\(\int \frac {(a+b x)^{3/2}}{(c+d x)^{9/4}} \, dx\) [477]

Optimal result

Integrand size = 19, antiderivative size = 138 \[ \int \frac {(a+b x)^{3/2}}{(c+d x)^{9/4}} \, dx=-\frac {4 (a+b x)^{3/2}}{5 d (c+d x)^{5/4}}+\frac {24 b \sqrt {a+b x}}{5 d^2 \sqrt [4]{c+d x}}-\frac {48 b \sqrt {b c-a d} \sqrt [4]{\frac {b (c+d x)}{b c-a d}} E\left (\left .\frac {1}{2} \arctan \left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b c-a d}}\right )\right |2\right )}{5 d^{5/2} \sqrt [4]{c+d x}} \] Output:

-4/5*(b*x+a)^(3/2)/d/(d*x+c)^(5/4)+24/5*b*(b*x+a)^(1/2)/d^2/(d*x+c)^(1/4)- 
48/5*b*(-a*d+b*c)^(1/2)*(b*(d*x+c)/(-a*d+b*c))^(1/4)*EllipticE(sin(1/2*arc 
tan(d^(1/2)*(b*x+a)^(1/2)/(-a*d+b*c)^(1/2))),2^(1/2))/d^(5/2)/(d*x+c)^(1/4 
)
 

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 0.05 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.53 \[ \int \frac {(a+b x)^{3/2}}{(c+d x)^{9/4}} \, dx=\frac {2 (a+b x)^{5/2} \left (\frac {b (c+d x)}{b c-a d}\right )^{9/4} \operatorname {Hypergeometric2F1}\left (\frac {9}{4},\frac {5}{2},\frac {7}{2},\frac {d (a+b x)}{-b c+a d}\right )}{5 b (c+d x)^{9/4}} \] Input:

Integrate[(a + b*x)^(3/2)/(c + d*x)^(9/4),x]
 

Output:

(2*(a + b*x)^(5/2)*((b*(c + d*x))/(b*c - a*d))^(9/4)*Hypergeometric2F1[9/4 
, 5/2, 7/2, (d*(a + b*x))/(-(b*c) + a*d)])/(5*b*(c + d*x)^(9/4))
 

Rubi [A] (verified)

Time = 0.44 (sec) , antiderivative size = 256, normalized size of antiderivative = 1.86, number of steps used = 10, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.474, Rules used = {57, 57, 73, 836, 765, 762, 1390, 1388, 327}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(a+b x)^{3/2}}{(c+d x)^{9/4}} \, dx\)

\(\Big \downarrow \) 57

\(\displaystyle \frac {6 b \int \frac {\sqrt {a+b x}}{(c+d x)^{5/4}}dx}{5 d}-\frac {4 (a+b x)^{3/2}}{5 d (c+d x)^{5/4}}\)

\(\Big \downarrow \) 57

\(\displaystyle \frac {6 b \left (\frac {2 b \int \frac {1}{\sqrt {a+b x} \sqrt [4]{c+d x}}dx}{d}-\frac {4 \sqrt {a+b x}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{3/2}}{5 d (c+d x)^{5/4}}\)

\(\Big \downarrow \) 73

\(\displaystyle \frac {6 b \left (\frac {8 b \int \frac {\sqrt {c+d x}}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [4]{c+d x}}{d^2}-\frac {4 \sqrt {a+b x}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{3/2}}{5 d (c+d x)^{5/4}}\)

\(\Big \downarrow \) 836

\(\displaystyle \frac {6 b \left (\frac {8 b \left (\frac {\sqrt {b c-a d} \int \frac {\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}+1}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [4]{c+d x}}{\sqrt {b}}-\frac {\sqrt {b c-a d} \int \frac {1}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [4]{c+d x}}{\sqrt {b}}\right )}{d^2}-\frac {4 \sqrt {a+b x}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{3/2}}{5 d (c+d x)^{5/4}}\)

\(\Big \downarrow \) 765

\(\displaystyle \frac {6 b \left (\frac {8 b \left (\frac {\sqrt {b c-a d} \int \frac {\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}+1}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [4]{c+d x}}{\sqrt {b}}-\frac {\sqrt {b c-a d} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \int \frac {1}{\sqrt {1-\frac {b (c+d x)}{b c-a d}}}d\sqrt [4]{c+d x}}{\sqrt {b} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}\right )}{d^2}-\frac {4 \sqrt {a+b x}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{3/2}}{5 d (c+d x)^{5/4}}\)

\(\Big \downarrow \) 762

\(\displaystyle \frac {6 b \left (\frac {8 b \left (\frac {\sqrt {b c-a d} \int \frac {\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}+1}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [4]{c+d x}}{\sqrt {b}}-\frac {(b c-a d)^{3/4} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{b^{3/4} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}\right )}{d^2}-\frac {4 \sqrt {a+b x}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{3/2}}{5 d (c+d x)^{5/4}}\)

