Integrand size = 26, antiderivative size = 107 \[ \int \frac {1}{(e x)^{5/2} (a+b x) (a c-b c x)} \, dx=-\frac {2}{3 a^2 c e (e x)^{3/2}}+\frac {b^{3/2} \arctan \left (\frac {\sqrt {b} \sqrt {e x}}{\sqrt {a} \sqrt {e}}\right )}{a^{7/2} c e^{5/2}}+\frac {b^{3/2} \text {arctanh}\left (\frac {\sqrt {b} \sqrt {e x}}{\sqrt {a} \sqrt {e}}\right )}{a^{7/2} c e^{5/2}} \] Output:
-2/3/a^2/c/e/(e*x)^(3/2)+b^(3/2)*arctan(b^(1/2)*(e*x)^(1/2)/a^(1/2)/e^(1/2 ))/a^(7/2)/c/e^(5/2)+b^(3/2)*arctanh(b^(1/2)*(e*x)^(1/2)/a^(1/2)/e^(1/2))/ a^(7/2)/c/e^(5/2)
Time = 0.05 (sec) , antiderivative size = 86, normalized size of antiderivative = 0.80 \[ \int \frac {1}{(e x)^{5/2} (a+b x) (a c-b c x)} \, dx=\frac {x \left (-2 a^{3/2}+3 b^{3/2} x^{3/2} \arctan \left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )+3 b^{3/2} x^{3/2} \text {arctanh}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )\right )}{3 a^{7/2} c (e x)^{5/2}} \] Input:
Integrate[1/((e*x)^(5/2)*(a + b*x)*(a*c - b*c*x)),x]
Output:
(x*(-2*a^(3/2) + 3*b^(3/2)*x^(3/2)*ArcTan[(Sqrt[b]*Sqrt[x])/Sqrt[a]] + 3*b ^(3/2)*x^(3/2)*ArcTanh[(Sqrt[b]*Sqrt[x])/Sqrt[a]]))/(3*a^(7/2)*c*(e*x)^(5/ 2))
Time = 0.21 (sec) , antiderivative size = 122, normalized size of antiderivative = 1.14, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.269, Rules used = {82, 264, 27, 266, 756, 218, 221}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{(e x)^{5/2} (a+b x) (a c-b c x)} \, dx\) |
\(\Big \downarrow \) 82 |
\(\displaystyle \int \frac {1}{(e x)^{5/2} \left (a^2 c-b^2 c x^2\right )}dx\) |
\(\Big \downarrow \) 264 |
\(\displaystyle \frac {b^2 \int \frac {1}{c \sqrt {e x} \left (a^2-b^2 x^2\right )}dx}{a^2 e^2}-\frac {2}{3 a^2 c e (e x)^{3/2}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {b^2 \int \frac {1}{\sqrt {e x} \left (a^2-b^2 x^2\right )}dx}{a^2 c e^2}-\frac {2}{3 a^2 c e (e x)^{3/2}}\) |
\(\Big \downarrow \) 266 |
\(\displaystyle \frac {2 b^2 \int \frac {1}{a^2-b^2 x^2}d\sqrt {e x}}{a^2 c e^3}-\frac {2}{3 a^2 c e (e x)^{3/2}}\) |
\(\Big \downarrow \) 756 |
\(\displaystyle \frac {2 b^2 \left (\frac {e \int \frac {1}{a e-b e x}d\sqrt {e x}}{2 a}+\frac {e \int \frac {1}{a e+b x e}d\sqrt {e x}}{2 a}\right )}{a^2 c e^3}-\frac {2}{3 a^2 c e (e x)^{3/2}}\) |
\(\Big \downarrow \) 218 |
\(\displaystyle \frac {2 b^2 \left (\frac {e \int \frac {1}{a e-b e x}d\sqrt {e x}}{2 a}+\frac {\sqrt {e} \arctan \left (\frac {\sqrt {b} \sqrt {e x}}{\sqrt {a} \sqrt {e}}\right )}{2 a^{3/2} \sqrt {b}}\right )}{a^2 c e^3}-\frac {2}{3 a^2 c e (e x)^{3/2}}\) |
