Integrand size = 15, antiderivative size = 112 \[ \int x^2 \sqrt [3]{-x+x^3} \, dx=\frac {1}{12} \sqrt [3]{-x+x^3} \left (-x+3 x^3\right )+\frac {\arctan \left (\frac {\sqrt {3} x}{x+2 \sqrt [3]{-x+x^3}}\right )}{6 \sqrt {3}}+\frac {1}{18} \log \left (-x+\sqrt [3]{-x+x^3}\right )-\frac {1}{36} \log \left (x^2+x \sqrt [3]{-x+x^3}+\left (-x+x^3\right )^{2/3}\right ) \] Output:
1/12*(x^3-x)^(1/3)*(3*x^3-x)+1/18*arctan(3^(1/2)*x/(x+2*(x^3-x)^(1/3)))*3^ (1/2)+1/18*ln(-x+(x^3-x)^(1/3))-1/36*ln(x^2+x*(x^3-x)^(1/3)+(x^3-x)^(2/3))
Time = 0.71 (sec) , antiderivative size = 153, normalized size of antiderivative = 1.37 \[ \int x^2 \sqrt [3]{-x+x^3} \, dx=\frac {x^{2/3} \left (-1+x^2\right )^{2/3} \left (-3 x^{4/3} \sqrt [3]{-1+x^2}+9 x^{10/3} \sqrt [3]{-1+x^2}+2 \sqrt {3} \arctan \left (\frac {\sqrt {3} x^{2/3}}{x^{2/3}+2 \sqrt [3]{-1+x^2}}\right )+2 \log \left (-x^{2/3}+\sqrt [3]{-1+x^2}\right )-\log \left (x^{4/3}+x^{2/3} \sqrt [3]{-1+x^2}+\left (-1+x^2\right )^{2/3}\right )\right )}{36 \left (x \left (-1+x^2\right )\right )^{2/3}} \] Input:
Integrate[x^2*(-x + x^3)^(1/3),x]
Output:
(x^(2/3)*(-1 + x^2)^(2/3)*(-3*x^(4/3)*(-1 + x^2)^(1/3) + 9*x^(10/3)*(-1 + x^2)^(1/3) + 2*Sqrt[3]*ArcTan[(Sqrt[3]*x^(2/3))/(x^(2/3) + 2*(-1 + x^2)^(1 /3))] + 2*Log[-x^(2/3) + (-1 + x^2)^(1/3)] - Log[x^(4/3) + x^(2/3)*(-1 + x ^2)^(1/3) + (-1 + x^2)^(2/3)]))/(36*(x*(-1 + x^2))^(2/3))
Time = 0.26 (sec) , antiderivative size = 118, normalized size of antiderivative = 1.05, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {1927, 1930, 1938, 266, 807, 853}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x^2 \sqrt [3]{x^3-x} \, dx\) |
\(\Big \downarrow \) 1927 |
\(\displaystyle \frac {1}{4} x^3 \sqrt [3]{x^3-x}-\frac {1}{6} \int \frac {x^3}{\left (x^3-x\right )^{2/3}}dx\) |
\(\Big \downarrow \) 1930 |
\(\displaystyle \frac {1}{6} \left (-\frac {2}{3} \int \frac {x}{\left (x^3-x\right )^{2/3}}dx-\frac {1}{2} \sqrt [3]{x^3-x} x\right )+\frac {1}{4} \sqrt [3]{x^3-x} x^3\) |
\(\Big \downarrow \) 1938 |
\(\displaystyle \frac {1}{6} \left (-\frac {2 \left (x^2-1\right )^{2/3} x^{2/3} \int \frac {\sqrt [3]{x}}{\left (x^2-1\right )^{2/3}}dx}{3 \left (x^3-x\right )^{2/3}}-\frac {1}{2} \sqrt [3]{x^3-x} x\right )+\frac {1}{4} \sqrt [3]{x^3-x} x^3\) |
\(\Big \downarrow \) 266 |
\(\displaystyle \frac {1}{6} \left (-\frac {2 \left (x^2-1\right )^{2/3} x^{2/3} \int \frac {x}{\left (x^2-1\right )^{2/3}}d\sqrt [3]{x}}{\left (x^3-x\right )^{2/3}}-\frac {1}{2} \sqrt [3]{x^3-x} x\right )+\frac {1}{4} \sqrt [3]{x^3-x} x^3\) |
\(\Big \downarrow \) 807 |
\(\displaystyle \frac {1}{6} \left (-\frac {\left (x^2-1\right )^{2/3} x^{2/3} \int \frac {x^{2/3}}{(x-1)^{2/3}}dx^{2/3}}{\left (x^3-x\right )^{2/3}}-\frac {1}{2} \sqrt [3]{x^3-x} x\right )+\frac {1}{4} \sqrt [3]{x^3-x} x^3\) |
