Integrand size = 19, antiderivative size = 150 \[ \int \frac {\sqrt {a+b x}}{\sqrt [4]{c+d x}} \, dx=-\frac {4 (b c-a d) \sqrt {a+b x}}{5 b d \sqrt [4]{c+d x}}+\frac {4 (a+b x)^{3/2}}{5 b \sqrt [4]{c+d x}}+\frac {8 (b c-a d)^{3/2} \sqrt [4]{\frac {b (c+d x)}{b c-a d}} E\left (\left .\frac {1}{2} \arctan \left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b c-a d}}\right )\right |2\right )}{5 b d^{3/2} \sqrt [4]{c+d x}} \] Output:
-4/5*(-a*d+b*c)*(b*x+a)^(1/2)/b/d/(d*x+c)^(1/4)+4/5*(b*x+a)^(3/2)/b/(d*x+c )^(1/4)+8/5*(-a*d+b*c)^(3/2)*(b*(d*x+c)/(-a*d+b*c))^(1/4)*EllipticE(sin(1/ 2*arctan(d^(1/2)*(b*x+a)^(1/2)/(-a*d+b*c)^(1/2))),2^(1/2))/b/d^(3/2)/(d*x+ c)^(1/4)
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.02 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.49 \[ \int \frac {\sqrt {a+b x}}{\sqrt [4]{c+d x}} \, dx=\frac {2 (a+b x)^{3/2} \sqrt [4]{\frac {b (c+d x)}{b c-a d}} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {3}{2},\frac {5}{2},\frac {d (a+b x)}{-b c+a d}\right )}{3 b \sqrt [4]{c+d x}} \] Input:
Integrate[Sqrt[a + b*x]/(c + d*x)^(1/4),x]
Output:
(2*(a + b*x)^(3/2)*((b*(c + d*x))/(b*c - a*d))^(1/4)*Hypergeometric2F1[1/4 , 3/2, 5/2, (d*(a + b*x))/(-(b*c) + a*d)])/(3*b*(c + d*x)^(1/4))
Time = 0.42 (sec) , antiderivative size = 233, normalized size of antiderivative = 1.55, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.421, Rules used = {60, 73, 836, 765, 762, 1390, 1388, 327}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\sqrt {a+b x}}{\sqrt [4]{c+d x}} \, dx\) |
\(\Big \downarrow \) 60 |
\(\displaystyle \frac {4 \sqrt {a+b x} (c+d x)^{3/4}}{5 d}-\frac {2 (b c-a d) \int \frac {1}{\sqrt {a+b x} \sqrt [4]{c+d x}}dx}{5 d}\) |
\(\Big \downarrow \) 73 |
\(\displaystyle \frac {4 \sqrt {a+b x} (c+d x)^{3/4}}{5 d}-\frac {8 (b c-a d) \int \frac {\sqrt {c+d x}}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [4]{c+d x}}{5 d^2}\) |
\(\Big \downarrow \) 836 |
\(\displaystyle \frac {4 \sqrt {a+b x} (c+d x)^{3/4}}{5 d}-\frac {8 (b c-a d) \left (\frac {\sqrt {b c-a d} \int \frac {\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}+1}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [4]{c+d x}}{\sqrt {b}}-\frac {\sqrt {b c-a d} \int \frac {1}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [4]{c+d x}}{\sqrt {b}}\right )}{5 d^2}\) |
\(\Big \downarrow \) 765 |
\(\displaystyle \frac {4 \sqrt {a+b x} (c+d x)^{3/4}}{5 d}-\frac {8 (b c-a d) \left (\frac {\sqrt {b c-a d} \int \frac {\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}+1}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [4]{c+d x}}{\sqrt {b}}-\frac {\sqrt {b c-a d} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \int \frac {1}{\sqrt {1-\frac {b (c+d x)}{b c-a d}}}d\sqrt [4]{c+d x}}{\sqrt {b} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}\right )}{5 d^2}\) |
\(\Big \downarrow \) 762 |
