Integrand size = 15, antiderivative size = 119 \[ \int \sqrt [4]{b x^7+a x^8} \, dx=\frac {\left (-7 b^2+4 a b x+32 a^2 x^2\right ) \sqrt [4]{b x^7+a x^8}}{96 a^2 x}+\frac {7 b^3 \arctan \left (\frac {\sqrt [4]{b x^7+a x^8}}{\sqrt [4]{a} x^2}\right )}{64 a^{11/4}}+\frac {7 b^3 \text {arctanh}\left (\frac {\sqrt [4]{b x^7+a x^8}}{\sqrt [4]{a} x^2}\right )}{64 a^{11/4}} \] Output:
1/96*(32*a^2*x^2+4*a*b*x-7*b^2)*(a*x^8+b*x^7)^(1/4)/a^2/x+7/64*b^3*arctan( (a*x^8+b*x^7)^(1/4)/a^(1/4)/x^2)/a^(11/4)+7/64*b^3*arctanh((a*x^8+b*x^7)^( 1/4)/a^(1/4)/x^2)/a^(11/4)
Time = 0.06 (sec) , antiderivative size = 129, normalized size of antiderivative = 1.08 \[ \int \sqrt [4]{b x^7+a x^8} \, dx=\frac {\sqrt [4]{x^7 (b+a x)} \left (2 a^{3/4} x^{3/4} \sqrt [4]{b+a x} \left (-7 b^2+4 a b x+32 a^2 x^2\right )-21 b^3 \arctan \left (\frac {\sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{b+a x}}\right )+21 b^3 \text {arctanh}\left (\frac {\sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{b+a x}}\right )\right )}{192 a^{11/4} x^{7/4} \sqrt [4]{b+a x}} \] Input:
Integrate[(b*x^7 + a*x^8)^(1/4),x]
Output:
((x^7*(b + a*x))^(1/4)*(2*a^(3/4)*x^(3/4)*(b + a*x)^(1/4)*(-7*b^2 + 4*a*b* x + 32*a^2*x^2) - 21*b^3*ArcTan[(a^(1/4)*x^(1/4))/(b + a*x)^(1/4)] + 21*b^ 3*ArcTanh[(a^(1/4)*x^(1/4))/(b + a*x)^(1/4)]))/(192*a^(11/4)*x^(7/4)*(b + a*x)^(1/4))
Time = 0.37 (sec) , antiderivative size = 176, normalized size of antiderivative = 1.48, number of steps used = 10, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.600, Rules used = {1910, 1930, 1930, 1938, 73, 854, 827, 216, 219}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \sqrt [4]{a x^8+b x^7} \, dx\) |
\(\Big \downarrow \) 1910 |
\(\displaystyle \frac {1}{12} b \int \frac {x^7}{\left (a x^8+b x^7\right )^{3/4}}dx+\frac {1}{3} x \sqrt [4]{a x^8+b x^7}\) |
\(\Big \downarrow \) 1930 |
\(\displaystyle \frac {1}{12} b \left (\frac {\sqrt [4]{a x^8+b x^7}}{2 a}-\frac {7 b \int \frac {x^6}{\left (a x^8+b x^7\right )^{3/4}}dx}{8 a}\right )+\frac {1}{3} x \sqrt [4]{a x^8+b x^7}\) |
\(\Big \downarrow \) 1930 |
\(\displaystyle \frac {1}{12} b \left (\frac {\sqrt [4]{a x^8+b x^7}}{2 a}-\frac {7 b \left (\frac {\sqrt [4]{a x^8+b x^7}}{a x}-\frac {3 b \int \frac {x^5}{\left (a x^8+b x^7\right )^{3/4}}dx}{4 a}\right )}{8 a}\right )+\frac {1}{3} x \sqrt [4]{a x^8+b x^7}\) |
\(\Big \downarrow \) 1938 |
\(\displaystyle \frac {1}{12} b \left (\frac {\sqrt [4]{a x^8+b x^7}}{2 a}-\frac {7 b \left (\frac {\sqrt [4]{a x^8+b x^7}}{a x}-\frac {3 b x^{21/4} (a x+b)^{3/4} \int \frac {1}{\sqrt [4]{x} (b+a x)^{3/4}}dx}{4 a \left (a x^8+b x^7\right )^{3/4}}\right )}{8 a}\right )+\frac {1}{3} x \sqrt [4]{a x^8+b x^7}\) |
\(\Big \downarrow \) 73 |
