3.1.57 \(\int \frac {\sinh ^{\frac {7}{3}}(a+b x)}{\cosh ^{\frac {7}{3}}(a+b x)} \, dx\) [57]

3.1.57.1 Optimal result
3.1.57.2 Mathematica [C] (verified)
3.1.57.3 Rubi [A] (warning: unable to verify)
3.1.57.4 Maple [F]
3.1.57.5 Fricas [B] (verification not implemented)
3.1.57.6 Sympy [F(-1)]
3.1.57.7 Maxima [F]
3.1.57.8 Giac [F]
3.1.57.9 Mupad [F(-1)]

3.1.57.1 Optimal result

Integrand size = 21, antiderivative size = 155 \[ \int \frac {\sinh ^{\frac {7}{3}}(a+b x)}{\cosh ^{\frac {7}{3}}(a+b x)} \, dx=-\frac {\sqrt {3} \arctan \left (\frac {1+\frac {2 \sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}}{\sqrt {3}}\right )}{2 b}-\frac {\log \left (1-\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}\right )}{2 b}+\frac {\log \left (1+\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}+\frac {\sinh ^{\frac {4}{3}}(a+b x)}{\cosh ^{\frac {4}{3}}(a+b x)}\right )}{4 b}-\frac {3 \sinh ^{\frac {4}{3}}(a+b x)}{4 b \cosh ^{\frac {4}{3}}(a+b x)} \]

output
-1/2*ln(1-sinh(b*x+a)^(2/3)/cosh(b*x+a)^(2/3))/b+1/4*ln(1+sinh(b*x+a)^(2/3 
)/cosh(b*x+a)^(2/3)+sinh(b*x+a)^(4/3)/cosh(b*x+a)^(4/3))/b-3/4*sinh(b*x+a) 
^(4/3)/b/cosh(b*x+a)^(4/3)-1/2*arctan(1/3*(1+2*sinh(b*x+a)^(2/3)/cosh(b*x+ 
a)^(2/3))*3^(1/2))*3^(1/2)/b
 
3.1.57.2 Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.

Time = 0.04 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.38 \[ \int \frac {\sinh ^{\frac {7}{3}}(a+b x)}{\cosh ^{\frac {7}{3}}(a+b x)} \, dx=\frac {3 \cosh ^2(a+b x)^{2/3} \operatorname {Hypergeometric2F1}\left (\frac {5}{3},\frac {5}{3},\frac {8}{3},-\sinh ^2(a+b x)\right ) \sinh ^{\frac {10}{3}}(a+b x)}{10 b \cosh ^{\frac {4}{3}}(a+b x)} \]

input
Integrate[Sinh[a + b*x]^(7/3)/Cosh[a + b*x]^(7/3),x]
 
output
(3*(Cosh[a + b*x]^2)^(2/3)*Hypergeometric2F1[5/3, 5/3, 8/3, -Sinh[a + b*x] 
^2]*Sinh[a + b*x]^(10/3))/(10*b*Cosh[a + b*x]^(4/3))
 
3.1.57.3 Rubi [A] (warning: unable to verify)

Time = 0.41 (sec) , antiderivative size = 137, normalized size of antiderivative = 0.88, number of steps used = 13, number of rules used = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.571, Rules used = {3042, 3046, 3042, 3054, 25, 807, 821, 16, 1142, 1083, 217, 1103}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\sinh ^{\frac {7}{3}}(a+b x)}{\cosh ^{\frac {7}{3}}(a+b x)} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {(-i \sin (i a+i b x))^{7/3}}{\cos (i a+i b x)^{7/3}}dx\)

\(\Big \downarrow \) 3046

\(\displaystyle \int \frac {\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}dx-\frac {3 \sinh ^{\frac {4}{3}}(a+b x)}{4 b \cosh ^{\frac {4}{3}}(a+b x)}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {3 \sinh ^{\frac {4}{3}}(a+b x)}{4 b \cosh ^{\frac {4}{3}}(a+b x)}+\int \frac {\sqrt [3]{-i \sin (i a+i b x)}}{\sqrt [3]{\cos (i a+i b x)}}dx\)

\(\Big \downarrow \) 3054

\(\displaystyle -\frac {3 \int -\frac {\tanh (a+b x)}{1-\tanh ^2(a+b x)}d\frac {\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}}{b}-\frac {3 \sinh ^{\frac {4}{3}}(a+b x)}{4 b \cosh ^{\frac {4}{3}}(a+b x)}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {3 \int \frac {\tanh (a+b x)}{1-\tanh ^2(a+b x)}d\frac {\sqrt [3]{\sinh (a+b x)}}{\sqrt [3]{\cosh (a+b x)}}}{b}-\frac {3 \sinh ^{\frac {4}{3}}(a+b x)}{4 b \cosh ^{\frac {4}{3}}(a+b x)}\)

