Integrand size = 98, antiderivative size = 26 \[ \int \frac {4^{\frac {1}{x}} \left (\frac {1}{1-4 x+6 x^2-4 x^3+x^4}\right )^{\frac {1}{x}} \left (-4 x-3 x^2-x^3+\left (1-x^2\right ) \log \left (\frac {4}{1-4 x+6 x^2-4 x^3+x^4}\right )\right )}{-2 x^2-2 x^3+2 x^4+2 x^5} \, dx=\frac {2^{-1+\frac {2}{x}} \left (\frac {1}{(1-x)^4}\right )^{\frac {1}{x}}}{1+x} \] Output:
1/2*exp(1/x*ln(4/(1-x)^4))/(1+x)
\[ \int \frac {4^{\frac {1}{x}} \left (\frac {1}{1-4 x+6 x^2-4 x^3+x^4}\right )^{\frac {1}{x}} \left (-4 x-3 x^2-x^3+\left (1-x^2\right ) \log \left (\frac {4}{1-4 x+6 x^2-4 x^3+x^4}\right )\right )}{-2 x^2-2 x^3+2 x^4+2 x^5} \, dx=\int \frac {4^{\frac {1}{x}} \left (\frac {1}{1-4 x+6 x^2-4 x^3+x^4}\right )^{\frac {1}{x}} \left (-4 x-3 x^2-x^3+\left (1-x^2\right ) \log \left (\frac {4}{1-4 x+6 x^2-4 x^3+x^4}\right )\right )}{-2 x^2-2 x^3+2 x^4+2 x^5} \, dx \] Input:
Integrate[(4^x^(-1)*((1 - 4*x + 6*x^2 - 4*x^3 + x^4)^(-1))^x^(-1)*(-4*x - 3*x^2 - x^3 + (1 - x^2)*Log[4/(1 - 4*x + 6*x^2 - 4*x^3 + x^4)]))/(-2*x^2 - 2*x^3 + 2*x^4 + 2*x^5),x]
Output:
Integrate[(4^x^(-1)*((1 - 4*x + 6*x^2 - 4*x^3 + x^4)^(-1))^x^(-1)*(-4*x - 3*x^2 - x^3 + (1 - x^2)*Log[4/(1 - 4*x + 6*x^2 - 4*x^3 + x^4)]))/(-2*x^2 - 2*x^3 + 2*x^4 + 2*x^5), x]
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {4^{\frac {1}{x}} \left (\frac {1}{x^4-4 x^3+6 x^2-4 x+1}\right )^{\frac {1}{x}} \left (-x^3-3 x^2+\left (1-x^2\right ) \log \left (\frac {4}{x^4-4 x^3+6 x^2-4 x+1}\right )-4 x\right )}{2 x^5+2 x^4-2 x^3-2 x^2} \, dx\) |
\(\Big \downarrow \) 2026 |
\(\displaystyle \int \frac {4^{\frac {1}{x}} \left (\frac {1}{x^4-4 x^3+6 x^2-4 x+1}\right )^{\frac {1}{x}} \left (-x^3-3 x^2+\left (1-x^2\right ) \log \left (\frac {4}{x^4-4 x^3+6 x^2-4 x+1}\right )-4 x\right )}{x^2 \left (2 x^3+2 x^2-2 x-2\right )}dx\) |
\(\Big \downarrow \) 2463 |
\(\displaystyle \int \left (\frac {4^{\frac {1}{x}-1} \left (\frac {1}{x^4-4 x^3+6 x^2-4 x+1}\right )^{\frac {1}{x}} \left (-x^3-3 x^2+\left (1-x^2\right ) \log \left (\frac {4}{x^4-4 x^3+6 x^2-4 x+1}\right )-4 x\right )}{x^2 \left (x^2-1\right )}-\frac {4^{\frac {1}{x}-1} \left (\frac {1}{x^4-4 x^3+6 x^2-4 x+1}\right )^{\frac {1}{x}} \left (-x^3-3 x^2+\left (1-x^2\right ) \log \left (\frac {4}{x^4-4 x^3+6 x^2-4 x+1}\right )-4 x\right )}{x^2 (x+1)^2}\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle -8 \int \frac {\int \frac {4^{\frac {1}{x}-1} \left (\frac {1}{(x-1)^4}\right )^{\frac {1}{x}}}{x^2}dx}{x-1}dx-2 \log \left (\frac {4}{(1-x)^4}\right ) \int \frac {4^{\frac {1}{x}-1} \left (\frac {1}{(x-1)^4}\right )^{\frac {1}{x}}}{x^2}dx+\int \frac {4^{\frac {1}{x}-1} \left (\frac {1}{(x-1)^4}\right )^{\frac {1}{x}}}{-x-1}dx-\int \frac {4^{\frac {1}{x}} \left (\frac {1}{(x-1)^4}\right )^{\frac {1}{x}}}{x-1}dx+2 \int \frac {4^{\frac {1}{x}} \left (\frac {1}{(x-1)^4}\right )^{\frac {1}{x}}}{x}dx-\int \frac {2^{\frac {2}{x}-1} \left (\frac {1}{(x-1)^4}\right )^{\frac {1}{x}}}{(x+1)^2}dx-3 \int \frac {4^{\frac {1}{x}-1} \left (\frac {1}{(x-1)^4}\right )^{\frac {1}{x}}}{x+1}dx+4 \int \frac {\int \frac {2^{\frac {2}{x}-1} \left (\frac {1}{(x-1)^4}\right )^{\frac {1}{x}}}{x}dx}{x-1}dx-4 \int \frac {\int \frac {2^{\frac {2}{x}-1} \left (\frac {1}{(x-1)^4}\right )^{\frac {1}{x}}}{x+1}dx}{x-1}dx+\log \left (\frac {4}{(1-x)^4}\right ) \int \frac {2^{\frac {2}{x}-1} \left (\frac {1}{(x-1)^4}\right )^{\frac {1}{x}}}{x}dx-\log \left (\frac {4}{(1-x)^4}\right ) \int \frac {2^{\frac {2}{x}-1} \left (\frac {1}{(x-1)^4}\right )^{\frac {1}{x}}}{x+1}dx\) |
Input:
Int[(4^x^(-1)*((1 - 4*x + 6*x^2 - 4*x^3 + x^4)^(-1))^x^(-1)*(-4*x - 3*x^2 - x^3 + (1 - x^2)*Log[4/(1 - 4*x + 6*x^2 - 4*x^3 + x^4)]))/(-2*x^2 - 2*x^3 + 2*x^4 + 2*x^5),x]
Output:
$Aborted
Time = 1.39 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.31
method | result | size |
risch | \(\frac {\left (\frac {4}{x^{4}-4 x^{3}+6 x^{2}-4 x +1}\right )^{\frac {1}{x}}}{2+2 x}\) | \(34\) |
parallelrisch | \(\frac {{\mathrm e}^{\frac {\ln \left (\frac {4}{x^{4}-4 x^{3}+6 x^{2}-4 x +1}\right )}{x}}}{2+2 x}\) | \(36\) |
Input:
int(((-x^2+1)*ln(4/(x^4-4*x^3+6*x^2-4*x+1))-x^3-3*x^2-4*x)*exp(ln(4/(x^4-4 *x^3+6*x^2-4*x+1))/x)/(2*x^5+2*x^4-2*x^3-2*x^2),x,method=_RETURNVERBOSE)
Output:
1/2/(1+x)*(4/(x^4-4*x^3+6*x^2-4*x+1))^(1/x)
Time = 0.07 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.27 \[ \int \frac {4^{\frac {1}{x}} \left (\frac {1}{1-4 x+6 x^2-4 x^3+x^4}\right )^{\frac {1}{x}} \left (-4 x-3 x^2-x^3+\left (1-x^2\right ) \log \left (\frac {4}{1-4 x+6 x^2-4 x^3+x^4}\right )\right )}{-2 x^2-2 x^3+2 x^4+2 x^5} \, dx=\frac {\left (\frac {4}{x^{4} - 4 \, x^{3} + 6 \, x^{2} - 4 \, x + 1}\right )^{\left (\frac {1}{x}\right )}}{2 \, {\left (x + 1\right )}} \] Input:
integrate(((-x^2+1)*log(4/(x^4-4*x^3+6*x^2-4*x+1))-x^3-3*x^2-4*x)*exp(log( 4/(x^4-4*x^3+6*x^2-4*x+1))/x)/(2*x^5+2*x^4-2*x^3-2*x^2),x, algorithm="fric as")
Output:
1/2*(4/(x^4 - 4*x^3 + 6*x^2 - 4*x + 1))^(1/x)/(x + 1)
Time = 0.13 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.12 \[ \int \frac {4^{\frac {1}{x}} \left (\frac {1}{1-4 x+6 x^2-4 x^3+x^4}\right )^{\frac {1}{x}} \left (-4 x-3 x^2-x^3+\left (1-x^2\right ) \log \left (\frac {4}{1-4 x+6 x^2-4 x^3+x^4}\right )\right )}{-2 x^2-2 x^3+2 x^4+2 x^5} \, dx=\frac {e^{\frac {\log {\left (\frac {4}{x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1} \right )}}{x}}}{2 x + 2} \] Input:
integrate(((-x**2+1)*ln(4/(x**4-4*x**3+6*x**2-4*x+1))-x**3-3*x**2-4*x)*exp (ln(4/(x**4-4*x**3+6*x**2-4*x+1))/x)/(2*x**5+2*x**4-2*x**3-2*x**2),x)
Output:
exp(log(4/(x**4 - 4*x**3 + 6*x**2 - 4*x + 1))/x)/(2*x + 2)
