3.1.16 \(\int \text {sech}^{-1}(a+b x)^3 \, dx\) [16]

3.1.16.1 Optimal result
3.1.16.2 Mathematica [A] (verified)
3.1.16.3 Rubi [A] (verified)
3.1.16.4 Maple [F]
3.1.16.5 Fricas [F]
3.1.16.6 Sympy [F]
3.1.16.7 Maxima [F]
3.1.16.8 Giac [F]
3.1.16.9 Mupad [F(-1)]

3.1.16.1 Optimal result

Integrand size = 8, antiderivative size = 136 \[ \int \text {sech}^{-1}(a+b x)^3 \, dx=\frac {(a+b x) \text {sech}^{-1}(a+b x)^3}{b}-\frac {6 \text {sech}^{-1}(a+b x)^2 \arctan \left (e^{\text {sech}^{-1}(a+b x)}\right )}{b}+\frac {6 i \text {sech}^{-1}(a+b x) \operatorname {PolyLog}\left (2,-i e^{\text {sech}^{-1}(a+b x)}\right )}{b}-\frac {6 i \text {sech}^{-1}(a+b x) \operatorname {PolyLog}\left (2,i e^{\text {sech}^{-1}(a+b x)}\right )}{b}-\frac {6 i \operatorname {PolyLog}\left (3,-i e^{\text {sech}^{-1}(a+b x)}\right )}{b}+\frac {6 i \operatorname {PolyLog}\left (3,i e^{\text {sech}^{-1}(a+b x)}\right )}{b} \]

output
(b*x+a)*arcsech(b*x+a)^3/b-6*arcsech(b*x+a)^2*arctan(1/(b*x+a)+(1/(b*x+a)- 
1)^(1/2)*(1/(b*x+a)+1)^(1/2))/b+6*I*arcsech(b*x+a)*polylog(2,-I*(1/(b*x+a) 
+(1/(b*x+a)-1)^(1/2)*(1/(b*x+a)+1)^(1/2)))/b-6*I*arcsech(b*x+a)*polylog(2, 
I*(1/(b*x+a)+(1/(b*x+a)-1)^(1/2)*(1/(b*x+a)+1)^(1/2)))/b-6*I*polylog(3,-I* 
(1/(b*x+a)+(1/(b*x+a)-1)^(1/2)*(1/(b*x+a)+1)^(1/2)))/b+6*I*polylog(3,I*(1/ 
(b*x+a)+(1/(b*x+a)-1)^(1/2)*(1/(b*x+a)+1)^(1/2)))/b
 
3.1.16.2 Mathematica [A] (verified)

Time = 0.14 (sec) , antiderivative size = 153, normalized size of antiderivative = 1.12 \[ \int \text {sech}^{-1}(a+b x)^3 \, dx=\frac {(a+b x) \text {sech}^{-1}(a+b x)^3}{b}-\frac {3 i \left (-\text {sech}^{-1}(a+b x)^2 \left (\log \left (1-i e^{-\text {sech}^{-1}(a+b x)}\right )-\log \left (1+i e^{-\text {sech}^{-1}(a+b x)}\right )\right )-2 \text {sech}^{-1}(a+b x) \left (\operatorname {PolyLog}\left (2,-i e^{-\text {sech}^{-1}(a+b x)}\right )-\operatorname {PolyLog}\left (2,i e^{-\text {sech}^{-1}(a+b x)}\right )\right )-2 \left (\operatorname {PolyLog}\left (3,-i e^{-\text {sech}^{-1}(a+b x)}\right )-\operatorname {PolyLog}\left (3,i e^{-\text {sech}^{-1}(a+b x)}\right )\right )\right )}{b} \]

input
Integrate[ArcSech[a + b*x]^3,x]
 
output
((a + b*x)*ArcSech[a + b*x]^3)/b - ((3*I)*(-(ArcSech[a + b*x]^2*(Log[1 - I 
/E^ArcSech[a + b*x]] - Log[1 + I/E^ArcSech[a + b*x]])) - 2*ArcSech[a + b*x 
]*(PolyLog[2, (-I)/E^ArcSech[a + b*x]] - PolyLog[2, I/E^ArcSech[a + b*x]]) 
 - 2*(PolyLog[3, (-I)/E^ArcSech[a + b*x]] - PolyLog[3, I/E^ArcSech[a + b*x 
]])))/b
 
3.1.16.3 Rubi [A] (verified)

Time = 0.57 (sec) , antiderivative size = 125, normalized size of antiderivative = 0.92, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.000, Rules used = {6869, 6833, 5941, 3042, 4668, 3011, 2720, 7143}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \text {sech}^{-1}(a+b x)^3 \, dx\)

