3.2.83 \(\int x^5 \cos (\frac {1}{2} b^2 \pi x^2) \operatorname {FresnelC}(b x) \, dx\) [183]

3.2.83.1 Optimal result

Integrand size = 20, antiderivative size = 157 \[ \int x^5 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x) \, dx=-\frac {2 x^3}{3 b^3 \pi ^2}+\frac {x^3 \cos \left (b^2 \pi x^2\right )}{4 b^3 \pi ^2}+\frac {4 x^2 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x)}{b^4 \pi ^2}+\frac {43 \operatorname {FresnelS}\left (\sqrt {2} b x\right )}{8 \sqrt {2} b^6 \pi ^3}-\frac {8 \operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{b^6 \pi ^3}+\frac {x^4 \operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{b^2 \pi }-\frac {11 x \sin \left (b^2 \pi x^2\right )}{8 b^5 \pi ^3} \]

output

-2/3*x^3/b^3/Pi^2+1/4*x^3*cos(b^2*Pi*x^2)/b^3/Pi^2+4*x^2*cos(1/2*b^2*Pi*x^ 
2)*FresnelC(b*x)/b^4/Pi^2-8*FresnelC(b*x)*sin(1/2*b^2*Pi*x^2)/b^6/Pi^3+x^4 
*FresnelC(b*x)*sin(1/2*b^2*Pi*x^2)/b^2/Pi-11/8*x*sin(b^2*Pi*x^2)/b^5/Pi^3+ 
43/16*FresnelS(b*x*2^(1/2))/b^6/Pi^3*2^(1/2)
 

3.2.83.2 Mathematica [A] (verified)

Time = 0.10 (sec) , antiderivative size = 120, normalized size of antiderivative = 0.76 \[ \int x^5 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x) \, dx=\frac {-32 b^3 \pi x^3+12 b^3 \pi x^3 \cos \left (b^2 \pi x^2\right )+129 \sqrt {2} \operatorname {FresnelS}\left (\sqrt {2} b x\right )+48 \operatorname {FresnelC}(b x) \left (4 b^2 \pi x^2 \cos \left (\frac {1}{2} b^2 \pi x^2\right )+\left (-8+b^4 \pi ^2 x^4\right ) \sin \left (\frac {1}{2} b^2 \pi x^2\right )\right )-66 b x \sin \left (b^2 \pi x^2\right )}{48 b^6 \pi ^3} \]

input

Integrate[x^5*Cos[(b^2*Pi*x^2)/2]*FresnelC[b*x],x]
 

output

(-32*b^3*Pi*x^3 + 12*b^3*Pi*x^3*Cos[b^2*Pi*x^2] + 129*Sqrt[2]*FresnelS[Sqr 
t[2]*b*x] + 48*FresnelC[b*x]*(4*b^2*Pi*x^2*Cos[(b^2*Pi*x^2)/2] + (-8 + b^4 
*Pi^2*x^4)*Sin[(b^2*Pi*x^2)/2]) - 66*b*x*Sin[b^2*Pi*x^2])/(48*b^6*Pi^3)
 

3.2.83.3 Rubi [A] (verified)

Time = 1.06 (sec) , antiderivative size = 271, normalized size of antiderivative = 1.73, number of steps used = 11, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.550, Rules used = {7009, 3866, 3867, 3832, 7017, 3873, 15, 3867, 3832, 7007, 3832}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int x^5 \operatorname {FresnelC}(b x) \cos \left (\frac {1}{2} \pi b^2 x^2\right ) \, dx\)

\(\Big \downarrow \) 7009

\(\displaystyle -\frac {4 \int x^3 \operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )dx}{\pi b^2}-\frac {\int x^4 \sin \left (b^2 \pi x^2\right )dx}{2 \pi b}+\frac {x^4 \operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}\)

