\(\int \frac {\log ^{\frac {2}{x}}(\frac {1}{9} x \log ^2(e^{-x} x)) (32-32 x+16 \log (e^{-x} x)-16 \log (e^{-x} x) \log (\frac {1}{9} x \log ^2(e^{-x} x)) \log (\log (\frac {1}{9} x \log ^2(e^{-x} x))))+\log ^{\frac {4}{x}}(\frac {1}{9} x \log ^2(e^{-x} x)) (32-32 x+16 \log (e^{-x} x)-16 \log (e^{-x} x) \log (\frac {1}{9} x \log ^2(e^{-x} x)) \log (\log (\frac {1}{9} x \log ^2(e^{-x} x))))}{x^2 \log (e^{-x} x) \log (\frac {1}{9} x \log ^2(e^{-x} x))} \, dx\) [2070]

Optimal result
Mathematica [A] (verified)
Rubi [F]
Maple [A] (verified)
Fricas [A] (verification not implemented)
Sympy [F(-1)]
Maxima [F]
Giac [F]
Mupad [B] (verification not implemented)
Reduce [B] (verification not implemented)

Optimal result

Integrand size = 195, antiderivative size = 30 \[ \int \frac {\log ^{\frac {2}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (32-32 x+16 \log \left (e^{-x} x\right )-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )\right )+\log ^{\frac {4}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (32-32 x+16 \log \left (e^{-x} x\right )-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )\right )}{x^2 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )} \, dx=4 \left (4+\left (1+\log ^{\frac {2}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )^2\right ) \] Output:

4*(1+exp(2*ln(ln(1/9*x*ln(x/exp(x))^2))/x))^2+16
 

Mathematica [A] (verified)

Time = 0.06 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.60 \[ \int \frac {\log ^{\frac {2}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (32-32 x+16 \log \left (e^{-x} x\right )-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )\right )+\log ^{\frac {4}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (32-32 x+16 \log \left (e^{-x} x\right )-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )\right )}{x^2 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )} \, dx=4 \log ^{\frac {2}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (2+\log ^{\frac {2}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right ) \] Input:

Integrate[(Log[(x*Log[x/E^x]^2)/9]^(2/x)*(32 - 32*x + 16*Log[x/E^x] - 16*L 
og[x/E^x]*Log[(x*Log[x/E^x]^2)/9]*Log[Log[(x*Log[x/E^x]^2)/9]]) + Log[(x*L 
og[x/E^x]^2)/9]^(4/x)*(32 - 32*x + 16*Log[x/E^x] - 16*Log[x/E^x]*Log[(x*Lo 
g[x/E^x]^2)/9]*Log[Log[(x*Log[x/E^x]^2)/9]]))/(x^2*Log[x/E^x]*Log[(x*Log[x 
/E^x]^2)/9]),x]
 

Output:

4*Log[(x*Log[x/E^x]^2)/9]^(2/x)*(2 + Log[(x*Log[x/E^x]^2)/9]^(2/x))
 

Rubi [F]

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\left (-32 x-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )+16 \log \left (e^{-x} x\right )+32\right ) \log ^{\frac {2}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )+\left (-32 x-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )+16 \log \left (e^{-x} x\right )+32\right ) \log ^{\frac {4}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )}{x^2 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )} \, dx\)

\(\Big \downarrow \) 7239

\(\displaystyle \int \frac {16 \log ^{\frac {2}{x}-1}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (\log ^{\frac {2}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )+1\right ) \left (-2 (x-1)-\log \left (e^{-x} x\right ) \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )-1\right )\right )}{x^2 \log \left (e^{-x} x\right )}dx\)

\(\Big \downarrow \) 27

\(\displaystyle 16 \int \frac {\log ^{\frac {2}{x}-1}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (\log ^{\frac {2}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )+1\right ) \left (2 (1-x)+\log \left (e^{-x} x\right ) \left (1-\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )\right )\right )}{x^2 \log \left (e^{-x} x\right )}dx\)