\(\Big \downarrow \) 6869

\(\displaystyle \frac {\int \text {sech}^{-1}(a+b x)^3d(a+b x)}{b}\)

\(\Big \downarrow \) 6833

\(\displaystyle -\frac {\int (a+b x) \sqrt {\frac {-a-b x+1}{a+b x+1}} (a+b x+1) \text {sech}^{-1}(a+b x)^3d\text {sech}^{-1}(a+b x)}{b}\)

\(\Big \downarrow \) 5941

\(\displaystyle -\frac {3 \int (a+b x) \text {sech}^{-1}(a+b x)^2d\text {sech}^{-1}(a+b x)-(a+b x) \text {sech}^{-1}(a+b x)^3}{b}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {-(a+b x) \text {sech}^{-1}(a+b x)^3+3 \int \text {sech}^{-1}(a+b x)^2 \csc \left (i \text {sech}^{-1}(a+b x)+\frac {\pi }{2}\right )d\text {sech}^{-1}(a+b x)}{b}\)

\(\Big \downarrow \) 4668

\(\displaystyle -\frac {-(a+b x) \text {sech}^{-1}(a+b x)^3+3 \left (-2 i \int \text {sech}^{-1}(a+b x) \log \left (1-i e^{\text {sech}^{-1}(a+b x)}\right )d\text {sech}^{-1}(a+b x)+2 i \int \text {sech}^{-1}(a+b x) \log \left (1+i e^{\text {sech}^{-1}(a+b x)}\right )d\text {sech}^{-1}(a+b x)+2 \text {sech}^{-1}(a+b x)^2 \arctan \left (e^{\text {sech}^{-1}(a+b x)}\right )\right )}{b}\)

\(\Big \downarrow \) 3011

\(\displaystyle -\frac {-(a+b x) \text {sech}^{-1}(a+b x)^3+3 \left (2 i \left (\int \operatorname {PolyLog}\left (2,-i e^{\text {sech}^{-1}(a+b x)}\right )d\text {sech}^{-1}(a+b x)-\text {sech}^{-1}(a+b x) \operatorname {PolyLog}\left (2,-i e^{\text {sech}^{-1}(a+b x)}\right )\right )-2 i \left (\int \operatorname {PolyLog}\left (2,i e^{\text {sech}^{-1}(a+b x)}\right )d\text {sech}^{-1}(a+b x)-\text {sech}^{-1}(a+b x) \operatorname {PolyLog}\left (2,i e^{\text {sech}^{-1}(a+b x)}\right )\right )+2 \text {sech}^{-1}(a+b x)^2 \arctan \left (e^{\text {sech}^{-1}(a+b x)}\right )\right )}{b}\)

\(\Big \downarrow \) 2720

\(\displaystyle -\frac {-(a+b x) \text {sech}^{-1}(a+b x)^3+3 \left (2 i \left (\int e^{-\text {sech}^{-1}(a+b x)} \operatorname {PolyLog}\left (2,-i e^{\text {sech}^{-1}(a+b x)}\right )de^{\text {sech}^{-1}(a+b x)}-\text {sech}^{-1}(a+b x) \operatorname {PolyLog}\left (2,-i e^{\text {sech}^{-1}(a+b x)}\right )\right )-2 i \left (\int e^{-\text {sech}^{-1}(a+b x)} \operatorname {PolyLog}\left (2,i e^{\text {sech}^{-1}(a+b x)}\right )de^{\text {sech}^{-1}(a+b x)}-\text {sech}^{-1}(a+b x) \operatorname {PolyLog}\left (2,i e^{\text {sech}^{-1}(a+b x)}\right )\right )+2 \text {sech}^{-1}(a+b x)^2 \arctan \left (e^{\text {sech}^{-1}(a+b x)}\right )\right )}{b}\)

\(\Big \downarrow \) 7143

\(\displaystyle -\frac {-(a+b x) \text {sech}^{-1}(a+b x)^3+3 \left (2 \text {sech}^{-1}(a+b x)^2 \arctan \left (e^{\text {sech}^{-1}(a+b x)}\right )+2 i \left (\operatorname {PolyLog}\left (3,-i e^{\text {sech}^{-1}(a+b x)}\right )-\text {sech}^{-1}(a+b x) \operatorname {PolyLog}\left (2,-i e^{\text {sech}^{-1}(a+b x)}\right )\right )-2 i \left (\operatorname {PolyLog}\left (3,i e^{\text {sech}^{-1}(a+b x)}\right )-\text {sech}^{-1}(a+b x) \operatorname {PolyLog}\left (2,i e^{\text {sech}^{-1}(a+b x)}\right )\right )\right )}{b}\)

