Integrand size = 30, antiderivative size = 444 \[ \int \frac {a+b \text {arcsinh}(c x)}{(f+g x)^2 \sqrt {d+c^2 d x^2}} \, dx=-\frac {g \left (1+c^2 x^2\right ) (a+b \text {arcsinh}(c x))}{\left (c^2 f^2+g^2\right ) (f+g x) \sqrt {d+c^2 d x^2}}+\frac {c^2 f \sqrt {1+c^2 x^2} (a+b \text {arcsinh}(c x)) \log \left (1+\frac {e^{\text {arcsinh}(c x)} g}{c f-\sqrt {c^2 f^2+g^2}}\right )}{\left (c^2 f^2+g^2\right )^{3/2} \sqrt {d+c^2 d x^2}}-\frac {c^2 f \sqrt {1+c^2 x^2} (a+b \text {arcsinh}(c x)) \log \left (1+\frac {e^{\text {arcsinh}(c x)} g}{c f+\sqrt {c^2 f^2+g^2}}\right )}{\left (c^2 f^2+g^2\right )^{3/2} \sqrt {d+c^2 d x^2}}+\frac {b c \sqrt {1+c^2 x^2} \log (f+g x)}{\left (c^2 f^2+g^2\right ) \sqrt {d+c^2 d x^2}}+\frac {b c^2 f \sqrt {1+c^2 x^2} \operatorname {PolyLog}\left (2,-\frac {e^{\text {arcsinh}(c x)} g}{c f-\sqrt {c^2 f^2+g^2}}\right )}{\left (c^2 f^2+g^2\right )^{3/2} \sqrt {d+c^2 d x^2}}-\frac {b c^2 f \sqrt {1+c^2 x^2} \operatorname {PolyLog}\left (2,-\frac {e^{\text {arcsinh}(c x)} g}{c f+\sqrt {c^2 f^2+g^2}}\right )}{\left (c^2 f^2+g^2\right )^{3/2} \sqrt {d+c^2 d x^2}} \]
-g*(c^2*x^2+1)*(a+b*arcsinh(c*x))/(c^2*f^2+g^2)/(g*x+f)/(c^2*d*x^2+d)^(1/2 )+b*c*ln(g*x+f)*(c^2*x^2+1)^(1/2)/(c^2*f^2+g^2)/(c^2*d*x^2+d)^(1/2)+c^2*f* (a+b*arcsinh(c*x))*ln(1+(c*x+(c^2*x^2+1)^(1/2))*g/(c*f-(c^2*f^2+g^2)^(1/2) ))*(c^2*x^2+1)^(1/2)/(c^2*f^2+g^2)^(3/2)/(c^2*d*x^2+d)^(1/2)-c^2*f*(a+b*ar csinh(c*x))*ln(1+(c*x+(c^2*x^2+1)^(1/2))*g/(c*f+(c^2*f^2+g^2)^(1/2)))*(c^2 *x^2+1)^(1/2)/(c^2*f^2+g^2)^(3/2)/(c^2*d*x^2+d)^(1/2)+b*c^2*f*polylog(2,-( c*x+(c^2*x^2+1)^(1/2))*g/(c*f-(c^2*f^2+g^2)^(1/2)))*(c^2*x^2+1)^(1/2)/(c^2 *f^2+g^2)^(3/2)/(c^2*d*x^2+d)^(1/2)-b*c^2*f*polylog(2,-(c*x+(c^2*x^2+1)^(1 /2))*g/(c*f+(c^2*f^2+g^2)^(1/2)))*(c^2*x^2+1)^(1/2)/(c^2*f^2+g^2)^(3/2)/(c ^2*d*x^2+d)^(1/2)
Time = 0.41 (sec) , antiderivative size = 251, normalized size of antiderivative = 0.57 \[ \int \frac {a+b \text {arcsinh}(c x)}{(f+g x)^2 \sqrt {d+c^2 d x^2}} \, dx=\frac {c \sqrt {1+c^2 x^2} \left (-\frac {g \sqrt {1+c^2 x^2} (a+b \text {arcsinh}(c x))}{c f+c g x}+b \log (f+g x)+\frac {c f \left ((a+b \text {arcsinh}(c x)) \left (\log \left (1+\frac {e^{\text {arcsinh}(c x)} g}{c f-\sqrt {c^2 f^2+g^2}}\right )-\log \left (1+\frac {e^{\text {arcsinh}(c x)} g}{c f+\sqrt {c^2 f^2+g^2}}\right )\right )+b \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(c x)} g}{-c f+\sqrt {c^2 f^2+g^2}}\right )-b \operatorname {PolyLog}\left (2,-\frac {e^{\text {arcsinh}(c x)} g}{c f+\sqrt {c^2 f^2+g^2}}\right )\right )}{\sqrt {c^2 f^2+g^2}}\right )}{\left (c^2 f^2+g^2\right ) \sqrt {d+c^2 d x^2}} \]
