3.1.27 \(\int x \text {Shi}(a+b x)^2 \, dx\) [27]

3.1.27.1 Optimal result
3.1.27.2 Mathematica [A] (verified)
3.1.27.3 Rubi [A] (verified)
3.1.27.4 Maple [A] (verified)
3.1.27.5 Fricas [F]
3.1.27.6 Sympy [F]
3.1.27.7 Maxima [F]
3.1.27.8 Giac [F]
3.1.27.9 Mupad [F(-1)]

3.1.27.1 Optimal result

Integrand size = 10, antiderivative size = 154 \[ \int x \text {Shi}(a+b x)^2 \, dx=\frac {\cosh (2 a+2 b x)}{4 b^2}-\frac {\text {Chi}(2 a+2 b x)}{2 b^2}+\frac {\log (a+b x)}{2 b^2}+\frac {a \cosh (a+b x) \text {Shi}(a+b x)}{b^2}-\frac {x \cosh (a+b x) \text {Shi}(a+b x)}{b}+\frac {\sinh (a+b x) \text {Shi}(a+b x)}{b^2}-\frac {a (a+b x) \text {Shi}(a+b x)^2}{2 b^2}+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}-\frac {a \text {Shi}(2 a+2 b x)}{b^2} \]

output
-1/2*Chi(2*b*x+2*a)/b^2+1/4*cosh(2*b*x+2*a)/b^2+1/2*ln(b*x+a)/b^2+a*cosh(b 
*x+a)*Shi(b*x+a)/b^2-x*cosh(b*x+a)*Shi(b*x+a)/b-1/2*a*(b*x+a)*Shi(b*x+a)^2 
/b^2+1/2*x*(b*x+a)*Shi(b*x+a)^2/b-a*Shi(2*b*x+2*a)/b^2+Shi(b*x+a)*sinh(b*x 
+a)/b^2
 
3.1.27.2 Mathematica [A] (verified)

Time = 0.22 (sec) , antiderivative size = 95, normalized size of antiderivative = 0.62 \[ \int x \text {Shi}(a+b x)^2 \, dx=\frac {\cosh (2 (a+b x))-2 \text {Chi}(2 (a+b x))+2 \log (a+b x)+4 ((a-b x) \cosh (a+b x)+\sinh (a+b x)) \text {Shi}(a+b x)-2 \left (a^2-b^2 x^2\right ) \text {Shi}(a+b x)^2-4 a \text {Shi}(2 (a+b x))}{4 b^2} \]

input
Integrate[x*SinhIntegral[a + b*x]^2,x]
 
output
(Cosh[2*(a + b*x)] - 2*CoshIntegral[2*(a + b*x)] + 2*Log[a + b*x] + 4*((a 
- b*x)*Cosh[a + b*x] + Sinh[a + b*x])*SinhIntegral[a + b*x] - 2*(a^2 - b^2 
*x^2)*SinhIntegral[a + b*x]^2 - 4*a*SinhIntegral[2*(a + b*x)])/(4*b^2)
 
3.1.27.3 Rubi [A] (verified)

Time = 1.66 (sec) , antiderivative size = 187, normalized size of antiderivative = 1.21, number of steps used = 18, number of rules used = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.800, Rules used = {7092, 7088, 7094, 5971, 27, 3042, 26, 3779, 7096, 6151, 7100, 3042, 25, 3793, 2009, 7292, 7293, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int x \text {Shi}(a+b x)^2 \, dx\)

\(\Big \downarrow \) 7092

\(\displaystyle -\frac {a \int \text {Shi}(a+b x)^2dx}{2 b}-\int x \sinh (a+b x) \text {Shi}(a+b x)dx+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}\)

\(\Big \downarrow \) 7088

\(\displaystyle -\frac {a \left (\frac {(a+b x) \text {Shi}(a+b x)^2}{b}-2 \int \sinh (a+b x) \text {Shi}(a+b x)dx\right )}{2 b}-\int x \sinh (a+b x) \text {Shi}(a+b x)dx+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}\)

\(\Big \downarrow \) 7094

\(\displaystyle -\int x \sinh (a+b x) \text {Shi}(a+b x)dx-\frac {a \left (\frac {(a+b x) \text {Shi}(a+b x)^2}{b}-2 \left (\frac {\text {Shi}(a+b x) \cosh (a+b x)}{b}-\int \frac {\cosh (a+b x) \sinh (a+b x)}{a+b x}dx\right )\right )}{2 b}+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}\)

