Integrand size = 19, antiderivative size = 890 \[ \int \frac {(a+b x)^{5/2}}{\sqrt [6]{c+d x}} \, dx=\frac {81 (b c-a d)^2 \sqrt {a+b x} (c+d x)^{5/6}}{224 d^3}-\frac {9 (b c-a d) (a+b x)^{3/2} (c+d x)^{5/6}}{28 d^2}+\frac {3 (a+b x)^{5/2} (c+d x)^{5/6}}{10 d}+\frac {243 \left (1+\sqrt {3}\right ) (b c-a d)^3 \sqrt {a+b x} \sqrt [6]{c+d x}}{448 b^{2/3} d^3 \left (\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}\right )}+\frac {243 \sqrt [4]{3} (b c-a d)^{10/3} \sqrt [6]{c+d x} \left (\sqrt [3]{b c-a d}-\sqrt [3]{b} \sqrt [3]{c+d x}\right ) \sqrt {\frac {(b c-a d)^{2/3}+\sqrt [3]{b} \sqrt [3]{b c-a d} \sqrt [3]{c+d x}+b^{2/3} (c+d x)^{2/3}}{\left (\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}\right )^2}} E\left (\arccos \left (\frac {\sqrt [3]{b c-a d}-\left (1-\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}}{\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{448 b^{2/3} d^4 \sqrt {a+b x} \sqrt {-\frac {\sqrt [3]{b} \sqrt [3]{c+d x} \left (\sqrt [3]{b c-a d}-\sqrt [3]{b} \sqrt [3]{c+d x}\right )}{\left (\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}\right )^2}}}+\frac {81\ 3^{3/4} \left (1-\sqrt {3}\right ) (b c-a d)^{10/3} \sqrt [6]{c+d x} \left (\sqrt [3]{b c-a d}-\sqrt [3]{b} \sqrt [3]{c+d x}\right ) \sqrt {\frac {(b c-a d)^{2/3}+\sqrt [3]{b} \sqrt [3]{b c-a d} \sqrt [3]{c+d x}+b^{2/3} (c+d x)^{2/3}}{\left (\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}\right )^2}} \operatorname {EllipticF}\left (\arccos \left (\frac {\sqrt [3]{b c-a d}-\left (1-\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}}{\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}}\right ),\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{896 b^{2/3} d^4 \sqrt {a+b x} \sqrt {-\frac {\sqrt [3]{b} \sqrt [3]{c+d x} \left (\sqrt [3]{b c-a d}-\sqrt [3]{b} \sqrt [3]{c+d x}\right )}{\left (\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}\right )^2}}} \] Output:
81/224*(-a*d+b*c)^2*(b*x+a)^(1/2)*(d*x+c)^(5/6)/d^3-9/28*(-a*d+b*c)*(b*x+a )^(3/2)*(d*x+c)^(5/6)/d^2+3/10*(b*x+a)^(5/2)*(d*x+c)^(5/6)/d+243/448*(1+3^ (1/2))*(-a*d+b*c)^3*(b*x+a)^(1/2)*(d*x+c)^(1/6)/b^(2/3)/d^3/((-a*d+b*c)^(1 /3)-(1+3^(1/2))*b^(1/3)*(d*x+c)^(1/3))+243/448*3^(1/4)*(-a*d+b*c)^(10/3)*( d*x+c)^(1/6)*((-a*d+b*c)^(1/3)-b^(1/3)*(d*x+c)^(1/3))*(((-a*d+b*c)^(2/3)+b ^(1/3)*(-a*d+b*c)^(1/3)*(d*x+c)^(1/3)+b^(2/3)*(d*x+c)^(2/3))/((-a*d+b*c)^( 1/3)-(1+3^(1/2))*b^(1/3)*(d*x+c)^(1/3))^2)^(1/2)*EllipticE((1-((-a*d+b*c)^ (1/3)-(1-3^(1/2))*b^(1/3)*(d*x+c)^(1/3))^2/((-a*d+b*c)^(1/3)-(1+3^(1/2))*b ^(1/3)*(d*x+c)^(1/3))^2)^(1/2),1/4*6^(1/2)+1/4*2^(1/2))/b^(2/3)/d^4/(b*x+a )^(1/2)/(-b^(1/3)*(d*x+c)^(1/3)*((-a*d+b*c)^(1/3)-b^(1/3)*(d*x+c)^(1/3))/( (-a*d+b*c)^(1/3)-(1+3^(1/2))*b^(1/3)*(d*x+c)^(1/3))^2)^(1/2)+81/896*3^(3/4 )*(1-3^(1/2))*(-a*d+b*c)^(10/3)*(d*x+c)^(1/6)*((-a*d+b*c)^(1/3)-b^(1/3)*(d *x+c)^(1/3))*(((-a*d+b*c)^(2/3)+b^(1/3)*(-a*d+b*c)^(1/3)*(d*x+c)^(1/3)+b^( 2/3)*(d*x+c)^(2/3))/((-a*d+b*c)^(1/3)-(1+3^(1/2))*b^(1/3)*(d*x+c)^(1/3))^2 )^(1/2)*InverseJacobiAM(arccos(((-a*d+b*c)^(1/3)-(1-3^(1/2))*b^(1/3)*(d*x+ c)^(1/3))/((-a*d+b*c)^(1/3)-(1+3^(1/2))*b^(1/3)*(d*x+c)^(1/3))),1/4*6^(1/2 )+1/4*2^(1/2))/b^(2/3)/d^4/(b*x+a)^(1/2)/(-b^(1/3)*(d*x+c)^(1/3)*((-a*d+b* c)^(1/3)-b^(1/3)*(d*x+c)^(1/3))/((-a*d+b*c)^(1/3)-(1+3^(1/2))*b^(1/3)*(d*x +c)^(1/3))^2)^(1/2)
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.03 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.08 \[ \int \frac {(a+b x)^{5/2}}{\sqrt [6]{c+d x}} \, dx=\frac {2 (a+b x)^{7/2} \sqrt [6]{\frac {b (c+d x)}{b c-a d}} \operatorname {Hypergeometric2F1}\left (\frac {1}{6},\frac {7}{2},\frac {9}{2},\frac {d (a+b x)}{-b c+a d}\right )}{7 b \sqrt [6]{c+d x}} \] Input:
Integrate[(a + b*x)^(5/2)/(c + d*x)^(1/6),x]
Output:
(2*(a + b*x)^(7/2)*((b*(c + d*x))/(b*c - a*d))^(1/6)*Hypergeometric2F1[1/6 , 7/2, 9/2, (d*(a + b*x))/(-(b*c) + a*d)])/(7*b*(c + d*x)^(1/6))
Time = 0.71 (sec) , antiderivative size = 940, normalized size of antiderivative = 1.06, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.421, Rules used = {60, 60, 60, 73, 837, 25, 766, 2420}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {(a+b x)^{5/2}}{\sqrt [6]{c+d x}} \, dx\) |
\(\Big \downarrow \) 60 |
\(\displaystyle \frac {3 (a+b x)^{5/2} (c+d x)^{5/6}}{10 d}-\frac {3 (b c-a d) \int \frac {(a+b x)^{3/2}}{\sqrt [6]{c+d x}}dx}{4 d}\) |
\(\Big \downarrow \) 60 |
\(\displaystyle \frac {3 (a+b x)^{5/2} (c+d x)^{5/6}}{10 d}-\frac {3 (b c-a d) \left (\frac {3 (a+b x)^{3/2} (c+d x)^{5/6}}{7 d}-\frac {9 (b c-a d) \int \frac {\sqrt {a+b x}}{\sqrt [6]{c+d x}}dx}{14 d}\right )}{4 d}\) |
\(\Big \downarrow \) 60 |
\(\displaystyle \frac {3 (a+b x)^{5/2} (c+d x)^{5/6}}{10 d}-\frac {3 (b c-a d) \left (\frac {3 (a+b x)^{3/2} (c+d x)^{5/6}}{7 d}-\frac {9 (b c-a d) \left (\frac {3 \sqrt {a+b x} (c+d x)^{5/6}}{4 d}-\frac {3 (b c-a d) \int \frac {1}{\sqrt {a+b x} \sqrt [6]{c+d x}}dx}{8 d}\right )}{14 d}\right )}{4 d}\) |
\(\Big \downarrow \) 73 |