\(\Big \downarrow \) 3866

\(\displaystyle -\frac {4 \int x^3 \operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )dx}{\pi b^2}-\frac {\frac {3 \int x^2 \cos \left (b^2 \pi x^2\right )dx}{2 \pi b^2}-\frac {x^3 \cos \left (\pi b^2 x^2\right )}{2 \pi b^2}}{2 \pi b}+\frac {x^4 \operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}\)

\(\Big \downarrow \) 3867

\(\displaystyle -\frac {4 \int x^3 \operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )dx}{\pi b^2}-\frac {\frac {3 \left (\frac {x \sin \left (\pi b^2 x^2\right )}{2 \pi b^2}-\frac {\int \sin \left (b^2 \pi x^2\right )dx}{2 \pi b^2}\right )}{2 \pi b^2}-\frac {x^3 \cos \left (\pi b^2 x^2\right )}{2 \pi b^2}}{2 \pi b}+\frac {x^4 \operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}\)

\(\Big \downarrow \) 3832

\(\displaystyle -\frac {4 \int x^3 \operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )dx}{\pi b^2}+\frac {x^4 \operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}-\frac {\frac {3 \left (\frac {x \sin \left (\pi b^2 x^2\right )}{2 \pi b^2}-\frac {\operatorname {FresnelS}\left (\sqrt {2} b x\right )}{2 \sqrt {2} \pi b^3}\right )}{2 \pi b^2}-\frac {x^3 \cos \left (\pi b^2 x^2\right )}{2 \pi b^2}}{2 \pi b}\)

\(\Big \downarrow \) 7017

\(\displaystyle -\frac {4 \left (\frac {2 \int x \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x)dx}{\pi b^2}+\frac {\int x^2 \cos ^2\left (\frac {1}{2} b^2 \pi x^2\right )dx}{\pi b}-\frac {x^2 \operatorname {FresnelC}(b x) \cos \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}\right )}{\pi b^2}+\frac {x^4 \operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}-\frac {\frac {3 \left (\frac {x \sin \left (\pi b^2 x^2\right )}{2 \pi b^2}-\frac {\operatorname {FresnelS}\left (\sqrt {2} b x\right )}{2 \sqrt {2} \pi b^3}\right )}{2 \pi b^2}-\frac {x^3 \cos \left (\pi b^2 x^2\right )}{2 \pi b^2}}{2 \pi b}\)

\(\Big \downarrow \) 3873

\(\displaystyle -\frac {4 \left (\frac {2 \int x \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x)dx}{\pi b^2}+\frac {\frac {1}{2} \int x^2 \cos \left (b^2 \pi x^2\right )dx+\frac {\int x^2dx}{2}}{\pi b}-\frac {x^2 \operatorname {FresnelC}(b x) \cos \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}\right )}{\pi b^2}+\frac {x^4 \operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}-\frac {\frac {3 \left (\frac {x \sin \left (\pi b^2 x^2\right )}{2 \pi b^2}-\frac {\operatorname {FresnelS}\left (\sqrt {2} b x\right )}{2 \sqrt {2} \pi b^3}\right )}{2 \pi b^2}-\frac {x^3 \cos \left (\pi b^2 x^2\right )}{2 \pi b^2}}{2 \pi b}\)

\(\Big \downarrow \) 15

\(\displaystyle -\frac {4 \left (\frac {2 \int x \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x)dx}{\pi b^2}+\frac {\frac {1}{2} \int x^2 \cos \left (b^2 \pi x^2\right )dx+\frac {x^3}{6}}{\pi b}-\frac {x^2 \operatorname {FresnelC}(b x) \cos \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}\right )}{\pi b^2}+\frac {x^4 \operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}-\frac {\frac {3 \left (\frac {x \sin \left (\pi b^2 x^2\right )}{2 \pi b^2}-\frac {\operatorname {FresnelS}\left (\sqrt {2} b x\right )}{2 \sqrt {2} \pi b^3}\right )}{2 \pi b^2}-\frac {x^3 \cos \left (\pi b^2 x^2\right )}{2 \pi b^2}}{2 \pi b}\)

