Integrand size = 15, antiderivative size = 94 \[ \int x \text {erf}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\frac {1}{2} x^2 \text {erf}\left (d \left (a+b \log \left (c x^n\right )\right )\right )-\frac {1}{2} e^{\frac {1-2 a b d^2 n}{b^2 d^2 n^2}} x^2 \left (c x^n\right )^{-2/n} \text {erf}\left (\frac {a b d^2-\frac {1}{n}+b^2 d^2 \log \left (c x^n\right )}{b d}\right ) \]
1/2*x^2*erf(d*(a+b*ln(c*x^n)))-1/2*exp((-2*a*b*d^2*n+1)/b^2/d^2/n^2)*x^2*e rf((a*b*d^2-1/n+b^2*d^2*ln(c*x^n))/b/d)/((c*x^n)^(2/n))
Time = 0.19 (sec) , antiderivative size = 84, normalized size of antiderivative = 0.89 \[ \int x \text {erf}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\frac {1}{2} \left (x^2 \text {erf}\left (d \left (a+b \log \left (c x^n\right )\right )\right )-e^{-\frac {\frac {-\frac {1}{d^2}+2 a b n}{b^2}+2 n \log \left (c x^n\right )}{n^2}} x^2 \text {erf}\left (a d-\frac {1}{b d n}+b d \log \left (c x^n\right )\right )\right ) \]
(x^2*Erf[d*(a + b*Log[c*x^n])] - (x^2*Erf[a*d - 1/(b*d*n) + b*d*Log[c*x^n] ])/E^(((-d^(-2) + 2*a*b*n)/b^2 + 2*n*Log[c*x^n])/n^2))/2
Time = 0.49 (sec) , antiderivative size = 111, normalized size of antiderivative = 1.18, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {6955, 2712, 2706, 2664, 2634}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x \text {erf}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx\) |
\(\Big \downarrow \) 6955 |
\(\displaystyle \frac {1}{2} x^2 \text {erf}\left (d \left (a+b \log \left (c x^n\right )\right )\right )-\frac {b d n \int e^{-d^2 \left (a+b \log \left (c x^n\right )\right )^2} xdx}{\sqrt {\pi }}\) |
\(\Big \downarrow \) 2712 |
\(\displaystyle \frac {1}{2} x^2 \text {erf}\left (d \left (a+b \log \left (c x^n\right )\right )\right )-\frac {b d n x^{2 a b d^2 n} \left (c x^n\right )^{-2 a b d^2} \int e^{-a^2 d^2-b^2 \log ^2\left (c x^n\right ) d^2} x^{1-2 a b d^2 n}dx}{\sqrt {\pi }}\) |
\(\Big \downarrow \) 2706 |
\(\displaystyle \frac {1}{2} x^2 \text {erf}\left (d \left (a+b \log \left (c x^n\right )\right )\right )-\frac {b d x^2 \left (c x^n\right )^{2 \left (a b d^2-\frac {1}{n}\right )-2 a b d^2} \int \exp \left (-a^2 d^2-b^2 \log ^2\left (c x^n\right ) d^2+\frac {2 \left (1-a b d^2 n\right ) \log \left (c x^n\right )}{n}\right )d\log \left (c x^n\right )}{\sqrt {\pi }}\) |
\(\Big \downarrow \) 2664 |
\(\displaystyle \frac {1}{2} x^2 \text {erf}\left (d \left (a+b \log \left (c x^n\right )\right )\right )-\frac {b d x^2 e^{\frac {1-2 a b d^2 n}{b^2 d^2 n^2}} \left (c x^n\right )^{2 \left (a b d^2-\frac {1}{n}\right )-2 a b d^2} \int \exp \left (-\frac {\left (a b d^2+b^2 \log \left (c x^n\right ) d^2-\frac {1}{n}\right )^2}{b^2 d^2}\right )d\log \left (c x^n\right )}{\sqrt {\pi }}\) |
\(\Big \downarrow \) 2634 |
\(\displaystyle \frac {1}{2} x^2 \text {erf}\left (d \left (a+b \log \left (c x^n\right )\right )\right )-\frac {1}{2} x^2 e^{\frac {1-2 a b d^2 n}{b^2 d^2 n^2}} \left (c x^n\right )^{2 \left (a b d^2-\frac {1}{n}\right )-2 a b d^2} \text {erf}\left (\frac {a b d^2+b^2 d^2 \log \left (c x^n\right )-\frac {1}{n}}{b d}\right )\) |
(x^2*Erf[d*(a + b*Log[c*x^n])])/2 - (E^((1 - 2*a*b*d^2*n)/(b^2*d^2*n^2))*x ^2*(c*x^n)^(-2*a*b*d^2 + 2*(a*b*d^2 - n^(-1)))*Erf[(a*b*d^2 - n^(-1) + b^2 *d^2*Log[c*x^n])/(b*d)])/2
3.1.41.3.1 Defintions of rubi rules used
Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[F^a*Sqrt [Pi]*(Erf[(c + d*x)*Rt[(-b)*Log[F], 2]]/(2*d*Rt[(-b)*Log[F], 2])), x] /; Fr eeQ[{F, a, b, c, d}, x] && NegQ[b]
