Integrand size = 18, antiderivative size = 981 \[ \int \frac {\log \left (x+\sqrt {1+x}\right )}{1+x^2} \, dx =\text {Too large to display} \] Output:
1/2*I*ln((1+I)^(1/2)+(1+x)^(1/2))*ln((1+5^(1/2)+2*(1+x)^(1/2))/(1-2*(1+I)^ (1/2)+5^(1/2)))+1/2*I*ln((1-I)^(1/2)-(1+x)^(1/2))*ln(x+(1+x)^(1/2))-1/2*I* ln((1+I)^(1/2)-(1+x)^(1/2))*ln(x+(1+x)^(1/2))-1/2*I*ln((1-I)^(1/2)-(1+x)^( 1/2))*ln((1+5^(1/2)+2*(1+x)^(1/2))/(1+2*(1-I)^(1/2)+5^(1/2)))+1/2*I*ln((1+ I)^(1/2)-(1+x)^(1/2))*ln((1+5^(1/2)+2*(1+x)^(1/2))/(1+2*(1+I)^(1/2)+5^(1/2 )))-1/2*I*ln((1-I)^(1/2)+(1+x)^(1/2))*ln((1-5^(1/2)+2*(1+x)^(1/2))/(1-2*(1 -I)^(1/2)-5^(1/2)))+1/2*I*polylog(2,2*((1+I)^(1/2)-(1+x)^(1/2))/(1+2*(1+I) ^(1/2)-5^(1/2)))-1/2*I*polylog(2,-2*((1-I)^(1/2)+(1+x)^(1/2))/(1-2*(1-I)^( 1/2)+5^(1/2)))-1/2*I*ln((1-I)^(1/2)-(1+x)^(1/2))*ln((1-5^(1/2)+2*(1+x)^(1/ 2))/(1+2*(1-I)^(1/2)-5^(1/2)))-1/2*I*polylog(2,-2*((1-I)^(1/2)+(1+x)^(1/2) )/(1-2*(1-I)^(1/2)-5^(1/2)))+1/2*I*polylog(2,-2*((1+I)^(1/2)+(1+x)^(1/2))/ (1-2*(1+I)^(1/2)-5^(1/2)))-1/2*I*ln((1-I)^(1/2)+(1+x)^(1/2))*ln((1+5^(1/2) +2*(1+x)^(1/2))/(1-2*(1-I)^(1/2)+5^(1/2)))+1/2*I*ln(x+(1+x)^(1/2))*ln((1-I )^(1/2)+(1+x)^(1/2))+1/2*I*ln((1+I)^(1/2)+(1+x)^(1/2))*ln((1-5^(1/2)+2*(1+ x)^(1/2))/(1-2*(1+I)^(1/2)-5^(1/2)))+1/2*I*ln((1+I)^(1/2)-(1+x)^(1/2))*ln( (1-5^(1/2)+2*(1+x)^(1/2))/(1+2*(1+I)^(1/2)-5^(1/2)))-1/2*I*polylog(2,2*((1 -I)^(1/2)-(1+x)^(1/2))/(1+2*(1-I)^(1/2)+5^(1/2)))+1/2*I*polylog(2,2*((1+I) ^(1/2)-(1+x)^(1/2))/(1+2*(1+I)^(1/2)+5^(1/2)))+1/2*I*polylog(2,-2*((1+I)^( 1/2)+(1+x)^(1/2))/(1-2*(1+I)^(1/2)+5^(1/2)))-1/2*I*polylog(2,2*((1-I)^(1/2 )-(1+x)^(1/2))/(1+2*(1-I)^(1/2)-5^(1/2)))-1/2*I*ln(x+(1+x)^(1/2))*ln((1...