\(\Big \downarrow \) 807

\(\displaystyle \frac {3 \int \frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x) (1-\tanh (a+b x))}d\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}}{2 b}-\frac {3 \sinh ^{\frac {4}{3}}(a+b x)}{4 b \cosh ^{\frac {4}{3}}(a+b x)}\)

\(\Big \downarrow \) 821

\(\displaystyle \frac {3 \left (\frac {1}{3} \int \frac {1}{1-\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}}d\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}-\frac {1}{3} \int \frac {1-\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}}{\frac {2 \sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}+1}d\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}\right )}{2 b}-\frac {3 \sinh ^{\frac {4}{3}}(a+b x)}{4 b \cosh ^{\frac {4}{3}}(a+b x)}\)

\(\Big \downarrow \) 16

\(\displaystyle \frac {3 \left (-\frac {1}{3} \int \frac {1-\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}}{\frac {2 \sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}+1}d\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}-\frac {1}{3} \log \left (1-\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}\right )\right )}{2 b}-\frac {3 \sinh ^{\frac {4}{3}}(a+b x)}{4 b \cosh ^{\frac {4}{3}}(a+b x)}\)

\(\Big \downarrow \) 1142

\(\displaystyle \frac {3 \left (\frac {1}{3} \left (\frac {1}{2} \int 1d\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}-\frac {3}{2} \int \frac {1}{\frac {2 \sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}+1}d\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}\right )-\frac {1}{3} \log \left (1-\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}\right )\right )}{2 b}-\frac {3 \sinh ^{\frac {4}{3}}(a+b x)}{4 b \cosh ^{\frac {4}{3}}(a+b x)}\)

\(\Big \downarrow \) 1083

\(\displaystyle \frac {3 \left (\frac {1}{3} \left (\frac {1}{2} \int 1d\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}+3 \int \frac {1}{-\frac {2 \sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}-4}d\left (\frac {2 \sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}+1\right )\right )-\frac {1}{3} \log \left (1-\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}\right )\right )}{2 b}-\frac {3 \sinh ^{\frac {4}{3}}(a+b x)}{4 b \cosh ^{\frac {4}{3}}(a+b x)}\)

\(\Big \downarrow \) 217

\(\displaystyle \frac {3 \left (\frac {1}{3} \left (\frac {1}{2} \int 1d\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}-\sqrt {3} \arctan \left (\frac {\frac {2 \sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}+1}{\sqrt {3}}\right )\right )-\frac {1}{3} \log \left (1-\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}\right )\right )}{2 b}-\frac {3 \sinh ^{\frac {4}{3}}(a+b x)}{4 b \cosh ^{\frac {4}{3}}(a+b x)}\)

\(\Big \downarrow \) 1103

\(\displaystyle \frac {3 \left (\frac {1}{3} \left (\frac {1}{2} \log \left (\frac {2 \sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}+1\right )-\sqrt {3} \arctan \left (\frac {\frac {2 \sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}+1}{\sqrt {3}}\right )\right )-\frac {1}{3} \log \left (1-\frac {\sinh ^{\frac {2}{3}}(a+b x)}{\cosh ^{\frac {2}{3}}(a+b x)}\right )\right )}{2 b}-\frac {3 \sinh ^{\frac {4}{3}}(a+b x)}{4 b \cosh ^{\frac {4}{3}}(a+b x)}\)

input
Int[Sinh[a + b*x]^(7/3)/Cosh[a + b*x]^(7/3),x]
 
output
(3*(-1/3*Log[1 - Sinh[a + b*x]^(2/3)/Cosh[a + b*x]^(2/3)] + (-(Sqrt[3]*Arc 
Tan[(1 + (2*Sinh[a + b*x]^(2/3))/Cosh[a + b*x]^(2/3))/Sqrt[3]]) + Log[1 + 
(2*Sinh[a + b*x]^(2/3))/Cosh[a + b*x]^(2/3)]/2)/3))/(2*b) - (3*Sinh[a + b* 
x]^(4/3))/(4*b*Cosh[a + b*x]^(4/3))
 

3.1.57.3.1 Defintions of rubi rules used

rule 16
Int[(c_.)/((a_.) + (b_.)*(x_)), x_Symbol] :> Simp[c*(Log[RemoveContent[a + 
b*x, x]]/b), x] /; FreeQ[{a, b, c}, x]
 

