Integrand size = 15, antiderivative size = 391 \[ \int x^2 \text {arctanh}(c+d \cot (a+b x)) \, dx=\frac {1}{3} x^3 \text {arctanh}(c+d \cot (a+b x))+\frac {1}{6} x^3 \log \left (1-\frac {(1-c-i d) e^{2 i a+2 i b x}}{1-c+i d}\right )-\frac {1}{6} x^3 \log \left (1-\frac {(1+c+i d) e^{2 i a+2 i b x}}{1+c-i d}\right )-\frac {i x^2 \operatorname {PolyLog}\left (2,\frac {(1-c-i d) e^{2 i a+2 i b x}}{1-c+i d}\right )}{4 b}+\frac {i x^2 \operatorname {PolyLog}\left (2,\frac {(1+c+i d) e^{2 i a+2 i b x}}{1+c-i d}\right )}{4 b}+\frac {x \operatorname {PolyLog}\left (3,\frac {(1-c-i d) e^{2 i a+2 i b x}}{1-c+i d}\right )}{4 b^2}-\frac {x \operatorname {PolyLog}\left (3,\frac {(1+c+i d) e^{2 i a+2 i b x}}{1+c-i d}\right )}{4 b^2}+\frac {i \operatorname {PolyLog}\left (4,\frac {(1-c-i d) e^{2 i a+2 i b x}}{1-c+i d}\right )}{8 b^3}-\frac {i \operatorname {PolyLog}\left (4,\frac {(1+c+i d) e^{2 i a+2 i b x}}{1+c-i d}\right )}{8 b^3} \]
1/3*x^3*arctanh(c+d*cot(b*x+a))+1/6*x^3*ln(1-(1-c-I*d)*exp(2*I*a+2*I*b*x)/ (1-c+I*d))-1/6*x^3*ln(1-(1+c+I*d)*exp(2*I*a+2*I*b*x)/(1+c-I*d))-1/4*I*x^2* polylog(2,(1-c-I*d)*exp(2*I*a+2*I*b*x)/(1-c+I*d))/b+1/4*I*x^2*polylog(2,(1 +c+I*d)*exp(2*I*a+2*I*b*x)/(1+c-I*d))/b+1/4*x*polylog(3,(1-c-I*d)*exp(2*I* a+2*I*b*x)/(1-c+I*d))/b^2-1/4*x*polylog(3,(1+c+I*d)*exp(2*I*a+2*I*b*x)/(1+ c-I*d))/b^2+1/8*I*polylog(4,(1-c-I*d)*exp(2*I*a+2*I*b*x)/(1-c+I*d))/b^3-1/ 8*I*polylog(4,(1+c+I*d)*exp(2*I*a+2*I*b*x)/(1+c-I*d))/b^3
Time = 3.51 (sec) , antiderivative size = 341, normalized size of antiderivative = 0.87 \[ \int x^2 \text {arctanh}(c+d \cot (a+b x)) \, dx=\frac {8 b^3 x^3 \text {arctanh}(c+d \cot (a+b x))+4 b^3 x^3 \log \left (1+\frac {(1-c+i d) e^{-2 i (a+b x)}}{-1+c+i d}\right )-4 b^3 x^3 \log \left (1+\frac {(-1-c+i d) e^{-2 i (a+b x)}}{1+c+i d}\right )+6 i b^2 x^2 \operatorname {PolyLog}\left (2,\frac {(-1+c-i d) e^{-2 i (a+b x)}}{-1+c+i d}\right )-6 i b^2 x^2 \operatorname {PolyLog}\left (2,\frac {(1+c-i d) e^{-2 i (a+b x)}}{1+c+i d}\right )+6 b x \operatorname {PolyLog}\left (3,\frac {(-1+c-i d) e^{-2 i (a+b x)}}{-1+c+i d}\right )-6 b x \operatorname {PolyLog}\left (3,\frac {(1+c-i d) e^{-2 i (a+b x)}}{1+c+i d}\right )-3 i \operatorname {PolyLog}\left (4,\frac {(-1+c-i d) e^{-2 i (a+b x)}}{-1+c+i d}\right )+3 i \operatorname {PolyLog}\left (4,\frac {(1+c-i d) e^{-2 i (a+b x)}}{1+c+i d}\right )}{24 b^3} \]
