Integrand size = 24, antiderivative size = 152 \[ \int \frac {(A+B x) (d+e x)^{3/2}}{(a+b x)^{5/2}} \, dx=-\frac {2 (b B d+A b e-2 a B e) \sqrt {d+e x}}{b^3 \sqrt {a+b x}}+\frac {B e \sqrt {a+b x} \sqrt {d+e x}}{b^3}-\frac {2 (A b-a B) (d+e x)^{3/2}}{3 b^2 (a+b x)^{3/2}}+\frac {\sqrt {e} (3 b B d+2 A b e-5 a B e) \text {arctanh}\left (\frac {\sqrt {e} \sqrt {a+b x}}{\sqrt {b} \sqrt {d+e x}}\right )}{b^{7/2}} \] Output:
-2*(A*b*e-2*B*a*e+B*b*d)*(e*x+d)^(1/2)/b^3/(b*x+a)^(1/2)+B*e*(b*x+a)^(1/2) *(e*x+d)^(1/2)/b^3-2/3*(A*b-B*a)*(e*x+d)^(3/2)/b^2/(b*x+a)^(3/2)+e^(1/2)*( 2*A*b*e-5*B*a*e+3*B*b*d)*arctanh(e^(1/2)*(b*x+a)^(1/2)/b^(1/2)/(e*x+d)^(1/ 2))/b^(7/2)
Time = 0.27 (sec) , antiderivative size = 133, normalized size of antiderivative = 0.88 \[ \int \frac {(A+B x) (d+e x)^{3/2}}{(a+b x)^{5/2}} \, dx=-\frac {\sqrt {d+e x} \left (B \left (-15 a^2 e+4 a b (d-5 e x)-3 b^2 x (-2 d+e x)\right )+2 A b (3 a e+b (d+4 e x))\right )}{3 b^3 (a+b x)^{3/2}}+\frac {\sqrt {e} (3 b B d+2 A b e-5 a B e) \text {arctanh}\left (\frac {\sqrt {e} \sqrt {a+b x}}{\sqrt {b} \sqrt {d+e x}}\right )}{b^{7/2}} \] Input:
Integrate[((A + B*x)*(d + e*x)^(3/2))/(a + b*x)^(5/2),x]
Output:
-1/3*(Sqrt[d + e*x]*(B*(-15*a^2*e + 4*a*b*(d - 5*e*x) - 3*b^2*x*(-2*d + e* x)) + 2*A*b*(3*a*e + b*(d + 4*e*x))))/(b^3*(a + b*x)^(3/2)) + (Sqrt[e]*(3* b*B*d + 2*A*b*e - 5*a*B*e)*ArcTanh[(Sqrt[e]*Sqrt[a + b*x])/(Sqrt[b]*Sqrt[d + e*x])])/b^(7/2)
Time = 0.26 (sec) , antiderivative size = 179, normalized size of antiderivative = 1.18, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.208, Rules used = {87, 57, 60, 66, 221}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {(A+B x) (d+e x)^{3/2}}{(a+b x)^{5/2}} \, dx\) |
\(\Big \downarrow \) 87 |
\(\displaystyle \frac {(-5 a B e+2 A b e+3 b B d) \int \frac {(d+e x)^{3/2}}{(a+b x)^{3/2}}dx}{3 b (b d-a e)}-\frac {2 (d+e x)^{5/2} (A b-a B)}{3 b (a+b x)^{3/2} (b d-a e)}\) |
\(\Big \downarrow \) 57 |
\(\displaystyle \frac {(-5 a B e+2 A b e+3 b B d) \left (\frac {3 e \int \frac {\sqrt {d+e x}}{\sqrt {a+b x}}dx}{b}-\frac {2 (d+e x)^{3/2}}{b \sqrt {a+b x}}\right )}{3 b (b d-a e)}-\frac {2 (d+e x)^{5/2} (A b-a B)}{3 b (a+b x)^{3/2} (b d-a e)}\) |
\(\Big \downarrow \) 60 |
\(\displaystyle \frac {(-5 a B e+2 A b e+3 b B d) \left (\frac {3 e \left (\frac {(b d-a e) \int \frac {1}{\sqrt {a+b x} \sqrt {d+e x}}dx}{2 b}+\frac {\sqrt {a+b x} \sqrt {d+e x}}{b}\right )}{b}-\frac {2 (d+e x)^{3/2}}{b \sqrt {a+b x}}\right )}{3 b (b d-a e)}-\frac {2 (d+e x)^{5/2} (A b-a B)}{3 b (a+b x)^{3/2} (b d-a e)}\) |
\(\Big \downarrow \) 66 |
