3.1.8 \(\int \text {sech}^6(\pi x) \, dx\) [8]

3.1.8.1 Optimal result
3.1.8.2 Mathematica [A] (verified)
3.1.8.3 Rubi [C] (verified)
3.1.8.4 Maple [A] (verified)
3.1.8.5 Fricas [B] (verification not implemented)
3.1.8.6 Sympy [F]
3.1.8.7 Maxima [B] (verification not implemented)
3.1.8.8 Giac [A] (verification not implemented)
3.1.8.9 Mupad [B] (verification not implemented)

3.1.8.1 Optimal result

Integrand size = 6, antiderivative size = 35 \[ \int \text {sech}^6(\pi x) \, dx=\frac {\tanh (\pi x)}{\pi }-\frac {2 \tanh ^3(\pi x)}{3 \pi }+\frac {\tanh ^5(\pi x)}{5 \pi } \]

output
tanh(Pi*x)/Pi-2/3*tanh(Pi*x)^3/Pi+1/5*tanh(Pi*x)^5/Pi
 
3.1.8.2 Mathematica [A] (verified)

Time = 0.01 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.00 \[ \int \text {sech}^6(\pi x) \, dx=\frac {\tanh (\pi x)}{\pi }-\frac {2 \tanh ^3(\pi x)}{3 \pi }+\frac {\tanh ^5(\pi x)}{5 \pi } \]

input
Integrate[Sech[Pi*x]^6,x]
 
output
Tanh[Pi*x]/Pi - (2*Tanh[Pi*x]^3)/(3*Pi) + Tanh[Pi*x]^5/(5*Pi)
 
3.1.8.3 Rubi [C] (verified)

Result contains complex when optimal does not.

Time = 0.20 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.14, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {3042, 4254, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \text {sech}^6(\pi x) \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \csc \left (\frac {\pi }{2}+i \pi x\right )^6dx\)

\(\Big \downarrow \) 4254

\(\displaystyle \frac {i \int \left (\tanh ^4(\pi x)-2 \tanh ^2(\pi x)+1\right )d(-i \tanh (\pi x))}{\pi }\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {i \left (-\frac {1}{5} i \tanh ^5(\pi x)+\frac {2}{3} i \tanh ^3(\pi x)-i \tanh (\pi x)\right )}{\pi }\)

input
Int[Sech[Pi*x]^6,x]
 
output
(I*((-I)*Tanh[Pi*x] + ((2*I)/3)*Tanh[Pi*x]^3 - (I/5)*Tanh[Pi*x]^5))/Pi
 

3.1.8.3.1 Defintions of rubi rules used

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 4254
Int[csc[(c_.) + (d_.)*(x_)]^(n_), x_Symbol] :> Simp[-d^(-1)   Subst[Int[Exp 
andIntegrand[(1 + x^2)^(n/2 - 1), x], x], x, Cot[c + d*x]], x] /; FreeQ[{c, 
 d}, x] && IGtQ[n/2, 0]
 
3.1.8.4 Maple [A] (verified)

Time = 0.77 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.77

method result size
derivativedivides \(\frac {\left (\frac {8}{15}+\frac {\operatorname {sech}\left (\pi x \right )^{4}}{5}+\frac {4 \operatorname {sech}\left (\pi x \right )^{2}}{15}\right ) \tanh \left (\pi x \right )}{\pi }\) \(27\)
default \(\frac {\left (\frac {8}{15}+\frac {\operatorname {sech}\left (\pi x \right )^{4}}{5}+\frac {4 \operatorname {sech}\left (\pi x \right )^{2}}{15}\right ) \tanh \left (\pi x \right )}{\pi }\) \(27\)
risch \(-\frac {16 \left (10 \,{\mathrm e}^{4 \pi x}+5 \,{\mathrm e}^{2 \pi x}+1\right )}{15 \pi \left ({\mathrm e}^{2 \pi x}+1\right )^{5}}\) \(31\)
parallelrisch \(\frac {2 \tanh \left (\frac {\pi x}{2}\right )+2 \tanh \left (\frac {\pi x}{2}\right )^{9}+\frac {116 \tanh \left (\frac {\pi x}{2}\right )^{5}}{15}+\frac {8 \tanh \left (\frac {\pi x}{2}\right )^{3}}{3}+\frac {8 \tanh \left (\frac {\pi x}{2}\right )^{7}}{3}}{\pi \left (1+\tanh \left (\frac {\pi x}{2}\right )^{2}\right )^{5}}\) \(61\)

input
int(sech(Pi*x)^6,x,method=_RETURNVERBOSE)
 
output
1/Pi*(8/15+1/5*sech(Pi*x)^4+4/15*sech(Pi*x)^2)*tanh(Pi*x)
 
3.1.8.5 Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 280 vs. \(2 (31) = 62\).

