Integrand size = 26, antiderivative size = 64 \[ \int \frac {1}{\sqrt {1-2 x} (2+3 x)^2 \sqrt {3+5 x}} \, dx=\frac {3 \sqrt {1-2 x} \sqrt {3+5 x}}{7 (2+3 x)}-\frac {37 \arctan \left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {3+5 x}}\right )}{7 \sqrt {7}} \] Output:
3*(1-2*x)^(1/2)*(3+5*x)^(1/2)/(14+21*x)-37/49*7^(1/2)*arctan(1/7*(1-2*x)^( 1/2)*7^(1/2)/(3+5*x)^(1/2))
Time = 0.11 (sec) , antiderivative size = 62, normalized size of antiderivative = 0.97 \[ \int \frac {1}{\sqrt {1-2 x} (2+3 x)^2 \sqrt {3+5 x}} \, dx=\frac {3 \sqrt {1-2 x} \sqrt {3+5 x}}{14+21 x}-\frac {37 \arctan \left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {3+5 x}}\right )}{7 \sqrt {7}} \] Input:
Integrate[1/(Sqrt[1 - 2*x]*(2 + 3*x)^2*Sqrt[3 + 5*x]),x]
Output:
(3*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/(14 + 21*x) - (37*ArcTan[Sqrt[1 - 2*x]/(Sq rt[7]*Sqrt[3 + 5*x])])/(7*Sqrt[7])
Time = 0.16 (sec) , antiderivative size = 64, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.115, Rules used = {107, 104, 217}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{\sqrt {1-2 x} (3 x+2)^2 \sqrt {5 x+3}} \, dx\) |
\(\Big \downarrow \) 107 |
\(\displaystyle \frac {37}{14} \int \frac {1}{\sqrt {1-2 x} (3 x+2) \sqrt {5 x+3}}dx+\frac {3 \sqrt {1-2 x} \sqrt {5 x+3}}{7 (3 x+2)}\) |
\(\Big \downarrow \) 104 |
\(\displaystyle \frac {37}{7} \int \frac {1}{-\frac {1-2 x}{5 x+3}-7}d\frac {\sqrt {1-2 x}}{\sqrt {5 x+3}}+\frac {3 \sqrt {1-2 x} \sqrt {5 x+3}}{7 (3 x+2)}\) |
\(\Big \downarrow \) 217 |
\(\displaystyle \frac {3 \sqrt {1-2 x} \sqrt {5 x+3}}{7 (3 x+2)}-\frac {37 \arctan \left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {5 x+3}}\right )}{7 \sqrt {7}}\) |
Input:
Int[1/(Sqrt[1 - 2*x]*(2 + 3*x)^2*Sqrt[3 + 5*x]),x]
Output:
(3*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/(7*(2 + 3*x)) - (37*ArcTan[Sqrt[1 - 2*x]/( Sqrt[7]*Sqrt[3 + 5*x])])/(7*Sqrt[7])
Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x _)), x_] :> With[{q = Denominator[m]}, Simp[q Subst[Int[x^(q*(m + 1) - 1) /(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^(1/q)], x] ] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && L tQ[-1, m, 0] && SimplerQ[a + b*x, c + d*x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_), x_] :> Simp[b*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1 )/((m + 1)*(b*c - a*d)*(b*e - a*f))), x] + Simp[(a*d*f*(m + 1) + b*c*f*(n + 1) + b*d*e*(p + 1))/((m + 1)*(b*c - a*d)*(b*e - a*f)) Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x ] && EqQ[Simplify[m + n + p + 3], 0] && (LtQ[m, -1] || SumSimplerQ[m, 1])
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( -1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & & (LtQ[a, 0] || LtQ[b, 0])
Leaf count of result is larger than twice the leaf count of optimal. \(107\) vs. \(2(49)=98\).
