Integrand size = 254, antiderivative size = 25 \[ \int \frac {-507 x^2+481 x^3-152 x^4+16 x^5+\left (-234 x^2+150 x^3-24 x^4\right ) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )+\left (-27 x^2+9 x^3\right ) \log ^2\left (81-108 x+54 x^2-12 x^3+x^4\right )+e^{\frac {1}{13 x-4 x^2+3 x \log \left (81-108 x+54 x^2-12 x^3+x^4\right )}} \left (39-49 x+8 x^2+(9-3 x) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )\right )}{-507 x^2+481 x^3-152 x^4+16 x^5+\left (-234 x^2+150 x^3-24 x^4\right ) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )+\left (-27 x^2+9 x^3\right ) \log ^2\left (81-108 x+54 x^2-12 x^3+x^4\right )} \, dx=e^{\frac {1}{x \left (4-4 x+3 \left (3+\log \left ((-3+x)^4\right )\right )\right )}}+x \] Output:
x+exp(1/x/(-4*x+13+3*ln((-3+x)^4)))
Time = 0.12 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.92 \[ \int \frac {-507 x^2+481 x^3-152 x^4+16 x^5+\left (-234 x^2+150 x^3-24 x^4\right ) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )+\left (-27 x^2+9 x^3\right ) \log ^2\left (81-108 x+54 x^2-12 x^3+x^4\right )+e^{\frac {1}{13 x-4 x^2+3 x \log \left (81-108 x+54 x^2-12 x^3+x^4\right )}} \left (39-49 x+8 x^2+(9-3 x) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )\right )}{-507 x^2+481 x^3-152 x^4+16 x^5+\left (-234 x^2+150 x^3-24 x^4\right ) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )+\left (-27 x^2+9 x^3\right ) \log ^2\left (81-108 x+54 x^2-12 x^3+x^4\right )} \, dx=e^{\frac {1}{x \left (13-4 x+3 \log \left ((-3+x)^4\right )\right )}}+x \] Input:
Integrate[(-507*x^2 + 481*x^3 - 152*x^4 + 16*x^5 + (-234*x^2 + 150*x^3 - 2 4*x^4)*Log[81 - 108*x + 54*x^2 - 12*x^3 + x^4] + (-27*x^2 + 9*x^3)*Log[81 - 108*x + 54*x^2 - 12*x^3 + x^4]^2 + E^(13*x - 4*x^2 + 3*x*Log[81 - 108*x + 54*x^2 - 12*x^3 + x^4])^(-1)*(39 - 49*x + 8*x^2 + (9 - 3*x)*Log[81 - 108 *x + 54*x^2 - 12*x^3 + x^4]))/(-507*x^2 + 481*x^3 - 152*x^4 + 16*x^5 + (-2 34*x^2 + 150*x^3 - 24*x^4)*Log[81 - 108*x + 54*x^2 - 12*x^3 + x^4] + (-27* x^2 + 9*x^3)*Log[81 - 108*x + 54*x^2 - 12*x^3 + x^4]^2),x]
Output:
E^(1/(x*(13 - 4*x + 3*Log[(-3 + x)^4]))) + x
Time = 4.39 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.92, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.012, Rules used = {7292, 7293, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\left (8 x^2+(9-3 x) \log \left (x^4-12 x^3+54 x^2-108 x+81\right )-49 x+39\right ) \exp \left (\frac {1}{-4 x^2+3 x \log \left (x^4-12 x^3+54 x^2-108 x+81\right )+13 x}\right )+16 x^5-152 x^4+481 x^3-507 x^2+\left (9 x^3-27 x^2\right ) \log ^2\left (x^4-12 x^3+54 x^2-108 x+81\right )+\left (-24 x^4+150 x^3-234 x^2\right ) \log \left (x^4-12 x^3+54 x^2-108 x+81\right )}{16 x^5-152 x^4+481 x^3-507 x^2+\left (9 x^3-27 x^2\right ) \log ^2\left (x^4-12 x^3+54 x^2-108 x+81\right )+\left (-24 x^4+150 x^3-234 x^2\right ) \log \left (x^4-12 x^3+54 x^2-108 x+81\right )} \, dx\) |
