Integrand size = 22, antiderivative size = 79 \[ \int (b x)^{3/2} (c+d x)^n (e+f x)^p \, dx=\frac {2 (b x)^{5/2} (c+d x)^n \left (1+\frac {d x}{c}\right )^{-n} (e+f x)^p \left (1+\frac {f x}{e}\right )^{-p} \operatorname {AppellF1}\left (\frac {5}{2},-n,-p,\frac {7}{2},-\frac {d x}{c},-\frac {f x}{e}\right )}{5 b} \] Output:
2/5*(b*x)^(5/2)*(d*x+c)^n*(f*x+e)^p*AppellF1(5/2,-n,-p,7/2,-d*x/c,-f*x/e)/ b/((1+d*x/c)^n)/((1+f*x/e)^p)
Time = 0.35 (sec) , antiderivative size = 79, normalized size of antiderivative = 1.00 \[ \int (b x)^{3/2} (c+d x)^n (e+f x)^p \, dx=\frac {2}{5} x (b x)^{3/2} (c+d x)^n \left (\frac {c+d x}{c}\right )^{-n} (e+f x)^p \left (\frac {e+f x}{e}\right )^{-p} \operatorname {AppellF1}\left (\frac {5}{2},-n,-p,\frac {7}{2},-\frac {d x}{c},-\frac {f x}{e}\right ) \] Input:
Integrate[(b*x)^(3/2)*(c + d*x)^n*(e + f*x)^p,x]
Output:
(2*x*(b*x)^(3/2)*(c + d*x)^n*(e + f*x)^p*AppellF1[5/2, -n, -p, 7/2, -((d*x )/c), -((f*x)/e)])/(5*((c + d*x)/c)^n*((e + f*x)/e)^p)
Time = 0.24 (sec) , antiderivative size = 79, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {152, 152, 150}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int (b x)^{3/2} (c+d x)^n (e+f x)^p \, dx\) |
\(\Big \downarrow \) 152 |
\(\displaystyle (c+d x)^n \left (\frac {d x}{c}+1\right )^{-n} \int (b x)^{3/2} \left (\frac {d x}{c}+1\right )^n (e+f x)^pdx\) |
\(\Big \downarrow \) 152 |
\(\displaystyle (c+d x)^n \left (\frac {d x}{c}+1\right )^{-n} (e+f x)^p \left (\frac {f x}{e}+1\right )^{-p} \int (b x)^{3/2} \left (\frac {d x}{c}+1\right )^n \left (\frac {f x}{e}+1\right )^pdx\) |
\(\Big \downarrow \) 150 |
\(\displaystyle \frac {2 (b x)^{5/2} (c+d x)^n \left (\frac {d x}{c}+1\right )^{-n} (e+f x)^p \left (\frac {f x}{e}+1\right )^{-p} \operatorname {AppellF1}\left (\frac {5}{2},-n,-p,\frac {7}{2},-\frac {d x}{c},-\frac {f x}{e}\right )}{5 b}\) |
Input:
Int[(b*x)^(3/2)*(c + d*x)^n*(e + f*x)^p,x]
Output:
(2*(b*x)^(5/2)*(c + d*x)^n*(e + f*x)^p*AppellF1[5/2, -n, -p, 7/2, -((d*x)/ c), -((f*x)/e)])/(5*b*(1 + (d*x)/c)^n*(1 + (f*x)/e)^p)
Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_)*((e_) + (f_.)*(x_))^(p_), x_ ] :> Simp[c^n*e^p*((b*x)^(m + 1)/(b*(m + 1)))*AppellF1[m + 1, -n, -p, m + 2 , (-d)*(x/c), (-f)*(x/e)], x] /; FreeQ[{b, c, d, e, f, m, n, p}, x] && !In tegerQ[m] && !IntegerQ[n] && GtQ[c, 0] && (IntegerQ[p] || GtQ[e, 0])
Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_)*((e_) + (f_.)*(x_))^(p_), x_ ] :> Simp[c^IntPart[n]*((c + d*x)^FracPart[n]/(1 + d*(x/c))^FracPart[n]) Int[(b*x)^m*(1 + d*(x/c))^n*(e + f*x)^p, x], x] /; FreeQ[{b, c, d, e, f, m, n, p}, x] && !IntegerQ[m] && !IntegerQ[n] && !GtQ[c, 0]
\[\int \left (b x \right )^{\frac {3}{2}} \left (x d +c \right )^{n} \left (f x +e \right )^{p}d x\]
Input:
int((b*x)^(3/2)*(d*x+c)^n*(f*x+e)^p,x)
Output:
int((b*x)^(3/2)*(d*x+c)^n*(f*x+e)^p,x)