\(\displaystyle \frac {1}{12} b \left (\frac {\sqrt [4]{a x^8+b x^7}}{2 a}-\frac {7 b \left (\frac {\sqrt [4]{a x^8+b x^7}}{a x}-\frac {3 b x^{21/4} (a x+b)^{3/4} \int \frac {\sqrt {x}}{(b+a x)^{3/4}}d\sqrt [4]{x}}{a \left (a x^8+b x^7\right )^{3/4}}\right )}{8 a}\right )+\frac {1}{3} x \sqrt [4]{a x^8+b x^7}\) |
\(\Big \downarrow \) 854 |
\(\displaystyle \frac {1}{12} b \left (\frac {\sqrt [4]{a x^8+b x^7}}{2 a}-\frac {7 b \left (\frac {\sqrt [4]{a x^8+b x^7}}{a x}-\frac {3 b x^{21/4} (a x+b)^{3/4} \int \frac {\sqrt {x}}{1-a x}d\frac {\sqrt [4]{x}}{\sqrt [4]{b+a x}}}{a \left (a x^8+b x^7\right )^{3/4}}\right )}{8 a}\right )+\frac {1}{3} x \sqrt [4]{a x^8+b x^7}\) |
\(\Big \downarrow \) 827 |
\(\displaystyle \frac {1}{12} b \left (\frac {\sqrt [4]{a x^8+b x^7}}{2 a}-\frac {7 b \left (\frac {\sqrt [4]{a x^8+b x^7}}{a x}-\frac {3 b x^{21/4} (a x+b)^{3/4} \left (\frac {\int \frac {1}{1-\sqrt {a} \sqrt {x}}d\frac {\sqrt [4]{x}}{\sqrt [4]{b+a x}}}{2 \sqrt {a}}-\frac {\int \frac {1}{\sqrt {a} \sqrt {x}+1}d\frac {\sqrt [4]{x}}{\sqrt [4]{b+a x}}}{2 \sqrt {a}}\right )}{a \left (a x^8+b x^7\right )^{3/4}}\right )}{8 a}\right )+\frac {1}{3} x \sqrt [4]{a x^8+b x^7}\) |
\(\Big \downarrow \) 216 |
\(\displaystyle \frac {1}{12} b \left (\frac {\sqrt [4]{a x^8+b x^7}}{2 a}-\frac {7 b \left (\frac {\sqrt [4]{a x^8+b x^7}}{a x}-\frac {3 b x^{21/4} (a x+b)^{3/4} \left (\frac {\int \frac {1}{1-\sqrt {a} \sqrt {x}}d\frac {\sqrt [4]{x}}{\sqrt [4]{b+a x}}}{2 \sqrt {a}}-\frac {\arctan \left (\frac {\sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2 a^{3/4}}\right )}{a \left (a x^8+b x^7\right )^{3/4}}\right )}{8 a}\right )+\frac {1}{3} x \sqrt [4]{a x^8+b x^7}\) |
\(\Big \downarrow \) 219 |
\(\displaystyle \frac {1}{12} b \left (\frac {\sqrt [4]{a x^8+b x^7}}{2 a}-\frac {7 b \left (\frac {\sqrt [4]{a x^8+b x^7}}{a x}-\frac {3 b x^{21/4} (a x+b)^{3/4} \left (\frac {\text {arctanh}\left (\frac {\sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2 a^{3/4}}-\frac {\arctan \left (\frac {\sqrt [4]{a} \sqrt [4]{x}}{\sqrt [4]{a x+b}}\right )}{2 a^{3/4}}\right )}{a \left (a x^8+b x^7\right )^{3/4}}\right )}{8 a}\right )+\frac {1}{3} x \sqrt [4]{a x^8+b x^7}\) |
Input:
Int[(b*x^7 + a*x^8)^(1/4),x]
Output:
(x*(b*x^7 + a*x^8)^(1/4))/3 + (b*((b*x^7 + a*x^8)^(1/4)/(2*a) - (7*b*((b*x ^7 + a*x^8)^(1/4)/(a*x) - (3*b*x^(21/4)*(b + a*x)^(3/4)*(-1/2*ArcTan[(a^(1 /4)*x^(1/4))/(b + a*x)^(1/4)]/a^(3/4) + ArcTanh[(a^(1/4)*x^(1/4))/(b + a*x )^(1/4)]/(2*a^(3/4))))/(a*(b*x^7 + a*x^8)^(3/4))))/(8*a)))/12
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ {p = Denominator[m]}, Simp[p/b Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL inearQ[a, b, c, d, m, n, x]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[b, 2]))*A rcTan[Rt[b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a , 0] || GtQ[b, 0])