\(\Big \downarrow \) 1390

\(\displaystyle \frac {6 b \left (\frac {8 b \left (\frac {\sqrt {b c-a d} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \int \frac {\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}+1}{\sqrt {1-\frac {b (c+d x)}{b c-a d}}}d\sqrt [4]{c+d x}}{\sqrt {b} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}-\frac {(b c-a d)^{3/4} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{b^{3/4} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}\right )}{d^2}-\frac {4 \sqrt {a+b x}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{3/2}}{5 d (c+d x)^{5/4}}\)

\(\Big \downarrow \) 1388

\(\displaystyle \frac {6 b \left (\frac {8 b \left (\frac {\sqrt {b c-a d} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \int \frac {\sqrt {\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}+1}}{\sqrt {1-\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}}}d\sqrt [4]{c+d x}}{\sqrt {b} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}-\frac {(b c-a d)^{3/4} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{b^{3/4} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}\right )}{d^2}-\frac {4 \sqrt {a+b x}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{3/2}}{5 d (c+d x)^{5/4}}\)

\(\Big \downarrow \) 327

\(\displaystyle \frac {6 b \left (\frac {8 b \left (\frac {(b c-a d)^{3/4} \sqrt {1-\frac {b (c+d x)}{b c-a d}} E\left (\left .\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{b^{3/4} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}-\frac {(b c-a d)^{3/4} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{b^{3/4} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}\right )}{d^2}-\frac {4 \sqrt {a+b x}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{3/2}}{5 d (c+d x)^{5/4}}\)

Input:

Int[(a + b*x)^(3/2)/(c + d*x)^(9/4),x]
 

Output:

(-4*(a + b*x)^(3/2))/(5*d*(c + d*x)^(5/4)) + (6*b*((-4*Sqrt[a + b*x])/(d*( 
c + d*x)^(1/4)) + (8*b*(((b*c - a*d)^(3/4)*Sqrt[1 - (b*(c + d*x))/(b*c - a 
*d)]*EllipticE[ArcSin[(b^(1/4)*(c + d*x)^(1/4))/(b*c - a*d)^(1/4)], -1])/( 
b^(3/4)*Sqrt[a - (b*c)/d + (b*(c + d*x))/d]) - ((b*c - a*d)^(3/4)*Sqrt[1 - 
 (b*(c + d*x))/(b*c - a*d)]*EllipticF[ArcSin[(b^(1/4)*(c + d*x)^(1/4))/(b* 
c - a*d)^(1/4)], -1])/(b^(3/4)*Sqrt[a - (b*c)/d + (b*(c + d*x))/d])))/d^2) 
)/(5*d)
 

Defintions of rubi rules used

rule 57

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ 
(a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + 1))), x] - Simp[d*(n/(b*(m + 1))) 
Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] & 
& GtQ[n, 0] && LtQ[m, -1] &&  !(IntegerQ[n] &&  !IntegerQ[m]) &&  !(ILeQ[m 
+ n + 2, 0] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c 
, d, m, n, x]
 

rule 73

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ 
{p = Denominator[m]}, Simp[p/b   Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + 
 d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt 
Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL 
inearQ[a, b, c, d, m, n, x]
 

rule 327

Int[Sqrt[(a_) + (b_.)*(x_)^2]/Sqrt[(c_) + (d_.)*(x_)^2], x_Symbol] :> Simp[ 
(Sqrt[a]/(Sqrt[c]*Rt[-d/c, 2]))*EllipticE[ArcSin[Rt[-d/c, 2]*x], b*(c/(a*d) 
)], x] /; FreeQ[{a, b, c, d}, x] && NegQ[d/c] && GtQ[c, 0] && GtQ[a, 0]
 

rule 762

Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> Simp[(1/(Sqrt[a]*Rt[-b/a, 4]) 
)*EllipticF[ArcSin[Rt[-b/a, 4]*x], -1], x] /; FreeQ[{a, b}, x] && NegQ[b/a] 
 && GtQ[a, 0]
 

rule 765

Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> Simp[Sqrt[1 + b*(x^4/a)]/Sqrt 
[a + b*x^4]   Int[1/Sqrt[1 + b*(x^4/a)], x], x] /; FreeQ[{a, b}, x] && NegQ 
[b/a] &&  !GtQ[a, 0]
 

rule 836

Int[(x_)^2/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[-b/a, 2]}, 
Simp[-q^(-1)   Int[1/Sqrt[a + b*x^4], x], x] + Simp[1/q   Int[(1 + q*x^2)/S 
qrt[a + b*x^4], x], x]] /; FreeQ[{a, b}, x] && NegQ[b/a]
 

rule 1388

Int[(u_.)*((a_) + (c_.)*(x_)^(n2_.))^(p_.)*((d_) + (e_.)*(x_)^(n_))^(q_.), 
x_Symbol] :> Int[u*(d + e*x^n)^(p + q)*(a/d + (c/e)*x^n)^p, x] /; FreeQ[{a, 
 c, d, e, n, p, q}, x] && EqQ[n2, 2*n] && EqQ[c*d^2 + a*e^2, 0] && (Integer 
Q[p] || (GtQ[a, 0] && GtQ[d, 0]))
 

