Integrand size = 24, antiderivative size = 114 \[ \int \frac {(1-2 x)^{3/2} (3+5 x)^3}{(2+3 x)^4} \, dx=\frac {2050}{243} \sqrt {1-2 x}+\frac {250}{243} (1-2 x)^{3/2}+\frac {7 \sqrt {1-2 x}}{729 (2+3 x)^3}-\frac {161 \sqrt {1-2 x}}{729 (2+3 x)^2}+\frac {3938 \sqrt {1-2 x}}{1701 (2+3 x)}-\frac {36038 \text {arctanh}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{567 \sqrt {21}} \] Output:
2050/243*(1-2*x)^(1/2)+250/243*(1-2*x)^(3/2)+7/729*(1-2*x)^(1/2)/(2+3*x)^3 -161/729*(1-2*x)^(1/2)/(2+3*x)^2+3938*(1-2*x)^(1/2)/(3402+5103*x)-36038/11 907*21^(1/2)*arctanh(1/7*21^(1/2)*(1-2*x)^(1/2))
Time = 0.19 (sec) , antiderivative size = 68, normalized size of antiderivative = 0.60 \[ \int \frac {(1-2 x)^{3/2} (3+5 x)^3}{(2+3 x)^4} \, dx=\frac {\sqrt {1-2 x} \left (47939+199243 x+259614 x^2+81900 x^3-31500 x^4\right )}{567 (2+3 x)^3}-\frac {36038 \text {arctanh}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{567 \sqrt {21}} \] Input:
Integrate[((1 - 2*x)^(3/2)*(3 + 5*x)^3)/(2 + 3*x)^4,x]
Output:
(Sqrt[1 - 2*x]*(47939 + 199243*x + 259614*x^2 + 81900*x^3 - 31500*x^4))/(5 67*(2 + 3*x)^3) - (36038*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]])/(567*Sqrt[21])
Time = 0.23 (sec) , antiderivative size = 135, normalized size of antiderivative = 1.18, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {108, 27, 166, 27, 166, 164, 73, 219}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {(1-2 x)^{3/2} (5 x+3)^3}{(3 x+2)^4} \, dx\) |
\(\Big \downarrow \) 108 |
\(\displaystyle \frac {1}{9} \int \frac {3 (2-15 x) \sqrt {1-2 x} (5 x+3)^2}{(3 x+2)^3}dx-\frac {(1-2 x)^{3/2} (5 x+3)^3}{9 (3 x+2)^3}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {1}{3} \int \frac {(2-15 x) \sqrt {1-2 x} (5 x+3)^2}{(3 x+2)^3}dx-\frac {(1-2 x)^{3/2} (5 x+3)^3}{9 (3 x+2)^3}\) |
\(\Big \downarrow \) 166 |
\(\displaystyle \frac {1}{3} \left (\frac {6 \sqrt {1-2 x} (5 x+3)^3}{(3 x+2)^2}-\frac {1}{6} \int \frac {6 (17-100 x) (5 x+3)^2}{\sqrt {1-2 x} (3 x+2)^2}dx\right )-\frac {(1-2 x)^{3/2} (5 x+3)^3}{9 (3 x+2)^3}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {1}{3} \left (\frac {6 \sqrt {1-2 x} (5 x+3)^3}{(3 x+2)^2}-\int \frac {(17-100 x) (5 x+3)^2}{\sqrt {1-2 x} (3 x+2)^2}dx\right )-\frac {(1-2 x)^{3/2} (5 x+3)^3}{9 (3 x+2)^3}\) |
\(\Big \downarrow \) 166 |
\(\displaystyle \frac {1}{3} \left (-\frac {1}{21} \int \frac {(1163-7265 x) (5 x+3)}{\sqrt {1-2 x} (3 x+2)}dx+\frac {6 \sqrt {1-2 x} (5 x+3)^3}{(3 x+2)^2}+\frac {251 \sqrt {1-2 x} (5 x+3)^2}{21 (3 x+2)}\right )-\frac {(1-2 x)^{3/2} (5 x+3)^3}{9 (3 x+2)^3}\) |
\(\Big \downarrow \) 164 |