\(\Big \downarrow \) 5971

\(\displaystyle -\int x \sinh (a+b x) \text {Shi}(a+b x)dx-\frac {a \left (\frac {(a+b x) \text {Shi}(a+b x)^2}{b}-2 \left (\frac {\text {Shi}(a+b x) \cosh (a+b x)}{b}-\int \frac {\sinh (2 a+2 b x)}{2 (a+b x)}dx\right )\right )}{2 b}+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}\)

\(\Big \downarrow \) 27

\(\displaystyle -\int x \sinh (a+b x) \text {Shi}(a+b x)dx-\frac {a \left (\frac {(a+b x) \text {Shi}(a+b x)^2}{b}-2 \left (\frac {\text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {1}{2} \int \frac {\sinh (2 a+2 b x)}{a+b x}dx\right )\right )}{2 b}+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\int x \sinh (a+b x) \text {Shi}(a+b x)dx-\frac {a \left (\frac {(a+b x) \text {Shi}(a+b x)^2}{b}-2 \left (\frac {\text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {1}{2} \int -\frac {i \sin (2 i a+2 i b x)}{a+b x}dx\right )\right )}{2 b}+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}\)

\(\Big \downarrow \) 26

\(\displaystyle -\int x \sinh (a+b x) \text {Shi}(a+b x)dx-\frac {a \left (\frac {(a+b x) \text {Shi}(a+b x)^2}{b}-2 \left (\frac {\text {Shi}(a+b x) \cosh (a+b x)}{b}+\frac {1}{2} i \int \frac {\sin (2 i a+2 i b x)}{a+b x}dx\right )\right )}{2 b}+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}\)

\(\Big \downarrow \) 3779

\(\displaystyle -\int x \sinh (a+b x) \text {Shi}(a+b x)dx+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}-\frac {a \left (\frac {(a+b x) \text {Shi}(a+b x)^2}{b}-2 \left (\frac {\text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {\text {Shi}(2 a+2 b x)}{2 b}\right )\right )}{2 b}\)

\(\Big \downarrow \) 7096

\(\displaystyle \frac {\int \cosh (a+b x) \text {Shi}(a+b x)dx}{b}+\int \frac {x \cosh (a+b x) \sinh (a+b x)}{a+b x}dx+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}-\frac {x \text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {a \left (\frac {(a+b x) \text {Shi}(a+b x)^2}{b}-2 \left (\frac {\text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {\text {Shi}(2 a+2 b x)}{2 b}\right )\right )}{2 b}\)

\(\Big \downarrow \) 6151

\(\displaystyle \frac {\int \cosh (a+b x) \text {Shi}(a+b x)dx}{b}+\frac {1}{2} \int \frac {x \sinh (2 (a+b x))}{a+b x}dx+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}-\frac {x \text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {a \left (\frac {(a+b x) \text {Shi}(a+b x)^2}{b}-2 \left (\frac {\text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {\text {Shi}(2 a+2 b x)}{2 b}\right )\right )}{2 b}\)

\(\Big \downarrow \) 7100

\(\displaystyle \frac {\frac {\text {Shi}(a+b x) \sinh (a+b x)}{b}-\int \frac {\sinh ^2(a+b x)}{a+b x}dx}{b}+\frac {1}{2} \int \frac {x \sinh (2 (a+b x))}{a+b x}dx+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}-\frac {x \text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {a \left (\frac {(a+b x) \text {Shi}(a+b x)^2}{b}-2 \left (\frac {\text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {\text {Shi}(2 a+2 b x)}{2 b}\right )\right )}{2 b}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\text {Shi}(a+b x) \sinh (a+b x)}{b}-\int -\frac {\sin (i a+i b x)^2}{a+b x}dx}{b}+\frac {1}{2} \int \frac {x \sinh (2 (a+b x))}{a+b x}dx+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}-\frac {x \text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {a \left (\frac {(a+b x) \text {Shi}(a+b x)^2}{b}-2 \left (\frac {\text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {\text {Shi}(2 a+2 b x)}{2 b}\right )\right )}{2 b}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {\frac {\text {Shi}(a+b x) \sinh (a+b x)}{b}+\int \frac {\sin (i a+i b x)^2}{a+b x}dx}{b}+\frac {1}{2} \int \frac {x \sinh (2 (a+b x))}{a+b x}dx+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}-\frac {x \text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {a \left (\frac {(a+b x) \text {Shi}(a+b x)^2}{b}-2 \left (\frac {\text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {\text {Shi}(2 a+2 b x)}{2 b}\right )\right )}{2 b}\)