Time = 0.25 (sec) , antiderivative size = 108, normalized size of antiderivative = 1.69
method | result | size |
default | \(\frac {\sqrt {1-2 x}\, \sqrt {3+5 x}\, \left (111 \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right ) x +74 \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right )+42 \sqrt {-10 x^{2}-x +3}\right )}{98 \sqrt {-10 x^{2}-x +3}\, \left (2+3 x \right )}\) | \(108\) |
risch | \(-\frac {3 \left (-1+2 x \right ) \sqrt {3+5 x}\, \sqrt {\left (1-2 x \right ) \left (3+5 x \right )}}{7 \left (2+3 x \right ) \sqrt {-\left (-1+2 x \right ) \left (3+5 x \right )}\, \sqrt {1-2 x}}+\frac {37 \sqrt {7}\, \arctan \left (\frac {9 \left (\frac {20}{3}+\frac {37 x}{3}\right ) \sqrt {7}}{14 \sqrt {-90 \left (\frac {2}{3}+x \right )^{2}+67+111 x}}\right ) \sqrt {\left (1-2 x \right ) \left (3+5 x \right )}}{98 \sqrt {1-2 x}\, \sqrt {3+5 x}}\) | \(114\) |
Input:
int(1/(1-2*x)^(1/2)/(2+3*x)^2/(3+5*x)^(1/2),x,method=_RETURNVERBOSE)
Output:
1/98*(1-2*x)^(1/2)*(3+5*x)^(1/2)*(111*7^(1/2)*arctan(1/14*(37*x+20)*7^(1/2 )/(-10*x^2-x+3)^(1/2))*x+74*7^(1/2)*arctan(1/14*(37*x+20)*7^(1/2)/(-10*x^2 -x+3)^(1/2))+42*(-10*x^2-x+3)^(1/2))/(-10*x^2-x+3)^(1/2)/(2+3*x)
Time = 0.09 (sec) , antiderivative size = 71, normalized size of antiderivative = 1.11 \[ \int \frac {1}{\sqrt {1-2 x} (2+3 x)^2 \sqrt {3+5 x}} \, dx=-\frac {37 \, \sqrt {7} {\left (3 \, x + 2\right )} \arctan \left (\frac {\sqrt {7} {\left (37 \, x + 20\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{14 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) - 42 \, \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{98 \, {\left (3 \, x + 2\right )}} \] Input:
integrate(1/(1-2*x)^(1/2)/(2+3*x)^2/(3+5*x)^(1/2),x, algorithm="fricas")
Output:
-1/98*(37*sqrt(7)*(3*x + 2)*arctan(1/14*sqrt(7)*(37*x + 20)*sqrt(5*x + 3)* sqrt(-2*x + 1)/(10*x^2 + x - 3)) - 42*sqrt(5*x + 3)*sqrt(-2*x + 1))/(3*x + 2)
\[ \int \frac {1}{\sqrt {1-2 x} (2+3 x)^2 \sqrt {3+5 x}} \, dx=\int \frac {1}{\sqrt {1 - 2 x} \left (3 x + 2\right )^{2} \sqrt {5 x + 3}}\, dx \] Input:
integrate(1/(1-2*x)**(1/2)/(2+3*x)**2/(3+5*x)**(1/2),x)
Output:
Integral(1/(sqrt(1 - 2*x)*(3*x + 2)**2*sqrt(5*x + 3)), x)
Time = 0.14 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.78 \[ \int \frac {1}{\sqrt {1-2 x} (2+3 x)^2 \sqrt {3+5 x}} \, dx=\frac {37}{98} \, \sqrt {7} \arcsin \left (\frac {37 \, x}{11 \, {\left | 3 \, x + 2 \right |}} + \frac {20}{11 \, {\left | 3 \, x + 2 \right |}}\right ) + \frac {3 \, \sqrt {-10 \, x^{2} - x + 3}}{7 \, {\left (3 \, x + 2\right )}} \] Input:
integrate(1/(1-2*x)^(1/2)/(2+3*x)^2/(3+5*x)^(1/2),x, algorithm="maxima")
Output:
37/98*sqrt(7)*arcsin(37/11*x/abs(3*x + 2) + 20/11/abs(3*x + 2)) + 3/7*sqrt (-10*x^2 - x + 3)/(3*x + 2)
Leaf count of result is larger than twice the leaf count of optimal. 193 vs. \(2 (49) = 98\).