\(\Big \downarrow \) 3867

\(\displaystyle -\frac {4 \left (\frac {2 \int x \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x)dx}{\pi b^2}+\frac {\frac {1}{2} \left (\frac {x \sin \left (\pi b^2 x^2\right )}{2 \pi b^2}-\frac {\int \sin \left (b^2 \pi x^2\right )dx}{2 \pi b^2}\right )+\frac {x^3}{6}}{\pi b}-\frac {x^2 \operatorname {FresnelC}(b x) \cos \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}\right )}{\pi b^2}+\frac {x^4 \operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}-\frac {\frac {3 \left (\frac {x \sin \left (\pi b^2 x^2\right )}{2 \pi b^2}-\frac {\operatorname {FresnelS}\left (\sqrt {2} b x\right )}{2 \sqrt {2} \pi b^3}\right )}{2 \pi b^2}-\frac {x^3 \cos \left (\pi b^2 x^2\right )}{2 \pi b^2}}{2 \pi b}\)

\(\Big \downarrow \) 3832

\(\displaystyle -\frac {4 \left (\frac {2 \int x \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x)dx}{\pi b^2}-\frac {x^2 \operatorname {FresnelC}(b x) \cos \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}+\frac {\frac {1}{2} \left (\frac {x \sin \left (\pi b^2 x^2\right )}{2 \pi b^2}-\frac {\operatorname {FresnelS}\left (\sqrt {2} b x\right )}{2 \sqrt {2} \pi b^3}\right )+\frac {x^3}{6}}{\pi b}\right )}{\pi b^2}+\frac {x^4 \operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}-\frac {\frac {3 \left (\frac {x \sin \left (\pi b^2 x^2\right )}{2 \pi b^2}-\frac {\operatorname {FresnelS}\left (\sqrt {2} b x\right )}{2 \sqrt {2} \pi b^3}\right )}{2 \pi b^2}-\frac {x^3 \cos \left (\pi b^2 x^2\right )}{2 \pi b^2}}{2 \pi b}\)

\(\Big \downarrow \) 7007

\(\displaystyle -\frac {4 \left (\frac {2 \left (\frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}-\frac {\int \sin \left (b^2 \pi x^2\right )dx}{2 \pi b}\right )}{\pi b^2}-\frac {x^2 \operatorname {FresnelC}(b x) \cos \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}+\frac {\frac {1}{2} \left (\frac {x \sin \left (\pi b^2 x^2\right )}{2 \pi b^2}-\frac {\operatorname {FresnelS}\left (\sqrt {2} b x\right )}{2 \sqrt {2} \pi b^3}\right )+\frac {x^3}{6}}{\pi b}\right )}{\pi b^2}+\frac {x^4 \operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}-\frac {\frac {3 \left (\frac {x \sin \left (\pi b^2 x^2\right )}{2 \pi b^2}-\frac {\operatorname {FresnelS}\left (\sqrt {2} b x\right )}{2 \sqrt {2} \pi b^3}\right )}{2 \pi b^2}-\frac {x^3 \cos \left (\pi b^2 x^2\right )}{2 \pi b^2}}{2 \pi b}\)

\(\Big \downarrow \) 3832

\(\displaystyle \frac {x^4 \operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}-\frac {4 \left (\frac {2 \left (\frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}-\frac {\operatorname {FresnelS}\left (\sqrt {2} b x\right )}{2 \sqrt {2} \pi b^2}\right )}{\pi b^2}-\frac {x^2 \operatorname {FresnelC}(b x) \cos \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}+\frac {\frac {1}{2} \left (\frac {x \sin \left (\pi b^2 x^2\right )}{2 \pi b^2}-\frac {\operatorname {FresnelS}\left (\sqrt {2} b x\right )}{2 \sqrt {2} \pi b^3}\right )+\frac {x^3}{6}}{\pi b}\right )}{\pi b^2}-\frac {\frac {3 \left (\frac {x \sin \left (\pi b^2 x^2\right )}{2 \pi b^2}-\frac {\operatorname {FresnelS}\left (\sqrt {2} b x\right )}{2 \sqrt {2} \pi b^3}\right )}{2 \pi b^2}-\frac {x^3 \cos \left (\pi b^2 x^2\right )}{2 \pi b^2}}{2 \pi b}\)