\(\displaystyle \frac {3 (a+b x)^{5/2} (c+d x)^{5/6}}{10 d}-\frac {3 (b c-a d) \left (\frac {3 (a+b x)^{3/2} (c+d x)^{5/6}}{7 d}-\frac {9 (b c-a d) \left (\frac {3 \sqrt {a+b x} (c+d x)^{5/6}}{4 d}-\frac {9 (b c-a d) \int \frac {(c+d x)^{2/3}}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [6]{c+d x}}{4 d^2}\right )}{14 d}\right )}{4 d}\) |
\(\Big \downarrow \) 837 |
\(\displaystyle \frac {3 (a+b x)^{5/2} (c+d x)^{5/6}}{10 d}-\frac {3 (b c-a d) \left (\frac {3 (a+b x)^{3/2} (c+d x)^{5/6}}{7 d}-\frac {9 (b c-a d) \left (\frac {3 \sqrt {a+b x} (c+d x)^{5/6}}{4 d}-\frac {9 (b c-a d) \left (-\frac {\left (1-\sqrt {3}\right ) (b c-a d)^{2/3} \int \frac {1}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [6]{c+d x}}{2 b^{2/3}}-\frac {\int -\frac {\left (1-\sqrt {3}\right ) (b c-a d)^{2/3}+2 b^{2/3} (c+d x)^{2/3}}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [6]{c+d x}}{2 b^{2/3}}\right )}{4 d^2}\right )}{14 d}\right )}{4 d}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {3 (a+b x)^{5/2} (c+d x)^{5/6}}{10 d}-\frac {3 (b c-a d) \left (\frac {3 (a+b x)^{3/2} (c+d x)^{5/6}}{7 d}-\frac {9 (b c-a d) \left (\frac {3 \sqrt {a+b x} (c+d x)^{5/6}}{4 d}-\frac {9 (b c-a d) \left (\frac {\int \frac {\left (1-\sqrt {3}\right ) (b c-a d)^{2/3}+2 b^{2/3} (c+d x)^{2/3}}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [6]{c+d x}}{2 b^{2/3}}-\frac {\left (1-\sqrt {3}\right ) (b c-a d)^{2/3} \int \frac {1}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [6]{c+d x}}{2 b^{2/3}}\right )}{4 d^2}\right )}{14 d}\right )}{4 d}\) |
\(\Big \downarrow \) 766 |
\(\displaystyle \frac {3 (a+b x)^{5/2} (c+d x)^{5/6}}{10 d}-\frac {3 (b c-a d) \left (\frac {3 (a+b x)^{3/2} (c+d x)^{5/6}}{7 d}-\frac {9 (b c-a d) \left (\frac {3 \sqrt {a+b x} (c+d x)^{5/6}}{4 d}-\frac {9 (b c-a d) \left (\frac {\int \frac {\left (1-\sqrt {3}\right ) (b c-a d)^{2/3}+2 b^{2/3} (c+d x)^{2/3}}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [6]{c+d x}}{2 b^{2/3}}-\frac {\left (1-\sqrt {3}\right ) \sqrt [6]{c+d x} \sqrt [3]{b c-a d} \left (\sqrt [3]{b c-a d}-\sqrt [3]{b} \sqrt [3]{c+d x}\right ) \sqrt {\frac {\sqrt [3]{b} \sqrt [3]{c+d x} \sqrt [3]{b c-a d}+(b c-a d)^{2/3}+b^{2/3} (c+d x)^{2/3}}{\left (\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}\right )^2}} \operatorname {EllipticF}\left (\arccos \left (\frac {\sqrt [3]{b c-a d}-\left (1-\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}}{\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}}\right ),\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{4 \sqrt [4]{3} b^{2/3} \sqrt {-\frac {\sqrt [3]{b} \sqrt [3]{c+d x} \left (\sqrt [3]{b c-a d}-\sqrt [3]{b} \sqrt [3]{c+d x}\right )}{\left (\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}\right )^2}} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}\right )}{4 d^2}\right )}{14 d}\right )}{4 d}\) |
