Integrand size = 103, antiderivative size = 33 \[ \int \frac {e^{\frac {e^x+x^2}{x^3 \log \left (-2+e^{3/2}\right ) \log (4+2 x)}} \left (-e^x x-x^3+\left (-2 x^2-x^3+e^x \left (-6-x+x^2\right )\right ) \log (4+2 x)\right )}{\left (2 x^4+x^5\right ) \log \left (-2+e^{3/2}\right ) \log ^2(4+2 x)} \, dx=e^{\frac {\frac {e^x}{x}+x}{x^2 \log \left (-2+e^{3/2}\right ) \log (4+2 x)}} \] Output:
exp((exp(x)/x+x)/x^2/ln(4+2*x)/ln(exp(3/2)-2))
Time = 0.07 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.94 \[ \int \frac {e^{\frac {e^x+x^2}{x^3 \log \left (-2+e^{3/2}\right ) \log (4+2 x)}} \left (-e^x x-x^3+\left (-2 x^2-x^3+e^x \left (-6-x+x^2\right )\right ) \log (4+2 x)\right )}{\left (2 x^4+x^5\right ) \log \left (-2+e^{3/2}\right ) \log ^2(4+2 x)} \, dx=e^{\frac {e^x+x^2}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 (2+x))}} \] Input:
Integrate[(E^((E^x + x^2)/(x^3*Log[-2 + E^(3/2)]*Log[4 + 2*x]))*(-(E^x*x) - x^3 + (-2*x^2 - x^3 + E^x*(-6 - x + x^2))*Log[4 + 2*x]))/((2*x^4 + x^5)* Log[-2 + E^(3/2)]*Log[4 + 2*x]^2),x]
Output:
E^((E^x + x^2)/(x^3*Log[-2 + E^(3/2)]*Log[2*(2 + x)]))
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {e^{\frac {x^2+e^x}{x^3 \log \left (e^{3/2}-2\right ) \log (2 x+4)}} \left (-x^3+\left (-x^3-2 x^2+e^x \left (x^2-x-6\right )\right ) \log (2 x+4)-e^x x\right )}{\left (x^5+2 x^4\right ) \log \left (e^{3/2}-2\right ) \log ^2(2 x+4)} \, dx\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {\int -\frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} \left (x^3+e^x x+\left (x^3+2 x^2+e^x \left (-x^2+x+6\right )\right ) \log (2 x+4)\right )}{\left (x^5+2 x^4\right ) \log ^2(2 x+4)}dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle -\frac {\int \frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} \left (x^3+e^x x+\left (x^3+2 x^2+e^x \left (-x^2+x+6\right )\right ) \log (2 x+4)\right )}{\left (x^5+2 x^4\right ) \log ^2(2 x+4)}dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 2026 |
\(\displaystyle -\frac {\int \frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} \left (x^3+e^x x+\left (x^3+2 x^2+e^x \left (-x^2+x+6\right )\right ) \log (2 x+4)\right )}{x^4 (x+2) \log ^2(2 x+4)}dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle -\frac {\int \left (\frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} (\log (2 (x+2)) x+x+2 \log (2 (x+2)))}{x^2 (x+2) \log ^2(2 x+4)}+\frac {\exp \left (x+\frac {x^2+e^x}{\log \left (-2+e^{3/2}\right ) \log (2 x+4) x^3}\right ) \left (-\log (2 (x+2)) x^2+\log (2 (x+2)) x+x+6 \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}\right )dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7239 |
\(\displaystyle -\frac {\int \frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} \left (x \left (x^2+e^x\right )+(x+2) \left (x^2-e^x (x-3)\right ) \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle -\frac {\int \left (\frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} (\log (2 (x+2)) x+x+2 \log (2 (x+2)))}{x^2 (x+2) \log ^2(2 x+4)}+\frac {\exp \left (x+\frac {x^2+e^x}{\log \left (-2+e^{3/2}\right ) \log (2 x+4) x^3}\right ) \left (-\log (2 (x+2)) x^2+\log (2 (x+2)) x+x+6 \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}\right )dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7239 |
