Integrand size = 107, antiderivative size = 21 \[ \int \frac {8-2 x+\left ((8-4 x) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+(4-2 x) \log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )\right ) \log \left (\frac {2+\log (3) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )}{\log \left (\log \left (\frac {1}{\log (x)}\right )\right )}\right )}{2 \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+\log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )} \, dx=(4-x) x \log \left (\log (3)+\frac {2}{\log \left (\log \left (\frac {1}{\log (x)}\right )\right )}\right ) \] Output:
x*ln(2/ln(ln(1/ln(x)))+ln(3))*(4-x)
Time = 0.36 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.95 \[ \int \frac {8-2 x+\left ((8-4 x) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+(4-2 x) \log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )\right ) \log \left (\frac {2+\log (3) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )}{\log \left (\log \left (\frac {1}{\log (x)}\right )\right )}\right )}{2 \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+\log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )} \, dx=-\left ((-4+x) x \log \left (\log (3)+\frac {2}{\log \left (\log \left (\frac {1}{\log (x)}\right )\right )}\right )\right ) \] Input:
Integrate[(8 - 2*x + ((8 - 4*x)*Log[x]*Log[Log[x]^(-1)]*Log[Log[Log[x]^(-1 )]] + (4 - 2*x)*Log[3]*Log[x]*Log[Log[x]^(-1)]*Log[Log[Log[x]^(-1)]]^2)*Lo g[(2 + Log[3]*Log[Log[Log[x]^(-1)]])/Log[Log[Log[x]^(-1)]]])/(2*Log[x]*Log [Log[x]^(-1)]*Log[Log[Log[x]^(-1)]] + Log[3]*Log[x]*Log[Log[x]^(-1)]*Log[L og[Log[x]^(-1)]]^2),x]
Output:
-((-4 + x)*x*Log[Log[3] + 2/Log[Log[Log[x]^(-1)]]])
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {-2 x+\left ((4-2 x) \log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )+(8-4 x) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )\right ) \log \left (\frac {\log (3) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+2}{\log \left (\log \left (\frac {1}{\log (x)}\right )\right )}\right )+8}{\log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )+2 \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )} \, dx\) |
\(\Big \downarrow \) 7292 |
\(\displaystyle \int \frac {-2 x+\left ((4-2 x) \log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )+(8-4 x) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )\right ) \log \left (\frac {\log (3) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+2}{\log \left (\log \left (\frac {1}{\log (x)}\right )\right )}\right )+8}{\log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right ) \left (\log (3) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+2\right )}dx\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle \int \left (-\frac {2 (x-4)}{\log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right ) \left (\log (3) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+2\right )}-2 (x-2) \log \left (\frac {2}{\log \left (\log \left (\frac {1}{\log (x)}\right )\right )}+\log (3)\right )\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle 4 \int \frac {1}{\log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )}dx-\int \frac {x}{\log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )}dx-4 \log (3) \int \frac {1}{\log (x) \log \left (\frac {1}{\log (x)}\right ) \left (\log (3) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+2\right )}dx+\log (3) \int \frac {x}{\log (x) \log \left (\frac {1}{\log (x)}\right ) \left (\log (3) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+2\right )}dx+4 \int \log \left (\log (3)+\frac {2}{\log \left (\log \left (\frac {1}{\log (x)}\right )\right )}\right )dx-2 \int x \log \left (\log (3)+\frac {2}{\log \left (\log \left (\frac {1}{\log (x)}\right )\right )}\right )dx\) |
Input:
Int[(8 - 2*x + ((8 - 4*x)*Log[x]*Log[Log[x]^(-1)]*Log[Log[Log[x]^(-1)]] + (4 - 2*x)*Log[3]*Log[x]*Log[Log[x]^(-1)]*Log[Log[Log[x]^(-1)]]^2)*Log[(2 + Log[3]*Log[Log[Log[x]^(-1)]])/Log[Log[Log[x]^(-1)]]])/(2*Log[x]*Log[Log[x ]^(-1)]*Log[Log[Log[x]^(-1)]] + Log[3]*Log[x]*Log[Log[x]^(-1)]*Log[Log[Log [x]^(-1)]]^2),x]
