Integrand size = 20, antiderivative size = 39 \[ \int x^m (1-a x)^n (2+2 a x)^n \, dx=\frac {2^n x^{1+m} \operatorname {Hypergeometric2F1}\left (\frac {1+m}{2},-n,\frac {3+m}{2},a^2 x^2\right )}{1+m} \] Output:
2^n*x^(1+m)*hypergeom([-n, 1/2+1/2*m],[3/2+1/2*m],a^2*x^2)/(1+m)
Time = 0.07 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.00 \[ \int x^m (1-a x)^n (2+2 a x)^n \, dx=\frac {2^n x^{1+m} \operatorname {Hypergeometric2F1}\left (\frac {1+m}{2},-n,\frac {3+m}{2},a^2 x^2\right )}{1+m} \] Input:
Integrate[x^m*(1 - a*x)^n*(2 + 2*a*x)^n,x]
Output:
(2^n*x^(1 + m)*Hypergeometric2F1[(1 + m)/2, -n, (3 + m)/2, a^2*x^2])/(1 + m)
Time = 0.15 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {135, 278}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x^m (1-a x)^n (2 a x+2)^n \, dx\) |
\(\Big \downarrow \) 135 |
\(\displaystyle \int x^m \left (2-2 a^2 x^2\right )^ndx\) |
\(\Big \downarrow \) 278 |
\(\displaystyle \frac {2^n x^{m+1} \operatorname {Hypergeometric2F1}\left (\frac {m+1}{2},-n,\frac {m+3}{2},a^2 x^2\right )}{m+1}\) |
Input:
Int[x^m*(1 - a*x)^n*(2 + 2*a*x)^n,x]
Output:
(2^n*x^(1 + m)*Hypergeometric2F1[(1 + m)/2, -n, (3 + m)/2, a^2*x^2])/(1 + m)
Int[((f_.)*(x_))^(p_)*((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_] :> Int[(a*c + b*d*x^2)^m*(f*x)^p, x] /; FreeQ[{a, b, c, d, f, m, n, p}, x] && EqQ[b*c + a*d, 0] && EqQ[n, m] && GtQ[a, 0] && GtQ[c, 0]
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[a^p*(( c*x)^(m + 1)/(c*(m + 1)))*Hypergeometric2F1[-p, (m + 1)/2, (m + 1)/2 + 1, ( -b)*(x^2/a)], x] /; FreeQ[{a, b, c, m, p}, x] && !IGtQ[p, 0] && (ILtQ[p, 0 ] || GtQ[a, 0])
\[\int x^{m} \left (-a x +1\right )^{n} \left (2 a x +2\right )^{n}d x\]
Input:
int(x^m*(-a*x+1)^n*(2*a*x+2)^n,x)
Output:
int(x^m*(-a*x+1)^n*(2*a*x+2)^n,x)
\[ \int x^m (1-a x)^n (2+2 a x)^n \, dx=\int { {\left (2 \, a x + 2\right )}^{n} {\left (-a x + 1\right )}^{n} x^{m} \,d x } \] Input:
integrate(x^m*(-a*x+1)^n*(2*a*x+2)^n,x, algorithm="fricas")
Output:
integral((2*a*x + 2)^n*(-a*x + 1)^n*x^m, x)
Result contains complex when optimal does not.
Time = 14.57 (sec) , antiderivative size = 212, normalized size of antiderivative = 5.44 \[ \int x^m (1-a x)^n (2+2 a x)^n \, dx=- \frac {2^{n} a^{- m - 1} {G_{6, 6}^{5, 3}\left (\begin {matrix} - \frac {m}{2} - \frac {n}{2}, - \frac {m}{2} - \frac {n}{2} + \frac {1}{2}, 1 & \frac {1}{2} - \frac {m}{2}, - \frac {m}{2} - n, - \frac {m}{2} - n + \frac {1}{2} \\- \frac {m}{2} - n - \frac {1}{2}, - \frac {m}{2} - n, - \frac {m}{2} - \frac {n}{2}, - \frac {m}{2} - n + \frac {1}{2}, - \frac {m}{2} - \frac {n}{2} + \frac {1}{2} & 0 \end {matrix} \middle | {\frac {1}{a^{2} x^{2}}} \right )} e^{i \pi n}}{4 \pi \Gamma \left (- n\right )} + \frac {2^{n} a^{- m - 