Time = 0.15 (sec) , antiderivative size = 193, normalized size of antiderivative = 3.02 \[ \int \frac {1}{\sqrt {1-2 x} (2+3 x)^2 \sqrt {3+5 x}} \, dx=\frac {37}{980} \, \sqrt {70} \sqrt {10} {\left (\pi + 2 \, \arctan \left (-\frac {\sqrt {70} \sqrt {5 \, x + 3} {\left (\frac {{\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{140 \, {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}}\right )\right )} + \frac {66 \, \sqrt {10} {\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}}{7 \, {\left ({\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}^{2} + 280\right )}} \] Input:
integrate(1/(1-2*x)^(1/2)/(2+3*x)^2/(3+5*x)^(1/2),x, algorithm="giac")
Output:
37/980*sqrt(70)*sqrt(10)*(pi + 2*arctan(-1/140*sqrt(70)*sqrt(5*x + 3)*((sq rt(2)*sqrt(-10*x + 5) - sqrt(22))^2/(5*x + 3) - 4)/(sqrt(2)*sqrt(-10*x + 5 ) - sqrt(22)))) + 66/7*sqrt(10)*((sqrt(2)*sqrt(-10*x + 5) - sqrt(22))/sqrt (5*x + 3) - 4*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))/(((sqrt( 2)*sqrt(-10*x + 5) - sqrt(22))/sqrt(5*x + 3) - 4*sqrt(5*x + 3)/(sqrt(2)*sq rt(-10*x + 5) - sqrt(22)))^2 + 280)
Time = 4.97 (sec) , antiderivative size = 716, normalized size of antiderivative = 11.19 \[ \int \frac {1}{\sqrt {1-2 x} (2+3 x)^2 \sqrt {3+5 x}} \, dx =\text {Too large to display} \] Input:
int(1/((1 - 2*x)^(1/2)*(3*x + 2)^2*(5*x + 3)^(1/2)),x)
Output:
(6*((1 - 2*x)^(1/2) - 1)^3)/(7*(3^(1/2) - (5*x + 3)^(1/2))^3*((14*((1 - 2* x)^(1/2) - 1)^2)/(25*(3^(1/2) - (5*x + 3)^(1/2))^2) + ((1 - 2*x)^(1/2) - 1 )^4/(3^(1/2) - (5*x + 3)^(1/2))^4 + (6*3^(1/2)*((1 - 2*x)^(1/2) - 1)^3)/(5 *(3^(1/2) - (5*x + 3)^(1/2))^3) - (12*3^(1/2)*((1 - 2*x)^(1/2) - 1))/(25*( 3^(1/2) - (5*x + 3)^(1/2))) + 4/25)) - (37*7^(1/2)*atan((32856*3^(1/2)*7^( 1/2))/(42875*((32856*((1 - 2*x)^(1/2) - 1)^2)/(1715*(3^(1/2) - (5*x + 3)^( 1/2))^2) + (607836*3^(1/2)*((1 - 2*x)^(1/2) - 1))/(42875*(3^(1/2) - (5*x + 3)^(1/2))) - 65712/8575)) + (16428*7^(1/2)*((1 - 2*x)^(1/2) - 1))/(42875* (3^(1/2) - (5*x + 3)^(1/2))*((32856*((1 - 2*x)^(1/2) - 1)^2)/(1715*(3^(1/2 ) - (5*x + 3)^(1/2))^2) + (607836*3^(1/2)*((1 - 2*x)^(1/2) - 1))/(42875*(3 ^(1/2) - (5*x + 3)^(1/2))) - 65712/8575)) - (16428*3^(1/2)*7^(1/2)*((1 - 2 *x)^(1/2) - 