\(\displaystyle \frac {1}{3} \left (\frac {1}{21} \left (\frac {18019}{9} \int \frac {1}{\sqrt {1-2 x} (3 x+2)}dx-\frac {5}{9} \sqrt {1-2 x} (7265 x+2323)\right )+\frac {6 \sqrt {1-2 x} (5 x+3)^3}{(3 x+2)^2}+\frac {251 \sqrt {1-2 x} (5 x+3)^2}{21 (3 x+2)}\right )-\frac {(1-2 x)^{3/2} (5 x+3)^3}{9 (3 x+2)^3}\) |
\(\Big \downarrow \) 73 |
\(\displaystyle \frac {1}{3} \left (\frac {1}{21} \left (-\frac {18019}{9} \int \frac {1}{\frac {7}{2}-\frac {3}{2} (1-2 x)}d\sqrt {1-2 x}-\frac {5}{9} \sqrt {1-2 x} (7265 x+2323)\right )+\frac {6 \sqrt {1-2 x} (5 x+3)^3}{(3 x+2)^2}+\frac {251 \sqrt {1-2 x} (5 x+3)^2}{21 (3 x+2)}\right )-\frac {(1-2 x)^{3/2} (5 x+3)^3}{9 (3 x+2)^3}\) |
\(\Big \downarrow \) 219 |
\(\displaystyle \frac {1}{3} \left (\frac {1}{21} \left (-\frac {36038 \text {arctanh}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{9 \sqrt {21}}-\frac {5}{9} \sqrt {1-2 x} (7265 x+2323)\right )+\frac {6 \sqrt {1-2 x} (5 x+3)^3}{(3 x+2)^2}+\frac {251 \sqrt {1-2 x} (5 x+3)^2}{21 (3 x+2)}\right )-\frac {(1-2 x)^{3/2} (5 x+3)^3}{9 (3 x+2)^3}\) |
Input:
Int[((1 - 2*x)^(3/2)*(3 + 5*x)^3)/(2 + 3*x)^4,x]
Output:
-1/9*((1 - 2*x)^(3/2)*(3 + 5*x)^3)/(2 + 3*x)^3 + ((251*Sqrt[1 - 2*x]*(3 + 5*x)^2)/(21*(2 + 3*x)) + (6*Sqrt[1 - 2*x]*(3 + 5*x)^3)/(2 + 3*x)^2 + ((-5* Sqrt[1 - 2*x]*(2323 + 7265*x))/9 - (36038*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]] )/(9*Sqrt[21]))/21)/3
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ {p = Denominator[m]}, Simp[p/b Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL inearQ[a, b, c, d, m, n, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_), x_] :> Simp[(a + b*x)^(m + 1)*(c + d*x)^n*((e + f*x)^p/(b*(m + 1))) , x] - Simp[1/(b*(m + 1)) Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f* x)^(p - 1)*Simp[d*e*n + c*f*p + d*f*(n + p)*x, x], x], x] /; FreeQ[{a, b, c , d, e, f}, x] && LtQ[m, -1] && GtQ[n, 0] && GtQ[p, 0] && (IntegersQ[2*m, 2 *n, 2*p] || IntegersQ[m, n + p] || IntegersQ[p, m + n])
Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_) + (f_.)*(x_ ))*((g_.) + (h_.)*(x_)), x_] :> Simp[(-(a*d*f*h*(n + 2) + b*c*f*h*(m + 2) - b*d*(f*g + e*h)*(m + n + 3) - b*d*f*h*(m + n + 2)*x))*(a + b*x)^(m + 1)*(( c + d*x)^(n + 1)/(b^2*d^2*(m + n + 2)*(m + n + 3))), x] + Simp[(a^2*d^2*f*h *(n + 1)*(n + 2) + a*b*d*(n + 1)*(2*c*f*h*(m + 1) - d*(f*g + e*h)*(m + n + 3)) + b^2*(c^2*f*h*(m + 1)*(m + 2) - c*d*(f*g + e*h)*(m + 1)*(m + n + 3) + d^2*e*g*(m + n + 2)*(m + n + 3)))/(b^2*d^2*(m + n + 2)*(m + n + 3)) Int[( a + b*x)^m*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, m, n}, x] && NeQ[m + n + 2, 0] && NeQ[m + n + 3, 0]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_)*((g_.) + (h_.)*(x_)), x_] :> Simp[(b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^n*((e + f*x)^(p + 1)/(b*(b*e - a*f)*(m + 1))), x] - Simp[1/(b*(b*e - a*f)*(m + 1)) Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[b* c*(f*g - e*h)*(m + 1) + (b*g - a*h)*(d*e*n + c*f*(p + 1)) + d*(b*(f*g - e*h )*(m + 1) + f*(b*g - a*h)*(n + p + 1))*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, h, p}, x] && ILtQ[m, -1] && GtQ[n, 0]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt Q[a, 0] || LtQ[b, 0])