\(\displaystyle \frac {4 \sqrt {a+b x} (c+d x)^{3/4}}{5 d}-\frac {8 (b c-a d) \left (\frac {\sqrt {b c-a d} \int \frac {\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}+1}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [4]{c+d x}}{\sqrt {b}}-\frac {(b c-a d)^{3/4} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{b^{3/4} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}\right )}{5 d^2}\) |
\(\Big \downarrow \) 1390 |
\(\displaystyle \frac {4 \sqrt {a+b x} (c+d x)^{3/4}}{5 d}-\frac {8 (b c-a d) \left (\frac {\sqrt {b c-a d} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \int \frac {\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}+1}{\sqrt {1-\frac {b (c+d x)}{b c-a d}}}d\sqrt [4]{c+d x}}{\sqrt {b} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}-\frac {(b c-a d)^{3/4} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{b^{3/4} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}\right )}{5 d^2}\) |
\(\Big \downarrow \) 1388 |
\(\displaystyle \frac {4 \sqrt {a+b x} (c+d x)^{3/4}}{5 d}-\frac {8 (b c-a d) \left (\frac {\sqrt {b c-a d} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \int \frac {\sqrt {\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}+1}}{\sqrt {1-\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}}}d\sqrt [4]{c+d x}}{\sqrt {b} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}-\frac {(b c-a d)^{3/4} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{b^{3/4} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}\right )}{5 d^2}\) |
\(\Big \downarrow \) 327 |
\(\displaystyle \frac {4 \sqrt {a+b x} (c+d x)^{3/4}}{5 d}-\frac {8 (b c-a d) \left (\frac {(b c-a d)^{3/4} \sqrt {1-\frac {b (c+d x)}{b c-a d}} E\left (\left .\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{b^{3/4} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}-\frac {(b c-a d)^{3/4} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{b^{3/4} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}\right )}{5 d^2}\) |
Input:
Int[Sqrt[a + b*x]/(c + d*x)^(1/4),x]
Output:
(4*Sqrt[a + b*x]*(c + d*x)^(3/4))/(5*d) - (8*(b*c - a*d)*(((b*c - a*d)^(3/ 4)*Sqrt[1 - (b*(c + d*x))/(b*c - a*d)]*EllipticE[ArcSin[(b^(1/4)*(c + d*x) ^(1/4))/(b*c - a*d)^(1/4)], -1])/(b^(3/4)*Sqrt[a - (b*c)/d + (b*(c + d*x)) /d]) - ((b*c - a*d)^(3/4)*Sqrt[1 - (b*(c + d*x))/(b*c - a*d)]*EllipticF[Ar cSin[(b^(1/4)*(c + d*x)^(1/4))/(b*c - a*d)^(1/4)], -1])/(b^(3/4)*Sqrt[a - (b*c)/d + (b*(c + d*x))/d])))/(5*d^2)
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + n + 1))), x] + Simp[n*((b*c - a*d)/( b*(m + n + 1))) Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] && GtQ[n, 0] && NeQ[m + n + 1, 0] && !(IGtQ[m, 0] && ( !Integer Q[n] || (GtQ[m, 0] && LtQ[m - n, 0]))) && !ILtQ[m + n + 2, 0] && IntLinear Q[a, b, c, d, m, n, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ {p = Denominator[m]}, Simp[p/b Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL inearQ[a, b, c, d, m, n, x]
