Integrand size = 125, antiderivative size = 45 \[ \int \frac {5^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} e^{-x} x^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} \left (-900 x+20000 x^3+20000 x^4+\left (-1800 x+900 x^2-40000 x^4-20000 x^5\right ) \log (5 x)\right )}{81-3600 x^2-3600 x^3+40000 x^4+80000 x^5+40000 x^6} \, dx=5^{\frac {e^{-x}}{2-\frac {9}{100 x^2}+2 x}} x^{\frac {e^{-x}}{2-\frac {9}{100 x^2}+2 x}} \] Output:
exp(ln(5*x)/exp(x)/(2*x+2-9/100/x^2))
\[ \int \frac {5^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} e^{-x} x^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} \left (-900 x+20000 x^3+20000 x^4+\left (-1800 x+900 x^2-40000 x^4-20000 x^5\right ) \log (5 x)\right )}{81-3600 x^2-3600 x^3+40000 x^4+80000 x^5+40000 x^6} \, dx=\int \frac {5^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} e^{-x} x^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} \left (-900 x+20000 x^3+20000 x^4+\left (-1800 x+900 x^2-40000 x^4-20000 x^5\right ) \log (5 x)\right )}{81-3600 x^2-3600 x^3+40000 x^4+80000 x^5+40000 x^6} \, dx \] Input:
Integrate[(5^((100*x^2)/(E^x*(-9 + 200*x^2 + 200*x^3)))*x^((100*x^2)/(E^x* (-9 + 200*x^2 + 200*x^3)))*(-900*x + 20000*x^3 + 20000*x^4 + (-1800*x + 90 0*x^2 - 40000*x^4 - 20000*x^5)*Log[5*x]))/(E^x*(81 - 3600*x^2 - 3600*x^3 + 40000*x^4 + 80000*x^5 + 40000*x^6)),x]
Output:
Integrate[(5^((100*x^2)/(E^x*(-9 + 200*x^2 + 200*x^3)))*x^((100*x^2)/(E^x* (-9 + 200*x^2 + 200*x^3)))*(-900*x + 20000*x^3 + 20000*x^4 + (-1800*x + 90 0*x^2 - 40000*x^4 - 20000*x^5)*Log[5*x]))/(E^x*(81 - 3600*x^2 - 3600*x^3 + 40000*x^4 + 80000*x^5 + 40000*x^6)), x]
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {5^{\frac {100 e^{-x} x^2}{200 x^3+200 x^2-9}} e^{-x} x^{\frac {100 e^{-x} x^2}{200 x^3+200 x^2-9}} \left (20000 x^4+20000 x^3+\left (-20000 x^5-40000 x^4+900 x^2-1800 x\right ) \log (5 x)-900 x\right )}{40000 x^6+80000 x^5+40000 x^4-3600 x^3-3600 x^2+81} \, dx\) |
\(\Big \downarrow \) 2463 |
\(\displaystyle \int \frac {5^{\frac {100 e^{-x} x^2}{200 x^3+200 x^2-9}} e^{-x} x^{\frac {100 e^{-x} x^2}{200 x^3+200 x^2-9}} \left (20000 x^4+20000 x^3+\left (-20000 x^5-40000 x^4+900 x^2-1800 x\right ) \log (5 x)-900 x\right )}{\left (200 x^3+200 x^2-9\right )^2}dx\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle \int \left (\frac {4\ 5^{\frac {100 e^{-x} x^2}{200 x^3+200 x^2-9}+2} e^{-x} x^{\frac {100 e^{-x} x^2}{200 x^3+200 x^2-9}+1}}{200 x^3+200 x^2-9}-\frac {4\ 5^{\frac {100 e^{-x} x^2}{200 x^3+200 x^2-9}+2} e^{-x} x^{\frac {100 e^{-x} x^2}{200 x^3+200 x^2-9}+1} \left (200 x^4+400 x^3-9 x+18\right ) \log (5 x)}{\left (200 x^3+200 x^2-9\right )^2}\right )dx\) |
\(\Big \downarrow \) 7299 |