\(\Big \downarrow \) 2420 |
\(\displaystyle \frac {3 (a+b x)^{5/2} (c+d x)^{5/6}}{10 d}-\frac {3 (b c-a d) \left (\frac {3 (a+b x)^{3/2} (c+d x)^{5/6}}{7 d}-\frac {9 (b c-a d) \left (\frac {3 \sqrt {a+b x} (c+d x)^{5/6}}{4 d}-\frac {9 (b c-a d) \left (\frac {-\frac {\left (1+\sqrt {3}\right ) \sqrt [6]{c+d x} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}} d}{\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}}-\frac {\sqrt [4]{3} \sqrt [3]{b c-a d} \sqrt [6]{c+d x} \left (\sqrt [3]{b c-a d}-\sqrt [3]{b} \sqrt [3]{c+d x}\right ) \sqrt {\frac {(b c-a d)^{2/3}+\sqrt [3]{b} \sqrt [3]{c+d x} \sqrt [3]{b c-a d}+b^{2/3} (c+d x)^{2/3}}{\left (\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}\right )^2}} E\left (\arccos \left (\frac {\sqrt [3]{b c-a d}-\left (1-\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}}{\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{\sqrt {-\frac {\sqrt [3]{b} \sqrt [3]{c+d x} \left (\sqrt [3]{b c-a d}-\sqrt [3]{b} \sqrt [3]{c+d x}\right )}{\left (\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}\right )^2}} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}}{2 b^{2/3}}-\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{b c-a d} \sqrt [6]{c+d x} \left (\sqrt [3]{b c-a d}-\sqrt [3]{b} \sqrt [3]{c+d x}\right ) \sqrt {\frac {(b c-a d)^{2/3}+\sqrt [3]{b} \sqrt [3]{c+d x} \sqrt [3]{b c-a d}+b^{2/3} (c+d x)^{2/3}}{\left (\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}\right )^2}} \operatorname {EllipticF}\left (\arccos \left (\frac {\sqrt [3]{b c-a d}-\left (1-\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}}{\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}}\right ),\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{4 \sqrt [4]{3} b^{2/3} \sqrt {-\frac {\sqrt [3]{b} \sqrt [3]{c+d x} \left (\sqrt [3]{b c-a d}-\sqrt [3]{b} \sqrt [3]{c+d x}\right )}{\left (\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}\right )^2}} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}\right )}{4 d^2}\right )}{14 d}\right )}{4 d}\) |
Input:
Int[(a + b*x)^(5/2)/(c + d*x)^(1/6),x]
Output:
(3*(a + b*x)^(5/2)*(c + d*x)^(5/6))/(10*d) - (3*(b*c - a*d)*((3*(a + b*x)^ (3/2)*(c + d*x)^(5/6))/(7*d) - (9*(b*c - a*d)*((3*Sqrt[a + b*x]*(c + d*x)^ (5/6))/(4*d) - (9*(b*c - a*d)*((-(((1 + Sqrt[3])*d*(c + d*x)^(1/6)*Sqrt[a - (b*c)/d + (b*(c + d*x))/d])/((b*c - a*d)^(1/3) - (1 + Sqrt[3])*b^(1/3)*( c + d*x)^(1/3))) - (3^(1/4)*(b*c - a*d)^(1/3)*(c + d*x)^(1/6)*((b*c - a*d) ^(1/3) - b^(1/3)*(c + d*x)^(1/3))*Sqrt[((b*c - a*d)^(2/3) + b^(1/3)*(b*c - a*d)^(1/3)*(c + d*x)^(1/3) + b^(2/3)*(c + d*x)^(2/3))/((b*c - a*d)^(1/3) - (1 + Sqrt[3])*b^(1/3)*(c + d*x)^(1/3))^2]*EllipticE[ArcCos[((b*c - a*d)^ (1/3) - (1 - Sqrt[3])*b^(1/3)*(c + d*x)^(1/3))/((b*c - a*d)^(1/3) - (1 + S qrt[3])*b^(1/3)*(c + d*x)^(1/3))], (2 + Sqrt[3])/4])/(Sqrt[-((b^(1/3)*(c + d*x)^(1/3)*((b*c - a*d)^(1/3) - b^(1/3)*(c + d*x)^(1/3)))/((b*c - a*d)^(1 /3) - (1 + Sqrt[3])*b^(1/3)*(c + d*x)^(1/3))^2)]*Sqrt[a - (b*c)/d + (b*(c + d*x))/d]))/(2*b^(2/3)) - ((1 - Sqrt[3])*(b*c - a*d)^(1/3)*(c + d*x)^(1/6 )*((b*c - a*d)^(1/3) - b^(1/3)*(c + d*x)^(1/3))*Sqrt[((b*c - a*d)^(2/3) + b^(1/3)*(b*c - a*d)^(1/3)*(c + d*x)^(1/3) + b^(2/3)*(c + d*x)^(2/3))/((b*c - a*d)^(1/3) - (1 + Sqrt[3])*b^(1/3)*(c + d*x)^(1/3))^2]*EllipticF[ArcCos [((b*c - a*d)^(1/3) - (1 - Sqrt[3])*b^(1/3)*(c + d*x)^(1/3))/((b*c - a*d)^ (1/3) - (1 + Sqrt[3])*b^(1/3)*(c + d*x)^(1/3))], (2 + Sqrt[3])/4])/(4*3^(1 /4)*b^(2/3)*Sqrt[-((b^(1/3)*(c + d*x)^(1/3)*((b*c - a*d)^(1/3) - b^(1/3)*( c + d*x)^(1/3)))/((b*c - a*d)^(1/3) - (1 + Sqrt[3])*b^(1/3)*(c + d*x)^(...
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + n + 1))), x] + Simp[n*((b*c - a*d)/( b*(m + n + 1))) Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] && GtQ[n, 0] && NeQ[m + n + 1, 0] && !(IGtQ[m, 0] && ( !Integer Q[n] || (GtQ[m, 0] && LtQ[m - n, 0]))) && !ILtQ[m + n + 2, 0] && IntLinear Q[a, b, c, d, m, n, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ {p = Denominator[m]}, Simp[p/b Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL inearQ[a, b, c, d, m, n, x]
Int[1/Sqrt[(a_) + (b_.)*(x_)^6], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, Simp[x*(s + r*x^2)*(Sqrt[(s^2 - r*s*x^2 + r^2*x^4)/ (s + (1 + Sqrt[3])*r*x^2)^2]/(2*3^(1/4)*s*Sqrt[a + b*x^6]*Sqrt[r*x^2*((s + r*x^2)/(s + (1 + Sqrt[3])*r*x^2)^2)]))*EllipticF[ArcCos[(s + (1 - Sqrt[3])* r*x^2)/(s + (1 + Sqrt[3])*r*x^2)], (2 + Sqrt[3])/4], x]] /; FreeQ[{a, b}, x ]
Int[(x_)^4/Sqrt[(a_) + (b_.)*(x_)^6], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, Simp[(Sqrt[3] - 1)*(s^2/(2*r^2)) Int[1/Sqrt[ a + b*x^6], x], x] - Simp[1/(2*r^2) Int[((Sqrt[3] - 1)*s^2 - 2*r^2*x^4)/S qrt[a + b*x^6], x], x]] /; FreeQ[{a, b}, x]