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt Q[a, 0] || LtQ[b, 0])
Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 2]], s = Denominator[Rt[-a/b, 2]]}, Simp[s/(2*b) Int[1/(r + s*x^2), x], x] - Simp[s/(2*b) Int[1/(r - s*x^2), x], x]] /; FreeQ[{a, b}, x] && !GtQ [a/b, 0]
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^(p + (m + 1)/n) Subst[Int[x^m/(1 - b*x^n)^(p + (m + 1)/n + 1), x], x, x/(a + b*x^n )^(1/n)], x] /; FreeQ[{a, b}, x] && IGtQ[n, 0] && LtQ[-1, p, 0] && NeQ[p, - 2^(-1)] && IntegersQ[m, p + (m + 1)/n]
Int[((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol] :> Simp[x*((a*x^j + b*x^n)^p/(n*p + 1)), x] + Simp[a*(n - j)*(p/(n*p + 1)) Int[x^j*(a*x^j + b*x^n)^(p - 1), x], x] /; FreeQ[{a, b}, x] && !IntegerQ[p] && LtQ[0, j, n] && GtQ[p, 0] && NeQ[n*p + 1, 0]
Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol ] :> Simp[c^(n - 1)*(c*x)^(m - n + 1)*((a*x^j + b*x^n)^(p + 1)/(b*(m + n*p + 1))), x] - Simp[a*c^(n - j)*((m + j*p - n + j + 1)/(b*(m + n*p + 1))) I nt[(c*x)^(m - (n - j))*(a*x^j + b*x^n)^p, x], x] /; FreeQ[{a, b, c, m, p}, x] && !IntegerQ[p] && LtQ[0, j, n] && (IntegersQ[j, n] || GtQ[c, 0]) && Gt Q[m + j*p - n + j + 1, 0] && NeQ[m + n*p + 1, 0]
Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol ] :> Simp[c^IntPart[m]*(c*x)^FracPart[m]*((a*x^j + b*x^n)^FracPart[p]/(x^(F racPart[m] + j*FracPart[p])*(a + b*x^(n - j))^FracPart[p])) Int[x^(m + j* p)*(a + b*x^(n - j))^p, x], x] /; FreeQ[{a, b, c, j, m, n, p}, x] && !Inte gerQ[p] && NeQ[n, j] && PosQ[n - j]
Time = 0.96 (sec) , antiderivative size = 140, normalized size of antiderivative = 1.18
method | result | size |
pseudoelliptic | \(\frac {128 \left (x^{7} \left (a x +b \right )\right )^{\frac {1}{4}} a^{\frac {11}{4}} x^{2}+16 a^{\frac {7}{4}} b x \left (x^{7} \left (a x +b \right )\right )^{\frac {1}{4}}-28 b^{2} \left (x^{7} \left (a x +b \right )\right )^{\frac {1}{4}} a^{\frac {3}{4}}+21 \ln \left (\frac {a^{\frac {1}{4}} x^{2}+\left (x^{7} \left (a x +b \right )\right )^{\frac {1}{4}}}{-a^{\frac {1}{4}} x^{2}+\left (x^{7} \left (a x +b \right )\right )^{\frac {1}{4}}}\right ) x \,b^{3}+42 \arctan \left (\frac {\left (x^{7} \left (a x +b \right )\right )^{\frac {1}{4}}}{a^{\frac {1}{4}} x^{2}}\right ) x \,b^{3}}{384 a^{\frac {11}{4}} x}\) | \(140\) |
Input:
int((a*x^8+b*x^7)^(1/4),x,method=_RETURNVERBOSE)
Output:
1/384/a^(11/4)/x*(128*(x^7*(a*x+b))^(1/4)*a^(11/4)*x^2+16*a^(7/4)*b*x*(x^7 *(a*x+b))^(1/4)-28*b^2*(x^7*(a*x+b))^(1/4)*a^(3/4)+21*ln((a^(1/4)*x^2+(x^7 *(a*x+b))^(1/4))/(-a^(1/4)*x^2+(x^7*(a*x+b))^(1/4)))*x*b^3+42*arctan((x^7* (a*x+b))^(1/4)/a^(1/4)/x^2)*x*b^3)
Result contains complex when optimal does not.