\(\displaystyle -\frac {\int \frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} \left (x \left (x^2+e^x\right )+(x+2) \left (x^2-e^x (x-3)\right ) \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle -\frac {\int \left (\frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} (\log (2 (x+2)) x+x+2 \log (2 (x+2)))}{x^2 (x+2) \log ^2(2 x+4)}+\frac {\exp \left (x+\frac {x^2+e^x}{\log \left (-2+e^{3/2}\right ) \log (2 x+4) x^3}\right ) \left (-\log (2 (x+2)) x^2+\log (2 (x+2)) x+x+6 \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}\right )dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7239 |
\(\displaystyle -\frac {\int \frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} \left (x \left (x^2+e^x\right )+(x+2) \left (x^2-e^x (x-3)\right ) \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle -\frac {\int \left (\frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} (\log (2 (x+2)) x+x+2 \log (2 (x+2)))}{x^2 (x+2) \log ^2(2 x+4)}+\frac {\exp \left (x+\frac {x^2+e^x}{\log \left (-2+e^{3/2}\right ) \log (2 x+4) x^3}\right ) \left (-\log (2 (x+2)) x^2+\log (2 (x+2)) x+x+6 \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}\right )dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7239 |
\(\displaystyle -\frac {\int \frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} \left (x \left (x^2+e^x\right )+(x+2) \left (x^2-e^x (x-3)\right ) \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle -\frac {\int \left (\frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} (\log (2 (x+2)) x+x+2 \log (2 (x+2)))}{x^2 (x+2) \log ^2(2 x+4)}+\frac {\exp \left (x+\frac {x^2+e^x}{\log \left (-2+e^{3/2}\right ) \log (2 x+4) x^3}\right ) \left (-\log (2 (x+2)) x^2+\log (2 (x+2)) x+x+6 \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}\right )dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7239 |
\(\displaystyle -\frac {\int \frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} \left (x \left (x^2+e^x\right )+(x+2) \left (x^2-e^x (x-3)\right ) \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle -\frac {\int \left (\frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} (\log (2 (x+2)) x+x+2 \log (2 (x+2)))}{x^2 (x+2) \log ^2(2 x+4)}+\frac {\exp \left (x+\frac {x^2+e^x}{\log \left (-2+e^{3/2}\right ) \log (2 x+4) x^3}\right ) \left (-\log (2 (x+2)) x^2+\log (2 (x+2)) x+x+6 \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}\right )dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7239 |
\(\displaystyle -\frac {\int \frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} \left (x \left (x^2+e^x\right )+(x+2) \left (x^2-e^x (x-3)\right ) \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle -\frac {\int \left (\frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} (\log (2 (x+2)) x+x+2 \log (2 (x+2)))}{x^2 (x+2) \log ^2(2 x+4)}+\frac {\exp \left (x+\frac {x^2+e^x}{\log \left (-2+e^{3/2}\right ) \log (2 x+4) x^3}\right ) \left (-\log (2 (x+2)) x^2+\log (2 (x+2)) x+x+6 \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}\right )dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7239 |
