Integrand size = 13, antiderivative size = 79 \[ \int x^m \left (a+b x^2\right )^4 \, dx=\frac {a^4 x^{1+m}}{1+m}+\frac {4 a^3 b x^{3+m}}{3+m}+\frac {6 a^2 b^2 x^{5+m}}{5+m}+\frac {4 a b^3 x^{7+m}}{7+m}+\frac {b^4 x^{9+m}}{9+m} \] Output:
a^4*x^(1+m)/(1+m)+4*a^3*b*x^(3+m)/(3+m)+6*a^2*b^2*x^(5+m)/(5+m)+4*a*b^3*x^ (7+m)/(7+m)+b^4*x^(9+m)/(9+m)
Time = 0.05 (sec) , antiderivative size = 72, normalized size of antiderivative = 0.91 \[ \int x^m \left (a+b x^2\right )^4 \, dx=x^{1+m} \left (\frac {a^4}{1+m}+\frac {4 a^3 b x^2}{3+m}+\frac {6 a^2 b^2 x^4}{5+m}+\frac {4 a b^3 x^6}{7+m}+\frac {b^4 x^8}{9+m}\right ) \] Input:
Integrate[x^m*(a + b*x^2)^4,x]
Output:
x^(1 + m)*(a^4/(1 + m) + (4*a^3*b*x^2)/(3 + m) + (6*a^2*b^2*x^4)/(5 + m) + (4*a*b^3*x^6)/(7 + m) + (b^4*x^8)/(9 + m))
Time = 0.20 (sec) , antiderivative size = 79, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {244, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x^m \left (a+b x^2\right )^4 \, dx\) |
\(\Big \downarrow \) 244 |
\(\displaystyle \int \left (a^4 x^m+4 a^3 b x^{m+2}+6 a^2 b^2 x^{m+4}+4 a b^3 x^{m+6}+b^4 x^{m+8}\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {a^4 x^{m+1}}{m+1}+\frac {4 a^3 b x^{m+3}}{m+3}+\frac {6 a^2 b^2 x^{m+5}}{m+5}+\frac {4 a b^3 x^{m+7}}{m+7}+\frac {b^4 x^{m+9}}{m+9}\) |
Input:
Int[x^m*(a + b*x^2)^4,x]
Output:
(a^4*x^(1 + m))/(1 + m) + (4*a^3*b*x^(3 + m))/(3 + m) + (6*a^2*b^2*x^(5 + m))/(5 + m) + (4*a*b^3*x^(7 + m))/(7 + m) + (b^4*x^(9 + m))/(9 + m)
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_.), x_Symbol] :> Int[Expand Integrand[(c*x)^m*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, m}, x] && IGtQ[p , 0]
Leaf count of result is larger than twice the leaf count of optimal. \(289\) vs. \(2(79)=158\).
Time = 0.29 (sec) , antiderivative size = 290, normalized size of antiderivative = 3.67
method | result | size |
risch | \(\frac {x \left (b^{4} m^{4} x^{8}+16 b^{4} m^{3} x^{8}+4 a \,b^{3} m^{4} x^{6}+86 b^{4} m^{2} x^{8}+72 a \,b^{3} m^{3} x^{6}+176 m \,x^{8} b^{4}+6 a^{2} b^{2} m^{4} x^{4}+416 a \,b^{3} m^{2} x^{6}+105 b^{4} x^{8}+120 a^{2} b^{2} m^{3} x^{4}+888 m \,x^{6} a \,b^{3}+4 a^{3} b \,m^{4} x^{2}+780 a^{2} b^{2} m^{2} x^{4}+540 a \,b^{3} x^{6}+88 a^{3} b \,m^{3} x^{2}+1800 m \,x^{4} a^{2} b^{2}+a^{4} m^{4}+656 a^{3} b \,m^{2} x^{2}+1134 a^{2} b^{2} x^{4}+24 a^{4} m^{3}+1832 m \,x^{2} a^{3} b +206 a^{4} m^{2}+1260 a^{3} b \,x^{2}+744 m \,a^{4}+945 a^{4}\right ) x^{m}}{\left (9+m \right ) \left (7+m \right ) \left (5+m \right ) \left (3+m \right ) \left (1+m \right )}\) | \(290\) |
