Integrand size = 26, antiderivative size = 65 \[ \int \frac {(e x)^{4/3}}{\sqrt {a+b x} (4 a+b x)} \, dx=\frac {3 (e x)^{7/3} \sqrt {1+\frac {b x}{a}} \operatorname {AppellF1}\left (\frac {7}{3},\frac {1}{2},1,\frac {10}{3},-\frac {b x}{a},-\frac {b x}{4 a}\right )}{28 a e \sqrt {a+b x}} \] Output:
3/28*(e*x)^(7/3)*(1+b*x/a)^(1/2)*AppellF1(7/3,1/2,1,10/3,-b*x/a,-1/4*b*x/a )/a/e/(b*x+a)^(1/2)
Time = 11.07 (sec) , antiderivative size = 117, normalized size of antiderivative = 1.80 \[ \int \frac {(e x)^{4/3}}{\sqrt {a+b x} (4 a+b x)} \, dx=-\frac {3 e \sqrt [3]{e x} \left (-16 (a+b x)+16 a \sqrt {1+\frac {b x}{a}} \operatorname {AppellF1}\left (\frac {1}{3},\frac {1}{2},1,\frac {4}{3},-\frac {b x}{a},-\frac {b x}{4 a}\right )+11 b x \sqrt {1+\frac {b x}{a}} \operatorname {AppellF1}\left (\frac {4}{3},\frac {1}{2},1,\frac {7}{3},-\frac {b x}{a},-\frac {b x}{4 a}\right )\right )}{40 b^2 \sqrt {a+b x}} \] Input:
Integrate[(e*x)^(4/3)/(Sqrt[a + b*x]*(4*a + b*x)),x]
Output:
(-3*e*(e*x)^(1/3)*(-16*(a + b*x) + 16*a*Sqrt[1 + (b*x)/a]*AppellF1[1/3, 1/ 2, 1, 4/3, -((b*x)/a), -1/4*(b*x)/a] + 11*b*x*Sqrt[1 + (b*x)/a]*AppellF1[4 /3, 1/2, 1, 7/3, -((b*x)/a), -1/4*(b*x)/a]))/(40*b^2*Sqrt[a + b*x])
Time = 0.25 (sec) , antiderivative size = 65, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {148, 27, 1013, 1012}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {(e x)^{4/3}}{\sqrt {a+b x} (4 a+b x)} \, dx\) |
\(\Big \downarrow \) 148 |
\(\displaystyle \frac {3 \int \frac {e^3 x^2}{\sqrt {a+b x} (4 a e+b x e)}d\sqrt [3]{e x}}{e}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle 3 \int \frac {e^2 x^2}{\sqrt {a+b x} (4 a e+b x e)}d\sqrt [3]{e x}\) |
\(\Big \downarrow \) 1013 |
\(\displaystyle \frac {3 \sqrt {\frac {b x}{a}+1} \int \frac {e^2 x^2}{\sqrt {\frac {b x}{a}+1} (4 a e+b x e)}d\sqrt [3]{e x}}{\sqrt {a+b x}}\) |
\(\Big \downarrow \) 1012 |
\(\displaystyle \frac {3 (e x)^{7/3} \sqrt {\frac {b x}{a}+1} \operatorname {AppellF1}\left (\frac {7}{3},1,\frac {1}{2},\frac {10}{3},-\frac {b x}{4 a},-\frac {b x}{a}\right )}{28 a e \sqrt {a+b x}}\) |
Input:
Int[(e*x)^(4/3)/(Sqrt[a + b*x]*(4*a + b*x)),x]
Output:
(3*(e*x)^(7/3)*Sqrt[1 + (b*x)/a]*AppellF1[7/3, 1, 1/2, 10/3, -1/4*(b*x)/a, -((b*x)/a)])/(28*a*e*Sqrt[a + b*x])
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_.)*((e_) + (f_.)*(x_))^(p_.), x_] :> With[{k = Denominator[m]}, Simp[k/b Subst[Int[x^(k*(m + 1) - 1)*(c + d*(x^k/b))^n*(e + f*(x^k/b))^p, x], x, (b*x)^(1/k)], x]] /; FreeQ[{b, c, d, e, f, n, p}, x] && FractionQ[m] && IntegerQ[p]
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_ ))^(q_), x_Symbol] :> Simp[a^p*c^q*((e*x)^(m + 1)/(e*(m + 1)))*AppellF1[(m + 1)/n, -p, -q, 1 + (m + 1)/n, (-b)*(x^n/a), (-d)*(x^n/c)], x] /; FreeQ[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n - 1] && (IntegerQ[p] || GtQ[a, 0]) && (IntegerQ[q] || GtQ[c, 0])