\(\Big \downarrow \) 221 |
\(\displaystyle \frac {2 b^2 \left (\frac {\sqrt {e} \arctan \left (\frac {\sqrt {b} \sqrt {e x}}{\sqrt {a} \sqrt {e}}\right )}{2 a^{3/2} \sqrt {b}}+\frac {\sqrt {e} \text {arctanh}\left (\frac {\sqrt {b} \sqrt {e x}}{\sqrt {a} \sqrt {e}}\right )}{2 a^{3/2} \sqrt {b}}\right )}{a^2 c e^3}-\frac {2}{3 a^2 c e (e x)^{3/2}}\) |
Input:
Int[1/((e*x)^(5/2)*(a + b*x)*(a*c - b*c*x)),x]
Output:
-2/(3*a^2*c*e*(e*x)^(3/2)) + (2*b^2*((Sqrt[e]*ArcTan[(Sqrt[b]*Sqrt[e*x])/( Sqrt[a]*Sqrt[e])])/(2*a^(3/2)*Sqrt[b]) + (Sqrt[e]*ArcTanh[(Sqrt[b]*Sqrt[e* x])/(Sqrt[a]*Sqrt[e])])/(2*a^(3/2)*Sqrt[b])))/(a^2*c*e^3)
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*(x_))^(m_.)*((c_) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_) )^(p_.), x_] :> Int[(a*c + b*d*x^2)^m*(e + f*x)^p, x] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x] && EqQ[b*c + a*d, 0] && EqQ[n, m] && IntegerQ[m]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/R t[a/b, 2]], x] /; FreeQ[{a, b}, x] && PosQ[a/b]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x /Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(c*x)^( m + 1)*((a + b*x^2)^(p + 1)/(a*c*(m + 1))), x] - Simp[b*((m + 2*p + 3)/(a*c ^2*(m + 1))) Int[(c*x)^(m + 2)*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, p }, x] && LtQ[m, -1] && IntBinomialQ[a, b, c, 2, m, p, x]
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{k = De nominator[m]}, Simp[k/c Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(2*k)/c^2)) ^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && FractionQ[m] && I ntBinomialQ[a, b, c, 2, m, p, x]
Int[((a_) + (b_.)*(x_)^4)^(-1), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 2 ]], s = Denominator[Rt[-a/b, 2]]}, Simp[r/(2*a) Int[1/(r - s*x^2), x], x] + Simp[r/(2*a) Int[1/(r + s*x^2), x], x]] /; FreeQ[{a, b}, x] && !GtQ[a /b, 0]
Time = 0.30 (sec) , antiderivative size = 81, normalized size of antiderivative = 0.76
method | result | size |
pseudoelliptic | \(-\frac {2 \left (-\frac {3 b^{2} \operatorname {arctanh}\left (\frac {b \sqrt {e x}}{\sqrt {a e b}}\right ) \left (e x \right )^{\frac {3}{2}}}{2}-\frac {3 b^{2} \arctan \left (\frac {b \sqrt {e x}}{\sqrt {a e b}}\right ) \left (e x \right )^{\frac {3}{2}}}{2}+e a \sqrt {a e b}\right )}{3 \sqrt {a e b}\, \left (e x \right )^{\frac {3}{2}} e^{2} c \,a^{3}}\) | \(81\) |
