Integrand size = 18, antiderivative size = 78 \[ \int e^{3 \coth ^{-1}(a x)} (c-a c x)^3 \, dx=\frac {3}{8} a c^3 \sqrt {1-\frac {1}{a^2 x^2}} x^2-\frac {1}{4} a^3 c^3 \left (1-\frac {1}{a^2 x^2}\right )^{3/2} x^4-\frac {3 c^3 \text {arctanh}\left (\sqrt {1-\frac {1}{a^2 x^2}}\right )}{8 a} \]
-1/4*a^3*c^3*(1-1/a^2/x^2)^(3/2)*x^4-3/8*c^3*arctanh((1-1/a^2/x^2)^(1/2))/ a+3/8*a*c^3*x^2*(1-1/a^2/x^2)^(1/2)
Time = 0.19 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.82 \[ \int e^{3 \coth ^{-1}(a x)} (c-a c x)^3 \, dx=\frac {c^3 \left (a^2 \sqrt {1-\frac {1}{a^2 x^2}} x^2 \left (5-2 a^2 x^2\right )-3 \log \left (a \left (1+\sqrt {1-\frac {1}{a^2 x^2}}\right ) x\right )\right )}{8 a} \]
(c^3*(a^2*Sqrt[1 - 1/(a^2*x^2)]*x^2*(5 - 2*a^2*x^2) - 3*Log[a*(1 + Sqrt[1 - 1/(a^2*x^2)])*x]))/(8*a)
Time = 0.26 (sec) , antiderivative size = 76, normalized size of antiderivative = 0.97, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {6724, 243, 51, 51, 73, 221}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int (c-a c x)^3 e^{3 \coth ^{-1}(a x)} \, dx\) |
\(\Big \downarrow \) 6724 |
\(\displaystyle a^3 c^3 \int \left (1-\frac {1}{a^2 x^2}\right )^{3/2} x^5d\frac {1}{x}\) |
\(\Big \downarrow \) 243 |
\(\displaystyle \frac {1}{2} a^3 c^3 \int \left (1-\frac {1}{a^2 x^2}\right )^{3/2} x^3d\frac {1}{x^2}\) |
\(\Big \downarrow \) 51 |
\(\displaystyle \frac {1}{2} a^3 c^3 \left (-\frac {3 \int \sqrt {1-\frac {1}{a^2 x^2}} x^2d\frac {1}{x^2}}{4 a^2}-\frac {1}{2} x^2 \left (1-\frac {1}{a^2 x^2}\right )^{3/2}\right )\) |
\(\Big \downarrow \) 51 |
\(\displaystyle \frac {1}{2} a^3 c^3 \left (-\frac {3 \left (x \left (-\sqrt {1-\frac {1}{a^2 x^2}}\right )-\frac {\int \frac {x}{\sqrt {1-\frac {1}{a^2 x^2}}}d\frac {1}{x^2}}{2 a^2}\right )}{4 a^2}-\frac {1}{2} x^2 \left (1-\frac {1}{a^2 x^2}\right )^{3/2}\right )\) |
\(\Big \downarrow \) 73 |
\(\displaystyle \frac {1}{2} a^3 c^3 \left (-\frac {3 \left (\int \frac {1}{a^2-a^2 \sqrt {1-\frac {1}{a^2 x^2}}}d\sqrt {1-\frac {1}{a^2 x^2}}-x \sqrt {1-\frac {1}{a^2 x^2}}\right )}{4 a^2}-\frac {1}{2} x^2 \left (1-\frac {1}{a^2 x^2}\right )^{3/2}\right )\) |
\(\Big \downarrow \) 221 |
\(\displaystyle \frac {1}{2} a^3 c^3 \left (-\frac {3 \left (\frac {\text {arctanh}\left (\sqrt {1-\frac {1}{a^2 x^2}}\right )}{a^2}-x \sqrt {1-\frac {1}{a^2 x^2}}\right )}{4 a^2}-\frac {1}{2} x^2 \left (1-\frac {1}{a^2 x^2}\right )^{3/2}\right )\) |
