Integrand size = 22, antiderivative size = 127 \[ \int \frac {e^{3 \coth ^{-1}(a x)}}{\left (c-a^2 c x^2\right )^4} \, dx=-\frac {16 e^{3 \coth ^{-1}(a x)}}{63 a c^4}-\frac {e^{3 \coth ^{-1}(a x)} (1-2 a x)}{9 a c^4 \left (1-a^2 x^2\right )^3}-\frac {10 e^{3 \coth ^{-1}(a x)} (3-4 a x)}{63 a c^4 \left (1-a^2 x^2\right )^2}+\frac {8 e^{3 \coth ^{-1}(a x)} (3-2 a x)}{21 a c^4 \left (1-a^2 x^2\right )} \]
-16/63/((a*x-1)/(a*x+1))^(3/2)/a/c^4-1/9/((a*x-1)/(a*x+1))^(3/2)*(-2*a*x+1 )/a/c^4/(-a^2*x^2+1)^3-10/63/((a*x-1)/(a*x+1))^(3/2)*(-4*a*x+3)/a/c^4/(-a^ 2*x^2+1)^2+8/21/((a*x-1)/(a*x+1))^(3/2)*(-2*a*x+3)/a/c^4/(-a^2*x^2+1)
Time = 0.49 (sec) , antiderivative size = 82, normalized size of antiderivative = 0.65 \[ \int \frac {e^{3 \coth ^{-1}(a x)}}{\left (c-a^2 c x^2\right )^4} \, dx=-\frac {\sqrt {1-\frac {1}{a^2 x^2}} x \left (19+6 a x-66 a^2 x^2+56 a^3 x^3+24 a^4 x^4-48 a^5 x^5+16 a^6 x^6\right )}{63 c^4 (-1+a x)^5 (1+a x)^2} \]
-1/63*(Sqrt[1 - 1/(a^2*x^2)]*x*(19 + 6*a*x - 66*a^2*x^2 + 56*a^3*x^3 + 24* a^4*x^4 - 48*a^5*x^5 + 16*a^6*x^6))/(c^4*(-1 + a*x)^5*(1 + a*x)^2)
Time = 0.59 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.03, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.227, Rules used = {6739, 27, 6739, 6739, 6737}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {e^{3 \coth ^{-1}(a x)}}{\left (c-a^2 c x^2\right )^4} \, dx\) |
\(\Big \downarrow \) 6739 |
\(\displaystyle \frac {10 \int \frac {e^{3 \coth ^{-1}(a x)}}{c^3 \left (1-a^2 x^2\right )^3}dx}{9 c}-\frac {(1-2 a x) e^{3 \coth ^{-1}(a x)}}{9 a c^4 \left (1-a^2 x^2\right )^3}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {10 \int \frac {e^{3 \coth ^{-1}(a x)}}{\left (1-a^2 x^2\right )^3}dx}{9 c^4}-\frac {(1-2 a x) e^{3 \coth ^{-1}(a x)}}{9 a c^4 \left (1-a^2 x^2\right )^3}\) |
\(\Big \downarrow \) 6739 |
\(\displaystyle \frac {10 \left (\frac {12}{7} \int \frac {e^{3 \coth ^{-1}(a x)}}{\left (1-a^2 x^2\right )^2}dx-\frac {(3-4 a x) e^{3 \coth ^{-1}(a x)}}{7 a \left (1-a^2 x^2\right )^2}\right )}{9 c^4}-\frac {(1-2 a x) e^{3 \coth ^{-1}(a x)}}{9 a c^4 \left (1-a^2 x^2\right )^3}\) |
\(\Big \downarrow \) 6739 |
\(\displaystyle \frac {10 \left (\frac {12}{7} \left (\frac {(3-2 a x) e^{3 \coth ^{-1}(a x)}}{5 a \left (1-a^2 x^2\right )}-\frac {2}{5} \int \frac {e^{3 \coth ^{-1}(a x)}}{1-a^2 x^2}dx\right )-\frac {(3-4 a x) e^{3 \coth ^{-1}(a x)}}{7 a \left (1-a^2 x^2\right )^2}\right )}{9 c^4}-\frac {(1-2 a x) e^{3 \coth ^{-1}(a x)}}{9 a c^4 \left (1-a^2 x^2\right )^3}\) |