(c*Sqrt[1 + c^2*x^2]*(-((g*Sqrt[1 + c^2*x^2]*(a + b*ArcSinh[c*x]))/(c*f + c*g*x)) + b*Log[f + g*x] + (c*f*((a + b*ArcSinh[c*x])*(Log[1 + (E^ArcSinh[ c*x]*g)/(c*f - Sqrt[c^2*f^2 + g^2])] - Log[1 + (E^ArcSinh[c*x]*g)/(c*f + S qrt[c^2*f^2 + g^2])]) + b*PolyLog[2, (E^ArcSinh[c*x]*g)/(-(c*f) + Sqrt[c^2 *f^2 + g^2])] - b*PolyLog[2, -((E^ArcSinh[c*x]*g)/(c*f + Sqrt[c^2*f^2 + g^ 2]))]))/Sqrt[c^2*f^2 + g^2]))/((c^2*f^2 + g^2)*Sqrt[d + c^2*d*x^2])
Time = 1.35 (sec) , antiderivative size = 327, normalized size of antiderivative = 0.74, number of steps used = 14, number of rules used = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.433, Rules used = {6260, 6258, 3042, 3805, 3042, 3147, 16, 3803, 2694, 27, 2620, 2715, 2838}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {a+b \text {arcsinh}(c x)}{\sqrt {c^2 d x^2+d} (f+g x)^2} \, dx\) |
\(\Big \downarrow \) 6260 |
\(\displaystyle \frac {\sqrt {c^2 x^2+1} \int \frac {a+b \text {arcsinh}(c x)}{(f+g x)^2 \sqrt {c^2 x^2+1}}dx}{\sqrt {c^2 d x^2+d}}\) |
\(\Big \downarrow \) 6258 |
\(\displaystyle \frac {c \sqrt {c^2 x^2+1} \int \frac {a+b \text {arcsinh}(c x)}{(c f+c g x)^2}d\text {arcsinh}(c x)}{\sqrt {c^2 d x^2+d}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {c \sqrt {c^2 x^2+1} \int \frac {a+b \text {arcsinh}(c x)}{(c f-i g \sin (i \text {arcsinh}(c x)))^2}d\text {arcsinh}(c x)}{\sqrt {c^2 d x^2+d}}\) |
\(\Big \downarrow \) 3805 |
\(\displaystyle \frac {c \sqrt {c^2 x^2+1} \left (\frac {c f \int \frac {a+b \text {arcsinh}(c x)}{c f+c g x}d\text {arcsinh}(c x)}{c^2 f^2+g^2}+\frac {b g \int \frac {\sqrt {c^2 x^2+1}}{c f+c g x}d\text {arcsinh}(c x)}{c^2 f^2+g^2}-\frac {g \sqrt {c^2 x^2+1} (a+b \text {arcsinh}(c x))}{\left (c^2 f^2+g^2\right ) (c f+c g x)}\right )}{\sqrt {c^2 d x^2+d}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {c \sqrt {c^2 x^2+1} \left (\frac {c f \int \frac {a+b \text {arcsinh}(c x)}{c f-i g \sin (i \text {arcsinh}(c x))}d\text {arcsinh}(c x)}{c^2 f^2+g^2}+\frac {b g \int \frac {\cos (i \text {arcsinh}(c x))}{c f-i g \sin (i \text {arcsinh}(c x))}d\text {arcsinh}(c x)}{c^2 f^2+g^2}-\frac {g \sqrt {c^2 x^2+1} (a+b \text {arcsinh}(c x))}{\left (c^2 f^2+g^2\right ) (c f+c g x)}\right )}{\sqrt {c^2 d x^2+d}}\) |