Time = 0.24 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.54
method | result | size |
risch | \(\frac {63000 x^{5}-195300 x^{4}-437328 x^{3}-138872 x^{2}+103365 x +47939}{567 \left (2+3 x \right )^{3} \sqrt {1-2 x}}-\frac {36038 \sqrt {21}\, \operatorname {arctanh}\left (\frac {\sqrt {21}\, \sqrt {1-2 x}}{7}\right )}{11907}\) | \(61\) |
pseudoelliptic | \(\frac {-36038 \,\operatorname {arctanh}\left (\frac {\sqrt {21}\, \sqrt {1-2 x}}{7}\right ) \left (2+3 x \right )^{3} \sqrt {21}-21 \sqrt {1-2 x}\, \left (31500 x^{4}-81900 x^{3}-259614 x^{2}-199243 x -47939\right )}{11907 \left (2+3 x \right )^{3}}\) | \(65\) |
derivativedivides | \(\frac {250 \left (1-2 x \right )^{\frac {3}{2}}}{243}+\frac {2050 \sqrt {1-2 x}}{243}+\frac {-\frac {7876 \left (1-2 x \right )^{\frac {5}{2}}}{189}+\frac {46612 \left (1-2 x \right )^{\frac {3}{2}}}{243}-\frac {53648 \sqrt {1-2 x}}{243}}{\left (-4-6 x \right )^{3}}-\frac {36038 \sqrt {21}\, \operatorname {arctanh}\left (\frac {\sqrt {21}\, \sqrt {1-2 x}}{7}\right )}{11907}\) | \(75\) |
default | \(\frac {250 \left (1-2 x \right )^{\frac {3}{2}}}{243}+\frac {2050 \sqrt {1-2 x}}{243}+\frac {-\frac {7876 \left (1-2 x \right )^{\frac {5}{2}}}{189}+\frac {46612 \left (1-2 x \right )^{\frac {3}{2}}}{243}-\frac {53648 \sqrt {1-2 x}}{243}}{\left (-4-6 x \right )^{3}}-\frac {36038 \sqrt {21}\, \operatorname {arctanh}\left (\frac {\sqrt {21}\, \sqrt {1-2 x}}{7}\right )}{11907}\) | \(75\) |
trager | \(-\frac {\left (31500 x^{4}-81900 x^{3}-259614 x^{2}-199243 x -47939\right ) \sqrt {1-2 x}}{567 \left (2+3 x \right )^{3}}+\frac {18019 \operatorname {RootOf}\left (\textit {\_Z}^{2}-21\right ) \ln \left (\frac {3 \operatorname {RootOf}\left (\textit {\_Z}^{2}-21\right ) x +21 \sqrt {1-2 x}-5 \operatorname {RootOf}\left (\textit {\_Z}^{2}-21\right )}{2+3 x}\right )}{11907}\) | \(82\) |
Input:
int((1-2*x)^(3/2)*(3+5*x)^3/(2+3*x)^4,x,method=_RETURNVERBOSE)
Output:
1/567*(63000*x^5-195300*x^4-437328*x^3-138872*x^2+103365*x+47939)/(2+3*x)^ 3/(1-2*x)^(1/2)-36038/11907*21^(1/2)*arctanh(1/7*21^(1/2)*(1-2*x)^(1/2))
Time = 0.08 (sec) , antiderivative size = 94, normalized size of antiderivative = 0.82 \[ \int \frac {(1-2 x)^{3/2} (3+5 x)^3}{(2+3 x)^4} \, dx=\frac {18019 \, \sqrt {21} {\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )} \log \left (\frac {3 \, x + \sqrt {21} \sqrt {-2 \, x + 1} - 5}{3 \, x + 2}\right ) - 21 \, {\left (31500 \, x^{4} - 81900 \, x^{3} - 259614 \, x^{2} - 199243 \, x - 47939\right )} \sqrt {-2 \, x + 1}}{11907 \, {\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )}} \] Input:
integrate((1-2*x)^(3/2)*(3+5*x)^3/(2+3*x)^4,x, algorithm="fricas")
Output:
1/11907*(18019*sqrt(21)*(27*x^3 + 54*x^2 + 36*x + 8)*log((3*x + sqrt(21)*s qrt(-2*x + 1) - 5)/(3*x + 2)) - 21*(31500*x^4 - 81900*x^3 - 259614*x^2 - 1 99243*x - 47939)*sqrt(-2*x + 1))/(27*x^3 + 54*x^2 + 36*x + 8)
Timed out. \[ \int \frac {(1-2 x)^{3/2} (3+5 x)^3}{(2+3 x)^4} \, dx=\text {Timed out} \] Input:
integrate((1-2*x)**(3/2)*(3+5*x)**3/(2+3*x)**4,x)
Output:
Timed out
Time = 0.13 (sec) , antiderivative size = 110, normalized size of antiderivative = 0.96 \[ \int \frac {(1-2 x)^{3/2} (3+5 x)^3}{(2+3 x)^4} \, dx=\frac {250}{243} \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} + \frac {18019}{11907} \, \sqrt {21} \log \left (-\frac {\sqrt {21} - 3 \, \sqrt {-2 \, x + 1}}{\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}}\right ) + \frac {2050}{243} \, \sqrt {-2 \, x + 1} + \frac {4 \, {\left (17721 \, {\left (-2 \, x + 1\right )}^{\frac {5}{2}} - 81571 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} + 93884 \, \sqrt {-2 \, x + 1}\right )}}{1701 \, {\left (27 \, {\left (2 \, x - 1\right )}^{3} + 189 \, {\left (2 \, x - 1\right )}^{2} + 882 \, x - 98\right )}} \] Input:
integrate((1-2*x)^(3/2)*(3+5*x)^3/(2+3*x)^4,x, algorithm="maxima")
Output:
250/243*(-2*x + 1)^(3/2) + 18019/11907*sqrt(21)*log(-(sqrt(21) - 3*sqrt(-2 *x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) + 2050/243*sqrt(-2*x + 1) + 4/1701 *(17721*(-2*x + 1)^(5/2) - 81571*(-2*x + 1)^(3/2) + 93884*sqrt(-2*x + 1))/ (27*(2*x - 1)^3 + 189*(2*x - 1)^2 + 882*x - 98)
Time = 0.13 (sec) , antiderivative size = 102, normalized size of antiderivative = 0.89 \[ \int \frac {(1-2 x)^{3/2} (3+5 x)^3}{(2+3 x)^4} \, dx=\frac {250}{243} \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} + \frac {18019}{11907} \, \sqrt {21} \log \left (\frac {{\left | -2 \, \sqrt {21} + 6 \, \sqrt {-2 \, x + 1} \right |}}{2 \, {\left (\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}\right )}}\right ) + \frac {2050}{243} \, \sqrt {-2 \, x + 1} + \frac {17721 \, {\left (2 \, x - 1\right )}^{2} \sqrt {-2 \, x + 1} - 81571 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} + 93884 \, \sqrt {-2 \, x + 1}}{3402 \, {\left (3 \, x + 2\right )}^{3}} \] Input:
integrate((1-2*x)^(3/2)*(3+5*x)^3/(2+3*x)^4,x, algorithm="giac")
Output:
250/243*(-2*x + 1)^(3/2) + 18019/11907*sqrt(21)*log(1/2*abs(-2*sqrt(21) + 6*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) + 2050/243*sqrt(-2*x + 1) + 1/3402*(17721*(2*x - 1)^2*sqrt(-2*x + 1) - 81571*(-2*x + 1)^(3/2) + 938 84*sqrt(-2*x + 1))/(3*x + 2)^3