\(\Big \downarrow \) 853 |
\(\displaystyle \frac {1}{6} \left (-\frac {\left (x^2-1\right )^{2/3} x^{2/3} \left (-\frac {\arctan \left (\frac {\frac {2 x^{2/3}}{\sqrt [3]{x-1}}+1}{\sqrt {3}}\right )}{\sqrt {3}}-\frac {1}{2} \log \left (x^{2/3}-\sqrt [3]{x-1}\right )\right )}{\left (x^3-x\right )^{2/3}}-\frac {1}{2} \sqrt [3]{x^3-x} x\right )+\frac {1}{4} \sqrt [3]{x^3-x} x^3\) |
Input:
Int[x^2*(-x + x^3)^(1/3),x]
Output:
(x^3*(-x + x^3)^(1/3))/4 + (-1/2*(x*(-x + x^3)^(1/3)) - (x^(2/3)*(-1 + x^2 )^(2/3)*(-(ArcTan[(1 + (2*x^(2/3))/(-1 + x)^(1/3))/Sqrt[3]]/Sqrt[3]) - Log [-(-1 + x)^(1/3) + x^(2/3)]/2))/(-x + x^3)^(2/3))/6
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{k = De nominator[m]}, Simp[k/c Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(2*k)/c^2)) ^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && FractionQ[m] && I ntBinomialQ[a, b, c, 2, m, p, x]
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = GCD[m + 1, n]}, Simp[1/k Subst[Int[x^((m + 1)/k - 1)*(a + b*x^(n/k))^p, x], x, x^k], x] /; k != 1] /; FreeQ[{a, b, p}, x] && IGtQ[n, 0] && IntegerQ[m]
Int[(x_)/((a_) + (b_.)*(x_)^3)^(2/3), x_Symbol] :> With[{q = Rt[b, 3]}, Sim p[-ArcTan[(1 + 2*q*(x/(a + b*x^3)^(1/3)))/Sqrt[3]]/(Sqrt[3]*q^2), x] - Simp [Log[q*x - (a + b*x^3)^(1/3)]/(2*q^2), x]] /; FreeQ[{a, b}, x]
Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol ] :> Simp[(c*x)^(m + 1)*((a*x^j + b*x^n)^p/(c*(m + n*p + 1))), x] + Simp[a* (n - j)*(p/(c^j*(m + n*p + 1))) Int[(c*x)^(m + j)*(a*x^j + b*x^n)^(p - 1) , x], x] /; FreeQ[{a, b, c, m}, x] && !IntegerQ[p] && LtQ[0, j, n] && (Int egersQ[j, n] || GtQ[c, 0]) && GtQ[p, 0] && NeQ[m + n*p + 1, 0]
Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol ] :> Simp[c^(n - 1)*(c*x)^(m - n + 1)*((a*x^j + b*x^n)^(p + 1)/(b*(m + n*p + 1))), x] - Simp[a*c^(n - j)*((m + j*p - n + j + 1)/(b*(m + n*p + 1))) I nt[(c*x)^(m - (n - j))*(a*x^j + b*x^n)^p, x], x] /; FreeQ[{a, b, c, m, p}, x] && !IntegerQ[p] && LtQ[0, j, n] && (IntegersQ[j, n] || GtQ[c, 0]) && Gt Q[m + j*p - n + j + 1, 0] && NeQ[m + n*p + 1, 0]
Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol ] :> Simp[c^IntPart[m]*(c*x)^FracPart[m]*((a*x^j + b*x^n)^FracPart[p]/(x^(F racPart[m] + j*FracPart[p])*(a + b*x^(n - j))^FracPart[p])) Int[x^(m + j* p)*(a + b*x^(n - j))^p, x], x] /; FreeQ[{a, b, c, j, m, n, p}, x] && !Inte gerQ[p] && NeQ[n, j] && PosQ[n - j]
Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 2.15 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.29
method | result | size |
meijerg | \(\frac {3 \operatorname {signum}\left (x^{2}-1\right )^{\frac {1}{3}} x^{\frac {10}{3}} \operatorname {hypergeom}\left (\left [-\frac {1}{3}, \frac {5}{3}\right ], \left [\frac {8}{3}\right ], x^{2}\right )}{10 {\left (-\operatorname {signum}\left (x^{2}-1\right )\right )}^{\frac {1}{3}}}\) | \(33\) |
