\(\int \frac {1}{(a+b x) (c+d x)^{9/5}} \, dx\) [673]

Optimal result
Mathematica [A] (verified)
Rubi [C] (verified)
Maple [A] (verified)
Fricas [C] (verification not implemented)
Sympy [F]
Maxima [A] (verification not implemented)
Giac [A] (verification not implemented)
Mupad [B] (verification not implemented)
Reduce [F]

Optimal result

Integrand size = 17, antiderivative size = 505 \[ \int \frac {1}{(a+b x) (c+d x)^{9/5}} \, dx=\frac {5}{4 (b c-a d) (c+d x)^{4/5}}+\frac {\sqrt {\frac {1}{2} \left (5+\sqrt {5}\right )} b^{4/5} \arctan \left (\sqrt {\frac {1}{5} \left (5-2 \sqrt {5}\right )}-\frac {2 \sqrt {\frac {2}{5+\sqrt {5}}} \sqrt [5]{b} \sqrt [5]{c+d x}}{\sqrt [5]{b c-a d}}\right )}{(b c-a d)^{9/5}}-\frac {\sqrt {\frac {1}{2} \left (5-\sqrt {5}\right )} b^{4/5} \arctan \left (\sqrt {\frac {1}{5} \left (5+2 \sqrt {5}\right )}+\frac {\sqrt {\frac {2}{5} \left (5+\sqrt {5}\right )} \sqrt [5]{b} \sqrt [5]{c+d x}}{\sqrt [5]{b c-a d}}\right )}{(b c-a d)^{9/5}}+\frac {b^{4/5} \log \left (\sqrt [5]{b c-a d}-\sqrt [5]{b} \sqrt [5]{c+d x}\right )}{(b c-a d)^{9/5}}-\frac {\left (1-\sqrt {5}\right ) b^{4/5} \log \left (2 (b c-a d)^{2/5}+\sqrt [5]{b} \sqrt [5]{b c-a d} \sqrt [5]{c+d x}-\sqrt {5} \sqrt [5]{b} \sqrt [5]{b c-a d} \sqrt [5]{c+d x}+2 b^{2/5} (c+d x)^{2/5}\right )}{4 (b c-a d)^{9/5}}-\frac {\left (1+\sqrt {5}\right ) b^{4/5} \log \left (2 (b c-a d)^{2/5}+\sqrt [5]{b} \sqrt [5]{b c-a d} \sqrt [5]{c+d x}+\sqrt {5} \sqrt [5]{b} \sqrt [5]{b c-a d} \sqrt [5]{c+d x}+2 b^{2/5} (c+d x)^{2/5}\right )}{4 (b c-a d)^{9/5}} \] Output:

5/4/(-a*d+b*c)/(d*x+c)^(4/5)-1/2*(10+2*5^(1/2))^(1/2)*b^(4/5)*arctan(-1/5* 
(25-10*5^(1/2))^(1/2)+2*2^(1/2)/(5+5^(1/2))^(1/2)*b^(1/5)*(d*x+c)^(1/5)/(- 
a*d+b*c)^(1/5))/(-a*d+b*c)^(9/5)-1/2*(10-2*5^(1/2))^(1/2)*b^(4/5)*arctan(1 
/5*(25+10*5^(1/2))^(1/2)+1/5*(50+10*5^(1/2))^(1/2)*b^(1/5)*(d*x+c)^(1/5)/( 
-a*d+b*c)^(1/5))/(-a*d+b*c)^(9/5)+b^(4/5)*ln((-a*d+b*c)^(1/5)-b^(1/5)*(d*x 
+c)^(1/5))/(-a*d+b*c)^(9/5)-1/4*(-5^(1/2)+1)*b^(4/5)*ln(2*(-a*d+b*c)^(2/5) 
+b^(1/5)*(-a*d+b*c)^(1/5)*(d*x+c)^(1/5)-5^(1/2)*b^(1/5)*(-a*d+b*c)^(1/5)*( 
d*x+c)^(1/5)+2*b^(2/5)*(d*x+c)^(2/5))/(-a*d+b*c)^(9/5)-1/4*(5^(1/2)+1)*b^( 
4/5)*ln(2*(-a*d+b*c)^(2/5)+b^(1/5)*(-a*d+b*c)^(1/5)*(d*x+c)^(1/5)+5^(1/2)* 
b^(1/5)*(-a*d+b*c)^(1/5)*(d*x+c)^(1/5)+2*b^(2/5)*(d*x+c)^(2/5))/(-a*d+b*c) 
^(9/5)
 