orering | \(\frac {x \left (b^{4} m^{4} x^{8}+16 b^{4} m^{3} x^{8}+4 a \,b^{3} m^{4} x^{6}+86 b^{4} m^{2} x^{8}+72 a \,b^{3} m^{3} x^{6}+176 m \,x^{8} b^{4}+6 a^{2} b^{2} m^{4} x^{4}+416 a \,b^{3} m^{2} x^{6}+105 b^{4} x^{8}+120 a^{2} b^{2} m^{3} x^{4}+888 m \,x^{6} a \,b^{3}+4 a^{3} b \,m^{4} x^{2}+780 a^{2} b^{2} m^{2} x^{4}+540 a \,b^{3} x^{6}+88 a^{3} b \,m^{3} x^{2}+1800 m \,x^{4} a^{2} b^{2}+a^{4} m^{4}+656 a^{3} b \,m^{2} x^{2}+1134 a^{2} b^{2} x^{4}+24 a^{4} m^{3}+1832 m \,x^{2} a^{3} b +206 a^{4} m^{2}+1260 a^{3} b \,x^{2}+744 m \,a^{4}+945 a^{4}\right ) x^{m}}{\left (9+m \right ) \left (7+m \right ) \left (5+m \right ) \left (3+m \right ) \left (1+m \right )}\) | \(290\) |
gosper | \(\frac {x^{1+m} \left (b^{4} m^{4} x^{8}+16 b^{4} m^{3} x^{8}+4 a \,b^{3} m^{4} x^{6}+86 b^{4} m^{2} x^{8}+72 a \,b^{3} m^{3} x^{6}+176 m \,x^{8} b^{4}+6 a^{2} b^{2} m^{4} x^{4}+416 a \,b^{3} m^{2} x^{6}+105 b^{4} x^{8}+120 a^{2} b^{2} m^{3} x^{4}+888 m \,x^{6} a \,b^{3}+4 a^{3} b \,m^{4} x^{2}+780 a^{2} b^{2} m^{2} x^{4}+540 a \,b^{3} x^{6}+88 a^{3} b \,m^{3} x^{2}+1800 m \,x^{4} a^{2} b^{2}+a^{4} m^{4}+656 a^{3} b \,m^{2} x^{2}+1134 a^{2} b^{2} x^{4}+24 a^{4} m^{3}+1832 m \,x^{2} a^{3} b +206 a^{4} m^{2}+1260 a^{3} b \,x^{2}+744 m \,a^{4}+945 a^{4}\right )}{\left (1+m \right ) \left (3+m \right ) \left (5+m \right ) \left (7+m \right ) \left (9+m \right )}\) | \(291\) |
parallelrisch | \(\frac {4 x^{7} x^{m} a \,b^{3} m^{4}+72 x^{7} x^{m} a \,b^{3} m^{3}+416 x^{7} x^{m} a \,b^{3} m^{2}+6 x^{5} x^{m} a^{2} b^{2} m^{4}+888 x^{7} x^{m} a \,b^{3} m +120 x^{5} x^{m} a^{2} b^{2} m^{3}+780 x^{5} x^{m} a^{2} b^{2} m^{2}+4 x^{3} x^{m} a^{3} b \,m^{4}+1800 x^{5} x^{m} a^{2} b^{2} m +88 x^{3} x^{m} a^{3} b \,m^{3}+656 x^{3} x^{m} a^{3} b \,m^{2}+1832 x^{3} x^{m} a^{3} b m +1134 x^{5} x^{m} a^{2} b^{2}+x \,x^{m} a^{4} m^{4}+24 x \,x^{m} a^{4} m^{3}+1260 x^{3} x^{m} a^{3} b +206 x \,x^{m} a^{4} m^{2}+744 x \,x^{m} a^{4} m +x^{9} x^{m} b^{4} m^{4}+16 x^{9} x^{m} b^{4} m^{3}+86 x^{9} x^{m} b^{4} m^{2}+176 x^{9} x^{m} b^{4} m +540 x^{7} x^{m} a \,b^{3}+105 x^{9} x^{m} b^{4}+945 x \,x^{m} a^{4}}{\left (9+m \right ) \left (7+m \right ) \left (5+m \right ) \left (3+m \right ) \left (1+m \right )}\) | \(366\) |
