Integrand size = 15, antiderivative size = 102 \[ \int \frac {1}{x^{7/4} (a+b x)^{7/4}} \, dx=\frac {4}{3 a x^{3/4} (a+b x)^{3/4}}-\frac {8 \sqrt [4]{a+b x}}{3 a^2 x^{3/4}}+\frac {16 \left (\frac {b x}{a+b x}\right )^{3/4} (a+b x)^{3/4} \operatorname {EllipticF}\left (\frac {1}{2} \arcsin \left (\frac {\sqrt {a}}{\sqrt {a+b x}}\right ),2\right )}{3 a^{5/2} x^{3/4}} \] Output:
4/3/a/x^(3/4)/(b*x+a)^(3/4)-8/3*(b*x+a)^(1/4)/a^2/x^(3/4)+16/3*(b*x/(b*x+a ))^(3/4)*(b*x+a)^(3/4)*InverseJacobiAM(1/2*arcsin(a^(1/2)/(b*x+a)^(1/2)),2 ^(1/2))/a^(5/2)/x^(3/4)
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.01 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.49 \[ \int \frac {1}{x^{7/4} (a+b x)^{7/4}} \, dx=-\frac {4 \left (1+\frac {b x}{a}\right )^{3/4} \operatorname {Hypergeometric2F1}\left (-\frac {3}{4},\frac {7}{4},\frac {1}{4},-\frac {b x}{a}\right )}{3 a x^{3/4} (a+b x)^{3/4}} \] Input:
Integrate[1/(x^(7/4)*(a + b*x)^(7/4)),x]
Output:
(-4*(1 + (b*x)/a)^(3/4)*Hypergeometric2F1[-3/4, 7/4, 1/4, -((b*x)/a)])/(3* a*x^(3/4)*(a + b*x)^(3/4))
Time = 0.23 (sec) , antiderivative size = 114, normalized size of antiderivative = 1.12, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.467, Rules used = {61, 61, 73, 768, 858, 807, 229}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{x^{7/4} (a+b x)^{7/4}} \, dx\) |
\(\Big \downarrow \) 61 |
\(\displaystyle \frac {2 \int \frac {1}{x^{7/4} (a+b x)^{3/4}}dx}{a}+\frac {4}{3 a x^{3/4} (a+b x)^{3/4}}\) |
\(\Big \downarrow \) 61 |
\(\displaystyle \frac {2 \left (-\frac {2 b \int \frac {1}{x^{3/4} (a+b x)^{3/4}}dx}{3 a}-\frac {4 \sqrt [4]{a+b x}}{3 a x^{3/4}}\right )}{a}+\frac {4}{3 a x^{3/4} (a+b x)^{3/4}}\) |
\(\Big \downarrow \) 73 |
\(\displaystyle \frac {2 \left (-\frac {8 b \int \frac {1}{(a+b x)^{3/4}}d\sqrt [4]{x}}{3 a}-\frac {4 \sqrt [4]{a+b x}}{3 a x^{3/4}}\right )}{a}+\frac {4}{3 a x^{3/4} (a+b x)^{3/4}}\) |
\(\Big \downarrow \) 768 |
\(\displaystyle \frac {2 \left (-\frac {8 b x^{3/4} \left (\frac {a}{b x}+1\right )^{3/4} \int \frac {1}{\left (\frac {a}{b x}+1\right )^{3/4} x^{3/4}}d\sqrt [4]{x}}{3 a (a+b x)^{3/4}}-\frac {4 \sqrt [4]{a+b x}}{3 a x^{3/4}}\right )}{a}+\frac {4}{3 a x^{3/4} (a+b x)^{3/4}}\) |
\(\Big \downarrow \) 858 |
\(\displaystyle \frac {2 \left (\frac {8 b x^{3/4} \left (\frac {a}{b x}+1\right )^{3/4} \int \frac {1}{\sqrt [4]{x} \left (\frac {a x}{b}+1\right )^{3/4}}d\frac {1}{\sqrt [4]{x}}}{3 a (a+b x)^{3/4}}-\frac {4 \sqrt [4]{a+b x}}{3 a x^{3/4}}\right )}{a}+\frac {4}{3 a x^{3/4} (a+b x)^{3/4}}\) |
\(\Big \downarrow \) 807 |
\(\displaystyle \frac {2 \left (\frac {4 b x^{3/4} \left (\frac {a}{b x}+1\right )^{3/4} \int \frac {1}{\left (\frac {\sqrt {x} a}{b}+1\right )^{3/4}}d\sqrt {x}}{3 a (a+b x)^{3/4}}-\frac {4 \sqrt [4]{a+b x}}{3 a x^{3/4}}\right )}{a}+\frac {4}{3 a x^{3/4} (a+b x)^{3/4}}\) |
\(\Big \downarrow \) 229 |
\(\displaystyle \frac {2 \left (\frac {8 b^{3/2} x^{3/4} \left (\frac {a}{b x}+1\right )^{3/4} \operatorname {EllipticF}\left (\frac {1}{2} \arctan \left (\frac {\sqrt {a} \sqrt {x}}{\sqrt {b}}\right ),2\right )}{3 a^{3/2} (a+b x)^{3/4}}-\frac {4 \sqrt [4]{a+b x}}{3 a x^{3/4}}\right )}{a}+\frac {4}{3 a x^{3/4} (a+b x)^{3/4}}\) |
Input:
Int[1/(x^(7/4)*(a + b*x)^(7/4)),x]
Output:
4/(3*a*x^(3/4)*(a + b*x)^(3/4)) + (2*((-4*(a + b*x)^(1/4))/(3*a*x^(3/4)) + (8*b^(3/2)*(1 + a/(b*x))^(3/4)*x^(3/4)*EllipticF[ArcTan[(Sqrt[a]*Sqrt[x]) /Sqrt[b]]/2, 2])/(3*a^(3/2)*(a + b*x)^(3/4))))/a
