Integrand size = 22, antiderivative size = 100 \[ \int e^{4 \text {arctanh}(a x)} \left (c-\frac {c}{a^2 x^2}\right )^4 \, dx=-\frac {c^4}{7 a^8 x^7}-\frac {2 c^4}{3 a^7 x^6}-\frac {4 c^4}{5 a^6 x^5}+\frac {c^4}{a^5 x^4}+\frac {10 c^4}{3 a^4 x^3}+\frac {2 c^4}{a^3 x^2}-\frac {4 c^4}{a^2 x}+c^4 x+\frac {4 c^4 \log (x)}{a} \]
-1/7*c^4/a^8/x^7-2/3*c^4/a^7/x^6-4/5*c^4/a^6/x^5+c^4/a^5/x^4+10/3*c^4/a^4/ x^3+2*c^4/a^3/x^2-4*c^4/a^2/x+c^4*x+4*c^4*ln(x)/a
Time = 0.03 (sec) , antiderivative size = 100, normalized size of antiderivative = 1.00 \[ \int e^{4 \text {arctanh}(a x)} \left (c-\frac {c}{a^2 x^2}\right )^4 \, dx=-\frac {c^4}{7 a^8 x^7}-\frac {2 c^4}{3 a^7 x^6}-\frac {4 c^4}{5 a^6 x^5}+\frac {c^4}{a^5 x^4}+\frac {10 c^4}{3 a^4 x^3}+\frac {2 c^4}{a^3 x^2}-\frac {4 c^4}{a^2 x}+c^4 x+\frac {4 c^4 \log (x)}{a} \]
-1/7*c^4/(a^8*x^7) - (2*c^4)/(3*a^7*x^6) - (4*c^4)/(5*a^6*x^5) + c^4/(a^5* x^4) + (10*c^4)/(3*a^4*x^3) + (2*c^4)/(a^3*x^2) - (4*c^4)/(a^2*x) + c^4*x + (4*c^4*Log[x])/a
Time = 0.39 (sec) , antiderivative size = 78, normalized size of antiderivative = 0.78, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {6707, 6700, 99, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int e^{4 \text {arctanh}(a x)} \left (c-\frac {c}{a^2 x^2}\right )^4 \, dx\) |
\(\Big \downarrow \) 6707 |
\(\displaystyle \frac {c^4 \int \frac {e^{4 \text {arctanh}(a x)} \left (1-a^2 x^2\right )^4}{x^8}dx}{a^8}\) |
\(\Big \downarrow \) 6700 |
\(\displaystyle \frac {c^4 \int \frac {(1-a x)^2 (a x+1)^6}{x^8}dx}{a^8}\) |
\(\Big \downarrow \) 99 |
\(\displaystyle \frac {c^4 \int \left (a^8+\frac {4 a^7}{x}+\frac {4 a^6}{x^2}-\frac {4 a^5}{x^3}-\frac {10 a^4}{x^4}-\frac {4 a^3}{x^5}+\frac {4 a^2}{x^6}+\frac {4 a}{x^7}+\frac {1}{x^8}\right )dx}{a^8}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {c^4 \left (a^8 x+4 a^7 \log (x)-\frac {4 a^6}{x}+\frac {2 a^5}{x^2}+\frac {10 a^4}{3 x^3}+\frac {a^3}{x^4}-\frac {4 a^2}{5 x^5}-\frac {2 a}{3 x^6}-\frac {1}{7 x^7}\right )}{a^8}\) |
(c^4*(-1/7*1/x^7 - (2*a)/(3*x^6) - (4*a^2)/(5*x^5) + a^3/x^4 + (10*a^4)/(3 *x^3) + (2*a^5)/x^2 - (4*a^6)/x + a^8*x + 4*a^7*Log[x]))/a^8
3.7.54.3.1 Defintions of rubi rules used
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_), x_] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] && (IntegerQ[p] | | (GtQ[m, 0] && GeQ[n, -1]))
Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(x_)^(m_.)*((c_) + (d_.)*(x_)^2)^(p_.), x _Symbol] :> Simp[c^p Int[x^m*(1 - a*x)^(p - n/2)*(1 + a*x)^(p + n/2), x], x] /; FreeQ[{a, c, d, m, n, p}, x] && EqQ[a^2*c + d, 0] && (IntegerQ[p] || GtQ[c, 0])
Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)/(x_)^2)^(p_.), x_Symb ol] :> Simp[d^p Int[(u/x^(2*p))*(1 - a^2*x^2)^p*E^(n*ArcTanh[a*x]), x], x ] /; FreeQ[{a, c, d, n}, x] && EqQ[c + a^2*d, 0] && IntegerQ[p]
Time = 0.19 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.71
method | result | size |
default | \(\frac {c^{4} \left (a^{8} x +4 a^{7} \ln \left (x \right )+\frac {a^{3}}{x^{4}}+\frac {10 a^{4}}{3 x^{3}}-\frac {2 a}{3 x^{6}}+\frac {2 a^{5}}{x^{2}}-\frac {4 a^{6}}{x}-\frac {1}{7 x^{7}}-\frac {4 a^{2}}{5 x^{5}}\right )}{a^{8}}\) | \(71\) |
risch | \(c^{4} x +\frac {-4 a^{6} c^{4} x^{6}+2 a^{5} c^{4} x^{5}+\frac {10}{3} a^{4} c^{4} x^{4}+a^{3} c^{4} x^{3}-\frac {4}{5} a^{2} c^{4} x^{2}-\frac {2}{3} a \,c^{4} x -\frac {1}{7} c^{4}}{a^{8} x^{7}}+\frac {4 c^{4} \ln \left (x \right )}{a}\) | \(91\) |
parallelrisch | \(\frac {105 a^{8} c^{4} x^{8}+420 c^{4} \ln \left (x \right ) a^{7} x^{7}-420 a^{6} c^{4} x^{6}+210 a^{5} c^{4} x^{5}+350 a^{4} c^{4} x^{4}+105 a^{3} c^{4} x^{3}-84 a^{2} c^{4} x^{2}-70 a \,c^{4} x -15 c^{4}}{105 a^{8} x^{7}}\) | \(101\) |
norman | \(\frac {2 a^{8} c^{4} x^{9}+a^{9} c^{4} x^{10}+\frac {c^{4}}{7 a}+\frac {2 c^{4} x}{3}+\frac {23 a \,c^{4} x^{2}}{35}-\frac {5 a^{2} c^{4} x^{3}}{3}-\frac {62 a^{3} c^{4} x^{4}}{15}-a^{4} c^{4} x^{5}+\frac {22 a^{5} c^{4} x^{6}}{3}-5 a^{7} c^{4} x^{8}}{\left (a^{2} x^{2}-1\right ) a^{7} x^{7}}+\frac {4 c^{4} \ln \left (x \right )}{a}\) | \(130\) |
meijerg | \(\frac {2 c^{4} \left (\frac {a^{2} x^{2}}{-a^{2} x^{2}+1}+\ln \left (-a^{2} x^{2}+1\right )\right )}{a}-\frac {14 c^{4} \left (-\frac {2 \left (-3 a^{2} x^{2}+2\right )}{x \sqrt {-a^{2}}\, \left (-2 a^{2} x^{2}+2\right )}+\frac {3 a \,\operatorname {arctanh}\left (a x \right )}{\sqrt {-a^{2}}}\right )}{\sqrt {-a^{2}}}-\frac {c^{4} \left (\frac {x \left (-a^{2}\right )^{\frac {3}{2}}}{a^{2} \left (-a^{2} x^{2}+1\right )}-\frac {\left (-a^{2}\right )^{\frac {3}{2}} \operatorname {arctanh}\left (a x \right )}{a^{3}}\right )}{\sqrt {-a^{2}}}-\frac {6 c^{4} \left (\frac {4 a^{2} x^{2}}{-4 a^{2} x^{2}+4}-3 \ln \left (-a^{2} x^{2}+1\right )+1+6 \ln \left (x \right )+3 \ln \left (-a^{2}\right )-\frac {1}{2 a^{4} x^{4}}-\frac {2}{a^{2} x^{2}}\right )}{a}+\frac {c^{4} \left (-\frac {2 \left (-315 a^{8} x^{8}+210 a^{6} x^{6}+42 a^{4} x^{4}+18 a^{2} x^{2}+10\right )}{7 x^{7} \left (-a^{2}\right )^{\frac {7}{2}} \left (-10 a^{2} x^{2}+10\right )}+\frac {9 a^{7} \operatorname {arctanh}\left (a x \right )}{\left (-a^{2}\right )^{\frac {7}{2}}}\right )}{2 \sqrt {-a^{2}}}-\frac {2 c^{4} \left (-\frac {5 a^{2} x^{2}}{-5 a^{2} x^{2}+5}+4 \ln \left (-a^{2} x^{2}+1\right )-1-8 \ln \left (x \right )-4 \ln \left (-a^{2}\right )+\frac {1}{3 a^{6} x^{6}}+\frac {1}{a^{4} x^{4}}+\frac {3}{a^{2} x^{2}}\right )}{a}-\frac {6 a \,c^{4} x^{2}}{-a^{2} x^{2}+1}-\frac {c^{4} \left (-\frac {2 \left (-105 a^{6} x^{6}+70 a^{4} x^{4}+14 a^{2} x^{2}+6\right )}{5 x^{5} \left (-a^{2}\right )^{\frac {5}{2}} \left (-6 a^{2} x^{2}+6\right )}+\frac {7 a^{5} \operatorname {arctanh}\left (a x \right )}{\left (-a^{2}\right )^{\frac {5}{2}}}\right )}{\sqrt {-a^{2}}}-\frac {17 c^{4} \left (\frac {2 x \sqrt {-a^{2}}}{-2 a^{2} x^{2}+2}+\frac {\sqrt {-a^{2}}\, \operatorname {arctanh}\left (a x \right )}{a}\right )}{2 \sqrt {-a^{2}}}-\frac {17 c^{4} \left (-\frac {2 \left (-15 a^{4} x^{4}+10 a^{2} x^{2}+2\right )}{3 x^{3} \left (-a^{2}\right )^{\frac {3}{2}} \left (-2 a^{2} x^{2}+2\right )}+\frac {5 a^{3} \operatorname {arctanh}\left (a x \right )}{\left (-a^{2}\right )^{\frac {3}{2}}}\right )}{2 \sqrt {-a^{2}}}-\frac {4 c^{4} \left (-\frac {3 a^{2} x^{2}}{-3 a^{2} x^{2}+3}+2 \ln \left (-a^{2} x^{2}+1\right )-1-4 \ln \left (x \right )-2 \ln \left (-a^{2}\right )+\frac {1}{a^{2} x^{2}}\right )}{a}+\frac {4 c^{4} \left (\frac {2 a^{2} x^{2}}{-2 a^{2} x^{2}+2}-\ln \left (-a^{2} x^{2}+1\right )+1+2 \ln \left (x \right )+\ln \left (-a^{2}\right )\right )}{a}+\frac {c^{4} \left (\frac {x \left (-a^{2}\right )^{\frac {5}{2}} \left (-10 a^{2} x^{2}+15\right )}{5 a^{4} \left (-a^{2} x^{2}+1\right )}-\frac {3 \left (-a^{2}\right )^{\frac {5}{2}} \operatorname {arctanh}\left (a x \right )}{a^{5}}\right )}{2 \sqrt {-a^{2}}}\) | \(791\) |
c^4/a^8*(a^8*x+4*a^7*ln(x)+a^3/x^4+10/3*a^4/x^3-2/3*a/x^6+2*a^5/x^2-4*a^6/ x-1/7/x^7-4/5*a^2/x^5)
Time = 0.26 (sec) , antiderivative size = 100, normalized size of antiderivative = 1.00 \[ \int e^{4 \text {arctanh}(a x)} \left (c-\frac {c}{a^2 x^2}\right )^4 \, dx=\frac {105 \, a^{8} c^{4} x^{8} + 420 \, a^{7} c^{4} x^{7} \log \left (x\right ) - 420 \, a^{6} c^{4} x^{6} + 210 \, a^{5} c^{4} x^{5} + 350 \, a^{4} c^{4} x^{4} + 105 \, a^{3} c^{4} x^{3} - 84 \, a^{2} c^{4} x^{2} - 70 \, a c^{4} x - 15 \, c^{4}}{105 \, a^{8} x^{7}} \]