\(\displaystyle \frac {(-5 a B e+2 A b e+3 b B d) \left (\frac {3 e \left (\frac {(b d-a e) \int \frac {1}{b-\frac {e (a+b x)}{d+e x}}d\frac {\sqrt {a+b x}}{\sqrt {d+e x}}}{b}+\frac {\sqrt {a+b x} \sqrt {d+e x}}{b}\right )}{b}-\frac {2 (d+e x)^{3/2}}{b \sqrt {a+b x}}\right )}{3 b (b d-a e)}-\frac {2 (d+e x)^{5/2} (A b-a B)}{3 b (a+b x)^{3/2} (b d-a e)}\) |
\(\Big \downarrow \) 221 |
\(\displaystyle \frac {(-5 a B e+2 A b e+3 b B d) \left (\frac {3 e \left (\frac {(b d-a e) \text {arctanh}\left (\frac {\sqrt {e} \sqrt {a+b x}}{\sqrt {b} \sqrt {d+e x}}\right )}{b^{3/2} \sqrt {e}}+\frac {\sqrt {a+b x} \sqrt {d+e x}}{b}\right )}{b}-\frac {2 (d+e x)^{3/2}}{b \sqrt {a+b x}}\right )}{3 b (b d-a e)}-\frac {2 (d+e x)^{5/2} (A b-a B)}{3 b (a+b x)^{3/2} (b d-a e)}\) |
Input:
Int[((A + B*x)*(d + e*x)^(3/2))/(a + b*x)^(5/2),x]
Output:
(-2*(A*b - a*B)*(d + e*x)^(5/2))/(3*b*(b*d - a*e)*(a + b*x)^(3/2)) + ((3*b *B*d + 2*A*b*e - 5*a*B*e)*((-2*(d + e*x)^(3/2))/(b*Sqrt[a + b*x]) + (3*e*( (Sqrt[a + b*x]*Sqrt[d + e*x])/b + ((b*d - a*e)*ArcTanh[(Sqrt[e]*Sqrt[a + b *x])/(Sqrt[b]*Sqrt[d + e*x])])/(b^(3/2)*Sqrt[e])))/b))/(3*b*(b*d - a*e))
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + 1))), x] - Simp[d*(n/(b*(m + 1))) Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] & & GtQ[n, 0] && LtQ[m, -1] && !(IntegerQ[n] && !IntegerQ[m]) && !(ILeQ[m + n + 2, 0] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c , d, m, n, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + n + 1))), x] + Simp[n*((b*c - a*d)/( b*(m + n + 1))) Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] && GtQ[n, 0] && NeQ[m + n + 1, 0] && !(IGtQ[m, 0] && ( !Integer Q[n] || (GtQ[m, 0] && LtQ[m - n, 0]))) && !ILtQ[m + n + 2, 0] && IntLinear Q[a, b, c, d, m, n, x]
Int[1/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]), x_Symbol] :> Simp[ 2 Subst[Int[1/(b - d*x^2), x], x, Sqrt[a + b*x]/Sqrt[c + d*x]], x] /; Fre eQ[{a, b, c, d}, x] && !GtQ[c - a*(d/b), 0]
Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p _.), x_] :> Simp[(-(b*e - a*f))*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/(f*(p + 1)*(c*f - d*e))), x] - Simp[(a*d*f*(n + p + 2) - b*(d*e*(n + 1) + c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)) Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || Intege rQ[p] || !(IntegerQ[n] || !(EqQ[e, 0] || !(EqQ[c, 0] || LtQ[p, n]))))
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x /Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
Leaf count of result is larger than twice the leaf count of optimal. \(697\) vs. \(2(126)=252\).