(8*b^3*x^3*ArcTanh[c + d*Cot[a + b*x]] + 4*b^3*x^3*Log[1 + (1 - c + I*d)/( (-1 + c + I*d)*E^((2*I)*(a + b*x)))] - 4*b^3*x^3*Log[1 + (-1 - c + I*d)/(( 1 + c + I*d)*E^((2*I)*(a + b*x)))] + (6*I)*b^2*x^2*PolyLog[2, (-1 + c - I* d)/((-1 + c + I*d)*E^((2*I)*(a + b*x)))] - (6*I)*b^2*x^2*PolyLog[2, (1 + c - I*d)/((1 + c + I*d)*E^((2*I)*(a + b*x)))] + 6*b*x*PolyLog[3, (-1 + c - I*d)/((-1 + c + I*d)*E^((2*I)*(a + b*x)))] - 6*b*x*PolyLog[3, (1 + c - I*d )/((1 + c + I*d)*E^((2*I)*(a + b*x)))] - (3*I)*PolyLog[4, (-1 + c - I*d)/( (-1 + c + I*d)*E^((2*I)*(a + b*x)))] + (3*I)*PolyLog[4, (1 + c - I*d)/((1 + c + I*d)*E^((2*I)*(a + b*x)))])/(24*b^3)
Time = 1.52 (sec) , antiderivative size = 514, normalized size of antiderivative = 1.31, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {6823, 2620, 3011, 7163, 2720, 7143}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x^2 \text {arctanh}(d \cot (a+b x)+c) \, dx\) |
\(\Big \downarrow \) 6823 |
\(\displaystyle -\frac {1}{3} b (-i c+d+i) \int \frac {e^{2 i a+2 i b x} x^3}{-c-(-c-i d+1) e^{2 i a+2 i b x}+i d+1}dx+\frac {1}{3} b (-d+i (c+1)) \int \frac {e^{2 i a+2 i b x} x^3}{c-(c+i d+1) e^{2 i a+2 i b x}-i d+1}dx+\frac {1}{3} x^3 \text {arctanh}(d \cot (a+b x)+c)\) |
\(\Big \downarrow \) 2620 |
\(\displaystyle -\frac {1}{3} b (-i c+d+i) \left (\frac {3 \int x^2 \log \left (1-\frac {(-c-i d+1) e^{2 i a+2 i b x}}{-c+i d+1}\right )dx}{2 b (d+i (1-c))}-\frac {x^3 \log \left (1-\frac {(-c-i d+1) e^{2 i a+2 i b x}}{-c+i d+1}\right )}{2 b (d+i (1-c))}\right )+\frac {1}{3} b (-d+i (c+1)) \left (\frac {3 \int x^2 \log \left (1-\frac {(c+i d+1) e^{2 i a+2 i b x}}{c-i d+1}\right )dx}{2 (-b d+i (b c+b))}-\frac {x^3 \log \left (1-\frac {(c+i d+1) e^{2 i a+2 i b x}}{c-i d+1}\right )}{2 (-b d+i (b c+b))}\right )+\frac {1}{3} x^3 \text {arctanh}(d \cot (a+b x)+c)\) |
\(\Big \downarrow \) 3011 |
\(\displaystyle -\frac {1}{3} b (-i c+d+i) \left (\frac {3 \left (\frac {i x^2 \operatorname {PolyLog}\left (2,\frac {(-c-i d+1) e^{2 i a+2 i b x}}{-c+i d+1}\right )}{2 b}-\frac {i \int x \operatorname {PolyLog}\left (2,\frac {(-c-i d+1) e^{2 i a+2 i b x}}{-c+i d+1}\right )dx}{b}\right )}{2 b (d+i (1-c))}-\frac {x^3 \log \left (1-\frac {(-c-i d+1) e^{2 i a+2 i b x}}{-c+i d+1}\right )}{2 b (d+i (1-c))}\right )+\frac {1}{3} b (-d+i (c+1)) \left (\frac {3 \left (\frac {i x^2 \operatorname {PolyLog}\left (2,\frac {(c+i d+1) e^{2 i a+2 i b x}}{c-i d+1}\right )}{2 b}-\frac {i \int x \operatorname {PolyLog}\left (2,\frac {(c+i d+1) e^{2 i a+2 i b x}}{c-i d+1}\right )dx}{b}\right )}{2 (-b d+i (b c+b))}-\frac {x^3 \log \left (1-\frac {(c+i d+1) e^{2 i a+2 i b x}}{c-i d+1}\right )}{2 (-b d+i (b c+b))}\right )+\frac {1}{3} x^3 \text {arctanh}(d \cot (a+b x)+c)\) |
