Integrand size = 15, antiderivative size = 105 \[ \int \frac {\operatorname {PolyLog}\left (2,a x^q\right )}{(d x)^{5/2}} \, dx=-\frac {8 a q^2 x^{-1+q} \operatorname {Hypergeometric2F1}\left (1,\frac {1}{2} \left (2-\frac {3}{q}\right ),\frac {1}{2} \left (4-\frac {3}{q}\right ),a x^q\right )}{9 d^2 (3-2 q) \sqrt {d x}}+\frac {4 q \log \left (1-a x^q\right )}{9 d (d x)^{3/2}}-\frac {2 \operatorname {PolyLog}\left (2,a x^q\right )}{3 d (d x)^{3/2}} \]
4/9*q*ln(1-a*x^q)/d/(d*x)^(3/2)-2/3*polylog(2,a*x^q)/d/(d*x)^(3/2)-8/9*a*q ^2*x^(-1+q)*hypergeom([1, 1-3/2/q],[2-3/2/q],a*x^q)/d^2/(3-2*q)/(d*x)^(1/2 )
Result contains higher order function than in optimal. Order 9 vs. order 5 in optimal.
Time = 0.04 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.46 \[ \int \frac {\operatorname {PolyLog}\left (2,a x^q\right )}{(d x)^{5/2}} \, dx=-\frac {x G_{4,4}^{1,4}\left (-a x^q|\begin {array}{c} 1,1,1,1+\frac {3}{2 q} \\ 1,0,0,\frac {3}{2 q} \\\end {array}\right )}{q (d x)^{5/2}} \]
-((x*MeijerG[{{1, 1, 1, 1 + 3/(2*q)}, {}}, {{1}, {0, 0, 3/(2*q)}}, -(a*x^q )])/(q*(d*x)^(5/2)))
Time = 0.30 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.04, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {7145, 25, 2905, 30, 888}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\operatorname {PolyLog}\left (2,a x^q\right )}{(d x)^{5/2}} \, dx\) |
\(\Big \downarrow \) 7145 |
\(\displaystyle \frac {2}{3} q \int -\frac {\log \left (1-a x^q\right )}{(d x)^{5/2}}dx-\frac {2 \operatorname {PolyLog}\left (2,a x^q\right )}{3 d (d x)^{3/2}}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle -\frac {2}{3} q \int \frac {\log \left (1-a x^q\right )}{(d x)^{5/2}}dx-\frac {2 \operatorname {PolyLog}\left (2,a x^q\right )}{3 d (d x)^{3/2}}\) |
\(\Big \downarrow \) 2905 |
\(\displaystyle -\frac {2}{3} q \left (-\frac {2 a q \int \frac {x^{q-1}}{(d x)^{3/2} \left (1-a x^q\right )}dx}{3 d}-\frac {2 \log \left (1-a x^q\right )}{3 d (d x)^{3/2}}\right )-\frac {2 \operatorname {PolyLog}\left (2,a x^q\right )}{3 d (d x)^{3/2}}\) |
\(\Big \downarrow \) 30 |
\(\displaystyle -\frac {2}{3} q \left (-\frac {2 a q \sqrt {x} \int \frac {x^{q-\frac {5}{2}}}{1-a x^q}dx}{3 d^2 \sqrt {d x}}-\frac {2 \log \left (1-a x^q\right )}{3 d (d x)^{3/2}}\right )-\frac {2 \operatorname {PolyLog}\left (2,a x^q\right )}{3 d (d x)^{3/2}}\) |
\(\Big \downarrow \) 888 |
\(\displaystyle -\frac {2}{3} q \left (\frac {4 a q x^{q-1} \operatorname {Hypergeometric2F1}\left (1,-\frac {\frac {3}{2}-q}{q},\frac {1}{2} \left (4-\frac {3}{q}\right ),a x^q\right )}{3 d^2 (3-2 q) \sqrt {d x}}-\frac {2 \log \left (1-a x^q\right )}{3 d (d x)^{3/2}}\right )-\frac {2 \operatorname {PolyLog}\left (2,a x^q\right )}{3 d (d x)^{3/2}}\) |
(-2*q*((4*a*q*x^(-1 + q)*Hypergeometric2F1[1, -((3/2 - q)/q), (4 - 3/q)/2, a*x^q])/(3*d^2*(3 - 2*q)*Sqrt[d*x]) - (2*Log[1 - a*x^q])/(3*d*(d*x)^(3/2) )))/3 - (2*PolyLog[2, a*x^q])/(3*d*(d*x)^(3/2))
3.1.90.3.1 Defintions of rubi rules used
Int[(u_.)*((a_.)*(x_))^(m_.)*((b_.)*(x_)^(i_.))^(p_), x_Symbol] :> Simp[b^I ntPart[p]*((b*x^i)^FracPart[p]/(a^(i*IntPart[p])*(a*x)^(i*FracPart[p]))) Int[u*(a*x)^(m + i*p), x], x] /; FreeQ[{a, b, i, m, p}, x] && IntegerQ[i] & & !IntegerQ[p]
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^p *((c*x)^(m + 1)/(c*(m + 1)))*Hypergeometric2F1[-p, (m + 1)/n, (m + 1)/n + 1 , (-b)*(x^n/a)], x] /; FreeQ[{a, b, c, m, n, p}, x] && !IGtQ[p, 0] && (ILt Q[p, 0] || GtQ[a, 0])
Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))*((f_.)*(x_))^ (m_.), x_Symbol] :> Simp[(f*x)^(m + 1)*((a + b*Log[c*(d + e*x^n)^p])/(f*(m + 1))), x] - Simp[b*e*n*(p/(f*(m + 1))) Int[x^(n - 1)*((f*x)^(m + 1)/(d + e*x^n)), x], x] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x] && NeQ[m, -1]
Int[((d_.)*(x_))^(m_.)*PolyLog[n_, (a_.)*((b_.)*(x_)^(p_.))^(q_.)], x_Symbo l] :> Simp[(d*x)^(m + 1)*(PolyLog[n, a*(b*x^p)^q]/(d*(m + 1))), x] - Simp[p *(q/(m + 1)) Int[(d*x)^m*PolyLog[n - 1, a*(b*x^p)^q], x], x] /; FreeQ[{a, b, d, m, p, q}, x] && NeQ[m, -1] && GtQ[n, 0]
Result contains higher order function than in optimal. Order 9 vs. order 5.
