3.3.10 \(\int \frac {\operatorname {FresnelC}(b x) \sin (\frac {1}{2} b^2 \pi x^2)}{x^2} \, dx\) [210]

3.3.10.1 Optimal result
3.3.10.2 Mathematica [A] (verified)
3.3.10.3 Rubi [A] (verified)
3.3.10.4 Maple [F]
3.3.10.5 Fricas [A] (verification not implemented)
3.3.10.6 Sympy [F]
3.3.10.7 Maxima [F]
3.3.10.8 Giac [F]
3.3.10.9 Mupad [F(-1)]

3.3.10.1 Optimal result

Integrand size = 20, antiderivative size = 48 \[ \int \frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^2} \, dx=\frac {1}{2} b \pi \operatorname {FresnelC}(b x)^2-\frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x}+\frac {1}{4} b \text {Si}\left (b^2 \pi x^2\right ) \]

output
1/2*b*Pi*FresnelC(b*x)^2+1/4*b*Si(b^2*Pi*x^2)-FresnelC(b*x)*sin(1/2*b^2*Pi 
*x^2)/x
 
3.3.10.2 Mathematica [A] (verified)

Time = 0.01 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.00 \[ \int \frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^2} \, dx=\frac {1}{2} b \pi \operatorname {FresnelC}(b x)^2-\frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x}+\frac {1}{4} b \text {Si}\left (b^2 \pi x^2\right ) \]

input
Integrate[(FresnelC[b*x]*Sin[(b^2*Pi*x^2)/2])/x^2,x]
 
output
(b*Pi*FresnelC[b*x]^2)/2 - (FresnelC[b*x]*Sin[(b^2*Pi*x^2)/2])/x + (b*SinI 
ntegral[b^2*Pi*x^2])/4
 
3.3.10.3 Rubi [A] (verified)

Time = 0.31 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {7019, 3856, 6995, 15}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{x^2} \, dx\)

\(\Big \downarrow \) 7019

\(\displaystyle \pi b^2 \int \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x)dx+\frac {1}{2} b \int \frac {\sin \left (b^2 \pi x^2\right )}{x}dx-\frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{x}\)

\(\Big \downarrow \) 3856

\(\displaystyle \pi b^2 \int \cos \left (\frac {1}{2} b^2 \pi x^2\right ) \operatorname {FresnelC}(b x)dx-\frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{x}+\frac {1}{4} b \text {Si}\left (b^2 \pi x^2\right )\)

\(\Big \downarrow \) 6995

\(\displaystyle \pi b \int \operatorname {FresnelC}(b x)d\operatorname {FresnelC}(b x)-\frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{x}+\frac {1}{4} b \text {Si}\left (b^2 \pi x^2\right )\)

\(\Big \downarrow \) 15

\(\displaystyle -\frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{x}+\frac {1}{4} b \text {Si}\left (b^2 \pi x^2\right )+\frac {1}{2} \pi b \operatorname {FresnelC}(b x)^2\)

input
Int[(FresnelC[b*x]*Sin[(b^2*Pi*x^2)/2])/x^2,x]
 
output
(b*Pi*FresnelC[b*x]^2)/2 - (FresnelC[b*x]*Sin[(b^2*Pi*x^2)/2])/x + (b*SinI 
ntegral[b^2*Pi*x^2])/4
 

3.3.10.3.1 Defintions of rubi rules used

rule 15
Int[(a_.)*(x_)^(m_.), x_Symbol] :> Simp[a*(x^(m + 1)/(m + 1)), x] /; FreeQ[ 
{a, m}, x] && NeQ[m, -1]
 

rule 3856
Int[Sin[(d_.)*(x_)^(n_)]/(x_), x_Symbol] :> Simp[SinIntegral[d*x^n]/n, x] / 
; FreeQ[{d, n}, x]
 

rule 6995
Int[Cos[(d_.)*(x_)^2]*FresnelC[(b_.)*(x_)]^(n_.), x_Symbol] :> Simp[Pi*(b/( 
2*d))   Subst[Int[x^n, x], x, FresnelC[b*x]], x] /; FreeQ[{b, d, n}, x] && 
EqQ[d^2, (Pi^2/4)*b^4]
 