\(\Big \downarrow \) 7292 |
\(\displaystyle \int \frac {-\left (8 x^2+(9-3 x) \log \left (x^4-12 x^3+54 x^2-108 x+81\right )-49 x+39\right ) \exp \left (\frac {1}{-4 x^2+3 x \log \left (x^4-12 x^3+54 x^2-108 x+81\right )+13 x}\right )-16 x^5+152 x^4-481 x^3+507 x^2-\left (9 x^3-27 x^2\right ) \log ^2\left (x^4-12 x^3+54 x^2-108 x+81\right )-\left (-24 x^4+150 x^3-234 x^2\right ) \log \left (x^4-12 x^3+54 x^2-108 x+81\right )}{(3-x) x^2 \left (-4 x+3 \log \left ((x-3)^4\right )+13\right )^2}dx\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle \int \left (\frac {16 x^3}{(x-3) \left (4 x-3 \log \left ((x-3)^4\right )-13\right )^2}-\frac {152 x^2}{(x-3) \left (4 x-3 \log \left ((x-3)^4\right )-13\right )^2}+\frac {e^{-\frac {1}{x \left (4 x-3 \log \left ((x-3)^4\right )-13\right )}} \left (8 x^2-49 x-3 x \log \left ((x-3)^4\right )+9 \log \left ((x-3)^4\right )+39\right )}{(x-3) x^2 \left (4 x-3 \log \left ((x-3)^4\right )-13\right )^2}+\frac {9 \log ^2\left ((x-3)^4\right )}{\left (-4 x+3 \log \left ((x-3)^4\right )+13\right )^2}+\frac {481 x}{(x-3) \left (4 x-3 \log \left ((x-3)^4\right )-13\right )^2}-\frac {6 (4 x-13) \log \left ((x-3)^4\right )}{\left (4 x-3 \log \left ((x-3)^4\right )-13\right )^2}-\frac {507}{(x-3) \left (4 x-3 \log \left ((x-3)^4\right )-13\right )^2}\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle x+e^{\frac {1}{x \left (-4 x+3 \log \left ((x-3)^4\right )+13\right )}}\) |
Input:
Int[(-507*x^2 + 481*x^3 - 152*x^4 + 16*x^5 + (-234*x^2 + 150*x^3 - 24*x^4) *Log[81 - 108*x + 54*x^2 - 12*x^3 + x^4] + (-27*x^2 + 9*x^3)*Log[81 - 108* x + 54*x^2 - 12*x^3 + x^4]^2 + E^(13*x - 4*x^2 + 3*x*Log[81 - 108*x + 54*x ^2 - 12*x^3 + x^4])^(-1)*(39 - 49*x + 8*x^2 + (9 - 3*x)*Log[81 - 108*x + 5 4*x^2 - 12*x^3 + x^4]))/(-507*x^2 + 481*x^3 - 152*x^4 + 16*x^5 + (-234*x^2 + 150*x^3 - 24*x^4)*Log[81 - 108*x + 54*x^2 - 12*x^3 + x^4] + (-27*x^2 + 9*x^3)*Log[81 - 108*x + 54*x^2 - 12*x^3 + x^4]^2),x]
Output:
E^(1/(x*(13 - 4*x + 3*Log[(-3 + x)^4]))) + x
Time = 7.02 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.48
method | result | size |
risch | \(x +{\mathrm e}^{-\frac {1}{x \left (-3 \ln \left (x^{4}-12 x^{3}+54 x^{2}-108 x +81\right )+4 x -13\right )}}\) | \(37\) |
parallelrisch | \(\frac {37}{4}+x +{\mathrm e}^{\frac {1}{x \left (3 \ln \left (x^{4}-12 x^{3}+54 x^{2}-108 x +81\right )-4 x +13\right )}}\) | \(37\) |
Input:
int((((-3*x+9)*ln(x^4-12*x^3+54*x^2-108*x+81)+8*x^2-49*x+39)*exp(1/(3*x*ln (x^4-12*x^3+54*x^2-108*x+81)-4*x^2+13*x))+(9*x^3-27*x^2)*ln(x^4-12*x^3+54* x^2-108*x+81)^2+(-24*x^4+150*x^3-234*x^2)*ln(x^4-12*x^3+54*x^2-108*x+81)+1 6*x^5-152*x^4+481*x^3-507*x^2)/((9*x^3-27*x^2)*ln(x^4-12*x^3+54*x^2-108*x+ 81)^2+(-24*x^4+150*x^3-234*x^2)*ln(x^4-12*x^3+54*x^2-108*x+81)+16*x^5-152* x^4+481*x^3-507*x^2),x,method=_RETURNVERBOSE)