\(\Big \downarrow \) 7163 |
\(\displaystyle -\frac {1}{3} b (-i c+d+i) \left (\frac {3 \left (\frac {i x^2 \operatorname {PolyLog}\left (2,\frac {(-c-i d+1) e^{2 i a+2 i b x}}{-c+i d+1}\right )}{2 b}-\frac {i \left (\frac {i \int \operatorname {PolyLog}\left (3,\frac {(-c-i d+1) e^{2 i a+2 i b x}}{-c+i d+1}\right )dx}{2 b}-\frac {i x \operatorname {PolyLog}\left (3,\frac {(-c-i d+1) e^{2 i a+2 i b x}}{-c+i d+1}\right )}{2 b}\right )}{b}\right )}{2 b (d+i (1-c))}-\frac {x^3 \log \left (1-\frac {(-c-i d+1) e^{2 i a+2 i b x}}{-c+i d+1}\right )}{2 b (d+i (1-c))}\right )+\frac {1}{3} b (-d+i (c+1)) \left (\frac {3 \left (\frac {i x^2 \operatorname {PolyLog}\left (2,\frac {(c+i d+1) e^{2 i a+2 i b x}}{c-i d+1}\right )}{2 b}-\frac {i \left (\frac {i \int \operatorname {PolyLog}\left (3,\frac {(c+i d+1) e^{2 i a+2 i b x}}{c-i d+1}\right )dx}{2 b}-\frac {i x \operatorname {PolyLog}\left (3,\frac {(c+i d+1) e^{2 i a+2 i b x}}{c-i d+1}\right )}{2 b}\right )}{b}\right )}{2 (-b d+i (b c+b))}-\frac {x^3 \log \left (1-\frac {(c+i d+1) e^{2 i a+2 i b x}}{c-i d+1}\right )}{2 (-b d+i (b c+b))}\right )+\frac {1}{3} x^3 \text {arctanh}(d \cot (a+b x)+c)\) |
\(\Big \downarrow \) 2720 |
\(\displaystyle -\frac {1}{3} b (-i c+d+i) \left (\frac {3 \left (\frac {i x^2 \operatorname {PolyLog}\left (2,\frac {(-c-i d+1) e^{2 i a+2 i b x}}{-c+i d+1}\right )}{2 b}-\frac {i \left (\frac {\int e^{-2 i a-2 i b x} \operatorname {PolyLog}\left (3,\frac {(-c-i d+1) e^{2 i a+2 i b x}}{-c+i d+1}\right )de^{2 i a+2 i b x}}{4 b^2}-\frac {i x \operatorname {PolyLog}\left (3,\frac {(-c-i d+1) e^{2 i a+2 i b x}}{-c+i d+1}\right )}{2 b}\right )}{b}\right )}{2 b (d+i (1-c))}-\frac {x^3 \log \left (1-\frac {(-c-i d+1) e^{2 i a+2 i b x}}{-c+i d+1}\right )}{2 b (d+i (1-c))}\right )+\frac {1}{3} b (-d+i (c+1)) \left (\frac {3 \left (\frac {i x^2 \operatorname {PolyLog}\left (2,\frac {(c+i d+1) e^{2 i a+2 i b x}}{c-i d+1}\right )}{2 b}-\frac {i \left (\frac {\int e^{-2 i a-2 i b x} \operatorname {PolyLog}\left (3,\frac {(c+i d+1) e^{2 i a+2 i b x}}{c-i d+1}\right )de^{2 i a+2 i b x}}{4 b^2}-\frac {i x \operatorname {PolyLog}\left (3,\frac {(c+i d+1) e^{2 i a+2 i b x}}{c-i d+1}\right )}{2 b}\right )}{b}\right )}{2 (-b d+i (b c+b))}-\frac {x^3 \log \left (1-\frac {(c+i d+1) e^{2 i a+2 i b x}}{c-i d+1}\right )}{2 (-b d+i (b c+b))}\right )+\frac {1}{3} x^3 \text {arctanh}(d \cot (a+b x)+c)\) |