\(\Big \downarrow \) 3147 |
\(\displaystyle \frac {c \sqrt {c^2 x^2+1} \left (\frac {c f \int \frac {a+b \text {arcsinh}(c x)}{c f-i g \sin (i \text {arcsinh}(c x))}d\text {arcsinh}(c x)}{c^2 f^2+g^2}+\frac {b \int \frac {1}{c f+c g x}d(c g x)}{c^2 f^2+g^2}-\frac {g \sqrt {c^2 x^2+1} (a+b \text {arcsinh}(c x))}{\left (c^2 f^2+g^2\right ) (c f+c g x)}\right )}{\sqrt {c^2 d x^2+d}}\) |
\(\Big \downarrow \) 16 |
\(\displaystyle \frac {c \sqrt {c^2 x^2+1} \left (\frac {c f \int \frac {a+b \text {arcsinh}(c x)}{c f-i g \sin (i \text {arcsinh}(c x))}d\text {arcsinh}(c x)}{c^2 f^2+g^2}-\frac {g \sqrt {c^2 x^2+1} (a+b \text {arcsinh}(c x))}{\left (c^2 f^2+g^2\right ) (c f+c g x)}+\frac {b \log (c f+c g x)}{c^2 f^2+g^2}\right )}{\sqrt {c^2 d x^2+d}}\) |
\(\Big \downarrow \) 3803 |
\(\displaystyle \frac {c \sqrt {c^2 x^2+1} \left (\frac {2 c f \int \frac {e^{\text {arcsinh}(c x)} (a+b \text {arcsinh}(c x))}{2 c e^{\text {arcsinh}(c x)} f+e^{2 \text {arcsinh}(c x)} g-g}d\text {arcsinh}(c x)}{c^2 f^2+g^2}-\frac {g \sqrt {c^2 x^2+1} (a+b \text {arcsinh}(c x))}{\left (c^2 f^2+g^2\right ) (c f+c g x)}+\frac {b \log (c f+c g x)}{c^2 f^2+g^2}\right )}{\sqrt {c^2 d x^2+d}}\) |
\(\Big \downarrow \) 2694 |
\(\displaystyle \frac {c \sqrt {c^2 x^2+1} \left (\frac {2 c f \left (\frac {g \int \frac {e^{\text {arcsinh}(c x)} (a+b \text {arcsinh}(c x))}{2 \left (c f+e^{\text {arcsinh}(c x)} g-\sqrt {c^2 f^2+g^2}\right )}d\text {arcsinh}(c x)}{\sqrt {c^2 f^2+g^2}}-\frac {g \int \frac {e^{\text {arcsinh}(c x)} (a+b \text {arcsinh}(c x))}{2 \left (c f+e^{\text {arcsinh}(c x)} g+\sqrt {c^2 f^2+g^2}\right )}d\text {arcsinh}(c x)}{\sqrt {c^2 f^2+g^2}}\right )}{c^2 f^2+g^2}-\frac {g \sqrt {c^2 x^2+1} (a+b \text {arcsinh}(c x))}{\left (c^2 f^2+g^2\right ) (c f+c g x)}+\frac {b \log (c f+c g x)}{c^2 f^2+g^2}\right )}{\sqrt {c^2 d x^2+d}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {c \sqrt {c^2 x^2+1} \left (\frac {2 c f \left (\frac {g \int \frac {e^{\text {arcsinh}(c x)} (a+b \text {arcsinh}(c x))}{c f+e^{\text {arcsinh}(c x)} g-\sqrt {c^2 f^2+g^2}}d\text {arcsinh}(c x)}{2 \sqrt {c^2 f^2+g^2}}-\frac {g \int \frac {e^{\text {arcsinh}(c x)} (a+b \text {arcsinh}(c x))}{c f+e^{\text {arcsinh}(c x)} g+\sqrt {c^2 f^2+g^2}}d\text {arcsinh}(c x)}{2 \sqrt {c^2 f^2+g^2}}\right )}{c^2 f^2+g^2}-\frac {g \sqrt {c^2 x^2+1} (a+b \text {arcsinh}(c x))}{\left (c^2 f^2+g^2\right ) (c f+c g x)}+\frac {b \log (c f+c g x)}{c^2 f^2+g^2}\right )}{\sqrt {c^2 d x^2+d}}\) |