Time = 0.27 (sec) , antiderivative size = 698, normalized size of antiderivative = 4.59
method | result | size |
default | \(\frac {\sqrt {e x +d}\, \left (6 A \ln \left (\frac {2 b e x +2 \sqrt {\left (e x +d \right ) \left (b x +a \right )}\, \sqrt {b e}+a e +d b}{2 \sqrt {b e}}\right ) b^{3} e^{2} x^{2}-15 B \ln \left (\frac {2 b e x +2 \sqrt {\left (e x +d \right ) \left (b x +a \right )}\, \sqrt {b e}+a e +d b}{2 \sqrt {b e}}\right ) a \,b^{2} e^{2} x^{2}+9 B \ln \left (\frac {2 b e x +2 \sqrt {\left (e x +d \right ) \left (b x +a \right )}\, \sqrt {b e}+a e +d b}{2 \sqrt {b e}}\right ) b^{3} d e \,x^{2}+12 A \ln \left (\frac {2 b e x +2 \sqrt {\left (e x +d \right ) \left (b x +a \right )}\, \sqrt {b e}+a e +d b}{2 \sqrt {b e}}\right ) a \,b^{2} e^{2} x -30 B \ln \left (\frac {2 b e x +2 \sqrt {\left (e x +d \right ) \left (b x +a \right )}\, \sqrt {b e}+a e +d b}{2 \sqrt {b e}}\right ) a^{2} b \,e^{2} x +18 B \ln \left (\frac {2 b e x +2 \sqrt {\left (e x +d \right ) \left (b x +a \right )}\, \sqrt {b e}+a e +d b}{2 \sqrt {b e}}\right ) a \,b^{2} d e x +6 B \,b^{2} e \,x^{2} \sqrt {b e}\, \sqrt {\left (e x +d \right ) \left (b x +a \right )}+6 A \ln \left (\frac {2 b e x +2 \sqrt {\left (e x +d \right ) \left (b x +a \right )}\, \sqrt {b e}+a e +d b}{2 \sqrt {b e}}\right ) a^{2} b \,e^{2}-16 A \,b^{2} e x \sqrt {b e}\, \sqrt {\left (e x +d \right ) \left (b x +a \right )}-15 B \ln \left (\frac {2 b e x +2 \sqrt {\left (e x +d \right ) \left (b x +a \right )}\, \sqrt {b e}+a e +d b}{2 \sqrt {b e}}\right ) a^{3} e^{2}+9 B \ln \left (\frac {2 b e x +2 \sqrt {\left (e x +d \right ) \left (b x +a \right )}\, \sqrt {b e}+a e +d b}{2 \sqrt {b e}}\right ) a^{2} b d e +40 B a b e x \sqrt {b e}\, \sqrt {\left (e x +d \right ) \left (b x +a \right )}-12 B \,b^{2} d x \sqrt {b e}\, \sqrt {\left (e x +d \right ) \left (b x +a \right )}-12 A a b e \sqrt {b e}\, \sqrt {\left (e x +d \right ) \left (b x +a \right )}-4 A \,b^{2} d \sqrt {b e}\, \sqrt {\left (e x +d \right ) \left (b x +a \right )}+30 B \,a^{2} e \sqrt {b e}\, \sqrt {\left (e x +d \right ) \left (b x +a \right )}-8 B a b d \sqrt {b e}\, \sqrt {\left (e x +d \right ) \left (b x +a \right )}\right )}{6 \sqrt {b e}\, \sqrt {\left (e x +d \right ) \left (b x +a \right )}\, b^{3} \left (b x +a \right )^{\frac {3}{2}}}\) | \(698\) |
Input:
int((B*x+A)*(e*x+d)^(3/2)/(b*x+a)^(5/2),x,method=_RETURNVERBOSE)
Output:
1/6*(e*x+d)^(1/2)*(6*A*ln(1/2*(2*b*e*x+2*((e*x+d)*(b*x+a))^(1/2)*(b*e)^(1/ 2)+a*e+d*b)/(b*e)^(1/2))*b^3*e^2*x^2-15*B*ln(1/2*(2*b*e*x+2*((e*x+d)*(b*x+ a))^(1/2)*(b*e)^(1/2)+a*e+d*b)/(b*e)^(1/2))*a*b^2*e^2*x^2+9*B*ln(1/2*(2*b* e*x+2*((e*x+d)*(b*x+a))^(1/2)*(b*e)^(1/2)+a*e+d*b)/(b*e)^(1/2))*b^3*d*e*x^ 2+12*A*ln(1/2*(2*b*e*x+2*((e*x+d)*(b*x+a))^(1/2)*(b*e)^(1/2)+a*e+d*b)/(b*e )^(1/2))*a*b^2*e^2*x-30*B*ln(1/2*(2*b*e*x+2*((e*x+d)*(b*x+a))^(1/2)*(b*e)^ (1/2)+a*e+d*b)/(b*e)^(1/2))*a^2*b*e^2*x+18*B*ln(1/2*(2*b*e*x+2*((e*x+d)*(b *x+a))^(1/2)*(b*e)^(1/2)+a*e+d*b)/(b*e)^(1/2))*a*b^2*d*e*x+6*B*b^2*e*x^2*( b*e)^(1/2)*((e*x+d)*(b*x+a))^(1/2)+6*A*ln(1/2*(2*b*e*x+2*((e*x+d)*(b*x+a)) ^(1/2)*(b*e)^(1/2)+a*e+d*b)/(b*e)^(1/2))*a^2*b*e^2-16*A*b^2*e*x*(b*e)^(1/2 )*((e*x+d)*(b*x+a))^(1/2)-15*B*ln(1/2*(2*b*e*x+2*((e*x+d)*(b*x+a))^(1/2)*( b*e)^(1/2)+a*e+d*b)/(b*e)^(1/2))*a^3*e^2+9*B*ln(1/2*(2*b*e*x+2*((e*x+d)*(b *x+a))^(1/2)*(b*e)^(1/2)+a*e+d*b)/(b*e)^(1/2))*a^2*b*d*e+40*B*a*b*e*x*(b*e )^(1/2)*((e*x+d)*(b*x+a))^(1/2)-12*B*b^2*d*x*(b*e)^(1/2)*((e*x+d)*(b*x+a)) ^(1/2)-12*A*a*b*e*(b*e)^(1/2)*((e*x+d)*(b*x+a))^(1/2)-4*A*b^2*d*(b*e)^(1/2 )*((e*x+d)*(b*x+a))^(1/2)+30*B*a^2*e*(b*e)^(1/2)*((e*x+d)*(b*x+a))^(1/2)-8 *B*a*b*d*(b*e)^(1/2)*((e*x+d)*(b*x+a))^(1/2))/(b*e)^(1/2)/((e*x+d)*(b*x+a) )^(1/2)/b^3/(b*x+a)^(3/2)
Leaf count of result is larger than twice the leaf count of optimal. 268 vs. \(2 (126) = 252\).