Output:
x+exp(-1/x/(-3*ln(x^4-12*x^3+54*x^2-108*x+81)+4*x-13))
Time = 0.10 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.52 \[ \int \frac {-507 x^2+481 x^3-152 x^4+16 x^5+\left (-234 x^2+150 x^3-24 x^4\right ) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )+\left (-27 x^2+9 x^3\right ) \log ^2\left (81-108 x+54 x^2-12 x^3+x^4\right )+e^{\frac {1}{13 x-4 x^2+3 x \log \left (81-108 x+54 x^2-12 x^3+x^4\right )}} \left (39-49 x+8 x^2+(9-3 x) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )\right )}{-507 x^2+481 x^3-152 x^4+16 x^5+\left (-234 x^2+150 x^3-24 x^4\right ) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )+\left (-27 x^2+9 x^3\right ) \log ^2\left (81-108 x+54 x^2-12 x^3+x^4\right )} \, dx=x + e^{\left (-\frac {1}{4 \, x^{2} - 3 \, x \log \left (x^{4} - 12 \, x^{3} + 54 \, x^{2} - 108 \, x + 81\right ) - 13 \, x}\right )} \] Input:
integrate((((-3*x+9)*log(x^4-12*x^3+54*x^2-108*x+81)+8*x^2-49*x+39)*exp(1/ (3*x*log(x^4-12*x^3+54*x^2-108*x+81)-4*x^2+13*x))+(9*x^3-27*x^2)*log(x^4-1 2*x^3+54*x^2-108*x+81)^2+(-24*x^4+150*x^3-234*x^2)*log(x^4-12*x^3+54*x^2-1 08*x+81)+16*x^5-152*x^4+481*x^3-507*x^2)/((9*x^3-27*x^2)*log(x^4-12*x^3+54 *x^2-108*x+81)^2+(-24*x^4+150*x^3-234*x^2)*log(x^4-12*x^3+54*x^2-108*x+81) +16*x^5-152*x^4+481*x^3-507*x^2),x, algorithm="fricas")
Output:
x + e^(-1/(4*x^2 - 3*x*log(x^4 - 12*x^3 + 54*x^2 - 108*x + 81) - 13*x))
Exception generated. \[ \int \frac {-507 x^2+481 x^3-152 x^4+16 x^5+\left (-234 x^2+150 x^3-24 x^4\right ) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )+\left (-27 x^2+9 x^3\right ) \log ^2\left (81-108 x+54 x^2-12 x^3+x^4\right )+e^{\frac {1}{13 x-4 x^2+3 x \log \left (81-108 x+54 x^2-12 x^3+x^4\right )}} \left (39-49 x+8 x^2+(9-3 x) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )\right )}{-507 x^2+481 x^3-152 x^4+16 x^5+\left (-234 x^2+150 x^3-24 x^4\right ) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )+\left (-27 x^2+9 x^3\right ) \log ^2\left (81-108 x+54 x^2-12 x^3+x^4\right )} \, dx=\text {Exception raised: TypeError} \] Input:
integrate((((-3*x+9)*ln(x**4-12*x**3+54*x**2-108*x+81)+8*x**2-49*x+39)*exp (1/(3*x*ln(x**4-12*x**3+54*x**2-108*x+81)-4*x**2+13*x))+(9*x**3-27*x**2)*l n(x**4-12*x**3+54*x**2-108*x+81)**2+(-24*x**4+150*x**3-234*x**2)*ln(x**4-1 2*x**3+54*x**2-108*x+81)+16*x**5-152*x**4+481*x**3-507*x**2)/((9*x**3-27*x **2)*ln(x**4-12*x**3+54*x**2-108*x+81)**2+(-24*x**4+150*x**3-234*x**2)*ln( x**4-12*x**3+54*x**2-108*x+81)+16*x**5-152*x**4+481*x**3-507*x**2),x)
Output:
Exception raised: TypeError >> '>' not supported between instances of 'Pol y' and 'int'
Leaf count of result is larger than twice the leaf count of optimal. 49 vs. \(2 (23) = 46\).