\[ \int \frac {\log \left (x+\sqrt {1+x}\right )}{1+x^2} \, dx=\int \frac {\log \left (x+\sqrt {1+x}\right )}{1+x^2} \, dx \] Input:
Integrate[Log[x + Sqrt[1 + x]]/(1 + x^2),x]
Output:
Integrate[Log[x + Sqrt[1 + x]]/(1 + x^2), x]
Time = 1.40 (sec) , antiderivative size = 983, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {3010, 7292, 3008, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\log \left (x+\sqrt {x+1}\right )}{x^2+1} \, dx\) |
\(\Big \downarrow \) 3010 |
\(\displaystyle 2 \int \frac {\sqrt {x+1} \log \left (x+\sqrt {x+1}\right )}{x^2+1}d\sqrt {x+1}\) |
\(\Big \downarrow \) 7292 |
\(\displaystyle 2 \int \frac {\sqrt {x+1} \log \left (x+\sqrt {x+1}\right )}{(x+1)^2-2 (x+1)+2}d\sqrt {x+1}\) |
\(\Big \downarrow \) 3008 |
\(\displaystyle 2 \int \left (\frac {i \sqrt {x+1} \log \left (x+\sqrt {x+1}\right )}{(2+2 i)-2 (x+1)}+\frac {i \sqrt {x+1} \log \left (x+\sqrt {x+1}\right )}{2 (x+1)-(2-2 i)}\right )d\sqrt {x+1}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle 2 \left (\frac {1}{4} i \log \left (\sqrt {1-i}-\sqrt {x+1}\right ) \log \left (x+\sqrt {x+1}\right )-\frac {1}{4} i \log \left (\sqrt {1+i}-\sqrt {x+1}\right ) \log \left (x+\sqrt {x+1}\right )+\frac {1}{4} i \log \left (\sqrt {x+1}+\sqrt {1-i}\right ) \log \left (x+\sqrt {x+1}\right )-\frac {1}{4} i \log \left (\sqrt {x+1}+\sqrt {1+i}\right ) \log \left (x+\sqrt {x+1}\right )-\frac {1}{4} i \log \left (\sqrt {x+1}+\sqrt {1-i}\right ) \log \left (\frac {2 \sqrt {x+1}-\sqrt {5}+1}{1-2 \sqrt {1-i}-\sqrt {5}}\right )-\frac {1}{4} i \log \left (\sqrt {1-i}-\sqrt {x+1}\right ) \log \left (\frac {2 \sqrt {x+1}-\sqrt {5}+1}{1+2 \sqrt {1-i}-\sqrt {5}}\right )+\frac {1}{4} i \log \left (\sqrt {x+1}+\sqrt {1+i}\right ) \log \left (\frac {2 \sqrt {x+1}-\sqrt {5}+1}{1-2 \sqrt {1+i}-\sqrt {5}}\right )+\frac {1}{4} i \log \left (\sqrt {1+i}-\sqrt {x+1}\right ) \log \left (\frac {2 \sqrt {x+1}-\sqrt {5}+1}{1+2 \sqrt {1+i}-\sqrt {5}}\right )-\frac {1}{4} i \log \left (\sqrt {x+1}+\sqrt {1-i}\right ) \log \left (\frac {2 \sqrt {x+1}+\sqrt {5}+1}{1-2 \sqrt {1-i}+\sqrt {5}}\right )-\frac {1}{4} i \log \left (\sqrt {1-i}-\sqrt {x+1}\right ) \log \left (\frac {2 \sqrt {x+1}+\sqrt {5}+1}{1+2 \sqrt {1-i}+\sqrt {5}}\right )+\frac {1}{4} i \log \left (\sqrt {x+1}+\sqrt {1+i}\right ) \log \left (\frac {2 \sqrt {x+1}+\sqrt {5}+1}{1-2 \sqrt {1+i}+\sqrt {5}}\right )+\frac {1}{4} i \log \left (\sqrt {1+i}-\sqrt {x+1}\right ) \log \left (\frac {2 \sqrt {x+1}+\sqrt {5}+1}{1+2 \sqrt {1+i}+\sqrt {5}}\right )-\frac {1}{4} i \operatorname {PolyLog}\left (2,\frac {2 \left (\sqrt {1-i}-\sqrt {x+1}\right )}{1+2 \sqrt {1-i}-\sqrt {5}}\right )-\frac {1}{4} i \operatorname {PolyLog}\left (2,\frac {2 \left (\sqrt {1-i}-\sqrt {x+1}\right )}{1+2 \sqrt {1-i}+\sqrt {5}}\right )+\frac {1}{4} i \operatorname {PolyLog}\left (2,\frac {2 \left (\sqrt {1+i}-\sqrt {x+1}\right )}{1+2 \sqrt {1+i}-\sqrt {5}}\right )+\frac {1}{4} i \operatorname {PolyLog}\left (2,\frac {2 \left (\sqrt {1+i}-\sqrt {x+1}\right )}{1+2 \sqrt {1+i}+\sqrt {5}}\right )-\frac {1}{4} i \operatorname {PolyLog}\left (2,-\frac {2 \left (\sqrt {x+1}+\sqrt {1-i}\right )}{1-2 \sqrt {1-i}-\sqrt {5}}\right )-\frac {1}{4} i \operatorname {PolyLog}\left (2,-\frac {2 \left (\sqrt {x+1}+\sqrt {1-i}\right )}{1-2 \sqrt {1-i}+\sqrt {5}}\right )+\frac {1}{4} i \operatorname {PolyLog}\left (2,-\frac {2 \left (\sqrt {x+1}+\sqrt {1+i}\right )}{1-2 \sqrt {1+i}-\sqrt {5}}\right )+\frac {1}{4} i \operatorname {PolyLog}\left (2,-\frac {2 \left (\sqrt {x+1}+\sqrt {1+i}\right )}{1-2 \sqrt {1+i}+\sqrt {5}}\right )\right )\) |
Input:
Int[Log[x + Sqrt[1 + x]]/(1 + x^2),x]
Output:
2*((I/4)*Log[Sqrt[1 - I] - Sqrt[1 + x]]*Log[x + Sqrt[1 + x]] - (I/4)*Log[S qrt[1 + I] - Sqrt[1 + x]]*Log[x + Sqrt[1 + x]] + (I/4)*Log[Sqrt[1 - I] + S qrt[1 + x]]*Log[x + Sqrt[1 + x]] - (I/4)*Log[Sqrt[1 + I] + Sqrt[1 + x]]*Lo g[x + Sqrt[1 + x]] - (I/4)*Log[Sqrt[1 - I] + Sqrt[1 + x]]*Log[(1 - Sqrt[5] + 2*Sqrt[1 + x])/(1 - 2*Sqrt[1 - I] - Sqrt[5])] - (I/4)*Log[Sqrt[1 - I] - Sqrt[1 + x]]*Log[(1 - Sqrt[5] + 2*Sqrt[1 + x])/(1 + 2*Sqrt[1 - I] - Sqrt[ 5])] + (I/4)*Log[Sqrt[1 + I] + Sqrt[1 + x]]*Log[(1 - Sqrt[5] + 2*Sqrt[1 + x])/(1 - 2*Sqrt[1 + I] - Sqrt[5])] + (I/4)*Log[Sqrt[1 + I] - Sqrt[1 + x]]* Log[(1 - Sqrt[5] + 2*Sqrt[1 + x])/(1 + 2*Sqrt[1 + I] - Sqrt[5])] - (I/4)*L og[Sqrt[1 - I] + Sqrt[1 + x]]*Log[(1 + Sqrt[5] + 2*Sqrt[1 + x])/(1 - 2*Sqr t[1 - I] + Sqrt[5])] - (I/4)*Log[Sqrt[1 - I] - Sqrt[1 + x]]*Log[(1 + Sqrt[ 5] + 2*Sqrt[1 + x])/(1 + 2*Sqrt[1 - I] + Sqrt[5])] + (I/4)*Log[Sqrt[1 + I] + Sqrt[1 + x]]*Log[(1 + Sqrt[5] + 2*Sqrt[1 + x])/(1 - 2*Sqrt[1 + I] + Sqr t[5])] + (I/4)*Log[Sqrt[1 + I] - Sqrt[1 + x]]*Log[(1 + Sqrt[5] + 2*Sqrt[1 + x])/(1 + 2*Sqrt[1 + I] + Sqrt[5])] - (I/4)*PolyLog[2, (2*(Sqrt[1 - I] - Sqrt[1 + x]))/(1 + 2*Sqrt[1 - I] - Sqrt[5])] - (I/4)*PolyLog[2, (2*(Sqrt[1 - I] - Sqrt[1 + x]))/(1 + 2*Sqrt[1 - I] + Sqrt[5])] + (I/4)*PolyLog[2, (2 *(Sqrt[1 + I] - Sqrt[1 + x]))/(1 + 2*Sqrt[1 + I] - Sqrt[5])] + (I/4)*PolyL og[2, (2*(Sqrt[1 + I] - Sqrt[1 + x]))/(1 + 2*Sqrt[1 + I] + Sqrt[5])] - (I/ 4)*PolyLog[2, (-2*(Sqrt[1 - I] + Sqrt[1 + x]))/(1 - 2*Sqrt[1 - I] - Sqr...
Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)*(RGx_), x_Symbol] :> With [{u = ExpandIntegrand[(a + b*Log[c*RFx^p])^n, RGx, x]}, Int[u, x] /; SumQ[u ]] /; FreeQ[{a, b, c, p}, x] && RationalFunctionQ[RFx, x] && RationalFuncti onQ[RGx, x] && IGtQ[n, 0]
Int[((a_.) + Log[u_]*(b_.))*(RFx_), x_Symbol] :> With[{lst = SubstForFracti onalPowerOfLinear[RFx*(a + b*Log[u]), x]}, Simp[lst[[2]]*lst[[4]] Subst[I nt[lst[[1]], x], x, lst[[3]]^(1/lst[[2]])], x] /; !FalseQ[lst]] /; FreeQ[{ a, b}, x] && RationalFunctionQ[RFx, x]
Time = 0.11 (sec) , antiderivative size = 722, normalized size of antiderivative = 0.74
method | result | size |
derivativedivides | \(\frac {i \left (\ln \left (\sqrt {1+x}-\sqrt {1-i}\right ) \ln \left (x +\sqrt {1+x}\right )-\ln \left (\sqrt {1+x}-\sqrt {1-i}\right ) \ln \left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1-i}-\sqrt {5}}\right )-\ln \left (\sqrt {1+x}-\sqrt {1-i}\right ) \ln \left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1-i}+\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1-i}-\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1-i}+\sqrt {5}}\right )\right )}{2}+\frac {i \left (\ln \left (\sqrt {1-i}+\sqrt {1+x}\right ) \ln \left (x +\sqrt {1+x}\right )-\ln \left (\sqrt {1-i}+\sqrt {1+x}\right ) \ln \left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1-i}-\sqrt {5}}\right )-\ln \left (\sqrt {1-i}+\sqrt {1+x}\right ) \ln \left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1-i}+\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1-i}-\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1-i}+\sqrt {5}}\right )\right )}{2}-\frac {i \left (\ln \left (\sqrt {1+x}-\sqrt {1+i}\right ) \ln \left (x +\sqrt {1+x}\right )-\ln \left (\sqrt {1+x}-\sqrt {1+i}\right ) \ln \left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1+i}-\sqrt {5}}\right )-\ln \left (\sqrt {1+x}-\sqrt {1+i}\right ) \ln \left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1+i}+\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1+i}-\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1+i}+\sqrt {5}}\right )\right )}{2}-\frac {i \left (\ln \left (\sqrt {1+i}+\sqrt {1+x}\right ) \ln \left (x +\sqrt {1+x}\right )-\ln \left (\sqrt {1+i}+\sqrt {1+x}\right ) \ln \left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1+i}-\sqrt {5}}\right )-\ln \left (\sqrt {1+i}+\sqrt {1+x}\right ) \ln \left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1+i}+\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1+i}-\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1+i}+\sqrt {5}}\right )\right )}{2}\) | \(722\) |
default | \(\frac {i \left (\ln \left (\sqrt {1+x}-\sqrt {1-i}\right ) \ln \left (x +\sqrt {1+x}\right )-\ln \left (\sqrt {1+x}-\sqrt {1-i}\right ) \ln \left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1-i}-\sqrt {5}}\right )-\ln \left (\sqrt {1+x}-\sqrt {1-i}\right ) \ln \left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1-i}+\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1-i}-\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1-i}+\sqrt {5}}\right )\right )}{2}+\frac {i \left (\ln \left (\sqrt {1-i}+\sqrt {1+x}\right ) \ln \left (x +\sqrt {1+x}\right )-\ln \left (\sqrt {1-i}+\sqrt {1+x}\right ) \ln \left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1-i}-\sqrt {5}}\right )-\ln \left (\sqrt {1-i}+\sqrt {1+x}\right ) \ln \left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1-i}+\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1-i}-\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1-i}+\sqrt {5}}\right )\right )}{2}-\frac {i \left (\ln \left (\sqrt {1+x}-\sqrt {1+i}\right ) \ln \left (x +\sqrt {1+x}\right )-\ln \left (\sqrt {1+x}-\sqrt {1+i}\right ) \ln \left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1+i}-\sqrt {5}}\right )-\ln \left (\sqrt {1+x}-\sqrt {1+i}\right ) \ln \left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1+i}+\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1+i}-\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1+i}+\sqrt {5}}\right )\right )}{2}-\frac {i \left (\ln \left (\sqrt {1+i}+\sqrt {1+x}\right ) \ln \left (x +\sqrt {1+x}\right )-\ln \left (\sqrt {1+i}+\sqrt {1+x}\right ) \ln \left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1+i}-\sqrt {5}}\right )-\ln \left (\sqrt {1+i}+\sqrt {1+x}\right ) \ln \left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1+i}+\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1+i}-\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1+i}+\sqrt {5}}\right )\right )}{2}\) | \(722\) |
parts | \(\frac {i \left (\ln \left (\sqrt {1+x}-\sqrt {1-i}\right ) \ln \left (x +\sqrt {1+x}\right )-\ln \left (\sqrt {1+x}-\sqrt {1-i}\right ) \ln \left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1-i}-\sqrt {5}}\right )-\ln \left (\sqrt {1+x}-\sqrt {1-i}\right ) \ln \left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1-i}+\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1-i}-\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1-i}+\sqrt {5}}\right )\right )}{2}+\frac {i \left (\ln \left (\sqrt {1-i}+\sqrt {1+x}\right ) \ln \left (x +\sqrt {1+x}\right )-\ln \left (\sqrt {1-i}+\sqrt {1+x}\right ) \ln \left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1-i}-\sqrt {5}}\right )-\ln \left (\sqrt {1-i}+\sqrt {1+x}\right ) \ln \left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1-i}+\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1-i}-\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1-i}+\sqrt {5}}\right )\right )}{2}-\frac {i \left (\ln \left (\sqrt {1+x}-\sqrt {1+i}\right ) \ln \left (x +\sqrt {1+x}\right )-\ln \left (\sqrt {1+x}-\sqrt {1+i}\right ) \ln \left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1+i}-\sqrt {5}}\right )-\ln \left (\sqrt {1+x}-\sqrt {1+i}\right ) \ln \left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1+i}+\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1+i}-\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1+2 \sqrt {1+i}+\sqrt {5}}\right )\right )}{2}-\frac {i \left (\ln \left (\sqrt {1+i}+\sqrt {1+x}\right ) \ln \left (x +\sqrt {1+x}\right )-\ln \left (\sqrt {1+i}+\sqrt {1+x}\right ) \ln \left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1+i}-\sqrt {5}}\right )-\ln \left (\sqrt {1+i}+\sqrt {1+x}\right ) \ln \left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1+i}+\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1-\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1+i}-\sqrt {5}}\right )-\operatorname {dilog}\left (\frac {1+\sqrt {5}+2 \sqrt {1+x}}{1-2 \sqrt {1+i}+\sqrt {5}}\right )\right )}{2}\) | \(722\) |
