2}\right )^2-2 a b \csc \left (i c+i d x+\frac {\pi }{2}\right )+2 \left (a^2-b^2\right )}{\left (a+b \csc \left (i c+i d x+\frac {\pi }{2}\right )\right )^2}dx}{2 a \left (a^2-b^2\right )}\) |
| \(\Big \downarrow \) 4548 |
| \(\displaystyle \frac {\frac {b^2 \left (5 a^2-2 b^2\right ) \tanh (c+d x)}{a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))}-\frac {\int -\frac {2 \left (a^2-b^2\right )^2-a b \left (4 a^2-b^2\right ) \text {sech}(c+d x)}{a+b \text {sech}(c+d x)}dx}{a \left (a^2-b^2\right )}}{2 a \left (a^2-b^2\right )}+\frac {b^2 \tanh (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))^2}\) |
| \(\Big \downarrow \) 25 |
| \(\displaystyle \frac {\frac {\int \frac {2 \left (a^2-b^2\right )^2-a b \left (4 a^2-b^2\right ) \text {sech}(c+d x)}{a+b \text {sech}(c+d x)}dx}{a \left (a^2-b^2\right )}+\frac {b^2 \left (5 a^2-2 b^2\right ) \tanh (c+d x)}{a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))}}{2 a \left (a^2-b^2\right )}+\frac {b^2 \tanh (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {b^2 \tanh (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))^2}+\frac {\frac {b^2 \left (5 a^2-2 b^2\right ) \tanh (c+d x)}{a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))}+\frac {\int \frac {2 \left (a^2-b^2\right )^2-a b \left (4 a^2-b^2\right ) \csc \left (i c+i d x+\frac {\pi }{2}\right )}{a+b \csc \left (i c+i d x+\frac {\pi }{2}\right )}dx}{a \left (a^2-b^2\right )}}{2 a \left (a^2-b^2\right )}\) |
| \(\Big \downarrow \) 4407 |
| \(\displaystyle \frac {\frac {\frac {2 x \left (a^2-b^2\right )^2}{a}-\frac {b \left (6 a^4-5 a^2 b^2+2 b^4\right ) \int \frac {\text {sech}(c+d x)}{a+b \text {sech}(c+d x)}dx}{a}}{a \left (a^2-b^2\right )}+\frac {b^2 \left (5 a^2-2 b^2\right ) \tanh (c+d x)}{a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))}}{2 a \left (a^2-b^2\right )}+\frac {b^2 \tanh (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {b^2 \tanh (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))^2}+\frac {\frac {b^2 \left (5 a^2-2 b^2\right ) \tanh (c+d x)}{a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))}+\frac {\frac {2 x \left (a^2-b^2\right )^2}{a}-\frac {b \left (6 a^4-5 a^2 b^2+2 b^4\right ) \int \frac {\csc \left (i c+i d x+\frac {\pi }{2}\right )}{a+b \csc \left (i c+i d x+\frac {\pi }{2}\right )}dx}{a}}{a \left (a^2-b^2\right )}}{2 a \left (a^2-b^2\right )}\) |
| \(\Big \downarrow \) 4318 |
| \(\displaystyle \frac {\frac {\frac {2 x \left (a^2-b^2\right )^2}{a}-\frac {\left (6 a^4-5 a^2 b^2+2 b^4\right ) \int \frac {1}{\frac {a \cosh (c+d x)}{b}+1}dx}{a}}{a \left (a^2-b^2\right )}+\frac {b^2 \left (5 a^2-2 b^2\right ) \tanh (c+d x)}{a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))}}{2 a \left (a^2-b^2\right )}+\frac {b^2 \tanh (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {b^2 \tanh (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))^2}+\frac {\frac {b^2 \left (5 a^2-2 b^2\right ) \tanh (c+d x)}{a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))}+\frac {\frac {2 x \left (a^2-b^2\right )^2}{a}-\frac {\left (6 a^4-5 a^2 b^2+2 b^4\right ) \int \frac {1}{\frac {a \sin \left (i c+i d x+\frac {\pi }{2}\right )}{b}+1}dx}{a}}{a \left (a^2-b^2\right )}}{2 a \left (a^2-b^2\right )}\) |