\(\Big \downarrow \) 7143 |
\(\displaystyle \frac {1}{3} x^3 \text {arctanh}(d \cot (a+b x)+c)-\frac {1}{3} b (-i c+d+i) \left (\frac {3 \left (\frac {i x^2 \operatorname {PolyLog}\left (2,\frac {(-c-i d+1) e^{2 i a+2 i b x}}{-c+i d+1}\right )}{2 b}-\frac {i \left (\frac {\operatorname {PolyLog}\left (4,\frac {(-c-i d+1) e^{2 i a+2 i b x}}{-c+i d+1}\right )}{4 b^2}-\frac {i x \operatorname {PolyLog}\left (3,\frac {(-c-i d+1) e^{2 i a+2 i b x}}{-c+i d+1}\right )}{2 b}\right )}{b}\right )}{2 b (d+i (1-c))}-\frac {x^3 \log \left (1-\frac {(-c-i d+1) e^{2 i a+2 i b x}}{-c+i d+1}\right )}{2 b (d+i (1-c))}\right )+\frac {1}{3} b (-d+i (c+1)) \left (\frac {3 \left (\frac {i x^2 \operatorname {PolyLog}\left (2,\frac {(c+i d+1) e^{2 i a+2 i b x}}{c-i d+1}\right )}{2 b}-\frac {i \left (\frac {\operatorname {PolyLog}\left (4,\frac {(c+i d+1) e^{2 i a+2 i b x}}{c-i d+1}\right )}{4 b^2}-\frac {i x \operatorname {PolyLog}\left (3,\frac {(c+i d+1) e^{2 i a+2 i b x}}{c-i d+1}\right )}{2 b}\right )}{b}\right )}{2 (-b d+i (b c+b))}-\frac {x^3 \log \left (1-\frac {(c+i d+1) e^{2 i a+2 i b x}}{c-i d+1}\right )}{2 (-b d+i (b c+b))}\right )\) |
(x^3*ArcTanh[c + d*Cot[a + b*x]])/3 - (b*(I - I*c + d)*(-1/2*(x^3*Log[1 - ((1 - c - I*d)*E^((2*I)*a + (2*I)*b*x))/(1 - c + I*d)])/(b*(I*(1 - c) + d) ) + (3*(((I/2)*x^2*PolyLog[2, ((1 - c - I*d)*E^((2*I)*a + (2*I)*b*x))/(1 - c + I*d)])/b - (I*(((-1/2*I)*x*PolyLog[3, ((1 - c - I*d)*E^((2*I)*a + (2* I)*b*x))/(1 - c + I*d)])/b + PolyLog[4, ((1 - c - I*d)*E^((2*I)*a + (2*I)* b*x))/(1 - c + I*d)]/(4*b^2)))/b))/(2*b*(I*(1 - c) + d))))/3 + (b*(I*(1 + c) - d)*(-1/2*(x^3*Log[1 - ((1 + c + I*d)*E^((2*I)*a + (2*I)*b*x))/(1 + c - I*d)])/(I*(b + b*c) - b*d) + (3*(((I/2)*x^2*PolyLog[2, ((1 + c + I*d)*E^ ((2*I)*a + (2*I)*b*x))/(1 + c - I*d)])/b - (I*(((-1/2*I)*x*PolyLog[3, ((1 + c + I*d)*E^((2*I)*a + (2*I)*b*x))/(1 + c - I*d)])/b + PolyLog[4, ((1 + c + I*d)*E^((2*I)*a + (2*I)*b*x))/(1 + c - I*d)]/(4*b^2)))/b))/(2*(I*(b + b *c) - b*d))))/3
3.4.34.3.1 Defintions of rubi rules used
