Integrand size = 23, antiderivative size = 209 \[ \int \frac {c e+d e x}{(a+b \text {arcsinh}(c+d x))^{5/2}} \, dx=-\frac {2 e (c+d x) \sqrt {1+(c+d x)^2}}{3 b d (a+b \text {arcsinh}(c+d x))^{3/2}}-\frac {4 e}{3 b^2 d \sqrt {a+b \text {arcsinh}(c+d x)}}-\frac {8 e (c+d x)^2}{3 b^2 d \sqrt {a+b \text {arcsinh}(c+d x)}}-\frac {2 e e^{\frac {2 a}{b}} \sqrt {2 \pi } \text {erf}\left (\frac {\sqrt {2} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{3 b^{5/2} d}+\frac {2 e e^{-\frac {2 a}{b}} \sqrt {2 \pi } \text {erfi}\left (\frac {\sqrt {2} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )}{3 b^{5/2} d} \]
-2/3*e*exp(2*a/b)*erf(2^(1/2)*(a+b*arcsinh(d*x+c))^(1/2)/b^(1/2))*2^(1/2)* Pi^(1/2)/b^(5/2)/d+2/3*e*erfi(2^(1/2)*(a+b*arcsinh(d*x+c))^(1/2)/b^(1/2))* 2^(1/2)*Pi^(1/2)/b^(5/2)/d/exp(2*a/b)-2/3*e*(d*x+c)*(1+(d*x+c)^2)^(1/2)/b/ d/(a+b*arcsinh(d*x+c))^(3/2)-4/3*e/b^2/d/(a+b*arcsinh(d*x+c))^(1/2)-8/3*e* (d*x+c)^2/b^2/d/(a+b*arcsinh(d*x+c))^(1/2)
Time = 0.52 (sec) , antiderivative size = 227, normalized size of antiderivative = 1.09 \[ \int \frac {c e+d e x}{(a+b \text {arcsinh}(c+d x))^{5/2}} \, dx=\frac {e e^{-2 \left (\frac {a}{b}+\text {arcsinh}(c+d x)\right )} \left (-4 \sqrt {2} b e^{2 \text {arcsinh}(c+d x)} \left (-\frac {a+b \text {arcsinh}(c+d x)}{b}\right )^{3/2} \Gamma \left (\frac {1}{2},-\frac {2 (a+b \text {arcsinh}(c+d x))}{b}\right )+e^{\frac {2 a}{b}} \left (-4 a+b-4 a e^{4 \text {arcsinh}(c+d x)}-b e^{4 \text {arcsinh}(c+d x)}-4 b \left (1+e^{4 \text {arcsinh}(c+d x)}\right ) \text {arcsinh}(c+d x)+4 \sqrt {2} e^{2 \left (\frac {a}{b}+\text {arcsinh}(c+d x)\right )} \sqrt {\frac {a}{b}+\text {arcsinh}(c+d x)} (a+b \text {arcsinh}(c+d x)) \Gamma \left (\frac {1}{2},\frac {2 (a+b \text {arcsinh}(c+d x))}{b}\right )\right )\right )}{6 b^2 d (a+b \text {arcsinh}(c+d x))^{3/2}} \]
(e*(-4*Sqrt[2]*b*E^(2*ArcSinh[c + d*x])*(-((a + b*ArcSinh[c + d*x])/b))^(3 /2)*Gamma[1/2, (-2*(a + b*ArcSinh[c + d*x]))/b] + E^((2*a)/b)*(-4*a + b - 4*a*E^(4*ArcSinh[c + d*x]) - b*E^(4*ArcSinh[c + d*x]) - 4*b*(1 + E^(4*ArcS inh[c + d*x]))*ArcSinh[c + d*x] + 4*Sqrt[2]*E^(2*(a/b + ArcSinh[c + d*x])) *Sqrt[a/b + ArcSinh[c + d*x]]*(a + b*ArcSinh[c + d*x])*Gamma[1/2, (2*(a + b*ArcSinh[c + d*x]))/b])))/(6*b^2*d*E^(2*(a/b + ArcSinh[c + d*x]))*(a + b* ArcSinh[c + d*x])^(3/2))
Result contains complex when optimal does not.