pseudoelliptic | \(-\frac {x^{2} \left (\left (-9 x^{3}+3 x \right ) \left (x^{3}-x \right )^{\frac {1}{3}}+2 \arctan \left (\frac {\sqrt {3}\, \left (x +2 \left (x^{3}-x \right )^{\frac {1}{3}}\right )}{3 x}\right ) \sqrt {3}-2 \ln \left (\frac {-x +\left (x^{3}-x \right )^{\frac {1}{3}}}{x}\right )+\ln \left (\frac {x^{2}+x \left (x^{3}-x \right )^{\frac {1}{3}}+\left (x^{3}-x \right )^{\frac {2}{3}}}{x^{2}}\right )\right )}{36 {\left (-\left (x^{3}-x \right )^{\frac {1}{3}}+x \right )}^{2} {\left (\left (x^{3}-x \right )^{\frac {2}{3}}+x \left (x +\left (x^{3}-x \right )^{\frac {1}{3}}\right )\right )}^{2}}\) | \(142\) |
trager | \(\frac {x \left (3 x^{2}-1\right ) \left (x^{3}-x \right )^{\frac {1}{3}}}{12}+\frac {\operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) \ln \left (1395 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )^{2} x^{2}+6768 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) \left (x^{3}-x \right )^{\frac {2}{3}}+6768 \left (x^{3}-x \right )^{\frac {1}{3}} \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) x +7233 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) x^{2}-5580 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )^{2}+7611 \left (x^{3}-x \right )^{\frac {2}{3}}+7611 x \left (x^{3}-x \right )^{\frac {1}{3}}+7766 x^{2}-11727 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )-4942\right )}{6}-\frac {\ln \left (1395 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )^{2} x^{2}-6768 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) \left (x^{3}-x \right )^{\frac {2}{3}}-6768 \left (x^{3}-x \right )^{\frac {1}{3}} \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) x -6303 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) x^{2}-5580 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )^{2}+5355 \left (x^{3}-x \right )^{\frac {2}{3}}+5355 x \left (x^{3}-x \right )^{\frac {1}{3}}+5510 x^{2}+8007 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )-1653\right )}{18}-\frac {\ln \left (1395 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )^{2} x^{2}-6768 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) \left (x^{3}-x \right )^{\frac {2}{3}}-6768 \left (x^{3}-x \right )^{\frac {1}{3}} \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) x -6303 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right ) x^{2}-5580 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )^{2}+5355 \left (x^{3}-x \right )^{\frac {2}{3}}+5355 x \left (x^{3}-x \right )^{\frac {1}{3}}+5510 x^{2}+8007 \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )-1653\right ) \operatorname {RootOf}\left (9 \textit {\_Z}^{2}+3 \textit {\_Z} +1\right )}{6}\) | \(463\) |