Mathematica [A] (verified)

Time = 1.20 (sec) , antiderivative size = 446, normalized size of antiderivative = 0.88 \[ \int \frac {1}{(a+b x) (c+d x)^{9/5}} \, dx=\frac {1}{4} \left (\frac {5}{(b c-a d) (c+d x)^{4/5}}+\frac {2 \sqrt {10-2 \sqrt {5}} b^{4/5} \arctan \left (\frac {1}{10} \sqrt {\frac {1}{2} \left (5+\sqrt {5}\right )} \left (5+\sqrt {5}-\frac {4 \sqrt {5} \sqrt [5]{b} \sqrt [5]{c+d x}}{\sqrt [5]{-b c+a d}}\right )\right )}{(-b c+a d)^{9/5}}-\frac {2 \sqrt {2 \left (5+\sqrt {5}\right )} b^{4/5} \arctan \left (\frac {1}{10} \sqrt {\frac {1}{2} \left (5-\sqrt {5}\right )} \left (5-\sqrt {5}+\frac {4 \sqrt {5} \sqrt [5]{b} \sqrt [5]{c+d x}}{\sqrt [5]{-b c+a d}}\right )\right )}{(-b c+a d)^{9/5}}-\frac {4 b^{4/5} \log \left (\sqrt [5]{-b c+a d}+\sqrt [5]{b} \sqrt [5]{c+d x}\right )}{(-b c+a d)^{9/5}}-\frac {\left (-1+\sqrt {5}\right ) b^{4/5} \log \left (2 (-b c+a d)^{2/5}+\left (-1+\sqrt {5}\right ) \sqrt [5]{b} \sqrt [5]{-b c+a d} \sqrt [5]{c+d x}+2 b^{2/5} (c+d x)^{2/5}\right )}{(-b c+a d)^{9/5}}+\frac {\left (1+\sqrt {5}\right ) b^{4/5} \log \left (2 (-b c+a d)^{2/5}-\left (1+\sqrt {5}\right ) \sqrt [5]{b} \sqrt [5]{-b c+a d} \sqrt [5]{c+d x}+2 b^{2/5} (c+d x)^{2/5}\right )}{(-b c+a d)^{9/5}}\right ) \] Input:

Integrate[1/((a + b*x)*(c + d*x)^(9/5)),x]
 

Output:

(5/((b*c - a*d)*(c + d*x)^(4/5)) + (2*Sqrt[10 - 2*Sqrt[5]]*b^(4/5)*ArcTan[ 
(Sqrt[(5 + Sqrt[5])/2]*(5 + Sqrt[5] - (4*Sqrt[5]*b^(1/5)*(c + d*x)^(1/5))/ 
(-(b*c) + a*d)^(1/5)))/10])/(-(b*c) + a*d)^(9/5) - (2*Sqrt[2*(5 + Sqrt[5]) 
]*b^(4/5)*ArcTan[(Sqrt[(5 - Sqrt[5])/2]*(5 - Sqrt[5] + (4*Sqrt[5]*b^(1/5)* 
(c + d*x)^(1/5))/(-(b*c) + a*d)^(1/5)))/10])/(-(b*c) + a*d)^(9/5) - (4*b^( 
4/5)*Log[(-(b*c) + a*d)^(1/5) + b^(1/5)*(c + d*x)^(1/5)])/(-(b*c) + a*d)^( 
9/5) - ((-1 + Sqrt[5])*b^(4/5)*Log[2*(-(b*c) + a*d)^(2/5) + (-1 + Sqrt[5]) 
*b^(1/5)*(-(b*c) + a*d)^(1/5)*(c + d*x)^(1/5) + 2*b^(2/5)*(c + d*x)^(2/5)] 
)/(-(b*c) + a*d)^(9/5) + ((1 + Sqrt[5])*b^(4/5)*Log[2*(-(b*c) + a*d)^(2/5) 
 - (1 + Sqrt[5])*b^(1/5)*(-(b*c) + a*d)^(1/5)*(c + d*x)^(1/5) + 2*b^(2/5)* 
(c + d*x)^(2/5)])/(-(b*c) + a*d)^(9/5))/4
 

Rubi [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.