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 217
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( 
-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & 
& (LtQ[a, 0] || LtQ[b, 0])
 

rule 807
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = GCD[m 
+ 1, n]}, Simp[1/k   Subst[Int[x^((m + 1)/k - 1)*(a + b*x^(n/k))^p, x], x, 
x^k], x] /; k != 1] /; FreeQ[{a, b, p}, x] && IGtQ[n, 0] && IntegerQ[m]
 

rule 821
Int[(x_)/((a_) + (b_.)*(x_)^3), x_Symbol] :> Simp[-(3*Rt[a, 3]*Rt[b, 3])^(- 
1)   Int[1/(Rt[a, 3] + Rt[b, 3]*x), x], x] + Simp[1/(3*Rt[a, 3]*Rt[b, 3]) 
 Int[(Rt[a, 3] + Rt[b, 3]*x)/(Rt[a, 3]^2 - Rt[a, 3]*Rt[b, 3]*x + Rt[b, 3]^2 
*x^2), x], x] /; FreeQ[{a, b}, x]
 

rule 1083
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Simp[-2   Subst[I 
nt[1/Simp[b^2 - 4*a*c - x^2, x], x], x, b + 2*c*x], x] /; FreeQ[{a, b, c}, 
x]
 

rule 1103
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, 
e}, x] && EqQ[2*c*d - b*e, 0]
 

rule 1142
Int[((d_.) + (e_.)*(x_))/((a_) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[(2*c*d - b*e)/(2*c)   Int[1/(a + b*x + c*x^2), x], x] + Simp[e/(2*c) 
Int[(b + 2*c*x)/(a + b*x + c*x^2), x], x] /; FreeQ[{a, b, c, d, e}, x]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3046
Int[(cos[(e_.) + (f_.)*(x_)]*(b_.))^(n_)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m 
_), x_Symbol] :> Simp[(-a)*(a*Sin[e + f*x])^(m - 1)*((b*Cos[e + f*x])^(n + 
1)/(b*f*(n + 1))), x] + Simp[a^2*((m - 1)/(b^2*(n + 1)))   Int[(a*Sin[e + f 
*x])^(m - 2)*(b*Cos[e + f*x])^(n + 2), x], x] /; FreeQ[{a, b, e, f}, x] && 
GtQ[m, 1] && LtQ[n, -1] && (IntegersQ[2*m, 2*n] || EqQ[m + n, 0])
 

rule 3054
Int[(cos[(e_.) + (f_.)*(x_)]*(b_.))^(n_)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m 
_), x_Symbol] :> With[{k = Denominator[m]}, Simp[k*a*(b/f)   Subst[Int[x^(k 
*(m + 1) - 1)/(a^2 + b^2*x^(2*k)), x], x, (a*Sin[e + f*x])^(1/k)/(b*Cos[e + 
 f*x])^(1/k)], x]] /; FreeQ[{a, b, e, f}, x] && EqQ[m + n, 0] && GtQ[m, 0] 
&& LtQ[m, 1]
 
3.1.57.4 Maple [F]

\[\int \frac {\sinh \left (b x +a \right )^{\frac {7}{3}}}{\cosh \left (b x +a \right )^{\frac {7}{3}}}d x\]

input
int(sinh(b*x+a)^(7/3)/cosh(b*x+a)^(7/3),x)
 
output
int(sinh(b*x+a)^(7/3)/cosh(b*x+a)^(7/3),x)
 
3.1.57.5 Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 1042 vs. \(2 (124) = 248\).

Time = 0.28 (sec) , antiderivative size = 1042, normalized size of antiderivative = 6.72 \[ \int \frac {\sinh ^{\frac {7}{3}}(a+b x)}{\cosh ^{\frac {7}{3}}(a+b x)} \, dx=\text {Too large to display} \]

input
integrate(sinh(b*x+a)^(7/3)/cosh(b*x+a)^(7/3),x, algorithm="fricas")
 