risch | \(\frac {x \left (3 x^{2}-1\right ) {\left (x \left (x^{2}-1\right )\right )}^{\frac {1}{3}}}{12}+\frac {\left (\frac {\ln \left (-\frac {-35 \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right )^{2} x^{4}-1956 \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right ) x^{4}-4104 \left (x^{6}-2 x^{4}+x^{2}\right )^{\frac {1}{3}} \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right ) x^{2}+175 \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right )^{2} x^{2}+23364 x^{4}+5850 \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right ) \left (x^{6}-2 x^{4}+x^{2}\right )^{\frac {2}{3}}-35100 \left (x^{6}-2 x^{4}+x^{2}\right )^{\frac {1}{3}} x^{2}+2010 \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right ) x^{2}+10476 \left (x^{6}-2 x^{4}+x^{2}\right )^{\frac {2}{3}}+4104 \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right ) \left (x^{6}-2 x^{4}+x^{2}\right )^{\frac {1}{3}}-140 \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right )^{2}-38232 x^{2}+35100 \left (x^{6}-2 x^{4}+x^{2}\right )^{\frac {1}{3}}-54 \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right )+14868}{\left (-1+x \right ) \left (1+x \right )}\right )}{18}+\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right ) \ln \left (\frac {59 \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right )^{2} x^{4}-3750 \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right ) x^{4}-1746 \left (x^{6}-2 x^{4}+x^{2}\right )^{\frac {1}{3}} \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right ) x^{2}-295 \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right )^{2} x^{2}+12600 x^{4}+5850 \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right ) \left (x^{6}-2 x^{4}+x^{2}\right )^{\frac {2}{3}}-35100 \left (x^{6}-2 x^{4}+x^{2}\right )^{\frac {1}{3}} x^{2}+5652 \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right ) x^{2}+24624 \left (x^{6}-2 x^{4}+x^{2}\right )^{\frac {2}{3}}+1746 \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right ) \left (x^{6}-2 x^{4}+x^{2}\right )^{\frac {1}{3}}+236 \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right )^{2}-16380 x^{2}+35100 \left (x^{6}-2 x^{4}+x^{2}\right )^{\frac {1}{3}}-1902 \operatorname {RootOf}\left (\textit {\_Z}^{2}+6 \textit {\_Z} +36\right )+3780}{\left (-1+x \right ) \left (1+x \right )}\right )}{108}\right ) {\left (x \left (x^{2}-1\right )\right )}^{\frac {1}{3}} \left (x^{2} \left (x^{2}-1\right )^{2}\right )^{\frac {1}{3}}}{x \left (x^{2}-1\right )}\) | \(543\) |
Input:
int(x^2*(x^3-x)^(1/3),x,method=_RETURNVERBOSE)
Output:
3/10*signum(x^2-1)^(1/3)/(-signum(x^2-1))^(1/3)*x^(10/3)*hypergeom([-1/3,5 /3],[8/3],x^2)