| \(\Big \downarrow \) 3138 |
| \(\displaystyle \frac {b^2 \tanh (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))^2}+\frac {\frac {b^2 \left (5 a^2-2 b^2\right ) \tanh (c+d x)}{a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))}+\frac {\frac {2 x \left (a^2-b^2\right )^2}{a}+\frac {2 i \left (6 a^4-5 a^2 b^2+2 b^4\right ) \int \frac {1}{\frac {a+b}{b}-\left (1-\frac {a}{b}\right ) \tanh ^2\left (\frac {1}{2} (c+d x)\right )}d\left (i \tanh \left (\frac {1}{2} (c+d x)\right )\right )}{a d}}{a \left (a^2-b^2\right )}}{2 a \left (a^2-b^2\right )}\) |
| \(\Big \downarrow \) 221 |
| \(\displaystyle \frac {b^2 \tanh (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))^2}+\frac {\frac {b^2 \left (5 a^2-2 b^2\right ) \tanh (c+d x)}{a d \left (a^2-b^2\right ) (a+b \text {sech}(c+d x))}+\frac {\frac {2 x \left (a^2-b^2\right )^2}{a}-\frac {2 b \left (6 a^4-5 a^2 b^2+2 b^4\right ) \arctan \left (\frac {\sqrt {a-b} \tanh \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a+b}}\right )}{a d \sqrt {a-b} \sqrt {a+b}}}{a \left (a^2-b^2\right )}}{2 a \left (a^2-b^2\right )}\) |
(b^2*Tanh[c + d*x])/(2*a*(a^2 - b^2)*d*(a + b*Sech[c + d*x])^2) + (((2*(a^ 2 - b^2)^2*x)/a - (2*b*(6*a^4 - 5*a^2*b^2 + 2*b^4)*ArcTan[(Sqrt[a - b]*Tan h[(c + d*x)/2])/Sqrt[a + b]])/(a*Sqrt[a - b]*Sqrt[a + b]*d))/(a*(a^2 - b^2 )) + (b^2*(5*a^2 - 2*b^2)*Tanh[c + d*x])/(a*(a^2 - b^2)*d*(a + b*Sech[c + d*x])))/(2*a*(a^2 - b^2))
3.1.93.3.1 Defintions of rubi rules used
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x /Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
Int[((a_) + (b_.)*sin[Pi/2 + (c_.) + (d_.)*(x_)])^(-1), x_Symbol] :> With[{ e = FreeFactors[Tan[(c + d*x)/2], x]}, Simp[2*(e/d) Subst[Int[1/(a + b + (a - b)*e^2*x^2), x], x, Tan[(c + d*x)/2]/e], x]] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2, 0]
Int[(csc[(c_.) + (d_.)*(x_)]*(b_.) + (a_))^(n_), x_Symbol] :> Simp[b^2*Cot[ c + d*x]*((a + b*Csc[c + d*x])^(n + 1)/(a*d*(n + 1)*(a^2 - b^2))), x] + Sim p[1/(a*(n + 1)*(a^2 - b^2)) Int[(a + b*Csc[c + d*x])^(n + 1)*Simp[(a^2 - b^2)*(n + 1) - a*b*(n + 1)*Csc[c + d*x] + b^2*(n + 2)*Csc[c + d*x]^2, x], x ], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && LtQ[n, -1] && Integ erQ[2*n]
Int[csc[(e_.) + (f_.)*(x_)]/(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_)), x_Symbo l] :> Simp[1/b Int[1/(1 + (a/b)*Sin[e + f*x]), x], x] /; FreeQ[{a, b, e, f}, x] && NeQ[a^2 - b^2, 0]
Int[(csc[(e_.) + (f_.)*(x_)]*(d_.) + (c_))/(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_)), x_Symbol] :> Simp[c*(x/a), x] - Simp[(b*c - a*d)/a Int[Csc[e + f* x]/(a + b*Csc[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0]
Int[((A_.) + csc[(e_.) + (f_.)*(x_)]*(B_.) + csc[(e_.) + (f_.)*(x_)]^2*(C_. ))*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_), x_Symbol] :> Simp[(A*b^2 - a*b*B + a^2*C)*Cot[e + f*x]*((a + b*Csc[e + f*x])^(m + 1)/(a*f*(m + 1)*(a^2 - b^2))), x] + Simp[1/(a*(m + 1)*(a^2 - b^2)) Int[(a + b*Csc[e + f*x])^( m + 1)*Simp[A*(a^2 - b^2)*(m + 1) - a*(A*b - a*B + b*C)*(m + 1)*Csc[e + f*x ] + (A*b^2 - a*b*B + a^2*C)*(m + 2)*Csc[e + f*x]^2, x], x], x] /; FreeQ[{a, b, e, f, A, B, C}, x] && NeQ[a^2 - b^2, 0] && LtQ[m, -1]