\(\Big \downarrow \) 7293

\(\displaystyle 16 \int \left (\frac {\log ^{\frac {2}{x}-1}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (-2 x+\log \left (e^{-x} x\right )-\log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )+2\right )}{x^2 \log \left (e^{-x} x\right )}-\frac {\log ^{\frac {4}{x}-1}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (2 x-\log \left (e^{-x} x\right )+\log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )-2\right )}{x^2 \log \left (e^{-x} x\right )}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle 16 \left (\int \frac {\log ^{\frac {2}{x}-1}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )}{x^2}dx+2 \int \frac {\log ^{\frac {2}{x}-1}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )}{x^2 \log \left (e^{-x} x\right )}dx+\int \frac {\log ^{\frac {4}{x}-1}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )}{x^2}dx+2 \int \frac {\log ^{\frac {4}{x}-1}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )}{x^2 \log \left (e^{-x} x\right )}dx-\int \frac {\log ^{\frac {2}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )}{x^2}dx-\int \frac {\log ^{\frac {4}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )}{x^2}dx-2 \int \frac {\log ^{\frac {2}{x}-1}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )}{x \log \left (e^{-x} x\right )}dx-2 \int \frac {\log ^{\frac {4}{x}-1}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )}{x \log \left (e^{-x} x\right )}dx\right )\)

Input:

Int[(Log[(x*Log[x/E^x]^2)/9]^(2/x)*(32 - 32*x + 16*Log[x/E^x] - 16*Log[x/E 
^x]*Log[(x*Log[x/E^x]^2)/9]*Log[Log[(x*Log[x/E^x]^2)/9]]) + Log[(x*Log[x/E 
^x]^2)/9]^(4/x)*(32 - 32*x + 16*Log[x/E^x] - 16*Log[x/E^x]*Log[(x*Log[x/E^ 
x]^2)/9]*Log[Log[(x*Log[x/E^x]^2)/9]]))/(x^2*Log[x/E^x]*Log[(x*Log[x/E^x]^ 
2)/9]),x]
 

Output:

$Aborted
 
Maple [A] (verified)

Time = 24.81 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.60

method result size
parallelrisch \(4 \,{\mathrm e}^{\frac {4 \ln \left (\ln \left (\frac {x \ln \left (x \,{\mathrm e}^{-x}\right )^{2}}{9}\right )\right )}{x}}+8 \,{\mathrm e}^{\frac {2 \ln \left (\ln \left (\frac {x \ln \left (x \,{\mathrm e}^{-x}\right )^{2}}{9}\right )\right )}{x}}\) \(48\)

Input:

int(((-16*ln(x/exp(x))*ln(1/9*x*ln(x/exp(x))^2)*ln(ln(1/9*x*ln(x/exp(x))^2 
))+16*ln(x/exp(x))-32*x+32)*exp(2*ln(ln(1/9*x*ln(x/exp(x))^2))/x)^2+(-16*l 
n(x/exp(x))*ln(1/9*x*ln(x/exp(x))^2)*ln(ln(1/9*x*ln(x/exp(x))^2))+16*ln(x/ 
exp(x))-32*x+32)*exp(2*ln(ln(1/9*x*ln(x/exp(x))^2))/x))/x^2/ln(x/exp(x))/l 
n(1/9*x*ln(x/exp(x))^2),x,method=_RETURNVERBOSE)
 

Output:

4*exp(2*ln(ln(1/9*x*ln(x/exp(x))^2))/x)^2+8*exp(2*ln(ln(1/9*x*ln(x/exp(x)) 
^2))/x)
 

Fricas [A] (verification not implemented)

Time = 0.07 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.43 \[ \int \frac {\log ^{\frac {2}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (32-32 x+16 \log \left (e^{-x} x\right )-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )\right )+\log ^{\frac {4}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (32-32 x+16 \log \left (e^{-x} x\right )-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )\right )}{x^2 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )} \, dx=4 \, \log \left (\frac {1}{9} \, x \log \left (x e^{\left (-x\right )}\right )^{2}\right )^{\frac {4}{x}} + 8 \, \log \left (\frac {1}{9} \, x \log \left (x e^{\left (-x\right )}\right )^{2}\right )^{\frac {2}{x}} \] Input:

integrate(((-16*log(x/exp(x))*log(1/9*x*log(x/exp(x))^2)*log(log(1/9*x*log 
(x/exp(x))^2))+16*log(x/exp(x))-32*x+32)*exp(2*log(log(1/9*x*log(x/exp(x)) 
^2))/x)^2+(-16*log(x/exp(x))*log(1/9*x*log(x/exp(x))^2)*log(log(1/9*x*log( 
x/exp(x))^2))+16*log(x/exp(x))-32*x+32)*exp(2*log(log(1/9*x*log(x/exp(x))^ 
2))/x))/x^2/log(x/exp(x))/log(1/9*x*log(x/exp(x))^2),x, algorithm="fricas" 
)
 