rule 1390

Int[((d_) + (e_.)*(x_)^2)/Sqrt[(a_) + (c_.)*(x_)^4], x_Symbol] :> Simp[Sqrt 
[1 + c*(x^4/a)]/Sqrt[a + c*x^4]   Int[(d + e*x^2)/Sqrt[1 + c*(x^4/a)], x], 
x] /; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 + a*e^2, 0] && NegQ[c/a] &&  !GtQ 
[a, 0] &&  !(LtQ[a, 0] && GtQ[c, 0])
 

Maple [F]

\[\int \frac {\left (b x +a \right )^{\frac {3}{2}}}{\left (x d +c \right )^{\frac {9}{4}}}d x\]

Input:

int((b*x+a)^(3/2)/(d*x+c)^(9/4),x)
 

Output:

int((b*x+a)^(3/2)/(d*x+c)^(9/4),x)
 

Fricas [F]

\[ \int \frac {(a+b x)^{3/2}}{(c+d x)^{9/4}} \, dx=\int { \frac {{\left (b x + a\right )}^{\frac {3}{2}}}{{\left (d x + c\right )}^{\frac {9}{4}}} \,d x } \] Input:

integrate((b*x+a)^(3/2)/(d*x+c)^(9/4),x, algorithm="fricas")
 

Output:

integral((b*x + a)^(3/2)*(d*x + c)^(3/4)/(d^3*x^3 + 3*c*d^2*x^2 + 3*c^2*d* 
x + c^3), x)
 

Sympy [F]

\[ \int \frac {(a+b x)^{3/2}}{(c+d x)^{9/4}} \, dx=\int \frac {\left (a + b x\right )^{\frac {3}{2}}}{\left (c + d x\right )^{\frac {9}{4}}}\, dx \] Input:

integrate((b*x+a)**(3/2)/(d*x+c)**(9/4),x)
 

Output:

Integral((a + b*x)**(3/2)/(c + d*x)**(9/4), x)
 

Maxima [F]

\[ \int \frac {(a+b x)^{3/2}}{(c+d x)^{9/4}} \, dx=\int { \frac {{\left (b x + a\right )}^{\frac {3}{2}}}{{\left (d x + c\right )}^{\frac {9}{4}}} \,d x } \] Input:

integrate((b*x+a)^(3/2)/(d*x+c)^(9/4),x, algorithm="maxima")
 

Output:

integrate((b*x + a)^(3/2)/(d*x + c)^(9/4), x)
                                                                                    
                                                                                    
 

Giac [F]

\[ \int \frac {(a+b x)^{3/2}}{(c+d x)^{9/4}} \, dx=\int { \frac {{\left (b x + a\right )}^{\frac {3}{2}}}{{\left (d x + c\right )}^{\frac {9}{4}}} \,d x } \] Input:

integrate((b*x+a)^(3/2)/(d*x+c)^(9/4),x, algorithm="giac")
 

Output:

integrate((b*x + a)^(3/2)/(d*x + c)^(9/4), x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {(a+b x)^{3/2}}{(c+d x)^{9/4}} \, dx=\int \frac {{\left (a+b\,x\right )}^{3/2}}{{\left (c+d\,x\right )}^{9/4}} \,d x \] Input:

int((a + b*x)^(3/2)/(c + d*x)^(9/4),x)
 

Output:

int((a + b*x)^(3/2)/(c + d*x)^(9/4), x)
 

Reduce [F]

\[ \int \frac {(a+b x)^{3/2}}{(c+d x)^{9/4}} \, dx=\left (\int \frac {\sqrt {b x +a}}{\left (d x +c \right )^{\frac {1}{4}} c^{2}+2 \left (d x +c \right )^{\frac {1}{4}} c d x +\left (d x +c \right )^{\frac {1}{4}} d^{2} x^{2}}d x \right ) a +\left (\int \frac {\sqrt {b x +a}\, x}{\left (d x +c \right )^{\frac {1}{4}} c^{2}+2 \left (d x +c \right )^{\frac {1}{4}} c d x +\left (d x +c \right )^{\frac {1}{4}} d^{2} x^{2}}d x \right ) b \] Input:

int((b*x+a)^(3/2)/(d*x+c)^(9/4),x)
 

Output:

int(sqrt(a + b*x)/((c + d*x)**(1/4)*c**2 + 2*(c + d*x)**(1/4)*c*d*x + (c + 
 d*x)**(1/4)*d**2*x**2),x)*a + int((sqrt(a + b*x)*x)/((c + d*x)**(1/4)*c** 
2 + 2*(c + d*x)**(1/4)*c*d*x + (c + d*x)**(1/4)*d**2*x**2),x)*b