Time = 0.40 (sec) , antiderivative size = 251, normalized size of antiderivative = 1.45
| method | result | size |
| derivativedivides | \(\frac {-\frac {2 b \left (\frac {-\frac {\left (6 a^{2}+a b -2 b^{2}\right ) a b \tanh \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{2 \left (a -b \right ) \left (a^{2}+2 a b +b^{2}\right )}-\frac {\left (6 a^{2}-a b -2 b^{2}\right ) a b \tanh \left (\frac {d x}{2}+\frac {c}{2}\right )}{2 \left (a +b \right ) \left (a^{2}-2 a b +b^{2}\right )}}{\left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a -\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} b +a +b \right )^{2}}+\frac {\left (6 a^{4}-5 a^{2} b^{2}+2 b^{4}\right ) \arctan \left (\frac {\left (a -b \right ) \tanh \left (\frac {d x}{2}+\frac {c}{2}\right )}{\sqrt {\left (a +b \right ) \left (a -b \right )}}\right )}{2 \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \sqrt {\left (a +b \right ) \left (a -b \right )}}\right )}{a^{3}}+\frac {\ln \left (1+\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a^{3}}-\frac {\ln \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{a^{3}}}{d}\) | \(251\) |
| default | \(\frac {-\frac {2 b \left (\frac {-\frac {\left (6 a^{2}+a b -2 b^{2}\right ) a b \tanh \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{2 \left (a -b \right ) \left (a^{2}+2 a b +b^{2}\right )}-\frac {\left (6 a^{2}-a b -2 b^{2}\right ) a b \tanh \left (\frac {d x}{2}+\frac {c}{2}\right )}{2 \left (a +b \right ) \left (a^{2}-2 a b +b^{2}\right )}}{\left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a -\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} b +a +b \right )^{2}}+\frac {\left (6 a^{4}-5 a^{2} b^{2}+2 b^{4}\right ) \arctan \left (\frac {\left (a -b \right ) \tanh \left (\frac {d x}{2}+\frac {c}{2}\right )}{\sqrt {\left (a +b \right ) \left (a -b \right )}}\right )}{2 \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \sqrt {\left (a +b \right ) \left (a -b \right )}}\right )}{a^{3}}+\frac {\ln \left (1+\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a^{3}}-\frac {\ln \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{a^{3}}}{d}\) | \(251\) |
| risch | \(\frac {x}{a^{3}}-\frac {b^{2} \left (7 a^{3} b \,{\mathrm e}^{3 d x +3 c}-4 a \,b^{3} {\mathrm e}^{3 d x +3 c}+6 a^{4} {\mathrm e}^{2 d x +2 c}+9 a^{2} b^{2} {\mathrm e}^{2 d x +2 c}-6 b^{4} {\mathrm e}^{2 d x +2 c}+17 a^{3} b \,{\mathrm e}^{d x +c}-8 \,{\mathrm e}^{d x +c} a \,b^{3}+6 a^{4}-3 a^{2} b^{2}\right )}{a^{3} d \left (a^{2}-b^{2}\right )^{2} \left ({\mathrm e}^{2 d x +2 c} a +2 \,{\mathrm e}^{d x +c} b +a \right )^{2}}-\frac {3 b a \ln \left ({\mathrm e}^{d x +c}+\frac {b \sqrt {-a^{2}+b^{2}}+a^{2}-b^{2}}{\sqrt {-a^{2}+b^{2}}\, a}\right )}{\sqrt {-a^{2}+b^{2}}\, \left (a +b \right )^{2} \left (a -b \right )^{2} d}+\frac {5 b^{3} \ln \left ({\mathrm e}^{d x +c}+\frac {b \sqrt {-a^{2}+b^{2}}+a^{2}-b^{2}}{\sqrt {-a^{2}+b^{2}}\, a}\right )}{2 \sqrt {-a^{2}+b^{2}}\, \left (a +b \right )^{2} \left (a -b \right )^{2} d a}-\frac {b^{5} \ln \left ({\mathrm e}^{d x +c}+\frac {b \sqrt {-a^{2}+b^{2}}+a^{2}-b^{2}}{\sqrt {-a^{2}+b^{2}}\, a}\right )}{\sqrt {-a^{2}+b^{2}}\, \left (a +b \right )^{2} \left (a -b \right )^{2} d \,a^{3}}+\frac {3 b a \ln \left ({\mathrm e}^{d x +c}+\frac {b \sqrt {-a^{2}+b^{2}}-a^{2}+b^{2}}{\sqrt {-a^{2}+b^{2}}\, a}\right )}{\sqrt {-a^{2}+b^{2}}\, \left (a +b \right )^{2} \left (a -b \right )^{2} d}-\frac {5 b^{3} \ln \left ({\mathrm e}^{d x +c}+\frac {b \sqrt {-a^{2}+b^{2}}-a^{2}+b^{2}}{\sqrt {-a^{2}+b^{2}}\, a}\right )}{2 \sqrt {-a^{2}+b^{2}}\, \left (a +b \right )^{2} \left (a -b \right )^{2} d a}+\frac {b^{5} \ln \left ({\mathrm e}^{d x +c}+\frac {b \sqrt {-a^{2}+b^{2}}-a^{2}+b^{2}}{\sqrt {-a^{2}+b^{2}}\, a}\right )}{\sqrt {-a^{2}+b^{2}}\, \left (a +b \right )^{2} \left (a -b \right )^{2} d \,a^{3}}\) | \(631\) |
1/d*(-2*b/a^3*((-1/2*(6*a^2+a*b-2*b^2)*a*b/(a-b)/(a^2+2*a*b+b^2)*tanh(1/2* d*x+1/2*c)^3-1/2*(6*a^2-a*b-2*b^2)*a*b/(a+b)/(a^2-2*a*b+b^2)*tanh(1/2*d*x+ 1/2*c))/(tanh(1/2*d*x+1/2*c)^2*a-tanh(1/2*d*x+1/2*c)^2*b+a+b)^2+1/2*(6*a^4 -5*a^2*b^2+2*b^4)/(a^4-2*a^2*b^2+b^4)/((a+b)*(a-b))^(1/2)*arctan((a-b)*tan h(1/2*d*x+1/2*c)/((a+b)*(a-b))^(1/2)))+1/a^3*ln(1+tanh(1/2*d*x+1/2*c))-1/a ^3*ln(tanh(1/2*d*x+1/2*c)-1))
Leaf count of result is larger than twice the leaf count of optimal. 2000 vs. \(2 (160) = 320\).
Time = 0.32 (sec) , antiderivative size = 4125, normalized size of antiderivative = 23.84 \[ \int \frac {1}{(a+b \text {sech}(c+d x))^3} \, dx=\text {Too large to display} \]
[-1/2*(12*a^6*b^2 - 18*a^4*b^4 + 6*a^2*b^6 - 2*(a^8 - 3*a^6*b^2 + 3*a^4*b^ 4 - a^2*b^6)*d*x*cosh(d*x + c)^4 - 2*(a^8 - 3*a^6*b^2 + 3*a^4*b^4 - a^2*b^ 6)*d*x*sinh(d*x + c)^4 + 2*(7*a^5*b^3 - 11*a^3*b^5 + 4*a*b^7 - 4*(a^7*b - 3*a^5*b^3 + 3*a^3*b^5 - a*b^7)*d*x)*cosh(d*x + c)^3 + 2*(7*a^5*b^3 - 11*a^ 3*b^5 + 4*a*b^7 - 4*(a^8 - 3*a^6*b^2 + 3*a^4*b^4 - a^2*b^6)*d*x*cosh(d*x + c) - 4*(a^7*b - 3*a^5*b^3 + 3*a^3*b^5 - a*b^7)*d*x)*sinh(d*x + c)^3 - 2*( a^8 - 3*a^6*b^2 + 3*a^4*b^4 - a^2*b^6)*d*x + 2*(6*a^6*b^2 + 3*a^4*b^4 - 15 *a^2*b^6 + 6*b^8 - 2*(a^8 - a^6*b^2 - 3*a^4*b^4 + 5*a^2*b^6 - 2*b^8)*d*x)* cosh(d*x + c)^2 + 2*(6*a^6*b^2 + 3*a^4*b^4 - 15*a^2*b^6 + 6*b^8 - 6*(a^8 - 3*a^6*b^2 + 3*a^4*b^4 - a^2*b^6)*d*x*cosh(d*x + c)^2 - 2*(a^8 - a^6*b^2 - 3*a^4*b^4 + 5*a^2*b^6 - 2*b^8)*d*x + 3*(7*a^5*b^3 - 11*a^3*b^5 + 4*a*b^7 - 4*(a^7*b - 3*a^5*b^3 + 3*a^3*b^5 - a*b^7)*d*x)*cosh(d*x + c))*sinh(d*x + c)^2 + (6*a^6*b - 5*a^4*b^3 + 2*a^2*b^5 + (6*a^6*b - 5*a^4*b^3 + 2*a^2*b^ 5)*cosh(d*x + c)^4 + (6*a^6*b - 5*a^4*b^3 + 2*a^2*b^5)*sinh(d*x + c)^4 + 4 *(6*a^5*b^2 - 5*a^3*b^4 + 2*a*b^6)*cosh(d*x + c)^3 + 4*(6*a^5*b^2 - 5*a^3* b^4 + 2*a*b^6 + (6*a^6*b - 5*a^4*b^3 + 2*a^2*b^5)*cosh(d*x + c))*sinh(d*x + c)^3 + 2*(6*a^6*b + 7*a^4*b^3 - 8*a^2*b^5 + 4*b^7)*cosh(d*x + c)^2 + 2*( 6*a^6*b + 7*a^4*b^3 - 8*a^2*b^5 + 4*b^7 + 3*(6*a^6*b - 5*a^4*b^3 + 2*a^2*b ^5)*cosh(d*x + c)^2 + 6*(6*a^5*b^2 - 5*a^3*b^4 + 2*a*b^6)*cosh(d*x + c))*s inh(d*x + c)^2 + 4*(6*a^5*b^2 - 5*a^3*b^4 + 2*a*b^6)*cosh(d*x + c) + 4*...