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^(n + 1)/((b*c - a*d)*(m + 1))), x] - Simp[d*(( m + n + 2)/((b*c - a*d)*(m + 1))) Int[(a + b*x)^(m + 1)*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && LtQ[m, -1] && !(LtQ[n, -1] && (EqQ[a, 0 ] || (NeQ[c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && IntLinearQ[a, b, c, d , m, n, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ {p = Denominator[m]}, Simp[p/b Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL inearQ[a, b, c, d, m, n, x]
Int[((a_) + (b_.)*(x_)^2)^(-3/4), x_Symbol] :> Simp[(2/(a^(3/4)*Rt[b/a, 2]) )*EllipticF[(1/2)*ArcTan[Rt[b/a, 2]*x], 2], x] /; FreeQ[{a, b}, x] && GtQ[a , 0] && PosQ[b/a]
Int[((a_) + (b_.)*(x_)^4)^(-3/4), x_Symbol] :> Simp[x^3*((1 + a/(b*x^4))^(3 /4)/(a + b*x^4)^(3/4)) Int[1/(x^3*(1 + a/(b*x^4))^(3/4)), x], x] /; FreeQ [{a, b}, x]
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = GCD[m + 1, n]}, Simp[1/k Subst[Int[x^((m + 1)/k - 1)*(a + b*x^(n/k))^p, x], x, x^k], x] /; k != 1] /; FreeQ[{a, b, p}, x] && IGtQ[n, 0] && IntegerQ[m]
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> -Subst[Int[(a + b/x^n)^p/x^(m + 2), x], x, 1/x] /; FreeQ[{a, b, p}, x] && ILtQ[n, 0] && Int egerQ[m]
\[\int \frac {1}{x^{\frac {7}{4}} \left (b x +a \right )^{\frac {7}{4}}}d x\]
Input:
int(1/x^(7/4)/(b*x+a)^(7/4),x)
Output:
int(1/x^(7/4)/(b*x+a)^(7/4),x)
\[ \int \frac {1}{x^{7/4} (a+b x)^{7/4}} \, dx=\int { \frac {1}{{\left (b x + a\right )}^{\frac {7}{4}} x^{\frac {7}{4}}} \,d x } \] Input:
integrate(1/x^(7/4)/(b*x+a)^(7/4),x, algorithm="fricas")
Output:
integral((b*x + a)^(1/4)*x^(1/4)/(b^2*x^4 + 2*a*b*x^3 + a^2*x^2), x)
Result contains complex when optimal does not.
Time = 7.65 (sec) , antiderivative size = 39, normalized size of antiderivative = 0.38 \[ \int \frac {1}{x^{7/4} (a+b x)^{7/4}} \, dx=\frac {\Gamma \left (- \frac {3}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {3}{4}, \frac {7}{4} \\ \frac {1}{4} \end {matrix}\middle | {\frac {b x e^{i \pi }}{a}} \right )}}{a^{\frac {7}{4}} x^{\frac {3}{4}} \Gamma \left (\frac {1}{4}\right )} \] Input:
integrate(1/x**(7/4)/(b*x+a)**(7/4),x)
Output:
gamma(-3/4)*hyper((-3/4, 7/4), (1/4,), b*x*exp_polar(I*pi)/a)/(a**(7/4)*x* *(3/4)*gamma(1/4))
\[ \int \frac {1}{x^{7/4} (a+b x)^{7/4}} \, dx=\int { \frac {1}{{\left (b x + a\right )}^{\frac {7}{4}} x^{\frac {7}{4}}} \,d x } \] Input:
integrate(1/x^(7/4)/(b*x+a)^(7/4),x, algorithm="maxima")
Output:
integrate(1/((b*x + a)^(7/4)*x^(7/4)), x)
\[ \int \frac {1}{x^{7/4} (a+b x)^{7/4}} \, dx=\int { \frac {1}{{\left (b x + a\right )}^{\frac {7}{4}} x^{\frac {7}{4}}} \,d x } \] Input:
integrate(1/x^(7/4)/(b*x+a)^(7/4),x, algorithm="giac")
Output:
integrate(1/((b*x + a)^(7/4)*x^(7/4)), x)
Timed out. \[ \int \frac {1}{x^{7/4} (a+b x)^{7/4}} \, dx=\int \frac {1}{x^{7/4}\,{\left (a+b\,x\right )}^{7/4}} \,d x \] Input:
int(1/(x^(7/4)*(a + b*x)^(7/4)),x)
Output:
int(1/(x^(7/4)*(a + b*x)^(7/4)), x)
Time = 0.17 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.26 \[ \int \frac {1}{x^{7/4} (a+b x)^{7/4}} \, dx=\frac {-\frac {16 b x}{3}-4 a}{x^{\frac {1}{4}} \left (b x +a \right )^{\frac {3}{4}} \sqrt {x}\, a^{2}} \] Input:
int(1/x^(7/4)/(b*x+a)^(7/4),x)
Output:
(4*x**(3/4)*(a + b*x)**(1/4)*( - 3*a - 4*b*x))/(3*sqrt(x)*a**2*x*(a + b*x) )