Time = 0.27 (sec) , antiderivative size = 280, normalized size of antiderivative = 8.00 \[ \int \text {sech}^6(\pi x) \, dx=-\frac {16 \, {\left (11 \, \cosh \left (\pi x\right )^{2} + 18 \, \cosh \left (\pi x\right ) \sinh \left (\pi x\right ) + 11 \, \sinh \left (\pi x\right )^{2} + 5\right )}}{15 \, {\left (5 \, \pi + \pi \cosh \left (\pi x\right )^{8} + 8 \, \pi \cosh \left (\pi x\right ) \sinh \left (\pi x\right )^{7} + \pi \sinh \left (\pi x\right )^{8} + 5 \, \pi \cosh \left (\pi x\right )^{6} + {\left (5 \, \pi + 28 \, \pi \cosh \left (\pi x\right )^{2}\right )} \sinh \left (\pi x\right )^{6} + 2 \, {\left (28 \, \pi \cosh \left (\pi x\right )^{3} + 15 \, \pi \cosh \left (\pi x\right )\right )} \sinh \left (\pi x\right )^{5} + 10 \, \pi \cosh \left (\pi x\right )^{4} + 5 \, {\left (2 \, \pi + 14 \, \pi \cosh \left (\pi x\right )^{4} + 15 \, \pi \cosh \left (\pi x\right )^{2}\right )} \sinh \left (\pi x\right )^{4} + 4 \, {\left (14 \, \pi \cosh \left (\pi x\right )^{5} + 25 \, \pi \cosh \left (\pi x\right )^{3} + 10 \, \pi \cosh \left (\pi x\right )\right )} \sinh \left (\pi x\right )^{3} + 11 \, \pi \cosh \left (\pi x\right )^{2} + {\left (11 \, \pi + 28 \, \pi \cosh \left (\pi x\right )^{6} + 75 \, \pi \cosh \left (\pi x\right )^{4} + 60 \, \pi \cosh \left (\pi x\right )^{2}\right )} \sinh \left (\pi x\right )^{2} + 2 \, {\left (4 \, \pi \cosh \left (\pi x\right )^{7} + 15 \, \pi \cosh \left (\pi x\right )^{5} + 20 \, \pi \cosh \left (\pi x\right )^{3} + 9 \, \pi \cosh \left (\pi x\right )\right )} \sinh \left (\pi x\right )\right )}} \]

input
integrate(sech(pi*x)^6,x, algorithm="fricas")
 
output
-16/15*(11*cosh(pi*x)^2 + 18*cosh(pi*x)*sinh(pi*x) + 11*sinh(pi*x)^2 + 5)/ 
(5*pi + pi*cosh(pi*x)^8 + 8*pi*cosh(pi*x)*sinh(pi*x)^7 + pi*sinh(pi*x)^8 + 
 5*pi*cosh(pi*x)^6 + (5*pi + 28*pi*cosh(pi*x)^2)*sinh(pi*x)^6 + 2*(28*pi*c 
osh(pi*x)^3 + 15*pi*cosh(pi*x))*sinh(pi*x)^5 + 10*pi*cosh(pi*x)^4 + 5*(2*p 
i + 14*pi*cosh(pi*x)^4 + 15*pi*cosh(pi*x)^2)*sinh(pi*x)^4 + 4*(14*pi*cosh( 
pi*x)^5 + 25*pi*cosh(pi*x)^3 + 10*pi*cosh(pi*x))*sinh(pi*x)^3 + 11*pi*cosh 
(pi*x)^2 + (11*pi + 28*pi*cosh(pi*x)^6 + 75*pi*cosh(pi*x)^4 + 60*pi*cosh(p 
i*x)^2)*sinh(pi*x)^2 + 2*(4*pi*cosh(pi*x)^7 + 15*pi*cosh(pi*x)^5 + 20*pi*c 
osh(pi*x)^3 + 9*pi*cosh(pi*x))*sinh(pi*x))
 