\(\Big \downarrow \) 6737 |
\(\displaystyle \frac {10 \left (\frac {12}{7} \left (\frac {(3-2 a x) e^{3 \coth ^{-1}(a x)}}{5 a \left (1-a^2 x^2\right )}-\frac {2 e^{3 \coth ^{-1}(a x)}}{15 a}\right )-\frac {(3-4 a x) e^{3 \coth ^{-1}(a x)}}{7 a \left (1-a^2 x^2\right )^2}\right )}{9 c^4}-\frac {(1-2 a x) e^{3 \coth ^{-1}(a x)}}{9 a c^4 \left (1-a^2 x^2\right )^3}\) |
-1/9*(E^(3*ArcCoth[a*x])*(1 - 2*a*x))/(a*c^4*(1 - a^2*x^2)^3) + (10*(-1/7* (E^(3*ArcCoth[a*x])*(3 - 4*a*x))/(a*(1 - a^2*x^2)^2) + (12*((-2*E^(3*ArcCo th[a*x]))/(15*a) + (E^(3*ArcCoth[a*x])*(3 - 2*a*x))/(5*a*(1 - a^2*x^2))))/ 7))/(9*c^4)
3.6.80.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[E^(ArcCoth[(a_.)*(x_)]*(n_.))/((c_) + (d_.)*(x_)^2), x_Symbol] :> Simp[ E^(n*ArcCoth[a*x])/(a*c*n), x] /; FreeQ[{a, c, d, n}, x] && EqQ[a^2*c + d, 0] && !IntegerQ[n/2]
Int[E^(ArcCoth[(a_.)*(x_)]*(n_.))*((c_) + (d_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(n + 2*a*(p + 1)*x)*(c + d*x^2)^(p + 1)*(E^(n*ArcCoth[a*x])/(a*c*(n^2 - 4*(p + 1)^2))), x] - Simp[2*(p + 1)*((2*p + 3)/(c*(n^2 - 4*(p + 1)^2))) Int[(c + d*x^2)^(p + 1)*E^(n*ArcCoth[a*x]), x], x] /; FreeQ[{a, c, d, n}, x] && EqQ[a^2*c + d, 0] && !IntegerQ[n/2] && LtQ[p, -1] && NeQ[p, -3/2] && NeQ[n^2 - 4*(p + 1)^2, 0] && (IntegerQ[p] || !IntegerQ[n])
Time = 0.49 (sec) , antiderivative size = 81, normalized size of antiderivative = 0.64
method | result | size |
gosper | \(-\frac {16 a^{6} x^{6}-48 a^{5} x^{5}+24 a^{4} x^{4}+56 a^{3} x^{3}-66 a^{2} x^{2}+6 a x +19}{63 \left (a^{2} x^{2}-1\right )^{3} c^{4} \left (\frac {a x -1}{a x +1}\right )^{\frac {3}{2}} a}\) | \(81\) |
default | \(-\frac {16 a^{6} x^{6}-48 a^{5} x^{5}+24 a^{4} x^{4}+56 a^{3} x^{3}-66 a^{2} x^{2}+6 a x +19}{63 \left (\frac {a x -1}{a x +1}\right )^{\frac {3}{2}} \left (a x +1\right )^{3} c^{4} \left (a x -1\right )^{3} a}\) | \(84\) |
trager | \(-\frac {\left (16 a^{6} x^{6}-48 a^{5} x^{5}+24 a^{4} x^{4}+56 a^{3} x^{3}-66 a^{2} x^{2}+6 a x +19\right ) \sqrt {-\frac {-a x +1}{a x +1}}}{63 a \,c^{4} \left (a x +1\right ) \left (a x -1\right )^{5}}\) | \(86\) |