output
-1/4*(2*(sqrt(3)*cosh(b*x + a)^4 + 4*sqrt(3)*cosh(b*x + a)*sinh(b*x + a)^3 
 + sqrt(3)*sinh(b*x + a)^4 + 2*(3*sqrt(3)*cosh(b*x + a)^2 + sqrt(3))*sinh( 
b*x + a)^2 + 2*sqrt(3)*cosh(b*x + a)^2 + 4*(sqrt(3)*cosh(b*x + a)^3 + sqrt 
(3)*cosh(b*x + a))*sinh(b*x + a) + sqrt(3))*arctan(1/3*(sqrt(3)*cosh(b*x + 
 a)^2 + 2*sqrt(3)*cosh(b*x + a)*sinh(b*x + a) + sqrt(3)*sinh(b*x + a)^2 + 
4*(sqrt(3)*cosh(b*x + a) + sqrt(3)*sinh(b*x + a))*cosh(b*x + a)^(1/3)*sinh 
(b*x + a)^(2/3) + sqrt(3))/(cosh(b*x + a)^2 + 2*cosh(b*x + a)*sinh(b*x + a 
) + sinh(b*x + a)^2 + 1)) - (cosh(b*x + a)^4 + 4*cosh(b*x + a)*sinh(b*x + 
a)^3 + sinh(b*x + a)^4 + 2*(3*cosh(b*x + a)^2 + 1)*sinh(b*x + a)^2 + 2*cos 
h(b*x + a)^2 + 4*(cosh(b*x + a)^3 + cosh(b*x + a))*sinh(b*x + a) + 1)*log( 
(cosh(b*x + a)^4 + 4*cosh(b*x + a)*sinh(b*x + a)^3 + sinh(b*x + a)^4 + 2*( 
3*cosh(b*x + a)^2 + 1)*sinh(b*x + a)^2 + 2*cosh(b*x + a)^2 + 2*(cosh(b*x + 
 a)^3 + 3*cosh(b*x + a)*sinh(b*x + a)^2 + sinh(b*x + a)^3 + (3*cosh(b*x + 
a)^2 - 1)*sinh(b*x + a) - cosh(b*x + a))*cosh(b*x + a)^(2/3)*sinh(b*x + a) 
^(1/3) + 2*(cosh(b*x + a)^3 + 3*cosh(b*x + a)*sinh(b*x + a)^2 + sinh(b*x + 
 a)^3 + (3*cosh(b*x + a)^2 + 1)*sinh(b*x + a) + cosh(b*x + a))*cosh(b*x + 
a)^(1/3)*sinh(b*x + a)^(2/3) + 4*(cosh(b*x + a)^3 + cosh(b*x + a))*sinh(b* 
x + a) + 1)/(cosh(b*x + a)^4 + 4*cosh(b*x + a)*sinh(b*x + a)^3 + sinh(b*x 
+ a)^4 + 2*(3*cosh(b*x + a)^2 + 1)*sinh(b*x + a)^2 + 2*cosh(b*x + a)^2 + 4 
*(cosh(b*x + a)^3 + cosh(b*x + a))*sinh(b*x + a) + 1)) + 2*(cosh(b*x + ...
 
3.1.57.6 Sympy [F(-1)]

Timed out. \[ \int \frac {\sinh ^{\frac {7}{3}}(a+b x)}{\cosh ^{\frac {7}{3}}(a+b x)} \, dx=\text {Timed out} \]

input
integrate(sinh(b*x+a)**(7/3)/cosh(b*x+a)**(7/3),x)
 
output
Timed out
 
3.1.57.7 Maxima [F]

\[ \int \frac {\sinh ^{\frac {7}{3}}(a+b x)}{\cosh ^{\frac {7}{3}}(a+b x)} \, dx=\int { \frac {\sinh \left (b x + a\right )^{\frac {7}{3}}}{\cosh \left (b x + a\right )^{\frac {7}{3}}} \,d x } \]

input
integrate(sinh(b*x+a)^(7/3)/cosh(b*x+a)^(7/3),x, algorithm="maxima")
 
output
integrate(sinh(b*x + a)^(7/3)/cosh(b*x + a)^(7/3), x)
 
3.1.57.8 Giac [F]

\[ \int \frac {\sinh ^{\frac {7}{3}}(a+b x)}{\cosh ^{\frac {7}{3}}(a+b x)} \, dx=\int { \frac {\sinh \left (b x + a\right )^{\frac {7}{3}}}{\cosh \left (b x + a\right )^{\frac {7}{3}}} \,d x } \]

input
integrate(sinh(b*x+a)^(7/3)/cosh(b*x+a)^(7/3),x, algorithm="giac")
 
output
integrate(sinh(b*x + a)^(7/3)/cosh(b*x + a)^(7/3), x)
 
3.1.57.9 Mupad [F(-1)]

Timed out. \[ \int \frac {\sinh ^{\frac {7}{3}}(a+b x)}{\cosh ^{\frac {7}{3}}(a+b x)} \, dx=\int \frac {{\mathrm {sinh}\left (a+b\,x\right )}^{7/3}}{{\mathrm {cosh}\left (a+b\,x\right )}^{7/3}} \,d x \]

input
int(sinh(a + b*x)^(7/3)/cosh(a + b*x)^(7/3),x)
 
output
int(sinh(a + b*x)^(7/3)/cosh(a + b*x)^(7/3), x)