\(\displaystyle -\frac {\int \frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} \left (x \left (x^2+e^x\right )+(x+2) \left (x^2-e^x (x-3)\right ) \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle -\frac {\int \left (\frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} (\log (2 (x+2)) x+x+2 \log (2 (x+2)))}{x^2 (x+2) \log ^2(2 x+4)}+\frac {\exp \left (x+\frac {x^2+e^x}{\log \left (-2+e^{3/2}\right ) \log (2 x+4) x^3}\right ) \left (-\log (2 (x+2)) x^2+\log (2 (x+2)) x+x+6 \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}\right )dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7239 |
\(\displaystyle -\frac {\int \frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} \left (x \left (x^2+e^x\right )+(x+2) \left (x^2-e^x (x-3)\right ) \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle -\frac {\int \left (\frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} (\log (2 (x+2)) x+x+2 \log (2 (x+2)))}{x^2 (x+2) \log ^2(2 x+4)}+\frac {\exp \left (x+\frac {x^2+e^x}{\log \left (-2+e^{3/2}\right ) \log (2 x+4) x^3}\right ) \left (-\log (2 (x+2)) x^2+\log (2 (x+2)) x+x+6 \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}\right )dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7239 |
\(\displaystyle -\frac {\int \frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} \left (x \left (x^2+e^x\right )+(x+2) \left (x^2-e^x (x-3)\right ) \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle -\frac {\int \left (\frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} (\log (2 (x+2)) x+x+2 \log (2 (x+2)))}{x^2 (x+2) \log ^2(2 x+4)}+\frac {\exp \left (x+\frac {x^2+e^x}{\log \left (-2+e^{3/2}\right ) \log (2 x+4) x^3}\right ) \left (-\log (2 (x+2)) x^2+\log (2 (x+2)) x+x+6 \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}\right )dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7239 |
\(\displaystyle -\frac {\int \frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} \left (x \left (x^2+e^x\right )+(x+2) \left (x^2-e^x (x-3)\right ) \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle -\frac {\int \left (\frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} (\log (2 (x+2)) x+x+2 \log (2 (x+2)))}{x^2 (x+2) \log ^2(2 x+4)}+\frac {\exp \left (x+\frac {x^2+e^x}{\log \left (-2+e^{3/2}\right ) \log (2 x+4) x^3}\right ) \left (-\log (2 (x+2)) x^2+\log (2 (x+2)) x+x+6 \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}\right )dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7239 |
\(\displaystyle -\frac {\int \frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} \left (x \left (x^2+e^x\right )+(x+2) \left (x^2-e^x (x-3)\right ) \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle -\frac {\int \left (\frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} (\log (2 (x+2)) x+x+2 \log (2 (x+2)))}{x^2 (x+2) \log ^2(2 x+4)}+\frac {\exp \left (x+\frac {x^2+e^x}{\log \left (-2+e^{3/2}\right ) \log (2 x+4) x^3}\right ) \left (-\log (2 (x+2)) x^2+\log (2 (x+2)) x+x+6 \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}\right )dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7239 |