Input:
int(x^m*(b*x^2+a)^4,x,method=_RETURNVERBOSE)
Output:
x*(b^4*m^4*x^8+16*b^4*m^3*x^8+4*a*b^3*m^4*x^6+86*b^4*m^2*x^8+72*a*b^3*m^3* x^6+176*b^4*m*x^8+6*a^2*b^2*m^4*x^4+416*a*b^3*m^2*x^6+105*b^4*x^8+120*a^2* b^2*m^3*x^4+888*a*b^3*m*x^6+4*a^3*b*m^4*x^2+780*a^2*b^2*m^2*x^4+540*a*b^3* x^6+88*a^3*b*m^3*x^2+1800*a^2*b^2*m*x^4+a^4*m^4+656*a^3*b*m^2*x^2+1134*a^2 *b^2*x^4+24*a^4*m^3+1832*a^3*b*m*x^2+206*a^4*m^2+1260*a^3*b*x^2+744*a^4*m+ 945*a^4)*x^m/(9+m)/(7+m)/(5+m)/(3+m)/(1+m)
Leaf count of result is larger than twice the leaf count of optimal. 251 vs. \(2 (79) = 158\).
Time = 0.07 (sec) , antiderivative size = 251, normalized size of antiderivative = 3.18 \[ \int x^m \left (a+b x^2\right )^4 \, dx=\frac {{\left ({\left (b^{4} m^{4} + 16 \, b^{4} m^{3} + 86 \, b^{4} m^{2} + 176 \, b^{4} m + 105 \, b^{4}\right )} x^{9} + 4 \, {\left (a b^{3} m^{4} + 18 \, a b^{3} m^{3} + 104 \, a b^{3} m^{2} + 222 \, a b^{3} m + 135 \, a b^{3}\right )} x^{7} + 6 \, {\left (a^{2} b^{2} m^{4} + 20 \, a^{2} b^{2} m^{3} + 130 \, a^{2} b^{2} m^{2} + 300 \, a^{2} b^{2} m + 189 \, a^{2} b^{2}\right )} x^{5} + 4 \, {\left (a^{3} b m^{4} + 22 \, a^{3} b m^{3} + 164 \, a^{3} b m^{2} + 458 \, a^{3} b m + 315 \, a^{3} b\right )} x^{3} + {\left (a^{4} m^{4} + 24 \, a^{4} m^{3} + 206 \, a^{4} m^{2} + 744 \, a^{4} m + 945 \, a^{4}\right )} x\right )} x^{m}}{m^{5} + 25 \, m^{4} + 230 \, m^{3} + 950 \, m^{2} + 1689 \, m + 945} \] Input:
integrate(x^m*(b*x^2+a)^4,x, algorithm="fricas")
Output:
((b^4*m^4 + 16*b^4*m^3 + 86*b^4*m^2 + 176*b^4*m + 105*b^4)*x^9 + 4*(a*b^3* m^4 + 18*a*b^3*m^3 + 104*a*b^3*m^2 + 222*a*b^3*m + 135*a*b^3)*x^7 + 6*(a^2 *b^2*m^4 + 20*a^2*b^2*m^3 + 130*a^2*b^2*m^2 + 300*a^2*b^2*m + 189*a^2*b^2) *x^5 + 4*(a^3*b*m^4 + 22*a^3*b*m^3 + 164*a^3*b*m^2 + 458*a^3*b*m + 315*a^3 *b)*x^3 + (a^4*m^4 + 24*a^4*m^3 + 206*a^4*m^2 + 744*a^4*m + 945*a^4)*x)*x^ m/(m^5 + 25*m^4 + 230*m^3 + 950*m^2 + 1689*m + 945)
Leaf count of result is larger than twice the leaf count of optimal. 1221 vs. \(2 (70) = 140\).