derivativedivides | \(-\frac {2 e \left (-\frac {b^{2} \operatorname {arctanh}\left (\frac {b \sqrt {e x}}{\sqrt {a e b}}\right )}{2 a^{3} e^{3} \sqrt {a e b}}-\frac {b^{2} \arctan \left (\frac {b \sqrt {e x}}{\sqrt {a e b}}\right )}{2 a^{3} e^{3} \sqrt {a e b}}+\frac {1}{3 a^{2} e^{2} \left (e x \right )^{\frac {3}{2}}}\right )}{c}\) | \(83\) |
default | \(\frac {2 e \left (\frac {b^{2} \operatorname {arctanh}\left (\frac {b \sqrt {e x}}{\sqrt {a e b}}\right )}{2 a^{3} e^{3} \sqrt {a e b}}+\frac {b^{2} \arctan \left (\frac {b \sqrt {e x}}{\sqrt {a e b}}\right )}{2 a^{3} e^{3} \sqrt {a e b}}-\frac {1}{3 a^{2} e^{2} \left (e x \right )^{\frac {3}{2}}}\right )}{c}\) | \(83\) |
risch | \(-\frac {2}{3 a^{2} x \sqrt {e x}\, e^{2} c}+\frac {\frac {b^{2} \arctan \left (\frac {b \sqrt {e x}}{\sqrt {a e b}}\right )}{a^{3} \sqrt {a e b}}+\frac {b^{2} \operatorname {arctanh}\left (\frac {b \sqrt {e x}}{\sqrt {a e b}}\right )}{a^{3} \sqrt {a e b}}}{e^{2} c}\) | \(83\) |
Input:
int(1/(e*x)^(5/2)/(b*x+a)/(-b*c*x+a*c),x,method=_RETURNVERBOSE)
Output:
-2/3/(a*e*b)^(1/2)*(-3/2*b^2*arctanh(b*(e*x)^(1/2)/(a*e*b)^(1/2))*(e*x)^(3 /2)-3/2*b^2*arctan(b*(e*x)^(1/2)/(a*e*b)^(1/2))*(e*x)^(3/2)+e*a*(a*e*b)^(1 /2))/(e*x)^(3/2)/e^2/c/a^3
Time = 0.14 (sec) , antiderivative size = 221, normalized size of antiderivative = 2.07 \[ \int \frac {1}{(e x)^{5/2} (a+b x) (a c-b c x)} \, dx=\left [\frac {6 \, b e x^{2} \sqrt {\frac {b}{a e}} \arctan \left (\sqrt {e x} \sqrt {\frac {b}{a e}}\right ) + 3 \, b e x^{2} \sqrt {\frac {b}{a e}} \log \left (\frac {b x + 2 \, \sqrt {e x} a \sqrt {\frac {b}{a e}} + a}{b x - a}\right ) - 4 \, \sqrt {e x} a}{6 \, a^{3} c e^{3} x^{2}}, -\frac {6 \, b e x^{2} \sqrt {-\frac {b}{a e}} \arctan \left (\sqrt {e x} \sqrt {-\frac {b}{a e}}\right ) - 3 \, b e x^{2} \sqrt {-\frac {b}{a e}} \log \left (\frac {b x + 2 \, \sqrt {e x} a \sqrt {-\frac {b}{a e}} - a}{b x + a}\right ) + 4 \, \sqrt {e x} a}{6 \, a^{3} c e^{3} x^{2}}\right ] \] Input:
integrate(1/(e*x)^(5/2)/(b*x+a)/(-b*c*x+a*c),x, algorithm="fricas")
Output:
[1/6*(6*b*e*x^2*sqrt(b/(a*e))*arctan(sqrt(e*x)*sqrt(b/(a*e))) + 3*b*e*x^2* sqrt(b/(a*e))*log((b*x + 2*sqrt(e*x)*a*sqrt(b/(a*e)) + a)/(b*x - a)) - 4*s qrt(e*x)*a)/(a^3*c*e^3*x^2), -1/6*(6*b*e*x^2*sqrt(-b/(a*e))*arctan(sqrt(e* x)*sqrt(-b/(a*e))) - 3*b*e*x^2*sqrt(-b/(a*e))*log((b*x + 2*sqrt(e*x)*a*sqr t(-b/(a*e)) - a)/(b*x + a)) + 4*sqrt(e*x)*a)/(a^3*c*e^3*x^2)]
Result contains complex when optimal does not.