1} {G_{6, 6}^{2, 6}\left (\begin {matrix} - \frac {m}{2} - \frac {1}{2}, - \frac {m}{2}, \frac {1}{2} - \frac {m}{2}, - \frac {m}{2} - \frac {n}{2} - \frac {1}{2}, - \frac {m}{2} - \frac {n}{2}, 1 & \\- \frac {m}{2} - \frac {n}{2} - \frac {1}{2}, - \frac {m}{2} - \frac {n}{2} & - \frac {m}{2} - \frac {1}{2}, - \frac {m}{2}, - \frac {m}{2} - n - \frac {1}{2}, 0 \end {matrix} \middle | {\frac {e^{- 2 i \pi }}{a^{2} x^{2}}} \right )} e^{- i \pi m}}{4 \pi \Gamma \left (- n\right )} \] Input:
integrate(x**m*(-a*x+1)**n*(2*a*x+2)**n,x)
Output:
-2**n*a**(-m - 1)*meijerg(((-m/2 - n/2, -m/2 - n/2 + 1/2, 1), (1/2 - m/2, -m/2 - n, -m/2 - n + 1/2)), ((-m/2 - n - 1/2, -m/2 - n, -m/2 - n/2, -m/2 - n + 1/2, -m/2 - n/2 + 1/2), (0,)), 1/(a**2*x**2))*exp(I*pi*n)/(4*pi*gamma (-n)) + 2**n*a**(-m - 1)*meijerg(((-m/2 - 1/2, -m/2, 1/2 - m/2, -m/2 - n/2 - 1/2, -m/2 - n/2, 1), ()), ((-m/2 - n/2 - 1/2, -m/2 - n/2), (-m/2 - 1/2, -m/2, -m/2 - n - 1/2, 0)), exp_polar(-2*I*pi)/(a**2*x**2))*exp(-I*pi*m)/( 4*pi*gamma(-n))
\[ \int x^m (1-a x)^n (2+2 a x)^n \, dx=\int { {\left (2 \, a x + 2\right )}^{n} {\left (-a x + 1\right )}^{n} x^{m} \,d x } \] Input:
integrate(x^m*(-a*x+1)^n*(2*a*x+2)^n,x, algorithm="maxima")
Output:
integrate((2*a*x + 2)^n*(-a*x + 1)^n*x^m, x)
\[ \int x^m (1-a x)^n (2+2 a x)^n \, dx=\int { {\left (2 \, a x + 2\right )}^{n} {\left (-a x + 1\right )}^{n} x^{m} \,d x } \] Input:
integrate(x^m*(-a*x+1)^n*(2*a*x+2)^n,x, algorithm="giac")
Output:
integrate((2*a*x + 2)^n*(-a*x + 1)^n*x^m, x)
Timed out. \[ \int x^m (1-a x)^n (2+2 a x)^n \, dx=\int x^m\,{\left (1-a\,x\right )}^n\,{\left (2\,a\,x+2\right )}^n \,d x \] Input:
int(x^m*(1 - a*x)^n*(2*a*x + 2)^n,x)
Output:
int(x^m*(1 - a*x)^n*(2*a*x + 2)^n, x)
\[ \int x^m (1-a x)^n (2+2 a x)^n \, dx=\frac {x^{m} \left (2 a x +2\right )^{n} \left (-a x +1\right )^{n} x -2 \left (\int \frac {x^{m} \left (2 a x +2\right )^{n} \left (-a x +1\right )^{n}}{a^{2} m \,x^{2}+2 a^{2} n \,x^{2}+a^{2} x^{2}-m -2 n -1}d x \right ) m n -4 \left (\int \frac {x^{m} \left (2 a x +2\right )^{n} \left (-a x +1\right )^{n}}{a^{2} m \,x^{2}+2 a^{2} n \,x^{2}+a^{2} x^{2}-m -2 n -1}d x \right ) n^{2}-2 \left (\int \frac {x^{m} \left (2 a x +2\right )^{n} \left (-a x +1\right )^{n}}{a^{2} m \,x^{2}+2 a^{2} n \,x^{2}+a^{2} x^{2}-m -2 n -1}d x \right ) n}{m +2 n +1} \] Input:
int(x^m*(-a*x+1)^n*(2*a*x+2)^n,x)
Output:
(x**m*(2*a*x + 2)**n*( - a*x + 1)**n*x - 2*int((x**m*(2*a*x + 2)**n*( - a* x + 1)**n)/(a**2*m*x**2 + 2*a**2*n*x**2 + a**2*x**2 - m - 2*n - 1),x)*m*n - 4*int((x**m*(2*a*x + 2)**n*( - a*x + 1)**n)/(a**2*m*x**2 + 2*a**2*n*x**2 + a**2*x**2 - m - 2*n - 1),x)*n**2 - 2*int((x**m*(2*a*x + 2)**n*( - a*x + 1)**n)/(a**2*m*x**2 + 2*a**2*n*x**2 + a**2*x**2 - m - 2*n - 1),x)*n)/(m + 2*n + 1)