\(\displaystyle \int \left (\frac {4\ 5^{\frac {100 e^{-x} x^2}{200 x^3+200 x^2-9}+2} e^{-x} x^{\frac {100 e^{-x} x^2}{200 x^3+200 x^2-9}+1}}{200 x^3+200 x^2-9}-\frac {4\ 5^{\frac {100 e^{-x} x^2}{200 x^3+200 x^2-9}+2} e^{-x} x^{\frac {100 e^{-x} x^2}{200 x^3+200 x^2-9}+1} \left (200 x^4+400 x^3-9 x+18\right ) \log (5 x)}{\left (200 x^3+200 x^2-9\right )^2}\right )dx\) |
Input:
Int[(5^((100*x^2)/(E^x*(-9 + 200*x^2 + 200*x^3)))*x^((100*x^2)/(E^x*(-9 + 200*x^2 + 200*x^3)))*(-900*x + 20000*x^3 + 20000*x^4 + (-1800*x + 900*x^2 - 40000*x^4 - 20000*x^5)*Log[5*x]))/(E^x*(81 - 3600*x^2 - 3600*x^3 + 40000 *x^4 + 80000*x^5 + 40000*x^6)),x]
Output:
$Aborted
Time = 299.98 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.62
method | result | size |
risch | \(\left (5 x \right )^{\frac {100 x^{2} {\mathrm e}^{-x}}{200 x^{3}+200 x^{2}-9}}\) | \(28\) |
parallelrisch | \({\mathrm e}^{\frac {100 x^{2} \ln \left (5 x \right ) {\mathrm e}^{-x}}{200 x^{3}+200 x^{2}-9}}\) | \(29\) |
Input:
int(((-20000*x^5-40000*x^4+900*x^2-1800*x)*ln(5*x)+20000*x^4+20000*x^3-900 *x)*exp(100*x^2*ln(5*x)/(200*x^3+200*x^2-9)/exp(x))/(40000*x^6+80000*x^5+4 0000*x^4-3600*x^3-3600*x^2+81)/exp(x),x,method=_RETURNVERBOSE)
Output:
(5*x)^(100*x^2/(200*x^3+200*x^2-9)*exp(-x))
Time = 0.09 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.60 \[ \int \frac {5^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} e^{-x} x^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} \left (-900 x+20000 x^3+20000 x^4+\left (-1800 x+900 x^2-40000 x^4-20000 x^5\right ) \log (5 x)\right )}{81-3600 x^2-3600 x^3+40000 x^4+80000 x^5+40000 x^6} \, dx=\left (5 \, x\right )^{\frac {100 \, x^{2} e^{\left (-x\right )}}{200 \, x^{3} + 200 \, x^{2} - 9}} \] Input:
integrate(((-20000*x^5-40000*x^4+900*x^2-1800*x)*log(5*x)+20000*x^4+20000* x^3-900*x)*exp(100*x^2*log(5*x)/(200*x^3+200*x^2-9)/exp(x))/(40000*x^6+800 00*x^5+40000*x^4-3600*x^3-3600*x^2+81)/exp(x),x, algorithm="fricas")
Output:
(5*x)^(100*x^2*e^(-x)/(200*x^3 + 200*x^2 - 9))
Time = 0.45 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.58 \[ \int \frac {5^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} e^{-x} x^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} \left (-900 x+20000 x^3+20000 x^4+\left (-1800 x+900 x^2-40000 x^4-20000 x^5\right ) \log (5 x)\right )}{81-3600 x^2-3600 x^3+40000 x^4+80000 x^5+40000 x^6} \, dx=e^{\frac {100 x^{2} e^{- x} \log {\left (5 x \right )}}{200 x^{3} + 200 x^{2} - 9}} \] Input:
integrate(((-20000*x**5-40000*x**4+900*x**2-1800*x)*ln(5*x)+20000*x**4+200 00*x**3-900*x)*exp(100*x**2*ln(5*x)/(200*x**3+200*x**2-9)/exp(x))/(40000*x **6+80000*x**5+40000*x**4-3600*x**3-3600*x**2+81)/exp(x),x)
Output:
exp(100*x**2*exp(-x)*log(5*x)/(200*x**3 + 200*x**2 - 9))
Leaf count of result is larger than twice the leaf count of optimal. 52 vs. \(2 (22) = 44\).