Time = 0.16 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.96 \[ \int \frac {4^{\frac {1}{x}} \left (\frac {1}{1-4 x+6 x^2-4 x^3+x^4}\right )^{\frac {1}{x}} \left (-4 x-3 x^2-x^3+\left (1-x^2\right ) \log \left (\frac {4}{1-4 x+6 x^2-4 x^3+x^4}\right )\right )}{-2 x^2-2 x^3+2 x^4+2 x^5} \, dx=\frac {e^{\left (\frac {2 \, \log \left (2\right )}{x} - \frac {4 \, \log \left (x - 1\right )}{x}\right )}}{2 \, {\left (x + 1\right )}} \] Input:
integrate(((-x^2+1)*log(4/(x^4-4*x^3+6*x^2-4*x+1))-x^3-3*x^2-4*x)*exp(log( 4/(x^4-4*x^3+6*x^2-4*x+1))/x)/(2*x^5+2*x^4-2*x^3-2*x^2),x, algorithm="maxi ma")
Output:
1/2*e^(2*log(2)/x - 4*log(x - 1)/x)/(x + 1)
\[ \int \frac {4^{\frac {1}{x}} \left (\frac {1}{1-4 x+6 x^2-4 x^3+x^4}\right )^{\frac {1}{x}} \left (-4 x-3 x^2-x^3+\left (1-x^2\right ) \log \left (\frac {4}{1-4 x+6 x^2-4 x^3+x^4}\right )\right )}{-2 x^2-2 x^3+2 x^4+2 x^5} \, dx=\int { -\frac {{\left (x^{3} + 3 \, x^{2} + {\left (x^{2} - 1\right )} \log \left (\frac {4}{x^{4} - 4 \, x^{3} + 6 \, x^{2} - 4 \, x + 1}\right ) + 4 \, x\right )} \left (\frac {4}{x^{4} - 4 \, x^{3} + 6 \, x^{2} - 4 \, x + 1}\right )^{\left (\frac {1}{x}\right )}}{2 \, {\left (x^{5} + x^{4} - x^{3} - x^{2}\right )}} \,d x } \] Input:
integrate(((-x^2+1)*log(4/(x^4-4*x^3+6*x^2-4*x+1))-x^3-3*x^2-4*x)*exp(log( 4/(x^4-4*x^3+6*x^2-4*x+1))/x)/(2*x^5+2*x^4-2*x^3-2*x^2),x, algorithm="giac ")
Output:
integrate(-1/2*(x^3 + 3*x^2 + (x^2 - 1)*log(4/(x^4 - 4*x^3 + 6*x^2 - 4*x + 1)) + 4*x)*(4/(x^4 - 4*x^3 + 6*x^2 - 4*x + 1))^(1/x)/(x^5 + x^4 - x^3 - x ^2), x)
Time = 0.72 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.31 \[ \int \frac {4^{\frac {1}{x}} \left (\frac {1}{1-4 x+6 x^2-4 x^3+x^4}\right )^{\frac {1}{x}} \left (-4 x-3 x^2-x^3+\left (1-x^2\right ) \log \left (\frac {4}{1-4 x+6 x^2-4 x^3+x^4}\right )\right )}{-2 x^2-2 x^3+2 x^4+2 x^5} \, dx=\frac {{\left (\frac {4}{x^4-4\,x^3+6\,x^2-4\,x+1}\right )}^{1/x}}{2\,\left (x+1\right )} \] Input:
int((exp(log(4/(6*x^2 - 4*x - 4*x^3 + x^4 + 1))/x)*(4*x + log(4/(6*x^2 - 4 *x - 4*x^3 + x^4 + 1))*(x^2 - 1) + 3*x^2 + x^3))/(2*x^2 + 2*x^3 - 2*x^4 - 2*x^5),x)
Output:
(4/(6*x^2 - 4*x - 4*x^3 + x^4 + 1))^(1/x)/(2*(x + 1))
Time = 0.22 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.42 \[ \int \frac {4^{\frac {1}{x}} \left (\frac {1}{1-4 x+6 x^2-4 x^3+x^4}\right )^{\frac {1}{x}} \left (-4 x-3 x^2-x^3+\left (1-x^2\right ) \log \left (\frac {4}{1-4 x+6 x^2-4 x^3+x^4}\right )\right )}{-2 x^2-2 x^3+2 x^4+2 x^5} \, dx=\frac {e^{\frac {\mathrm {log}\left (\frac {4}{x^{4}-4 x^{3}+6 x^{2}-4 x +1}\right )}{x}}}{2 x +2} \] Input:
int(((-x^2+1)*log(4/(x^4-4*x^3+6*x^2-4*x+1))-x^3-3*x^2-4*x)*exp(log(4/(x^4 -4*x^3+6*x^2-4*x+1))/x)/(2*x^5+2*x^4-2*x^3-2*x^2),x)
Output:
e**(log(4/(x**4 - 4*x**3 + 6*x**2 - 4*x + 1))/x)/(2*(x + 1))