input
Int[ArcSech[a + b*x]^3,x]
 
output
-((-((a + b*x)*ArcSech[a + b*x]^3) + 3*(2*ArcSech[a + b*x]^2*ArcTan[E^ArcS 
ech[a + b*x]] + (2*I)*(-(ArcSech[a + b*x]*PolyLog[2, (-I)*E^ArcSech[a + b* 
x]]) + PolyLog[3, (-I)*E^ArcSech[a + b*x]]) - (2*I)*(-(ArcSech[a + b*x]*Po 
lyLog[2, I*E^ArcSech[a + b*x]]) + PolyLog[3, I*E^ArcSech[a + b*x]])))/b)
 

3.1.16.3.1 Defintions of rubi rules used

rule 2720
Int[u_, x_Symbol] :> With[{v = FunctionOfExponential[u, x]}, Simp[v/D[v, x] 
   Subst[Int[FunctionOfExponentialFunction[u, x]/x, x], x, v], x]] /; Funct 
ionOfExponentialQ[u, x] &&  !MatchQ[u, (w_)*((a_.)*(v_)^(n_))^(m_) /; FreeQ 
[{a, m, n}, x] && IntegerQ[m*n]] &&  !MatchQ[u, E^((c_.)*((a_.) + (b_.)*x)) 
*(F_)[v_] /; FreeQ[{a, b, c}, x] && InverseFunctionQ[F[x]]]
 

rule 3011
Int[Log[1 + (e_.)*((F_)^((c_.)*((a_.) + (b_.)*(x_))))^(n_.)]*((f_.) + (g_.) 
*(x_))^(m_.), x_Symbol] :> Simp[(-(f + g*x)^m)*(PolyLog[2, (-e)*(F^(c*(a + 
b*x)))^n]/(b*c*n*Log[F])), x] + Simp[g*(m/(b*c*n*Log[F]))   Int[(f + g*x)^( 
m - 1)*PolyLog[2, (-e)*(F^(c*(a + b*x)))^n], x], x] /; FreeQ[{F, a, b, c, e 
, f, g, n}, x] && GtQ[m, 0]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 4668
Int[csc[(e_.) + Pi*(k_.) + (Complex[0, fz_])*(f_.)*(x_)]*((c_.) + (d_.)*(x_ 
))^(m_.), x_Symbol] :> Simp[-2*(c + d*x)^m*(ArcTanh[E^((-I)*e + f*fz*x)/E^( 
I*k*Pi)]/(f*fz*I)), x] + (-Simp[d*(m/(f*fz*I))   Int[(c + d*x)^(m - 1)*Log[ 
1 - E^((-I)*e + f*fz*x)/E^(I*k*Pi)], x], x] + Simp[d*(m/(f*fz*I))   Int[(c 
+ d*x)^(m - 1)*Log[1 + E^((-I)*e + f*fz*x)/E^(I*k*Pi)], x], x]) /; FreeQ[{c 
, d, e, f, fz}, x] && IntegerQ[2*k] && IGtQ[m, 0]
 

rule 5941
Int[(x_)^(m_.)*Sech[(a_.) + (b_.)*(x_)^(n_.)]^(p_.)*Tanh[(a_.) + (b_.)*(x_) 
^(n_.)]^(q_.), x_Symbol] :> Simp[(-x^(m - n + 1))*(Sech[a + b*x^n]^p/(b*n*p 
)), x] + Simp[(m - n + 1)/(b*n*p)   Int[x^(m - n)*Sech[a + b*x^n]^p, x], x] 
 /; FreeQ[{a, b, p}, x] && RationalQ[m] && IntegerQ[n] && GeQ[m - n, 0] && 
EqQ[q, 1]
 

rule 6833
Int[((a_.) + ArcSech[(c_.)*(x_)]*(b_.))^(n_), x_Symbol] :> Simp[-c^(-1)   S 
ubst[Int[(a + b*x)^n*Sech[x]*Tanh[x], x], x, ArcSech[c*x]], x] /; FreeQ[{a, 
 b, c, n}, x] && IGtQ[n, 0]
 

rule 6869
Int[((a_.) + ArcSech[(c_) + (d_.)*(x_)]*(b_.))^(p_.), x_Symbol] :> Simp[1/d 
   Subst[Int[(a + b*ArcSech[x])^p, x], x, c + d*x], x] /; FreeQ[{a, b, c, d 
}, x] && IGtQ[p, 0]
 

rule 7143
Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_S 
ymbol] :> Simp[PolyLog[n + 1, c*(a + b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d 
, e, n, p}, x] && EqQ[b*d, a*e]
 