Int[(((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)*((c_.) + (d_.)*(x_))^(m_.))/ ((a_) + (b_.)*((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)), x_Symbol] :> Simp [((c + d*x)^m/(b*f*g*n*Log[F]))*Log[1 + b*((F^(g*(e + f*x)))^n/a)], x] - Si mp[d*(m/(b*f*g*n*Log[F])) Int[(c + d*x)^(m - 1)*Log[1 + b*((F^(g*(e + f*x )))^n/a)], x], x] /; FreeQ[{F, a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]
Int[u_, x_Symbol] :> With[{v = FunctionOfExponential[u, x]}, Simp[v/D[v, x] Subst[Int[FunctionOfExponentialFunction[u, x]/x, x], x, v], x]] /; Funct ionOfExponentialQ[u, x] && !MatchQ[u, (w_)*((a_.)*(v_)^(n_))^(m_) /; FreeQ [{a, m, n}, x] && IntegerQ[m*n]] && !MatchQ[u, E^((c_.)*((a_.) + (b_.)*x)) *(F_)[v_] /; FreeQ[{a, b, c}, x] && InverseFunctionQ[F[x]]]
Int[Log[1 + (e_.)*((F_)^((c_.)*((a_.) + (b_.)*(x_))))^(n_.)]*((f_.) + (g_.) *(x_))^(m_.), x_Symbol] :> Simp[(-(f + g*x)^m)*(PolyLog[2, (-e)*(F^(c*(a + b*x)))^n]/(b*c*n*Log[F])), x] + Simp[g*(m/(b*c*n*Log[F])) Int[(f + g*x)^( m - 1)*PolyLog[2, (-e)*(F^(c*(a + b*x)))^n], x], x] /; FreeQ[{F, a, b, c, e , f, g, n}, x] && GtQ[m, 0]
Int[ArcTanh[(c_.) + Cot[(a_.) + (b_.)*(x_)]*(d_.)]*((e_.) + (f_.)*(x_))^(m_ .), x_Symbol] :> Simp[(e + f*x)^(m + 1)*(ArcTanh[c + d*Cot[a + b*x]]/(f*(m + 1))), x] + (-Simp[I*b*((1 - c - I*d)/(f*(m + 1))) Int[(e + f*x)^(m + 1) *(E^(2*I*a + 2*I*b*x)/(1 - c + I*d - (1 - c - I*d)*E^(2*I*a + 2*I*b*x))), x ], x] + Simp[I*b*((1 + c + I*d)/(f*(m + 1))) Int[(e + f*x)^(m + 1)*(E^(2* I*a + 2*I*b*x)/(1 + c - I*d - (1 + c + I*d)*E^(2*I*a + 2*I*b*x))), x], x]) /; FreeQ[{a, b, c, d, e, f}, x] && IGtQ[m, 0] && NeQ[(c - I*d)^2, 1]
Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_S ymbol] :> Simp[PolyLog[n + 1, c*(a + b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d , e, n, p}, x] && EqQ[b*d, a*e]
Int[((e_.) + (f_.)*(x_))^(m_.)*PolyLog[n_, (d_.)*((F_)^((c_.)*((a_.) + (b_. )*(x_))))^(p_.)], x_Symbol] :> Simp[(e + f*x)^m*(PolyLog[n + 1, d*(F^(c*(a + b*x)))^p]/(b*c*p*Log[F])), x] - Simp[f*(m/(b*c*p*Log[F])) Int[(e + f*x) ^(m - 1)*PolyLog[n + 1, d*(F^(c*(a + b*x)))^p], x], x] /; FreeQ[{F, a, b, c , d, e, f, n, p}, x] && GtQ[m, 0]
Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 24.30 (sec) , antiderivative size = 6693, normalized size of antiderivative = 17.12
Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 1799 vs. \(2 (275) = 550\).