Time = 0.98 (sec) , antiderivative size = 561, normalized size of antiderivative = 3.69 \[ \int \frac {(A+B x) (d+e x)^{3/2}}{(a+b x)^{5/2}} \, dx=\left [\frac {3 \, {\left (3 \, B a^{2} b d + {\left (3 \, B b^{3} d - {\left (5 \, B a b^{2} - 2 \, A b^{3}\right )} e\right )} x^{2} - {\left (5 \, B a^{3} - 2 \, A a^{2} b\right )} e + 2 \, {\left (3 \, B a b^{2} d - {\left (5 \, B a^{2} b - 2 \, A a b^{2}\right )} e\right )} x\right )} \sqrt {\frac {e}{b}} \log \left (8 \, b^{2} e^{2} x^{2} + b^{2} d^{2} + 6 \, a b d e + a^{2} e^{2} + 4 \, {\left (2 \, b^{2} e x + b^{2} d + a b e\right )} \sqrt {b x + a} \sqrt {e x + d} \sqrt {\frac {e}{b}} + 8 \, {\left (b^{2} d e + a b e^{2}\right )} x\right ) + 4 \, {\left (3 \, B b^{2} e x^{2} - 2 \, {\left (2 \, B a b + A b^{2}\right )} d + 3 \, {\left (5 \, B a^{2} - 2 \, A a b\right )} e - 2 \, {\left (3 \, B b^{2} d - 2 \, {\left (5 \, B a b - 2 \, A b^{2}\right )} e\right )} x\right )} \sqrt {b x + a} \sqrt {e x + d}}{12 \, {\left (b^{5} x^{2} + 2 \, a b^{4} x + a^{2} b^{3}\right )}}, -\frac {3 \, {\left (3 \, B a^{2} b d + {\left (3 \, B b^{3} d - {\left (5 \, B a b^{2} - 2 \, A b^{3}\right )} e\right )} x^{2} - {\left (5 \, B a^{3} - 2 \, A a^{2} b\right )} e + 2 \, {\left (3 \, B a b^{2} d - {\left (5 \, B a^{2} b - 2 \, A a b^{2}\right )} e\right )} x\right )} \sqrt {-\frac {e}{b}} \arctan \left (\frac {{\left (2 \, b e x + b d + a e\right )} \sqrt {b x + a} \sqrt {e x + d} \sqrt {-\frac {e}{b}}}{2 \, {\left (b e^{2} x^{2} + a d e + {\left (b d e + a e^{2}\right )} x\right )}}\right ) - 2 \, {\left (3 \, B b^{2} e x^{2} - 2 \, {\left (2 \, B a b + A b^{2}\right )} d + 3 \, {\left (5 \, B a^{2} - 2 \, A a b\right )} e - 2 \, {\left (3 \, B b^{2} d - 2 \, {\left (5 \, B a b - 2 \, A b^{2}\right )} e\right )} x\right )} \sqrt {b x + a} \sqrt {e x + d}}{6 \, {\left (b^{5} x^{2} + 2 \, a b^{4} x + a^{2} b^{3}\right )}}\right ] \] Input:
integrate((B*x+A)*(e*x+d)^(3/2)/(b*x+a)^(5/2),x, algorithm="fricas")
Output:
[1/12*(3*(3*B*a^2*b*d + (3*B*b^3*d - (5*B*a*b^2 - 2*A*b^3)*e)*x^2 - (5*B*a ^3 - 2*A*a^2*b)*e + 2*(3*B*a*b^2*d - (5*B*a^2*b - 2*A*a*b^2)*e)*x)*sqrt(e/ b)*log(8*b^2*e^2*x^2 + b^2*d^2 + 6*a*b*d*e + a^2*e^2 + 4*(2*b^2*e*x + b^2* d + a*b*e)*sqrt(b*x + a)*sqrt(e*x + d)*sqrt(e/b) + 8*(b^2*d*e + a*b*e^2)*x ) + 4*(3*B*b^2*e*x^2 - 2*(2*B*a*b + A*b^2)*d + 3*(5*B*a^2 - 2*A*a*b)*e - 2 *(3*B*b^2*d - 2*(5*B*a*b - 2*A*b^2)*e)*x)*sqrt(b*x + a)*sqrt(e*x + d))/(b^ 5*x^2 + 2*a*b^4*x + a^2*b^3), -1/6*(3*(3*B*a^2*b*d + (3*B*b^3*d - (5*B*a*b ^2 - 2*A*b^3)*e)*x^2 - (5*B*a^3 - 2*A*a^2*b)*e + 2*(3*B*a*b^2*d - (5*B*a^2 *b - 2*A*a*b^2)*e)*x)*sqrt(-e/b)*arctan(1/2*(2*b*e*x + b*d + a*e)*sqrt(b*x + a)*sqrt(e*x + d)*sqrt(-e/b)/(b*e^2*x^2 + a*d*e + (b*d*e + a*e^2)*x)) - 2*(3*B*b^2*e*x^2 - 2*(2*B*a*b + A*b^2)*d + 3*(5*B*a^2 - 2*A*a*b)*e - 2*(3* B*b^2*d - 2*(5*B*a*b - 2*A*b^2)*e)*x)*sqrt(b*x + a)*sqrt(e*x + d))/(b^5*x^ 2 + 2*a*b^4*x + a^2*b^3)]
\[ \int \frac {(A+B x) (d+e x)^{3/2}}{(a+b x)^{5/2}} \, dx=\int \frac {\left (A + B x\right ) \left (d + e x\right )^{\frac {3}{2}}}{\left (a + b x\right )^{\frac {5}{2}}}\, dx \] Input:
integrate((B*x+A)*(e*x+d)**(3/2)/(b*x+a)**(5/2),x)
Output:
Integral((A + B*x)*(d + e*x)**(3/2)/(a + b*x)**(5/2), x)
Exception generated. \[ \int \frac {(A+B x) (d+e x)^{3/2}}{(a+b x)^{5/2}} \, dx=\text {Exception raised: ValueError} \] Input:
integrate((B*x+A)*(e*x+d)^(3/2)/(b*x+a)^(5/2),x, algorithm="maxima")
Output:
Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'assume' command before evaluation *may* help (example of legal syntax is 'assume(a*e-b*d>0)', see `assume?` for m ore detail
Leaf count of result is larger than twice the leaf count of optimal. 1019 vs. \(2 (126) = 252\).
Time = 0.34 (sec) , antiderivative size = 1019, normalized size of antiderivative = 6.70 \[ \int \frac {(A+B x) (d+e x)^{3/2}}{(a+b x)^{5/2}} \, dx =\text {Too large to display} \] Input:
integrate((B*x+A)*(e*x+d)^(3/2)/(b*x+a)^(5/2),x, algorithm="giac")
Output:
sqrt(b^2*d + (b*x + a)*b*e - a*b*e)*sqrt(b*x + a)*B*e*abs(b)/b^5 - 1/2*(3* sqrt(b*e)*B*b*d*abs(b) - 5*sqrt(b*e)*B*a*e*abs(b) + 2*sqrt(b*e)*A*b*e*abs( b))*log((sqrt(b*e)*sqrt(b*x + a) - sqrt(b^2*d + (b*x + a)*b*e - a*b*e))^2) /b^5 - 4/3*(3*sqrt(b*e)*B*b^6*d^4*abs(b) - 16*sqrt(b*e)*B*a*b^5*d^3*e*abs( b) + 4*sqrt(b*e)*A*b^6*d^3*e*abs(b) + 30*sqrt(b*e)*B*a^2*b^4*d^2*e^2*abs(b ) - 12*sqrt(b*e)*A*a*b^5*d^2*e^2*abs(b) - 24*sqrt(b*e)*B*a^3*b^3*d*e^3*abs (b) + 12*sqrt(b*e)*A*a^2*b^4*d*e^3*abs(b) + 7*sqrt(b*e)*B*a^4*b^2*e^4*abs( b) - 4*sqrt(b*e)*A*a^3*b^3*e^4*abs(b) - 6*sqrt(b*e)*(sqrt(b*e)*sqrt(b*x + a) - sqrt(b^2*d + (b*x + a)*b*e - a*b*e))^2*B*b^4*d^3*abs(b) + 24*sqrt(b*e )*(sqrt(b*e)*sqrt(b*x + a) - sqrt(b^2*d + (b*x + a)*b*e - a*b*e))^2*B*a*b^ 3*d^2*e*abs(b) - 6*sqrt(b*e)*(sqrt(b*e)*sqrt(b*x + a) - sqrt(b^2*d + (b*x + a)*b*e - a*b*e))^2*A*b^4*d^2*e*abs(b) - 30*sqrt(b*e)*(sqrt(b*e)*sqrt(b*x + a) - sqrt(b^2*d + (b*x + a)*b*e - a*b*e))^2*B*a^2*b^2*d*e^2*abs(b) + 12 *sqrt(b*e)*(sqrt(b*e)*sqrt(b*x + a) - sqrt(b^2*d + (b*x + a)*b*e - a*b*e)) ^2*A*a*b^3*d*e^2*abs(b) + 12*sqrt(b*e)*(sqrt(b*e)*sqrt(b*x + a) - sqrt(b^2 *d + (b*x + a)*b*e - a*b*e))^2*B*a^3*b*e^3*abs(b) - 6*sqrt(b*e)*(sqrt(b*e) *sqrt(b*x + a) - sqrt(b^2*d + (b*x + a)*b*e - a*b*e))^2*A*a^2*b^2*e^3*abs( b) + 3*sqrt(b*e)*(sqrt(b*e)*sqrt(b*x + a) - sqrt(b^2*d + (b*x + a)*b*e - a *b*e))^4*B*b^2*d^2*abs(b) - 12*sqrt(b*e)*(sqrt(b*e)*sqrt(b*x + a) - sqrt(b ^2*d + (b*x + a)*b*e - a*b*e))^4*B*a*b*d*e*abs(b) + 6*sqrt(b*e)*(sqrt(b...
Timed out. \[ \int \frac {(A+B x) (d+e x)^{3/2}}{(a+b x)^{5/2}} \, dx=\int \frac {\left (A+B\,x\right )\,{\left (d+e\,x\right )}^{3/2}}{{\left (a+b\,x\right )}^{5/2}} \,d x \] Input:
int(((A + B*x)*(d + e*x)^(3/2))/(a + b*x)^(5/2),x)
Output:
int(((A + B*x)*(d + e*x)^(3/2))/(a + b*x)^(5/2), x)
Time = 0.16 (sec) , antiderivative size = 170, normalized size of antiderivative = 1.12 \[ \int \frac {(A+B x) (d+e x)^{3/2}}{(a+b x)^{5/2}} \, dx=\frac {-12 \sqrt {e}\, \sqrt {b}\, \sqrt {b x +a}\, \mathrm {log}\left (\frac {\sqrt {e}\, \sqrt {b x +a}+\sqrt {b}\, \sqrt {e x +d}}{\sqrt {a e -b d}}\right ) a e +12 \sqrt {e}\, \sqrt {b}\, \sqrt {b x +a}\, \mathrm {log}\left (\frac {\sqrt {e}\, \sqrt {b x +a}+\sqrt {b}\, \sqrt {e x +d}}{\sqrt {a e -b d}}\right ) b d +9 \sqrt {e}\, \sqrt {b}\, \sqrt {b x +a}\, a e -9 \sqrt {e}\, \sqrt {b}\, \sqrt {b x +a}\, b d +12 \sqrt {e x +d}\, a b e -8 \sqrt {e x +d}\, b^{2} d +4 \sqrt {e x +d}\, b^{2} e x}{4 \sqrt {b x +a}\, b^{3}} \] Input:
int((B*x+A)*(e*x+d)^(3/2)/(b*x+a)^(5/2),x)
Output:
( - 12*sqrt(e)*sqrt(b)*sqrt(a + b*x)*log((sqrt(e)*sqrt(a + b*x) + sqrt(b)* sqrt(d + e*x))/sqrt(a*e - b*d))*a*e + 12*sqrt(e)*sqrt(b)*sqrt(a + b*x)*log ((sqrt(e)*sqrt(a + b*x) + sqrt(b)*sqrt(d + e*x))/sqrt(a*e - b*d))*b*d + 9* sqrt(e)*sqrt(b)*sqrt(a + b*x)*a*e - 9*sqrt(e)*sqrt(b)*sqrt(a + b*x)*b*d + 12*sqrt(d + e*x)*a*b*e - 8*sqrt(d + e*x)*b**2*d + 4*sqrt(d + e*x)*b**2*e*x )/(4*sqrt(a + b*x)*b**3)