Time = 0.18 (sec) , antiderivative size = 107, normalized size of antiderivative = 0.96 \[ \int x^2 \sqrt [3]{-x+x^3} \, dx=\frac {1}{18} \, \sqrt {3} \arctan \left (-\frac {44032959556 \, \sqrt {3} {\left (x^{3} - x\right )}^{\frac {1}{3}} x + \sqrt {3} {\left (16754327161 \, x^{2} - 2707204793\right )} - 10524305234 \, \sqrt {3} {\left (x^{3} - x\right )}^{\frac {2}{3}}}{81835897185 \, x^{2} - 1102302937}\right ) + \frac {1}{12} \, {\left (3 \, x^{3} - x\right )} {\left (x^{3} - x\right )}^{\frac {1}{3}} + \frac {1}{36} \, \log \left (-3 \, {\left (x^{3} - x\right )}^{\frac {1}{3}} x + 3 \, {\left (x^{3} - x\right )}^{\frac {2}{3}} + 1\right ) \] Input:
integrate(x^2*(x^3-x)^(1/3),x, algorithm="fricas")
Output:
1/18*sqrt(3)*arctan(-(44032959556*sqrt(3)*(x^3 - x)^(1/3)*x + sqrt(3)*(167 54327161*x^2 - 2707204793) - 10524305234*sqrt(3)*(x^3 - x)^(2/3))/(8183589 7185*x^2 - 1102302937)) + 1/12*(3*x^3 - x)*(x^3 - x)^(1/3) + 1/36*log(-3*( x^3 - x)^(1/3)*x + 3*(x^3 - x)^(2/3) + 1)
\[ \int x^2 \sqrt [3]{-x+x^3} \, dx=\int x^{2} \sqrt [3]{x \left (x - 1\right ) \left (x + 1\right )}\, dx \] Input:
integrate(x**2*(x**3-x)**(1/3),x)
Output:
Integral(x**2*(x*(x - 1)*(x + 1))**(1/3), x)
\[ \int x^2 \sqrt [3]{-x+x^3} \, dx=\int { {\left (x^{3} - x\right )}^{\frac {1}{3}} x^{2} \,d x } \] Input:
integrate(x^2*(x^3-x)^(1/3),x, algorithm="maxima")
Output:
integrate((x^3 - x)^(1/3)*x^2, x)
Time = 0.29 (sec) , antiderivative size = 89, normalized size of antiderivative = 0.79 \[ \int x^2 \sqrt [3]{-x+x^3} \, dx=\frac {1}{12} \, {\left ({\left (-\frac {1}{x^{2}} + 1\right )}^{\frac {4}{3}} + 2 \, {\left (-\frac {1}{x^{2}} + 1\right )}^{\frac {1}{3}}\right )} x^{4} - \frac {1}{18} \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, {\left (-\frac {1}{x^{2}} + 1\right )}^{\frac {1}{3}} + 1\right )}\right ) - \frac {1}{36} \, \log \left ({\left (-\frac {1}{x^{2}} + 1\right )}^{\frac {2}{3}} + {\left (-\frac {1}{x^{2}} + 1\right )}^{\frac {1}{3}} + 1\right ) + \frac {1}{18} \, \log \left ({\left | {\left (-\frac {1}{x^{2}} + 1\right )}^{\frac {1}{3}} - 1 \right |}\right ) \] Input:
integrate(x^2*(x^3-x)^(1/3),x, algorithm="giac")
Output:
1/12*((-1/x^2 + 1)^(4/3) + 2*(-1/x^2 + 1)^(1/3))*x^4 - 1/18*sqrt(3)*arctan (1/3*sqrt(3)*(2*(-1/x^2 + 1)^(1/3) + 1)) - 1/36*log((-1/x^2 + 1)^(2/3) + ( -1/x^2 + 1)^(1/3) + 1) + 1/18*log(abs((-1/x^2 + 1)^(1/3) - 1))
Timed out. \[ \int x^2 \sqrt [3]{-x+x^3} \, dx=\int x^2\,{\left (x^3-x\right )}^{1/3} \,d x \] Input:
int(x^2*(x^3 - x)^(1/3),x)
Output:
int(x^2*(x^3 - x)^(1/3), x)
\[ \int x^2 \sqrt [3]{-x+x^3} \, dx=\frac {x^{\frac {10}{3}} \left (x^{2}-1\right )^{\frac {1}{3}}}{4}-\frac {x^{\frac {4}{3}} \left (x^{2}-1\right )^{\frac {1}{3}}}{12}-\frac {\left (\int \frac {x^{\frac {1}{3}}}{\left (x^{2}-1\right )^{\frac {2}{3}}}d x \right )}{9} \] Input:
int(x^2*(x^3-x)^(1/3),x)
Output:
(9*x**(1/3)*(x**2 - 1)**(1/3)*x**3 - 3*x**(1/3)*(x**2 - 1)**(1/3)*x - 4*in t((x**(1/3)*(x**2 - 1)**(1/3))/(x**2 - 1),x))/36