\(\Big \downarrow \) 2620 |
\(\displaystyle \frac {c \sqrt {c^2 x^2+1} \left (\frac {2 c f \left (\frac {g \left (\frac {(a+b \text {arcsinh}(c x)) \log \left (\frac {g e^{\text {arcsinh}(c x)}}{c f-\sqrt {c^2 f^2+g^2}}+1\right )}{g}-\frac {b \int \log \left (\frac {e^{\text {arcsinh}(c x)} g}{c f-\sqrt {c^2 f^2+g^2}}+1\right )d\text {arcsinh}(c x)}{g}\right )}{2 \sqrt {c^2 f^2+g^2}}-\frac {g \left (\frac {(a+b \text {arcsinh}(c x)) \log \left (\frac {g e^{\text {arcsinh}(c x)}}{\sqrt {c^2 f^2+g^2}+c f}+1\right )}{g}-\frac {b \int \log \left (\frac {e^{\text {arcsinh}(c x)} g}{c f+\sqrt {c^2 f^2+g^2}}+1\right )d\text {arcsinh}(c x)}{g}\right )}{2 \sqrt {c^2 f^2+g^2}}\right )}{c^2 f^2+g^2}-\frac {g \sqrt {c^2 x^2+1} (a+b \text {arcsinh}(c x))}{\left (c^2 f^2+g^2\right ) (c f+c g x)}+\frac {b \log (c f+c g x)}{c^2 f^2+g^2}\right )}{\sqrt {c^2 d x^2+d}}\) |
\(\Big \downarrow \) 2715 |
\(\displaystyle \frac {c \sqrt {c^2 x^2+1} \left (\frac {2 c f \left (\frac {g \left (\frac {(a+b \text {arcsinh}(c x)) \log \left (\frac {g e^{\text {arcsinh}(c x)}}{c f-\sqrt {c^2 f^2+g^2}}+1\right )}{g}-\frac {b \int e^{-\text {arcsinh}(c x)} \log \left (\frac {e^{\text {arcsinh}(c x)} g}{c f-\sqrt {c^2 f^2+g^2}}+1\right )de^{\text {arcsinh}(c x)}}{g}\right )}{2 \sqrt {c^2 f^2+g^2}}-\frac {g \left (\frac {(a+b \text {arcsinh}(c x)) \log \left (\frac {g e^{\text {arcsinh}(c x)}}{\sqrt {c^2 f^2+g^2}+c f}+1\right )}{g}-\frac {b \int e^{-\text {arcsinh}(c x)} \log \left (\frac {e^{\text {arcsinh}(c x)} g}{c f+\sqrt {c^2 f^2+g^2}}+1\right )de^{\text {arcsinh}(c x)}}{g}\right )}{2 \sqrt {c^2 f^2+g^2}}\right )}{c^2 f^2+g^2}-\frac {g \sqrt {c^2 x^2+1} (a+b \text {arcsinh}(c x))}{\left (c^2 f^2+g^2\right ) (c f+c g x)}+\frac {b \log (c f+c g x)}{c^2 f^2+g^2}\right )}{\sqrt {c^2 d x^2+d}}\) |
\(\Big \downarrow \) 2838 |