\[ \int \frac {1}{(a+b \text {sech}(c+d x))^3} \, dx=\int \frac {1}{\left (a + b \operatorname {sech}{\left (c + d x \right )}\right )^{3}}\, dx \]
Exception generated. \[ \int \frac {1}{(a+b \text {sech}(c+d x))^3} \, dx=\text {Exception raised: ValueError} \]
Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'assume' command before evaluation *may* help (example of legal syntax is 'assume(4*b^2-4*a^2>0)', see `assume?` f or more de
Time = 0.30 (sec) , antiderivative size = 261, normalized size of antiderivative = 1.51 \[ \int \frac {1}{(a+b \text {sech}(c+d x))^3} \, dx=-\frac {\frac {{\left (6 \, a^{4} b - 5 \, a^{2} b^{3} + 2 \, b^{5}\right )} \arctan \left (\frac {a e^{\left (d x + c\right )} + b}{\sqrt {a^{2} - b^{2}}}\right )}{{\left (a^{7} - 2 \, a^{5} b^{2} + a^{3} b^{4}\right )} \sqrt {a^{2} - b^{2}}} + \frac {7 \, a^{3} b^{3} e^{\left (3 \, d x + 3 \, c\right )} - 4 \, a b^{5} e^{\left (3 \, d x + 3 \, c\right )} + 6 \, a^{4} b^{2} e^{\left (2 \, d x + 2 \, c\right )} + 9 \, a^{2} b^{4} e^{\left (2 \, d x + 2 \, c\right )} - 6 \, b^{6} e^{\left (2 \, d x + 2 \, c\right )} + 17 \, a^{3} b^{3} e^{\left (d x + c\right )} - 8 \, a b^{5} e^{\left (d x + c\right )} + 6 \, a^{4} b^{2} - 3 \, a^{2} b^{4}}{{\left (a^{7} - 2 \, a^{5} b^{2} + a^{3} b^{4}\right )} {\left (a e^{\left (2 \, d x + 2 \, c\right )} + 2 \, b e^{\left (d x + c\right )} + a\right )}^{2}} - \frac {d x + c}{a^{3}}}{d} \]
-((6*a^4*b - 5*a^2*b^3 + 2*b^5)*arctan((a*e^(d*x + c) + b)/sqrt(a^2 - b^2) )/((a^7 - 2*a^5*b^2 + a^3*b^4)*sqrt(a^2 - b^2)) + (7*a^3*b^3*e^(3*d*x + 3* c) - 4*a*b^5*e^(3*d*x + 3*c) + 6*a^4*b^2*e^(2*d*x + 2*c) + 9*a^2*b^4*e^(2* d*x + 2*c) - 6*b^6*e^(2*d*x + 2*c) + 17*a^3*b^3*e^(d*x + c) - 8*a*b^5*e^(d *x + c) + 6*a^4*b^2 - 3*a^2*b^4)/((a^7 - 2*a^5*b^2 + a^3*b^4)*(a*e^(2*d*x + 2*c) + 2*b*e^(d*x + c) + a)^2) - (d*x + c)/a^3)/d
Timed out. \[ \int \frac {1}{(a+b \text {sech}(c+d x))^3} \, dx=\int \frac {1}{{\left (a+\frac {b}{\mathrm {cosh}\left (c+d\,x\right )}\right )}^3} \,d x \]