Time = 0.52 (sec) , antiderivative size = 1221, normalized size of antiderivative = 15.46 \[ \int x^m \left (a+b x^2\right )^4 \, dx=\text {Too large to display} \] Input:
integrate(x**m*(b*x**2+a)**4,x)
Output:
Piecewise((-a**4/(8*x**8) - 2*a**3*b/(3*x**6) - 3*a**2*b**2/(2*x**4) - 2*a *b**3/x**2 + b**4*log(x), Eq(m, -9)), (-a**4/(6*x**6) - a**3*b/x**4 - 3*a* *2*b**2/x**2 + 4*a*b**3*log(x) + b**4*x**2/2, Eq(m, -7)), (-a**4/(4*x**4) - 2*a**3*b/x**2 + 6*a**2*b**2*log(x) + 2*a*b**3*x**2 + b**4*x**4/4, Eq(m, -5)), (-a**4/(2*x**2) + 4*a**3*b*log(x) + 3*a**2*b**2*x**2 + a*b**3*x**4 + b**4*x**6/6, Eq(m, -3)), (a**4*log(x) + 2*a**3*b*x**2 + 3*a**2*b**2*x**4/ 2 + 2*a*b**3*x**6/3 + b**4*x**8/8, Eq(m, -1)), (a**4*m**4*x*x**m/(m**5 + 2 5*m**4 + 230*m**3 + 950*m**2 + 1689*m + 945) + 24*a**4*m**3*x*x**m/(m**5 + 25*m**4 + 230*m**3 + 950*m**2 + 1689*m + 945) + 206*a**4*m**2*x*x**m/(m** 5 + 25*m**4 + 230*m**3 + 950*m**2 + 1689*m + 945) + 744*a**4*m*x*x**m/(m** 5 + 25*m**4 + 230*m**3 + 950*m**2 + 1689*m + 945) + 945*a**4*x*x**m/(m**5 + 25*m**4 + 230*m**3 + 950*m**2 + 1689*m + 945) + 4*a**3*b*m**4*x**3*x**m/ (m**5 + 25*m**4 + 230*m**3 + 950*m**2 + 1689*m + 945) + 88*a**3*b*m**3*x** 3*x**m/(m**5 + 25*m**4 + 230*m**3 + 950*m**2 + 1689*m + 945) + 656*a**3*b* m**2*x**3*x**m/(m**5 + 25*m**4 + 230*m**3 + 950*m**2 + 1689*m + 945) + 183 2*a**3*b*m*x**3*x**m/(m**5 + 25*m**4 + 230*m**3 + 950*m**2 + 1689*m + 945) + 1260*a**3*b*x**3*x**m/(m**5 + 25*m**4 + 230*m**3 + 950*m**2 + 1689*m + 945) + 6*a**2*b**2*m**4*x**5*x**m/(m**5 + 25*m**4 + 230*m**3 + 950*m**2 + 1689*m + 945) + 120*a**2*b**2*m**3*x**5*x**m/(m**5 + 25*m**4 + 230*m**3 + 950*m**2 + 1689*m + 945) + 780*a**2*b**2*m**2*x**5*x**m/(m**5 + 25*m**4...
Time = 0.04 (sec) , antiderivative size = 79, normalized size of antiderivative = 1.00 \[ \int x^m \left (a+b x^2\right )^4 \, dx=\frac {b^{4} x^{m + 9}}{m + 9} + \frac {4 \, a b^{3} x^{m + 7}}{m + 7} + \frac {6 \, a^{2} b^{2} x^{m + 5}}{m + 5} + \frac {4 \, a^{3} b x^{m + 3}}{m + 3} + \frac {a^{4} x^{m + 1}}{m + 1} \] Input:
integrate(x^m*(b*x^2+a)^4,x, algorithm="maxima")
Output:
b^4*x^(m + 9)/(m + 9) + 4*a*b^3*x^(m + 7)/(m + 7) + 6*a^2*b^2*x^(m + 5)/(m + 5) + 4*a^3*b*x^(m + 3)/(m + 3) + a^4*x^(m + 1)/(m + 1)
Leaf count of result is larger than twice the leaf count of optimal. 365 vs. \(2 (79) = 158\).