Time = 0.09 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.96 \[ \int \frac {-507 x^2+481 x^3-152 x^4+16 x^5+\left (-234 x^2+150 x^3-24 x^4\right ) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )+\left (-27 x^2+9 x^3\right ) \log ^2\left (81-108 x+54 x^2-12 x^3+x^4\right )+e^{\frac {1}{13 x-4 x^2+3 x \log \left (81-108 x+54 x^2-12 x^3+x^4\right )}} \left (39-49 x+8 x^2+(9-3 x) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )\right )}{-507 x^2+481 x^3-152 x^4+16 x^5+\left (-234 x^2+150 x^3-24 x^4\right ) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )+\left (-27 x^2+9 x^3\right ) \log ^2\left (81-108 x+54 x^2-12 x^3+x^4\right )} \, dx=x + e^{\left (-\frac {4}{4 \, x {\left (12 \, \log \left (x - 3\right ) + 13\right )} - 144 \, \log \left (x - 3\right )^{2} - 312 \, \log \left (x - 3\right ) - 169} + \frac {1}{x {\left (12 \, \log \left (x - 3\right ) + 13\right )}}\right )} \] Input:
integrate((((-3*x+9)*log(x^4-12*x^3+54*x^2-108*x+81)+8*x^2-49*x+39)*exp(1/ (3*x*log(x^4-12*x^3+54*x^2-108*x+81)-4*x^2+13*x))+(9*x^3-27*x^2)*log(x^4-1 2*x^3+54*x^2-108*x+81)^2+(-24*x^4+150*x^3-234*x^2)*log(x^4-12*x^3+54*x^2-1 08*x+81)+16*x^5-152*x^4+481*x^3-507*x^2)/((9*x^3-27*x^2)*log(x^4-12*x^3+54 *x^2-108*x+81)^2+(-24*x^4+150*x^3-234*x^2)*log(x^4-12*x^3+54*x^2-108*x+81) +16*x^5-152*x^4+481*x^3-507*x^2),x, algorithm="maxima")
Output:
x + e^(-4/(4*x*(12*log(x - 3) + 13) - 144*log(x - 3)^2 - 312*log(x - 3) - 169) + 1/(x*(12*log(x - 3) + 13)))
Time = 1.25 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.52 \[ \int \frac {-507 x^2+481 x^3-152 x^4+16 x^5+\left (-234 x^2+150 x^3-24 x^4\right ) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )+\left (-27 x^2+9 x^3\right ) \log ^2\left (81-108 x+54 x^2-12 x^3+x^4\right )+e^{\frac {1}{13 x-4 x^2+3 x \log \left (81-108 x+54 x^2-12 x^3+x^4\right )}} \left (39-49 x+8 x^2+(9-3 x) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )\right )}{-507 x^2+481 x^3-152 x^4+16 x^5+\left (-234 x^2+150 x^3-24 x^4\right ) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )+\left (-27 x^2+9 x^3\right ) \log ^2\left (81-108 x+54 x^2-12 x^3+x^4\right )} \, dx=x + e^{\left (-\frac {1}{4 \, x^{2} - 3 \, x \log \left (x^{4} - 12 \, x^{3} + 54 \, x^{2} - 108 \, x + 81\right ) - 13 \, x}\right )} \] Input:
integrate((((-3*x+9)*log(x^4-12*x^3+54*x^2-108*x+81)+8*x^2-49*x+39)*exp(1/ (3*x*log(x^4-12*x^3+54*x^2-108*x+81)-4*x^2+13*x))+(9*x^3-27*x^2)*log(x^4-1 2*x^3+54*x^2-108*x+81)^2+(-24*x^4+150*x^3-234*x^2)*log(x^4-12*x^3+54*x^2-1 08*x+81)+16*x^5-152*x^4+481*x^3-507*x^2)/((9*x^3-27*x^2)*log(x^4-12*x^3+54 *x^2-108*x+81)^2+(-24*x^4+150*x^3-234*x^2)*log(x^4-12*x^3+54*x^2-108*x+81) +16*x^5-152*x^4+481*x^3-507*x^2),x, algorithm="giac")
