3.3.96 \(\int \frac {1}{\sqrt {1+b x^2} \text {arccosh}(\sqrt {1+b x^2})} \, dx\) [296]

3.3.96.1 Optimal result

Integrand size = 26, antiderivative size = 54 \[ \int \frac {1}{\sqrt {1+b x^2} \text {arccosh}\left (\sqrt {1+b x^2}\right )} \, dx=\frac {\sqrt {-1+\sqrt {1+b x^2}} \sqrt {1+\sqrt {1+b x^2}} \log \left (\text {arccosh}\left (\sqrt {1+b x^2}\right )\right )}{b x} \]

output

ln(arccosh((b*x^2+1)^(1/2)))*(-1+(b*x^2+1)^(1/2))^(1/2)*(1+(b*x^2+1)^(1/2) 
)^(1/2)/b/x
 

3.3.96.2 Mathematica [A] (verified)

Time = 0.07 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.00 \[ \int \frac {1}{\sqrt {1+b x^2} \text {arccosh}\left (\sqrt {1+b x^2}\right )} \, dx=\frac {\sqrt {-1+\sqrt {1+b x^2}} \sqrt {1+\sqrt {1+b x^2}} \log \left (\text {arccosh}\left (\sqrt {1+b x^2}\right )\right )}{b x} \]

input

Integrate[1/(Sqrt[1 + b*x^2]*ArcCosh[Sqrt[1 + b*x^2]]),x]
 

output

(Sqrt[-1 + Sqrt[1 + b*x^2]]*Sqrt[1 + Sqrt[1 + b*x^2]]*Log[ArcCosh[Sqrt[1 + 
 b*x^2]]])/(b*x)
 

3.3.96.3 Rubi [A] (verified)

Time = 0.35 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {6428, 6306}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{\sqrt {b x^2+1} \text {arccosh}\left (\sqrt {b x^2+1}\right )} \, dx\)

\(\Big \downarrow \) 6428

\(\displaystyle \frac {\sqrt {\sqrt {b x^2+1}-1} \sqrt {\sqrt {b x^2+1}+1} \int \frac {1}{\sqrt {\sqrt {b x^2+1}-1} \sqrt {\sqrt {b x^2+1}+1} \text {arccosh}\left (\sqrt {b x^2+1}\right )}d\sqrt {b x^2+1}}{b x}\)

\(\Big \downarrow \) 6306

\(\displaystyle \frac {\sqrt {\sqrt {b x^2+1}-1} \sqrt {\sqrt {b x^2+1}+1} \log \left (\text {arccosh}\left (\sqrt {b x^2+1}\right )\right )}{b x}\)

input

Int[1/(Sqrt[1 + b*x^2]*ArcCosh[Sqrt[1 + b*x^2]]),x]
 

output

(Sqrt[-1 + Sqrt[1 + b*x^2]]*Sqrt[1 + Sqrt[1 + b*x^2]]*Log[ArcCosh[Sqrt[1 + 
 b*x^2]]])/(b*x)
 

3.3.96.3.1 Defintions of rubi rules used

rule 6306

Int[1/(((a_.) + ArcCosh[(c_.)*(x_)]*(b_.))*Sqrt[(d1_) + (e1_.)*(x_)]*Sqrt[( 
d2_) + (e2_.)*(x_)]), x_Symbol] :> Simp[(1/(b*c))*Simp[Sqrt[1 + c*x]/Sqrt[d 
1 + e1*x]]*Simp[Sqrt[-1 + c*x]/Sqrt[d2 + e2*x]]*Log[a + b*ArcCosh[c*x]], x] 
 /; FreeQ[{a, b, c, d1, e1, d2, e2}, x] && EqQ[e1, c*d1] && EqQ[e2, (-c)*d2 
]
 

rule 6428

Int[ArcCosh[Sqrt[1 + (b_.)*(x_)^2]]^(n_.)/Sqrt[1 + (b_.)*(x_)^2], x_Symbol] 
 :> Simp[Sqrt[-1 + Sqrt[1 + b*x^2]]*(Sqrt[1 + Sqrt[1 + b*x^2]]/(b*x))   Sub 
st[Int[ArcCosh[x]^n/(Sqrt[-1 + x]*Sqrt[1 + x]), x], x, Sqrt[1 + b*x^2]], x] 
 /; FreeQ[{b, n}, x]
 