\(\displaystyle \frac {c \sqrt {c^2 x^2+1} \left (\frac {2 c f \left (\frac {g \left (\frac {(a+b \text {arcsinh}(c x)) \log \left (\frac {g e^{\text {arcsinh}(c x)}}{c f-\sqrt {c^2 f^2+g^2}}+1\right )}{g}+\frac {b \operatorname {PolyLog}\left (2,-\frac {e^{\text {arcsinh}(c x)} g}{c f-\sqrt {c^2 f^2+g^2}}\right )}{g}\right )}{2 \sqrt {c^2 f^2+g^2}}-\frac {g \left (\frac {(a+b \text {arcsinh}(c x)) \log \left (\frac {g e^{\text {arcsinh}(c x)}}{\sqrt {c^2 f^2+g^2}+c f}+1\right )}{g}+\frac {b \operatorname {PolyLog}\left (2,-\frac {e^{\text {arcsinh}(c x)} g}{c f+\sqrt {c^2 f^2+g^2}}\right )}{g}\right )}{2 \sqrt {c^2 f^2+g^2}}\right )}{c^2 f^2+g^2}-\frac {g \sqrt {c^2 x^2+1} (a+b \text {arcsinh}(c x))}{\left (c^2 f^2+g^2\right ) (c f+c g x)}+\frac {b \log (c f+c g x)}{c^2 f^2+g^2}\right )}{\sqrt {c^2 d x^2+d}}\) |
(c*Sqrt[1 + c^2*x^2]*(-((g*Sqrt[1 + c^2*x^2]*(a + b*ArcSinh[c*x]))/((c^2*f ^2 + g^2)*(c*f + c*g*x))) + (b*Log[c*f + c*g*x])/(c^2*f^2 + g^2) + (2*c*f* ((g*(((a + b*ArcSinh[c*x])*Log[1 + (E^ArcSinh[c*x]*g)/(c*f - Sqrt[c^2*f^2 + g^2])])/g + (b*PolyLog[2, -((E^ArcSinh[c*x]*g)/(c*f - Sqrt[c^2*f^2 + g^2 ]))])/g))/(2*Sqrt[c^2*f^2 + g^2]) - (g*(((a + b*ArcSinh[c*x])*Log[1 + (E^A rcSinh[c*x]*g)/(c*f + Sqrt[c^2*f^2 + g^2])])/g + (b*PolyLog[2, -((E^ArcSin h[c*x]*g)/(c*f + Sqrt[c^2*f^2 + g^2]))])/g))/(2*Sqrt[c^2*f^2 + g^2])))/(c^ 2*f^2 + g^2)))/Sqrt[d + c^2*d*x^2]
3.1.52.3.1 Defintions of rubi rules used
Int[(c_.)/((a_.) + (b_.)*(x_)), x_Symbol] :> Simp[c*(Log[RemoveContent[a + b*x, x]]/b), x] /; FreeQ[{a, b, c}, x]
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[(((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)*((c_.) + (d_.)*(x_))^(m_.))/ ((a_) + (b_.)*((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)), x_Symbol] :> Simp [((c + d*x)^m/(b*f*g*n*Log[F]))*Log[1 + b*((F^(g*(e + f*x)))^n/a)], x] - Si mp[d*(m/(b*f*g*n*Log[F])) Int[(c + d*x)^(m - 1)*Log[1 + b*((F^(g*(e + f*x )))^n/a)], x], x] /; FreeQ[{F, a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]
Int[((F_)^(u_)*((f_.) + (g_.)*(x_))^(m_.))/((a_.) + (b_.)*(F_)^(u_) + (c_.) *(F_)^(v_)), x_Symbol] :> With[{q = Rt[b^2 - 4*a*c, 2]}, Simp[2*(c/q) Int [(f + g*x)^m*(F^u/(b - q + 2*c*F^u)), x], x] - Simp[2*(c/q) Int[(f + g*x) ^m*(F^u/(b + q + 2*c*F^u)), x], x]] /; FreeQ[{F, a, b, c, f, g}, x] && EqQ[ v, 2*u] && LinearQ[u, x] && NeQ[b^2 - 4*a*c, 0] && IGtQ[m, 0]
Int[Log[(a_) + (b_.)*((F_)^((e_.)*((c_.) + (d_.)*(x_))))^(n_.)], x_Symbol] :> Simp[1/(d*e*n*Log[F]) Subst[Int[Log[a + b*x]/x, x], x, (F^(e*(c + d*x) ))^n], x] /; FreeQ[{F, a, b, c, d, e, n}, x] && GtQ[a, 0]
Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> Simp[-PolyLog[2 , (-c)*e*x^n]/n, x] /; FreeQ[{c, d, e, n}, x] && EqQ[c*d, 1]