input

Int[x^5*Cos[(b^2*Pi*x^2)/2]*FresnelC[b*x],x]
 

output

(x^4*FresnelC[b*x]*Sin[(b^2*Pi*x^2)/2])/(b^2*Pi) - (-1/2*(x^3*Cos[b^2*Pi*x 
^2])/(b^2*Pi) + (3*(-1/2*FresnelS[Sqrt[2]*b*x]/(Sqrt[2]*b^3*Pi) + (x*Sin[b 
^2*Pi*x^2])/(2*b^2*Pi)))/(2*b^2*Pi))/(2*b*Pi) - (4*(-((x^2*Cos[(b^2*Pi*x^2 
)/2]*FresnelC[b*x])/(b^2*Pi)) + (2*(-1/2*FresnelS[Sqrt[2]*b*x]/(Sqrt[2]*b^ 
2*Pi) + (FresnelC[b*x]*Sin[(b^2*Pi*x^2)/2])/(b^2*Pi)))/(b^2*Pi) + (x^3/6 + 
 (-1/2*FresnelS[Sqrt[2]*b*x]/(Sqrt[2]*b^3*Pi) + (x*Sin[b^2*Pi*x^2])/(2*b^2 
*Pi))/2)/(b*Pi)))/(b^2*Pi)
 

3.2.83.3.1 Defintions of rubi rules used

rule 15

Int[(a_.)*(x_)^(m_.), x_Symbol] :> Simp[a*(x^(m + 1)/(m + 1)), x] /; FreeQ[ 
{a, m}, x] && NeQ[m, -1]
 

rule 3832

Int[Sin[(d_.)*((e_.) + (f_.)*(x_))^2], x_Symbol] :> Simp[(Sqrt[Pi/2]/(f*Rt[ 
d, 2]))*FresnelS[Sqrt[2/Pi]*Rt[d, 2]*(e + f*x)], x] /; FreeQ[{d, e, f}, x]
 

rule 3866

Int[((e_.)*(x_))^(m_.)*Sin[(c_.) + (d_.)*(x_)^(n_)], x_Symbol] :> Simp[(-e^ 
(n - 1))*(e*x)^(m - n + 1)*(Cos[c + d*x^n]/(d*n)), x] + Simp[e^n*((m - n + 
1)/(d*n))   Int[(e*x)^(m - n)*Cos[c + d*x^n], x], x] /; FreeQ[{c, d, e}, x] 
 && IGtQ[n, 0] && LtQ[n, m + 1]
 

rule 3867

Int[Cos[(c_.) + (d_.)*(x_)^(n_)]*((e_.)*(x_))^(m_.), x_Symbol] :> Simp[e^(n 
 - 1)*(e*x)^(m - n + 1)*(Sin[c + d*x^n]/(d*n)), x] - Simp[e^n*((m - n + 1)/ 
(d*n))   Int[(e*x)^(m - n)*Sin[c + d*x^n], x], x] /; FreeQ[{c, d, e}, x] && 
 IGtQ[n, 0] && LtQ[n, m + 1]
 

rule 3873

Int[Cos[(a_.) + ((b_.)*(x_)^(n_))/2]^2*(x_)^(m_.), x_Symbol] :> Simp[1/2 
Int[x^m, x], x] + Simp[1/2   Int[x^m*Cos[2*a + b*x^n], x], x] /; FreeQ[{a, 
b, m, n}, x]
 

rule 7007

Int[Cos[(d_.)*(x_)^2]*FresnelC[(b_.)*(x_)]*(x_), x_Symbol] :> Simp[Sin[d*x^ 
2]*(FresnelC[b*x]/(2*d)), x] - Simp[b/(4*d)   Int[Sin[2*d*x^2], x], x] /; F 
reeQ[{b, d}, x] && EqQ[d^2, (Pi^2/4)*b^4]
 