Time = 0.46 (sec) , antiderivative size = 1799, normalized size of antiderivative = 4.60 \[ \int x^2 \text {arctanh}(c+d \cot (a+b x)) \, dx=\text {Too large to display} \]
1/48*(8*b^3*x^3*log(-(d*cos(2*b*x + 2*a) + (c + 1)*sin(2*b*x + 2*a) + d)/( d*cos(2*b*x + 2*a) + (c - 1)*sin(2*b*x + 2*a) + d)) + 6*I*b^2*x^2*dilog(-( c^2 + d^2 - (c^2 + 2*I*(c + 1)*d - d^2 + 2*c + 1)*cos(2*b*x + 2*a) + (-I*c ^2 + 2*(c + 1)*d + I*d^2 - 2*I*c - I)*sin(2*b*x + 2*a) + 2*c + 1)/(c^2 + d ^2 + 2*c + 1) + 1) - 6*I*b^2*x^2*dilog(-(c^2 + d^2 - (c^2 - 2*I*(c + 1)*d - d^2 + 2*c + 1)*cos(2*b*x + 2*a) + (I*c^2 + 2*(c + 1)*d - I*d^2 + 2*I*c + I)*sin(2*b*x + 2*a) + 2*c + 1)/(c^2 + d^2 + 2*c + 1) + 1) - 6*I*b^2*x^2*d ilog(-(c^2 + d^2 - (c^2 + 2*I*(c - 1)*d - d^2 - 2*c + 1)*cos(2*b*x + 2*a) + (-I*c^2 + 2*(c - 1)*d + I*d^2 + 2*I*c - I)*sin(2*b*x + 2*a) - 2*c + 1)/( c^2 + d^2 - 2*c + 1) + 1) + 6*I*b^2*x^2*dilog(-(c^2 + d^2 - (c^2 - 2*I*(c - 1)*d - d^2 - 2*c + 1)*cos(2*b*x + 2*a) + (I*c^2 + 2*(c - 1)*d - I*d^2 - 2*I*c + I)*sin(2*b*x + 2*a) - 2*c + 1)/(c^2 + d^2 - 2*c + 1) + 1) + 4*a^3* log(1/2*c^2 + I*(c + 1)*d - 1/2*d^2 - 1/2*(c^2 + d^2 + 2*c + 1)*cos(2*b*x + 2*a) + 1/2*(I*c^2 + I*d^2 + 2*I*c + I)*sin(2*b*x + 2*a) + c + 1/2) - 4*a ^3*log(1/2*c^2 + I*(c - 1)*d - 1/2*d^2 - 1/2*(c^2 + d^2 - 2*c + 1)*cos(2*b *x + 2*a) + 1/2*(I*c^2 + I*d^2 - 2*I*c + I)*sin(2*b*x + 2*a) - c + 1/2) + 4*a^3*log(-1/2*c^2 + I*(c + 1)*d + 1/2*d^2 + 1/2*(c^2 + d^2 + 2*c + 1)*cos (2*b*x + 2*a) + 1/2*(I*c^2 + I*d^2 + 2*I*c + I)*sin(2*b*x + 2*a) - c - 1/2 ) - 4*a^3*log(-1/2*c^2 + I*(c - 1)*d + 1/2*d^2 + 1/2*(c^2 + d^2 - 2*c + 1) *cos(2*b*x + 2*a) + 1/2*(I*c^2 + I*d^2 - 2*I*c + I)*sin(2*b*x + 2*a) + ...