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_ ))^(q_), x_Symbol] :> Simp[a^IntPart[p]*((a + b*x^n)^FracPart[p]/(1 + b*(x^ n/a))^FracPart[p]) Int[(e*x)^m*(1 + b*(x^n/a))^p*(c + d*x^n)^q, x], x] /; FreeQ[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] & & NeQ[m, n - 1] && !(IntegerQ[p] || GtQ[a, 0])
\[\int \frac {\left (e x \right )^{\frac {4}{3}}}{\sqrt {b x +a}\, \left (b x +4 a \right )}d x\]
Input:
int((e*x)^(4/3)/(b*x+a)^(1/2)/(b*x+4*a),x)
Output:
int((e*x)^(4/3)/(b*x+a)^(1/2)/(b*x+4*a),x)
Timed out. \[ \int \frac {(e x)^{4/3}}{\sqrt {a+b x} (4 a+b x)} \, dx=\text {Timed out} \] Input:
integrate((e*x)^(4/3)/(b*x+a)^(1/2)/(b*x+4*a),x, algorithm="fricas")
Output:
Timed out
\[ \int \frac {(e x)^{4/3}}{\sqrt {a+b x} (4 a+b x)} \, dx=\int \frac {\left (e x\right )^{\frac {4}{3}}}{\sqrt {a + b x} \left (4 a + b x\right )}\, dx \] Input:
integrate((e*x)**(4/3)/(b*x+a)**(1/2)/(b*x+4*a),x)
Output:
Integral((e*x)**(4/3)/(sqrt(a + b*x)*(4*a + b*x)), x)
\[ \int \frac {(e x)^{4/3}}{\sqrt {a+b x} (4 a+b x)} \, dx=\int { \frac {\left (e x\right )^{\frac {4}{3}}}{{\left (b x + 4 \, a\right )} \sqrt {b x + a}} \,d x } \] Input:
integrate((e*x)^(4/3)/(b*x+a)^(1/2)/(b*x+4*a),x, algorithm="maxima")
Output:
integrate((e*x)^(4/3)/((b*x + 4*a)*sqrt(b*x + a)), x)
\[ \int \frac {(e x)^{4/3}}{\sqrt {a+b x} (4 a+b x)} \, dx=\int { \frac {\left (e x\right )^{\frac {4}{3}}}{{\left (b x + 4 \, a\right )} \sqrt {b x + a}} \,d x } \] Input:
integrate((e*x)^(4/3)/(b*x+a)^(1/2)/(b*x+4*a),x, algorithm="giac")
Output:
integrate((e*x)^(4/3)/((b*x + 4*a)*sqrt(b*x + a)), x)
Timed out. \[ \int \frac {(e x)^{4/3}}{\sqrt {a+b x} (4 a+b x)} \, dx=\int \frac {{\left (e\,x\right )}^{4/3}}{\left (4\,a+b\,x\right )\,\sqrt {a+b\,x}} \,d x \] Input:
int((e*x)^(4/3)/((4*a + b*x)*(a + b*x)^(1/2)),x)
Output:
int((e*x)^(4/3)/((4*a + b*x)*(a + b*x)^(1/2)), x)
\[ \int \frac {(e x)^{4/3}}{\sqrt {a+b x} (4 a+b x)} \, dx=\frac {2 e^{\frac {4}{3}} \left (66 \sqrt {b x +a}\, a +3 \sqrt {b x +a}\, b x +176 x^{\frac {2}{3}} \left (\int \frac {\sqrt {b x +a}}{4 x^{\frac {5}{3}} a^{2}+5 x^{\frac {8}{3}} a b +x^{\frac {11}{3}} b^{2}}d x \right ) a^{3}+84 x^{\frac {2}{3}} \left (\int \frac {\sqrt {b x +a}}{4 x^{\frac {2}{3}} a^{2}+5 x^{\frac {5}{3}} a b +x^{\frac {8}{3}} b^{2}}d x \right ) a^{2} b \right )}{5 x^{\frac {2}{3}} b^{3}} \] Input:
int((e*x)^(4/3)/(b*x+a)^(1/2)/(b*x+4*a),x)
Output:
(2*e**(1/3)*e*(66*sqrt(a + b*x)*a + 3*sqrt(a + b*x)*b*x + 176*x**(2/3)*int (sqrt(a + b*x)/(4*x**(2/3)*a**2*x + 5*x**(2/3)*a*b*x**2 + x**(2/3)*b**2*x* *3),x)*a**3 + 84*x**(2/3)*int(sqrt(a + b*x)/(4*x**(2/3)*a**2 + 5*x**(2/3)* a*b*x + x**(2/3)*b**2*x**2),x)*a**2*b))/(5*x**(2/3)*b**3)