Time = 0.15 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.10, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.059, Rules used = {78}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{(a+b x) (c+d x)^{9/5}} \, dx\)

\(\Big \downarrow \) 78

\(\displaystyle \frac {5 \operatorname {Hypergeometric2F1}\left (-\frac {4}{5},1,\frac {1}{5},\frac {b (c+d x)}{b c-a d}\right )}{4 (c+d x)^{4/5} (b c-a d)}\)

Input:

Int[1/((a + b*x)*(c + d*x)^(9/5)),x]
 

Output:

(5*Hypergeometric2F1[-4/5, 1, 1/5, (b*(c + d*x))/(b*c - a*d)])/(4*(b*c - a 
*d)*(c + d*x)^(4/5))
 

Defintions of rubi rules used

rule 78
Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(b 
*c - a*d)^n*((a + b*x)^(m + 1)/(b^(n + 1)*(m + 1)))*Hypergeometric2F1[-n, m 
 + 1, m + 2, (-d)*((a + b*x)/(b*c - a*d))], x] /; FreeQ[{a, b, c, d, m}, x] 
 &&  !IntegerQ[m] && IntegerQ[n]
 
Maple [A] (verified)

Time = 1.31 (sec) , antiderivative size = 431, normalized size of antiderivative = 0.85

method result size
pseudoelliptic \(-\frac {4 \left (-\frac {\sqrt {5+\sqrt {5}}\, \left (x d +c \right )^{\frac {4}{5}} \sqrt {5-\sqrt {5}}\, \left (\sqrt {5}+1\right ) \ln \left (-2 \left (\frac {a d -b c}{b}\right )^{\frac {2}{5}}+\left (\sqrt {5}+1\right ) \left (x d +c \right )^{\frac {1}{5}} \left (\frac {a d -b c}{b}\right )^{\frac {1}{5}}-2 \left (x d +c \right )^{\frac {2}{5}}\right )}{4}+\frac {\sqrt {5+\sqrt {5}}\, \left (x d +c \right )^{\frac {4}{5}} \sqrt {5-\sqrt {5}}\, \left (\sqrt {5}-1\right ) \ln \left (2 \left (\frac {a d -b c}{b}\right )^{\frac {2}{5}}+\left (\sqrt {5}-1\right ) \left (x d +c \right )^{\frac {1}{5}} \left (\frac {a d -b c}{b}\right )^{\frac {1}{5}}+2 \left (x d +c \right )^{\frac {2}{5}}\right )}{4}+\frac {\sqrt {2}\, \sqrt {5+\sqrt {5}}\, \left (x d +c \right )^{\frac {4}{5}} \left (\sqrt {5}-5\right ) \arctan \left (\frac {\sqrt {2}\, \left (\left (\sqrt {5}+1\right ) \left (\frac {a d -b c}{b}\right )^{\frac {1}{5}}-4 \left (x d +c \right )^{\frac {1}{5}}\right )}{2 \sqrt {5-\sqrt {5}}\, \left (\frac {a d -b c}{b}\right )^{\frac {1}{5}}}\right )}{2}+\left (\frac {\sqrt {2}\, \left (x d +c \right )^{\frac {4}{5}} \left (5+\sqrt {5}\right ) \arctan \left (\frac {\left (\left (\sqrt {5}-1\right ) \left (\frac {a d -b c}{b}\right )^{\frac {1}{5}}+4 \left (x d +c \right )^{\frac {1}{5}}\right ) \sqrt {2}}{2 \sqrt {5+\sqrt {5}}\, \left (\frac {a d -b c}{b}\right )^{\frac {1}{5}}}\right )}{2}+\sqrt {5+\sqrt {5}}\, \left (\left (x d +c \right )^{\frac {4}{5}} \ln \left (\left (x d +c \right )^{\frac {1}{5}}+\left (\frac {a d -b c}{b}\right )^{\frac {1}{5}}\right )+\frac {5 \left (\frac {a d -b c}{b}\right )^{\frac {4}{5}}}{4}\right )\right ) \sqrt {5-\sqrt {5}}\right ) \sqrt {5}}{\left (x d +c \right )^{\frac {4}{5}} \left (\frac {a d -b c}{b}\right )^{\frac {4}{5}} \left (40 a d -40 b c \right )}\) \(431\)
derivativedivides \(\text {Expression too large to display}\) \(1354\)
default \(\text {Expression too large to display}\) \(1354\)