rule 7019
Int[FresnelC[(b_.)*(x_)]*(x_)^(m_)*Sin[(d_.)*(x_)^2], x_Symbol] :> Simp[x^( 
m + 1)*Sin[d*x^2]*(FresnelC[b*x]/(m + 1)), x] + (-Simp[2*(d/(m + 1))   Int[ 
x^(m + 2)*Cos[d*x^2]*FresnelC[b*x], x], x] - Simp[b/(2*(m + 1))   Int[x^(m 
+ 1)*Sin[2*d*x^2], x], x]) /; FreeQ[{b, d}, x] && EqQ[d^2, (Pi^2/4)*b^4] && 
 ILtQ[m, -1]
 
3.3.10.4 Maple [F]

\[\int \frac {\operatorname {FresnelC}\left (b x \right ) \sin \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{x^{2}}d x\]

input
int(FresnelC(b*x)*sin(1/2*b^2*Pi*x^2)/x^2,x)
 
output
int(FresnelC(b*x)*sin(1/2*b^2*Pi*x^2)/x^2,x)
 
3.3.10.5 Fricas [A] (verification not implemented)

Time = 0.26 (sec) , antiderivative size = 45, normalized size of antiderivative = 0.94 \[ \int \frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^2} \, dx=\frac {2 \, \pi b x \operatorname {C}\left (b x\right )^{2} + b x \operatorname {Si}\left (\pi b^{2} x^{2}\right ) - 4 \, \operatorname {C}\left (b x\right ) \sin \left (\frac {1}{2} \, \pi b^{2} x^{2}\right )}{4 \, x} \]

input
integrate(fresnel_cos(b*x)*sin(1/2*b^2*pi*x^2)/x^2,x, algorithm="fricas")
 
output
1/4*(2*pi*b*x*fresnel_cos(b*x)^2 + b*x*sin_integral(pi*b^2*x^2) - 4*fresne 
l_cos(b*x)*sin(1/2*pi*b^2*x^2))/x
 
3.3.10.6 Sympy [F]

\[ \int \frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^2} \, dx=\int \frac {\sin {\left (\frac {\pi b^{2} x^{2}}{2} \right )} C\left (b x\right )}{x^{2}}\, dx \]

input
integrate(fresnelc(b*x)*sin(1/2*b**2*pi*x**2)/x**2,x)
 
output
Integral(sin(pi*b**2*x**2/2)*fresnelc(b*x)/x**2, x)
 
3.3.10.7 Maxima [F]

\[ \int \frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^2} \, dx=\int { \frac {\operatorname {C}\left (b x\right ) \sin \left (\frac {1}{2} \, \pi b^{2} x^{2}\right )}{x^{2}} \,d x } \]

input
integrate(fresnel_cos(b*x)*sin(1/2*b^2*pi*x^2)/x^2,x, algorithm="maxima")
 
output
integrate(fresnel_cos(b*x)*sin(1/2*pi*b^2*x^2)/x^2, x)
 
3.3.10.8 Giac [F]

\[ \int \frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^2} \, dx=\int { \frac {\operatorname {C}\left (b x\right ) \sin \left (\frac {1}{2} \, \pi b^{2} x^{2}\right )}{x^{2}} \,d x } \]

input
integrate(fresnel_cos(b*x)*sin(1/2*b^2*pi*x^2)/x^2,x, algorithm="giac")
 
output
integrate(fresnel_cos(b*x)*sin(1/2*pi*b^2*x^2)/x^2, x)
 
3.3.10.9 Mupad [F(-1)]

Timed out. \[ \int \frac {\operatorname {FresnelC}(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^2} \, dx=\int \frac {\mathrm {FresnelC}\left (b\,x\right )\,\sin \left (\frac {\Pi \,b^2\,x^2}{2}\right )}{x^2} \,d x \]

input
int((FresnelC(b*x)*sin((Pi*b^2*x^2)/2))/x^2,x)
 
output
int((FresnelC(b*x)*sin((Pi*b^2*x^2)/2))/x^2, x)