Time = 0.10 (sec) , antiderivative size = 268, normalized size of antiderivative = 2.25 \[ \int \sqrt [4]{b x^7+a x^8} \, dx=\frac {21 \, a^{2} \left (\frac {b^{12}}{a^{11}}\right )^{\frac {1}{4}} x \log \left (\frac {7 \, {\left (a^{3} \left (\frac {b^{12}}{a^{11}}\right )^{\frac {1}{4}} x^{2} + {\left (a x^{8} + b x^{7}\right )}^{\frac {1}{4}} b^{3}\right )}}{x^{2}}\right ) - 21 \, a^{2} \left (\frac {b^{12}}{a^{11}}\right )^{\frac {1}{4}} x \log \left (-\frac {7 \, {\left (a^{3} \left (\frac {b^{12}}{a^{11}}\right )^{\frac {1}{4}} x^{2} - {\left (a x^{8} + b x^{7}\right )}^{\frac {1}{4}} b^{3}\right )}}{x^{2}}\right ) - 21 i \, a^{2} \left (\frac {b^{12}}{a^{11}}\right )^{\frac {1}{4}} x \log \left (-\frac {7 \, {\left (i \, a^{3} \left (\frac {b^{12}}{a^{11}}\right )^{\frac {1}{4}} x^{2} - {\left (a x^{8} + b x^{7}\right )}^{\frac {1}{4}} b^{3}\right )}}{x^{2}}\right ) + 21 i \, a^{2} \left (\frac {b^{12}}{a^{11}}\right )^{\frac {1}{4}} x \log \left (-\frac {7 \, {\left (-i \, a^{3} \left (\frac {b^{12}}{a^{11}}\right )^{\frac {1}{4}} x^{2} - {\left (a x^{8} + b x^{7}\right )}^{\frac {1}{4}} b^{3}\right )}}{x^{2}}\right ) + 4 \, {\left (a x^{8} + b x^{7}\right )}^{\frac {1}{4}} {\left (32 \, a^{2} x^{2} + 4 \, a b x - 7 \, b^{2}\right )}}{384 \, a^{2} x} \] Input:
integrate((a*x^8+b*x^7)^(1/4),x, algorithm="fricas")
Output:
1/384*(21*a^2*(b^12/a^11)^(1/4)*x*log(7*(a^3*(b^12/a^11)^(1/4)*x^2 + (a*x^ 8 + b*x^7)^(1/4)*b^3)/x^2) - 21*a^2*(b^12/a^11)^(1/4)*x*log(-7*(a^3*(b^12/ a^11)^(1/4)*x^2 - (a*x^8 + b*x^7)^(1/4)*b^3)/x^2) - 21*I*a^2*(b^12/a^11)^( 1/4)*x*log(-7*(I*a^3*(b^12/a^11)^(1/4)*x^2 - (a*x^8 + b*x^7)^(1/4)*b^3)/x^ 2) + 21*I*a^2*(b^12/a^11)^(1/4)*x*log(-7*(-I*a^3*(b^12/a^11)^(1/4)*x^2 - ( a*x^8 + b*x^7)^(1/4)*b^3)/x^2) + 4*(a*x^8 + b*x^7)^(1/4)*(32*a^2*x^2 + 4*a *b*x - 7*b^2))/(a^2*x)
\[ \int \sqrt [4]{b x^7+a x^8} \, dx=\int \sqrt [4]{a x^{8} + b x^{7}}\, dx \] Input:
integrate((a*x**8+b*x**7)**(1/4),x)
Output:
Integral((a*x**8 + b*x**7)**(1/4), x)
\[ \int \sqrt [4]{b x^7+a x^8} \, dx=\int { {\left (a x^{8} + b x^{7}\right )}^{\frac {1}{4}} \,d x } \] Input:
integrate((a*x^8+b*x^7)^(1/4),x, algorithm="maxima")
Output:
integrate((a*x^8 + b*x^7)^(1/4), x)
Leaf count of result is larger than twice the leaf count of optimal. 240 vs. \(2 (99) = 198\).