Output:

4*log(1/9*x*log(x*e^(-x))^2)^(4/x) + 8*log(1/9*x*log(x*e^(-x))^2)^(2/x)
 

Sympy [F(-1)]

Timed out. \[ \int \frac {\log ^{\frac {2}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (32-32 x+16 \log \left (e^{-x} x\right )-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )\right )+\log ^{\frac {4}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (32-32 x+16 \log \left (e^{-x} x\right )-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )\right )}{x^2 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )} \, dx=\text {Timed out} \] Input:

integrate(((-16*ln(x/exp(x))*ln(1/9*x*ln(x/exp(x))**2)*ln(ln(1/9*x*ln(x/ex 
p(x))**2))+16*ln(x/exp(x))-32*x+32)*exp(2*ln(ln(1/9*x*ln(x/exp(x))**2))/x) 
**2+(-16*ln(x/exp(x))*ln(1/9*x*ln(x/exp(x))**2)*ln(ln(1/9*x*ln(x/exp(x))** 
2))+16*ln(x/exp(x))-32*x+32)*exp(2*ln(ln(1/9*x*ln(x/exp(x))**2))/x))/x**2/ 
ln(x/exp(x))/ln(1/9*x*ln(x/exp(x))**2),x)
 

Output:

Timed out
 

Maxima [F]

\[ \int \frac {\log ^{\frac {2}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (32-32 x+16 \log \left (e^{-x} x\right )-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )\right )+\log ^{\frac {4}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (32-32 x+16 \log \left (e^{-x} x\right )-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )\right )}{x^2 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )} \, dx=\int { -\frac {16 \, {\left ({\left (\log \left (\frac {1}{9} \, x \log \left (x e^{\left (-x\right )}\right )^{2}\right ) \log \left (x e^{\left (-x\right )}\right ) \log \left (\log \left (\frac {1}{9} \, x \log \left (x e^{\left (-x\right )}\right )^{2}\right )\right ) + 2 \, x - \log \left (x e^{\left (-x\right )}\right ) - 2\right )} \log \left (\frac {1}{9} \, x \log \left (x e^{\left (-x\right )}\right )^{2}\right )^{\frac {4}{x}} + {\left (\log \left (\frac {1}{9} \, x \log \left (x e^{\left (-x\right )}\right )^{2}\right ) \log \left (x e^{\left (-x\right )}\right ) \log \left (\log \left (\frac {1}{9} \, x \log \left (x e^{\left (-x\right )}\right )^{2}\right )\right ) + 2 \, x - \log \left (x e^{\left (-x\right )}\right ) - 2\right )} \log \left (\frac {1}{9} \, x \log \left (x e^{\left (-x\right )}\right )^{2}\right )^{\frac {2}{x}}\right )}}{x^{2} \log \left (\frac {1}{9} \, x \log \left (x e^{\left (-x\right )}\right )^{2}\right ) \log \left (x e^{\left (-x\right )}\right )} \,d x } \] Input:

integrate(((-16*log(x/exp(x))*log(1/9*x*log(x/exp(x))^2)*log(log(1/9*x*log 
(x/exp(x))^2))+16*log(x/exp(x))-32*x+32)*exp(2*log(log(1/9*x*log(x/exp(x)) 
^2))/x)^2+(-16*log(x/exp(x))*log(1/9*x*log(x/exp(x))^2)*log(log(1/9*x*log( 
x/exp(x))^2))+16*log(x/exp(x))-32*x+32)*exp(2*log(log(1/9*x*log(x/exp(x))^ 
2))/x))/x^2/log(x/exp(x))/log(1/9*x*log(x/exp(x))^2),x, algorithm="maxima" 
)
 

Output:

4*(-2*log(3) + log(x) + 2*log(-x + log(x)))^(4/x) + 8*(-2*log(3) + log(x) 
+ 2*log(-x + log(x)))^(2/x) + 16*integrate(-2*((3*x - log(x) - 2)*log(x - 
log(x)) - (3*x - log(x) - 2)*log(-x + log(x)))*(-2*log(3) + log(x) + 2*log 
(-x + log(x)))^(4/x)/(4*x^3*log(3)^2 - x^2*log(x)^3 + (x^3 + 4*x^2*log(3)) 
*log(x)^2 - 2*(2*x^3*log(3) + x^2*log(x)^2 - (x^3 + 2*x^2*log(3))*log(x))* 
log(x - log(x)) - 4*(x^3*log(3) + x^2*log(3)^2)*log(x) - 2*(2*x^3*log(3) + 
 x^2*log(x)^2 - 2*(x^3 - x^2*log(x))*log(x - log(x)) - (x^3 + 2*x^2*log(3) 
)*log(x))*log(-x + log(x))), x) + 16*integrate(-2*((3*x - log(x) - 2)*log( 
x - log(x)) - (3*x - log(x) - 2)*log(-x + log(x)))*(-2*log(3) + log(x) + 2 
*log(-x + log(x)))^(2/x)/(4*x^3*log(3)^2 - x^2*log(x)^3 + (x^3 + 4*x^2*log 
(3))*log(x)^2 - 2*(2*x^3*log(3) + x^2*log(x)^2 - (x^3 + 2*x^2*log(3))*log( 
x))*log(x - log(x)) - 4*(x^3*log(3) + x^2*log(3)^2)*log(x) - 2*(2*x^3*log( 
3) + x^2*log(x)^2 - 2*(x^3 - x^2*log(x))*log(x - log(x)) - (x^3 + 2*x^2*lo 
g(3))*log(x))*log(-x + log(x))), x)
 

Giac [F]

\[ \int \frac {\log ^{\frac {2}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (32-32 x+16 \log \left (e^{-x} x\right )-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )\right )+\log ^{\frac {4}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (32-32 x+16 \log \left (e^{-x} x\right )-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )\right )}{x^2 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )} \, dx=\int { -\frac {16 \, {\left ({\left (\log \left (\frac {1}{9} \, x \log \left (x e^{\left (-x\right )}\right )^{2}\right ) \log \left (x e^{\left (-x\right )}\right ) \log \left (\log \left (\frac {1}{9} \, x \log \left (x e^{\left (-x\right )}\right )^{2}\right )\right ) + 2 \, x - \log \left (x e^{\left (-x\right )}\right ) - 2\right )} \log \left (\frac {1}{9} \, x \log \left (x e^{\left (-x\right )}\right )^{2}\right )^{\frac {4}{x}} + {\left (\log \left (\frac {1}{9} \, x \log \left (x e^{\left (-x\right )}\right )^{2}\right ) \log \left (x e^{\left (-x\right )}\right ) \log \left (\log \left (\frac {1}{9} \, x \log \left (x e^{\left (-x\right )}\right )^{2}\right )\right ) + 2 \, x - \log \left (x e^{\left (-x\right )}\right ) - 2\right )} \log \left (\frac {1}{9} \, x \log \left (x e^{\left (-x\right )}\right )^{2}\right )^{\frac {2}{x}}\right )}}{x^{2} \log \left (\frac {1}{9} \, x \log \left (x e^{\left (-x\right )}\right )^{2}\right ) \log \left (x e^{\left (-x\right )}\right )} \,d x } \] Input:

integrate(((-16*log(x/exp(x))*log(1/9*x*log(x/exp(x))^2)*log(log(1/9*x*log 
(x/exp(x))^2))+16*log(x/exp(x))-32*x+32)*exp(2*log(log(1/9*x*log(x/exp(x)) 
^2))/x)^2+(-16*log(x/exp(x))*log(1/9*x*log(x/exp(x))^2)*log(log(1/9*x*log( 
x/exp(x))^2))+16*log(x/exp(x))-32*x+32)*exp(2*log(log(1/9*x*log(x/exp(x))^ 
2))/x))/x^2/log(x/exp(x))/log(1/9*x*log(x/exp(x))^2),x, algorithm="giac")
 