Time = 1.28 (sec) , antiderivative size = 216, normalized size of antiderivative = 1.03, number of steps used = 16, number of rules used = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.652, Rules used = {6274, 27, 6194, 6198, 6233, 6195, 25, 5971, 27, 3042, 26, 3789, 2611, 2633, 2634}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {c e+d e x}{(a+b \text {arcsinh}(c+d x))^{5/2}} \, dx\) |
\(\Big \downarrow \) 6274 |
\(\displaystyle \frac {\int \frac {e (c+d x)}{(a+b \text {arcsinh}(c+d x))^{5/2}}d(c+d x)}{d}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {e \int \frac {c+d x}{(a+b \text {arcsinh}(c+d x))^{5/2}}d(c+d x)}{d}\) |
\(\Big \downarrow \) 6194 |
\(\displaystyle \frac {e \left (\frac {2 \int \frac {1}{\sqrt {(c+d x)^2+1} (a+b \text {arcsinh}(c+d x))^{3/2}}d(c+d x)}{3 b}+\frac {4 \int \frac {(c+d x)^2}{\sqrt {(c+d x)^2+1} (a+b \text {arcsinh}(c+d x))^{3/2}}d(c+d x)}{3 b}-\frac {2 \sqrt {(c+d x)^2+1} (c+d x)}{3 b (a+b \text {arcsinh}(c+d x))^{3/2}}\right )}{d}\) |
\(\Big \downarrow \) 6198 |
\(\displaystyle \frac {e \left (\frac {4 \int \frac {(c+d x)^2}{\sqrt {(c+d x)^2+1} (a+b \text {arcsinh}(c+d x))^{3/2}}d(c+d x)}{3 b}-\frac {4}{3 b^2 \sqrt {a+b \text {arcsinh}(c+d x)}}-\frac {2 \sqrt {(c+d x)^2+1} (c+d x)}{3 b (a+b \text {arcsinh}(c+d x))^{3/2}}\right )}{d}\) |
\(\Big \downarrow \) 6233 |
\(\displaystyle \frac {e \left (\frac {4 \left (\frac {4 \int \frac {c+d x}{\sqrt {a+b \text {arcsinh}(c+d x)}}d(c+d x)}{b}-\frac {2 (c+d x)^2}{b \sqrt {a+b \text {arcsinh}(c+d x)}}\right )}{3 b}-\frac {4}{3 b^2 \sqrt {a+b \text {arcsinh}(c+d x)}}-\frac {2 \sqrt {(c+d x)^2+1} (c+d x)}{3 b (a+b \text {arcsinh}(c+d x))^{3/2}}\right )}{d}\) |
\(\Big \downarrow \) 6195 |
\(\displaystyle \frac {e \left (\frac {4 \left (\frac {4 \int -\frac {\cosh \left (\frac {a}{b}-\frac {a+b \text {arcsinh}(c+d x)}{b}\right ) \sinh \left (\frac {a}{b}-\frac {a+b \text {arcsinh}(c+d x)}{b}\right )}{\sqrt {a+b \text {arcsinh}(c+d x)}}d(a+b \text {arcsinh}(c+d x))}{b^2}-\frac {2 (c+d x)^2}{b \sqrt {a+b \text {arcsinh}(c+d x)}}\right )}{3 b}-\frac {4}{3 b^2 \sqrt {a+b \text {arcsinh}(c+d x)}}-\frac {2 \sqrt {(c+d x)^2+1} (c+d x)}{3 b (a+b \text {arcsinh}(c+d x))^{3/2}}\right )}{d}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {e \left (\frac {4 \left (-\frac {4 \int \frac {\cosh \left (\frac {a}{b}-\frac {a+b \text {arcsinh}(c+d x)}{b}\right ) \sinh \left (\frac {a}{b}-\frac {a+b \text {arcsinh}(c+d x)}{b}\right )}{\sqrt {a+b \text {arcsinh}(c+d x)}}d(a+b \text {arcsinh}(c+d x))}{b^2}-\frac {2 (c+d x)^2}{b \sqrt {a+b \text {arcsinh}(c+d x)}}\right )}{3 b}-\frac {4}{3 b^2 \sqrt {a+b \text {arcsinh}(c+d x)}}-\frac {2 \sqrt {(c+d x)^2+1} (c+d x)}{3 b (a+b \text {arcsinh}(c+d x))^{3/2}}\right )}{d}\) |
\(\Big \downarrow \) 5971 |