Input:
int(ln(x+(1+x)^(1/2))/(x^2+1),x,method=_RETURNVERBOSE)
Output:
1/2*I*(ln((1+x)^(1/2)-(1-I)^(1/2))*ln(x+(1+x)^(1/2))-ln((1+x)^(1/2)-(1-I)^ (1/2))*ln((1-5^(1/2)+2*(1+x)^(1/2))/(1+2*(1-I)^(1/2)-5^(1/2)))-ln((1+x)^(1 /2)-(1-I)^(1/2))*ln((1+5^(1/2)+2*(1+x)^(1/2))/(1+2*(1-I)^(1/2)+5^(1/2)))-d ilog((1-5^(1/2)+2*(1+x)^(1/2))/(1+2*(1-I)^(1/2)-5^(1/2)))-dilog((1+5^(1/2) +2*(1+x)^(1/2))/(1+2*(1-I)^(1/2)+5^(1/2))))+1/2*I*(ln((1-I)^(1/2)+(1+x)^(1 /2))*ln(x+(1+x)^(1/2))-ln((1-I)^(1/2)+(1+x)^(1/2))*ln((1-5^(1/2)+2*(1+x)^( 1/2))/(1-2*(1-I)^(1/2)-5^(1/2)))-ln((1-I)^(1/2)+(1+x)^(1/2))*ln((1+5^(1/2) +2*(1+x)^(1/2))/(1-2*(1-I)^(1/2)+5^(1/2)))-dilog((1-5^(1/2)+2*(1+x)^(1/2)) /(1-2*(1-I)^(1/2)-5^(1/2)))-dilog((1+5^(1/2)+2*(1+x)^(1/2))/(1-2*(1-I)^(1/ 2)+5^(1/2))))-1/2*I*(ln((1+x)^(1/2)-(1+I)^(1/2))*ln(x+(1+x)^(1/2))-ln((1+x )^(1/2)-(1+I)^(1/2))*ln((1-5^(1/2)+2*(1+x)^(1/2))/(1+2*(1+I)^(1/2)-5^(1/2) ))-ln((1+x)^(1/2)-(1+I)^(1/2))*ln((1+5^(1/2)+2*(1+x)^(1/2))/(1+2*(1+I)^(1/ 2)+5^(1/2)))-dilog((1-5^(1/2)+2*(1+x)^(1/2))/(1+2*(1+I)^(1/2)-5^(1/2)))-di log((1+5^(1/2)+2*(1+x)^(1/2))/(1+2*(1+I)^(1/2)+5^(1/2))))-1/2*I*(ln((1+I)^ (1/2)+(1+x)^(1/2))*ln(x+(1+x)^(1/2))-ln((1+I)^(1/2)+(1+x)^(1/2))*ln((1-5^( 1/2)+2*(1+x)^(1/2))/(1-2*(1+I)^(1/2)-5^(1/2)))-ln((1+I)^(1/2)+(1+x)^(1/2)) *ln((1+5^(1/2)+2*(1+x)^(1/2))/(1-2*(1+I)^(1/2)+5^(1/2)))-dilog((1-5^(1/2)+ 2*(1+x)^(1/2))/(1-2*(1+I)^(1/2)-5^(1/2)))-dilog((1+5^(1/2)+2*(1+x)^(1/2))/ (1-2*(1+I)^(1/2)+5^(1/2))))
\[ \int \frac {\log \left (x+\sqrt {1+x}\right )}{1+x^2} \, dx=\int { \frac {\log \left (x + \sqrt {x + 1}\right )}{x^{2} + 1} \,d x } \] Input:
integrate(log(x+(1+x)^(1/2))/(x^2+1),x, algorithm="fricas")
Output:
integral(log(x + sqrt(x + 1))/(x^2 + 1), x)
\[ \int \frac {\log \left (x+\sqrt {1+x}\right )}{1+x^2} \, dx=\int \frac {\log {\left (x + \sqrt {x + 1} \right )}}{x^{2} + 1}\, dx \] Input:
integrate(ln(x+(1+x)**(1/2))/(x**2+1),x)
Output:
Integral(log(x + sqrt(x + 1))/(x**2 + 1), x)
\[ \int \frac {\log \left (x+\sqrt {1+x}\right )}{1+x^2} \, dx=\int { \frac {\log \left (x + \sqrt {x + 1}\right )}{x^{2} + 1} \,d x } \] Input:
integrate(log(x+(1+x)^(1/2))/(x^2+1),x, algorithm="maxima")
Output:
integrate(log(x + sqrt(x + 1))/(x^2 + 1), x)
\[ \int \frac {\log \left (x+\sqrt {1+x}\right )}{1+x^2} \, dx=\int { \frac {\log \left (x + \sqrt {x + 1}\right )}{x^{2} + 1} \,d x } \] Input:
integrate(log(x+(1+x)^(1/2))/(x^2+1),x, algorithm="giac")
Output:
integrate(log(x + sqrt(x + 1))/(x^2 + 1), x)
Timed out. \[ \int \frac {\log \left (x+\sqrt {1+x}\right )}{1+x^2} \, dx=\int \frac {\ln \left (x+\sqrt {x+1}\right )}{x^2+1} \,d x \] Input:
int(log(x + (x + 1)^(1/2))/(x^2 + 1),x)
Output:
int(log(x + (x + 1)^(1/2))/(x^2 + 1), x)
\[ \int \frac {\log \left (x+\sqrt {1+x}\right )}{1+x^2} \, dx=\int \frac {\mathrm {log}\left (\sqrt {x +1}+x \right )}{x^{2}+1}d x \] Input:
int(log(x+(1+x)^(1/2))/(x^2+1),x)
Output:
int(log(sqrt(x + 1) + x)/(x**2 + 1),x)