Output:
x + e^(-1/(4*x^2 - 3*x*log(x^4 - 12*x^3 + 54*x^2 - 108*x + 81) - 13*x))
Time = 7.72 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.44 \[ \int \frac {-507 x^2+481 x^3-152 x^4+16 x^5+\left (-234 x^2+150 x^3-24 x^4\right ) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )+\left (-27 x^2+9 x^3\right ) \log ^2\left (81-108 x+54 x^2-12 x^3+x^4\right )+e^{\frac {1}{13 x-4 x^2+3 x \log \left (81-108 x+54 x^2-12 x^3+x^4\right )}} \left (39-49 x+8 x^2+(9-3 x) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )\right )}{-507 x^2+481 x^3-152 x^4+16 x^5+\left (-234 x^2+150 x^3-24 x^4\right ) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )+\left (-27 x^2+9 x^3\right ) \log ^2\left (81-108 x+54 x^2-12 x^3+x^4\right )} \, dx=x+{\mathrm {e}}^{\frac {1}{13\,x+3\,x\,\ln \left (x^4-12\,x^3+54\,x^2-108\,x+81\right )-4\,x^2}} \] Input:
int((exp(1/(13*x + 3*x*log(54*x^2 - 108*x - 12*x^3 + x^4 + 81) - 4*x^2))*( 49*x + log(54*x^2 - 108*x - 12*x^3 + x^4 + 81)*(3*x - 9) - 8*x^2 - 39) + l og(54*x^2 - 108*x - 12*x^3 + x^4 + 81)*(234*x^2 - 150*x^3 + 24*x^4) + log( 54*x^2 - 108*x - 12*x^3 + x^4 + 81)^2*(27*x^2 - 9*x^3) + 507*x^2 - 481*x^3 + 152*x^4 - 16*x^5)/(log(54*x^2 - 108*x - 12*x^3 + x^4 + 81)*(234*x^2 - 1 50*x^3 + 24*x^4) + log(54*x^2 - 108*x - 12*x^3 + x^4 + 81)^2*(27*x^2 - 9*x ^3) + 507*x^2 - 481*x^3 + 152*x^4 - 16*x^5),x)
Output:
x + exp(1/(13*x + 3*x*log(54*x^2 - 108*x - 12*x^3 + x^4 + 81) - 4*x^2))
Time = 0.18 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.48 \[ \int \frac {-507 x^2+481 x^3-152 x^4+16 x^5+\left (-234 x^2+150 x^3-24 x^4\right ) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )+\left (-27 x^2+9 x^3\right ) \log ^2\left (81-108 x+54 x^2-12 x^3+x^4\right )+e^{\frac {1}{13 x-4 x^2+3 x \log \left (81-108 x+54 x^2-12 x^3+x^4\right )}} \left (39-49 x+8 x^2+(9-3 x) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )\right )}{-507 x^2+481 x^3-152 x^4+16 x^5+\left (-234 x^2+150 x^3-24 x^4\right ) \log \left (81-108 x+54 x^2-12 x^3+x^4\right )+\left (-27 x^2+9 x^3\right ) \log ^2\left (81-108 x+54 x^2-12 x^3+x^4\right )} \, dx=e^{\frac {1}{3 \,\mathrm {log}\left (x^{4}-12 x^{3}+54 x^{2}-108 x +81\right ) x -4 x^{2}+13 x}}+x \] Input:
int((((-3*x+9)*log(x^4-12*x^3+54*x^2-108*x+81)+8*x^2-49*x+39)*exp(1/(3*x*l og(x^4-12*x^3+54*x^2-108*x+81)-4*x^2+13*x))+(9*x^3-27*x^2)*log(x^4-12*x^3+ 54*x^2-108*x+81)^2+(-24*x^4+150*x^3-234*x^2)*log(x^4-12*x^3+54*x^2-108*x+8 1)+16*x^5-152*x^4+481*x^3-507*x^2)/((9*x^3-27*x^2)*log(x^4-12*x^3+54*x^2-1 08*x+81)^2+(-24*x^4+150*x^3-234*x^2)*log(x^4-12*x^3+54*x^2-108*x+81)+16*x^ 5-152*x^4+481*x^3-507*x^2),x)
Output:
e**(1/(3*log(x**4 - 12*x**3 + 54*x**2 - 108*x + 81)*x - 4*x**2 + 13*x)) + x