Time = 0.26 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.16 \[ \int \frac {5^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} e^{-x} x^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} \left (-900 x+20000 x^3+20000 x^4+\left (-1800 x+900 x^2-40000 x^4-20000 x^5\right ) \log (5 x)\right )}{81-3600 x^2-3600 x^3+40000 x^4+80000 x^5+40000 x^6} \, dx=e^{\left (\frac {100 \, x^{2} e^{\left (-x\right )} \log \left (5\right )}{200 \, x^{3} + 200 \, x^{2} - 9} + \frac {100 \, x^{2} e^{\left (-x\right )} \log \left (x\right )}{200 \, x^{3} + 200 \, x^{2} - 9}\right )} \] Input:
integrate(((-20000*x^5-40000*x^4+900*x^2-1800*x)*log(5*x)+20000*x^4+20000* x^3-900*x)*exp(100*x^2*log(5*x)/(200*x^3+200*x^2-9)/exp(x))/(40000*x^6+800 00*x^5+40000*x^4-3600*x^3-3600*x^2+81)/exp(x),x, algorithm="maxima")
Output:
e^(100*x^2*e^(-x)*log(5)/(200*x^3 + 200*x^2 - 9) + 100*x^2*e^(-x)*log(x)/( 200*x^3 + 200*x^2 - 9))
Time = 2.87 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.60 \[ \int \frac {5^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} e^{-x} x^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} \left (-900 x+20000 x^3+20000 x^4+\left (-1800 x+900 x^2-40000 x^4-20000 x^5\right ) \log (5 x)\right )}{81-3600 x^2-3600 x^3+40000 x^4+80000 x^5+40000 x^6} \, dx=\left (5 \, x\right )^{\frac {100 \, x^{2} e^{\left (-x\right )}}{200 \, x^{3} + 200 \, x^{2} - 9}} \] Input:
integrate(((-20000*x^5-40000*x^4+900*x^2-1800*x)*log(5*x)+20000*x^4+20000* x^3-900*x)*exp(100*x^2*log(5*x)/(200*x^3+200*x^2-9)/exp(x))/(40000*x^6+800 00*x^5+40000*x^4-3600*x^3-3600*x^2+81)/exp(x),x, algorithm="giac")
Output:
(5*x)^(100*x^2*e^(-x)/(200*x^3 + 200*x^2 - 9))
Time = 3.61 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.13 \[ \int \frac {5^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} e^{-x} x^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} \left (-900 x+20000 x^3+20000 x^4+\left (-1800 x+900 x^2-40000 x^4-20000 x^5\right ) \log (5 x)\right )}{81-3600 x^2-3600 x^3+40000 x^4+80000 x^5+40000 x^6} \, dx=5^{\frac {100\,x^2\,{\mathrm {e}}^{-x}}{200\,x^3+200\,x^2-9}}\,x^{\frac {100\,x^2\,{\mathrm {e}}^{-x}}{200\,x^3+200\,x^2-9}} \] Input:
int(-(exp(-x)*exp((100*x^2*log(5*x)*exp(-x))/(200*x^2 + 200*x^3 - 9))*(900 *x + log(5*x)*(1800*x - 900*x^2 + 40000*x^4 + 20000*x^5) - 20000*x^3 - 200 00*x^4))/(40000*x^4 - 3600*x^3 - 3600*x^2 + 80000*x^5 + 40000*x^6 + 81),x)
Output:
5^((100*x^2*exp(-x))/(200*x^2 + 200*x^3 - 9))*x^((100*x^2*exp(-x))/(200*x^ 2 + 200*x^3 - 9))
Time = 0.16 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.78 \[ \int \frac {5^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} e^{-x} x^{\frac {100 e^{-x} x^2}{-9+200 x^2+200 x^3}} \left (-900 x+20000 x^3+20000 x^4+\left (-1800 x+900 x^2-40000 x^4-20000 x^5\right ) \log (5 x)\right )}{81-3600 x^2-3600 x^3+40000 x^4+80000 x^5+40000 x^6} \, dx=e^{\frac {100 \,\mathrm {log}\left (5 x \right ) x^{2}}{200 e^{x} x^{3}+200 e^{x} x^{2}-9 e^{x}}} \] Input:
int(((-20000*x^5-40000*x^4+900*x^2-1800*x)*log(5*x)+20000*x^4+20000*x^3-90 0*x)*exp(100*x^2*log(5*x)/(200*x^3+200*x^2-9)/exp(x))/(40000*x^6+80000*x^5 +40000*x^4-3600*x^3-3600*x^2+81)/exp(x),x)
Output:
e**((100*log(5*x)*x**2)/(200*e**x*x**3 + 200*e**x*x**2 - 9*e**x))