Time = 2.59 (sec) , antiderivative size = 371, normalized size of antiderivative = 3.47 \[ \int \frac {1}{(e x)^{5/2} (a+b x) (a c-b c x)} \, dx=\begin {cases} \frac {1}{5 a b c e^{\frac {5}{2}} x^{\frac {5}{2}}} - \frac {2}{3 a^{2} c e^{\frac {5}{2}} x^{\frac {3}{2}}} + \frac {b^{\frac {3}{2}} \operatorname {acoth}{\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}} \right )}}{a^{\frac {7}{2}} c e^{\frac {5}{2}}} + \frac {b^{\frac {3}{2}} \operatorname {atan}{\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}} \right )}}{a^{\frac {7}{2}} c e^{\frac {5}{2}}} & \text {for}\: \left |{\frac {b x}{a}}\right | > 1 \\- \frac {i \left (3 + 3 i\right )}{30 a b c e^{\frac {5}{2}} x^{\frac {5}{2}}} + \frac {3 + 3 i}{30 a b c e^{\frac {5}{2}} x^{\frac {5}{2}}} + \frac {-10 - 10 i}{30 a^{2} c e^{\frac {5}{2}} x^{\frac {3}{2}}} - \frac {i \left (-10 - 10 i\right )}{30 a^{2} c e^{\frac {5}{2}} x^{\frac {3}{2}}} - \frac {i b^{\frac {3}{2}} \cdot \left (15 + 15 i\right ) \operatorname {atan}{\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}} \right )}}{30 a^{\frac {7}{2}} c e^{\frac {5}{2}}} + \frac {b^{\frac {3}{2}} \cdot \left (15 + 15 i\right ) \operatorname {atan}{\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}} \right )}}{30 a^{\frac {7}{2}} c e^{\frac {5}{2}}} - \frac {i b^{\frac {3}{2}} \cdot \left (15 + 15 i\right ) \operatorname {atanh}{\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}} \right )}}{30 a^{\frac {7}{2}} c e^{\frac {5}{2}}} + \frac {b^{\frac {3}{2}} \cdot \left (15 + 15 i\right ) \operatorname {atanh}{\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}} \right )}}{30 a^{\frac {7}{2}} c e^{\frac {5}{2}}} & \text {otherwise} \end {cases} \] Input:
integrate(1/(e*x)**(5/2)/(b*x+a)/(-b*c*x+a*c),x)
Output:
Piecewise((1/(5*a*b*c*e**(5/2)*x**(5/2)) - 2/(3*a**2*c*e**(5/2)*x**(3/2)) + b**(3/2)*acoth(sqrt(b)*sqrt(x)/sqrt(a))/(a**(7/2)*c*e**(5/2)) + b**(3/2) *atan(sqrt(b)*sqrt(x)/sqrt(a))/(a**(7/2)*c*e**(5/2)), Abs(b*x/a) > 1), (-I *(3 + 3*I)/(30*a*b*c*e**(5/2)*x**(5/2)) + (3 + 3*I)/(30*a*b*c*e**(5/2)*x** (5/2)) + (-10 - 10*I)/(30*a**2*c*e**(5/2)*x**(3/2)) - I*(-10 - 10*I)/(30*a **2*c*e**(5/2)*x**(3/2)) - I*b**(3/2)*(15 + 15*I)*atan(sqrt(b)*sqrt(x)/sqr t(a))/(30*a**(7/2)*c*e**(5/2)) + b**(3/2)*(15 + 15*I)*atan(sqrt(b)*sqrt(x) /sqrt(a))/(30*a**(7/2)*c*e**(5/2)) - I*b**(3/2)*(15 + 15*I)*atanh(sqrt(b)* sqrt(x)/sqrt(a))/(30*a**(7/2)*c*e**(5/2)) + b**(3/2)*(15 + 15*I)*atanh(sqr t(b)*sqrt(x)/sqrt(a))/(30*a**(7/2)*c*e**(5/2)), True))