Time = 0.97 (sec) , antiderivative size = 121, normalized size of antiderivative = 1.15
method | result | size |
meijerg | \(-\frac {x^{\frac {5}{2}} \left (-a \right )^{\frac {3}{2 q}} \left (-\frac {4 q^{2} \left (-a \right )^{-\frac {3}{2 q}} \ln \left (1-a \,x^{q}\right )}{9 x^{\frac {3}{2}}}-\frac {2 q \left (-a \right )^{-\frac {3}{2 q}} \left (1-\frac {2 q}{3}\right ) \operatorname {polylog}\left (2, a \,x^{q}\right )}{\left (-3+2 q \right ) x^{\frac {3}{2}}}-\frac {4 q^{2} x^{q -\frac {3}{2}} a \left (-a \right )^{-\frac {3}{2 q}} \operatorname {LerchPhi}\left (a \,x^{q}, 1, \frac {-3+2 q}{2 q}\right )}{9}\right )}{\left (d x \right )^{\frac {5}{2}} q}\) | \(121\) |
-1/(d*x)^(5/2)*x^(5/2)*(-a)^(3/2/q)/q*(-4/9*q^2/x^(3/2)*(-a)^(-3/2/q)*ln(1 -a*x^q)-2*q/(-3+2*q)/x^(3/2)*(-a)^(-3/2/q)*(1-2/3*q)*polylog(2,a*x^q)-4/9* q^2*x^(q-3/2)*a*(-a)^(-3/2/q)*LerchPhi(a*x^q,1,1/2*(-3+2*q)/q))
\[ \int \frac {\operatorname {PolyLog}\left (2,a x^q\right )}{(d x)^{5/2}} \, dx=\int { \frac {{\rm Li}_2\left (a x^{q}\right )}{\left (d x\right )^{\frac {5}{2}}} \,d x } \]
Timed out. \[ \int \frac {\operatorname {PolyLog}\left (2,a x^q\right )}{(d x)^{5/2}} \, dx=\text {Timed out} \]
\[ \int \frac {\operatorname {PolyLog}\left (2,a x^q\right )}{(d x)^{5/2}} \, dx=\int { \frac {{\rm Li}_2\left (a x^{q}\right )}{\left (d x\right )^{\frac {5}{2}}} \,d x } \]
8*q^3*integrate(1/9/((2*d^(5/2)*q + 3*d^(5/2) + (2*a^2*d^(5/2)*q + 3*a^2*d ^(5/2))*x^(2*q) - 2*(2*a*d^(5/2)*q + 3*a*d^(5/2))*x^q)*x^(5/2)), x) + 2/27 *(9*((2*a*sqrt(d)*q + 3*a*sqrt(d))*x*x^q - (2*sqrt(d)*q + 3*sqrt(d))*x)*di log(a*x^q)/x^(5/2) - 6*((2*a*sqrt(d)*q^2 + 3*a*sqrt(d)*q)*x*x^q - (2*sqrt( d)*q^2 + 3*sqrt(d)*q)*x)*log(-a*x^q + 1)/x^(5/2) + 4*(2*sqrt(d)*q^3*x - (2 *a*sqrt(d)*q^3 + 3*a*sqrt(d)*q^2)*x*x^q)/x^(5/2))/(2*d^3*q + 3*d^3 - (2*a* d^3*q + 3*a*d^3)*x^q)
\[ \int \frac {\operatorname {PolyLog}\left (2,a x^q\right )}{(d x)^{5/2}} \, dx=\int { \frac {{\rm Li}_2\left (a x^{q}\right )}{\left (d x\right )^{\frac {5}{2}}} \,d x } \]
Timed out. \[ \int \frac {\operatorname {PolyLog}\left (2,a x^q\right )}{(d x)^{5/2}} \, dx=\int \frac {\mathrm {polylog}\left (2,a\,x^q\right )}{{\left (d\,x\right )}^{5/2}} \,d x \]