(a^3*c^3*(-1/2*((1 - 1/(a^2*x^2))^(3/2)*x^2) - (3*(-(Sqrt[1 - 1/(a^2*x^2)] *x) + ArcTanh[Sqrt[1 - 1/(a^2*x^2)]]/a^2))/(4*a^2)))/2
3.2.79.3.1 Defintions of rubi rules used
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + 1))), x] - Simp[d*(n/(b*(m + 1))) Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d, n}, x ] && ILtQ[m, -1] && FractionQ[n] && GtQ[n, 0]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ {p = Denominator[m]}, Simp[p/b Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL inearQ[a, b, c, d, m, n, x]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x /Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[1/2 Subst[In t[x^((m - 1)/2)*(a + b*x)^p, x], x, x^2], x] /; FreeQ[{a, b, m, p}, x] && I ntegerQ[(m - 1)/2]
Int[E^(ArcCoth[(a_.)*(x_)]*(n_.))*((c_) + (d_.)*(x_))^(p_.), x_Symbol] :> S imp[-d^n Subst[Int[(d + c*x)^(p - n)*((1 - x^2/a^2)^(n/2)/x^(p + 2)), x], x, 1/x], x] /; FreeQ[{a, c, d}, x] && EqQ[a*c + d, 0] && IntegerQ[p] && In tegerQ[n]
Time = 0.42 (sec) , antiderivative size = 106, normalized size of antiderivative = 1.36
method | result | size |
risch | \(-\frac {x \left (2 a^{2} x^{2}-5\right ) \left (a x -1\right ) c^{3}}{8 \sqrt {\frac {a x -1}{a x +1}}}-\frac {3 \ln \left (\frac {a^{2} x}{\sqrt {a^{2}}}+\sqrt {a^{2} x^{2}-1}\right ) c^{3} \sqrt {\left (a x -1\right ) \left (a x +1\right )}}{8 \sqrt {a^{2}}\, \left (a x +1\right ) \sqrt {\frac {a x -1}{a x +1}}}\) | \(106\) |
default | \(-\frac {\left (a x -1\right )^{2} c^{3} \left (2 x \left (a^{2} x^{2}-1\right )^{\frac {3}{2}} \sqrt {a^{2}}-3 x \sqrt {a^{2} x^{2}-1}\, \sqrt {a^{2}}+3 \ln \left (\frac {a^{2} x +\sqrt {a^{2} x^{2}-1}\, \sqrt {a^{2}}}{\sqrt {a^{2}}}\right )\right )}{8 \left (\frac {a x -1}{a x +1}\right )^{\frac {3}{2}} \left (a x +1\right ) \sqrt {\left (a x -1\right ) \left (a x +1\right )}\, \sqrt {a^{2}}}\) | \(124\) |
-1/8*x*(2*a^2*x^2-5)*(a*x-1)*c^3/((a*x-1)/(a*x+1))^(1/2)-3/8*ln(a^2*x/(a^2 )^(1/2)+(a^2*x^2-1)^(1/2))/(a^2)^(1/2)*c^3/(a*x+1)/((a*x-1)/(a*x+1))^(1/2) *((a*x-1)*(a*x+1))^(1/2)
Time = 0.26 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.40 \[ \int e^{3 \coth ^{-1}(a x)} (c-a c x)^3 \, dx=-\frac {3 \, c^{3} \log \left (\sqrt {\frac {a x - 1}{a x + 1}} + 1\right ) - 3 \, c^{3} \log \left (\sqrt {\frac {a x - 1}{a x + 1}} - 1\right ) + {\left (2 \, a^{4} c^{3} x^{4} + 2 \, a^{3} c^{3} x^{3} - 5 \, a^{2} c^{3} x^{2} - 5 \, a c^{3} x\right )} \sqrt {\frac {a x - 1}{a x + 1}}}{8 \, a} \]