\(\Big \downarrow \) 3793

\(\displaystyle \frac {\int \left (\frac {1}{2 (a+b x)}-\frac {\cosh (2 a+2 b x)}{2 (a+b x)}\right )dx+\frac {\text {Shi}(a+b x) \sinh (a+b x)}{b}}{b}+\frac {1}{2} \int \frac {x \sinh (2 (a+b x))}{a+b x}dx+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}-\frac {x \text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {a \left (\frac {(a+b x) \text {Shi}(a+b x)^2}{b}-2 \left (\frac {\text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {\text {Shi}(2 a+2 b x)}{2 b}\right )\right )}{2 b}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {1}{2} \int \frac {x \sinh (2 (a+b x))}{a+b x}dx+\frac {-\frac {\text {Chi}(2 a+2 b x)}{2 b}+\frac {\text {Shi}(a+b x) \sinh (a+b x)}{b}+\frac {\log (a+b x)}{2 b}}{b}+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}-\frac {x \text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {a \left (\frac {(a+b x) \text {Shi}(a+b x)^2}{b}-2 \left (\frac {\text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {\text {Shi}(2 a+2 b x)}{2 b}\right )\right )}{2 b}\)

\(\Big \downarrow \) 7292

\(\displaystyle \frac {1}{2} \int \frac {x \sinh (2 a+2 b x)}{a+b x}dx+\frac {-\frac {\text {Chi}(2 a+2 b x)}{2 b}+\frac {\text {Shi}(a+b x) \sinh (a+b x)}{b}+\frac {\log (a+b x)}{2 b}}{b}+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}-\frac {x \text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {a \left (\frac {(a+b x) \text {Shi}(a+b x)^2}{b}-2 \left (\frac {\text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {\text {Shi}(2 a+2 b x)}{2 b}\right )\right )}{2 b}\)

\(\Big \downarrow \) 7293

\(\displaystyle \frac {1}{2} \int \left (\frac {\sinh (2 a+2 b x)}{b}+\frac {a \sinh (2 a+2 b x)}{b (-a-b x)}\right )dx+\frac {-\frac {\text {Chi}(2 a+2 b x)}{2 b}+\frac {\text {Shi}(a+b x) \sinh (a+b x)}{b}+\frac {\log (a+b x)}{2 b}}{b}+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}-\frac {x \text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {a \left (\frac {(a+b x) \text {Shi}(a+b x)^2}{b}-2 \left (\frac {\text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {\text {Shi}(2 a+2 b x)}{2 b}\right )\right )}{2 b}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {1}{2} \left (\frac {\cosh (2 a+2 b x)}{2 b^2}-\frac {a \text {Shi}(2 a+2 b x)}{b^2}\right )+\frac {-\frac {\text {Chi}(2 a+2 b x)}{2 b}+\frac {\text {Shi}(a+b x) \sinh (a+b x)}{b}+\frac {\log (a+b x)}{2 b}}{b}+\frac {x (a+b x) \text {Shi}(a+b x)^2}{2 b}-\frac {x \text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {a \left (\frac {(a+b x) \text {Shi}(a+b x)^2}{b}-2 \left (\frac {\text {Shi}(a+b x) \cosh (a+b x)}{b}-\frac {\text {Shi}(2 a+2 b x)}{2 b}\right )\right )}{2 b}\)

input
Int[x*SinhIntegral[a + b*x]^2,x]
 
output
-((x*Cosh[a + b*x]*SinhIntegral[a + b*x])/b) + (x*(a + b*x)*SinhIntegral[a 
 + b*x]^2)/(2*b) + (-1/2*CoshIntegral[2*a + 2*b*x]/b + Log[a + b*x]/(2*b) 
+ (Sinh[a + b*x]*SinhIntegral[a + b*x])/b)/b + (Cosh[2*a + 2*b*x]/(2*b^2) 
- (a*SinhIntegral[2*a + 2*b*x])/b^2)/2 - (a*(((a + b*x)*SinhIntegral[a + b 
*x]^2)/b - 2*((Cosh[a + b*x]*SinhIntegral[a + b*x])/b - SinhIntegral[2*a + 
 2*b*x]/(2*b))))/(2*b)
 