Output:

integrate(-16*((log(1/9*x*log(x*e^(-x))^2)*log(x*e^(-x))*log(log(1/9*x*log 
(x*e^(-x))^2)) + 2*x - log(x*e^(-x)) - 2)*log(1/9*x*log(x*e^(-x))^2)^(4/x) 
 + (log(1/9*x*log(x*e^(-x))^2)*log(x*e^(-x))*log(log(1/9*x*log(x*e^(-x))^2 
)) + 2*x - log(x*e^(-x)) - 2)*log(1/9*x*log(x*e^(-x))^2)^(2/x))/(x^2*log(1 
/9*x*log(x*e^(-x))^2)*log(x*e^(-x))), x)
 

Mupad [B] (verification not implemented)

Time = 2.17 (sec) , antiderivative size = 58, normalized size of antiderivative = 1.93 \[ \int \frac {\log ^{\frac {2}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (32-32 x+16 \log \left (e^{-x} x\right )-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )\right )+\log ^{\frac {4}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (32-32 x+16 \log \left (e^{-x} x\right )-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )\right )}{x^2 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )} \, dx=4\,{\ln \left (\frac {x^3}{9}-\frac {2\,x^2\,\ln \left (x\right )}{9}+\frac {x\,{\ln \left (x\right )}^2}{9}\right )}^{2/x}\,\left ({\ln \left (\frac {x^3}{9}-\frac {2\,x^2\,\ln \left (x\right )}{9}+\frac {x\,{\ln \left (x\right )}^2}{9}\right )}^{2/x}+2\right ) \] Input:

int(-(exp((2*log(log((x*log(x*exp(-x))^2)/9)))/x)*(32*x - 16*log(x*exp(-x) 
) + 16*log((x*log(x*exp(-x))^2)/9)*log(x*exp(-x))*log(log((x*log(x*exp(-x) 
)^2)/9)) - 32) + exp((4*log(log((x*log(x*exp(-x))^2)/9)))/x)*(32*x - 16*lo 
g(x*exp(-x)) + 16*log((x*log(x*exp(-x))^2)/9)*log(x*exp(-x))*log(log((x*lo 
g(x*exp(-x))^2)/9)) - 32))/(x^2*log((x*log(x*exp(-x))^2)/9)*log(x*exp(-x)) 
),x)
 

Output:

4*log((x*log(x)^2)/9 - (2*x^2*log(x))/9 + x^3/9)^(2/x)*(log((x*log(x)^2)/9 
 - (2*x^2*log(x))/9 + x^3/9)^(2/x) + 2)
 

Reduce [B] (verification not implemented)

Time = 0.19 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.60 \[ \int \frac {\log ^{\frac {2}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (32-32 x+16 \log \left (e^{-x} x\right )-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )\right )+\log ^{\frac {4}{x}}\left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \left (32-32 x+16 \log \left (e^{-x} x\right )-16 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right ) \log \left (\log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )\right )\right )}{x^2 \log \left (e^{-x} x\right ) \log \left (\frac {1}{9} x \log ^2\left (e^{-x} x\right )\right )} \, dx=4 e^{\frac {2 \,\mathrm {log}\left (\mathrm {log}\left (\frac {\mathrm {log}\left (\frac {x}{e^{x}}\right )^{2} x}{9}\right )\right )}{x}} \left (e^{\frac {2 \,\mathrm {log}\left (\mathrm {log}\left (\frac {\mathrm {log}\left (\frac {x}{e^{x}}\right )^{2} x}{9}\right )\right )}{x}}+2\right ) \] Input:

int(((-16*log(x/exp(x))*log(1/9*x*log(x/exp(x))^2)*log(log(1/9*x*log(x/exp 
(x))^2))+16*log(x/exp(x))-32*x+32)*exp(2*log(log(1/9*x*log(x/exp(x))^2))/x 
)^2+(-16*log(x/exp(x))*log(1/9*x*log(x/exp(x))^2)*log(log(1/9*x*log(x/exp( 
x))^2))+16*log(x/exp(x))-32*x+32)*exp(2*log(log(1/9*x*log(x/exp(x))^2))/x) 
)/x^2/log(x/exp(x))/log(1/9*x*log(x/exp(x))^2),x)
 

Output:

4*e**((2*log(log((log(x/e**x)**2*x)/9)))/x)*(e**((2*log(log((log(x/e**x)** 
2*x)/9)))/x) + 2)