Output:
$Aborted
Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 0.24 (sec) , antiderivative size = 397, normalized size of antiderivative = 18.90
\[\left (-x^{2}+4 x \right ) \ln \left (\ln \left (3\right ) \ln \left (-\ln \left (\ln \left (x \right )\right )\right )+2\right )+x^{2} \ln \left (\ln \left (-\ln \left (\ln \left (x \right )\right )\right )\right )-4 x \ln \left (\ln \left (-\ln \left (\ln \left (x \right )\right )\right )\right )+\frac {i \pi \,x^{2} \operatorname {csgn}\left (i \left (\ln \left (3\right ) \ln \left (-\ln \left (\ln \left (x \right )\right )\right )+2\right )\right ) \operatorname {csgn}\left (\frac {i}{\ln \left (-\ln \left (\ln \left (x \right )\right )\right )}\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (3\right ) \ln \left (-\ln \left (\ln \left (x \right )\right )\right )+2\right )}{\ln \left (-\ln \left (\ln \left (x \right )\right )\right )}\right )}{2}-\frac {i \pi \,x^{2} \operatorname {csgn}\left (i \left (\ln \left (3\right ) \ln \left (-\ln \left (\ln \left (x \right )\right )\right )+2\right )\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (3\right ) \ln \left (-\ln \left (\ln \left (x \right )\right )\right )+2\right )}{\ln \left (-\ln \left (\ln \left (x \right )\right )\right )}\right )^{2}}{2}-\frac {i \pi \,x^{2} \operatorname {csgn}\left (\frac {i}{\ln \left (-\ln \left (\ln \left (x \right )\right )\right )}\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (3\right ) \ln \left (-\ln \left (\ln \left (x \right )\right )\right )+2\right )}{\ln \left (-\ln \left (\ln \left (x \right )\right )\right )}\right )^{2}}{2}+\frac {i \pi \,x^{2} \operatorname {csgn}\left (\frac {i \left (\ln \left (3\right ) \ln \left (-\ln \left (\ln \left (x \right )\right )\right )+2\right )}{\ln \left (-\ln \left (\ln \left (x \right )\right )\right )}\right )^{3}}{2}-2 i \pi x \,\operatorname {csgn}\left (i \left (\ln \left (3\right ) \ln \left (-\ln \left (\ln \left (x \right )\right )\right )+2\right )\right ) \operatorname {csgn}\left (\frac {i}{\ln \left (-\ln \left (\ln \left (x \right )\right )\right )}\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (3\right ) \ln \left (-\ln \left (\ln \left (x \right )\right )\right )+2\right )}{\ln \left (-\ln \left (\ln \left (x \right )\right )\right )}\right )+2 i \pi x \,\operatorname {csgn}\left (i \left (\ln \left (3\right ) \ln \left (-\ln \left (\ln \left (x \right )\right )\right )+2\right )\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (3\right ) \ln \left (-\ln \left (\ln \left (x \right )\right )\right )+2\right )}{\ln \left (-\ln \left (\ln \left (x \right )\right )\right )}\right )^{2}+2 i \pi x \,\operatorname {csgn}\left (\frac {i}{\ln \left (-\ln \left (\ln \left (x \right )\right )\right )}\right ) \operatorname {csgn}\left (\frac {i \left (\ln \left (3\right ) \ln \left (-\ln \left (\ln \left (x \right )\right )\right )+2\right )}{\ln \left (-\ln \left (\ln \left (x \right )\right )\right )}\right )^{2}-2 i \pi x \operatorname {csgn}\left (\frac {i \left (\ln \left (3\right ) \ln \left (-\ln \left (\ln \left (x \right )\right )\right )+2\right )}{\ln \left (-\ln \left (\ln \left (x \right )\right )\right )}\right )^{3}\]
Input:
int((((4-2*x)*ln(3)*ln(x)*ln(1/ln(x))*ln(ln(1/ln(x)))^2+(-4*x+8)*ln(x)*ln( 1/ln(x))*ln(ln(1/ln(x))))*ln((ln(3)*ln(ln(1/ln(x)))+2)/ln(ln(1/ln(x))))-2* x+8)/(ln(3)*ln(x)*ln(1/ln(x))*ln(ln(1/ln(x)))^2+2*ln(x)*ln(1/ln(x))*ln(ln( 1/ln(x)))),x)
Output:
(-x^2+4*x)*ln(ln(3)*ln(-ln(ln(x)))+2)+x^2*ln(ln(-ln(ln(x))))-4*x*ln(ln(-ln (ln(x))))+1/2*I*Pi*x^2*csgn(I*(ln(3)*ln(-ln(ln(x)))+2))*csgn(I/ln(-ln(ln(x ))))*csgn(I/ln(-ln(ln(x)))*(ln(3)*ln(-ln(ln(x)))+2))-1/2*I*Pi*x^2*csgn(I*( ln(3)*ln(-ln(ln(x)))+2))*csgn(I/ln(-ln(ln(x)))*(ln(3)*ln(-ln(ln(x)))+2))^2 -1/2*I*Pi*x^2*csgn(I/ln(-ln(ln(x))))*csgn(I/ln(-ln(ln(x)))*(ln(3)*ln(-ln(l n(x)))+2))^2+1/2*I*Pi*x^2*csgn(I/ln(-ln(ln(x)))*(ln(3)*ln(-ln(ln(x)))+2))^ 3-2*I*Pi*x*csgn(I*(ln(3)*ln(-ln(ln(x)))+2))*csgn(I/ln(-ln(ln(x))))*csgn(I/ ln(-ln(ln(x)))*(ln(3)*ln(-ln(ln(x)))+2))+2*I*Pi*x*csgn(I*(ln(3)*ln(-ln(ln( x)))+2))*csgn(I/ln(-ln(ln(x)))*(ln(3)*ln(-ln(ln(x)))+2))^2+2*I*Pi*x*csgn(I /ln(-ln(ln(x))))*csgn(I/ln(-ln(ln(x)))*(ln(3)*ln(-ln(ln(x)))+2))^2-2*I*Pi* x*csgn(I/ln(-ln(ln(x)))*(ln(3)*ln(-ln(ln(x)))+2))^3
Time = 0.12 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.43 \[ \int \frac {8-2 x+\left ((8-4 x) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+(4-2 x) \log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )\right ) \log \left (\frac {2+\log (3) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )}{\log \left (\log \left (\frac {1}{\log (x)}\right )\right )}\right )}{2 \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+\log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )} \, dx=-{\left (x^{2} - 4 \, x\right )} \log \left (\frac {\log \left (3\right ) \log \left (\log \left (\frac {1}{\log \left (x\right )}\right )\right ) + 2}{\log \left (\log \left (\frac {1}{\log \left (x\right )}\right )\right )}\right ) \] Input:
integrate((((4-2*x)*log(3)*log(x)*log(1/log(x))*log(log(1/log(x)))^2+(-4*x +8)*log(x)*log(1/log(x))*log(log(1/log(x))))*log((log(3)*log(log(1/log(x)) )+2)/log(log(1/log(x))))-2*x+8)/(log(3)*log(x)*log(1/log(x))*log(log(1/log (x)))^2+2*log(x)*log(1/log(x))*log(log(1/log(x)))),x, algorithm="fricas")
Output:
-(x^2 - 4*x)*log((log(3)*log(log(1/log(x))) + 2)/log(log(1/log(x))))
Time = 1.09 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.38 \[ \int \frac {8-2 x+\left ((8-4 x) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+(4-2 x) \log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )\right ) \log \left (\frac {2+\log (3) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )}{\log \left (\log \left (\frac {1}{\log (x)}\right )\right )}\right )}{2 \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+\log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )} \, dx=\left (- x^{2} + 4 x\right ) \log {\left (\frac {\log {\left (3 \right )} \log {\left (\log {\left (\frac {1}{\log {\left (x \right )}} \right )} \right )} + 2}{\log {\left (\log {\left (\frac {1}{\log {\left (x \right )}} \right )} \right )}} \right )} \] Input:
integrate((((4-2*x)*ln(3)*ln(x)*ln(1/ln(x))*ln(ln(1/ln(x)))**2+(-4*x+8)*ln (x)*ln(1/ln(x))*ln(ln(1/ln(x))))*ln((ln(3)*ln(ln(1/ln(x)))+2)/ln(ln(1/ln(x ))))-2*x+8)/(ln(3)*ln(x)*ln(1/ln(x))*ln(ln(1/ln(x)))**2+2*ln(x)*ln(1/ln(x) )*ln(ln(1/ln(x)))),x)
Output:
(-x**2 + 4*x)*log((log(3)*log(log(1/log(x))) + 2)/log(log(1/log(x))))
Time = 0.18 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.76 \[ \int \frac {8-2 x+\left ((8-4 x) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+(4-2 x) \log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )\right ) \log \left (\frac {2+\log (3) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )}{\log \left (\log \left (\frac {1}{\log (x)}\right )\right )}\right )}{2 \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+\log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )} \, dx=-{\left (x^{2} - 4 \, x\right )} \log \left (\log \left (3\right ) \log \left (-\log \left (\log \left (x\right )\right )\right ) + 2\right ) + {\left (x^{2} - 4 \, x\right )} \log \left (\log \left (-\log \left (\log \left (x\right )\right )\right )\right ) \] Input:
integrate((((4-2*x)*log(3)*log(x)*log(1/log(x))*log(log(1/log(x)))^2+(-4*x +8)*log(x)*log(1/log(x))*log(log(1/log(x))))*log((log(3)*log(log(1/log(x)) )+2)/log(log(1/log(x))))-2*x+8)/(log(3)*log(x)*log(1/log(x))*log(log(1/log (x)))^2+2*log(x)*log(1/log(x))*log(log(1/log(x)))),x, algorithm="maxima")
Output:
-(x^2 - 4*x)*log(log(3)*log(-log(log(x))) + 2) + (x^2 - 4*x)*log(log(-log( log(x))))
Leaf count of result is larger than twice the leaf count of optimal. 54 vs. \(2 (20) = 40\).