Int[Sqrt[(a_) + (b_.)*(x_)^2]/Sqrt[(c_) + (d_.)*(x_)^2], x_Symbol] :> Simp[ (Sqrt[a]/(Sqrt[c]*Rt[-d/c, 2]))*EllipticE[ArcSin[Rt[-d/c, 2]*x], b*(c/(a*d) )], x] /; FreeQ[{a, b, c, d}, x] && NegQ[d/c] && GtQ[c, 0] && GtQ[a, 0]
Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> Simp[(1/(Sqrt[a]*Rt[-b/a, 4]) )*EllipticF[ArcSin[Rt[-b/a, 4]*x], -1], x] /; FreeQ[{a, b}, x] && NegQ[b/a] && GtQ[a, 0]
Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> Simp[Sqrt[1 + b*(x^4/a)]/Sqrt [a + b*x^4] Int[1/Sqrt[1 + b*(x^4/a)], x], x] /; FreeQ[{a, b}, x] && NegQ [b/a] && !GtQ[a, 0]
Int[(x_)^2/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[-b/a, 2]}, Simp[-q^(-1) Int[1/Sqrt[a + b*x^4], x], x] + Simp[1/q Int[(1 + q*x^2)/S qrt[a + b*x^4], x], x]] /; FreeQ[{a, b}, x] && NegQ[b/a]
Int[(u_.)*((a_) + (c_.)*(x_)^(n2_.))^(p_.)*((d_) + (e_.)*(x_)^(n_))^(q_.), x_Symbol] :> Int[u*(d + e*x^n)^(p + q)*(a/d + (c/e)*x^n)^p, x] /; FreeQ[{a, c, d, e, n, p, q}, x] && EqQ[n2, 2*n] && EqQ[c*d^2 + a*e^2, 0] && (Integer Q[p] || (GtQ[a, 0] && GtQ[d, 0]))
Int[((d_) + (e_.)*(x_)^2)/Sqrt[(a_) + (c_.)*(x_)^4], x_Symbol] :> Simp[Sqrt [1 + c*(x^4/a)]/Sqrt[a + c*x^4] Int[(d + e*x^2)/Sqrt[1 + c*(x^4/a)], x], x] /; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 + a*e^2, 0] && NegQ[c/a] && !GtQ [a, 0] && !(LtQ[a, 0] && GtQ[c, 0])
\[\int \frac {\sqrt {b x +a}}{\left (x d +c \right )^{\frac {1}{4}}}d x\]
Input:
int((b*x+a)^(1/2)/(d*x+c)^(1/4),x)
Output:
int((b*x+a)^(1/2)/(d*x+c)^(1/4),x)
\[ \int \frac {\sqrt {a+b x}}{\sqrt [4]{c+d x}} \, dx=\int { \frac {\sqrt {b x + a}}{{\left (d x + c\right )}^{\frac {1}{4}}} \,d x } \] Input:
integrate((b*x+a)^(1/2)/(d*x+c)^(1/4),x, algorithm="fricas")
Output:
integral(sqrt(b*x + a)/(d*x + c)^(1/4), x)
\[ \int \frac {\sqrt {a+b x}}{\sqrt [4]{c+d x}} \, dx=\int \frac {\sqrt {a + b x}}{\sqrt [4]{c + d x}}\, dx \] Input:
integrate((b*x+a)**(1/2)/(d*x+c)**(1/4),x)
Output:
Integral(sqrt(a + b*x)/(c + d*x)**(1/4), x)
\[ \int \frac {\sqrt {a+b x}}{\sqrt [4]{c+d x}} \, dx=\int { \frac {\sqrt {b x + a}}{{\left (d x + c\right )}^{\frac {1}{4}}} \,d x } \] Input:
integrate((b*x+a)^(1/2)/(d*x+c)^(1/4),x, algorithm="maxima")
Output:
integrate(sqrt(b*x + a)/(d*x + c)^(1/4), x)
\[ \int \frac {\sqrt {a+b x}}{\sqrt [4]{c+d x}} \, dx=\int { \frac {\sqrt {b x + a}}{{\left (d x + c\right )}^{\frac {1}{4}}} \,d x } \] Input:
integrate((b*x+a)^(1/2)/(d*x+c)^(1/4),x, algorithm="giac")
Output:
integrate(sqrt(b*x + a)/(d*x + c)^(1/4), x)
Timed out. \[ \int \frac {\sqrt {a+b x}}{\sqrt [4]{c+d x}} \, dx=\int \frac {\sqrt {a+b\,x}}{{\left (c+d\,x\right )}^{1/4}} \,d x \] Input:
int((a + b*x)^(1/2)/(c + d*x)^(1/4),x)
Output:
int((a + b*x)^(1/2)/(c + d*x)^(1/4), x)
\[ \int \frac {\sqrt {a+b x}}{\sqrt [4]{c+d x}} \, dx=\int \frac {\sqrt {b x +a}}{\left (d x +c \right )^{\frac {1}{4}}}d x \] Input:
int((b*x+a)^(1/2)/(d*x+c)^(1/4),x)
Output:
int(sqrt(a + b*x)/(c + d*x)**(1/4),x)