\(\displaystyle \frac {e \left (\frac {4 \left (-\frac {4 \int \frac {\sinh \left (\frac {2 a}{b}-\frac {2 (a+b \text {arcsinh}(c+d x))}{b}\right )}{2 \sqrt {a+b \text {arcsinh}(c+d x)}}d(a+b \text {arcsinh}(c+d x))}{b^2}-\frac {2 (c+d x)^2}{b \sqrt {a+b \text {arcsinh}(c+d x)}}\right )}{3 b}-\frac {4}{3 b^2 \sqrt {a+b \text {arcsinh}(c+d x)}}-\frac {2 \sqrt {(c+d x)^2+1} (c+d x)}{3 b (a+b \text {arcsinh}(c+d x))^{3/2}}\right )}{d}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {e \left (\frac {4 \left (-\frac {2 \int \frac {\sinh \left (\frac {2 a}{b}-\frac {2 (a+b \text {arcsinh}(c+d x))}{b}\right )}{\sqrt {a+b \text {arcsinh}(c+d x)}}d(a+b \text {arcsinh}(c+d x))}{b^2}-\frac {2 (c+d x)^2}{b \sqrt {a+b \text {arcsinh}(c+d x)}}\right )}{3 b}-\frac {4}{3 b^2 \sqrt {a+b \text {arcsinh}(c+d x)}}-\frac {2 \sqrt {(c+d x)^2+1} (c+d x)}{3 b (a+b \text {arcsinh}(c+d x))^{3/2}}\right )}{d}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {e \left (\frac {4 \left (-\frac {2 (c+d x)^2}{b \sqrt {a+b \text {arcsinh}(c+d x)}}-\frac {2 \int -\frac {i \sin \left (\frac {2 i a}{b}-\frac {2 i (a+b \text {arcsinh}(c+d x))}{b}\right )}{\sqrt {a+b \text {arcsinh}(c+d x)}}d(a+b \text {arcsinh}(c+d x))}{b^2}\right )}{3 b}-\frac {4}{3 b^2 \sqrt {a+b \text {arcsinh}(c+d x)}}-\frac {2 \sqrt {(c+d x)^2+1} (c+d x)}{3 b (a+b \text {arcsinh}(c+d x))^{3/2}}\right )}{d}\) |
\(\Big \downarrow \) 26 |
\(\displaystyle \frac {e \left (\frac {4 \left (-\frac {2 (c+d x)^2}{b \sqrt {a+b \text {arcsinh}(c+d x)}}+\frac {2 i \int \frac {\sin \left (\frac {2 i a}{b}-\frac {2 i (a+b \text {arcsinh}(c+d x))}{b}\right )}{\sqrt {a+b \text {arcsinh}(c+d x)}}d(a+b \text {arcsinh}(c+d x))}{b^2}\right )}{3 b}-\frac {4}{3 b^2 \sqrt {a+b \text {arcsinh}(c+d x)}}-\frac {2 \sqrt {(c+d x)^2+1} (c+d x)}{3 b (a+b \text {arcsinh}(c+d x))^{3/2}}\right )}{d}\) |
\(\Big \downarrow \) 3789 |
\(\displaystyle \frac {e \left (\frac {4 \left (-\frac {2 (c+d x)^2}{b \sqrt {a+b \text {arcsinh}(c+d x)}}+\frac {2 i \left (\frac {1}{2} i \int \frac {e^{\frac {2 (a-c-d x)}{b}}}{\sqrt {a+b \text {arcsinh}(c+d x)}}d(a+b \text {arcsinh}(c+d x))-\frac {1}{2} i \int \frac {e^{-\frac {2 (a-c-d x)}{b}}}{\sqrt {a+b \text {arcsinh}(c+d x)}}d(a+b \text {arcsinh}(c+d x))\right )}{b^2}\right )}{3 b}-\frac {4}{3 b^2 \sqrt {a+b \text {arcsinh}(c+d x)}}-\frac {2 \sqrt {(c+d x)^2+1} (c+d x)}{3 b (a+b \text {arcsinh}(c+d x))^{3/2}}\right )}{d}\) |
\(\Big \downarrow \) 2611 |
\(\displaystyle \frac {e \left (\frac {4 \left (-\frac {2 (c+d x)^2}{b \sqrt {a+b \text {arcsinh}(c+d x)}}+\frac {2 i \left (i \int e^{\frac {2 a}{b}-\frac {2 (a+b \text {arcsinh}(c+d x))}{b}}d\sqrt {a+b \text {arcsinh}(c+d x)}-i \int e^{\frac {2 (a+b \text {arcsinh}(c+d x))}{b}-\frac {2 a}{b}}d\sqrt {a+b \text {arcsinh}(c+d x)}\right )}{b^2}\right )}{3 b}-\frac {4}{3 b^2 \sqrt {a+b \text {arcsinh}(c+d x)}}-\frac {2 \sqrt {(c+d x)^2+1} (c+d x)}{3 b (a+b \text {arcsinh}(c+d x))^{3/2}}\right )}{d}\) |
\(\Big \downarrow \) 2633 |