3.1.16.4 Maple [F]

\[\int \operatorname {arcsech}\left (b x +a \right )^{3}d x\]

input
int(arcsech(b*x+a)^3,x)
 
output
int(arcsech(b*x+a)^3,x)
 
3.1.16.5 Fricas [F]

\[ \int \text {sech}^{-1}(a+b x)^3 \, dx=\int { \operatorname {arsech}\left (b x + a\right )^{3} \,d x } \]

input
integrate(arcsech(b*x+a)^3,x, algorithm="fricas")
 
output
integral(arcsech(b*x + a)^3, x)
 
3.1.16.6 Sympy [F]

\[ \int \text {sech}^{-1}(a+b x)^3 \, dx=\int \operatorname {asech}^{3}{\left (a + b x \right )}\, dx \]

input
integrate(asech(b*x+a)**3,x)
 
output
Integral(asech(a + b*x)**3, x)
 
3.1.16.7 Maxima [F]

\[ \int \text {sech}^{-1}(a+b x)^3 \, dx=\int { \operatorname {arsech}\left (b x + a\right )^{3} \,d x } \]

input
integrate(arcsech(b*x+a)^3,x, algorithm="maxima")
 
output
x*log(sqrt(b*x + a + 1)*sqrt(-b*x - a + 1)*b*x + sqrt(b*x + a + 1)*sqrt(-b 
*x - a + 1)*a + b*x + a)^3 - integrate((8*(b^3*x^3 + 3*a*b^2*x^2 + a^3 + ( 
3*a^2*b - b)*x - a)*sqrt(b*x + a + 1)*sqrt(-b*x - a + 1)*log(b*x + a)^3 + 
8*(b^3*x^3 + 3*a*b^2*x^2 + a^3 + (3*a^2*b - b)*x - a)*log(b*x + a)^3 + 3*( 
b^3*x^3 + 2*a*b^2*x^2 + (a^2*b - b)*x + 2*(b^3*x^3 + 3*a*b^2*x^2 + a^3 + ( 
3*a^2*b - b)*x - a)*log(b*x + a) + ((b^3*x^3 + 3*a*b^2*x^2 + a^3 + (3*a^2* 
b - b)*x - a)*sqrt(b*x + a + 1)*log(b*x + a) + (2*b^3*x^3 + 4*a*b^2*x^2 + 
(2*a^2*b - b)*x + (b^3*x^3 + 3*a*b^2*x^2 + a^3 + (3*a^2*b - b)*x - a)*log( 
b*x + a))*sqrt(b*x + a + 1))*sqrt(-b*x - a + 1))*log(sqrt(b*x + a + 1)*sqr 
t(-b*x - a + 1)*b*x + sqrt(b*x + a + 1)*sqrt(-b*x - a + 1)*a + b*x + a)^2 
- 12*((b^3*x^3 + 3*a*b^2*x^2 + a^3 + (3*a^2*b - b)*x - a)*sqrt(b*x + a + 1 
)*sqrt(-b*x - a + 1)*log(b*x + a)^2 + (b^3*x^3 + 3*a*b^2*x^2 + a^3 + (3*a^ 
2*b - b)*x - a)*log(b*x + a)^2)*log(sqrt(b*x + a + 1)*sqrt(-b*x - a + 1)*b 
*x + sqrt(b*x + a + 1)*sqrt(-b*x - a + 1)*a + b*x + a))/(b^3*x^3 + 3*a*b^2 
*x^2 + a^3 + (b^3*x^3 + 3*a*b^2*x^2 + a^3 + (3*a^2*b - b)*x - a)*sqrt(b*x 
+ a + 1)*sqrt(-b*x - a + 1) + (3*a^2*b - b)*x - a), x)
 
3.1.16.8 Giac [F]

\[ \int \text {sech}^{-1}(a+b x)^3 \, dx=\int { \operatorname {arsech}\left (b x + a\right )^{3} \,d x } \]

input
integrate(arcsech(b*x+a)^3,x, algorithm="giac")
 
output
integrate(arcsech(b*x + a)^3, x)
 
3.1.16.9 Mupad [F(-1)]

Timed out. \[ \int \text {sech}^{-1}(a+b x)^3 \, dx=\int {\mathrm {acosh}\left (\frac {1}{a+b\,x}\right )}^3 \,d x \]

input
int(acosh(1/(a + b*x))^3,x)
 
output
int(acosh(1/(a + b*x))^3, x)