1/105*(105*a^8*c^4*x^8 + 420*a^7*c^4*x^7*log(x) - 420*a^6*c^4*x^6 + 210*a^ 5*c^4*x^5 + 350*a^4*c^4*x^4 + 105*a^3*c^4*x^3 - 84*a^2*c^4*x^2 - 70*a*c^4* x - 15*c^4)/(a^8*x^7)
Time = 0.31 (sec) , antiderivative size = 100, normalized size of antiderivative = 1.00 \[ \int e^{4 \text {arctanh}(a x)} \left (c-\frac {c}{a^2 x^2}\right )^4 \, dx=\frac {a^{8} c^{4} x + 4 a^{7} c^{4} \log {\left (x \right )} + \frac {- 420 a^{6} c^{4} x^{6} + 210 a^{5} c^{4} x^{5} + 350 a^{4} c^{4} x^{4} + 105 a^{3} c^{4} x^{3} - 84 a^{2} c^{4} x^{2} - 70 a c^{4} x - 15 c^{4}}{105 x^{7}}}{a^{8}} \]
(a**8*c**4*x + 4*a**7*c**4*log(x) + (-420*a**6*c**4*x**6 + 210*a**5*c**4*x **5 + 350*a**4*c**4*x**4 + 105*a**3*c**4*x**3 - 84*a**2*c**4*x**2 - 70*a*c **4*x - 15*c**4)/(105*x**7))/a**8
Time = 0.20 (sec) , antiderivative size = 92, normalized size of antiderivative = 0.92 \[ \int e^{4 \text {arctanh}(a x)} \left (c-\frac {c}{a^2 x^2}\right )^4 \, dx=c^{4} x + \frac {4 \, c^{4} \log \left (x\right )}{a} - \frac {420 \, a^{6} c^{4} x^{6} - 210 \, a^{5} c^{4} x^{5} - 350 \, a^{4} c^{4} x^{4} - 105 \, a^{3} c^{4} x^{3} + 84 \, a^{2} c^{4} x^{2} + 70 \, a c^{4} x + 15 \, c^{4}}{105 \, a^{8} x^{7}} \]
c^4*x + 4*c^4*log(x)/a - 1/105*(420*a^6*c^4*x^6 - 210*a^5*c^4*x^5 - 350*a^ 4*c^4*x^4 - 105*a^3*c^4*x^3 + 84*a^2*c^4*x^2 + 70*a*c^4*x + 15*c^4)/(a^8*x ^7)
Time = 0.27 (sec) , antiderivative size = 93, normalized size of antiderivative = 0.93 \[ \int e^{4 \text {arctanh}(a x)} \left (c-\frac {c}{a^2 x^2}\right )^4 \, dx=c^{4} x + \frac {4 \, c^{4} \log \left ({\left | x \right |}\right )}{a} - \frac {420 \, a^{6} c^{4} x^{6} - 210 \, a^{5} c^{4} x^{5} - 350 \, a^{4} c^{4} x^{4} - 105 \, a^{3} c^{4} x^{3} + 84 \, a^{2} c^{4} x^{2} + 70 \, a c^{4} x + 15 \, c^{4}}{105 \, a^{8} x^{7}} \]
c^4*x + 4*c^4*log(abs(x))/a - 1/105*(420*a^6*c^4*x^6 - 210*a^5*c^4*x^5 - 3 50*a^4*c^4*x^4 - 105*a^3*c^4*x^3 + 84*a^2*c^4*x^2 + 70*a*c^4*x + 15*c^4)/( a^8*x^7)
Time = 3.53 (sec) , antiderivative size = 72, normalized size of antiderivative = 0.72 \[ \int e^{4 \text {arctanh}(a x)} \left (c-\frac {c}{a^2 x^2}\right )^4 \, dx=\frac {c^4\,\left (a^3\,x^3-\frac {4\,a^2\,x^2}{5}-\frac {2\,a\,x}{3}+\frac {10\,a^4\,x^4}{3}+2\,a^5\,x^5-4\,a^6\,x^6+a^8\,x^8+4\,a^7\,x^7\,\ln \left (x\right )-\frac {1}{7}\right )}{a^8\,x^7} \]