Integrand size = 15, antiderivative size = 78 \[ \int \frac {(c+d x)^3}{(a+b x)^3} \, dx=\frac {d^3 x}{b^3}-\frac {(b c-a d)^3}{2 b^4 (a+b x)^2}-\frac {3 d (b c-a d)^2}{b^4 (a+b x)}+\frac {3 d^2 (b c-a d) \log (a+b x)}{b^4} \] Output:
d^3*x/b^3-1/2*(-a*d+b*c)^3/b^4/(b*x+a)^2-3*d*(-a*d+b*c)^2/b^4/(b*x+a)+3*d^ 2*(-a*d+b*c)*ln(b*x+a)/b^4
Time = 0.03 (sec) , antiderivative size = 114, normalized size of antiderivative = 1.46 \[ \int \frac {(c+d x)^3}{(a+b x)^3} \, dx=\frac {-5 a^3 d^3+a^2 b d^2 (9 c-4 d x)+a b^2 d \left (-3 c^2+12 c d x+4 d^2 x^2\right )-b^3 \left (c^3+6 c^2 d x-2 d^3 x^3\right )-6 d^2 (-b c+a d) (a+b x)^2 \log (a+b x)}{2 b^4 (a+b x)^2} \] Input:
Integrate[(c + d*x)^3/(a + b*x)^3,x]
Output:
(-5*a^3*d^3 + a^2*b*d^2*(9*c - 4*d*x) + a*b^2*d*(-3*c^2 + 12*c*d*x + 4*d^2 *x^2) - b^3*(c^3 + 6*c^2*d*x - 2*d^3*x^3) - 6*d^2*(-(b*c) + a*d)*(a + b*x) ^2*Log[a + b*x])/(2*b^4*(a + b*x)^2)
Time = 0.21 (sec) , antiderivative size = 78, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {49, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {(c+d x)^3}{(a+b x)^3} \, dx\) |
\(\Big \downarrow \) 49 |
\(\displaystyle \int \left (\frac {3 d^2 (b c-a d)}{b^3 (a+b x)}+\frac {3 d (b c-a d)^2}{b^3 (a+b x)^2}+\frac {(b c-a d)^3}{b^3 (a+b x)^3}+\frac {d^3}{b^3}\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {3 d^2 (b c-a d) \log (a+b x)}{b^4}-\frac {3 d (b c-a d)^2}{b^4 (a+b x)}-\frac {(b c-a d)^3}{2 b^4 (a+b x)^2}+\frac {d^3 x}{b^3}\) |
Input:
Int[(c + d*x)^3/(a + b*x)^3,x]
Output:
(d^3*x)/b^3 - (b*c - a*d)^3/(2*b^4*(a + b*x)^2) - (3*d*(b*c - a*d)^2)/(b^4 *(a + b*x)) + (3*d^2*(b*c - a*d)*Log[a + b*x])/b^4
Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int [ExpandIntegrand[(a + b*x)^m*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && IGtQ[m, 0] && IGtQ[m + n + 2, 0]
Time = 0.10 (sec) , antiderivative size = 114, normalized size of antiderivative = 1.46
method | result | size |
default | \(\frac {d^{3} x}{b^{3}}-\frac {-a^{3} d^{3}+3 a^{2} b c \,d^{2}-3 a \,b^{2} c^{2} d +b^{3} c^{3}}{2 b^{4} \left (b x +a \right )^{2}}-\frac {3 d \left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right )}{b^{4} \left (b x +a \right )}-\frac {3 d^{2} \left (a d -b c \right ) \ln \left (b x +a \right )}{b^{4}}\) | \(114\) |