3.1.27.3.1 Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 26
Int[(Complex[0, a_])*(Fx_), x_Symbol] :> Simp[(Complex[Identity[0], a])   I 
nt[Fx, x], x] /; FreeQ[a, x] && EqQ[a^2, 1]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3779
Int[sin[(e_.) + (Complex[0, fz_])*(f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbo 
l] :> Simp[I*(SinhIntegral[c*f*(fz/d) + f*fz*x]/d), x] /; FreeQ[{c, d, e, f 
, fz}, x] && EqQ[d*e - c*f*fz*I, 0]
 

rule 3793
Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> In 
t[ExpandTrigReduce[(c + d*x)^m, Sin[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f 
, m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1]))
 

rule 5971
Int[Cosh[(a_.) + (b_.)*(x_)]^(p_.)*((c_.) + (d_.)*(x_))^(m_.)*Sinh[(a_.) + 
(b_.)*(x_)]^(n_.), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sinh[a + 
b*x]^n*Cosh[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n, 0] & 
& IGtQ[p, 0]
 

rule 6151
Int[Cosh[w_]^(p_.)*(u_.)*Sinh[v_]^(p_.), x_Symbol] :> Simp[1/2^p   Int[u*Si 
nh[2*v]^p, x], x] /; EqQ[w, v] && IntegerQ[p]
 

rule 7088
Int[SinhIntegral[(a_.) + (b_.)*(x_)]^2, x_Symbol] :> Simp[(a + b*x)*(SinhIn 
tegral[a + b*x]^2/b), x] - Simp[2   Int[Sinh[a + b*x]*SinhIntegral[a + b*x] 
, x], x] /; FreeQ[{a, b}, x]
 

rule 7092
Int[((c_.) + (d_.)*(x_))^(m_.)*SinhIntegral[(a_) + (b_.)*(x_)]^2, x_Symbol] 
 :> Simp[(a + b*x)*(c + d*x)^m*(SinhIntegral[a + b*x]^2/(b*(m + 1))), x] + 
(-Simp[2/(m + 1)   Int[(c + d*x)^m*Sinh[a + b*x]*SinhIntegral[a + b*x], x], 
 x] + Simp[(b*c - a*d)*(m/(b*(m + 1)))   Int[(c + d*x)^(m - 1)*SinhIntegral 
[a + b*x]^2, x], x]) /; FreeQ[{a, b, c, d}, x] && IGtQ[m, 0]
 

rule 7094
Int[Sinh[(a_.) + (b_.)*(x_)]*SinhIntegral[(c_.) + (d_.)*(x_)], x_Symbol] :> 
 Simp[Cosh[a + b*x]*(SinhIntegral[c + d*x]/b), x] - Simp[d/b   Int[Cosh[a + 
 b*x]*(Sinh[c + d*x]/(c + d*x)), x], x] /; FreeQ[{a, b, c, d}, x]
 

rule 7096
Int[((e_.) + (f_.)*(x_))^(m_.)*Sinh[(a_.) + (b_.)*(x_)]*SinhIntegral[(c_.) 
+ (d_.)*(x_)], x_Symbol] :> Simp[(e + f*x)^m*Cosh[a + b*x]*(SinhIntegral[c 
+ d*x]/b), x] + (-Simp[d/b   Int[(e + f*x)^m*Cosh[a + b*x]*(Sinh[c + d*x]/( 
c + d*x)), x], x] - Simp[f*(m/b)   Int[(e + f*x)^(m - 1)*Cosh[a + b*x]*Sinh 
Integral[c + d*x], x], x]) /; FreeQ[{a, b, c, d, e, f}, x] && IGtQ[m, 0]
 

rule 7100
Int[Cosh[(a_.) + (b_.)*(x_)]*SinhIntegral[(c_.) + (d_.)*(x_)], x_Symbol] :> 
 Simp[Sinh[a + b*x]*(SinhIntegral[c + d*x]/b), x] - Simp[d/b   Int[Sinh[a + 
 b*x]*(Sinh[c + d*x]/(c + d*x)), x], x] /; FreeQ[{a, b, c, d}, x]
 

rule 7292
Int[u_, x_Symbol] :> With[{v = NormalizeIntegrand[u, x]}, Int[v, x] /; v =! 
= u]
 

rule 7293
Int[u_, x_Symbol] :> With[{v = ExpandIntegrand[u, x]}, Int[v, x] /; SumQ[v] 
]
 
