3.14.17 \(\int \frac {e^{n \text {arctanh}(a x)}}{x^2 (c-a^2 c x^2)} \, dx\) [1317]

3.14.17.1 Optimal result

Integrand size = 25, antiderivative size = 123 \[ \int \frac {e^{n \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )} \, dx=\frac {a (1+n) (1-a x)^{-n/2} (1+a x)^{n/2}}{c n}-\frac {(1-a x)^{-n/2} (1+a x)^{n/2}}{c x}-\frac {2 a (1-a x)^{-n/2} (1+a x)^{n/2} \operatorname {Hypergeometric2F1}\left (1,\frac {n}{2},\frac {2+n}{2},\frac {1+a x}{1-a x}\right )}{c} \]

output

a*(1+n)*(a*x+1)^(1/2*n)/c/n/((-a*x+1)^(1/2*n))-(a*x+1)^(1/2*n)/c/x/((-a*x+ 
1)^(1/2*n))-2*a*(a*x+1)^(1/2*n)*hypergeom([1, 1/2*n],[1+1/2*n],(a*x+1)/(-a 
*x+1))/c/((-a*x+1)^(1/2*n))
 

3.14.17.2 Mathematica [A] (verified)

Time = 0.03 (sec) , antiderivative size = 103, normalized size of antiderivative = 0.84 \[ \int \frac {e^{n \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )} \, dx=\frac {(1-a x)^{-n/2} (1+a x)^{-1+\frac {n}{2}} \left ((-2+n) (1+a x) (a x+n (-1+a x))-2 a n^2 x (-1+a x) \operatorname {Hypergeometric2F1}\left (1,1-\frac {n}{2},2-\frac {n}{2},\frac {1-a x}{1+a x}\right )\right )}{c (-2+n) n x} \]

input

Integrate[E^(n*ArcTanh[a*x])/(x^2*(c - a^2*c*x^2)),x]
 

output

((1 + a*x)^(-1 + n/2)*((-2 + n)*(1 + a*x)*(a*x + n*(-1 + a*x)) - 2*a*n^2*x 
*(-1 + a*x)*Hypergeometric2F1[1, 1 - n/2, 2 - n/2, (1 - a*x)/(1 + a*x)]))/ 
(c*(-2 + n)*n*x*(1 - a*x)^(n/2))
 

3.14.17.3 Rubi [A] (verified)

Time = 0.35 (sec) , antiderivative size = 119, normalized size of antiderivative = 0.97, number of steps used = 8, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.320, Rules used = {6700, 144, 25, 27, 172, 25, 27, 141}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {e^{n \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )} \, dx\)

\(\Big \downarrow \) 6700

\(\displaystyle \frac {\int \frac {(1-a x)^{-\frac {n}{2}-1} (a x+1)^{\frac {n-2}{2}}}{x^2}dx}{c}\)

\(\Big \downarrow \) 144

\(\displaystyle \frac {-\int -\frac {a (1-a x)^{-\frac {n}{2}-1} (a x+1)^{\frac {n-2}{2}} (n+a x)}{x}dx-\frac {(a x+1)^{n/2} (1-a x)^{-n/2}}{x}}{c}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {\int \frac {a (1-a x)^{-\frac {n}{2}-1} (a x+1)^{\frac {n-2}{2}} (n+a x)}{x}dx-\frac {(1-a x)^{-n/2} (a x+1)^{n/2}}{x}}{c}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {a \int \frac {(1-a x)^{-\frac {n}{2}-1} (a x+1)^{\frac {n-2}{2}} (n+a x)}{x}dx-\frac {(1-a x)^{-n/2} (a x+1)^{n/2}}{x}}{c}\)

