Integrand size = 25, antiderivative size = 87 \[ \int e^{2 \text {arctanh}(a x)} x^4 \left (c-a^2 c x^2\right )^3 \, dx=\frac {c^3 x^5}{5}+\frac {1}{3} a c^3 x^6-\frac {1}{7} a^2 c^3 x^7-\frac {1}{2} a^3 c^3 x^8-\frac {1}{9} a^4 c^3 x^9+\frac {1}{5} a^5 c^3 x^{10}+\frac {1}{11} a^6 c^3 x^{11} \]
1/5*c^3*x^5+1/3*a*c^3*x^6-1/7*a^2*c^3*x^7-1/2*a^3*c^3*x^8-1/9*a^4*c^3*x^9+ 1/5*a^5*c^3*x^10+1/11*a^6*c^3*x^11
Time = 0.03 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.80 \[ \int e^{2 \text {arctanh}(a x)} x^4 \left (c-a^2 c x^2\right )^3 \, dx=c^3 \left (\frac {x^5}{5}+\frac {a x^6}{3}-\frac {a^2 x^7}{7}-\frac {a^3 x^8}{2}-\frac {a^4 x^9}{9}+\frac {a^5 x^{10}}{5}+\frac {a^6 x^{11}}{11}\right ) \]
c^3*(x^5/5 + (a*x^6)/3 - (a^2*x^7)/7 - (a^3*x^8)/2 - (a^4*x^9)/9 + (a^5*x^ 10)/5 + (a^6*x^11)/11)
Time = 0.31 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.80, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.120, Rules used = {6700, 99, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x^4 e^{2 \text {arctanh}(a x)} \left (c-a^2 c x^2\right )^3 \, dx\) |
\(\Big \downarrow \) 6700 |
\(\displaystyle c^3 \int x^4 (1-a x)^2 (a x+1)^4dx\) |
\(\Big \downarrow \) 99 |
\(\displaystyle c^3 \int \left (a^6 x^{10}+2 a^5 x^9-a^4 x^8-4 a^3 x^7-a^2 x^6+2 a x^5+x^4\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle c^3 \left (\frac {a^6 x^{11}}{11}+\frac {a^5 x^{10}}{5}-\frac {a^4 x^9}{9}-\frac {a^3 x^8}{2}-\frac {a^2 x^7}{7}+\frac {a x^6}{3}+\frac {x^5}{5}\right )\) |
c^3*(x^5/5 + (a*x^6)/3 - (a^2*x^7)/7 - (a^3*x^8)/2 - (a^4*x^9)/9 + (a^5*x^ 10)/5 + (a^6*x^11)/11)
3.11.39.3.1 Defintions of rubi rules used
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_), x_] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] && (IntegerQ[p] | | (GtQ[m, 0] && GeQ[n, -1]))
Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(x_)^(m_.)*((c_) + (d_.)*(x_)^2)^(p_.), x _Symbol] :> Simp[c^p Int[x^m*(1 - a*x)^(p - n/2)*(1 + a*x)^(p + n/2), x], x] /; FreeQ[{a, c, d, m, n, p}, x] && EqQ[a^2*c + d, 0] && (IntegerQ[p] || GtQ[c, 0])
Time = 0.41 (sec) , antiderivative size = 55, normalized size of antiderivative = 0.63
method | result | size |
gosper | \(\frac {c^{3} x^{5} \left (630 a^{6} x^{6}+1386 a^{5} x^{5}-770 a^{4} x^{4}-3465 a^{3} x^{3}-990 a^{2} x^{2}+2310 a x +1386\right )}{6930}\) | \(55\) |
default | \(c^{3} \left (\frac {1}{11} a^{6} x^{11}+\frac {1}{5} a^{5} x^{10}-\frac {1}{9} a^{4} x^{9}-\frac {1}{2} a^{3} x^{8}-\frac {1}{7} a^{2} x^{7}+\frac {1}{3} a \,x^{6}+\frac {1}{5} x^{5}\right )\) | \(57\) |