3.1.8.6 Sympy [F]

\[ \int \text {sech}^6(\pi x) \, dx=\int \operatorname {sech}^{6}{\left (\pi x \right )}\, dx \]

input
integrate(sech(pi*x)**6,x)
 
output
Integral(sech(pi*x)**6, x)
 
3.1.8.7 Maxima [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 137 vs. \(2 (31) = 62\).

Time = 0.19 (sec) , antiderivative size = 137, normalized size of antiderivative = 3.91 \[ \int \text {sech}^6(\pi x) \, dx=\frac {16 \, e^{\left (-2 \, \pi x\right )}}{3 \, \pi {\left (5 \, e^{\left (-2 \, \pi x\right )} + 10 \, e^{\left (-4 \, \pi x\right )} + 10 \, e^{\left (-6 \, \pi x\right )} + 5 \, e^{\left (-8 \, \pi x\right )} + e^{\left (-10 \, \pi x\right )} + 1\right )}} + \frac {32 \, e^{\left (-4 \, \pi x\right )}}{3 \, \pi {\left (5 \, e^{\left (-2 \, \pi x\right )} + 10 \, e^{\left (-4 \, \pi x\right )} + 10 \, e^{\left (-6 \, \pi x\right )} + 5 \, e^{\left (-8 \, \pi x\right )} + e^{\left (-10 \, \pi x\right )} + 1\right )}} + \frac {16}{15 \, \pi {\left (5 \, e^{\left (-2 \, \pi x\right )} + 10 \, e^{\left (-4 \, \pi x\right )} + 10 \, e^{\left (-6 \, \pi x\right )} + 5 \, e^{\left (-8 \, \pi x\right )} + e^{\left (-10 \, \pi x\right )} + 1\right )}} \]

input
integrate(sech(pi*x)^6,x, algorithm="maxima")
 
output
16/3*e^(-2*pi*x)/(pi*(5*e^(-2*pi*x) + 10*e^(-4*pi*x) + 10*e^(-6*pi*x) + 5* 
e^(-8*pi*x) + e^(-10*pi*x) + 1)) + 32/3*e^(-4*pi*x)/(pi*(5*e^(-2*pi*x) + 1 
0*e^(-4*pi*x) + 10*e^(-6*pi*x) + 5*e^(-8*pi*x) + e^(-10*pi*x) + 1)) + 16/1 
5/(pi*(5*e^(-2*pi*x) + 10*e^(-4*pi*x) + 10*e^(-6*pi*x) + 5*e^(-8*pi*x) + e 
^(-10*pi*x) + 1))
 
3.1.8.8 Giac [A] (verification not implemented)

Time = 0.27 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.86 \[ \int \text {sech}^6(\pi x) \, dx=-\frac {16 \, {\left (10 \, e^{\left (4 \, \pi x\right )} + 5 \, e^{\left (2 \, \pi x\right )} + 1\right )}}{15 \, \pi {\left (e^{\left (2 \, \pi x\right )} + 1\right )}^{5}} \]

input
integrate(sech(pi*x)^6,x, algorithm="giac")
 
output
-16/15*(10*e^(4*pi*x) + 5*e^(2*pi*x) + 1)/(pi*(e^(2*pi*x) + 1)^5)
 
3.1.8.9 Mupad [B] (verification not implemented)

Time = 2.07 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.86 \[ \int \text {sech}^6(\pi x) \, dx=-\frac {16\,\left (5\,{\mathrm {e}}^{2\,\Pi \,x}+10\,{\mathrm {e}}^{4\,\Pi \,x}+1\right )}{15\,\Pi \,{\left ({\mathrm {e}}^{2\,\Pi \,x}+1\right )}^5} \]

input
int(1/cosh(Pi*x)^6,x)
 
output
-(16*(5*exp(2*Pi*x) + 10*exp(4*Pi*x) + 1))/(15*Pi*(exp(2*Pi*x) + 1)^5)