\(\displaystyle -\frac {\int \frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} \left (x \left (x^2+e^x\right )+(x+2) \left (x^2-e^x (x-3)\right ) \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle -\frac {\int \left (\frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} (\log (2 (x+2)) x+x+2 \log (2 (x+2)))}{x^2 (x+2) \log ^2(2 x+4)}+\frac {\exp \left (x+\frac {x^2+e^x}{\log \left (-2+e^{3/2}\right ) \log (2 x+4) x^3}\right ) \left (-\log (2 (x+2)) x^2+\log (2 (x+2)) x+x+6 \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}\right )dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7239 |
\(\displaystyle -\frac {\int \frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} \left (x \left (x^2+e^x\right )+(x+2) \left (x^2-e^x (x-3)\right ) \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}dx}{\log \left (e^{3/2}-2\right )}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle -\frac {\int \left (\frac {e^{\frac {x^2+e^x}{x^3 \log \left (-2+e^{3/2}\right ) \log (2 x+4)}} (\log (2 (x+2)) x+x+2 \log (2 (x+2)))}{x^2 (x+2) \log ^2(2 x+4)}+\frac {\exp \left (x+\frac {x^2+e^x}{\log \left (-2+e^{3/2}\right ) \log (2 x+4) x^3}\right ) \left (-\log (2 (x+2)) x^2+\log (2 (x+2)) x+x+6 \log (2 (x+2))\right )}{x^4 (x+2) \log ^2(2 x+4)}\right )dx}{\log \left (e^{3/2}-2\right )}\) |
Input:
Int[(E^((E^x + x^2)/(x^3*Log[-2 + E^(3/2)]*Log[4 + 2*x]))*(-(E^x*x) - x^3 + (-2*x^2 - x^3 + E^x*(-6 - x + x^2))*Log[4 + 2*x]))/((2*x^4 + x^5)*Log[-2 + E^(3/2)]*Log[4 + 2*x]^2),x]
Output:
$Aborted
Time = 0.10 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.82
\[{\mathrm e}^{\frac {x^{2}+{\mathrm e}^{x}}{x^{3} \ln \left (4+2 x \right ) \ln \left ({\mathrm e}^{\frac {3}{2}}-2\right )}}\]
Input:
int((((x^2-x-6)*exp(x)-x^3-2*x^2)*ln(4+2*x)-exp(x)*x-x^3)*exp((x^2+exp(x)) /x^3/ln(4+2*x)/ln(exp(3/2)-2))/(x^5+2*x^4)/ln(4+2*x)^2/ln(exp(3/2)-2),x)
Output:
exp((x^2+exp(x))/x^3/ln(4+2*x)/ln(exp(3/2)-2))
Time = 0.12 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.79 \[ \int \frac {e^{\frac {e^x+x^2}{x^3 \log \left (-2+e^{3/2}\right ) \log (4+2 x)}} \left (-e^x x-x^3+\left (-2 x^2-x^3+e^x \left (-6-x+x^2\right )\right ) \log (4+2 x)\right )}{\left (2 x^4+x^5\right ) \log \left (-2+e^{3/2}\right ) \log ^2(4+2 x)} \, dx=e^{\left (\frac {x^{2} + e^{x}}{x^{3} \log \left (2 \, x + 4\right ) \log \left (e^{\frac {3}{2}} - 2\right )}\right )} \] Input:
integrate((((x^2-x-6)*exp(x)-x^3-2*x^2)*log(4+2*x)-exp(x)*x-x^3)*exp((x^2+ exp(x))/x^3/log(4+2*x)/log(exp(3/2)-2))/(x^5+2*x^4)/log(4+2*x)^2/log(exp(3 /2)-2),x, algorithm="fricas")
Output:
e^((x^2 + e^x)/(x^3*log(2*x + 4)*log(e^(3/2) - 2)))
Time = 0.58 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.79 \[ \int \frac {e^{\frac {e^x+x^2}{x^3 \log \left (-2+e^{3/2}\right ) \log (4+2 x)}} \left (-e^x x-x^3+\left (-2 x^2-x^3+e^x \left (-6-x+x^2\right )\right ) \log (4+2 x)\right )}{\left (2 x^4+x^5\right ) \log \left (-2+e^{3/2}\right ) \log ^2(4+2 x)} \, dx=e^{\frac {x^{2} + e^{x}}{x^{3} \log {\left (-2 + e^{\frac {3}{2}} \right )} \log {\left (2 x + 4 \right )}}} \] Input:
integrate((((x**2-x-6)*exp(x)-x**3-2*x**2)*ln(4+2*x)-exp(x)*x-x**3)*exp((x **2+exp(x))/x**3/ln(4+2*x)/ln(exp(3/2)-2))/(x**5+2*x**4)/ln(4+2*x)**2/ln(e xp(3/2)-2),x)