Time = 1.06 (sec) , antiderivative size = 91, normalized size of antiderivative = 0.80 \[ \int \frac {(1-2 x)^{3/2} (3+5 x)^3}{(2+3 x)^4} \, dx=\frac {2050\,\sqrt {1-2\,x}}{243}+\frac {250\,{\left (1-2\,x\right )}^{3/2}}{243}+\frac {\frac {53648\,\sqrt {1-2\,x}}{6561}-\frac {46612\,{\left (1-2\,x\right )}^{3/2}}{6561}+\frac {7876\,{\left (1-2\,x\right )}^{5/2}}{5103}}{\frac {98\,x}{3}+7\,{\left (2\,x-1\right )}^2+{\left (2\,x-1\right )}^3-\frac {98}{27}}+\frac {\sqrt {21}\,\mathrm {atan}\left (\frac {\sqrt {21}\,\sqrt {1-2\,x}\,1{}\mathrm {i}}{7}\right )\,36038{}\mathrm {i}}{11907} \] Input:
int(((1 - 2*x)^(3/2)*(5*x + 3)^3)/(3*x + 2)^4,x)
Output:
(21^(1/2)*atan((21^(1/2)*(1 - 2*x)^(1/2)*1i)/7)*36038i)/11907 + (2050*(1 - 2*x)^(1/2))/243 + (250*(1 - 2*x)^(3/2))/243 + ((53648*(1 - 2*x)^(1/2))/65 61 - (46612*(1 - 2*x)^(3/2))/6561 + (7876*(1 - 2*x)^(5/2))/5103)/((98*x)/3 + 7*(2*x - 1)^2 + (2*x - 1)^3 - 98/27)
Time = 0.15 (sec) , antiderivative size = 219, normalized size of antiderivative = 1.92 \[ \int \frac {(1-2 x)^{3/2} (3+5 x)^3}{(2+3 x)^4} \, dx=\frac {-661500 \sqrt {-2 x +1}\, x^{4}+1719900 \sqrt {-2 x +1}\, x^{3}+5451894 \sqrt {-2 x +1}\, x^{2}+4184103 \sqrt {-2 x +1}\, x +1006719 \sqrt {-2 x +1}+486513 \sqrt {21}\, \mathrm {log}\left (3 \sqrt {-2 x +1}-\sqrt {21}\right ) x^{3}+973026 \sqrt {21}\, \mathrm {log}\left (3 \sqrt {-2 x +1}-\sqrt {21}\right ) x^{2}+648684 \sqrt {21}\, \mathrm {log}\left (3 \sqrt {-2 x +1}-\sqrt {21}\right ) x +144152 \sqrt {21}\, \mathrm {log}\left (3 \sqrt {-2 x +1}-\sqrt {21}\right )-486513 \sqrt {21}\, \mathrm {log}\left (3 \sqrt {-2 x +1}+\sqrt {21}\right ) x^{3}-973026 \sqrt {21}\, \mathrm {log}\left (3 \sqrt {-2 x +1}+\sqrt {21}\right ) x^{2}-648684 \sqrt {21}\, \mathrm {log}\left (3 \sqrt {-2 x +1}+\sqrt {21}\right ) x -144152 \sqrt {21}\, \mathrm {log}\left (3 \sqrt {-2 x +1}+\sqrt {21}\right )}{321489 x^{3}+642978 x^{2}+428652 x +95256} \] Input:
int((1-2*x)^(3/2)*(3+5*x)^3/(2+3*x)^4,x)
Output:
( - 661500*sqrt( - 2*x + 1)*x**4 + 1719900*sqrt( - 2*x + 1)*x**3 + 5451894 *sqrt( - 2*x + 1)*x**2 + 4184103*sqrt( - 2*x + 1)*x + 1006719*sqrt( - 2*x + 1) + 486513*sqrt(21)*log(3*sqrt( - 2*x + 1) - sqrt(21))*x**3 + 973026*sq rt(21)*log(3*sqrt( - 2*x + 1) - sqrt(21))*x**2 + 648684*sqrt(21)*log(3*sqr t( - 2*x + 1) - sqrt(21))*x + 144152*sqrt(21)*log(3*sqrt( - 2*x + 1) - sqr t(21)) - 486513*sqrt(21)*log(3*sqrt( - 2*x + 1) + sqrt(21))*x**3 - 973026* sqrt(21)*log(3*sqrt( - 2*x + 1) + sqrt(21))*x**2 - 648684*sqrt(21)*log(3*s qrt( - 2*x + 1) + sqrt(21))*x - 144152*sqrt(21)*log(3*sqrt( - 2*x + 1) + s qrt(21)))/(11907*(27*x**3 + 54*x**2 + 36*x + 8))