-1/63*(16*a^6*x^6-48*a^5*x^5+24*a^4*x^4+56*a^3*x^3-66*a^2*x^2+6*a*x+19)/(a ^2*x^2-1)^3/c^4/((a*x-1)/(a*x+1))^(3/2)/a
Time = 0.25 (sec) , antiderivative size = 124, normalized size of antiderivative = 0.98 \[ \int \frac {e^{3 \coth ^{-1}(a x)}}{\left (c-a^2 c x^2\right )^4} \, dx=-\frac {{\left (16 \, a^{6} x^{6} - 48 \, a^{5} x^{5} + 24 \, a^{4} x^{4} + 56 \, a^{3} x^{3} - 66 \, a^{2} x^{2} + 6 \, a x + 19\right )} \sqrt {\frac {a x - 1}{a x + 1}}}{63 \, {\left (a^{7} c^{4} x^{6} - 4 \, a^{6} c^{4} x^{5} + 5 \, a^{5} c^{4} x^{4} - 5 \, a^{3} c^{4} x^{2} + 4 \, a^{2} c^{4} x - a c^{4}\right )}} \]
-1/63*(16*a^6*x^6 - 48*a^5*x^5 + 24*a^4*x^4 + 56*a^3*x^3 - 66*a^2*x^2 + 6* a*x + 19)*sqrt((a*x - 1)/(a*x + 1))/(a^7*c^4*x^6 - 4*a^6*c^4*x^5 + 5*a^5*c ^4*x^4 - 5*a^3*c^4*x^2 + 4*a^2*c^4*x - a*c^4)
Timed out. \[ \int \frac {e^{3 \coth ^{-1}(a x)}}{\left (c-a^2 c x^2\right )^4} \, dx=\text {Timed out} \]
Time = 0.19 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.03 \[ \int \frac {e^{3 \coth ^{-1}(a x)}}{\left (c-a^2 c x^2\right )^4} \, dx=\frac {1}{4032} \, a {\left (\frac {21 \, {\left (\left (\frac {a x - 1}{a x + 1}\right )^{\frac {3}{2}} - 18 \, \sqrt {\frac {a x - 1}{a x + 1}}\right )}}{a^{2} c^{4}} + \frac {\frac {54 \, {\left (a x - 1\right )}}{a x + 1} - \frac {189 \, {\left (a x - 1\right )}^{2}}{{\left (a x + 1\right )}^{2}} + \frac {420 \, {\left (a x - 1\right )}^{3}}{{\left (a x + 1\right )}^{3}} - \frac {945 \, {\left (a x - 1\right )}^{4}}{{\left (a x + 1\right )}^{4}} - 7}{a^{2} c^{4} \left (\frac {a x - 1}{a x + 1}\right )^{\frac {9}{2}}}\right )} \]
1/4032*a*(21*(((a*x - 1)/(a*x + 1))^(3/2) - 18*sqrt((a*x - 1)/(a*x + 1)))/ (a^2*c^4) + (54*(a*x - 1)/(a*x + 1) - 189*(a*x - 1)^2/(a*x + 1)^2 + 420*(a *x - 1)^3/(a*x + 1)^3 - 945*(a*x - 1)^4/(a*x + 1)^4 - 7)/(a^2*c^4*((a*x - 1)/(a*x + 1))^(9/2)))
\[ \int \frac {e^{3 \coth ^{-1}(a x)}}{\left (c-a^2 c x^2\right )^4} \, dx=\int { \frac {1}{{\left (a^{2} c x^{2} - c\right )}^{4} \left (\frac {a x - 1}{a x + 1}\right )^{\frac {3}{2}}} \,d x } \]
Time = 3.98 (sec) , antiderivative size = 76, normalized size of antiderivative = 0.60 \[ \int \frac {e^{3 \coth ^{-1}(a x)}}{\left (c-a^2 c x^2\right )^4} \, dx=-\frac {16\,a^6\,x^6-48\,a^5\,x^5+24\,a^4\,x^4+56\,a^3\,x^3-66\,a^2\,x^2+6\,a\,x+19}{63\,a\,c^4\,{\left (a\,x+1\right )}^6\,{\left (\frac {a\,x-1}{a\,x+1}\right )}^{9/2}} \]