\[ \int x^2 \text {arctanh}(c+d \cot (a+b x)) \, dx=\int x^{2} \operatorname {atanh}{\left (c + d \cot {\left (a + b x \right )} \right )}\, dx \]
\[ \int x^2 \text {arctanh}(c+d \cot (a+b x)) \, dx=\int { x^{2} \operatorname {artanh}\left (d \cot \left (b x + a\right ) + c\right ) \,d x } \]
1/12*x^3*log((c^2 + d^2 + 2*c + 1)*cos(2*b*x + 2*a)^2 + 4*(c + 1)*d*sin(2* b*x + 2*a) + (c^2 + d^2 + 2*c + 1)*sin(2*b*x + 2*a)^2 + c^2 + d^2 - 2*(c^2 - d^2 + 2*c + 1)*cos(2*b*x + 2*a) + 2*c + 1) - 1/12*x^3*log((c^2 + d^2 - 2*c + 1)*cos(2*b*x + 2*a)^2 + 4*(c - 1)*d*sin(2*b*x + 2*a) + (c^2 + d^2 - 2*c + 1)*sin(2*b*x + 2*a)^2 + c^2 + d^2 - 2*(c^2 - d^2 - 2*c + 1)*cos(2*b* x + 2*a) - 2*c + 1) - 4*b*d*integrate(1/3*(2*(c^2 + d^2 - 1)*x^3*cos(2*b*x + 2*a)^2 + 2*c*d*x^3*sin(2*b*x + 2*a) + 2*(c^2 + d^2 - 1)*x^3*sin(2*b*x + 2*a)^2 - (c^2 - d^2 - 1)*x^3*cos(2*b*x + 2*a) - (2*c*d*x^3*sin(2*b*x + 2* a) + (c^2 - d^2 - 1)*x^3*cos(2*b*x + 2*a))*cos(4*b*x + 4*a) + (2*c*d*x^3*c os(2*b*x + 2*a) - (c^2 - d^2 - 1)*x^3*sin(2*b*x + 2*a))*sin(4*b*x + 4*a))/ (c^4 + d^4 + 2*(c^2 + 1)*d^2 + (c^4 + d^4 + 2*(c^2 + 1)*d^2 - 2*c^2 + 1)*c os(4*b*x + 4*a)^2 + 4*(c^4 + d^4 + 2*(c^2 - 1)*d^2 - 2*c^2 + 1)*cos(2*b*x + 2*a)^2 + (c^4 + d^4 + 2*(c^2 + 1)*d^2 - 2*c^2 + 1)*sin(4*b*x + 4*a)^2 + 4*(c^4 + d^4 + 2*(c^2 - 1)*d^2 - 2*c^2 + 1)*sin(2*b*x + 2*a)^2 - 2*c^2 + 2 *(c^4 + d^4 - 2*(3*c^2 - 1)*d^2 - 2*c^2 - 2*(c^4 - d^4 - 2*c^2 + 1)*cos(2* b*x + 2*a) - 4*(c*d^3 + (c^3 - c)*d)*sin(2*b*x + 2*a) + 1)*cos(4*b*x + 4*a ) - 4*(c^4 - d^4 - 2*c^2 + 1)*cos(2*b*x + 2*a) + 4*(2*c*d^3 - 2*(c^3 - c)* d + 2*(c*d^3 + (c^3 - c)*d)*cos(2*b*x + 2*a) - (c^4 - d^4 - 2*c^2 + 1)*sin (2*b*x + 2*a))*sin(4*b*x + 4*a) + 8*(c*d^3 + (c^3 - c)*d)*sin(2*b*x + 2*a) + 1), x)
\[ \int x^2 \text {arctanh}(c+d \cot (a+b x)) \, dx=\int { x^{2} \operatorname {artanh}\left (d \cot \left (b x + a\right ) + c\right ) \,d x } \]
Timed out. \[ \int x^2 \text {arctanh}(c+d \cot (a+b x)) \, dx=\int x^2\,\mathrm {atanh}\left (c+d\,\mathrm {cot}\left (a+b\,x\right )\right ) \,d x \]