\(\displaystyle \frac {e \left (\frac {4 \left (-\frac {2 (c+d x)^2}{b \sqrt {a+b \text {arcsinh}(c+d x)}}+\frac {2 i \left (i \int e^{\frac {2 a}{b}-\frac {2 (a+b \text {arcsinh}(c+d x))}{b}}d\sqrt {a+b \text {arcsinh}(c+d x)}-\frac {1}{2} i \sqrt {\frac {\pi }{2}} \sqrt {b} e^{-\frac {2 a}{b}} \text {erfi}\left (\frac {\sqrt {2} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )\right )}{b^2}\right )}{3 b}-\frac {4}{3 b^2 \sqrt {a+b \text {arcsinh}(c+d x)}}-\frac {2 \sqrt {(c+d x)^2+1} (c+d x)}{3 b (a+b \text {arcsinh}(c+d x))^{3/2}}\right )}{d}\) |
\(\Big \downarrow \) 2634 |
\(\displaystyle \frac {e \left (\frac {4 \left (-\frac {2 (c+d x)^2}{b \sqrt {a+b \text {arcsinh}(c+d x)}}+\frac {2 i \left (\frac {1}{2} i \sqrt {\frac {\pi }{2}} \sqrt {b} e^{\frac {2 a}{b}} \text {erf}\left (\frac {\sqrt {2} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )-\frac {1}{2} i \sqrt {\frac {\pi }{2}} \sqrt {b} e^{-\frac {2 a}{b}} \text {erfi}\left (\frac {\sqrt {2} \sqrt {a+b \text {arcsinh}(c+d x)}}{\sqrt {b}}\right )\right )}{b^2}\right )}{3 b}-\frac {4}{3 b^2 \sqrt {a+b \text {arcsinh}(c+d x)}}-\frac {2 \sqrt {(c+d x)^2+1} (c+d x)}{3 b (a+b \text {arcsinh}(c+d x))^{3/2}}\right )}{d}\) |
(e*((-2*(c + d*x)*Sqrt[1 + (c + d*x)^2])/(3*b*(a + b*ArcSinh[c + d*x])^(3/ 2)) - 4/(3*b^2*Sqrt[a + b*ArcSinh[c + d*x]]) + (4*((-2*(c + d*x)^2)/(b*Sqr t[a + b*ArcSinh[c + d*x]]) + ((2*I)*((I/2)*Sqrt[b]*E^((2*a)/b)*Sqrt[Pi/2]* Erf[(Sqrt[2]*Sqrt[a + b*ArcSinh[c + d*x]])/Sqrt[b]] - ((I/2)*Sqrt[b]*Sqrt[ Pi/2]*Erfi[(Sqrt[2]*Sqrt[a + b*ArcSinh[c + d*x]])/Sqrt[b]])/E^((2*a)/b)))/ b^2))/(3*b)))/d
3.3.19.3.1 Defintions of rubi rules used
Int[(Complex[0, a_])*(Fx_), x_Symbol] :> Simp[(Complex[Identity[0], a]) I nt[Fx, x], x] /; FreeQ[a, x] && EqQ[a^2, 1]
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] : > Simp[2/d Subst[Int[F^(g*(e - c*(f/d)) + f*g*(x^2/d)), x], x, Sqrt[c + d *x]], x] /; FreeQ[{F, c, d, e, f, g}, x] && !TrueQ[$UseGamma]
Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[F^a*Sqrt [Pi]*(Erfi[(c + d*x)*Rt[b*Log[F], 2]]/(2*d*Rt[b*Log[F], 2])), x] /; FreeQ[{ F, a, b, c, d}, x] && PosQ[b]
Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[F^a*Sqrt [Pi]*(Erf[(c + d*x)*Rt[(-b)*Log[F], 2]]/(2*d*Rt[(-b)*Log[F], 2])), x] /; Fr eeQ[{F, a, b, c, d}, x] && NegQ[b]
Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + (f_.)*(x_)], x_Symbol] :> Simp[I /2 Int[(c + d*x)^m/E^(I*(e + f*x)), x], x] - Simp[I/2 Int[(c + d*x)^m*E ^(I*(e + f*x)), x], x] /; FreeQ[{c, d, e, f, m}, x]
Int[Cosh[(a_.) + (b_.)*(x_)]^(p_.)*((c_.) + (d_.)*(x_))^(m_.)*Sinh[(a_.) + (b_.)*(x_)]^(n_.), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sinh[a + b*x]^n*Cosh[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n, 0] & & IGtQ[p, 0]
Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Simp[ x^m*Sqrt[1 + c^2*x^2]*((a + b*ArcSinh[c*x])^(n + 1)/(b*c*(n + 1))), x] + (- Simp[c*((m + 1)/(b*(n + 1))) Int[x^(m + 1)*((a + b*ArcSinh[c*x])^(n + 1)/ Sqrt[1 + c^2*x^2]), x], x] - Simp[m/(b*c*(n + 1)) Int[x^(m - 1)*((a + b*A rcSinh[c*x])^(n + 1)/Sqrt[1 + c^2*x^2]), x], x]) /; FreeQ[{a, b, c}, x] && IGtQ[m, 0] && LtQ[n, -2]
Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Simp[ 1/(b*c^(m + 1)) Subst[Int[x^n*Sinh[-a/b + x/b]^m*Cosh[-a/b + x/b], x], x, a + b*ArcSinh[c*x]], x] /; FreeQ[{a, b, c, n}, x] && IGtQ[m, 0]
Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_ Symbol] :> Simp[(1/(b*c*(n + 1)))*Simp[Sqrt[1 + c^2*x^2]/Sqrt[d + e*x^2]]*( a + b*ArcSinh[c*x])^(n + 1), x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ[e, c ^2*d] && NeQ[n, -1]
Int[(((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_)*((f_.)*(x_))^(m_.))/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[((f*x)^m/(b*c*(n + 1)))*Simp[Sqrt[1 + c ^2*x^2]/Sqrt[d + e*x^2]]*(a + b*ArcSinh[c*x])^(n + 1), x] - Simp[f*(m/(b*c* (n + 1)))*Simp[Sqrt[1 + c^2*x^2]/Sqrt[d + e*x^2]] Int[(f*x)^(m - 1)*(a + b*ArcSinh[c*x])^(n + 1), x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && EqQ[e , c^2*d] && LtQ[n, -1]
Int[((a_.) + ArcSinh[(c_) + (d_.)*(x_)]*(b_.))^(n_.)*((e_.) + (f_.)*(x_))^( m_.), x_Symbol] :> Simp[1/d Subst[Int[((d*e - c*f)/d + f*(x/d))^m*(a + b* ArcSinh[x])^n, x], x, c + d*x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x]
\[\int \frac {d e x +c e}{\left (a +b \,\operatorname {arcsinh}\left (d x +c \right )\right )^{\frac {5}{2}}}d x\]
Exception generated. \[ \int \frac {c e+d e x}{(a+b \text {arcsinh}(c+d x))^{5/2}} \, dx=\text {Exception raised: TypeError} \]
Exception raised: TypeError >> Error detected within library code: inte grate: implementation incomplete (constant residues)
\[ \int \frac {c e+d e x}{(a+b \text {arcsinh}(c+d x))^{5/2}} \, dx=e \left (\int \frac {c}{a^{2} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} + 2 a b \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}{\left (c + d x \right )} + b^{2} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}^{2}{\left (c + d x \right )}}\, dx + \int \frac {d x}{a^{2} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} + 2 a b \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}{\left (c + d x \right )} + b^{2} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}^{2}{\left (c + d x \right )}}\, dx\right ) \]
e*(Integral(c/(a**2*sqrt(a + b*asinh(c + d*x)) + 2*a*b*sqrt(a + b*asinh(c + d*x))*asinh(c + d*x) + b**2*sqrt(a + b*asinh(c + d*x))*asinh(c + d*x)**2 ), x) + Integral(d*x/(a**2*sqrt(a + b*asinh(c + d*x)) + 2*a*b*sqrt(a + b*a sinh(c + d*x))*asinh(c + d*x) + b**2*sqrt(a + b*asinh(c + d*x))*asinh(c + d*x)**2), x))
\[ \int \frac {c e+d e x}{(a+b \text {arcsinh}(c+d x))^{5/2}} \, dx=\int { \frac {d e x + c e}{{\left (b \operatorname {arsinh}\left (d x + c\right ) + a\right )}^{\frac {5}{2}}} \,d x } \]
\[ \int \frac {c e+d e x}{(a+b \text {arcsinh}(c+d x))^{5/2}} \, dx=\int { \frac {d e x + c e}{{\left (b \operatorname {arsinh}\left (d x + c\right ) + a\right )}^{\frac {5}{2}}} \,d x } \]
Timed out. \[ \int \frac {c e+d e x}{(a+b \text {arcsinh}(c+d x))^{5/2}} \, dx=\int \frac {c\,e+d\,e\,x}{{\left (a+b\,\mathrm {asinh}\left (c+d\,x\right )\right )}^{5/2}} \,d x \]