-1/8*(3*c^3*log(sqrt((a*x - 1)/(a*x + 1)) + 1) - 3*c^3*log(sqrt((a*x - 1)/ (a*x + 1)) - 1) + (2*a^4*c^3*x^4 + 2*a^3*c^3*x^3 - 5*a^2*c^3*x^2 - 5*a*c^3 *x)*sqrt((a*x - 1)/(a*x + 1)))/a
\[ \int e^{3 \coth ^{-1}(a x)} (c-a c x)^3 \, dx=- c^{3} \left (\int \frac {3 a x}{\frac {a x \sqrt {\frac {a x}{a x + 1} - \frac {1}{a x + 1}}}{a x + 1} - \frac {\sqrt {\frac {a x}{a x + 1} - \frac {1}{a x + 1}}}{a x + 1}}\, dx + \int \left (- \frac {3 a^{2} x^{2}}{\frac {a x \sqrt {\frac {a x}{a x + 1} - \frac {1}{a x + 1}}}{a x + 1} - \frac {\sqrt {\frac {a x}{a x + 1} - \frac {1}{a x + 1}}}{a x + 1}}\right )\, dx + \int \frac {a^{3} x^{3}}{\frac {a x \sqrt {\frac {a x}{a x + 1} - \frac {1}{a x + 1}}}{a x + 1} - \frac {\sqrt {\frac {a x}{a x + 1} - \frac {1}{a x + 1}}}{a x + 1}}\, dx + \int \left (- \frac {1}{\frac {a x \sqrt {\frac {a x}{a x + 1} - \frac {1}{a x + 1}}}{a x + 1} - \frac {\sqrt {\frac {a x}{a x + 1} - \frac {1}{a x + 1}}}{a x + 1}}\right )\, dx\right ) \]
-c**3*(Integral(3*a*x/(a*x*sqrt(a*x/(a*x + 1) - 1/(a*x + 1))/(a*x + 1) - s qrt(a*x/(a*x + 1) - 1/(a*x + 1))/(a*x + 1)), x) + Integral(-3*a**2*x**2/(a *x*sqrt(a*x/(a*x + 1) - 1/(a*x + 1))/(a*x + 1) - sqrt(a*x/(a*x + 1) - 1/(a *x + 1))/(a*x + 1)), x) + Integral(a**3*x**3/(a*x*sqrt(a*x/(a*x + 1) - 1/( a*x + 1))/(a*x + 1) - sqrt(a*x/(a*x + 1) - 1/(a*x + 1))/(a*x + 1)), x) + I ntegral(-1/(a*x*sqrt(a*x/(a*x + 1) - 1/(a*x + 1))/(a*x + 1) - sqrt(a*x/(a* x + 1) - 1/(a*x + 1))/(a*x + 1)), x))
Leaf count of result is larger than twice the leaf count of optimal. 221 vs. \(2 (66) = 132\).
Time = 0.20 (sec) , antiderivative size = 221, normalized size of antiderivative = 2.83 \[ \int e^{3 \coth ^{-1}(a x)} (c-a c x)^3 \, dx=-\frac {1}{8} \, {\left (\frac {3 \, c^{3} \log \left (\sqrt {\frac {a x - 1}{a x + 1}} + 1\right )}{a^{2}} - \frac {3 \, c^{3} \log \left (\sqrt {\frac {a x - 1}{a x + 1}} - 1\right )}{a^{2}} + \frac {2 \, {\left (3 \, c^{3} \left (\frac {a x - 1}{a x + 1}\right )^{\frac {7}{2}} - 11 \, c^{3} \left (\frac {a x - 1}{a x + 1}\right )^{\frac {5}{2}} - 11 \, c^{3} \left (\frac {a x - 1}{a x + 1}\right )^{\frac {3}{2}} + 3 \, c^{3} \sqrt {\frac {a x - 1}{a x + 1}}\right )}}{\frac {4 \, {\left (a x - 1\right )} a^{2}}{a x + 1} - \frac {6 \, {\left (a x - 1\right )}^{2} a^{2}}{{\left (a x + 1\right )}^{2}} + \frac {4 \, {\left (a x - 1\right )}^{3} a^{2}}{{\left (a x + 1\right )}^{3}} - \frac {{\left (a x - 1\right )}^{4} a^{2}}{{\left (a x + 1\right )}^{4}} - a^{2}}\right )} a \]