1)^2)/(8575*(3^(1/2) - (5*x + 3)^(1/2))^2*((32856*((1 - 2*x)^( 1/2) - 1)^2)/(1715*(3^(1/2) - (5*x + 3)^(1/2))^2) + (607836*3^(1/2)*((1 - 2*x)^(1/2) - 1))/(42875*(3^(1/2) - (5*x + 3)^(1/2))) - 65712/8575))))/49 - (12*((1 - 2*x)^(1/2) - 1))/(35*(3^(1/2) - (5*x + 3)^(1/2))*((14*((1 - 2*x )^(1/2) - 1)^2)/(25*(3^(1/2) - (5*x + 3)^(1/2))^2) + ((1 - 2*x)^(1/2) - 1) ^4/(3^(1/2) - (5*x + 3)^(1/2))^4 + (6*3^(1/2)*((1 - 2*x)^(1/2) - 1)^3)/(5* (3^(1/2) - (5*x + 3)^(1/2))^3) - (12*3^(1/2)*((1 - 2*x)^(1/2) - 1))/(25*(3 ^(1/2) - (5*x + 3)^(1/2))) + 4/25)) + (111*3^(1/2)*((1 - 2*x)^(1/2) - 1)^2 )/(175*(3^(1/2) - (5*x + 3)^(1/2))^2*((14*((1 - 2*x)^(1/2) - 1)^2)/(25*...
Time = 0.25 (sec) , antiderivative size = 159, normalized size of antiderivative = 2.48 \[ \int \frac {1}{\sqrt {1-2 x} (2+3 x)^2 \sqrt {3+5 x}} \, dx=\frac {111 \sqrt {7}\, \mathit {atan} \left (\frac {\sqrt {33}-\sqrt {35}\, \tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-2 x +1}\, \sqrt {5}}{\sqrt {11}}\right )}{2}\right )}{\sqrt {2}}\right ) x +74 \sqrt {7}\, \mathit {atan} \left (\frac {\sqrt {33}-\sqrt {35}\, \tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-2 x +1}\, \sqrt {5}}{\sqrt {11}}\right )}{2}\right )}{\sqrt {2}}\right )-111 \sqrt {7}\, \mathit {atan} \left (\frac {\sqrt {33}+\sqrt {35}\, \tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-2 x +1}\, \sqrt {5}}{\sqrt {11}}\right )}{2}\right )}{\sqrt {2}}\right ) x -74 \sqrt {7}\, \mathit {atan} \left (\frac {\sqrt {33}+\sqrt {35}\, \tan \left (\frac {\mathit {asin} \left (\frac {\sqrt {-2 x +1}\, \sqrt {5}}{\sqrt {11}}\right )}{2}\right )}{\sqrt {2}}\right )+21 \sqrt {5 x +3}\, \sqrt {-2 x +1}}{147 x +98} \] Input:
int(1/(1-2*x)^(1/2)/(2+3*x)^2/(3+5*x)^(1/2),x)
Output:
(111*sqrt(7)*atan((sqrt(33) - sqrt(35)*tan(asin((sqrt( - 2*x + 1)*sqrt(5)) /sqrt(11))/2))/sqrt(2))*x + 74*sqrt(7)*atan((sqrt(33) - sqrt(35)*tan(asin( (sqrt( - 2*x + 1)*sqrt(5))/sqrt(11))/2))/sqrt(2)) - 111*sqrt(7)*atan((sqrt (33) + sqrt(35)*tan(asin((sqrt( - 2*x + 1)*sqrt(5))/sqrt(11))/2))/sqrt(2)) *x - 74*sqrt(7)*atan((sqrt(33) + sqrt(35)*tan(asin((sqrt( - 2*x + 1)*sqrt( 5))/sqrt(11))/2))/sqrt(2)) + 21*sqrt(5*x + 3)*sqrt( - 2*x + 1))/(49*(3*x + 2))