rule 7009

Int[Cos[(d_.)*(x_)^2]*FresnelC[(b_.)*(x_)]*(x_)^(m_), x_Symbol] :> Simp[x^( 
m - 1)*Sin[d*x^2]*(FresnelC[b*x]/(2*d)), x] + (-Simp[(m - 1)/(2*d)   Int[x^ 
(m - 2)*Sin[d*x^2]*FresnelC[b*x], x], x] - Simp[b/(4*d)   Int[x^(m - 1)*Sin 
[2*d*x^2], x], x]) /; FreeQ[{b, d}, x] && EqQ[d^2, (Pi^2/4)*b^4] && IGtQ[m, 
 1]
 

rule 7017

Int[FresnelC[(b_.)*(x_)]*(x_)^(m_)*Sin[(d_.)*(x_)^2], x_Symbol] :> Simp[(-x 
^(m - 1))*Cos[d*x^2]*(FresnelC[b*x]/(2*d)), x] + (Simp[(m - 1)/(2*d)   Int[ 
x^(m - 2)*Cos[d*x^2]*FresnelC[b*x], x], x] + Simp[b/(2*d)   Int[x^(m - 1)*C 
os[d*x^2]^2, x], x]) /; FreeQ[{b, d}, x] && EqQ[d^2, (Pi^2/4)*b^4] && IGtQ[ 
m, 1]
 

3.2.83.4 Maple [A] (verified)

Time = 2.40 (sec) , antiderivative size = 202, normalized size of antiderivative = 1.29

method	result	size
default	\(\frac {\frac {\operatorname {FresnelC}\left (b x \right ) \left (\frac {b^{4} x^{4} \sin \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{\pi }-\frac {4 \left (-\frac {b^{2} x^{2} \cos \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{\pi }+\frac {2 \sin \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{\pi ^{2}}\right )}{\pi }\right )}{b^{5}}-\frac {\frac {2 b^{3} x^{3}}{3 \pi ^{2}}+\frac {\frac {b x \sin \left (b^{2} \pi \,x^{2}\right )}{\pi }-\frac {\sqrt {2}\, \operatorname {FresnelS}\left (b x \sqrt {2}\right )}{2 \pi }}{\pi ^{2}}+\frac {-\frac {\pi \,b^{3} x^{3} \cos \left (b^{2} \pi \,x^{2}\right )}{2}+\frac {3 \pi \left (\frac {b x \sin \left (b^{2} \pi \,x^{2}\right )}{2 \pi }-\frac {\sqrt {2}\, \operatorname {FresnelS}\left (b x \sqrt {2}\right )}{4 \pi }\right )}{2}-4 \sqrt {2}\, \operatorname {FresnelS}\left (b x \sqrt {2}\right )}{2 \pi ^{3}}}{b^{5}}}{b}\)	\(202\)

input

int(x^5*cos(1/2*b^2*Pi*x^2)*FresnelC(b*x),x,method=_RETURNVERBOSE)
 

output

(FresnelC(b*x)/b^5*(1/Pi*b^4*x^4*sin(1/2*b^2*Pi*x^2)-4/Pi*(-1/Pi*b^2*x^2*c 
os(1/2*b^2*Pi*x^2)+2/Pi^2*sin(1/2*b^2*Pi*x^2)))-1/b^5*(2/3/Pi^2*b^3*x^3+2/ 
Pi^2*(1/2/Pi*b*x*sin(b^2*Pi*x^2)-1/4/Pi*2^(1/2)*FresnelS(b*x*2^(1/2)))+1/2 
/Pi^3*(-1/2*Pi*b^3*x^3*cos(b^2*Pi*x^2)+3/2*Pi*(1/2/Pi*b*x*sin(b^2*Pi*x^2)- 
1/4/Pi*2^(1/2)*FresnelS(b*x*2^(1/2)))-4*2^(1/2)*FresnelS(b*x*2^(1/2)))))/b
 