norman | \(\frac {1}{5} c^{3} x^{5}+\frac {1}{3} a \,c^{3} x^{6}-\frac {1}{7} a^{2} c^{3} x^{7}-\frac {1}{2} a^{3} c^{3} x^{8}-\frac {1}{9} a^{4} c^{3} x^{9}+\frac {1}{5} a^{5} c^{3} x^{10}+\frac {1}{11} a^{6} c^{3} x^{11}\) | \(74\) |
risch | \(\frac {1}{5} c^{3} x^{5}+\frac {1}{3} a \,c^{3} x^{6}-\frac {1}{7} a^{2} c^{3} x^{7}-\frac {1}{2} a^{3} c^{3} x^{8}-\frac {1}{9} a^{4} c^{3} x^{9}+\frac {1}{5} a^{5} c^{3} x^{10}+\frac {1}{11} a^{6} c^{3} x^{11}\) | \(74\) |
parallelrisch | \(\frac {1}{5} c^{3} x^{5}+\frac {1}{3} a \,c^{3} x^{6}-\frac {1}{7} a^{2} c^{3} x^{7}-\frac {1}{2} a^{3} c^{3} x^{8}-\frac {1}{9} a^{4} c^{3} x^{9}+\frac {1}{5} a^{5} c^{3} x^{10}+\frac {1}{11} a^{6} c^{3} x^{11}\) | \(74\) |
meijerg | \(-\frac {c^{3} \left (-\frac {2 x \left (-a^{2}\right )^{\frac {13}{2}} \left (4095 x^{10} a^{10}+5005 a^{8} x^{8}+6435 a^{6} x^{6}+9009 a^{4} x^{4}+15015 a^{2} x^{2}+45045\right )}{45045 a^{12}}+\frac {2 \left (-a^{2}\right )^{\frac {13}{2}} \operatorname {arctanh}\left (a x \right )}{a^{13}}\right )}{2 a^{4} \sqrt {-a^{2}}}-\frac {c^{3} \left (-\frac {2 x \left (-a^{2}\right )^{\frac {11}{2}} \left (385 a^{8} x^{8}+495 a^{6} x^{6}+693 a^{4} x^{4}+1155 a^{2} x^{2}+3465\right )}{3465 a^{10}}+\frac {2 \left (-a^{2}\right )^{\frac {11}{2}} \operatorname {arctanh}\left (a x \right )}{a^{11}}\right )}{a^{4} \sqrt {-a^{2}}}+\frac {c^{3} \left (-\frac {2 x \left (-a^{2}\right )^{\frac {7}{2}} \left (21 a^{4} x^{4}+35 a^{2} x^{2}+105\right )}{105 a^{6}}+\frac {2 \left (-a^{2}\right )^{\frac {7}{2}} \operatorname {arctanh}\left (a x \right )}{a^{7}}\right )}{a^{4} \sqrt {-a^{2}}}-\frac {c^{3} \left (-\frac {x^{2} a^{2} \left (12 a^{8} x^{8}+15 a^{6} x^{6}+20 a^{4} x^{4}+30 a^{2} x^{2}+60\right )}{60}-\ln \left (-a^{2} x^{2}+1\right )\right )}{a^{5}}-\frac {3 c^{3} \left (\frac {x^{2} a^{2} \left (15 a^{6} x^{6}+20 a^{4} x^{4}+30 a^{2} x^{2}+60\right )}{60}+\ln \left (-a^{2} x^{2}+1\right )\right )}{a^{5}}-\frac {3 c^{3} \left (-\frac {x^{2} a^{2} \left (4 a^{4} x^{4}+6 a^{2} x^{2}+12\right )}{12}-\ln \left (-a^{2} x^{2}+1\right )\right )}{a^{5}}-\frac {c^{3} \left (\frac {x^{2} a^{2} \left (3 a^{2} x^{2}+6\right )}{6}+\ln \left (-a^{2} x^{2}+1\right )\right )}{a^{5}}+\frac {c^{3} \left (-\frac {2 x \left (-a^{2}\right )^{\frac {5}{2}} \left (5 a^{2} x^{2}+15\right )}{15 a^{4}}+\frac {2 \left (-a^{2}\right )^{\frac {5}{2}} \operatorname {arctanh}\left (a x \right )}{a^{5}}\right )}{2 a^{4} \sqrt {-a^{2}}}\) | \(489\) |