3.1.27.4 Maple [A] (verified)

Time = 0.97 (sec) , antiderivative size = 113, normalized size of antiderivative = 0.73

method result size
derivativedivides \(\frac {\operatorname {Shi}\left (b x +a \right )^{2} \left (-\left (b x +a \right ) a +\frac {\left (b x +a \right )^{2}}{2}\right )-2 \,\operatorname {Shi}\left (b x +a \right ) \left (-a \cosh \left (b x +a \right )+\frac {\left (b x +a \right ) \cosh \left (b x +a \right )}{2}-\frac {\sinh \left (b x +a \right )}{2}\right )-a \,\operatorname {Shi}\left (2 b x +2 a \right )+\frac {\cosh \left (b x +a \right )^{2}}{2}+\frac {\ln \left (b x +a \right )}{2}-\frac {\operatorname {Chi}\left (2 b x +2 a \right )}{2}}{b^{2}}\) \(113\)
default \(\frac {\operatorname {Shi}\left (b x +a \right )^{2} \left (-\left (b x +a \right ) a +\frac {\left (b x +a \right )^{2}}{2}\right )-2 \,\operatorname {Shi}\left (b x +a \right ) \left (-a \cosh \left (b x +a \right )+\frac {\left (b x +a \right ) \cosh \left (b x +a \right )}{2}-\frac {\sinh \left (b x +a \right )}{2}\right )-a \,\operatorname {Shi}\left (2 b x +2 a \right )+\frac {\cosh \left (b x +a \right )^{2}}{2}+\frac {\ln \left (b x +a \right )}{2}-\frac {\operatorname {Chi}\left (2 b x +2 a \right )}{2}}{b^{2}}\) \(113\)

input
int(x*Shi(b*x+a)^2,x,method=_RETURNVERBOSE)
 
output
1/b^2*(Shi(b*x+a)^2*(-(b*x+a)*a+1/2*(b*x+a)^2)-2*Shi(b*x+a)*(-a*cosh(b*x+a 
)+1/2*(b*x+a)*cosh(b*x+a)-1/2*sinh(b*x+a))-a*Shi(2*b*x+2*a)+1/2*cosh(b*x+a 
)^2+1/2*ln(b*x+a)-1/2*Chi(2*b*x+2*a))
 
3.1.27.5 Fricas [F]

\[ \int x \text {Shi}(a+b x)^2 \, dx=\int { x {\rm Shi}\left (b x + a\right )^{2} \,d x } \]

input
integrate(x*Shi(b*x+a)^2,x, algorithm="fricas")
 
output
integral(x*sinh_integral(b*x + a)^2, x)
 
3.1.27.6 Sympy [F]

\[ \int x \text {Shi}(a+b x)^2 \, dx=\int x \operatorname {Shi}^{2}{\left (a + b x \right )}\, dx \]

input
integrate(x*Shi(b*x+a)**2,x)
 
output
Integral(x*Shi(a + b*x)**2, x)
 
3.1.27.7 Maxima [F]

\[ \int x \text {Shi}(a+b x)^2 \, dx=\int { x {\rm Shi}\left (b x + a\right )^{2} \,d x } \]

input
integrate(x*Shi(b*x+a)^2,x, algorithm="maxima")
 
output
integrate(x*Shi(b*x + a)^2, x)
 
3.1.27.8 Giac [F]

\[ \int x \text {Shi}(a+b x)^2 \, dx=\int { x {\rm Shi}\left (b x + a\right )^{2} \,d x } \]

input
integrate(x*Shi(b*x+a)^2,x, algorithm="giac")
 
output
integrate(x*Shi(b*x + a)^2, x)
 
3.1.27.9 Mupad [F(-1)]

Timed out. \[ \int x \text {Shi}(a+b x)^2 \, dx=\int x\,{\mathrm {sinhint}\left (a+b\,x\right )}^2 \,d x \]

input
int(x*sinhint(a + b*x)^2,x)
 
output
int(x*sinhint(a + b*x)^2, x)