-1/8*(3*c^3*log(sqrt((a*x - 1)/(a*x + 1)) + 1)/a^2 - 3*c^3*log(sqrt((a*x - 1)/(a*x + 1)) - 1)/a^2 + 2*(3*c^3*((a*x - 1)/(a*x + 1))^(7/2) - 11*c^3*(( a*x - 1)/(a*x + 1))^(5/2) - 11*c^3*((a*x - 1)/(a*x + 1))^(3/2) + 3*c^3*sqr t((a*x - 1)/(a*x + 1)))/(4*(a*x - 1)*a^2/(a*x + 1) - 6*(a*x - 1)^2*a^2/(a* x + 1)^2 + 4*(a*x - 1)^3*a^2/(a*x + 1)^3 - (a*x - 1)^4*a^2/(a*x + 1)^4 - a ^2))*a
Time = 0.28 (sec) , antiderivative size = 84, normalized size of antiderivative = 1.08 \[ \int e^{3 \coth ^{-1}(a x)} (c-a c x)^3 \, dx=-\frac {1}{8} \, {\left (\frac {2 \, a^{2} c^{3} x^{2}}{\mathrm {sgn}\left (a x + 1\right )} - \frac {5 \, c^{3}}{\mathrm {sgn}\left (a x + 1\right )}\right )} \sqrt {a^{2} x^{2} - 1} x + \frac {3 \, c^{3} \log \left ({\left | -x {\left | a \right |} + \sqrt {a^{2} x^{2} - 1} \right |}\right )}{8 \, {\left | a \right |} \mathrm {sgn}\left (a x + 1\right )} \]
-1/8*(2*a^2*c^3*x^2/sgn(a*x + 1) - 5*c^3/sgn(a*x + 1))*sqrt(a^2*x^2 - 1)*x + 3/8*c^3*log(abs(-x*abs(a) + sqrt(a^2*x^2 - 1)))/(abs(a)*sgn(a*x + 1))
Time = 4.33 (sec) , antiderivative size = 176, normalized size of antiderivative = 2.26 \[ \int e^{3 \coth ^{-1}(a x)} (c-a c x)^3 \, dx=\frac {\frac {3\,c^3\,\sqrt {\frac {a\,x-1}{a\,x+1}}}{4}-\frac {11\,c^3\,{\left (\frac {a\,x-1}{a\,x+1}\right )}^{3/2}}{4}-\frac {11\,c^3\,{\left (\frac {a\,x-1}{a\,x+1}\right )}^{5/2}}{4}+\frac {3\,c^3\,{\left (\frac {a\,x-1}{a\,x+1}\right )}^{7/2}}{4}}{a-\frac {4\,a\,\left (a\,x-1\right )}{a\,x+1}+\frac {6\,a\,{\left (a\,x-1\right )}^2}{{\left (a\,x+1\right )}^2}-\frac {4\,a\,{\left (a\,x-1\right )}^3}{{\left (a\,x+1\right )}^3}+\frac {a\,{\left (a\,x-1\right )}^4}{{\left (a\,x+1\right )}^4}}-\frac {3\,c^3\,\mathrm {atanh}\left (\sqrt {\frac {a\,x-1}{a\,x+1}}\right )}{4\,a} \]
((3*c^3*((a*x - 1)/(a*x + 1))^(1/2))/4 - (11*c^3*((a*x - 1)/(a*x + 1))^(3/ 2))/4 - (11*c^3*((a*x - 1)/(a*x + 1))^(5/2))/4 + (3*c^3*((a*x - 1)/(a*x + 1))^(7/2))/4)/(a - (4*a*(a*x - 1))/(a*x + 1) + (6*a*(a*x - 1)^2)/(a*x + 1) ^2 - (4*a*(a*x - 1)^3)/(a*x + 1)^3 + (a*(a*x - 1)^4)/(a*x + 1)^4) - (3*c^3 *atanh(((a*x - 1)/(a*x + 1))^(1/2)))/(4*a)