norman | \(\frac {\frac {d^{3} x^{3}}{b}-\frac {9 a^{3} d^{3}-9 a^{2} b c \,d^{2}+3 a \,b^{2} c^{2} d +b^{3} c^{3}}{2 b^{4}}-\frac {\left (6 a^{2} d^{3}-6 a b c \,d^{2}+3 b^{2} c^{2} d \right ) x}{b^{3}}}{\left (b x +a \right )^{2}}-\frac {3 d^{2} \left (a d -b c \right ) \ln \left (b x +a \right )}{b^{4}}\) | \(116\) |
risch | \(\frac {d^{3} x}{b^{3}}+\frac {\left (-3 a^{2} d^{3}+6 a b c \,d^{2}-3 b^{2} c^{2} d \right ) x -\frac {5 a^{3} d^{3}-9 a^{2} b c \,d^{2}+3 a \,b^{2} c^{2} d +b^{3} c^{3}}{2 b}}{b^{3} \left (b x +a \right )^{2}}-\frac {3 d^{3} \ln \left (b x +a \right ) a}{b^{4}}+\frac {3 d^{2} \ln \left (b x +a \right ) c}{b^{3}}\) | \(121\) |
parallelrisch | \(-\frac {6 \ln \left (b x +a \right ) x^{2} a \,b^{2} d^{3}-6 \ln \left (b x +a \right ) x^{2} b^{3} c \,d^{2}-2 d^{3} x^{3} b^{3}+12 \ln \left (b x +a \right ) x \,a^{2} b \,d^{3}-12 \ln \left (b x +a \right ) x a \,b^{2} c \,d^{2}+6 \ln \left (b x +a \right ) a^{3} d^{3}-6 \ln \left (b x +a \right ) a^{2} b c \,d^{2}+12 x \,a^{2} b \,d^{3}-12 x a \,b^{2} c \,d^{2}+6 x \,b^{3} c^{2} d +9 a^{3} d^{3}-9 a^{2} b c \,d^{2}+3 a \,b^{2} c^{2} d +b^{3} c^{3}}{2 b^{4} \left (b x +a \right )^{2}}\) | \(190\) |
Input:
int((d*x+c)^3/(b*x+a)^3,x,method=_RETURNVERBOSE)
Output:
d^3*x/b^3-1/2/b^4*(-a^3*d^3+3*a^2*b*c*d^2-3*a*b^2*c^2*d+b^3*c^3)/(b*x+a)^2 -3*d/b^4*(a^2*d^2-2*a*b*c*d+b^2*c^2)/(b*x+a)-3/b^4*d^2*(a*d-b*c)*ln(b*x+a)
Leaf count of result is larger than twice the leaf count of optimal. 188 vs. \(2 (76) = 152\).
Time = 0.08 (sec) , antiderivative size = 188, normalized size of antiderivative = 2.41 \[ \int \frac {(c+d x)^3}{(a+b x)^3} \, dx=\frac {2 \, b^{3} d^{3} x^{3} + 4 \, a b^{2} d^{3} x^{2} - b^{3} c^{3} - 3 \, a b^{2} c^{2} d + 9 \, a^{2} b c d^{2} - 5 \, a^{3} d^{3} - 2 \, {\left (3 \, b^{3} c^{2} d - 6 \, a b^{2} c d^{2} + 2 \, a^{2} b d^{3}\right )} x + 6 \, {\left (a^{2} b c d^{2} - a^{3} d^{3} + {\left (b^{3} c d^{2} - a b^{2} d^{3}\right )} x^{2} + 2 \, {\left (a b^{2} c d^{2} - a^{2} b d^{3}\right )} x\right )} \log \left (b x + a\right )}{2 \, {\left (b^{6} x^{2} + 2 \, a b^{5} x + a^{2} b^{4}\right )}} \] Input:
integrate((d*x+c)^3/(b*x+a)^3,x, algorithm="fricas")
Output:
1/2*(2*b^3*d^3*x^3 + 4*a*b^2*d^3*x^2 - b^3*c^3 - 3*a*b^2*c^2*d + 9*a^2*b*c *d^2 - 5*a^3*d^3 - 2*(3*b^3*c^2*d - 6*a*b^2*c*d^2 + 2*a^2*b*d^3)*x + 6*(a^ 2*b*c*d^2 - a^3*d^3 + (b^3*c*d^2 - a*b^2*d^3)*x^2 + 2*(a*b^2*c*d^2 - a^2*b *d^3)*x)*log(b*x + a))/(b^6*x^2 + 2*a*b^5*x + a^2*b^4)
Time = 0.39 (sec) , antiderivative size = 128, normalized size of antiderivative = 1.64 \[ \int \frac {(c+d x)^3}{(a+b x)^3} \, dx=\frac {- 5 a^{3} d^{3} + 9 a^{2} b c d^{2} - 3 a b^{2} c^{2} d - b^{3} c^{3} + x \left (- 6 a^{2} b d^{3} + 12 a b^{2} c d^{2} - 6 b^{3} c^{2} d\right )}{2 a^{2} b^{4} + 4 a b^{5} x + 2 b^{6} x^{2}} + \frac {d^{3} x}{b^{3}} - \frac {3 d^{2} \left (a d - b c\right ) \log {\left (a + b x \right )}}{b^{4}} \] Input:
integrate((d*x+c)**3/(b*x+a)**3,x)
Output:
(-5*a**3*d**3 + 9*a**2*b*c*d**2 - 3*a*b**2*c**2*d - b**3*c**3 + x*(-6*a**2 *b*d**3 + 12*a*b**2*c*d**2 - 6*b**3*c**2*d))/(2*a**2*b**4 + 4*a*b**5*x + 2 *b**6*x**2) + d**3*x/b**3 - 3*d**2*(a*d - b*c)*log(a + b*x)/b**4
Time = 0.04 (sec) , antiderivative size = 125, normalized size of antiderivative = 1.60 \[ \int \frac {(c+d x)^3}{(a+b x)^3} \, dx=\frac {d^{3} x}{b^{3}} - \frac {b^{3} c^{3} + 3 \, a b^{2} c^{2} d - 9 \, a^{2} b c d^{2} + 5 \, a^{3} d^{3} + 6 \, {\left (b^{3} c^{2} d - 2 \, a b^{2} c d^{2} + a^{2} b d^{3}\right )} x}{2 \, {\left (b^{6} x^{2} + 2 \, a b^{5} x + a^{2} b^{4}\right )}} + \frac {3 \, {\left (b c d^{2} - a d^{3}\right )} \log \left (b x + a\right )}{b^{4}} \] Input:
integrate((d*x+c)^3/(b*x+a)^3,x, algorithm="maxima")
Output:
d^3*x/b^3 - 1/2*(b^3*c^3 + 3*a*b^2*c^2*d - 9*a^2*b*c*d^2 + 5*a^3*d^3 + 6*( b^3*c^2*d - 2*a*b^2*c*d^2 + a^2*b*d^3)*x)/(b^6*x^2 + 2*a*b^5*x + a^2*b^4) + 3*(b*c*d^2 - a*d^3)*log(b*x + a)/b^4
Time = 0.12 (sec) , antiderivative size = 112, normalized size of antiderivative = 1.44 \[ \int \frac {(c+d x)^3}{(a+b x)^3} \, dx=\frac {d^{3} x}{b^{3}} + \frac {3 \, {\left (b c d^{2} - a d^{3}\right )} \log \left ({\left | b x + a \right |}\right )}{b^{4}} - \frac {b^{3} c^{3} + 3 \, a b^{2} c^{2} d - 9 \, a^{2} b c d^{2} + 5 \, a^{3} d^{3} + 6 \, {\left (b^{3} c^{2} d - 2 \, a b^{2} c d^{2} + a^{2} b d^{3}\right )} x}{2 \, {\left (b x + a\right )}^{2} b^{4}} \] Input:
integrate((d*x+c)^3/(b*x+a)^3,x, algorithm="giac")
Output:
d^3*x/b^3 + 3*(b*c*d^2 - a*d^3)*log(abs(b*x + a))/b^4 - 1/2*(b^3*c^3 + 3*a *b^2*c^2*d - 9*a^2*b*c*d^2 + 5*a^3*d^3 + 6*(b^3*c^2*d - 2*a*b^2*c*d^2 + a^ 2*b*d^3)*x)/((b*x + a)^2*b^4)
Time = 0.07 (sec) , antiderivative size = 130, normalized size of antiderivative = 1.67 \[ \int \frac {(c+d x)^3}{(a+b x)^3} \, dx=\frac {d^3\,x}{b^3}-\frac {\ln \left (a+b\,x\right )\,\left (3\,a\,d^3-3\,b\,c\,d^2\right )}{b^4}-\frac {\frac {5\,a^3\,d^3-9\,a^2\,b\,c\,d^2+3\,a\,b^2\,c^2\,d+b^3\,c^3}{2\,b}+x\,\left (3\,a^2\,d^3-6\,a\,b\,c\,d^2+3\,b^2\,c^2\,d\right )}{a^2\,b^3+2\,a\,b^4\,x+b^5\,x^2} \] Input:
int((c + d*x)^3/(a + b*x)^3,x)
Output:
(d^3*x)/b^3 - (log(a + b*x)*(3*a*d^3 - 3*b*c*d^2))/b^4 - ((5*a^3*d^3 + b^3 *c^3 + 3*a*b^2*c^2*d - 9*a^2*b*c*d^2)/(2*b) + x*(3*a^2*d^3 + 3*b^2*c^2*d - 6*a*b*c*d^2))/(a^2*b^3 + b^5*x^2 + 2*a*b^4*x)
Time = 0.16 (sec) , antiderivative size = 209, normalized size of antiderivative = 2.68 \[ \int \frac {(c+d x)^3}{(a+b x)^3} \, dx=\frac {-6 \,\mathrm {log}\left (b x +a \right ) a^{4} d^{3}+6 \,\mathrm {log}\left (b x +a \right ) a^{3} b c \,d^{2}-12 \,\mathrm {log}\left (b x +a \right ) a^{3} b \,d^{3} x +12 \,\mathrm {log}\left (b x +a \right ) a^{2} b^{2} c \,d^{2} x -6 \,\mathrm {log}\left (b x +a \right ) a^{2} b^{2} d^{3} x^{2}+6 \,\mathrm {log}\left (b x +a \right ) a \,b^{3} c \,d^{2} x^{2}-3 a^{4} d^{3}+3 a^{3} b c \,d^{2}+6 a^{2} b^{2} d^{3} x^{2}-a \,b^{3} c^{3}-6 a \,b^{3} c \,d^{2} x^{2}+2 a \,b^{3} d^{3} x^{3}+3 b^{4} c^{2} d \,x^{2}}{2 a \,b^{4} \left (b^{2} x^{2}+2 a b x +a^{2}\right )} \] Input:
int((d*x+c)^3/(b*x+a)^3,x)
Output:
( - 6*log(a + b*x)*a**4*d**3 + 6*log(a + b*x)*a**3*b*c*d**2 - 12*log(a + b *x)*a**3*b*d**3*x + 12*log(a + b*x)*a**2*b**2*c*d**2*x - 6*log(a + b*x)*a* *2*b**2*d**3*x**2 + 6*log(a + b*x)*a*b**3*c*d**2*x**2 - 3*a**4*d**3 + 3*a* *3*b*c*d**2 + 6*a**2*b**2*d**3*x**2 - a*b**3*c**3 - 6*a*b**3*c*d**2*x**2 + 2*a*b**3*d**3*x**3 + 3*b**4*c**2*d*x**2)/(2*a*b**4*(a**2 + 2*a*b*x + b**2 *x**2))