Time = 1.10 (sec) , antiderivative size = 54, normalized size of antiderivative = 2.57 \[ \int \frac {8-2 x+\left ((8-4 x) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+(4-2 x) \log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )\right ) \log \left (\frac {2+\log (3) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )}{\log \left (\log \left (\frac {1}{\log (x)}\right )\right )}\right )}{2 \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+\log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )} \, dx=-x^{2} \log \left (\log \left (3\right ) \log \left (-\log \left (\log \left (x\right )\right )\right ) + 2\right ) + x^{2} \log \left (\log \left (-\log \left (\log \left (x\right )\right )\right )\right ) + 4 \, x \log \left (\log \left (3\right ) \log \left (-\log \left (\log \left (x\right )\right )\right ) + 2\right ) - 4 \, x \log \left (\log \left (-\log \left (\log \left (x\right )\right )\right )\right ) \] Input:
integrate((((4-2*x)*log(3)*log(x)*log(1/log(x))*log(log(1/log(x)))^2+(-4*x +8)*log(x)*log(1/log(x))*log(log(1/log(x))))*log((log(3)*log(log(1/log(x)) )+2)/log(log(1/log(x))))-2*x+8)/(log(3)*log(x)*log(1/log(x))*log(log(1/log (x)))^2+2*log(x)*log(1/log(x))*log(log(1/log(x)))),x, algorithm="giac")
Output:
-x^2*log(log(3)*log(-log(log(x))) + 2) + x^2*log(log(-log(log(x)))) + 4*x* log(log(3)*log(-log(log(x))) + 2) - 4*x*log(log(-log(log(x))))
Time = 3.96 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.29 \[ \int \frac {8-2 x+\left ((8-4 x) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+(4-2 x) \log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )\right ) \log \left (\frac {2+\log (3) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )}{\log \left (\log \left (\frac {1}{\log (x)}\right )\right )}\right )}{2 \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+\log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )} \, dx=-x\,\ln \left (\frac {\ln \left (\ln \left (\frac {1}{\ln \left (x\right )}\right )\right )\,\ln \left (3\right )+2}{\ln \left (\ln \left (\frac {1}{\ln \left (x\right )}\right )\right )}\right )\,\left (x-4\right ) \] Input:
int(-(2*x + log((log(log(1/log(x)))*log(3) + 2)/log(log(1/log(x))))*(log(l og(1/log(x)))*log(1/log(x))*log(x)*(4*x - 8) + log(log(1/log(x)))^2*log(3) *log(1/log(x))*log(x)*(2*x - 4)) - 8)/(2*log(log(1/log(x)))*log(1/log(x))* log(x) + log(log(1/log(x)))^2*log(3)*log(1/log(x))*log(x)),x)
Output:
-x*log((log(log(1/log(x)))*log(3) + 2)/log(log(1/log(x))))*(x - 4)
Time = 0.24 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.33 \[ \int \frac {8-2 x+\left ((8-4 x) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+(4-2 x) \log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )\right ) \log \left (\frac {2+\log (3) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )}{\log \left (\log \left (\frac {1}{\log (x)}\right )\right )}\right )}{2 \log (x) \log \left (\frac {1}{\log (x)}\right ) \log \left (\log \left (\frac {1}{\log (x)}\right )\right )+\log (3) \log (x) \log \left (\frac {1}{\log (x)}\right ) \log ^2\left (\log \left (\frac {1}{\log (x)}\right )\right )} \, dx=\mathrm {log}\left (\frac {\mathrm {log}\left (-\mathrm {log}\left (\mathrm {log}\left (x \right )\right )\right ) \mathrm {log}\left (3\right )+2}{\mathrm {log}\left (-\mathrm {log}\left (\mathrm {log}\left (x \right )\right )\right )}\right ) x \left (-x +4\right ) \] Input:
int((((4-2*x)*log(3)*log(x)*log(1/log(x))*log(log(1/log(x)))^2+(-4*x+8)*lo g(x)*log(1/log(x))*log(log(1/log(x))))*log((log(3)*log(log(1/log(x)))+2)/l og(log(1/log(x))))-2*x+8)/(log(3)*log(x)*log(1/log(x))*log(log(1/log(x)))^ 2+2*log(x)*log(1/log(x))*log(log(1/log(x)))),x)
Output:
log((log( - log(log(x)))*log(3) + 2)/log( - log(log(x))))*x*( - x + 4)