\(\Big \downarrow \) 172

\(\displaystyle \frac {a \left (\frac {(n+1) (1-a x)^{-n/2} (a x+1)^{n/2}}{n}-\frac {\int -\frac {a n^2 (1-a x)^{-n/2} (a x+1)^{\frac {n-2}{2}}}{x}dx}{a n}\right )-\frac {(1-a x)^{-n/2} (a x+1)^{n/2}}{x}}{c}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {a \left (\frac {\int \frac {a n^2 (1-a x)^{-n/2} (a x+1)^{\frac {n-2}{2}}}{x}dx}{a n}+\frac {(n+1) (a x+1)^{n/2} (1-a x)^{-n/2}}{n}\right )-\frac {(1-a x)^{-n/2} (a x+1)^{n/2}}{x}}{c}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {a \left (n \int \frac {(1-a x)^{-n/2} (a x+1)^{\frac {n-2}{2}}}{x}dx+\frac {(n+1) (a x+1)^{n/2} (1-a x)^{-n/2}}{n}\right )-\frac {(1-a x)^{-n/2} (a x+1)^{n/2}}{x}}{c}\)

\(\Big \downarrow \) 141

\(\displaystyle \frac {a \left (\frac {(n+1) (1-a x)^{-n/2} (a x+1)^{n/2}}{n}-2 (1-a x)^{-n/2} (a x+1)^{n/2} \operatorname {Hypergeometric2F1}\left (1,\frac {n}{2},\frac {n+2}{2},\frac {a x+1}{1-a x}\right )\right )-\frac {(1-a x)^{-n/2} (a x+1)^{n/2}}{x}}{c}\)

input

Int[E^(n*ArcTanh[a*x])/(x^2*(c - a^2*c*x^2)),x]
 

output

(-((1 + a*x)^(n/2)/(x*(1 - a*x)^(n/2))) + a*(((1 + n)*(1 + a*x)^(n/2))/(n* 
(1 - a*x)^(n/2)) - (2*(1 + a*x)^(n/2)*Hypergeometric2F1[1, n/2, (2 + n)/2, 
 (1 + a*x)/(1 - a*x)])/(1 - a*x)^(n/2)))/c
 

3.14.17.3.1 Defintions of rubi rules used

rule 25

Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27

Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 141

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_), x_] :> Simp[(b*c - a*d)^n*((a + b*x)^(m + 1)/((m + 1)*(b*e - a*f)^( 
n + 1)*(e + f*x)^(m + 1)))*Hypergeometric2F1[m + 1, -n, m + 2, (-(d*e - c*f 
))*((a + b*x)/((b*c - a*d)*(e + f*x)))], x] /; FreeQ[{a, b, c, d, e, f, m, 
p}, x] && EqQ[m + n + p + 2, 0] && ILtQ[n, 0] && (SumSimplerQ[m, 1] ||  !Su 
mSimplerQ[p, 1]) &&  !ILtQ[m, 0]
 

rule 144

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_), x_] :> With[{mnp = Simplify[m + n + p]}, Simp[b*(a + b*x)^(m + 1)*( 
c + d*x)^(n + 1)*((e + f*x)^(p + 1)/((m + 1)*(b*c - a*d)*(b*e - a*f))), x] 
+ Simp[1/((m + 1)*(b*c - a*d)*(b*e - a*f))   Int[(a + b*x)^(m + 1)*(c + d*x 
)^n*(e + f*x)^p*Simp[a*d*f*(m + 1) - b*(d*e*(m + n + 2) + c*f*(m + p + 2)) 
- b*d*f*(mnp + 3)*x, x], x], x] /; ILtQ[mnp + 2, 0] && (SumSimplerQ[m, 1] | 
| ( !SumSimplerQ[n, 1] &&  !SumSimplerQ[p, 1]))] /; FreeQ[{a, b, c, d, e, f 
, m, n, p}, x] && NeQ[m, -1]
 

rule 172

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_)*((g_.) + (h_.)*(x_)), x_] :> With[{mnp = Simplify[m + n + p]}, Simp[ 
(b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/((m + 1) 
*(b*c - a*d)*(b*e - a*f))), x] + Simp[1/((m + 1)*(b*c - a*d)*(b*e - a*f)) 
 Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[(a*d*f*g - b*(d*e + c*f 
)*g + b*c*e*h)*(m + 1) - (b*g - a*h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g 
 - a*h)*(mnp + 3)*x, x], x], x] /; ILtQ[mnp + 2, 0] && (SumSimplerQ[m, 1] | 
| ( !(NeQ[n, -1] && SumSimplerQ[n, 1]) &&  !(NeQ[p, -1] && SumSimplerQ[p, 1 
])))] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && NeQ[m, -1]
 