Time = 0.13 (sec) , antiderivative size = 365, normalized size of antiderivative = 4.62 \[ \int x^m \left (a+b x^2\right )^4 \, dx=\frac {b^{4} m^{4} x^{9} x^{m} + 16 \, b^{4} m^{3} x^{9} x^{m} + 4 \, a b^{3} m^{4} x^{7} x^{m} + 86 \, b^{4} m^{2} x^{9} x^{m} + 72 \, a b^{3} m^{3} x^{7} x^{m} + 176 \, b^{4} m x^{9} x^{m} + 6 \, a^{2} b^{2} m^{4} x^{5} x^{m} + 416 \, a b^{3} m^{2} x^{7} x^{m} + 105 \, b^{4} x^{9} x^{m} + 120 \, a^{2} b^{2} m^{3} x^{5} x^{m} + 888 \, a b^{3} m x^{7} x^{m} + 4 \, a^{3} b m^{4} x^{3} x^{m} + 780 \, a^{2} b^{2} m^{2} x^{5} x^{m} + 540 \, a b^{3} x^{7} x^{m} + 88 \, a^{3} b m^{3} x^{3} x^{m} + 1800 \, a^{2} b^{2} m x^{5} x^{m} + a^{4} m^{4} x x^{m} + 656 \, a^{3} b m^{2} x^{3} x^{m} + 1134 \, a^{2} b^{2} x^{5} x^{m} + 24 \, a^{4} m^{3} x x^{m} + 1832 \, a^{3} b m x^{3} x^{m} + 206 \, a^{4} m^{2} x x^{m} + 1260 \, a^{3} b x^{3} x^{m} + 744 \, a^{4} m x x^{m} + 945 \, a^{4} x x^{m}}{m^{5} + 25 \, m^{4} + 230 \, m^{3} + 950 \, m^{2} + 1689 \, m + 945} \] Input:
integrate(x^m*(b*x^2+a)^4,x, algorithm="giac")
Output:
(b^4*m^4*x^9*x^m + 16*b^4*m^3*x^9*x^m + 4*a*b^3*m^4*x^7*x^m + 86*b^4*m^2*x ^9*x^m + 72*a*b^3*m^3*x^7*x^m + 176*b^4*m*x^9*x^m + 6*a^2*b^2*m^4*x^5*x^m + 416*a*b^3*m^2*x^7*x^m + 105*b^4*x^9*x^m + 120*a^2*b^2*m^3*x^5*x^m + 888* a*b^3*m*x^7*x^m + 4*a^3*b*m^4*x^3*x^m + 780*a^2*b^2*m^2*x^5*x^m + 540*a*b^ 3*x^7*x^m + 88*a^3*b*m^3*x^3*x^m + 1800*a^2*b^2*m*x^5*x^m + a^4*m^4*x*x^m + 656*a^3*b*m^2*x^3*x^m + 1134*a^2*b^2*x^5*x^m + 24*a^4*m^3*x*x^m + 1832*a ^3*b*m*x^3*x^m + 206*a^4*m^2*x*x^m + 1260*a^3*b*x^3*x^m + 744*a^4*m*x*x^m + 945*a^4*x*x^m)/(m^5 + 25*m^4 + 230*m^3 + 950*m^2 + 1689*m + 945)
Time = 0.60 (sec) , antiderivative size = 272, normalized size of antiderivative = 3.44 \[ \int x^m \left (a+b x^2\right )^4 \, dx=\frac {a^4\,x\,x^m\,\left (m^4+24\,m^3+206\,m^2+744\,m+945\right )}{m^5+25\,m^4+230\,m^3+950\,m^2+1689\,m+945}+\frac {b^4\,x^m\,x^9\,\left (m^4+16\,m^3+86\,m^2+176\,m+105\right )}{m^5+25\,m^4+230\,m^3+950\,m^2+1689\,m+945}+\frac {6\,a^2\,b^2\,x^m\,x^5\,\left (m^4+20\,m^3+130\,m^2+300\,m+189\right )}{m^5+25\,m^4+230\,m^3+950\,m^2+1689\,m+945}+\frac {4\,a\,b^3\,x^m\,x^7\,\left (m^4+18\,m^3+104\,m^2+222\,m+135\right )}{m^5+25\,m^4+230\,m^3+950\,m^2+1689\,m+945}+\frac {4\,a^3\,b\,x^m\,x^3\,\left (m^4+22\,m^3+164\,m^2+458\,m+315\right )}{m^5+25\,m^4+230\,m^3+950\,m^2+1689\,m+945} \] Input:
int(x^m*(a + b*x^2)^4,x)
Output:
(a^4*x*x^m*(744*m + 206*m^2 + 24*m^3 + m^4 + 945))/(1689*m + 950*m^2 + 230 *m^3 + 25*m^4 + m^5 + 945) + (b^4*x^m*x^9*(176*m + 86*m^2 + 16*m^3 + m^4 + 105))/(1689*m + 950*m^2 + 230*m^3 + 25*m^4 + m^5 + 945) + (6*a^2*b^2*x^m* x^5*(300*m + 130*m^2 + 20*m^3 + m^4 + 189))/(1689*m + 950*m^2 + 230*m^3 + 25*m^4 + m^5 + 945) + (4*a*b^3*x^m*x^7*(222*m + 104*m^2 + 18*m^3 + m^4 + 1 35))/(1689*m + 950*m^2 + 230*m^3 + 25*m^4 + m^5 + 945) + (4*a^3*b*x^m*x^3* (458*m + 164*m^2 + 22*m^3 + m^4 + 315))/(1689*m + 950*m^2 + 230*m^3 + 25*m ^4 + m^5 + 945)
Time = 0.20 (sec) , antiderivative size = 289, normalized size of antiderivative = 3.66 \[ \int x^m \left (a+b x^2\right )^4 \, dx=\frac {x^{m} x \left (b^{4} m^{4} x^{8}+16 b^{4} m^{3} x^{8}+4 a \,b^{3} m^{4} x^{6}+86 b^{4} m^{2} x^{8}+72 a \,b^{3} m^{3} x^{6}+176 b^{4} m \,x^{8}+6 a^{2} b^{2} m^{4} x^{4}+416 a \,b^{3} m^{2} x^{6}+105 b^{4} x^{8}+120 a^{2} b^{2} m^{3} x^{4}+888 a \,b^{3} m \,x^{6}+4 a^{3} b \,m^{4} x^{2}+780 a^{2} b^{2} m^{2} x^{4}+540 a \,b^{3} x^{6}+88 a^{3} b \,m^{3} x^{2}+1800 a^{2} b^{2} m \,x^{4}+a^{4} m^{4}+656 a^{3} b \,m^{2} x^{2}+1134 a^{2} b^{2} x^{4}+24 a^{4} m^{3}+1832 a^{3} b m \,x^{2}+206 a^{4} m^{2}+1260 a^{3} b \,x^{2}+744 a^{4} m +945 a^{4}\right )}{m^{5}+25 m^{4}+230 m^{3}+950 m^{2}+1689 m +945} \] Input:
int(x^m*(b*x^2+a)^4,x)
Output:
(x**m*x*(a**4*m**4 + 24*a**4*m**3 + 206*a**4*m**2 + 744*a**4*m + 945*a**4 + 4*a**3*b*m**4*x**2 + 88*a**3*b*m**3*x**2 + 656*a**3*b*m**2*x**2 + 1832*a **3*b*m*x**2 + 1260*a**3*b*x**2 + 6*a**2*b**2*m**4*x**4 + 120*a**2*b**2*m* *3*x**4 + 780*a**2*b**2*m**2*x**4 + 1800*a**2*b**2*m*x**4 + 1134*a**2*b**2 *x**4 + 4*a*b**3*m**4*x**6 + 72*a*b**3*m**3*x**6 + 416*a*b**3*m**2*x**6 + 888*a*b**3*m*x**6 + 540*a*b**3*x**6 + b**4*m**4*x**8 + 16*b**4*m**3*x**8 + 86*b**4*m**2*x**8 + 176*b**4*m*x**8 + 105*b**4*x**8))/(m**5 + 25*m**4 + 2 30*m**3 + 950*m**2 + 1689*m + 945)