\[ \int (b x)^{3/2} (c+d x)^n (e+f x)^p \, dx=\int { \left (b x\right )^{\frac {3}{2}} {\left (d x + c\right )}^{n} {\left (f x + e\right )}^{p} \,d x } \] Input:
integrate((b*x)^(3/2)*(d*x+c)^n*(f*x+e)^p,x, algorithm="fricas")
Output:
integral(sqrt(b*x)*(d*x + c)^n*(f*x + e)^p*b*x, x)
Timed out. \[ \int (b x)^{3/2} (c+d x)^n (e+f x)^p \, dx=\text {Timed out} \] Input:
integrate((b*x)**(3/2)*(d*x+c)**n*(f*x+e)**p,x)
Output:
Timed out
\[ \int (b x)^{3/2} (c+d x)^n (e+f x)^p \, dx=\int { \left (b x\right )^{\frac {3}{2}} {\left (d x + c\right )}^{n} {\left (f x + e\right )}^{p} \,d x } \] Input:
integrate((b*x)^(3/2)*(d*x+c)^n*(f*x+e)^p,x, algorithm="maxima")
Output:
integrate((b*x)^(3/2)*(d*x + c)^n*(f*x + e)^p, x)
\[ \int (b x)^{3/2} (c+d x)^n (e+f x)^p \, dx=\int { \left (b x\right )^{\frac {3}{2}} {\left (d x + c\right )}^{n} {\left (f x + e\right )}^{p} \,d x } \] Input:
integrate((b*x)^(3/2)*(d*x+c)^n*(f*x+e)^p,x, algorithm="giac")
Output:
integrate((b*x)^(3/2)*(d*x + c)^n*(f*x + e)^p, x)
Timed out. \[ \int (b x)^{3/2} (c+d x)^n (e+f x)^p \, dx=\int {\left (e+f\,x\right )}^p\,{\left (b\,x\right )}^{3/2}\,{\left (c+d\,x\right )}^n \,d x \] Input:
int((e + f*x)^p*(b*x)^(3/2)*(c + d*x)^n,x)
Output:
int((e + f*x)^p*(b*x)^(3/2)*(c + d*x)^n, x)
\[ \int (b x)^{3/2} (c+d x)^n (e+f x)^p \, dx=\text {too large to display} \] Input:
int((b*x)^(3/2)*(d*x+c)^n*(f*x+e)^p,x)
Output:
(2*sqrt(b)*b*( - 6*sqrt(x)*(e + f*x)**p*(c + d*x)**n*c**2*e*f*n + 4*sqrt(x )*(e + f*x)**p*(c + d*x)**n*c**2*f**2*n*p*x + 2*sqrt(x)*(e + f*x)**p*(c + d*x)**n*c**2*f**2*n*x - 6*sqrt(x)*(e + f*x)**p*(c + d*x)**n*c*d*e**2*p + 4 *sqrt(x)*(e + f*x)**p*(c + d*x)**n*c*d*e*f*n**2*x + 2*sqrt(x)*(e + f*x)**p *(c + d*x)**n*c*d*e*f*n*x + 4*sqrt(x)*(e + f*x)**p*(c + d*x)**n*c*d*e*f*p* *2*x + 2*sqrt(x)*(e + f*x)**p*(c + d*x)**n*c*d*e*f*p*x + 4*sqrt(x)*(e + f* x)**p*(c + d*x)**n*c*d*f**2*n*p*x**2 + 2*sqrt(x)*(e + f*x)**p*(c + d*x)**n *c*d*f**2*n*x**2 + 4*sqrt(x)*(e + f*x)**p*(c + d*x)**n*c*d*f**2*p**2*x**2 + 8*sqrt(x)*(e + f*x)**p*(c + d*x)**n*c*d*f**2*p*x**2 + 3*sqrt(x)*(e + f*x )**p*(c + d*x)**n*c*d*f**2*x**2 + 4*sqrt(x)*(e + f*x)**p*(c + d*x)**n*d**2 *e**2*n*p*x + 2*sqrt(x)*(e + f*x)**p*(c + d*x)**n*d**2*e**2*p*x + 4*sqrt(x )*(e + f*x)**p*(c + d*x)**n*d**2*e*f*n**2*x**2 + 4*sqrt(x)*(e + f*x)**p*(c + d*x)**n*d**2*e*f*n*p*x**2 + 8*sqrt(x)*(e + f*x)**p*(c + d*x)**n*d**2*e* f*n*x**2 + 2*sqrt(x)*(e + f*x)**p*(c + d*x)**n*d**2*e*f*p*x**2 + 3*sqrt(x) *(e + f*x)**p*(c + d*x)**n*d**2*e*f*x**2 - 32*int((sqrt(x)*(e + f*x)**p*(c + d*x)**n*x)/(8*c**2*e*f*n**2*p + 4*c**2*e*f*n**2 + 16*c**2*e*f*n*p**2 + 40*c**2*e*f*n*p + 16*c**2*e*f*n + 8*c**2*e*f*p**3 + 36*c**2*e*f*p**2 + 46* c**2*e*f*p + 15*c**2*e*f + 8*c**2*f**2*n**2*p*x + 4*c**2*f**2*n**2*x + 16* c**2*f**2*n*p**2*x + 40*c**2*f**2*n*p*x + 16*c**2*f**2*n*x + 8*c**2*f**2*p **3*x + 36*c**2*f**2*p**2*x + 46*c**2*f**2*p*x + 15*c**2*f**2*x + 8*c*d...