Int[(F_)^((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[F^(a - b^2/ (4*c)) Int[F^((b + 2*c*x)^2/(4*c)), x], x] /; FreeQ[{F, a, b, c}, x]
Int[(F_)^(((a_.) + Log[(c_.)*((d_.) + (e_.)*(x_))^(n_.)]^2*(b_.))*(f_.))*(( g_.) + (h_.)*(x_))^(m_.), x_Symbol] :> Simp[(g + h*x)^(m + 1)/(h*n*(c*(d + e*x)^n)^((m + 1)/n)) Subst[Int[E^(a*f*Log[F] + ((m + 1)*x)/n + b*f*Log[F] *x^2), x], x, Log[c*(d + e*x)^n]], x] /; FreeQ[{F, a, b, c, d, e, f, g, h, m, n}, x] && EqQ[e*g - d*h, 0]
Int[(F_)^(((a_.) + Log[(c_.)*((d_.) + (e_.)*(x_))^(n_.)]*(b_.))^2*(f_.))*(( g_.) + (h_.)*(x_))^(m_.), x_Symbol] :> Simp[(g + h*x)^m*((c*(d + e*x)^n)^(2 *a*b*f*Log[F])/(d + e*x)^(m + 2*a*b*f*n*Log[F]))*Int[(d + e*x)^(m + 2*a*b*f *n*Log[F])*F^(a^2*f + b^2*f*Log[c*(d + e*x)^n]^2), x], x] /; FreeQ[{F, a, b , c, d, e, f, g, h, m, n}, x] && EqQ[e*g - d*h, 0]
Int[Erf[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*(d_.)]*((e_.)*(x_))^(m_.), x_ Symbol] :> Simp[(e*x)^(m + 1)*(Erf[d*(a + b*Log[c*x^n])]/(e*(m + 1))), x] - Simp[2*b*d*(n/(Sqrt[Pi]*(m + 1))) Int[(e*x)^m/E^(d*(a + b*Log[c*x^n]))^2 , x], x] /; FreeQ[{a, b, c, d, e, m, n}, x] && NeQ[m, -1]
\[\int x \,\operatorname {erf}\left (d \left (a +b \ln \left (c \,x^{n}\right )\right )\right )d x\]
Time = 0.26 (sec) , antiderivative size = 121, normalized size of antiderivative = 1.29 \[ \int x \text {erf}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\frac {1}{2} \, x^{2} \operatorname {erf}\left (b d \log \left (c x^{n}\right ) + a d\right ) - \frac {1}{2} \, \sqrt {b^{2} d^{2} n^{2}} \operatorname {erf}\left (\frac {{\left (b^{2} d^{2} n^{2} \log \left (x\right ) + b^{2} d^{2} n \log \left (c\right ) + a b d^{2} n - 1\right )} \sqrt {b^{2} d^{2} n^{2}}}{b^{2} d^{2} n^{2}}\right ) e^{\left (-\frac {2 \, b^{2} d^{2} n \log \left (c\right ) + 2 \, a b d^{2} n - 1}{b^{2} d^{2} n^{2}}\right )} \]
1/2*x^2*erf(b*d*log(c*x^n) + a*d) - 1/2*sqrt(b^2*d^2*n^2)*erf((b^2*d^2*n^2 *log(x) + b^2*d^2*n*log(c) + a*b*d^2*n - 1)*sqrt(b^2*d^2*n^2)/(b^2*d^2*n^2 ))*e^(-(2*b^2*d^2*n*log(c) + 2*a*b*d^2*n - 1)/(b^2*d^2*n^2))
\[ \int x \text {erf}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\int x \operatorname {erf}{\left (a d + b d \log {\left (c x^{n} \right )} \right )}\, dx \]
\[ \int x \text {erf}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\int { x \operatorname {erf}\left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right ) \,d x } \]
1/2*x^2*erf(b*d*log(x^n) + (b*log(c) + a)*d) - b*d*n*integrate(x*e^(-b^2*d ^2*log(c)^2 - 2*b^2*d^2*log(c)*log(x^n) - b^2*d^2*log(x^n)^2 - 2*a*b*d^2*l og(x^n) - a^2*d^2), x)/(sqrt(pi)*c^(2*a*b*d^2))
Time = 0.46 (sec) , antiderivative size = 83, normalized size of antiderivative = 0.88 \[ \int x \text {erf}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\frac {1}{2} \, x^{2} \operatorname {erf}\left (b d n \log \left (x\right ) + b d \log \left (c\right ) + a d\right ) + \frac {\operatorname {erf}\left (-b d n \log \left (x\right ) - b d \log \left (c\right ) - a d + \frac {1}{b d n}\right ) e^{\left (-\frac {2 \, a}{b n} + \frac {1}{b^{2} d^{2} n^{2}}\right )}}{2 \, c^{\frac {2}{n}}} \]
1/2*x^2*erf(b*d*n*log(x) + b*d*log(c) + a*d) + 1/2*erf(-b*d*n*log(x) - b*d *log(c) - a*d + 1/(b*d*n))*e^(-2*a/(b*n) + 1/(b^2*d^2*n^2))/c^(2/n)
Timed out. \[ \int x \text {erf}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx=\int x\,\mathrm {erf}\left (d\,\left (a+b\,\ln \left (c\,x^n\right )\right )\right ) \,d x \]