Output:
exp((x**2 + exp(x))/(x**3*log(-2 + exp(3/2))*log(2*x + 4)))
Exception generated. \[ \int \frac {e^{\frac {e^x+x^2}{x^3 \log \left (-2+e^{3/2}\right ) \log (4+2 x)}} \left (-e^x x-x^3+\left (-2 x^2-x^3+e^x \left (-6-x+x^2\right )\right ) \log (4+2 x)\right )}{\left (2 x^4+x^5\right ) \log \left (-2+e^{3/2}\right ) \log ^2(4+2 x)} \, dx=\text {Exception raised: RuntimeError} \] Input:
integrate((((x^2-x-6)*exp(x)-x^3-2*x^2)*log(4+2*x)-exp(x)*x-x^3)*exp((x^2+ exp(x))/x^3/log(4+2*x)/log(exp(3/2)-2))/(x^5+2*x^4)/log(4+2*x)^2/log(exp(3 /2)-2),x, algorithm="maxima")
Output:
Exception raised: RuntimeError >> ECL says: In function CAR, the value of the first argument is 0which is not of the expected type LIST
\[ \int \frac {e^{\frac {e^x+x^2}{x^3 \log \left (-2+e^{3/2}\right ) \log (4+2 x)}} \left (-e^x x-x^3+\left (-2 x^2-x^3+e^x \left (-6-x+x^2\right )\right ) \log (4+2 x)\right )}{\left (2 x^4+x^5\right ) \log \left (-2+e^{3/2}\right ) \log ^2(4+2 x)} \, dx=\int { -\frac {{\left (x^{3} + x e^{x} + {\left (x^{3} + 2 \, x^{2} - {\left (x^{2} - x - 6\right )} e^{x}\right )} \log \left (2 \, x + 4\right )\right )} e^{\left (\frac {x^{2} + e^{x}}{x^{3} \log \left (2 \, x + 4\right ) \log \left (e^{\frac {3}{2}} - 2\right )}\right )}}{{\left (x^{5} + 2 \, x^{4}\right )} \log \left (2 \, x + 4\right )^{2} \log \left (e^{\frac {3}{2}} - 2\right )} \,d x } \] Input:
integrate((((x^2-x-6)*exp(x)-x^3-2*x^2)*log(4+2*x)-exp(x)*x-x^3)*exp((x^2+ exp(x))/x^3/log(4+2*x)/log(exp(3/2)-2))/(x^5+2*x^4)/log(4+2*x)^2/log(exp(3 /2)-2),x, algorithm="giac")
Output:
integrate(-(x^3 + x*e^x + (x^3 + 2*x^2 - (x^2 - x - 6)*e^x)*log(2*x + 4))* e^((x^2 + e^x)/(x^3*log(2*x + 4)*log(e^(3/2) - 2)))/((x^5 + 2*x^4)*log(2*x + 4)^2*log(e^(3/2) - 2)), x)
Time = 3.57 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.79 \[ \int \frac {e^{\frac {e^x+x^2}{x^3 \log \left (-2+e^{3/2}\right ) \log (4+2 x)}} \left (-e^x x-x^3+\left (-2 x^2-x^3+e^x \left (-6-x+x^2\right )\right ) \log (4+2 x)\right )}{\left (2 x^4+x^5\right ) \log \left (-2+e^{3/2}\right ) \log ^2(4+2 x)} \, dx={\mathrm {e}}^{\frac {{\mathrm {e}}^x+x^2}{x^3\,\ln \left ({\mathrm {e}}^{3/2}-2\right )\,\ln \left (2\,x+4\right )}} \] Input:
int(-(exp((exp(x) + x^2)/(x^3*log(exp(3/2) - 2)*log(2*x + 4)))*(x*exp(x) + log(2*x + 4)*(exp(x)*(x - x^2 + 6) + 2*x^2 + x^3) + x^3))/(log(exp(3/2) - 2)*log(2*x + 4)^2*(2*x^4 + x^5)),x)
Output:
exp((exp(x) + x^2)/(x^3*log(exp(3/2) - 2)*log(2*x + 4)))
Time = 0.17 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.91 \[ \int \frac {e^{\frac {e^x+x^2}{x^3 \log \left (-2+e^{3/2}\right ) \log (4+2 x)}} \left (-e^x x-x^3+\left (-2 x^2-x^3+e^x \left (-6-x+x^2\right )\right ) \log (4+2 x)\right )}{\left (2 x^4+x^5\right ) \log \left (-2+e^{3/2}\right ) \log ^2(4+2 x)} \, dx=e^{\frac {e^{x}+x^{2}}{\mathrm {log}\left (\sqrt {e}\, e -2\right ) \mathrm {log}\left (2 x +4\right ) x^{3}}} \] Input:
int((((x^2-x-6)*exp(x)-x^3-2*x^2)*log(4+2*x)-exp(x)*x-x^3)*exp((x^2+exp(x) )/x^3/log(4+2*x)/log(exp(3/2)-2))/(x^5+2*x^4)/log(4+2*x)^2/log(exp(3/2)-2) ,x)
Output:
e**((e**x + x**2)/(log(sqrt(e)*e - 2)*log(2*x + 4)*x**3))