Exception generated. \[ \int \frac {1}{(e x)^{5/2} (a+b x) (a c-b c x)} \, dx=\text {Exception raised: ValueError} \] Input:
integrate(1/(e*x)^(5/2)/(b*x+a)/(-b*c*x+a*c),x, algorithm="maxima")
Output:
Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'assume' command before evaluation *may* help (example of legal syntax is 'assume(e>0)', see `assume?` for more de tails)Is e
Time = 0.13 (sec) , antiderivative size = 89, normalized size of antiderivative = 0.83 \[ \int \frac {1}{(e x)^{5/2} (a+b x) (a c-b c x)} \, dx=\frac {b^{2} \arctan \left (\frac {\sqrt {e x} b}{\sqrt {a b e}}\right )}{\sqrt {a b e} a^{3} c e^{2}} - \frac {b^{2} \arctan \left (\frac {\sqrt {e x} b}{\sqrt {-a b e}}\right )}{\sqrt {-a b e} a^{3} c e^{2}} - \frac {2}{3 \, \sqrt {e x} a^{2} c e^{2} x} \] Input:
integrate(1/(e*x)^(5/2)/(b*x+a)/(-b*c*x+a*c),x, algorithm="giac")
Output:
b^2*arctan(sqrt(e*x)*b/sqrt(a*b*e))/(sqrt(a*b*e)*a^3*c*e^2) - b^2*arctan(s qrt(e*x)*b/sqrt(-a*b*e))/(sqrt(-a*b*e)*a^3*c*e^2) - 2/3/(sqrt(e*x)*a^2*c*e ^2*x)
Time = 0.29 (sec) , antiderivative size = 75, normalized size of antiderivative = 0.70 \[ \int \frac {1}{(e x)^{5/2} (a+b x) (a c-b c x)} \, dx=\frac {b^{3/2}\,\mathrm {atan}\left (\frac {\sqrt {b}\,\sqrt {e\,x}}{\sqrt {a}\,\sqrt {e}}\right )}{a^{7/2}\,c\,e^{5/2}}-\frac {2}{3\,a^2\,c\,e\,{\left (e\,x\right )}^{3/2}}+\frac {b^{3/2}\,\mathrm {atanh}\left (\frac {\sqrt {b}\,\sqrt {e\,x}}{\sqrt {a}\,\sqrt {e}}\right )}{a^{7/2}\,c\,e^{5/2}} \] Input:
int(1/((a*c - b*c*x)*(e*x)^(5/2)*(a + b*x)),x)
Output:
(b^(3/2)*atan((b^(1/2)*(e*x)^(1/2))/(a^(1/2)*e^(1/2))))/(a^(7/2)*c*e^(5/2) ) - 2/(3*a^2*c*e*(e*x)^(3/2)) + (b^(3/2)*atanh((b^(1/2)*(e*x)^(1/2))/(a^(1 /2)*e^(1/2))))/(a^(7/2)*c*e^(5/2))
Time = 0.16 (sec) , antiderivative size = 89, normalized size of antiderivative = 0.83 \[ \int \frac {1}{(e x)^{5/2} (a+b x) (a c-b c x)} \, dx=\frac {\sqrt {e}\, \left (6 \sqrt {x}\, \sqrt {b}\, \sqrt {a}\, \mathit {atan} \left (\frac {\sqrt {x}\, b}{\sqrt {b}\, \sqrt {a}}\right ) b x -3 \sqrt {x}\, \sqrt {b}\, \sqrt {a}\, \mathrm {log}\left (-\sqrt {a}+\sqrt {x}\, \sqrt {b}\right ) b x +3 \sqrt {x}\, \sqrt {b}\, \sqrt {a}\, \mathrm {log}\left (\sqrt {a}+\sqrt {x}\, \sqrt {b}\right ) b x -4 a^{2}\right )}{6 \sqrt {x}\, a^{4} c \,e^{3} x} \] Input:
int(1/(e*x)^(5/2)/(b*x+a)/(-b*c*x+a*c),x)
Output:
(sqrt(e)*(6*sqrt(x)*sqrt(b)*sqrt(a)*atan((sqrt(x)*b)/(sqrt(b)*sqrt(a)))*b* x - 3*sqrt(x)*sqrt(b)*sqrt(a)*log( - sqrt(a) + sqrt(x)*sqrt(b))*b*x + 3*sq rt(x)*sqrt(b)*sqrt(a)*log(sqrt(a) + sqrt(x)*sqrt(b))*b*x - 4*a**2))/(6*sqr t(x)*a**4*c*e**3*x)