rule 6700

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(x_)^(m_.)*((c_) + (d_.)*(x_)^2)^(p_.), x 
_Symbol] :> Simp[c^p   Int[x^m*(1 - a*x)^(p - n/2)*(1 + a*x)^(p + n/2), x], 
 x] /; FreeQ[{a, c, d, m, n, p}, x] && EqQ[a^2*c + d, 0] && (IntegerQ[p] || 
 GtQ[c, 0])
 

3.14.17.4 Maple [F]

\[\int \frac {{\mathrm e}^{n \,\operatorname {arctanh}\left (a x \right )}}{x^{2} \left (-a^{2} c \,x^{2}+c \right )}d x\]

input

int(exp(n*arctanh(a*x))/x^2/(-a^2*c*x^2+c),x)
 

output

int(exp(n*arctanh(a*x))/x^2/(-a^2*c*x^2+c),x)
 

3.14.17.5 Fricas [F]

\[ \int \frac {e^{n \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )} \, dx=\int { -\frac {\left (-\frac {a x + 1}{a x - 1}\right )^{\frac {1}{2} \, n}}{{\left (a^{2} c x^{2} - c\right )} x^{2}} \,d x } \]

input

integrate(exp(n*arctanh(a*x))/x^2/(-a^2*c*x^2+c),x, algorithm="fricas")
 

output

integral(-(-(a*x + 1)/(a*x - 1))^(1/2*n)/(a^2*c*x^4 - c*x^2), x)
 

3.14.17.6 Sympy [F]

\[ \int \frac {e^{n \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )} \, dx=- \frac {\int \frac {e^{n \operatorname {atanh}{\left (a x \right )}}}{a^{2} x^{4} - x^{2}}\, dx}{c} \]

input

integrate(exp(n*atanh(a*x))/x**2/(-a**2*c*x**2+c),x)
 

output

-Integral(exp(n*atanh(a*x))/(a**2*x**4 - x**2), x)/c
 

3.14.17.7 Maxima [F]

\[ \int \frac {e^{n \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )} \, dx=\int { -\frac {\left (-\frac {a x + 1}{a x - 1}\right )^{\frac {1}{2} \, n}}{{\left (a^{2} c x^{2} - c\right )} x^{2}} \,d x } \]

input

integrate(exp(n*arctanh(a*x))/x^2/(-a^2*c*x^2+c),x, algorithm="maxima")
 

output

-integrate((-(a*x + 1)/(a*x - 1))^(1/2*n)/((a^2*c*x^2 - c)*x^2), x)
 

3.14.17.8 Giac [F]

\[ \int \frac {e^{n \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )} \, dx=\int { -\frac {\left (-\frac {a x + 1}{a x - 1}\right )^{\frac {1}{2} \, n}}{{\left (a^{2} c x^{2} - c\right )} x^{2}} \,d x } \]

input

integrate(exp(n*arctanh(a*x))/x^2/(-a^2*c*x^2+c),x, algorithm="giac")
 

output

integrate(-(-(a*x + 1)/(a*x - 1))^(1/2*n)/((a^2*c*x^2 - c)*x^2), x)
 

3.14.17.9 Mupad [F(-1)]

Timed out. \[ \int \frac {e^{n \text {arctanh}(a x)}}{x^2 \left (c-a^2 c x^2\right )} \, dx=\int \frac {{\mathrm {e}}^{n\,\mathrm {atanh}\left (a\,x\right )}}{x^2\,\left (c-a^2\,c\,x^2\right )} \,d x \]

input

int(exp(n*atanh(a*x))/(x^2*(c - a^2*c*x^2)),x)
 

output

int(exp(n*atanh(a*x))/(x^2*(c - a^2*c*x^2)), x)