3.2.83.5 Fricas [A] (verification not implemented)

Time = 0.26 (sec) , antiderivative size = 132, normalized size of antiderivative = 0.84 \[ \int x^5 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x) \, dx=\frac {24 \, \pi b^{4} x^{3} \cos \left (\frac {1}{2} \, \pi b^{2} x^{2}\right )^{2} - 44 \, \pi b^{4} x^{3} + 192 \, \pi b^{3} x^{2} \cos \left (\frac {1}{2} \, \pi b^{2} x^{2}\right ) \operatorname {C}\left (b x\right ) + 129 \, \sqrt {2} \sqrt {b^{2}} \operatorname {S}\left (\sqrt {2} \sqrt {b^{2}} x\right ) - 12 \, {\left (11 \, b^{2} x \cos \left (\frac {1}{2} \, \pi b^{2} x^{2}\right ) - 4 \, {\left (\pi ^{2} b^{5} x^{4} - 8 \, b\right )} \operatorname {C}\left (b x\right )\right )} \sin \left (\frac {1}{2} \, \pi b^{2} x^{2}\right )}{48 \, \pi ^{3} b^{7}} \]

input

integrate(x^5*cos(1/2*b^2*pi*x^2)*fresnel_cos(b*x),x, algorithm="fricas")
 

output

1/48*(24*pi*b^4*x^3*cos(1/2*pi*b^2*x^2)^2 - 44*pi*b^4*x^3 + 192*pi*b^3*x^2 
*cos(1/2*pi*b^2*x^2)*fresnel_cos(b*x) + 129*sqrt(2)*sqrt(b^2)*fresnel_sin( 
sqrt(2)*sqrt(b^2)*x) - 12*(11*b^2*x*cos(1/2*pi*b^2*x^2) - 4*(pi^2*b^5*x^4 
- 8*b)*fresnel_cos(b*x))*sin(1/2*pi*b^2*x^2))/(pi^3*b^7)
 

3.2.83.6 Sympy [F]

\[ \int x^5 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x) \, dx=\int x^{5} \cos {\left (\frac {\pi b^{2} x^{2}}{2} \right )} C\left (b x\right )\, dx \]

input

integrate(x**5*cos(1/2*b**2*pi*x**2)*fresnelc(b*x),x)
 

output

Integral(x**5*cos(pi*b**2*x**2/2)*fresnelc(b*x), x)
 

3.2.83.7 Maxima [F]

\[ \int x^5 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x) \, dx=\int { x^{5} \cos \left (\frac {1}{2} \, \pi b^{2} x^{2}\right ) \operatorname {C}\left (b x\right ) \,d x } \]

input

integrate(x^5*cos(1/2*b^2*pi*x^2)*fresnel_cos(b*x),x, algorithm="maxima")
 

output

integrate(x^5*cos(1/2*pi*b^2*x^2)*fresnel_cos(b*x), x)
 

3.2.83.8 Giac [F]

\[ \int x^5 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x) \, dx=\int { x^{5} \cos \left (\frac {1}{2} \, \pi b^{2} x^{2}\right ) \operatorname {C}\left (b x\right ) \,d x } \]

input

integrate(x^5*cos(1/2*b^2*pi*x^2)*fresnel_cos(b*x),x, algorithm="giac")
 

output

integrate(x^5*cos(1/2*pi*b^2*x^2)*fresnel_cos(b*x), x)
 

3.2.83.9 Mupad [F(-1)]

Timed out. \[ \int x^5 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x) \, dx=\int x^5\,\mathrm {FresnelC}\left (b\,x\right )\,\cos \left (\frac {\Pi \,b^2\,x^2}{2}\right ) \,d x \]

input

int(x^5*FresnelC(b*x)*cos((Pi*b^2*x^2)/2),x)
 

output

int(x^5*FresnelC(b*x)*cos((Pi*b^2*x^2)/2), x)