Input:

int(1/(b*x+a)/(d*x+c)^(9/5),x,method=_RETURNVERBOSE)
 

Output:

-4/(d*x+c)^(4/5)*(-1/4*(5+5^(1/2))^(1/2)*(d*x+c)^(4/5)*(5-5^(1/2))^(1/2)*( 
5^(1/2)+1)*ln(-2*((a*d-b*c)/b)^(2/5)+(5^(1/2)+1)*(d*x+c)^(1/5)*((a*d-b*c)/ 
b)^(1/5)-2*(d*x+c)^(2/5))+1/4*(5+5^(1/2))^(1/2)*(d*x+c)^(4/5)*(5-5^(1/2))^ 
(1/2)*(5^(1/2)-1)*ln(2*((a*d-b*c)/b)^(2/5)+(5^(1/2)-1)*(d*x+c)^(1/5)*((a*d 
-b*c)/b)^(1/5)+2*(d*x+c)^(2/5))+1/2*2^(1/2)*(5+5^(1/2))^(1/2)*(d*x+c)^(4/5 
)*(5^(1/2)-5)*arctan(1/2/(5-5^(1/2))^(1/2)*2^(1/2)/((a*d-b*c)/b)^(1/5)*((5 
^(1/2)+1)*((a*d-b*c)/b)^(1/5)-4*(d*x+c)^(1/5)))+(1/2*2^(1/2)*(d*x+c)^(4/5) 
*(5+5^(1/2))*arctan(1/2*((5^(1/2)-1)*((a*d-b*c)/b)^(1/5)+4*(d*x+c)^(1/5))/ 
(5+5^(1/2))^(1/2)/((a*d-b*c)/b)^(1/5)*2^(1/2))+(5+5^(1/2))^(1/2)*((d*x+c)^ 
(4/5)*ln((d*x+c)^(1/5)+((a*d-b*c)/b)^(1/5))+5/4*((a*d-b*c)/b)^(4/5)))*(5-5 
^(1/2))^(1/2))*5^(1/2)/((a*d-b*c)/b)^(4/5)/(40*a*d-40*b*c)
 

Fricas [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 5.65 (sec) , antiderivative size = 216715, normalized size of antiderivative = 429.14 \[ \int \frac {1}{(a+b x) (c+d x)^{9/5}} \, dx=\text {Too large to display} \] Input:

integrate(1/(b*x+a)/(d*x+c)^(9/5),x, algorithm="fricas")
 

Output:

Too large to include
 

Sympy [F]

\[ \int \frac {1}{(a+b x) (c+d x)^{9/5}} \, dx=\int \frac {1}{\left (a + b x\right ) \left (c + d x\right )^{\frac {9}{5}}}\, dx \] Input:

integrate(1/(b*x+a)/(d*x+c)**(9/5),x)
 

Output:

Integral(1/((a + b*x)*(c + d*x)**(9/5)), x)
                                                                                    
                                                                                    
 

Maxima [A] (verification not implemented)

Time = 0.15 (sec) , antiderivative size = 534, normalized size of antiderivative = 1.06 \[ \int \frac {1}{(a+b x) (c+d x)^{9/5}} \, dx =\text {Too large to display} \] Input:

integrate(1/(b*x+a)/(d*x+c)^(9/5),x, algorithm="maxima")
 

Output:

1/4*(2*(sqrt(5)*d*(sqrt(5) - 1)*log(((-b*c + a*d)^(1/5)*b^(1/5)*(sqrt(5) + 
 1) + (-b*c + a*d)^(1/5)*b^(1/5)*sqrt(2*sqrt(5) - 10) - 4*(d*x + c)^(1/5)* 
b^(2/5))/((-b*c + a*d)^(1/5)*b^(1/5)*(sqrt(5) + 1) - (-b*c + a*d)^(1/5)*b^ 
(1/5)*sqrt(2*sqrt(5) - 10) - 4*(d*x + c)^(1/5)*b^(2/5)))/((-b*c + a*d)^(4/ 
5)*b^(1/5)*sqrt(2*sqrt(5) - 10)) + sqrt(5)*d*(sqrt(5) + 1)*log(((-b*c + a* 
d)^(1/5)*b^(1/5)*(sqrt(5) - 1) - (-b*c + a*d)^(1/5)*b^(1/5)*sqrt(-2*sqrt(5 
) - 10) + 4*(d*x + c)^(1/5)*b^(2/5))/((-b*c + a*d)^(1/5)*b^(1/5)*(sqrt(5) 
- 1) + (-b*c + a*d)^(1/5)*b^(1/5)*sqrt(-2*sqrt(5) - 10) + 4*(d*x + c)^(1/5 
)*b^(2/5)))/((-b*c + a*d)^(4/5)*b^(1/5)*sqrt(-2*sqrt(5) - 10)) - d*(sqrt(5 
) + 3)*log(-(-b*c + a*d)^(1/5)*(d*x + c)^(1/5)*b^(1/5)*(sqrt(5) + 1) + 2*( 
d*x + c)^(2/5)*b^(2/5) + 2*(-b*c + a*d)^(2/5))/((-b*c + a*d)^(4/5)*b^(1/5) 
*(sqrt(5) + 1)) - d*(sqrt(5) - 3)*log((-b*c + a*d)^(1/5)*(d*x + c)^(1/5)*b 
^(1/5)*(sqrt(5) - 1) + 2*(d*x + c)^(2/5)*b^(2/5) + 2*(-b*c + a*d)^(2/5))/( 
(-b*c + a*d)^(4/5)*b^(1/5)*(sqrt(5) - 1)) + 2*d*log((d*x + c)^(1/5)*b^(1/5 
) + (-b*c + a*d)^(1/5))/((-b*c + a*d)^(4/5)*b^(1/5)))*b/(b*c - a*d) + 5*d/ 
((b*c - a*d)*(d*x + c)^(4/5)))/d
 

Giac [A] (verification not implemented)

Time = 0.36 (sec) , antiderivative size = 535, normalized size of antiderivative = 1.06 \[ \int \frac {1}{(a+b x) (c+d x)^{9/5}} \, dx=\frac {b \left (\frac {b c - a d}{b}\right )^{\frac {1}{5}} \log \left ({\left | {\left (d x + c\right )}^{\frac {1}{5}} - \left (\frac {b c - a d}{b}\right )^{\frac {1}{5}} \right |}\right )}{b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}} - \frac {{\left (b^{5} c - a b^{4} d\right )}^{\frac {1}{5}} \sqrt {2 \, \sqrt {5} + 10} \arctan \left (-\frac {{\left (\sqrt {5} - 1\right )} \left (\frac {b c - a d}{b}\right )^{\frac {1}{5}} - 4 \, {\left (d x + c\right )}^{\frac {1}{5}}}{\sqrt {2 \, \sqrt {5} + 10} \left (\frac {b c - a d}{b}\right )^{\frac {1}{5}}}\right )}{2 \, {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )}} - \frac {{\left (b^{5} c - a b^{4} d\right )}^{\frac {1}{5}} \sqrt {-2 \, \sqrt {5} + 10} \arctan \left (\frac {{\left (\sqrt {5} + 1\right )} \left (\frac {b c - a d}{b}\right )^{\frac {1}{5}} + 4 \, {\left (d x + c\right )}^{\frac {1}{5}}}{\sqrt {-2 \, \sqrt {5} + 10} \left (\frac {b c - a d}{b}\right )^{\frac {1}{5}}}\right )}{2 \, {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )}} - \frac {{\left (b^{5} c - a b^{4} d\right )}^{\frac {1}{5}} \log \left (\frac {1}{2} \, {\left (d x + c\right )}^{\frac {1}{5}} {\left (\sqrt {5} \left (\frac {b c - a d}{b}\right )^{\frac {1}{5}} + \left (\frac {b c - a d}{b}\right )^{\frac {1}{5}}\right )} + {\left (d x + c\right )}^{\frac {2}{5}} + \left (\frac {b c - a d}{b}\right )^{\frac {2}{5}}\right )}{b^{2} c^{2} {\left (\sqrt {5} - 1\right )} - 2 \, a b c d {\left (\sqrt {5} - 1\right )} + a^{2} d^{2} {\left (\sqrt {5} - 1\right )}} + \frac {{\left (b^{5} c - a b^{4} d\right )}^{\frac {1}{5}} \log \left (-\frac {1}{2} \, {\left (d x + c\right )}^{\frac {1}{5}} {\left (\sqrt {5} \left (\frac {b c - a d}{b}\right )^{\frac {1}{5}} - \left (\frac {b c - a d}{b}\right )^{\frac {1}{5}}\right )} + {\left (d x + c\right )}^{\frac {2}{5}} + \left (\frac {b c - a d}{b}\right )^{\frac {2}{5}}\right )}{b^{2} c^{2} {\left (\sqrt {5} + 1\right )} - 2 \, a b c d {\left (\sqrt {5} + 1\right )} + a^{2} d^{2} {\left (\sqrt {5} + 1\right )}} + \frac {5}{4 \, {\left (b c - a d\right )} {\left (d x + c\right )}^{\frac {4}{5}}} \] Input:

integrate(1/(b*x+a)/(d*x+c)^(9/5),x, algorithm="giac")
 

Output:

b*((b*c - a*d)/b)^(1/5)*log(abs((d*x + c)^(1/5) - ((b*c - a*d)/b)^(1/5)))/ 
(b^2*c^2 - 2*a*b*c*d + a^2*d^2) - 1/2*(b^5*c - a*b^4*d)^(1/5)*sqrt(2*sqrt( 
5) + 10)*arctan(-((sqrt(5) - 1)*((b*c - a*d)/b)^(1/5) - 4*(d*x + c)^(1/5)) 
/(sqrt(2*sqrt(5) + 10)*((b*c - a*d)/b)^(1/5)))/(b^2*c^2 - 2*a*b*c*d + a^2* 
d^2) - 1/2*(b^5*c - a*b^4*d)^(1/5)*sqrt(-2*sqrt(5) + 10)*arctan(((sqrt(5) 
+ 1)*((b*c - a*d)/b)^(1/5) + 4*(d*x + c)^(1/5))/(sqrt(-2*sqrt(5) + 10)*((b 
*c - a*d)/b)^(1/5)))/(b^2*c^2 - 2*a*b*c*d + a^2*d^2) - (b^5*c - a*b^4*d)^( 
1/5)*log(1/2*(d*x + c)^(1/5)*(sqrt(5)*((b*c - a*d)/b)^(1/5) + ((b*c - a*d) 
/b)^(1/5)) + (d*x + c)^(2/5) + ((b*c - a*d)/b)^(2/5))/(b^2*c^2*(sqrt(5) - 
1) - 2*a*b*c*d*(sqrt(5) - 1) + a^2*d^2*(sqrt(5) - 1)) + (b^5*c - a*b^4*d)^ 
(1/5)*log(-1/2*(d*x + c)^(1/5)*(sqrt(5)*((b*c - a*d)/b)^(1/5) - ((b*c - a* 
d)/b)^(1/5)) + (d*x + c)^(2/5) + ((b*c - a*d)/b)^(2/5))/(b^2*c^2*(sqrt(5) 
+ 1) - 2*a*b*c*d*(sqrt(5) + 1) + a^2*d^2*(sqrt(5) + 1)) + 5/4/((b*c - a*d) 
*(d*x + c)^(4/5))
 

Mupad [B] (verification not implemented)

Time = 0.13 (sec) , antiderivative size = 1059, normalized size of antiderivative = 2.10 \[ \int \frac {1}{(a+b x) (c+d x)^{9/5}} \, dx =\text {Too large to display} \] Input:

int(1/((a + b*x)*(c + d*x)^(9/5)),x)
 