3.3.96.4 Maple [F]

\[\int \frac {1}{\operatorname {arccosh}\left (\sqrt {b \,x^{2}+1}\right ) \sqrt {b \,x^{2}+1}}d x\]

input

int(1/arccosh((b*x^2+1)^(1/2))/(b*x^2+1)^(1/2),x)
 

output

int(1/arccosh((b*x^2+1)^(1/2))/(b*x^2+1)^(1/2),x)
 

3.3.96.5 Fricas [A] (verification not implemented)

Time = 0.26 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.61 \[ \int \frac {1}{\sqrt {1+b x^2} \text {arccosh}\left (\sqrt {1+b x^2}\right )} \, dx=\frac {\sqrt {b x^{2}} \log \left (\log \left (\sqrt {b x^{2} + 1} + \sqrt {b x^{2}}\right )\right )}{b x} \]

input

integrate(1/arccosh((b*x^2+1)^(1/2))/(b*x^2+1)^(1/2),x, algorithm="fricas" 
)
 

output

sqrt(b*x^2)*log(log(sqrt(b*x^2 + 1) + sqrt(b*x^2)))/(b*x)
 

3.3.96.6 Sympy [F]

\[ \int \frac {1}{\sqrt {1+b x^2} \text {arccosh}\left (\sqrt {1+b x^2}\right )} \, dx=\int \frac {1}{\sqrt {b x^{2} + 1} \operatorname {acosh}{\left (\sqrt {b x^{2} + 1} \right )}}\, dx \]

input

integrate(1/acosh((b*x**2+1)**(1/2))/(b*x**2+1)**(1/2),x)
 

output

Integral(1/(sqrt(b*x**2 + 1)*acosh(sqrt(b*x**2 + 1))), x)
 

3.3.96.7 Maxima [F]

\[ \int \frac {1}{\sqrt {1+b x^2} \text {arccosh}\left (\sqrt {1+b x^2}\right )} \, dx=\int { \frac {1}{\sqrt {b x^{2} + 1} \operatorname {arcosh}\left (\sqrt {b x^{2} + 1}\right )} \,d x } \]

input

integrate(1/arccosh((b*x^2+1)^(1/2))/(b*x^2+1)^(1/2),x, algorithm="maxima" 
)
 

output

integrate(1/(sqrt(b*x^2 + 1)*arccosh(sqrt(b*x^2 + 1))), x)
 

3.3.96.8 Giac [F(-1)]

Timed out. \[ \int \frac {1}{\sqrt {1+b x^2} \text {arccosh}\left (\sqrt {1+b x^2}\right )} \, dx=\text {Timed out} \]

input

integrate(1/arccosh((b*x^2+1)^(1/2))/(b*x^2+1)^(1/2),x, algorithm="giac")
 

output

Timed out
 

3.3.96.9 Mupad [F(-1)]

Timed out. \[ \int \frac {1}{\sqrt {1+b x^2} \text {arccosh}\left (\sqrt {1+b x^2}\right )} \, dx=\int \frac {1}{\mathrm {acosh}\left (\sqrt {b\,x^2+1}\right )\,\sqrt {b\,x^2+1}} \,d x \]

input

int(1/(acosh((b*x^2 + 1)^(1/2))*(b*x^2 + 1)^(1/2)),x)
 

output

int(1/(acosh((b*x^2 + 1)^(1/2))*(b*x^2 + 1)^(1/2)), x)