1/6930*c^3*x^5*(630*a^6*x^6+1386*a^5*x^5-770*a^4*x^4-3465*a^3*x^3-990*a^2* x^2+2310*a*x+1386)
Time = 0.24 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.84 \[ \int e^{2 \text {arctanh}(a x)} x^4 \left (c-a^2 c x^2\right )^3 \, dx=\frac {1}{11} \, a^{6} c^{3} x^{11} + \frac {1}{5} \, a^{5} c^{3} x^{10} - \frac {1}{9} \, a^{4} c^{3} x^{9} - \frac {1}{2} \, a^{3} c^{3} x^{8} - \frac {1}{7} \, a^{2} c^{3} x^{7} + \frac {1}{3} \, a c^{3} x^{6} + \frac {1}{5} \, c^{3} x^{5} \]
1/11*a^6*c^3*x^11 + 1/5*a^5*c^3*x^10 - 1/9*a^4*c^3*x^9 - 1/2*a^3*c^3*x^8 - 1/7*a^2*c^3*x^7 + 1/3*a*c^3*x^6 + 1/5*c^3*x^5
Time = 0.05 (sec) , antiderivative size = 76, normalized size of antiderivative = 0.87 \[ \int e^{2 \text {arctanh}(a x)} x^4 \left (c-a^2 c x^2\right )^3 \, dx=\frac {a^{6} c^{3} x^{11}}{11} + \frac {a^{5} c^{3} x^{10}}{5} - \frac {a^{4} c^{3} x^{9}}{9} - \frac {a^{3} c^{3} x^{8}}{2} - \frac {a^{2} c^{3} x^{7}}{7} + \frac {a c^{3} x^{6}}{3} + \frac {c^{3} x^{5}}{5} \]
a**6*c**3*x**11/11 + a**5*c**3*x**10/5 - a**4*c**3*x**9/9 - a**3*c**3*x**8 /2 - a**2*c**3*x**7/7 + a*c**3*x**6/3 + c**3*x**5/5
Time = 0.20 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.84 \[ \int e^{2 \text {arctanh}(a x)} x^4 \left (c-a^2 c x^2\right )^3 \, dx=\frac {1}{11} \, a^{6} c^{3} x^{11} + \frac {1}{5} \, a^{5} c^{3} x^{10} - \frac {1}{9} \, a^{4} c^{3} x^{9} - \frac {1}{2} \, a^{3} c^{3} x^{8} - \frac {1}{7} \, a^{2} c^{3} x^{7} + \frac {1}{3} \, a c^{3} x^{6} + \frac {1}{5} \, c^{3} x^{5} \]
1/11*a^6*c^3*x^11 + 1/5*a^5*c^3*x^10 - 1/9*a^4*c^3*x^9 - 1/2*a^3*c^3*x^8 - 1/7*a^2*c^3*x^7 + 1/3*a*c^3*x^6 + 1/5*c^3*x^5
Time = 0.27 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.84 \[ \int e^{2 \text {arctanh}(a x)} x^4 \left (c-a^2 c x^2\right )^3 \, dx=\frac {1}{11} \, a^{6} c^{3} x^{11} + \frac {1}{5} \, a^{5} c^{3} x^{10} - \frac {1}{9} \, a^{4} c^{3} x^{9} - \frac {1}{2} \, a^{3} c^{3} x^{8} - \frac {1}{7} \, a^{2} c^{3} x^{7} + \frac {1}{3} \, a c^{3} x^{6} + \frac {1}{5} \, c^{3} x^{5} \]
1/11*a^6*c^3*x^11 + 1/5*a^5*c^3*x^10 - 1/9*a^4*c^3*x^9 - 1/2*a^3*c^3*x^8 - 1/7*a^2*c^3*x^7 + 1/3*a*c^3*x^6 + 1/5*c^3*x^5
Time = 3.40 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.84 \[ \int e^{2 \text {arctanh}(a x)} x^4 \left (c-a^2 c x^2\right )^3 \, dx=\frac {a^6\,c^3\,x^{11}}{11}+\frac {a^5\,c^3\,x^{10}}{5}-\frac {a^4\,c^3\,x^9}{9}-\frac {a^3\,c^3\,x^8}{2}-\frac {a^2\,c^3\,x^7}{7}+\frac {a\,c^3\,x^6}{3}+\frac {c^3\,x^5}{5} \]