Output:

(b^(4/5)*log((c + d*x)^(1/5)*(625*b^11*c^4 + 625*a^4*b^7*d^4 - 2500*a^3*b^ 
8*c*d^3 + 3750*a^2*b^9*c^2*d^2 - 2500*a*b^10*c^3*d) - (b^(4/5)*(625*b^12*c 
^6 + 625*a^6*b^6*d^6 - 3750*a^5*b^7*c*d^5 + 9375*a^2*b^10*c^4*d^2 - 12500* 
a^3*b^9*c^3*d^3 + 9375*a^4*b^8*c^2*d^4 - 3750*a*b^11*c^5*d))/(b*c - a*d)^( 
9/5)))/(b*c - a*d)^(9/5) - 5/(4*(a*d - b*c)*(c + d*x)^(4/5)) - (b^(4/5)*lo 
g((c + d*x)^(1/5)*(625*b^11*c^4 + 625*a^4*b^7*d^4 - 2500*a^3*b^8*c*d^3 + 3 
750*a^2*b^9*c^2*d^2 - 2500*a*b^10*c^3*d) + (b^(4/5)*((- 2*5^(1/2) - 10)^(1 
/2)/4 - 5^(1/2)/4 + 1/4)*(625*b^12*c^6 + 625*a^6*b^6*d^6 - 3750*a^5*b^7*c* 
d^5 + 9375*a^2*b^10*c^4*d^2 - 12500*a^3*b^9*c^3*d^3 + 9375*a^4*b^8*c^2*d^4 
 - 3750*a*b^11*c^5*d))/(b*c - a*d)^(9/5))*((- 2*5^(1/2) - 10)^(1/2)/4 - 5^ 
(1/2)/4 + 1/4))/(b*c - a*d)^(9/5) - (b^(4/5)*log((c + d*x)^(1/5)*(625*b^11 
*c^4 + 625*a^4*b^7*d^4 - 2500*a^3*b^8*c*d^3 + 3750*a^2*b^9*c^2*d^2 - 2500* 
a*b^10*c^3*d) + (b^(4/5)*(5^(1/2)/4 - (2*5^(1/2) - 10)^(1/2)/4 + 1/4)*(625 
*b^12*c^6 + 625*a^6*b^6*d^6 - 3750*a^5*b^7*c*d^5 + 9375*a^2*b^10*c^4*d^2 - 
 12500*a^3*b^9*c^3*d^3 + 9375*a^4*b^8*c^2*d^4 - 3750*a*b^11*c^5*d))/(b*c - 
 a*d)^(9/5))*(5^(1/2)/4 - (2*5^(1/2) - 10)^(1/2)/4 + 1/4))/(b*c - a*d)^(9/ 
5) - (b^(4/5)*log((c + d*x)^(1/5)*(625*b^11*c^4 + 625*a^4*b^7*d^4 - 2500*a 
^3*b^8*c*d^3 + 3750*a^2*b^9*c^2*d^2 - 2500*a*b^10*c^3*d) + (b^(4/5)*(5^(1/ 
2)/4 + (2*5^(1/2) - 10)^(1/2)/4 + 1/4)*(625*b^12*c^6 + 625*a^6*b^6*d^6 - 3 
750*a^5*b^7*c*d^5 + 9375*a^2*b^10*c^4*d^2 - 12500*a^3*b^9*c^3*d^3 + 937...
 

Reduce [F]

\[ \int \frac {1}{(a+b x) (c+d x)^{9/5}} \, dx=\int \frac {\left (d x +c \right )^{\frac {1}{5}}}{b \,d^{2} x^{3}+a \,d^{2} x^{2}+2 b c d \,x^{2}+2 a c d x +b \,c^{2} x +a \,c^{2}}d x \] Input:

int(1/(b*x+a)/(d*x+c)^(9/5),x)
 

Output:

int((c + d*x)**(1/5)/(a*c**2 + 2*a*c*d*x + a*d**2*x**2 + b*c**2*x + 2*b*c* 
d*x**2 + b*d**2*x**3),x)