Time = 0.25 (sec) , antiderivative size = 240, normalized size of antiderivative = 2.02 \[ \int \sqrt [4]{b x^7+a x^8} \, dx=-\frac {1}{768} \, b^{3} {\left (\frac {8 \, {\left (7 \, {\left (a + \frac {b}{x}\right )}^{\frac {9}{4}} - 18 \, {\left (a + \frac {b}{x}\right )}^{\frac {5}{4}} a - 21 \, {\left (a + \frac {b}{x}\right )}^{\frac {1}{4}} a^{2}\right )} x^{3}}{a^{2} b^{3}} - \frac {42 \, \sqrt {2} \left (-a\right )^{\frac {1}{4}} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (-a\right )^{\frac {1}{4}} + 2 \, {\left (a + \frac {b}{x}\right )}^{\frac {1}{4}}\right )}}{2 \, \left (-a\right )^{\frac {1}{4}}}\right )}{a^{3}} - \frac {42 \, \sqrt {2} \left (-a\right )^{\frac {1}{4}} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (-a\right )^{\frac {1}{4}} - 2 \, {\left (a + \frac {b}{x}\right )}^{\frac {1}{4}}\right )}}{2 \, \left (-a\right )^{\frac {1}{4}}}\right )}{a^{3}} - \frac {21 \, \sqrt {2} \left (-a\right )^{\frac {1}{4}} \log \left (\sqrt {2} \left (-a\right )^{\frac {1}{4}} {\left (a + \frac {b}{x}\right )}^{\frac {1}{4}} + \sqrt {-a} + \sqrt {a + \frac {b}{x}}\right )}{a^{3}} + \frac {21 \, \sqrt {2} \left (-a\right )^{\frac {1}{4}} \log \left (-\sqrt {2} \left (-a\right )^{\frac {1}{4}} {\left (a + \frac {b}{x}\right )}^{\frac {1}{4}} + \sqrt {-a} + \sqrt {a + \frac {b}{x}}\right )}{a^{3}}\right )} \] Input:
integrate((a*x^8+b*x^7)^(1/4),x, algorithm="giac")
Output:
-1/768*b^3*(8*(7*(a + b/x)^(9/4) - 18*(a + b/x)^(5/4)*a - 21*(a + b/x)^(1/ 4)*a^2)*x^3/(a^2*b^3) - 42*sqrt(2)*(-a)^(1/4)*arctan(1/2*sqrt(2)*(sqrt(2)* (-a)^(1/4) + 2*(a + b/x)^(1/4))/(-a)^(1/4))/a^3 - 42*sqrt(2)*(-a)^(1/4)*ar ctan(-1/2*sqrt(2)*(sqrt(2)*(-a)^(1/4) - 2*(a + b/x)^(1/4))/(-a)^(1/4))/a^3 - 21*sqrt(2)*(-a)^(1/4)*log(sqrt(2)*(-a)^(1/4)*(a + b/x)^(1/4) + sqrt(-a) + sqrt(a + b/x))/a^3 + 21*sqrt(2)*(-a)^(1/4)*log(-sqrt(2)*(-a)^(1/4)*(a + b/x)^(1/4) + sqrt(-a) + sqrt(a + b/x))/a^3)
Time = 8.39 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.32 \[ \int \sqrt [4]{b x^7+a x^8} \, dx=\frac {4\,x\,{\left (a\,x^8+b\,x^7\right )}^{1/4}\,{{}}_2{\mathrm {F}}_1\left (-\frac {1}{4},\frac {11}{4};\ \frac {15}{4};\ -\frac {a\,x}{b}\right )}{11\,{\left (\frac {a\,x}{b}+1\right )}^{1/4}} \] Input:
int((a*x^8 + b*x^7)^(1/4),x)
Output:
(4*x*(a*x^8 + b*x^7)^(1/4)*hypergeom([-1/4, 11/4], 15/4, -(a*x)/b))/(11*(( a*x)/b + 1)^(1/4))
\[ \int \sqrt [4]{b x^7+a x^8} \, dx=\frac {128 x^{\frac {11}{4}} \left (a x +b \right )^{\frac {1}{4}} a^{2}+16 x^{\frac {7}{4}} \left (a x +b \right )^{\frac {1}{4}} a b -28 x^{\frac {3}{4}} \left (a x +b \right )^{\frac {1}{4}} b^{2}+21 \left (\int \frac {\left (a x +b \right )^{\frac {1}{4}}}{x^{\frac {5}{4}} a +x^{\frac {1}{4}} b}d x \right ) b^{3}}{384 a^{2}} \] Input:
int((a*x^8+b*x^7)^(1/4),x)
Output:
(128*x**(3/4)*(a*x + b)**(1/4)*a**2*x**2 + 16*x**(3/4)*(a*x + b)**(1/4)*a* b*x - 28*x**(3/4)*(a*x + b)**(1/4)*b**2 + 21*int((a*x + b)**(1/4)/(x**(1/4 )*a*x + x**(1/4)*b),x)*b**3)/(384*a**2)