Int[cos[(e_.) + (f_.)*(x_)]^(p_.)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m _.), x_Symbol] :> Simp[1/(b^p*f) Subst[Int[(a + x)^m*(b^2 - x^2)^((p - 1) /2), x], x, b*Sin[e + f*x]], x] /; FreeQ[{a, b, e, f, m}, x] && IntegerQ[(p - 1)/2] && NeQ[a^2 - b^2, 0]
Int[((c_.) + (d_.)*(x_))^(m_.)/((a_) + (b_.)*sin[(e_.) + (Complex[0, fz_])* (f_.)*(x_)]), x_Symbol] :> Simp[2 Int[(c + d*x)^m*(E^((-I)*e + f*fz*x)/(( -I)*b + 2*a*E^((-I)*e + f*fz*x) + I*b*E^(2*((-I)*e + f*fz*x)))), x], x] /; FreeQ[{a, b, c, d, e, f, fz}, x] && NeQ[a^2 - b^2, 0] && IGtQ[m, 0]
Int[((c_.) + (d_.)*(x_))^(m_.)/((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^2, x_ Symbol] :> Simp[b*(c + d*x)^m*(Cos[e + f*x]/(f*(a^2 - b^2)*(a + b*Sin[e + f *x]))), x] + (Simp[a/(a^2 - b^2) Int[(c + d*x)^m/(a + b*Sin[e + f*x]), x] , x] - Simp[b*d*(m/(f*(a^2 - b^2))) Int[(c + d*x)^(m - 1)*(Cos[e + f*x]/( a + b*Sin[e + f*x])), x], x]) /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[a^2 - b^2, 0] && IGtQ[m, 0]
Int[(((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*((f_) + (g_.)*(x_))^(m_.))/S qrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[1/(c^(m + 1)*Sqrt[d]) Subst[I nt[(a + b*x)^n*(c*f + g*Sinh[x])^m, x], x, ArcSinh[c*x]], x] /; FreeQ[{a, b , c, d, e, f, g, n}, x] && EqQ[e, c^2*d] && IntegerQ[m] && GtQ[d, 0] && (Gt Q[m, 0] || IGtQ[n, 0])
Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*((f_) + (g_.)*(x_))^(m_.)*((d _) + (e_.)*(x_)^2)^(p_), x_Symbol] :> Simp[Simp[(d + e*x^2)^p/(1 + c^2*x^2) ^p] Int[(f + g*x)^m*(1 + c^2*x^2)^p*(a + b*ArcSinh[c*x])^n, x], x] /; Fre eQ[{a, b, c, d, e, f, g, n}, x] && EqQ[e, c^2*d] && IntegerQ[m] && IntegerQ [p - 1/2] && !GtQ[d, 0]
Leaf count of result is larger than twice the leaf count of optimal. \(1769\) vs. \(2(442)=884\).
Time = 0.85 (sec) , antiderivative size = 1770, normalized size of antiderivative = 3.99
method | result | size |
default | \(\text {Expression too large to display}\) | \(1770\) |
parts | \(\text {Expression too large to display}\) | \(1770\) |