Int[((c_) + (d_.)*(x_)^4)/Sqrt[(a_) + (b_.)*(x_)^6], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, Simp[(1 + Sqrt[3])*d*s^3*x*(Sqr t[a + b*x^6]/(2*a*r^2*(s + (1 + Sqrt[3])*r*x^2))), x] - Simp[3^(1/4)*d*s*x* (s + r*x^2)*(Sqrt[(s^2 - r*s*x^2 + r^2*x^4)/(s + (1 + Sqrt[3])*r*x^2)^2]/(2 *r^2*Sqrt[(r*x^2*(s + r*x^2))/(s + (1 + Sqrt[3])*r*x^2)^2]*Sqrt[a + b*x^6]) )*EllipticE[ArcCos[(s + (1 - Sqrt[3])*r*x^2)/(s + (1 + Sqrt[3])*r*x^2)], (2 + Sqrt[3])/4], x]] /; FreeQ[{a, b, c, d}, x] && EqQ[2*Rt[b/a, 3]^2*c - (1 - Sqrt[3])*d, 0]
\[\int \frac {\left (b x +a \right )^{\frac {5}{2}}}{\left (x d +c \right )^{\frac {1}{6}}}d x\]
Input:
int((b*x+a)^(5/2)/(d*x+c)^(1/6),x)
Output:
int((b*x+a)^(5/2)/(d*x+c)^(1/6),x)
\[ \int \frac {(a+b x)^{5/2}}{\sqrt [6]{c+d x}} \, dx=\int { \frac {{\left (b x + a\right )}^{\frac {5}{2}}}{{\left (d x + c\right )}^{\frac {1}{6}}} \,d x } \] Input:
integrate((b*x+a)^(5/2)/(d*x+c)^(1/6),x, algorithm="fricas")
Output:
integral((b^2*x^2 + 2*a*b*x + a^2)*sqrt(b*x + a)/(d*x + c)^(1/6), x)
\[ \int \frac {(a+b x)^{5/2}}{\sqrt [6]{c+d x}} \, dx=\int \frac {\left (a + b x\right )^{\frac {5}{2}}}{\sqrt [6]{c + d x}}\, dx \] Input:
integrate((b*x+a)**(5/2)/(d*x+c)**(1/6),x)
Output:
Integral((a + b*x)**(5/2)/(c + d*x)**(1/6), x)
\[ \int \frac {(a+b x)^{5/2}}{\sqrt [6]{c+d x}} \, dx=\int { \frac {{\left (b x + a\right )}^{\frac {5}{2}}}{{\left (d x + c\right )}^{\frac {1}{6}}} \,d x } \] Input:
integrate((b*x+a)^(5/2)/(d*x+c)^(1/6),x, algorithm="maxima")
Output:
integrate((b*x + a)^(5/2)/(d*x + c)^(1/6), x)
\[ \int \frac {(a+b x)^{5/2}}{\sqrt [6]{c+d x}} \, dx=\int { \frac {{\left (b x + a\right )}^{\frac {5}{2}}}{{\left (d x + c\right )}^{\frac {1}{6}}} \,d x } \] Input:
integrate((b*x+a)^(5/2)/(d*x+c)^(1/6),x, algorithm="giac")
Output:
integrate((b*x + a)^(5/2)/(d*x + c)^(1/6), x)
Timed out. \[ \int \frac {(a+b x)^{5/2}}{\sqrt [6]{c+d x}} \, dx=\int \frac {{\left (a+b\,x\right )}^{5/2}}{{\left (c+d\,x\right )}^{1/6}} \,d x \] Input:
int((a + b*x)^(5/2)/(c + d*x)^(1/6),x)
Output:
int((a + b*x)^(5/2)/(c + d*x)^(1/6), x)
\[ \int \frac {(a+b x)^{5/2}}{\sqrt [6]{c+d x}} \, dx=\left (\int \frac {\sqrt {b x +a}}{\left (d x +c \right )^{\frac {1}{6}}}d x \right ) a^{2}+\left (\int \frac {\sqrt {b x +a}\, x^{2}}{\left (d x +c \right )^{\frac {1}{6}}}d x \right ) b^{2}+2 \left (\int \frac {\sqrt {b x +a}\, x}{\left (d x +c \right )^{\frac {1}{6}}}d x \right ) a b \] Input:
int((b*x+a)^(5/2)/(d*x+c)^(1/6),x)
Output:
int(sqrt(a + b*x)/(c + d*x)**(1/6),x)*a**2 + int((sqrt(a + b*x)*x**2)/(c + d*x)**(1/6),x)*b**2 + 2*int((sqrt(a + b*x)*x)/(c + d*x)**(1/6),x)*a*b