-a/d/(c^2*f^2+g^2)/(x+f/g)*((x+f/g)^2*c^2*d-2*c^2*d*f/g*(x+f/g)+d*(c^2*f^2 +g^2)/g^2)^(1/2)-a/g*c^2*f/(c^2*f^2+g^2)/(d*(c^2*f^2+g^2)/g^2)^(1/2)*ln((2 *d*(c^2*f^2+g^2)/g^2-2*c^2*d*f/g*(x+f/g)+2*(d*(c^2*f^2+g^2)/g^2)^(1/2)*((x +f/g)^2*c^2*d-2*c^2*d*f/g*(x+f/g)+d*(c^2*f^2+g^2)/g^2)^(1/2))/(x+f/g))+b*( d*(c^2*x^2+1))^(1/2)*arcsinh(c*x)/d/(c^2*x^2+1)/(c^2*f^2+g^2)/(g*x+f)*x^3* c^4*f-b*(d*(c^2*x^2+1))^(1/2)*arcsinh(c*x)/d/(c^2*f^2+g^2)/(g*x+f)*x*c^2*f -b*(d*(c^2*x^2+1))^(1/2)*arcsinh(c*x)/d/(c^2*x^2+1)/(c^2*f^2+g^2)/(g*x+f)* x^2*c^2*g+b*(d*(c^2*x^2+1))^(1/2)*arcsinh(c*x)/d/(c^2*x^2+1)^(1/2)/(c^2*f^ 2+g^2)/(g*x+f)*x*c*g+b*(d*(c^2*x^2+1))^(1/2)*arcsinh(c*x)/d/(c^2*x^2+1)/(c ^2*f^2+g^2)/(g*x+f)*x*c^2*f+b*(d*(c^2*x^2+1))^(1/2)*arcsinh(c*x)/d/(c^2*x^ 2+1)^(1/2)/(c^2*f^2+g^2)/(g*x+f)*c*f-b*(d*(c^2*x^2+1))^(1/2)*arcsinh(c*x)/ d/(c^2*x^2+1)/(c^2*f^2+g^2)/(g*x+f)*g+b*(d*(c^2*x^2+1))^(1/2)*(c^2*x^2+1)^ (1/2)/d/(c^6*f^4*x^2+2*c^4*f^2*g^2*x^2+c^4*f^4+c^2*g^4*x^2+2*c^2*f^2*g^2+g ^4)*c^3*ln((c*x+(c^2*x^2+1)^(1/2))^2*g+2*c*f*(c*x+(c^2*x^2+1)^(1/2))-g)*f^ 2-2*b*(d*(c^2*x^2+1))^(1/2)*(c^2*x^2+1)^(1/2)/d/(c^6*f^4*x^2+2*c^4*f^2*g^2 *x^2+c^4*f^4+c^2*g^4*x^2+2*c^2*f^2*g^2+g^4)*c^3*ln(c*x+(c^2*x^2+1)^(1/2))* f^2+b*(d*(c^2*x^2+1))^(1/2)*(c^2*x^2+1)^(1/2)/d/(c^6*f^4*x^2+2*c^4*f^2*g^2 *x^2+c^4*f^4+c^2*g^4*x^2+2*c^2*f^2*g^2+g^4)*c^2*ln((-(c*x+(c^2*x^2+1)^(1/2 ))*g-c*f+(c^2*f^2+g^2)^(1/2))/(-c*f+(c^2*f^2+g^2)^(1/2)))*arcsinh(c*x)*(c^ 2*f^2+g^2)^(1/2)*f-b*(d*(c^2*x^2+1))^(1/2)*(c^2*x^2+1)^(1/2)/d/(c^6*f^4...
\[ \int \frac {a+b \text {arcsinh}(c x)}{(f+g x)^2 \sqrt {d+c^2 d x^2}} \, dx=\int { \frac {b \operatorname {arsinh}\left (c x\right ) + a}{\sqrt {c^{2} d x^{2} + d} {\left (g x + f\right )}^{2}} \,d x } \]
integral(sqrt(c^2*d*x^2 + d)*(b*arcsinh(c*x) + a)/(c^2*d*g^2*x^4 + 2*c^2*d *f*g*x^3 + 2*d*f*g*x + d*f^2 + (c^2*d*f^2 + d*g^2)*x^2), x)
\[ \int \frac {a+b \text {arcsinh}(c x)}{(f+g x)^2 \sqrt {d+c^2 d x^2}} \, dx=\int \frac {a + b \operatorname {asinh}{\left (c x \right )}}{\sqrt {d \left (c^{2} x^{2} + 1\right )} \left (f + g x\right )^{2}}\, dx \]
\[ \int \frac {a+b \text {arcsinh}(c x)}{(f+g x)^2 \sqrt {d+c^2 d x^2}} \, dx=\int { \frac {b \operatorname {arsinh}\left (c x\right ) + a}{\sqrt {c^{2} d x^{2} + d} {\left (g x + f\right )}^{2}} \,d x } \]
\[ \int \frac {a+b \text {arcsinh}(c x)}{(f+g x)^2 \sqrt {d+c^2 d x^2}} \, dx=\int { \frac {b \operatorname {arsinh}\left (c x\right ) + a}{\sqrt {c^{2} d x^{2} + d} {\left (g x + f\right )}^{2}} \,d x } \]
Timed out. \[ \int \frac {a+b \text {arcsinh}(c x)}{(f+g x)^2 \sqrt {d+c^2 d x^2}} \, dx=\int \frac {a+b\,\mathrm {asinh}\left (c\,x\right )}{{\left (f+g\,x\right )}^2\,\sqrt {d\,c^2\,x^2+d}} \,d x \]